The probability that the manufacturing unit has carbon emissions beyond the permissible emission level is 0.2975
Given that the probability that carbon emissions from the company’s factory exceed the permissible level is 35% and the accuracy of the test is 85%.
The possibility of an event or outcome happening contingent on the occurrence of a prior event or outcome is known as conditional probability. The probability of the prior event is multiplied by the current likelihood of the subsequent, or conditional, occurrence to determine the conditional probability.
Event A: The given Carbon emission beyond to the given permissible emission level.
Event B: Test predicts this.
To get the probability of this problem, first we need to divide by 100 the given values.
A=35/100
A=0.35
The probability of event A is P(A)=0.35
And the probability is P(B|A)=85/100=0.85
Now, we will use the conditional probability formula, we get
P(B|A)=P(A∩B)/P(A)
0.85=P(A∩B)/0.35
P(A∩B)=0.85×0.35
P(A∩B)=0.2975
Hence, the probability that the manufacturing unit has carbon emissions beyond the permissible emission level and the test predicts is0.2975.
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In the following diagram, PQRS is a square of sides 21 cm. PTS and QTR are two semicircles touching each other at T.
Calculate the area, in cm², of the shaded region.
A 94.5 C 141.8 B 113.4 D 189.0 S
Answer:
[tex]94.6cm^{2}[/tex]
Step-by-step explanation:
First we will find the area of Square PQRS.
Area of Square PQRS = Length x Width = 21 x 21
= [tex]441cm^{2}[/tex]
Next we will found the Area of Semicircles PS and QR.
Note: Area of Semicircle PS = Area of Semicircle QR
Area of Semicircle = [tex]\frac{1}{2} \pi r^{2}[/tex]
Total Area of Semicircles PS and QR combined = [tex]2(\frac{1}{2} \pi r^{2} )\\=\pi r^{2}[/tex]
We know that the diameter of PS = QR = 21 cm (due to the length of the square)
Radius = Half of Diameter = 0.5 x 21cm = 10.5cm
Total Area of Semicircles PS and QR = [tex]\pi (10.5)^{2} \\=110.25\pi cm^{2}[/tex]
Finally,
Area of Shaded Region = Area of Rectangle PQRS - Total Area of Semicircles PS and QR
= [tex]441 - 110.25\pi\\= 94.6cm^{2} (1dp)[/tex]
In this case , you can choose the nearest answer as there might be some rounding differences.
What is the solution of √x+ 12 =
= x?
O x = -3
O x = 4
O x = -3 or x = 4
Ono solution
PLEASE HELP
Answer:
x₁ = 4
(x₂ = -3)
Step-by-step explanation:
√(x + 12) = x
x + 12 = x²
x² - x - 12 = 0
Δ = 49
x = (1 ±√Δ)/2
x₁ = 4
x₂ = -3
the right solution is 4 this can be seen by inserting the solutions found in the starting equation
five times Linda’s age is 85
The perimeter of a square field is 336 yards. How long is each side?
Question:
The perimeter of a square field is 336 yd. How long is each side?
Answer:
1,344 yd
what is something you do that can be set up as a two- step equation? how would you set that up as an equation to explain to someone else how it can be solved?
What you can do that can be set up as a two- step equation is to follow the form which is [tex]ax + b = c[/tex] and should be noted that a, b, c are real numbers.
Two- step equation can be solved by following these
Perform the Simplification by getting rid of all brackets and parenthesis. perform Addition or subtraction to isolate the variable.Simplify to determine the value of the variable.Perform verification through substituting of answers in the given equation.What is two- step equation?Two step equations serves as algebraic equations which can be solved in exactly two steps to get the final value of the variable .
Example of this is [tex]2x + 3 = 7.[/tex]
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A searchlight uses a parabolic mirror to cast a beam of light in parallel rays where the light bulb is located at the focus of the parabola in order to give the best illumination. The mirror is modeled by y^2=36(x-10), where the measurements are in cm. What is the location of the light bulb?
Answer:
the third option
Step-by-step explanation:
Our equation is
[tex] {y}^{2} = 36(x - 10)[/tex]
Equation of a vertical parabola is
[tex]( {y - k)}^{2} = 4p(x - h)[/tex]
where (h,k) is the center
The focus is
(h+p, k)
Equation of directrix is
x= h-p,
Here the center is (10,0)
Next, we factor out 4 in the original equation
[tex]4(9)[/tex]
So we have
[tex] {y}^{2} = 4(9)(x - 10)[/tex]
So our p=9,
So our focus is
(10+9,0) or (19,0)
The third option is the answer
The location of the light bulb is at point A. (10, 0).
