A ping pong ball rolls off a table at 2.33 m/s. What is the magnitude of the ball's velocity after 0.428 seconds? (Ignore direction, unit = m/s, 50 points)

Answer:

The horizontal component of velocity (B) remains constant because no components of the external force act on this component of velocity

(the force of gravity affects the vertical component of velocity)

Answer:

experiments provide course effective means of quantitative process kind of examing the bounds of theory is specially when the Nolan reality is important analysis

Explanation:

regardless of such topic the purpose of laboratory experiment is to test theory occurs by focusing on one server predictive elements of the theory is isolating the influence of elements on outcomes

The change in the internal energy of the system is increased by 1 Kj.

According to the first law of thermodynamics,

Therefore, Δ∪=q+w

[Δ∪= change of internal energy; q=heat; w=work]

Provided,

q= -3Kj (as heat is given away)

w= +2Kj (work done in the system is positive)

So, Δ∪= -3 + (+2) Kj

⇒Δ∪= -1 Kj

Therefore the internal energy of the system is increased by 1 kj.

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The stone will strike the ground with velocity of 33.5 m/s.

What is velocity:

What is displacement:

Here,

Stone is dropped freely from rest, so it's Initial velocity will be zero.

u = 0 m/s

displacement is equal to half of total height.

y = h/2

since Stone is dropped freely, a=g ( acceleration of gravity)

According to Newton's equation of motion:

y = u* t + 1/2 (at^2)

h/2 = 0 + 1/2 (gt^2)

h = g* t^2 -----1

now at t= t+1 , displacement y = h

h = u* t + ½ g (t + 1)²

h = ½ g (t + 1)² -----2

comparing both equations,

g* t^2 = ½ g (t + 1)²

2t² = (t + 1)²

2t² = t² + 2t + 1

t² − 2t = 1

t² − 2t + 1 = 2

(t − 1)² = 2

t − 1 = ±√2

t = 1 ± √2

Since t > 0, t = 1 + √2.  

So t+1 = 2 + √2.

At that time, the speed is:

v = at + u

v = g (2 + √2) + 0

v = g (2 + √2)

If g = 9.8 m/s²,

v = 33.5 m/s.

The stone will strike the ground with velocity of 33.5 m/s.

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Answer:

In solid it is high because the molecules are closely packed.

In liquid it is lesser than solids as they are loosely

packed.

In gas it is least because they are very loosely packed

The best name for the ionic bond that forms between them is Beryllium Bromide.

We have been provided with data,

Beryllium charge, q = 2

Bromine charge, q = -1

As we know the valance electron of Be is +2  and the valance electron of bromine is -1. Since one is metallic and the other is non-metallic.

Now, when they combine they exchange valance electron, and bromine change into bromide so they form Beryllium Bromide.

So, the best name for the ionic bond that forms between them is Beryllium Bromide.  

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Answer:

slows down

Explanation:

slow down and speed up

Considering the definition of potential energy, the potential energy of the bungee jumper is 90,889.65 J.

Potential energy is the energy that measures the ability of a system to do work based on its position. In other words, this is the energy that a body located at a certain height above the ground has.

Gravitational potential energy is the energy associated with the gravitational force. This will depend on the relative height of an object to some reference point, the mass, and the strength of gravity.

So for an object with mass m, at height h, the expression applied to the gravitational energy of the object is:

Ep= m×g×h

Where:

In this case, you know:

Replacing in the definition of potential energy:

Ep= 85 kg × 9.81 m/s² × 109 m

Solving:

Ep= 90,889.65 J

Finally, the potential energy of the bungee jumper is 90,889.65 J.

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The corresponding height of the given parallelogram is 5.4 units

steps involved:

Given that the basis of the parallelogram RSTU is thought to be the line segment RU with vertices R(1, 1) and U(4, 5).

The parallelogram's top is therefore defined as the line segment ST with vertices S(7, 0) and T(10, 4).

The length of a line with endpoints at RU and ST and that is perpendicular to both RU and ST is the length that corresponds to the parallelogram's height.

Given by is the equation for the line segment RU.

Let the slope of the line perpendicular to line RU be m, then provided that two lines are perpendicular, the product of the slope of the two lines is -1.

Consequently, the equation for the line passing through point (1, 1) and perpendicular to RU is

Therefore, the corresponding height of the given parallelogram is 5.4 units

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This is a uniformly accelerated rectilinear motion exercise.

To start solving this exercise, we obtain the following data:

To find the acceleration, divide the change in velocity by the time over which the velocity changed. The SI unit of speed is the meter per second (m/s). To find the acceleration, the velocity is divided by the time expressed in seconds (s). Therefore, the unit of acceleration is m/s².

