A drugstore sells vitamins in bottles with different pill counts. The price of each bottle is shown in the table below.

The equation in slope-intercept form of the line containing the points (3,-1) and (6, 7) is; y = ⁸/₃x - 7

We are given the coordinates of two points as;

(3,-1) and (6, 7).

Now, the formula for the equation of the line containing the two points in slope intercept form is;

(y - y1)/(x - x1) = (y2 - y1)/(x2 - x1)

Thus, we have;

(y + 1)/(x - 3) = (7 + 1)/(6 - 3)

(y + 1)/(x - 3) = = 8/3

y + 1 = (8/3)(x - 3)

y + 1 = ⁸/₃x - 8

y = ⁸/₃x - 7

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The measure of angles 1, 2, 4, and 5 are 54 degrees, 90 degrees, 36 degrees, and angle 36 degrees.

A rhombus is a two-dimensional shape having four parallel opposite pairs of straight, equal sides. This shape resembles a diamond and is what you'd find on a deck of cards to represent the diamond suit. Rhombuses can be encountered in a variety of common situations.

We have shown the rhombus in the picture.

As we know the diagonals bisect at a 90-degree angle.

So angle 2 = 90 degree

angle 1 = angle 3

angle 1 = 54 degrees

angle 1 + angle 2 + angle 5 = 180

54 + 90 + angle 5 = 180

angle 5 = 36 degrees

angle 5 = angle 4 = 36 degrees

Thus, the measure of angles 1, 2, 4, and 5 are 54 degrees, 90 degrees, 36 degrees, and angle 36 degrees.

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The proportional graph that corresponds to M = 3n is: Graph C.

The constant of proportionality, k, of a proportional graph is given as, y/x. The graph is expressed by the equation, y = kx.

The equation given, M = 3n, represents a proportional relationship where k = 3.

Using a point on graph C, (400, 1,200):

k = 1,200/400

k = 3

Therefore, the graph that corresponds to the situation is: C.

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Answer:

c and d, because they both have 2 squares

If f(x) is an odd function, the greatest number of points that can lie in Quadrant II is 1

The given parameters are:

Function f(x) = Odd function

Points in quadrant IV

The number of points in the upper quadrants is:

Upper = 14/2

This gives

Upper = 7

The upper quadrants are I and II

This means that:

I + II = 7

So, we have:

6 + II = 7

Subtract 6 from both sides

II  = 1

Hence, the greatest number of points that can lie in Quadrant II is 1

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The equation which best models the data in the scatterplot is: D. y = -16743x² + 19.76x + 745.73.

By critically observing the scatter plot shown in the image attached below, we can logically deduce that it's data are best modelled by a quadratic equation (parabolic curve).

Mathematically, the equation of a quadratic equation (parabolic curve) is given by:

y = ax² + bx + c

Since the parabolic curve opens downward, we have:

a < 0, c > 0, x = 0 and y > 0;

y = -16743x² + 19.76x + 745.73.

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Because the cosine and sine must be negative when evaluated in theta, the angle lies on the third quadrant.

We know that if:

Here we know that:

sec(θ) < 0

And we know that:

sec(θ)  = 1/cos(θ)

Then we have cos(θ) < 0

We also have that:

sec(θ)*csc(θ) > 0

Because sec(θ) < 0, we must have that csc(θ) < 0.

Remember: csc(θ) = 1/sen(θ)

Then sen(θ) < 0.

Then we have the two conditions:

sen(θ) < 0

cos(θ) < 0

The only quadrant where both are negative is the third quadrant, so that is the correct option.

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The attached figure represents the image of the triangle under the rotation

The coordinates of the triangle are given as:

P = (2, 1)

Q = (4, 1)

R = (4, -3)

The rule of 90 degrees rotation about the origin is:

(x, y) = (y, -x).

So, we have:

P' = (1, -2)

Q' = (1, -4)

R' = (-3, -4)

See attachment for the figure under the rotation

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Answer:

I believe the answer is C

Step-by-step explanation:

Hope this helps!!!

The Triangle inequality theorem of a triangle says that the sum of any of the two sides of a triangle is always greater than the third side. The length of QS can lie between 3 < QS < 13.

