Triangles T S R and Q R S overlap at point P. Angle S T R is 66 degrees and angle S Q R is 66 degrees. The lengths of T S and Q R are both 5 inches.

Can ΔTSR and ΔQRS be proven congruent by SAS?
yes, because along with the given information on the diagram, SR ≅ RS by the reflexive property
yes, because a reflection will map ΔTSR onto ΔQRS
yes, because P appears to be the midpoint of SQ and TR
no, because not enough is information given to prove the triangles congruent by SAS

Answers

Answer 1

No,  ΔTSR and ΔQRS cannot be proven congruent by SAS because not enough is information given to prove the triangles congruent by SAS.

What is Congruency?

Two figures or objects are congruent if they have the same shape and size.

To prove using SAS congruency we should have at least two congruent side and one congruent angle.

But we don't have the sufficient information.

Hence, ΔTSR and ΔQRS cannot be proven congruent by SAS.

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Answer 2

Answer:

d

Step-by-step explanation:


Related Questions

NOTE: Angles not necessarily drawn to scale.

Answers

Answer:

60

Step-by-step explanation:

I'm assuming that ED is an exactly straight line, that would mean the angle is 180 degrees. So the sum of the angles in between should also equal 180. This gives you the equation

100 + 20 + x = 180

120 + x = 180

60  = x

3/a times x -4 equals 20

Answers

Answer:

a = -5/3

Step-by-step explanation:

3/a × -4 = 20

3a × -4/-4 = 20/-4

3a = -5

a = -5/3

Check:

3/(-5/3) × - 4 = 20

-5 × - 4 = 20

Solve for y
:
V=−4y+4x

Answers

[tex] - 4y = v - 4x \\ y = \frac{ - v}{4} + x[/tex]

[tex]\\ \rm\dashrightarrow V=-4y+4x[/tex]

[tex]\\ \rm\dashrightarrow -4y=V-4x[/tex]

[tex]\\ \rm\dashrightarrow y=\dfrac{V-4x}{-4}[/tex]

[tex]\\ \rm\dashrightarrow y=x-\dfrac{V}{4}[/tex]

If I have 8$and something 3$ how many change wil I get?

Answers

If you have $8 and something’s cost $3 you will be getting $5 dollars back

use an exponential expression to calculate the area covered by purple loosestrife seven years from now. is this a valid prediction? What does this result tell you about the constraints on the exponential model?

Answers

The area of the wetland that will be covered in purple loosestrife 7 years from now is modeled by this expression 500(1.2)^7

How to illustrate the information?

The exponential expression to calculate the area covered by purple loosestrife seven years from now will be:

= 500 × 1.2^7

After evaluating the expression, the model predicts that approximately 1,792 acres of the wetland will be covered in purple loosestrife 7 years from now.

This is not a valid prediction because the total area of the wetland is only 1,240 acres. Therefore, a constraint on the model is that the value of the expression 500(1.2)^t must be less than or equal to 1,240.

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20) Find the surface area of the solid shown. 16 dm 17 dm 30 dm​

Answers

Answer:

680π dm² = 2136.28 dm²

Step-by-step explanation:

Recall:

lateral area of cone = πrs; where s = slant height = 17 dm

area of circle = πr²

lateral area of cylinder = πdh

Lateral area of cone: (3.14159)(8 dm)(17 dm) = 427.26 dm²

Area of base of cylinder: (3.14159)(8 dm)² = 201.06 dm²

Lateral area of cylinder: (3.14159)(16 dm)(30 dm) = 1507.96 dm²

Total surface area = 427.26 dm² + 201.06 dm² + 1507.96 dm²

Total surface area = 680π dm² = 2136.28 dm²

In a binomial​ experiement, what does it mean to say that each trial is independent of the other​ trials?.

Answers

In a binomialexperiment to say that each trial is independent of the other​ trials means that the outcome of one trial does not affect the other trial.

An experiment with a set number of independent trials and just two results is referred to as a binomial experiment.

To say that in a binomial experiment, each trial is independent of the other trials means that the outcome of one trial does not affect the other trials.

This means that whatever we get in the first trial, does not affect the outcome of the second or any other trial.