We apply the following formula:

[tex]\large\displaystyle\text{$\begin{gathered}\sf a=\frac{V_{f}-V_{o}}{t} \end{gathered}$}[/tex]

where,

We substitute our data in the formula and solve:

[tex]\large\displaystyle\text{$\begin{gathered}\sf a=\frac{20 \ m/s-45 \ m/s}{0.5 \ s} \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf a=\frac{-25 \ m/s}{0.5 \ s} \end{gathered}$}[/tex]

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf a=-50 \ m/s^{2} \end{gathered}$}}[/tex]

Answer: The acceleration when the ball slows down is -50 m/s².

The uniformly accelerated rectilinear motion, also known as uniformly varied rectilinear motion, is one in which a mobile moves on a straight path being subjected to a constant acceleration.

Final Speed (Vf) = 20 m/s

Initial Speed (Vo) = 45 m/s

Time (t) = 0.5 sec

Acceleration (a) = ¿?

To calculate the acceleration, subtract the initial velocity minus the initial velocity, divided by the time.

To solve, we substitute our data into the given formula:

Answer: The acceleration with which the ball stops is -50 m/s².

Answer:

The angle of launch is 52.49 Degree.

Explanation:

The Range R and Height H of a thrown object is calculated using the formula,

R=V₀² sin(2φ)/g

H=V₀²sin²(φ)/g

From these equations it can be written,

V₀²=R g/ sin(2φ)

V₀²=H g/ sin²(φ)

These values are equal so it can be written by equating these equations,

R g/sin(2φ)=H g/sin²(φ)

tan(φ)= 2H/R

Given H=72.3 m and R=111 m, the angle of launch is,

tan(φ)= 2*72.3/111

φ= 52.49 Degree.

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Moment of inertia decreases about the axis of rotation.

The term "moment of inertia" refers to the quantity that describes how a body resists angular acceleration and is calculated by multiplying each particle's mass by its square of distance from the rotational axis.

Means,

I=mr² where,

I= Moment of inertia

m= mass of particle

r= distance of the particle from the axis of rotation.

So, Moment of inertia is directly proportional to the square of the distance from the axis of rotation.

I ∝ r²

As the distance of body from the axis of rotation increases, moment of inertia also increases and vice versa.

So, that's why when an ice skater performs a pirouette (a fast spin) by pulling in his outstretched arms close to his body , then he/she will decrease his/her distance from the axis of rotation.

That's why moment of inertia decreases about the axis of rotation.

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The deflection angle would have been 37.29º if the prism had been made of polystyrene plastic.

As we know that the deflection angle is an angle between the moving object from its directed course.

In the following question the deflection angle as laser enters the beam is, B = 22.6º

refractive index of glass, n1= 1.52

refractive index of polystyrene plastic, n2 = 1.59

Now when we see for the second surface then ,

B  = 45º - 22.6º

B  = 22.40º

So from Snell's law:

n1 sinθ1 = n2 sinθ2

→ sin B / sinθ = n1 / n2

sinθ = (sin 22.40º) × ( 1/ 1.59)

θ = 37.29º

Thus, the deflection angle should be 37.29º if the prism is made of polystyrene plastic.

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Answer:

according to the Archimedes principle , the floating substance displaces some liquid, so when the ice melts ,there will be no change in the water level as the melted ice will occupy the same volume as it was occupying earlier.

Explanation:

Expenses including those for linen service, ice, and paper goods might fluctuate depending on demand. Other variables are constants. No change occurs to it. This is further explained below.

Generally, Fixed expenditures, in contrast to the more unpredictable variable costs like advertising, happen regularly at the same time each year regardless of fluctuations in revenue or other variables. It doesn't get the performance bus.

Here, we are given with table.

[tex]\begin{tabular}{|c|c|c|}Other Expenses & Variable Expense & Fixed Expense. \\ Linen rental & $X$ & \\ piano rental & & $X$ \\ ice & $X$ & $X$ \\insurance & & $X$ \\ Pension plan & & $X$ \\Snow shoveling dees cparkinglot) & & \\Paper products & $X$ & $X$ \\ Kituen equipment & & $X$ \\ lease (mixer) & & \\Longterm debt. & & \\ Realestate tax. & & \\\end{tabular}[/tex]

In conclusion,

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The force of the body is obtained as 81144 N.

The term pressure is defined as the mass per unit area of a body. We have the pressure at the top of the tank as 225400 Pa and the area of the tank as 0.6 m by 0.6 m.

Thus;

Pressure = Force/Area

Force = Pressure * Area

Force = 225400 Pa *  0.6 m *0.6 m

Force = 81144 N

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The speed of the rocket at the end of 10 seconds is 66.7 m/s.