Option A is the correct answer.
We have,
To find the location of the light bulb, we need to identify the coordinates (x, y) at which the light bulb is located.
In the given parabolic mirror equation, y² = 36(x - 10), the vertex form of the equation for a parabola with a vertical axis is (h, k), where h is the
x-coordinate of the vertex and k is the y-coordinate of the vertex.
Comparing the given equation with the standard form
(y - k)² = 4a(x - h),
we can see that h = 10 and k = 0.
So, the location of the light bulb is at the point (10, 0).
Therefore,
The location of the light bulb is at point A. (10, 0).
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A searchlight uses a parabolic mirror to cast a beam of light in parallel rays where the light bulb is located at the focus of the parabola in order to give the best illumination.
The mirror is modeled by y² = 36 (x-10), where the measurements are in cm.
What is the location of the light bulb?
A. (10, 0)
B. (14, 0)
C. (19, 0)
D. (36, 0)
Find the missing angles. will give brainliest if done correctly.
Answer:
x = 69 v = 103
Step-by-step explanation:
Angles in a triangle add up to 180 degrees:
34 + 77 + x = 180
x = 69
Angles on a straight line add up to 180:
77 + v = 180
v = 103
Answer:
x = 69°V = 103°Step-by-step explanation:
the sum of the interior angles in a triangles is 180°, take away from 180 the know angles (34° and 77°) and you will have your answer
180 - 34 - 77 = 69°
Now we find angle V
The angle V and the angle of 77 ° are on a straight line, so the sum is 180°, from 180° you subtract 77 ° and you have the value of V
180 - 77 = 103 °
What function does this graph represent? f(x) 6 -4 -2 = 6- 4 2- A -6 lo 2 OA. f(x) = -3(x - 2)² + 4 OB. f(x) 3(x + 2)² + 4 Oc. f(x) = 3(x - 2)² + 4 OD. f(x) = -3(x + 2)² + 4
This graph represents Option D = [tex]-3(x+2)^{2} + 4[/tex]
As the given figure is a parabola, it will have quadratic equation because the general equation of parabola corresponds to [tex]x^{2} = 4ay[/tex] which has highest power of the variable equals to 2, thus its a quadratic equation.
The maximum value of a quadratic equation [tex]ax^{2} + b x +c[/tex] is at points
[tex](-b/2a, c-\frac{b^{2} }{4a} )[/tex]
By looking at the graph we can observe the point at which the graph has achieved maxima is (-2,4).
∴ ([tex]-b/2a = -2[/tex] , [tex]c-\frac{b^{2} }{4a} = 4[/tex]
The coefficient of [tex]x^2[/tex] should be negative the graph opens downwards.
∴ Option B and C are eliminated.
On putting x = -2 only option D yields 4.
Thus this graph represents Option D = [tex]-3(x+2)^{2} + 4[/tex]
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pls step by step on how to do that
wth is that wdym ???
The actual half-life of amoxicillin is about 62 minutes. Recall that half-life is the amount of time it takes for a substance to decay to half of its original amount. How long after Haidar gives Aldi his last dose of medication will it take before the amount of medication in Aldi's bloodstream is effectively 0? Describe how you determined your solving method.
Using an exponential function, it would take 824 minutes before the amount of medication in Aldi's bloodstream is effectively 0.
How to determine the timeA decaying exponential function is given as;
[tex]A(t) = A(0)e^-kt[/tex]
Where A = initial value
k = decay constant
We have the half-life of amoxicillin as 62minutes, to determine k, we get
[tex]A(62) = 0. 5(0)[/tex]
[tex]A(62) = 0.5A(0)[/tex]
[tex]0. 5A(0) = A(0) e^{-62k}[/tex]
Solve the exponential function thus
[tex]e^{-62k} = 0. 5[/tex]
㏑ [tex]e^{-62k}[/tex] = ㏑ 0. 5
- 62k = ㏑ 0.5
Make k subject of formula
k = -㏑[tex]\frac{0. 5}{62}[/tex]
k = 0. 011179
The equation is given by
[tex]A(t) = A(0)e^-0.011179[/tex]
We have
[tex]0. 0001A(0) = A(0)e^-0.01179[/tex]
[tex]e^-0.011179t = 0. 0001[/tex]
㏑ [tex]e^-0.011179[/tex] = ㏑ 0.0001
[tex]-0.011179t = In 0.0001[/tex]
t = [tex]-\frac{In 0. 0001}{0. 011179}[/tex]
t = [tex]824[/tex]
Therefore, it would take 824 minutes before the amount of medication in Aldi's bloodstream is effectively 0.