For example, in the tossing of a coin 10 times, the outcome of the first trial doesn't affect any of the other nine trials.

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When two variables are being examined, and one variable moves one way and the other variable moves in the opposite direction, this is called a(n):

Answers

When two variables are being examined, and one variable moves one way and the other variable moves in the opposite direction, this is called an inverse relation.

Correlation is a statistical degree (expressed as various) that describes the size and path of a courting among or extra variables. A correlation between variables, however, does now not robotically suggest that the trade in a single variable is the purpose of the alternate inside the values of the opposite variable.

A positive correlation is clear while variables move within an equal course. An inverse correlation is clear whilst variables circulate inside the opposite route.

A negative correlation is a relationship among variables that pass in contrary instructions. In other phrases, while variable A increases, variable B decreases. A poor correlation is likewise known as an inverse correlation.

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When two variables are being examined, and one variable moves one way and the other variable moves in the opposite direction, this is called a(n): Inverse Relationship.

Consumption is subject to diminishing marginal utility. -A lower price increases the purchasing power of a buyer's income, enabling a buyer to purchase more of a product.

The law of supply and demand is a keystone of modern economics. According to this theory, the price of goods is inversely related to the quantity offered. This makes sense for many goods, since the more costly it becomes, fewer people will be able to afford them and demand will subsequently drop.

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What is the area of the sector
shown in the diagram below?


OA. 11.1 cm²
OB. 2.5 cm²
OC. 39.3 cm²
OD. 50 cm²

Answers

Answer:

OC. 39.3 cm²

Step-by-step explanation:

Area of a circle = πr²    (π ≈ 3.14)

45 degrees = 1/8 of a full circle

Area of the full circle : 3.14 × 10² =

3.14 × 100 = 314 cm²

Area of the sector : 314 × 1/8 = 39.25 cm² ≈ 39.3 cm²

37. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.
37. x-intercept at (-5, 0) and y-intercept at (0, 4)

Answers

Answer:

The linear equation for the line with an x-intercept at (-5,0) and y-intercept at (0,4) is found as [tex]$y=\frac{4}{5} x+4$[/tex].

Step-by-step explanation:

A condition is given that a line has an x- intercept at (-5,0) and y- intercept at (0,4).

It is asked to find a linear equation satisfying the given condition.

To do so, first determine the slope of the line using coordinates of the given intercepts. Then write the equation in the slope-intercept form using the slope and the y- intercept.

Step 1 of 2

Determine the slope of the line.

The points of the intercepts of the line are given as (-5,0) and (0,4). Next, the formula for the slope is given as,[tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$[/tex]

Substitute 4&0 for [tex]$y_{2}$[/tex] and [tex]$y_{1}$[/tex]respectively, and 0&-5 for [tex]$x_{2}$[/tex] and [tex]$x_{1}$[/tex] respectively in the above formula. Then simplify to get the slope as follows,

[tex]$$\begin{aligned}m &=\frac{4-0}{0-(-5)} \\m &=\frac{4}{5}\end{aligned}$$[/tex]

Step 2 of 2

Write the equation in the slope-intercept form.

The slope-intercept form of a line is given as follows,

[tex]$$y=m x+b$$[/tex]

The coordinates at the y- intercept is (0,4). Now, as the y- coordinate is 4 , so b=4.

So, substitute 4 for b and [tex]$\frac{4}{5}$[/tex] for m in the equation y=mx+b, as follows,

[tex]$y=\frac{4}{5} x+4$$[/tex]

This is the required linear equation.

Calculate the residuals for the scatter plot (image provided)

Answers

From the given graph, and using the scatter plot function of a graphing calculator, the residuals are;

-0.08693, -0.019376, -0.518, -0.183, -0.083, 0.135, 0.318, and 0.578

Which method can be used to find the residuals?

