3.03 Plate Tectonics


Objective(s):
In your own words, what was the purpose of this lab?


Hypothesis:
In this section, please include the if/then statements you developed during your lab activity for each location on the map. These statements reflect your predicted outcomes for the experiment.

Location One: Select two events that you predict will be observed. If I explore two continental plates at a convergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Two: Select three events that you predict will be observed. If I explore two continental plates at a divergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Three: Select three events that you predict will be observed. If I explore two continental plates at a transform boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading

Location Four: Select two events that you predict will be observed. If I explore two oceanic plates at a convergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Five: Select three events that you predict will be observed. If I explore two oceanic plates at a divergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Six: Select two events that you predict will be observed. If I explore two oceanic plates at a transform boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading

Procedure:
The procedures are listed in your virtual lab. You do not need to repeat them here. Please be sure to identify the test variable (independent variable), outcome variable (dependent variable).
Reminder: Test variable = the item you are changing or manipulating; Outcome variable = the item you are measuring
Test variable (independent variable):
Outcome variable (dependent variable):

Data:
Record the data from each location below.
Location Name
Boundary Type
(C=Convergent, D=Divergent, or T=Transform)
Year Observed
(5, 10, or 20 million years)
Geologic Events Observed
(earthquakes, faults, ocean formation, mountains, volcanoes, island chains, seafloor spreading)
Location One
Himalayas

5
Event 1-
20
Event 2-
Location Two
East Africa

5
Event 1-
10
Event 2-
20
Event 3-
Location Three
San Andreas fault zone

5
Event 1-
10
Event 2-
20
Event 3-
Location Four
Aleutian Islands

5
Event 1-
20
Event 2-
Location Five
Mid-Atlantic Ridge

5
Event 1-
10
Event 2-
20
Event 3-
Location Six
Alpine Fault

5
Event 1-
20
Event 2-


Conclusion:
Your conclusion will include a summary of the lab results and an interpretation of the results. Please write in complete sentences.
What types of geological events or changes occur at divergent plate boundaries?
What types of geological events or changes occur at convergent plate boundaries?
What types of geological events or changes occur at transform plate boundaries?
Explain how these geological processes and interactions have changed Earth's surface through the years. Be sure to use evidence to support your answer.

Answers

Answer 1
Location One earthquakesfaults

Location Two: ocean formationvolcanoesseafloor spreading

Location Three: earthquakesfaultsisland chains

Location Four: mountainsvolcanoes

Location Five: earthquakesfaultsseafloor spreading

Location Six: faultsisland chains

The types of geological events or changes that occur at divergent plate boundaries are earthquakes and magma because there is a fault when two plates move away from each other.

The types of geological events or changes that occur at convergent plate boundaries are earthquakes, volcanoes, and the formation of mountains because the tectonic plates are moving towards each other.

The types of geological events or changes that occur at transform plate boundaries are shallow earthquakes, lateral displacement of rock, and a broad zone of crustal deformation.

These geological processes have changed the surface of the earth as they have helped to form ocean basins, and mountain chains, and the formation of glaciers and volcanoes, and earthquakes have changed the underground geology of the earth.

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Related Questions

Which is the correct mole ratio of
K PO to KNO in the chemical
reaction
Mg(NO₂)₂ (aq) + K,PO (aq) -->
Mg (PO )₂(aq) + KNO₂(aq)?

Answers

The correct mole ratio of K₃PO₃ and KNO₂ in the chemical reaction is 1 : 3

Balanced equation

3Mg(NO₂)₂ (aq) + 2K₃PO₃ (aq) -> Mg₃(PO₃)₂(aq) + 6KNO₂(aq)

from the balance equation,

The number of mole of K₃PO₃ = 2 molesThe number of mole of KNO₂ = 6 moles

How to determine the mole ratio of K₃PO₃ and KNO₂Number of mole of K₃PO₃ = 2 molesNumber of mole of KNO₂ = 6 molesMole ratio of K₃PO₃ and KNO₂ =?

Mole ratio = mole of K₃PO₃ / mole of KNO₂

Mole ratio of K₃PO₃ and KNO₂ = 2 / 6

Mole ratio of K₃PO₃ and KNO₂ = 1 : 3

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Carbon fiber (CFRC) is generally stronger than steel, however, steel has a density that is about ____ compared to carbon fiber.