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Jamie has a restaurant bill of $70.70. About how much money should she leave for a 10% tip?
$7.00
$0.70
$1.00
$7.70
Point O is the center of dilation. Triangle A B C is dilated to create triangle A prime B prime C prime. The length of O A is 3. The length of A A prime is 9.
Triangle ABC is dilated to create triangle A'B'C' using point O as the center of dilation.
What is the scale factor of the dilation?
One-third
3
4
One-fourth
The scale factor of the dilation shown in the image is: C. 4.
How to Find the Scale Factor of Dilation?Scale factor = New dimension/corresponding old dimension.
From the image given, we have:
Scale factor = OA'/OA
OA' = 3 + 9 = 12 units
OA = 3 units
Scale factor of dilation = 12 units/3 units
Scale factor of dilation = 4
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C. 4
Next one is 6 if you have the option on edge
PLEASE HELP!!!!!!!!!!!!I BEG YOU
Which quadratic equation does not have a real solution? (1 point)
3x2 − 6x + 3 = 0
−4x2 − 4x − 6 = 0
−x2 − 6x − 9 = 0
2x2 − 10x − 5 = 0
Since it has a negative discriminant, the quadratic equation that does not have a real solution is given by:
−4x2 − 4x − 6 = 0.
What is the discriminant of a quadratic equation and how does it influence the solutions?A quadratic equation is modeled by:
[tex]y = ax^2 + bx + c[/tex]
The discriminant is:
[tex]\Delta = b^2 - 4ac[/tex]
The solutions are as follows:
If [tex]\mathbf{\Delta > 0}[/tex], it has 2 rational solutions.If [tex]\mathbf{\Delta = 0}[/tex], it has 1 rational solutions.If [tex]\mathbf{\Delta < 0}[/tex], it has 0 real solutions.We want [tex]\Delta < 0[/tex], hence, for equation -4x² - 4x - 6, we have that a = -4, b = -4, c = -6, hence:
[tex]\Delta = (-4)^2 - 4(-4)(-6) = 16 - 96 = -80[/tex]
Negative discriminant, hence it does not have a real solution.
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Answer:
The answer above is correct. The answer was confirmed by a teacher, and was marked as correct on the test
Step-by-step explanation:
To collect data from a number of people in a sample, use alan
The ways to collect data in a sample include:
Use of questionnaire.Through observations.Through surveys.What is a sample?It should be noted that a sample simply means a subset of a population that has the characteristics of the entire population.
In this case, the ways to collect data in a sample include the use of questionnaire, through observations, and through surveys.
l
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PLEASE I NEED THIS
SO MANY POINTS
The speed of Sali is 18.75 km/hr.
Given,
Total distance travelled by Jane and Sali =63 km.
The total time is taken by Jane=3.5 hours.
Sali started to cycle 4 minutes after Jane started to cycle [tex]=\frac{4}{60}=\frac{1}{15}[/tex] hours.
What is the formula to find speed?The formula to find speed is [tex]Speed=\frac{Distance}{Time} \ km/hr[/tex].
The speed of Jane[tex]=\frac{63}{3.5}=18 \ km/hr[/tex].
Let the speed of Sali be [tex]x \ km/hr[/tex].
Sali caught up with Jane when they had both cycled 30 km.
Thus, [tex]\frac{30}{18}-\frac{30}{x}=\frac{1}{15}[/tex]
[tex]\implies \ \frac{30x-540}{18x} =\frac{1}{15}[/tex]
[tex]\implies \ 15(30x-540)=18x[/tex]
[tex]\implies \ 5(30x-540)=6x[/tex]
[tex]\implies \ 150x-2700=6x[/tex]
[tex]\implies \ 144x=2700\implies \ x=18.75[/tex]
Therefore, the speed of Sali is 18.75 km/hr.