From the diagram, the given points are;

(14, 4), (15, 4), (16.5, 3.5), (18, 4), (18, 3.9), (19.5, 3.85), (20, 4), (26.8, 3.8)

Utilizing a graphing calculator, using the scatter plot function we have the following predicted values;

Best fit line; y = 5.032 - 0.0676•x

Residuals = Actual - Predicted from equation

The residuals are;

y1 = 4 - 4.08693 = -0.08693

y2 = 4 - 4.019376 = -0.019376

y3 = 3.5 - 3.918 = -0.518

y4 = 4 - 3.817 = -0.183

y5 = 3.9 - 3.817 = -0.083

y6 = 3.85 - 3.715 = 0.135

y7 = 4 - 3.682 = 0.318

y8 = 3.8 - 3.222 = 0.578

The residuals are therefore;

The residuals are;

-0.08693, -0.019376, -0.518, -0.183, -0.083, 0.135, 0.318, and 0.578

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A space shuttle can orbit the earth at 330 mi above sea level. The average commercial airplane can fly at 5.7 mi above sea level. What is the distance between the two aircraft?

Answers

Answer:

324.3mi

Step-by-step explanation:

Given Space Shuttle height above ground = 330mi

Airplane height above ground = 5.7mi

Difference between two aircrafts = Space Shuttle height - airplane height above ground

= 330 - 5.7

= 324.3mi

pls help me in this i really need help :( :)

Answers

Hello and Good Morning/Afternoon:

Let's take this problem step-by-step:

First off, let's write the line in point-slope form:

  [tex]\rm \hookrightarrow (y-y_0)=m(x-x_0)[/tex]

(x₀, y₀) any random point on the line'm' is the value of the slope

Let's calculate the slope:

 [tex]\rm \hookrightarrow Slope = \frac{y_2-y_1}{x_2-x_1}[/tex]

(x₁, y₁): any random point on the line                                     ⇒   (-2, -6)(x₂,y₂): any random point on the line that is not (x₁, y₁)         ⇒   (2, -3)

                 [tex]\rm \hookrightarrow slope = \frac{-3--6}{2--2} =\frac{3}{4}[/tex]

Now that we found the slope, let's put it into the point-slope form

  ⇒ we need (x₀, y₀) ⇒ let's use (2,-3)

     [tex](y-(-3))=\frac{3}{4} (x-2)\\y+3=\frac{3}{4} (x-2)[/tex]

The equation, however, could also be put into 'slope-intercept form'

     ⇒ gotten by isolating the 'y' variable to the left

          [tex]y = \frac{3}{4}x-\frac{9}{2}[/tex]  

Answer:[tex]y = \frac{3}{4}x-\frac{9}{2}[/tex] or [tex]y+3=\frac{3}{4} (x-2)[/tex]

   *Either equations work, put the one that you are the most familiar with

Hope that helps!

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he coordinate grid shows the graph of four equations: A coordinate grid is shown from negative 12 to positive 12 on the x axis and also on the y axis. Line A passes through the ordered pairs negative 3, 4 and 9, negative 2. Line B passes through the ordered pairs 2, 8 and 8, negative 8. Line C passes through the ordered pairs negative 3, negative 4 and 4, 6. Line D passes through the points 2, negative 2 and 5 and 6. Which set of equations has (5, 0) as its solution? A and B C and D B and D A and D

Answers

The set of equation that is known to have 5 and 0 as solutions is A and B.

How to solve for the system of equations.

From the graph that we have here in this question, we are supposed to identify the equations that have this point.

We can do this by tracing the lines in order to locate 5 and 0 on the grid.

When we trace the bine that has 5 and 0, We would find out that it is traceable to A and B.

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question on the image​

Answers

Let [tex]x,y[/tex] be the legs of the triangle, with [tex]x[tex]\mathrm{area}_{\rm square} = y^2[/tex]

[tex]\mathrm{area}_{\rm triangle} = \dfrac12 xy[/tex]

The square has 3 times the area of the triangle, so

[tex]y^2 = \dfrac32 xy[/tex]

Meanwhile, in the triangle we have

[tex]\tan(\theta) = \dfrac xy[/tex]

Now,

[tex]y^2 = \dfrac32 xy \implies \dfrac23 = \dfrac xy \implies \boxed{\tan(\theta) = \dfrac23}[/tex]

Solve the equation
(6x18) (3x + 2) = 0

Answers

Answer:

[tex] - \frac{2}{3} [/tex]

Step-by-step explanation:

Given (6x18)(3x+2) = 0

[tex]108(3x + 2) = 0 \\ 324x + 216 = 0 \\ 324x = - 216 \\ x = \frac{ - 216}{324} \\ = - \frac{2}{3} [/tex]

approximately how high to the nearest tenth of a metre is emma's kite above ground

Answers

11 thanks to the sun light abs the rv light we get from the lunar eclipse

At which of the given values is the graph discontinuous?
a. 7
b. -2
C. -4
d. 0

Answers

According to the
figure when ×<7. fx<0..