Answers

Carbon fiber Vs Steel:

Steel has a density that is about five times more when compared to carbon fiber.

What is Carbon fiber (CFRC):

Carbon is an element that occurs naturally, and carbon fiber is made of this element. Because of its crystalline structure, carbon fiber possesses excellent tensile strength and stiffness capabilities. It is used to create lightweight composite parts that have great strength by wrapping the fiber in a polymer matrix.

What is steel:

Steel has long been a preferred material due to its high elasticity, which is around 200 GPa. Its relative abundance and stiffness have made it a widely used manufacturing material. However, because of its weight and density of around 8 g/cm3, it can be exceedingly difficult on the machines it is intended to protect. This weighs nearly five times as much as carbon fiber materials which would offer an equivalent or higher level of stiffness.

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How many moles of sodium atoms is 5.43 x 10^24 atoms of sodium? *

Answers

Answer:

9.02 moles Na

Explanation:

To find the amount of moles, you need to multiply the given amount by Avogadro's Number. This number allows you to convert from atoms to moles of any substance.

Avogadro's Number:

6.022 x 10²³ atoms = 1 mole

5.43 x 10²⁴ atoms Na                    1 mole
--------------------------------  x  ---------------------------------  = 9.02 moles Na
                                             6.022 x 10²³ atoms

In a titration of 12.5 ML of 0.20m NaOH is used to neutralize 10.0 ML of HCL. Calculate the acid concentration

Answers

=> 0.25 M

The question is asking us to find the molarity/concentration of the acid (HCl).

We have been provided with;

12.50 mL of 0.20 M NaOH

10.0 mL of HCl

We know that molarity (M) of a solution is contained in 1 L or 1000 mL or 1000 cm³.

This means that;

0.20 M is contained in 1000 mL.

X mol is contained in 12.50 mL

[tex] x \: mol \: = \frac{12.50 \times 0.20}{1000} \\ = 0.0025 \: moles[/tex]

= 0.0025 moles

These 0.0025 moles is contained in 10 mL of HCl.

To find the molarity of the acid;

0.0025 moles is contained in 10 mL

x mol is contained in 1000 mL

[tex]x \: mol \: = \frac{0.0025 \times 1000}{10} \\ = 0.25 \: mol[/tex]

= 0.25 M

Therefore the Concentration of the acid (HCl) is 0.25 M

Using the name of the ionic compound, select the appropriate chemical formula. Use the periodic table
that has been provided. Click here to access the common polyatomic ion sheet
Ammonium Phosphate

Answers

The compound Ammonium Phosphate is (NH4)3PO4 while that of sodium acetate is NaC2H3O2.

What is an ionic compound?

An ionic compound is  compound that is composed of ions. We know that a poly atomic ion is an ion that contains more than one atom.

Looking at the options that have been provided, we know that the correct formula for the compound Ammonium Phosphate is (NH4)3PO4 while that of sodium acetate is NaC2H3O2.

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Q1. What are decomposition reactions? Explain with the help of a balanced chemical equation. (2 marks)
Q2. Draw the structure of a nephron and label the following on it- Glomerulus, Bowman’s capsule, Renal artery and Collecting duct. (2 marks)
Q3. What happens when zinc metal reacts with sulphuric acid? Write the chemical equation involved in this reaction. (2 marks)
Q4. Draw ray diagrams showing the image formation by a convex lens when an object is placed (2 marks)
(a) between optical centre and focus of the lens
(b) between focus and twice the focal length of the lens
Q5. Sunita and her mother had an appointment with an optician. Optician prescribed corrective lenses to Sunita having a power equal to + 5.0 D. The lens prescribed to
her mother has power equal to – 2.5 D. (3 marks)
(a) What is the focal length of the lens prescribed to Sunita?
(b) Which type of spherical lens is prescribed to Sunita’s mother?
(c) What is the power of the combination of the two lenses (if placed in contact), prescribed to Sunita and her mother?
Q6. Give the reason for the following: (3 marks)
(a) The taste and smell of chips change when the packet is left open for a few days.
(b) Magnesium ribbon is cleaned before burning in air.
(c) Iron articles get coated with reddish brown powder when left for sometime.
Q7. (a) Why do arteries have thick and elastic walls while veins have thin walls? (2 marks)
(b) What is the role of valves in the heart? (1 mark)

Answers

Decomposition reaction represents the breakdown of single compound into more products.