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Please answer with everything needed i appreciate everyones help:))
Answer:
[tex]a = (h)(2h - 5)[/tex]
Answer:
Area of the rectangle = 2h² - 5
Step-by-step explanation:
• base length l = 5 less than twice the height h
= 2h - 5
• height = h
Area of rectangle = base × height
⇒ l × h
⇒ (2h - 5)(h)
⇒ 2h² - 5
X=
Help mea please thank u :)
The value of x is the length GH, which is determined as 6.
Value of xThe value of x is the length GH and can be calculated from Pythagoras theorem.
|OG|² = |OS|² + |SG|²
|OG|² = 9² + 12²
|OG|² = 225
|OG| = √225
|OG| = 15
x + H = |OG|
where;
H is radius of the circle = 9x + 9 = 15
x = 15 - 9
x = 6
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find f(-1) and find one value of x for which f(x)=0
[tex]f( - 1) = - 3[/tex]
[tex]f(x) = 0 \\ for \: x = 2 \: or \: x = - 2[/tex]
Select the correct graph of −x − 2y = 6.
Answer:
x = -6-2y
Step-by-step explanation:
According to a report in USA Today, more and more parents are helping their young adult children get homes. Suppose eight persons in a random sample of 60 young adults who recently purchased a home in Kentucky received help from their parents. You have been asked to construct a 95% confidence interval for the population proportion of all young adults in Kentucky who received help from their parents. What is the margin of error for a 95% confidence interval for the population proportion
The margin of error for a 95% confidence interval for the population proportion is 0.0815.
Given sample size=60 and confidence interval of 95%.
We have to calculate margin of error for a confidence interval of 95%.
Margin of error is the difference between actual values and calculated values. Margin of error is a part of z test.
We have been given sample size=60.
8 people have received help from their parents from the sample.
p=8/60=0.13
which is sample proportion.
z=1-0.13
=0.87
To calculate standard error=[tex]\sqrt{p*z/n}[/tex]
=[tex]\sqrt{0.13*0.8/60}[/tex]
=0.0416
at 95% confidence interval
z(α/2)=1.96
therefore margin of error=1.96*0.0416
=0.081536
=0.0815
Hence the margin of error for 95% confidence interval is 0.0815
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(2, -7) and (4, -13)
Answer:
-14 or (6,20)
How many liters are in 21 cups
Answer:
4.968
Step-by-step explanation:
bc yes
Jackson has a gift card for $120 to use at a department store. he wants to purchase 2 shirts and 3 pairs of pants with his gift card. if x represents the cost of the shirts and y represents the cost of the pants, what are the domain and range of this relationship?
0 ≤ x ≤ 60
The range of this relationship can be defined as,0 ≤ y ≤ 40
Definition of Domain and Range
The set of all the possible input values for which the provided function is defined is termed as the domain of that function.
The set of all the possible values that a given function can generate as an output is termed as the range of that function.
Forming the Relation
It is given that,
Jackson wants to purchase 2 shirts and 3 pairs of pants with his gift cardx represents the cost of the shirts and y represents the cost of the pantsThe limit of the gift card = $120Thus, the relation formed is given by,
[tex]2x + 3y \leq 120[/tex]
Domain and Range of the Given Relation
We have,
[tex]2x + 3y \leq 120[/tex]
⇒ [tex]2x \leq 120[/tex]
⇒ [tex]x\leq60[/tex]
Thus, the domain is given by,
⇒ [tex]0\leq x\leq 60[/tex]
Similarly,
[tex]3y\leq 120[/tex]
⇒ [tex]y\leq 40[/tex]
Thus, the range is given by,
⇒ [tex]0\leq y\leq 40[/tex]
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Using the unique pythagorean triple 5 12 13 as a guide, what is the missing number from the triple x, 48, 52?
The missing number from the triplet x, 48, 52, using the triplet 5, 12, 13, is found to be 5.
The Pythagoras Theorem states that in a right triangle, the square of the hypotenuse is always equal to the sum of the squares of the other two legs.
If the hypotenuse is taken as a, and the two legs are taken as b and c, then by the Pythagoras Theorem, we can write that:
a² = b² + c².
A Pythagoras triplet, is the combination of c, b, and a.