The speed of the rocket at the end of 10 seconds is calculated as follows;

F = mv/t

where;

F = (m/t)v

F = (0.025 kg /s) x 80 m/s

F = 2 N

F = ma

a = F/m

a = 2/(0.3)

a = 6.67 m/s²

v = at

v = 6.67 x 10

v = 66.7 m/s

Thus, the speed of the rocket at the end of 10 seconds is 66.7 m/s.

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Answer:

A object in rest will remain in rest and a object in motion will move at a constant pace and in a straight line unless a unbalanced force acts upon it

Explanation:

give brainliest if you'd like

Newton's first law: the law of inertia

Newton's first law states that

if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

hope you understand thank you.

Answer: efficiency =WQH=1−TCTH

Explanation: i looked it up

The magnetic flux through one turn of the wire making the solenoid is 7.88*10^-7 T m^2.

B = unI

= 4pi*10^-7*(100/0.1)*2

= 0.00251 T

Therefore, Flux = B*Area

= 0.00251*pi*(0.01^2)

= 7.88*10^-7 T m^2

Magnetic flux is a measurement of the entire magnetic discipline which passes thru a given vicinity. It's far a useful device for helping describe the outcomes of the magnetic pressure on something occupying a given vicinity. The size of the magnetic flux is tied to the specific location chosen.

The SI unit of magnetic flux is the Weber (Wb). A flux density of 1 Wb/m2 (one Weber in keeping with rectangular meter) is one Tesla (T).

A magnetic subject describes a location in which a magnetic pressure may be felt. Magnetic flux describes how a good deal of magnetic discipline passes through a place.

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The mass of a body if the acceleration the body used to move is given as 5 m/s-2 will be 3 kg.

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

Given data;

Force,F = 30 N

Mass,m =  kg

Acceleration,a = 5 m/s²

The force is found as;

F=ma

30 N =m kg × 5 m/s²

m=3 kg

Hence the mass of a body will be 3 kg.

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Answer:

At 820 K, the object lose heat at the rate of 0.072 J/min.

Explanation:

By using Newton's cooling law, the formula to calculate the rate of cooling R is,

R=-k(T-To)

where k is a constant, T is the temperature of the object and To is the temperature of the surrounding.

At T=950 K, R=0.15 J/min and To=700 K,

Therefore, 0.15=-k(950-700)

k=0.15/250 J/K min.

At T=820 K,

R=-(0.15 / 250)*(820-700)

R=-0.072 J/min

Therefore the rate of heat loss at T=820 K is 0.072 J/min.

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Answer:

if the car is traveling north, the person is also traveling north,

If the car turns to (left) to the west, the person will still tend to travel to the north and will slide to the right (north) on a slippery car seat.

The engine is rated at 400 horsepower at 6,400 rpm and 350 lb-ft of torque starting from 1,600 to 5,200 rpm.

Horsepower:

The power an engine produces is referred to as horsepower. It is determined by the amount of force required to move 550 pounds one foot in a second or 33,000 pounds one foot in a minute. The speed at which the work is completed serves as a gauge of power.

Equation to calculate horsepowe:

Simple math can be used to get horsepower: Horsepower = Torque x RPM / 5,252. To test it out for yourself, use the horsepower calculator below. Knowing a few more fundamental terminology and formulas can help you comprehend how a dynamometer determines torque and power.

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If it takes cool air and passes it through the heat source using a fan or blower, the type of heat transfer is convection heat transfer.

Convection is the transfer of heat from one place to another due to the movement of fluid.

During heat transfer by convection, cold air replaces hot risen air.

Thus, if it takes cool air and passes it through the heat source using a fan or blower, the type of heat transfer is convection heat transfer.

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The mechanical energy of the river water per unit mass is 887.4 J/kg

The power generated is 452.574 MW.

Given:

Average velocity (v) = 3 m/s

Rate = 510 m³/s

Height (h)  = 90 m

We know, that mechanical energy is the sum of potential energy and kinetic energy.

So,

E = [tex]\frac{1}{2}[/tex]×m×v² + m×g×h                    

and energy per mass unit is

E/m =  [tex]\frac{1}{2}[/tex]×v² + g×h

E/m =  [tex]\frac{1}{2}[/tex]×3² + 9.81×90

E/m = 887.4 J/kg

So, mechanical energy per unit mass is 887.4 J/kg.

Power generated is expressed as;

Power generated = energy per unit mass ×rate×density

Density of water = 1000 kg/m³

Power generated = 887.4× 510× 1000

Power generated = 452574000 W

So, the power generated is 452.574 MW.

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Answer:

Zodiac signs

Explanation:

Answer:

The heat from the water deforms the sides because it melts the plastic

The food substance being used which turned Fehling's solution to brick red is a reducing sugar.

This is an indicator which is used to test for the presence of reducing sugar or aldehydes in a solution.

Brick red precipitate of copper(I) oxide is formed when it tests positive to compounds such as glucose etc.

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