What are decomposition reactions?

A decomposition reaction is a type of reaction in which one reactant breaks down into two or more products. This can be represented by the general equation: H2O2 →  2H + 2O. In this example the breakdown of hydrogen peroxide occurs and  water and oxygen are formed.

What happens when zinc metal reacts with sulphuric acid?

Zinc reacts with dilute sulphuric acid to form zinc sulphate and hydrogen This hydrogen goes up into the atmosphere whereas the zinc sulphate remains.

Why should a magnesium ribbon be cleaned before burning in air?

Magnesium ribbon should be cleaned before burning in air because Magnesium metal combines with oxygen to form Magnesium Oxide (MgO) layer, which is a very stable molecule.

Why arteries have thick, elastic walls, while veins have thin walls?

Arteries have thick, elastic walls, while veins have thin walls because arteries are under more pressure, as compared to veins that are under less pressure. Arteries are big in size whereas veins are small.

What is the role of valves in the heart?

The role of valves in the heart is that these valves prevent the backward flow of blood.

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Compare the atomic sizes of sodium and magnesium. Explain. ​

Answers

Answer:

Sodium atom is larger than Magnesium atom.

Explanation:

Looking at the electronic configurations of Sodium and Magnesium:

[tex]_{11}Na: 1s^2 2s^2 p^6 3s^1\\\\_{12}Mg : 1s^2 2s^2 p^6 3s^2[/tex] ,

we can see that they both have their valence electrons in the 3rd shell.

But because Magnesium has a higher nuclear charge of +12 because of its 12 protons than that of Sodium's +11, the nucleus of Magnesium attracts its outer electrons more strongly than Sodium does. This makes the Magnesium atom smaller.

Using the equation

C12H22O11+12O2-->12CO2+11H2O

if 156 L of O2 at STP are consumed how many moles of sucrose are required?

Answers

Answer:

0.5804 moles sucrose are required to react with 156 liters of oxygen.

Explanation:

Since the conditions of the gas are STP, standard temperature and pressure, we can use a very useful conversion factor that is valid for all gases at STP:  All gases occupy 22.4 liters per mole of gas:

22.4 L/mole

156 liters of O2 at STP may be converted to moles O2 by dividing by the conversion factor:

 (156 L)/(22.4 L/mole) = 6.96 moles O2

The balanced equation tells us that 12 moles of O2 are consumed for every 1 mole of sucrose.  That's a molar ratio of (1 mole sucrose/12 moles O2).

We can use this ratio to determine the moles of sucrose required to react with 6.96 moles of O2:

(6.96 moles O2)*((1 mole sucrose/12 moles O2) = 0.5804 moles sucrose

what is the bond formed between N and Br

A) non-polar covalent
B) Polar Covalent
C) Ionic

Answers

Answer:

Bond between N and Br is non polar bond

Nitrogen being the element of group 15 , it required only 3 electrons to complete it's octace and BR, element of group 17 requires only one electron to complete it's octace both nitrogen and br share their electrons as for forming ionic bond it requires too much energy for nitrogen to remove 3 electrons also here, valency of br is only one. both are non metal so they formed covalent bond.

A sample of metal has a mass of 16.5916.59 g, and a volume of 5.815.81 mL. What is the density of this metal

Answers

Answer:

=> 2.8554 g/mL

Explanation:

To determine the formula to use in solving such a problem, you have to consider what you have been given.

We have;

mass (m)     = 16.59 g

Volume (v) =  5.81 mL

From our question, we are to determine the density (rho) of the rock.

The formula:

[tex]p = \frac{m}{v}[/tex]

Substitute the values into the formula:

​[tex]p = \frac{16.59 g}{5.81 mL} \\ = 2.8554 g/mL[/tex]

= 2.8554 g/mL

Therefore, the density (rho) of the rock is 2.8554 g/mL.