Copy the figure below onto a separate sheet of paper. Find the image of the figure under reflections in line m and then line t. In the box below, describe the rotation equivalent to the composition of reflections with respect to lines m and t.

Answers

The reflection of the triangle DEFG will be given in the figure.

What is a transformation of geometry?

A spatial transformation is each mapping of feature shapes to itself, and it maintains some spatial correlation between figures.

Reflection does not change the size and shape of the geometry.

The image of the figure under reflections in line m and then line t.

The reflection of the triangle DEF will be given in the figure.

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please help me out somebody!

Answers

Answer:

Step-by-step explanation:

16 percent of what number is 17

Answers

Answer:   106.25

Work Shown:

16% of x = 17

0.16x = 17

x = 17/(0.16)

x = 106.25

what’s the slope and y-int of, [-1,7] and [0,4]

Answers

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{What is the formula for finding slope?}[/tex]

[tex]\mathbf{\dfrac{y_2 - y_1}{x_2 - x_1} = slope}[/tex]

[tex]\huge\textbf{Often people understand it better by:}[/tex]

[tex]\mathbf{\dfrac{rise}{run} = slope}[/tex]

[tex]\huge\textbf{Answering the given question:}[/tex]

[tex]\mathbf{y_2 \rightarrow 4}\\\\\mathbf{y_1 \rightarrow 7}\\\\\mathbf{x_2\rightarrow 0}\\\\\mathbf{x_1 \rightarrow -1}[/tex]

[tex]\huge\textbf{Now, that we have that information out}\\\huge\textbf{the way, we can answer the question.}[/tex]

[tex]\huge\textbf{Solving for the answer:}[/tex]

[tex]\mathbf{\dfrac{4 - 7}{0 - (-1)} = slope}[/tex]

[tex]\mathbf{\rightarrow \dfrac{4 - 7}{0 + 1} = slope}[/tex]

[tex]\mathbf{\rightarrow \dfrac{-3}{1} = slope}[/tex]

[tex]\mathbf{-3\div 1 = slope}[/tex]

[tex]\mathbf{\rightarrow -3 = slope}[/tex]

[tex]\huge\textbf{Therefore, your answer should be:}[/tex]

[tex]\huge\boxed{\textsf{S}\frak{lope \rightarrow -3}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

What is a solution to the system of equations that includes quadratic function f(x) and linear function g(x)?
f(x)=2x²+x+4

Answers

The solution to the system of equations that includes quadratic function f(x) and linear function g(x) is (1, 7)

How to solve system of equation?

The solution to the linear and quadratic equation is as follows:

For the linear, a solution is 1 and 7.

This is because when x = 1, f(x) = 7

For the quadratic equation, 1 and 7 also works.

2x² + x + 4

2(1)² + 1 + 4

2 + 1 + 4 = 7

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Having some trouble here

Answers

Answer:

None of them are correct i believe

Step-by-step explanation:

its sideways lol

Adrian brought snacks for his team's practice. He bought a bag of apples for $1.68 and a 12-pack of juice bottles. The total cost before tax was $10.92. How much was each bottle of juice

Answers

Answer:

x = 77/100

Step-by-step explanation:

When you solve this equation: 1.68+ 12x = 10.92

The answer is x = 77/100

The cost of each bottle of juice will be $0.77.

What is an expression?

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given that Adrian brought snacks for his team's practice. He bought a bag of apples for $1.68 and a 12-pack of juice bottles. The total cost before tax was $10.92.

From the given data the expression will be formed as below:-

1.68+ 12x = 10.92

12x = 10.92 - 1.68

12x = 9.24

x =9.24 / 12

x = $0.77

Therefore, the cost of each bottle of juice will be $0.77.