If all three sides of a right triangle are multiplied by the same quantity, we get another right triangle, where the sides of both make Pythagoras Triplet.
In the question, we are given a unique triplet: 5,12, 13, and are asked to find x in x, 48, 52.
We divide the second triplet by the first one, to get:
x/5, 48/12, 52/13,
or, x/5, 4, 4.
The ratio of the two triplets will always be a constant, thus
x/5 = 4,
or, x = 5*4 = 20.
Thus, the missing number from the triplet x, 48, 52, using the triplet 5, 12, 13, is found to be 5.
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Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!
Question 4
1) [tex]\overline{BD}[/tex] bisects [tex]\angle ABC[/tex], [tex]\overline{EF} \perp \overline{AB}[/tex], and [tex]\overline{EG} \perp \overline{BC}[/tex] (given)
2) [tex]\angle FBE \cong \angle GBE[/tex] (an angle bisector splits an angle into two congruent parts)
3) [tex]\angle BFE[/tex] and [tex]\angle BGE[/tex] are right angles (perpendicular lines form right angles)
4) [tex]\triangle BFE[/tex] and [tex]\triangle BGE[/tex] are right triangles (a triangle with a right angle is a right triangle)
5) [tex]\overline{BE} \cong \overline{BE}[/tex] (reflexive property)
6) [tex]\triangle BFE \cong \triangle BGE[/tex] (HA)
Question 5
1) [tex]\angle AXO[/tex] and [tex]\angle BYO[/tex] are right angles, [tex]\angle A \cong \angle B[/tex], [tex]O[/tex] is the midpoint of [tex]\overline{AB}[/tex] (given)
2) [tex]\triangle AXO[/tex] and [tex]\triangle BYO[/tex] are right triangles (a triangle with a right angle is a right triangle)
3) [tex]\overline{AO} \cong \overline{OB}[/tex] (a midpoint splits a segment into two congruent parts)
4) [tex]\triangle AXO \cong \triangle BYO[/tex] (HA)
5) [tex]\overline{OX} \cong \overline{OY}[/tex] (CPCTC)
Question 6
1) [tex]\angle B[/tex] and [tex]\angle D[/tex] are right angles, [tex]\overline{AC}[/tex] bisects [tex]\angle BAD[/tex] (given)
2) [tex]\overline{AC} \cong \overline{AC}[/tex] (reflexive property)
3) [tex]\angle BAC \cong \angle CAD[/tex] (an angle bisector splits an angle into two congruent parts)
4) [tex]\triangle BAC[/tex] and [tex]\triangle CAD[/tex] are right triangles (a triangle with a right angle is a right triangle)
5) [tex]\triangle BAC \cong \triangle DCA[/tex] (HA)
6) [tex]\angle BCA \cong \angle DCA[/tex] (CPCTC)
7) [tex]\overline{CA}[/tex] bisects [tex]\angle ACD[/tex] (if a segment splits an angle into two congruent parts, it is an angle bisector)
Question 7
1) [tex]\angle B[/tex] and [tex]\angle C[/tex] are right angles, [tex]\angle 4 \cong \angle 1[/tex] (given)
2) [tex]\triangle BAD[/tex] and [tex]\triangle CAD[/tex] are right triangles (definition of a right triangle)
3) [tex]\angle 1 \cong \angle 3[/tex] (vertical angles are congruent)
4) [tex]\angle 4 \cong \angle 3[/tex] (transitive property of congruence)
5) [tex]\overline{AD} \cong \overline{AD}[/tex] (reflexive property)
6) [tex]\therefore \triangle BAD \cong \triangle CAD[/tex] (HA theorem)
7) [tex]\angle BDA \cong \angle CDA[/tex] (CPCTC)
8) [tex]\therefore \vec{DA}[/tex] bisects [tex]\angle BDC[/tex] (definition of bisector of an angle)
A test started at 10:55. the teacher collected the answer scripts 1 hour and 15 minutes later . At what time did she collect them?
Answer:
10+1=11 but the 55 so it is now 11:55+15min so it makes it 12:10
Answer:
Hello! The answer to your question is 12:10.
Step-by-step explanation:
1 hour after 10:55 is equivalent to 11:55. Now, we have 15 minutes remaining. We can add in increments of 5 to get to 15 in terms of time:
11:55 + 5 minutes
= 12:00 + 5 minutes
= 12:05 + 5 minutes
= 12:10
5 + 5 + 5 = 15, so we reached 15.
