A chemist prepares a standard solution in the lab using a 500.0 mL volumetric flask. 4.865 g of NaCl is used. What is the molarity of the NaCl solution?

Answer:

2.35 atm

Explanation:

According to the Ideal Gas Equation,

Here :

Solving :

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[tex]\large \sf\underline{Question:}[/tex]

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[tex]\large \sf\underline{Answer:}[/tex]

[tex] \qquad \qquad \huge \bold{Option \: B}[/tex]

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[tex]\large \sf\underline{Explanation:}[/tex]

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Answer:

5.09 moles of Fe is required to react with 3.82 moles of O₂.

0.326 moles of O₂ are needed to produce 34.7 grams of Fe₂O₃.

Reaction stoichiometry

In first place, the balanced reaction is:

4 Fe + 3 O₂ → 2 Fe₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Fe: 4 moles

O₂: 3 moles

Fe₂O₃: 2 moles

The molar mass of the compounds is:

Fe: 55.85 g/mole

O₂: 32 g/mole

Fe₂O₃: 159.7 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Fe: 4 moles ×55.85 g/mole= 223.4 grams

O₂: 3 moles ×32 g/mole= 96 grams

Fe₂O₃: 2 moles ×159.7 g/mole= 319.3 grams

Moles of Fe needed

The following rule of three can be applied: If by stoichiometry of the reaction 3 moles of O₂ react with 4 moles of Fe, 3.82 moles of O₂ react with how many moles of Fe?

moles of Fe= 5.09 moles

Finally, 5.09 moles of Fe is required to react with 3.82 moles of O₂.

Moles of O₂ needed

The following rules of three can be applied: If by reaction stoichiometry 319.3 grams of Fe₂O₃ are formed from 3 moles of O₂, 34.7 grams of Fe₂O₃ are formed from how many moles of O₂?

moles of O₂= 0.326 moles

Finally, 0.326 moles of O₂ are needed to produce 34.7 grams of Fe₂O₃.

Explanation:

Answer:

do u like fishing

Explanation:

because i do

Answer:

23.2 C

Explanation:

By looking at the dimension of specific heat ( J/g-C) , you can compute these type of questions:

 149.4 J  / ( .129 J / g-C   * 50 g) = 23.2 C  

           (see how dimensions g and J cancel out and you are left with C ? )

Answer:1950-200

Explanation:

During 1950-2000​ of the following 50-year intervals has the world's population increased the most. Hence, option D is correct.

The whole number of people or inhabitants in a country or region.

The world's population increased from 2.5 billion in 1950 to around 7.3 billion in 2015 and is expected to continue to rise until 2050/2100 under most UN.

During 1950-2000​ of the following 50-year intervals has the world's population increased the most. Hence, option D is correct.

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Answer:

14.61 g NaCl

Explanation:

Molarity = moles / volume of solution (litres)

0.500 = moles / 0.500 L

moles = 0.25

Molar mass of NaCl is 58.44 g NaCl /1 mol NaCl.

0.25 moles NaCl x 58.44 g NaCl /1 mol NaCl

= 14.61 g NaCl

At STP one mol weighs 22.4L

Moles of O_2

1 mol.O_2 can create 2mol water

moles of water

Volume of water

Answer:

The given equation is:

N2H4(l) + O2(g) → N2(g) + 2H2O(g)

From the periodic table:

Therefore:

molar mass of N2H4 = 2(14) + 4(1) = 32 grams

mass of water = 2(1) + 16 = 18 grams

From the balanced equation:

1 moles of N2H4 produces 2 moles of H2O.

32 grams of N2H4 produce 18*2=36 grams of water

To know the mass of N2H4 needed to produce 96 grams of water, all you need to do is cross multiplication as follows:

They have no definite shape and no definite volume because they are gases.

Gases have no definite shape and no definite volume because they are present in free state. Those substances that are close together and held tightly have definite shape and volume.

So we can conclude that they have no definite shape and no definite volume because they are gases.

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Moles of oxygen

2 mol reactants required for 3mol O_2

So our answer is 2

The energy comes from the sun, captured through photosynthesis.

Answer:

B. Spectator ions

Explanation:

Spectator ions are described as spectators literally because they "spectate", or, in other words, do not participate in the overall reaction. They may show up in the reaction equation, but they don't react themselves.

Thus, spectator ions stay unchanged throughout a reaction. We see many spectator ions in precipitation reactions. Remember that ionic compounds disassociate in solution.

For example, the reaction between silver nitrate [tex]AgNO_{3}[/tex] and sodium chloride [tex]NaCl[/tex] produces a solid precipitate of silver chloride [tex]AgCl[/tex] as represented by the equation below:

[tex]Ag^+_{(aq)} + NO^-_{3(aq)}+Na^+_{(aq)}+Cl^-_{(aq)}[/tex] -------> [tex]AgCl_{(s)}+Na^+_{(aq)}+NO_{3(aq)}^-[/tex]

However, the sodium and nitrate ions remained aqueous, like before, so they did not react. Thus, they are spectator ions.

Answer:

I think the answer might be yes..

Answer:

Factories because they have helped with producing goods faster but in the meanwhile, our future will slowly get warmer.

Explanation:

According to the research, levers are used to modify or generate a force and transmit displacement.

It is a simple machine composed of a rigid bar of some moderately resistant material, which rotates freely on a support point.

It can be used to maximize the mechanical force applied to an object, increasing its speed or the distance it travels, by applying a proportionally smaller amount of force.

Therefore, we can conclude that according to the research, levers are used to modify or generate a force and transmit displacement.