Which statement best describes the science of chemistry?
A. Chemistry is mainly the study of energy and forces in matter in the
universe.
B. Chemistry is mainly the study of forces in matter.


C. Chemistry is mainly the study of the composition of and changes
in matter.
D. Chemistry is mainly the study of matter in living things.

Answers

Answer:

Explanation:Matter is anything that has weight and occupies space

The oxidation number of an element in a compound is equal to the charge the atoms would have if the compound was ___________. Select the correct answer below: ionic covalent molecular

Answers

The oxidation number of an element in a compound is equal to the charge of the atoms if the compound was an ionic compound.

What are types of compounds and how their oxidation number is calculated?

The types of compounds are:

Ionic compoundsCovalent compounds and Molecular compounds

Ionic compounds:

When a metal reacts with a non-metal an ionic compound is formed.The metal and ono-metals share electrons in between them and forms an anion and a cation respectively.The oxidation number of an ionic compound is equal to the charge of the ion.For a polyatomic ion, the sum of the oxidation numbers is equal to the charge of the ion.

Covalent compound:

When non-metals reacts together a covalent compound is formed.They share electrons in between them by forming a covalent bond.The oxidation number of a covalent compound is the charge that results when the electrons are assigned to the more electronegative atom.

Molecular compounds:

Molecular compounds are like the covalent compounds shares a covalent bond in between the atoms.The oxidation number of a molecule is given by gaining or losing of an electron by the atoms in it.

Therefore, the oxidation number of an element in a compound is equal to the charge of the ion that would have if the compound was an ionic compound.

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What is the symbol for temperature?

m

q

T

J

Answers

Answer:

T

Explanation:

m is mass

q is heat

J is energy

Which of the following statements is true?
A. A high atom economy means that most of the starting materials end up as waste products.
B. The actual yield of a reaction is the amount of product you expected to make.
OC. A reaction with a high percentage yield is an efficient reaction.
D. The percentage yield of a reaction can be over 100%.

Answers

Answer:

B. The actual yield of a reaction is the amount of product you expected to make.

Explanation:

The actual yield of a reaction is the quantity of a product that is obtained from a chemical reaction. Therefore part B is the right solution to our question since it is true that actual yield of a reaction is the amount of product you expected to make.

How many grams of NH3 form when 22g H2 react completely?

Answers

The Answer to the question is 124.66 grams approximately.

It is given that H₂ will react completely

Molar mass of H₂ = 2 × 1 = 2 gm/mol

Given mass of H₂ = 22 gm

Moles of H₂ reacting = given mass of H₂ / molar mass of H₂

Moles of H₂ reacting = 22 / 2 moles = 11 moles

So, 11 moles of H₂ are taking part in reaction.

The Balanced chemical reaction is as follows as:

N₂ + 3 H₂ → 2 NH₃

It is clear from the reaction that 3 moles of H₂ are making 2 mole of NH₃

3 moles of H₂ → 2 mole of NH₃

1 moles of H₂ → 2/3 mole of NH₃

11 moles of H₂ → (2/3)×11 mole of NH₃

11 moles of H₂ → 22/3 mole of NH₃

So, 11 moles of H₂ will make 22/3 mole of NH₃

22/3 mole NH₃ = mass formed NH₃ / molar mass of NH₃

mass formed NH₃ = 22/3 × molar mass of NH₃

mass formed NH₃ = 22/3 × 17

mass formed NH₃ = 22/3 × 17

mass formed NH₃ = 124.66 grams    (approximately)

124.66 grams of NH₃ will be formed.

So, approximately 124.66 grams of NH₃ is formed from 22 grams of H₂.

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4 b + 3 o2 → 2 b2o3 if 8 moles of b and 4 moles of o2 are allowed to react, how many moles of b2o3 can be formed?

Answers

The number of moles of  b2o3 that will be formed is determined as 4 moles.

Limiting reagent

The limiting reagent is the reactant that will be completely used up.

4 b + 3O₂ → 2b₂O₃

from the equation above;

4 b ------------> 2 b₂O₃

2b ------------> b₂O₃

2 : 1

3O₂  -------------> 2b₂O₃

3  :  2

b is the limiting reagent, thus, the amount of b2o3 to be formed is calculated as;

4 b ------------> 2 moles of  b2o3

8 moles -------> ?