The Triangle inequality theorem of a triangle says that the sum of any of the two sides of a triangle is always greater than the third side.

Suppose a, b and c are the three sides of a triangle. Thus according to this theorem,

As per the given law of triangle inequality, the sum of the two sides of the triangle is greater than the third side.

x + 8 > 5

x > -3

x + 5 > 8

x > 3

8 + 5 > x

13 > x

Hence, the length of QS can lie between 3 < QS < 13.

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Because the lines drawn are straight.

Explanation:

When the straight lines join together, the original point from where the first line started, becomes a right angle (90°)

The material needed to make the hat is 3840 cm³.

The hat occupies the whole volume of the rectangular box. Therefore, the material needed to make the hat is the volume of the rectangular box it occupies.

Therefore,

volume of a rectangular prism = lwh

where

Therefore,

l = 16 cm

w = 16 cm

h = 15 cm

volume of a rectangular prism = 16 × 15 × 16

volume of a rectangular prism = 3840 cm³

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Answer:

m = 2

Step-by-step explanation:

m - 2 = 2 - m

2m = 4

m = 2

Hello,

Answer: m = 2

Step-by-step explanation:

       m - 2 = 2 - m

⇔ m - 2 + m = 2 - m + m

⇔ 2m - 2 = 2

⇔ 2m - 2 + 2 = 2 + 2

⇔ 2m = 4

⇔ 2m/2 = 4/2

⇔ m = 2

Answer:

[tex]3x^{2} -2x+3x-3[/tex]

Step-by-step explanation:

This is one of the easier things to do so definitely learn how to do it.

You just start by taking the first number in each parenthesis (F) and then multiply. 2x by x is 3x^2

Then take the outer (O) number from both problems, so the leftmost and rightmost number. 2x times -1 is -2x

Then take the two inner (I) numbers, 3 and x. Multiply and get 3x

Then take the last number in each parentheses (L) which is 3 and -1, get -3

Answer:

a) 7

b) -1

c) 9

Step-by-step explanation:

a) Substitute -1 into the x's of the function.

f(-1) = -5(-1) + 2

f(-1) = 5 + 2

f(-1) = 7

b) f^-1(7) means: find the inverse of the function with 7 substituted as x.

Let y = f(x)

y = -5x + 2

5x = 2 - y

x = 2 - y / 5

f^-1(x) = 2 - x / 5

f^-1(7) = 2 - 7 / 5

f^-1(7) = -5/5

f^-1(7) = -1

c) We have already found the inverse of the- original function. Substitute -43 into the x's of the inverse function.

f^-1(-43) = 2 - (-43) / 5

f^-1(-43) = 2 + 43 / 5

f^-1(-43) = 45/5

f^-1(-43) = 9

Answer:

4 units to the left and 2 units up.

Step-by-step explanation:

Suppose Z has a standard normal distribution with a mean of 0 and a standard deviation of 1. 27% of the possible Z values are smaller than  0.613.

The standard normal distribution, also known as the z-distribution, is a special normal distribution with a mean of 0 and a standard deviation of 1. The normal distribution can be standardized by converting its value to a z-score. The Z-score indicates how many standard deviations each value has from the mean.

The standard normal distribution (z distribution) is a normal distribution with a mean of 0 and a standard deviation of 1. Each point (x) of the normal distribution can be converted to the standard normal distribution (z) using the equation z = (x-mean) / standard deviation.

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See below for the solution to the inverse function and the rational equation

Create functions f(x) and g(x)

The functions are given as:

f(x) = x + a/b

g(x) = cx − d

Let a = 4 and b = 2.

