Solve for a... b=5/7(a-11)

Answer:

it 288

Step-by-step explanation:

if u multiply 24x12 it gives you 288 hope this help you

Using linear function concepts, it is found that representation of the value of -4.8 is given by:

It means that there are 4.8 thousand less sales for every dollar the price is increased.

A linear function is modeled by:

y = mx + b

In which:

In this problem, the model for the number of sales(in thousands), with the price at x dollars, is given by:

f(x) = -4.8x + 121.02.

The slope is of -4.8, which means that when x increases by 1, y decreases by 4.8 thousand, hence the correct option is given by:

It means that there are 4.8 thousand less sales for every dollar the price is increased.

More can be learned about linear function concepts at https://brainly.com/question/24808124

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The provided graph is not a function because  it touches the graph more than one point.

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have given a graph of a function.

We can check the whether the given graph is a function or not by drawing a vertical line if the vertical line touches the graph more than two points then the graph is not a function.

The given graph is not a function because it touches the graph more than one point.

Thus, the provided graph is not a function because  it touches the graph more than one point.

Learn more about the function here:

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Answer:

SolutioN :

[tex] \bf \: \star ( - 3x^{2} + 4x) + (2 {x}^{2} - x - 11)[/tex]

[tex] \longrightarrow \bf \: - 3 {x}^{2} + 4x + 2 {x}^{2} - x - 11[/tex]

[tex] \longrightarrow \bf \: - 3 {x}^{2} + 2 {x}^{2} + 4x - x - 11[/tex]

[tex] \longrightarrow \boxed{\bf \: - {x}^{2} + 3x - 11}[/tex]

-------------HappY Learning <3 ----------

Given expression:

[tex](-3x^2+4x)+(2x^2-x-11)[/tex]

To simplify the expression, it is needed to open the parentheses.

[tex]\implies (-3x^2+4x)+(2x^2-x-11)[/tex]

[tex]\implies -3x^2+4x+2x^2-x-11[/tex]

To further simplify the expression, let us combine like terms.

[tex]\implies -3x^2+4x+2x^2-x-11[/tex]

[tex]\implies x^{2} (-3 + 2)+x(4-1)-11[/tex]

Now, simplify the expression as needed.

[tex]\implies x^{2} (-3 + 2)+x(4-1)-11[/tex]

[tex]\implies x^{2} (-1)+x(3)-11[/tex]

Finally, open the parentheses to get the simplified form

[tex]\implies x^{2} (-1)+x(3)-11[/tex]

[tex]\implies \boxed{\bold{-x^{2} +3x-11}}[/tex]

[tex]\text{Therefore, the simplified expression is} \ \boxed{-x^{2} +3x-11}[/tex]

To find the point of symmetry:

  ⇒ must find where the distance between the original point and the

   line of symmetry and reflected point and the line of symmetry are

   equally distant from each other

Based on that knowledge:

 ⇒ the image appears to be entirely reflected horizontally

    ⇒ when the line of symmetry is the y-axis

        ⇒ A, A' equal distant from line of symmetry

        ⇒ B, B' equal distant from line of symmetry

        ⇒ C, C' equal distant from line of symmetry

Answer: y- axis

Hope that helps!

Answer:

bottom left

Step-by-step explanation:

when divideing/mult by neg number, sign flips.

Answer:

m = [tex]\frac{1}{2}[/tex] , c = [tex]\frac{5}{2}[/tex]

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given

y + 2x = 4 ( subtract 2x from both sides )

y = - 2x + 4 ← in slope- intercept form

with slope m = - 2

given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-2}[/tex] = [tex]\frac{1}{2}[/tex] , then

y = [tex]\frac{1}{2}[/tex] x + c ← is the partial equation

to find c substitute (3, 4 ) into the partial equation

4 = [tex]\frac{3}{2}[/tex] + c ⇒ c = 4 - [tex]\frac{3}{2}[/tex] = [tex]\frac{5}{2}[/tex]

y = [tex]\frac{1}{2}[/tex] x + [tex]\frac{5}{2}[/tex] ← equation of line

with m = [tex]\frac{1}{2}[/tex] and c = [tex]\frac{5}{2}[/tex]

Answer:

the region of the graph where the shaded regions of the graph of each inequality overlap, or where the regions intersect

Step-by-step explanation:

The formula is given by

Or

Where

Answer:

(-∞, ∞)

Step-by-step explanation:

Solving :

Answer:

-3125

Hope this helps!!

Answer:

135

Step-by-step explanation:

All triangles =180 degrees
Angle ADC is 45
This means that angle ACD is also 45
ACD and ACB are supplementary which means they add to 180 as well
180 - 45 = 135

Answer:

true

Step-by-step explanation:

yas

Answer:

  6.1 km

Step-by-step explanation:

The Pythagorean theorem tells you the relationship between the lengths of the sides of a right triangle.

  c² = a² +b² . . . . a, b are the short sides; c is the hypotenuse

__

The geometry of this problem can be modeled by a right triangle with legs 3.7 km and 4.9 km. The distance of interest is the hypotenuse of the triangle.

  c² = 3.7² +4.9² = 13.69 +24.01 = 37.70

  c = √37.70 ≈ 6.1

The straight-line distance is about 6.1 km.