= (8 x 2)/4

= 4 moles

Thus, the number of moles of  b2o3 that will be formed is determined as 4 moles.

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In molecules, c, h, o, and n atoms usually make __, __, __, and __ bonds respectively

Answers

Answer:   " 4, 1, 2, 3."

_______________
  " In molecules, C, H, O, and N atoms  usually make _4_, _1_, _2_, and  

_3_ bonds, respectively."
_______________
Note the following mnemonic device:

" H O N C " —>  "Honc" if you love molecules!"

  1   2  3  4 ;

{"hydrogen"} H → 1

{"oxygen"} O  → 2

{"nitrogen"} N → 3

{"carbon"} C → 4

___

So:  by using this mnemonic:
H  O  N  C ;

1   2   3   4 ;
___
We can answer the question:
" C, H, O,  N " → in sequence:
" 4,  1,  2,  3 " ;

{just use the corresponding numbers as per the mnemonic device.}.
The answer:  
" 4, 1, 2, 3 ".

Hope this is helpful to you!  Best wishes!

A nonpolar solvent has the highest solubility with a(n) _____ solute. A. polar B. nonpolar C. ionic D. electrically charged solute. ​

Answers

Answer:

nonpolar

Explanation:

A nonpolar solvent has the highest solubility with a nonpolar solute.

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Question 9(Multiple Choice Worth 5 points)
(01.02 LC)
Which of the following is true about the weight of an object?
O It remains same for the object.
O It cannot be measured accurately.
O It is a force acting on the object.
O It is always less than the mass of the object.
PLS HELP

Answers

Answer:

It is a force acting on the object.

Explanation:

The answer option which is true about the weight of an object is: C. It is a force acting on the object.

Weight can be defined as the force acting on a physical body or an object as a result of gravity. Also, the weight of an object is measured in Newton.

Mathematically, the weight of an object is given by the formula;

Where;

m is the mass of the object.

g is the acceleration due to gravity.

In conclusion, the weight of an object is the force acting on an object due to gravity.

If 82.5 mol of an ideal gas occupies 10.5 l at 317 k, what is the pressure of the gas?

Answers

P=20707.7 atm

What is the molar form of the ideal gas law?

The ideal gas law is a straightforward formula that describes the relationship between an ideal gas's pressure P, volume V, and temperature T. Unless there is a strong reason to treat gases differently, we normally treat gases as ideal because of how straightforward this relationship is:-

PV=nRT

where ;

P= Pressure=?

V= Volume= 10.5 L

n= no.of mol.= 82.5 mol

R=Ideal gas constant= 8.314 joule / mol kelvin

T=Temperature= 317 K

using Given value:-

P= nRT/ V

P=(82.5 x 8.314 x 317) / 10.5

P=20707.7 atm

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Mia has a 32.0 g sample of Fe(OH)3 for the investigation purpose. How many
grams of oxygen be recovered from the sample?
O 3.6g
21.6 g
7.2 g
O 14.4 g

Answers

The amount of oxygen that can be recovered would be 14.37 grams

Percentage composition

[tex]Fe(OH)_3[/tex] has 3 atoms of oxygen.

The percentage oxygen composition in the compound can be calculated as:

              mass of oxygen content/total mass

The molar mass of the compound is 106.87 g/mol.

Percent oxygen = 3 x 16/106.87 x 100% = 44.91%

Thus, the amount of oxygen that can be recovered from 32.0 grams of Fe(OH)3 will be:

            44.91/100 x 32 = 14.37 grams

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what might be a scientific question

Answers

Answer:

Example of a scientific question:

Does the angle of a ramp change the distance a toy car will travel?

Explanation:

What is the correct ratio of the atoms of the two elements present in a sample of the compound copper chloride, CuCl2?

Each answer will be formatted as Copper : Chlorine .

Select one:
a. 0:0
b. 2:1
c. 1:2
d. 1:1

Answers

The correct ratio of the atoms of the two elements in the sample of copper chloride compound would be 1:2.