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How far does judy travel in 2 3/4 hours if she travels at the rate of 5 1/2 miles per hour

Answers

Judy travel's 15.125 miles or 15[tex]\frac{1}{8}[/tex] miles in 2 3/4 hours

How to solve such time related questions?

The key concept for solving such questions is the relationship between speed, distance and time.

The relationship between them is Distance = Speed x Time

Given:

  Speed = 5 1/2 miles per hour    Time  =   2 3/4 hours

Substituting it in the relationship we get,

Distance = Speed x Time

Distance =  5 1/2 miles per hour  x 2 3/4 hours

Distance = [tex]\frac{11}{2} X \frac{11}{4}[/tex] miles

Distance =  [tex]\frac{121}{8}[/tex] miles or 15[tex]\frac{1}{8}[/tex] miles

Thus Judy travel's 15.125 miles or 15[tex]\frac{1}{8}[/tex] miles in 2 3/4 hours

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E
What is the solution to the system of equations?
y = 0x + 3
x = −2
O [--]
O
[22]
[2
O
[-2]

Answers

Answer:

-2

Step-by-step explanation:

The solution to the system of equations is (x, y) = (-2, 1).

What is an equation?

An equation contains one or more terms with variables connected by an equal sign.

Example:

2x + 4y = 9 is an equation.

2x = 8 is an equation.

We have,

The second equation tells us that x = -2.

Substituting this value into the first equation, we get:

y = -2 + 3

Simplifying, we get:

y = 1

Therefore,

The solution to the system of equations is (x, y) = (-2, 1).

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N= ???
Please help asap

Answers

Answer:

N=[tex]\sqrt{61}[/tex]

Step-by-step explanation:

We have the first point as (2,4), and the second point as (-3,-2). This means that [tex]x_1=2, y_1=4,x_2=-3,y_2=-2.[/tex] Using the distance formula, we get [tex]\sqrt{(2-(-3))^2+(4-(-2))^2} \\\sqrt{(2+3)^2+(4+2)^2}\\\sqrt{25+36}=\sqrt{61}[/tex]

Answer:

[tex]\sqrt{61}[/tex]

Step-by-step explanation:

Solve for x
[tex]\ \textless \ br /\ \textgreater \ x = \dfrac{1}{2-\dfrac{1}{2-\dfrac{1}{2-x} } } \: \: \: , (x \neq 2)[/tex]
Help me with this!​

Answers

Answer:

[tex]x= \dfrac{3-2x}{4-3x}[/tex]

Step-by-step explanation:

Given:

[tex]x=\dfrac{1}{2-\dfrac{1}{2-\dfrac{1}{2-x}}}}[/tex]

Simplify:

[tex]\begin{aligned}2-\dfrac{1}{2-x} & =\dfrac{2(2-x)-1}{2-x}\\\\ & =\dfrac{3-2x}{2-x}\end{alilgned}[/tex]

Therefore:

[tex]x=\dfrac{1}{2-\dfrac{1}{\dfrac{3-2x}{2-x}}}[/tex]

Simplify:

[tex]\begin{aligned}2-\dfrac{1}{\dfrac{3-2x}{2-x}} & =2-\dfrac{2-x}{3-2x}\\\\ & =\dfrac{2(3-2x)-(2-x)}{3-2x}\\\\ & = \dfrac{6-4x-2+x}{3-2x}\\\\ & = \dfrac{4-3x}{3-2x}\end{aligned}[/tex]

Therefore:

[tex]x & =\dfrac{1}{\dfrac{4-3x}{3-2x}}[/tex]

[tex]\textsf{Apply the fraction rule}: \quad \dfrac{1}{\frac{b}{c}}=\dfrac{c}{b}[/tex]

[tex]\implies x& = \dfrac{3-2x}{4-3x}[/tex]

Use the properties of 30-60-90 and 45-45-90 triangles to solve for x in each of the problems below. Then decode the secret message by matching the answer with the corresponding letter/symbol from the exercises.

Answers

Answer:

a

Step-by-step explanation:

this is the anser on e2020

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