Answer: F

Step-by-step explanation:

Answer:

6x+8

Step-by-step explanation:

2(3x+4)= 2(3x) + 2(4) = 6x+8

Answer:

Count the tally marks to determine the frequency of each class. The relative frequency of a data class is the percentage of data elements in that class. The relative frequency can be calculated using the formula fi=fn f i = f n , where f is the absolute frequency and n is the sum of all frequencies

Answer:

See below

Step-by-step explanation:

each term is the sum of the two before it

2 3 5 8 13 21 34

Answer:

(-1, -5)

(0, -2)

(-3, -11)

Step-by-step explanation:

y = 3x - 2.

→ 3×(-2)-2=-8 ≠0 ⇒(-2, 0) doesn’t correspond to input-output pairs for the function

→ 3×(-1)-2=-5 ⇒(-1, -5) corresponds to input-output pairs for the function

→ 3×(0)-2=-2 ⇒(0, -2) corresponds to input-output pairs for the function

→ 3×(2)-2=4≠3 ⇒(2, 3) doesn’t correspond to input-output pairs for the function

→ 3×(-3)-2=-11 ⇒(-3, -11) corresponds to input-output pairs for the function

Answer:

Step-by-step explanation:

Minimum: 2

Quartile Q1: 4.5

Median: 10

Quartile Q3: 15

Maximum: 19

Answer:

If we square both sides then we get

x2-8x+16 = (x-4)2

Now if we expand the right side of the equation we get

x2-8x+16 = (x-4)(x-4)

x2-8x+16 = x2-8x+16

So no matter what x is, the right side will be equal to the left side.

However, if we look at the original equation on the left side, √(x2-8x+16) , the value under the square root symbol has to be greater than or equal to zero (otherwise we get an imaginary number and you might not be working with those yet)

Step-by-step explanation:

So in order for √(x2-8x+16) to be greater than or equal to zero, x has to be greater than or equal to 4. If x is less than 4 you get a negative number. If x is greater than 4, you'll get the same answer on both sides no matter what x is

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's solve ~

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 8x + 16} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 4x - 4x + 16} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{} (x - 4) - 4(x - 4)} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ (x - 4)(x - 4)} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ (x - 4) {}^{2} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: x - 4[/tex]

Now, it's given that ~

[tex]\qquad \sf  \dashrightarrow \:x \geqslant 4[/tex]

plug the value of x as 4 :

[tex]\qquad \sf  \dashrightarrow \:4 - 4[/tex]

[tex]\qquad \sf  \dashrightarrow \:0[/tex]

So, we can infer that :

Value of the required expression lies in :

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 8x + 16} \geqslant 0[/tex]

it's value is always greater than pr equal to 0, satisfying the given condition ~

Answer:

14.167

Step-by-step explanation:

assuming you meant 5+13

Answer:

The mass of salt!

Step-by-step explanation:

The responding variable is the part of an experiment that a scientists measures and observes closely for a change or a response

[tex]\\ \rm\Rrightarrow \sqrt{x²-10x+25}[/tex]

[tex]\\ \rm\Rrightarrow \sqrt{x²-5x-5x+25}[/tex]

[tex]\\ \rm\Rrightarrow \sqrt{x(x-5)-5(x-5)}[/tex]

[tex]\\ \rm\Rrightarrow \sqrt{(x-5)(x-5)}[/tex]

[tex]\\ \rm\Rrightarrow \sqrt{(x-5)^2}[/tex]

[tex]\\ \rm\Rrightarrow\pm (x-5)[/tex]

Solution set(for x-5)

for 5-x

Answer:

First, simplify the expression under the square root sign by factoring:

[tex]\implies x^2-10x+25[/tex]

[tex]\implies x^2-5x-5x+25[/tex]

[tex]\implies x(x-5)-5(x-5)[/tex]

[tex]\implies (x-5)(x-5)[/tex]

[tex]\implies (x-5)^2[/tex]

Therefore:

[tex]\implies \sqrt{x^2-10x+25}=\sqrt{(x-5)^2}[/tex]

[tex]\implies \sqrt{x^2-10x+25}=\pm(x-5)[/tex]

[tex]\implies \sqrt{x^2-10x+25}=|x-5|[/tex]

As the domain is -5 ≤ x < 5, then:

[tex]\implies y=-x+5[/tex]

and the range is 0 < y ≤ 10

1inch = 2.5cm

∆ 30cm

5cm =2inch

Answer:

0 pars

Step-by-step explanation:

3-3=0

Answer:

[tex]\sf \cos(G)=\dfrac{1}{2}[/tex]

Step-by-step explanation:

Trigonometric ratios

[tex]\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}[/tex]

where:

Given:

[tex]\implies \sf \cos(G)=\dfrac{2}{4}=\dfrac{1}{2}[/tex]