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Density is the ratio of mass and volume. The temperature in kelvin is 296 kelvin and the density of the block is 2.78 x 10⁻⁵ g/cm³. Thus, option D is correct.

Density is the gms of the substance present in a cubic centimeter of volume. It is calculated in g/ cm³.

Given,

Mass of the block = 150.0 mg

Volume = 5382 cm³

Density is calculated as:

D = Mass ÷ volume

= 0.15 gm ÷ 5382 cm³

= 2.78 × 10⁻⁵ gm/ cm³

Temperature from Celsius to kelvin is converted as:

0°C + 273.15 = 273.15K

22.5 + 273.15 = 295.65 Kelvin

Therefore, option D. 296⁰K; 2.78 x 10⁻⁵ g/cm³ is correct.

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Answer:

Diamond.

Graphite.

Fullerene

Explanation:

these are three crystalline forms of carbon.

Answer:

= 1.35M

Explanation:

data:

volume = 437ml

               = 437 /1000

                 = 0.437dm^3

no. of moles = 0.590 moles

solution:

        molarity = [tex]\frac{no. of moles}{volume in dm^3}[/tex]

                       = 0.590 / 0.437

        molarity = 1.35M

The number of moles in 72 gram H₂O is 3.942 MOL.

The mole is a SI unit of measurement that is used to calculate the quantity of any substance.

First, know the molar mass of water.

The given mass is 71 gram

[tex]\rm Number\;of \;moles= \dfrac{mass}{molar\;mass}\\\\\rm Number\;of \;moles= \dfrac{71}{18.01}= 3.942 mol[/tex]

Thus, the number of moles in 72 gram H₂O is 3.942 MOL.

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Answer:

It contains 6.02*10^23 molecules

Explanation:

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Answer:

5.4 moles CaO   1 mole CaCl₂   5.4 mole CaCl₂

                           1 mole CaO

Explanation:

The detection time when an industrial process wastewater contains a mixture of metal fragments and sand is 1392.8 seconds.

From the information regarding the industrial process wastewater, the settling velocity for the sand particles will be:

= 9.81/[18(1.002 × 10^-6] × (2.65 - 1) × (0.04 × 10^-³)²

= 0.001435

Therefore, the detection time will be:

t = 2/0.001435

t = 1392.8 seconds.

The detection time is 1392.8 seconds.

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The pressure of the N₂ collected if the temperature was 22°C celcius is 98.6823 kPa.

What is atmospheric pressure?

The air around you has weight, and it presses against everything it touches. That pressure is called atmospheric pressure, or air pressure.

Atmospheric pressure = 101.325 kPa

Vapor pressure of water at 22°C = 2.6427 kPa

Pressure of N₂ = (Atmospheric pressure) - (vapour pressure of water at 22°C)

Pressure of N₂ = (101.325 kPa) - ( 2.6427 kPa)

Pressure of N₂ = 98.6823 kPa

Therefore, the pressure of the N₂ collected if the temperature was 22°C celcius is 98.6823 kPa.

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Answer:

85.4

Explanation:

Explanation:

When working with moles only, you will start by applying stoichiometry to determine how the reactants will affect your amount of products in this reaction. For this question, we will assume that other reactants are in infinite qualities, so therefore, it is the amount of aluminum that we will be concerned with. You need to figure out how much aluminum is in the specified amount of aluminum bromide, and then how much aluminum hydroxide that will be able to create. Make sure all your units cancel out!

9.24 mol AlBr3 x (1 mol Al / 1 mol AlBr3) x (1 mol Al(OH)3 / 1 mol Al) = 9.24 mol AlBr3

When you're working with mole ratios that involve grams to moles conversions, the first thing you want to do is calculate the molecular weight of each component you are being asked about. Because the question was given to you as words instead of chemical formulas, you will want to figure out the chemical formulas. For example, aluminum hydroxide is Al(OH)3 and aluminum bromide is AlBr3. To calculate molecular weight, you will want to consult a periodic table, find the molecular weight for each atom, and then calculate the correct sum of each molecular weight. Make sure you keep track of the number of each atom you have, i.e. 3 oxygen and 3 hydrogen for aluminum hydroxide.

Na = 22.990 g/mol

O = 15.999 g/mol

H = 1.008 g/mol

NaOH = 22.990 g/mol + 15.999 g/mol + 1.008 g/mol = 39.997 g/mol

Al = 26.982 g/mol

O = 15.999 g/mol

H = 1.008 g/mol

Al(OH)3 = 26.982 g/mol + (3 x 15.999 g/mol) + (3 x 1.008 g/mol) = 78.003 g/mol

Now, if you begin with an amount of NaOH in grams, you will first have to convert that to moles in order to use the mole ratio.

24 g NaOH x (1 mol NaOH / 39.997 g NaOH) = 0.600 mol NaOH

Now, you will have to account for the part of the sodium hydroxide that will be present in the aluminum hydroxide. In this case, it is the hydroxide (OH) portion of the formula. There is one mole of OH in each mole of NaOH, but there are 3 moles of OH in each mole of Al(OH)3. You will start with the 0.600 mol NaOH you know you have and then use the mole ratio.

0.600 mol NaOH x (1 mol OH / 1 mol NaOH) x (1 mol Al(OH)3 / 3 mol OH) = 0.200 mol Al(OH)3

Finally, when you are converting from grams to grams, you will have to find the molecular weight of both the reactant and the product, convert reactants in grams to reactants in moles, then use the mole ratio, then convert the moles of product back to grams of product. This time, you are concerned about the mole ratio of sodium, as that is the element that is in both chemical formulas.

Answer:

that is your answer hope this helps u