So, we have:

f(x) = x + 4/2

Rewrite as:

y = x + 2

Swap x and y

x = y + 2

Make y the subject

y = x - 2

So, we have:

g(x) = x - 2

So, the functions are:

f(x) = x + a/b ⇒ f(x) = x + 4/2

g(x) = cx − d ⇒ g(x) = x - 2

Show that the functions are inverse functions

In (a), we have:

f(x) = x + 4/2

g(x)= x - 2

If the functions are inverse functions, then:

f(g(x)) = x

We have:

f(x) = x + 4/2

This gives

f(g(x)) = g(x) + 4/2

This gives

f(g(x)) = x - 2 + 4/2

Evaluate

f(g(x)) = x

Evaluate g(f(x))

In (a), we have:

f(x) = x + 4/2

g(x)= x - 2

We have:

g(x)= x - 2

This gives

g(f(x)) = f(x) - 2

This gives

g(f(x)) = x + 4/2 - 2

Evaluate

g(f(x)) = x

Graph the functions

See attachment for the graph

The table of values is:

x    f(x)    g(x)

0    2     -2

1     3      -1

2    4       0

3    5      1

4    6      2

Create the equations

The form of the equations is given as:

[tex]a\sqrt{x + b} + c= d[/tex]

So, we have:

[tex]\sqrt{4x + 5} + 1 = 0[/tex] --- has extraneous solution

[tex]2\sqrt{3x - 1} + 2 = 8[/tex] --- has no extraneous solution

The equation solution

Equation 1 with extraneous solution

[tex]\sqrt{4x + 5} + 1 = 0[/tex]

Subtract 1 from both sides

[tex]\sqrt{4x + 5} = -1[/tex]

Square both sides

4x + 5 = 1

Evaluate the like terms

4x = -4

Divide by 4

x = -1

Substitute x = -1 in [tex]\sqrt{4x + 5} + 1 = 0[/tex] to check

[tex]\sqrt{4(-1) + 5} + 1 = 0[/tex]

[tex]\sqrt{-4 + 5} + 1 = 0[/tex]

[tex]\sqrt{1} + 1 = 0[/tex]

Evaluate the root

[tex]1 + 1 = 0[/tex]

[tex]2= 0[/tex] --- false

Equation 2 without extraneous solution

[tex]2\sqrt{3x - 1} + 2 = 8[/tex]

Subtract 2 from both sides

[tex]2\sqrt{3x - 1} = 6[/tex]

Divide by 2

[tex]\sqrt{3x - 1} = 3[/tex]

Square both sides

3x - 1 = 9

Evaluate the like terms

3x = 10

Divide by 3

x = 10/3

Substitute x = x = 10/3 in [tex]2\sqrt{3x - 1} + 2 = 8[/tex] to check

[tex]2\sqrt{3 * \frac{10}{3} - 1} + 2 = 8[/tex]

[tex]2\sqrt{10 - 1} + 2 = 8[/tex]

[tex]2\sqrt{9} + 2 = 8[/tex]

Evaluate the root

[tex]2*3 + 2 = 8[/tex]

[tex]8 = 8[/tex] --- true

Why the equations have (or do not have) an extraneous solution

The first equation has an extraneous solution because the solution is false for the original equation and the second does not have an extraneous solution because the solution is true for the original equation

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The probability that the train will be there when Alex arrives is 5/18

If Alex arrives at any time after 1.20pm the chances that train will  be there is 1/3.

However  if alex arrives at 1.00pm exactly there is no chance the train will be arrive there.

The probability that the train will be there increase linearly to 1/3 as alex's arrival time moves from 1.00pm to 1.20pm.

By arranging the probabilities over the first 20 minutes to get a 1/6 chance the train will be there if alex arrives between 1.00pm to 1.20pm

we get the final answer by

=1/3( 1/6 + 1/3 + 1/3)

=5/18

So, the probability that the train will be there when Alex arrives is 5/18

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The domain is (-2, 3) and the range is (-3, 4]

The domain

This is the possible x values

From the graph, we have the following highlights:

The endpoints at these intervals is a open circle

Hence, the domain is (-2, 3)

The range

This is the possible y values

From the graph, we have the following highlights:

The endpoint at the minimum is a open circle, while the maximum is a closed circle

Hence, the range is (-3, 4]

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The proportion of defective corks produced by this machine through z test comes out is 0.320.

Given mean of 2 cm and standard deviation of 0.1 cm, The diameter is between 1.9 and 2.1 cm.

We have to find the proportion of defective corks that are produced by machine.

In this problem we have to first find z score and then we will be able to find the probability of defective corks produced by the machine.