The teacher collected the answer scripts at 12:10.
20 points!!
Show that for any real numbers a and b, and any integers x and y so that x≠0, y≠0, x≠y, and x≠-y,
(y/x-x/y)((ax+by)/(x+y)-(ax-by)/(x-y))=2(a-b).
See below for the proof of the equation [tex]\frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b)[/tex]
How to prove the equation?The equation is given as:
[tex]\frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b)[/tex]
Take the LCM
[tex]\frac{(ax + by)(x - y) -(ax - by)(x + y)}{(x + y)(x - y)}= 2(a - b)[/tex]
Expand
[tex]\frac{ax^2 - axy + bxy - by^2 -ax^2 - axy + bxy + by^2}{(x + y)(x - y)}= 2(a - b)[/tex]
Evaluate the like terms
[tex]\frac{-2axy + 2bxy }{(x + y)(x - y)}= 2(a - b)[/tex]
Rewrite as:
[tex]\frac{-2axy + 2bxy }{x^2 - y^2}= 2(a - b)[/tex]
Factorize the numerator
[tex]\frac{2(a - b)(x^2 - y^2)}{x^2 - y^2}= 2(a - b)[/tex]
Divide
2(a - b)= 2(a - b)
Both sides are equal
Hence, the equation [tex]\frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b)[/tex] has been proved
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PROBLABILITY!!!
(I added the picture needed)
1.Create a sample space and find the product of each combination. What is the probability that a person wins the game? Express your answer as a fraction in lowest terms and as a percent rounded to the nearest tenth.
(answer to this one is 9/28 and 32.1%)
2. You realize a short time into the carnival that you don’t have enough prizes to last the entire event. You call your teacher, and she suggests that you change the winning number so that a participant will win only 25% of the time. What number will that be? Support your answer.
3. Participants achieving a winning score of 36 or higher in four consecutive attempts will receive a large prize! What is the probability of this occurring?
4. After changing the game rules, participants and the crowd are disappointed when the first five games yield scores of 12, 18, 30, 28, and 24. What statement can you recommend the teacher posts to reassure everyone that the game is fair?
The probability that a person wins the game is 32.1%
How to illustrate the probability?Based on the information given, the following can be depicted. It should be noted that there are 6 sides as well as 4 cards.
Therefore, the numbers on the dice i.e from 1 - 6 will be represented 4 times each. This gives a total of (4 × 6) = 24. There are also 4 cards. The total in sample space will now be:
= 24 + 4 = 28
The frequency table will be such that 28 or more has a relative frequency of 9. Therefore, the probability that a person wins the game will be:
= 9/28 = 32.1%
When you win 25% of the time, this illustrates that the number of products picked will be:
= 25% × 28
= 7 products.
The probability of participants achieving a winning score of 36 or higher in four consecutive attempts will be:
= 1/6⁴
= 1/1296
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The Surface Area of a square pyramid is 3600 ft2. The slant height is 80 feet and the base is 20 feet. At most how many 1 foot cubic blocks can be stuffed in the pyramid?
(*Some of the blocks might have to be cut up to fit into crevices*)
The number of 1 foot cubic blocks that can be stuffed in the pyramid are; 10,583 cubes
How to find the surface area of a Pyramid?The equation for the surface area of a square pyramid is;
Surface area = A + 1/2·p·s
where;
A = area of base
p = perimeter
s = slant height
The volume of the pyramid = (1/3) × A × h
Where:
A = Area of the base = 20 × 20 = 400 ft²
h = The height of the pyramid = √((slant height)² - ((base side length)/2)²)
h = √(80² - (20/2)²) = 30√7
The volume of the pyramid = 1/3*400*30·√7 = 4000·√7 ft³ = 10,583.005 ft³
If the cubes are flexible, then there are approximately 10,583 cubes
For rigid cubes we have;
Given that the height of the pyramid = 30·√7
The slope of the pyramid = (30/10)√7 = 3·√7
A increase in height of 1 foot gives a reduction in width of 2/(3√7)
The bottom can hold 400 cubes, Then next layer can hold;
19 × 19 = 361
If we continue to iterate, we will get a total of approximately 9915 rigid cubes in the pyramid.
Read more about Pyramid Surface Area at; https://brainly.com/question/22744289
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