Atoms of elements

Copper chloride has a chemical formula, [tex]CuCl_2[/tex].

Thus, an atom of copper, Cu, combines with 2 atoms of chlorine, Cl.

The 2 chlorine atoms are recipients of an electron each from the copper atom which happens to have 2 electrons in its outermost valence shell.

Therefore, the ratio of copper to chlorine atoms in the compound is 1:2.

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If a radioactive decay produced 1.26 × 1012 J of energy, how much mass was lost in the reaction?

Answers

The mass lost in the process is 1.4 * 10^-5Kg.

What is the Einstein equation?

The Einstein equation is able to relate the mass lost to the energy that is evolved in a nuclear process.

Given that;

E = Δmc^2

Δm = E/c^2

Δm =  1.26 × 10^12 J/( 3 * 10^8)^2

Δm = 1.4 * 10^-5Kg

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Which is the correct name for p2o5? phosphorus dioxide phosphorus pentoxide diphosphorus pentoxide diphosphorus hexaoxide

Answers

Correct option:

The correct name for [tex]P_{2}O_{5}[/tex]  is diphosphorus pentoxide.

Why [tex]P_{2}O_{5}[/tex] is called diphosphorus pentoxide?

[tex]P_{2}O_{5}[/tex] is commonly known as diphosphorus pentoxide.

Phosphorus pentoxide has an intriguing property in that [tex]P_{2}O_{5}[/tex] is actually its empirical formula, whereas [tex]P_{4}O_{10}[/tex] is its actual molecular formula.

However, the name of the chemical was obtained from its empirical formula rather than from its molecular formula. The official name for this substance is diphosphorus pentoxide.

Oxygen-containing binary compounds have "oxide" as their "last name." Phosphorus is the "first name."

We list each atom's numbers below:

The di- and Penta- prefixes are used to indicate the presence of two and five oxygen atoms, respectively, in the molecule.

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Answer:

diphosphorus pentoxide

Explanation:

The value of Gfor a reaction conducted at 25C is 2.8 KJ/mol. The equilibrium for a reaction is _____ at this temperature.

Answers

The equilibrium constant of the reaction is 0.323.

Equilibrium constant:

It is expressed as the ratio of concentration of the products to the concentration of reactants. It is represented by K.

The relationship of K with G (Gibbs free energy) is expressed as:

G° = -RTlnK

Here R is the gas constant, T is the temperature.

Calculations:

Convert 25°C to K.

25°C = (25 + 273.15) K

= 298.15 K

Substitute the values in the above expression.

2.8 x 1000 J/mol = -8.314 J/mol.K x 298.15 K x ln(K)

lnK = 2800 J/mol/(-8.314 J/mol.K x 298.15 K)

lnK = -1.13

K = e^-1.13

  = 0.323

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What is the freezing point, in °C, of
a 0.655 m solution of C4H10 in
benzene?
FP (benzene) = 5.5 °C
Kr(benzene) = 5.12°C/m
[?] °C
Give your answer to the thousandths place.
Freezing Point
Enter

Answers

The freezing point of the solution is - 2.15.

What is the freezing point?

The freezing point is the point at which a liquid is changed to solid. We can use the formula;

ΔT = K m I

ΔT = temperature change

K = freezing constant of benzene

m = molality

i = Van't Hoff factor

Now;

ΔT =  5.12°C/m * 0.655 m  * 1

ΔT = 3.35°C

ΔT = Freezing point of pure benzene - Freezing point of solution  

Freezing point of solution  = ΔT -  Freezing point of pure benzene

= 3.35°C -  5.5 °C = - 2.15

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Answer:

2.143 degrees celsius

Explanation:

Ascorbic acid (Vitamin C) is a diprotic acid, H₂C6H6O6. What is the pH of a 0.10 M
solution? What will be the concentration of C6H6O62-? Ka1 = 7.9 x 105 and Ka2 = 1.6 x 10-12

Answers

The pH of the solution is 1.52 and the concentration of C6H6O62- is 2.2 * 10^-7 M.

What is the concentration of  C6H6O62-?