Z=(X-μ)/σ

μ=2 cm and σ=0.1 cm.

Z value corresponding to X=1.9.

Z=(1.9-2)/0.1

=-0.1/0.1

=-1

Z value corresponding to X=2.1.

Z=(2.1-2)/0.1

=0.1/0.1

=1

P value of P(-1<Z<1)=2*0.3410=0.6820

Proportion of corks which are not defective=0.6820.

Proportion of corks which are defective=1-0.680.

=0.320

Hence the proportion of defective corks produced by machine is 0.320.

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Answer:

4230.14

Step-by-step explanation:

2040/1700=1.2

2448x1.2=2937.6

2937.6x1.2=3525.12

3525.12x1.2=4230.144

round to the nearest hundredth

4230.14

brainliest please

Answer:

See below.

Step-by-step explanation:

Sides: 15, 36, 41

True: 15 + 36 greater-than 41, so the side lengths will form a triangle.

True: 15 squared + 36 squared = 1,521

True: 41 squared = 1,681

True: Since a squared + b squared not-equals c squared, it will not be a right triangle.

Answer:

A) 15 + 36 greater-than 41, so the side lengths will form a triangle.

C) 15 squared + 36 squared = 1,521

D) 41 squared = 1,681

E) Since a squared + b squared not-equals c squared, it will not be a right triangle.

Proof:

If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500

Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.

We have to find the probability of observing at least one car during any 5 minute time interval.

Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.

Probability during 20 minutes interval=609/625

Probability during 1 minute interval=609/625*20

=609/12500

Probability during 5 minute interval=(609/12500)*5

=609/2500

Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.

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Answer:

D

Step-by-step explanation:

As you can observe from the pattern, the numerator gets multiplied by 4 every increase in the sequence.

So , clearly, the 5th term will be = [tex]\frac{64*4}{5} =\frac{256}{5}[/tex]

and the 6th term will be = [tex]\frac{256*4}{5} =\frac{1024}{5}[/tex]

Therefore , D will be the answer.

Answer:

319

Step-by-step explanation:

i am really not sure but i believe so i hope it is the right answer

Answer:

1600 people

Step-by-step explanation:

This is a ratio problem. We can set up the proportion by letting x be the number of people who applied for admission:

[tex]\frac{4}{10}=\frac{640}{x}[/tex]

Since we know that 4 people get in for every 10 people that apply, we can set up an equation like the one above and solve for x by cross multiplying:

[tex]6400=4x\\x=1600[/tex]

This means that 1600 people applied for admission to the vocational school.

Answer: e= x + y = 10

Step-by-step explanation :
check out the attachment for the answer

We got the value of [tex]e=\frac{78}{7}[/tex] by solving the given equations [tex]3x+2y=26[/tex] and [tex]5x+y=26[/tex] by reduction method.

The reduction or elimination approach includes using arithmetic operations between equations to produce equivalent equations with fewer unknowns that are simpler to analyze and evaluate.

Given equations are

[tex]3x+2y=26[/tex] .........(1)

[tex]5x+y=26[/tex] ...........(2)

We need to find the value of [tex]e=x+y[/tex]

Simplifying the given equation (2) and we get

[tex]5x+y=26\\\Rightarrow y=26-5x[/tex]................(3)

Now, substitute the equation (3) in equation (1) and we get

[tex]3x+2(26-5x)=26\\\Rightarrow 3x+52-10x=26\\\Rightarrow -7x+52=26\\\Rightarrow -7x=26-52\\\Rightarrow -7x=-26\\\Rightarrow x=\frac{26}{7}[/tex]

Substitute the value of x in equation (3), we get

[tex]y=26-5\frac{26}{7} \\\Rightarrow y=26-\frac{110}{7}\\\Rightarrow y=\frac{162-110}{7}\\\Rightarrow y=\frac{52}{7}\\[/tex]

Now adding the values of x and y, we get

[tex]\therefore e=\frac{26}{7}+\frac{52}{7}\\\Rightarrow e=-{[\frac{26+52}{7}]\\\Rightarrow e={[\frac{78}{7}][/tex]

Therefore, the value of [tex]e=\frac{78}{7}[/tex].

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