We know that;

H₂C6H6O6 ⇔HC6H6O6^-(aq)    +   H^+(aq) ----- (1)

Ka1 = 7.9 x 10^-5

Again;

HC6H6O6^-(aq) ⇔ C6H6O6^2-(aq)  +   H^+(aq) ------- (2)

Ka2 = 1.6 x 10^-12

Given that Ka2 <<<< Ka1 we have to apply equation 1 to obtain H^+ hence;

Ka1 = [HC6H6O6^-] [H^+]/[H₂C6H6O6]

Let  [HC6H6O6^-] = [H^+] =x

7.9 x 10^5 =x^2/0.1 - x

But x <<< 0.1 thus;

7.9 x 10^5 =x^2/0.1

x = √7.9 x 10^-5  * 0.1

x = 0.03 M

pH = -log(0.03 M)

pH = 1.52

To obtain  C6H6O6^2-;

Ka2 = [ C6H6O6^2-] [ H^+]/[HC6H6O6^-]

Also;

[ C6H6O6^2-] = [ H^+]= x

Now;

1.6 x 10^-12 = x^2/0.03 -x

But x<<<0.3

Hence;

1.6 x 10^-12 = x^2/0.03

x = √1.6 x 10^-12 * 0.03

x = 2.2 * 10^-7 M

The concentration of C6H6O6^2- is  2.2 * 10^-7 M.

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A 0.261 g piece of solid magnesium reacts with gaseous oxygen from the atmosphere to form solid magnesium oxide. in the laboratory a student weighs the mass of the magnesium oxide collected from this reaction as 0.254 g. what is the percent yield ?

Answers

The percent yield of [tex]MgO[/tex] is 58.79%

According to the following balanced reaction, magnesium interacts with oxygen to generate magnesium oxide:

[tex]2Mg + O_2 \rightarrow 2MgO[/tex]

Given mass of solid magnesium = 0.261g

Molar mass of Mg = 24g/mol

Using formula , [tex]Number of moles =\dfrac {mass} {molar mass} = \dfrac {0.261g} {24g/mol} = 0.0108mole[/tex]

We could theoretically make 0.0108 moles of [tex]MgO[/tex] since the reaction yields an equimolar quantity of [tex]MgO[/tex]. It is clear from the above reaction that 2 moles of magnesium result in 2 moles of magnesium oxide.

Hence, mass of [tex]MgO[/tex] = Number of moles [tex]\times[/tex] Molar mass of MgO

mass of [tex]MgO[/tex]  = [tex]0.0108mole \times 40g/mole = 0.432g[/tex]

Percent yield =  [tex]\dfrac{Actual mass of MgO} {Theoretical mass of MgO} \times 100[/tex]

                       =  [tex]\dfrac{0.254} {0.432} \times 100 = 58.79percentage[/tex]

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An aqueous solution contains
32.7% KCI (weight/weight %).
What is the mole fraction of KCI in
this aqueous solution?
Molar Mass
KCI: 74.55 g/mol
H₂O: 18.016 g/mol
Enter text here
Enter

Answers

Answer:

0.105 KCl

Explanation:

(Step 1)

If the solution is 32.7% KCl, we can assume that there are 32.7 grams KCl in the solution. This means that there would be 67.3 grams H₂O (100% - 32.7% = 67.3%) in the solution.

32.7% KCl = 32.7 g KCl

67.3% H₂O = 67.3 g H₂O

(Step 2)

Now, we need to convert both the solute (KCl) and the solvent (H₂O) into moles. This can be done by multiply the grams of each substance by their molar masses.

32.7 g KCl              1 mole
------------------  x  --------------------  = 0.439 mole KCl
                               74.55 g

67.3 g H₂O           1 mole
------------------  x  -----------------  =  3.74 moles H₂O
                             18.016 g

(Step 3)

Finally, we can calculate the mole fraction of KCl using the following equation. The final answer should have 3 sig figs to match the given value with the lowest amount of sig figs (32.7 g).

                                             moles of solute
Mole Fraction  =  -----------------------------------------------------  
                              moles of solute + moles of solvent

                                            0.439 mole KCl
Mole Fraction  =  ------------------------------------------------------  
                              0.439 mole KCl + 3.74 moles H₂O

Mole Fraction  =  0.105 KCl

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