Suppose you performed the experiment in atmosphere of Argon at 25 deg. C, (viscosity of argon is 2.26X10^-5 N.s/m^2 at that temperature), and measured terminal speed of 2.64X10^-5 m/s and weight-neutralizing voltage of 35.0 V. How many electrons have been attached to, or detached from the initially neutral plastic sphere

Answers

Answer 1

Following are the calculation to the given question:

Given:

Please find the given question.

To find:

value=?

Solution:

With terminal voltage, no force equals zero.

So,

[tex]\to mg = 6\times \pi \times \eta \times r\times \vartheta \\\\[/tex]

As [tex]35\ V[/tex] is weight neutralizing voltage

[tex]\to mg= q\times v \times r\\\\[/tex]

So,

[tex]\to q\times v \times r= 6 \times \pi \times \eta \times r \times \vartheta \\\\\to q\times v = 6 \times \pi \times \eta \times \vartheta \\\\\to q =\frac{6 \times \pi \times \eta \times \vartheta}{v} \\\\[/tex]

      [tex]=\frac{6 \times 3.14 \times \eta \times 2.64 \times 10^{-5}\ \frac{m}{s}}{35} \\\\=\frac{ 18.84 \times \eta \times 2.64 \times 10^{-5}\ \frac{m}{s}}{35} \\\\=\frac{ 49.7376 \times \eta \times 10^{-5}\ \frac{m}{s}}{35} \\\\=\frac{ 49.7376 \times \eta \times 10^{-5}\ \frac{m}{s}}{35} \\\\ =3.2 \times 10^{-10}\ coulombs[/tex]

Therefore

[tex]\to q= n \times e\\\\[/tex]

Hence n comes to be [tex]2\times 10^9\[/tex] electrons.

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Related Questions

In electronic circuits it is not unusual to encounter currents in the microampere range. Assume a 36 μA current, due to the flow of electrons. Part A What is the average number of electrons per second that flow past a fixed reference cross section that is perpendicular to the direction of flow?

Answers

Answer:

n = 2.25 x 10¹⁴ electrons/s

Explanation:

The amount of electric current is defined as the electric charge passing through an area per unit time. Hence:

I = q/t

where,

I = Current

q = amount of charge

t = time interval

but,

q = ne

therefore,

I = ne/t

where,

n = no. of electrons

e = charge on single electron = 1.6 x 10⁻¹⁹ C

t = 1 s (for electrons passing per second)

I = Current = 36 μA = 3.6 x 10⁻⁵ A

Therefore,

3.6 x 10⁻⁵ A = n(1.6 x 10⁻¹⁹ C)/1 s

n = (3.6 x 10⁻⁵ A)/(1.6 x 10⁻¹⁹ C)

n = 2.25 x 10¹⁴ electrons/s

Enter the expression 2cos2(θ)−1 , where θ is the lowercase Greek letter theta.

Answers

Answer:

[tex]2cos^2(\theta) - 1 = cos(2\theta)[/tex]

Explanation:

Given

[tex]2cos^2(\theta) - 1[/tex]

Required

Simplify

In trigonometry:

[tex]sin^2(\theta) + cos^2(\theta) = 1[/tex]

So; the given expression becomes

[tex]2cos^2(\theta) - (sin^2(\theta) + cos^2(\theta))[/tex]

Open Bracket

[tex]2cos^2(\theta) - sin^2(\theta) - cos^2(\theta)[/tex]

Collect Like Terms

[tex]2cos^2(\theta) - cos^2(\theta)- sin^2(\theta)[/tex]

[tex]cos^2(\theta)- sin^2(\theta)[/tex]

In trigonometry:

[tex]cos(\theta + \theta) = cos^2(\theta)- sin^2(\theta)[/tex]

This implies that:

[tex]cos^2(\theta)- sin^2(\theta) = cos(\theta + \theta)[/tex]

=

[tex]cos(\theta + \theta)[/tex]

[tex]cos(2\theta)[/tex]

Hence:

[tex]2cos^2(\theta) - 1 = cos(2\theta)[/tex]

and aunt travels toward the right along a meter stick. if it starts at the 25.00 cm mark and then travels to the 80.00 cm mark, what is its displacement

Answers

Answer:

displacement = 55 cm

Explanation:

Initial position = 25 cm

Final position = 80 cm

Displacement = final position-finitial position

Putting values in above formula,

D = 80 cm - 25 cm

D = 55 cm

It means that the displacement of the ant is 55 cm.

HELP ASAP CORRECT ANSWER ONLY 10 PTS Collaboration, listening, and negotiating are considered __________ skills. interpersonal mathematical personal verbal

Answers

Answer:

Explanation:

verbal as they are all linked to communication and speaking

Answer: Verbal

Explanation: all three hints are signs of communication.

13.
14. Why does a person feel weightlessness during freefall?​

Answers

Answer:

When in free fall, the only force acting upon your body is the force of gravity - a non-contact force. Since the force of gravity cannot be felt without any other opposing forces, you would have no sensation of it. You would feel weightless when in a state of free fall.

How is newton's third law different from newton's first law

Answers

First law states every object will remain at rest or in a straight line

Third law states that for every action there is an equal and opposite reaction

Hope that’s helps

Answer : Newton's first law of motion (also known as Law of Inertia) describes about the tendency of an object to resist change from its state of rest / motion / direction (inertia).

Whereas, Newton's third law of motion tells us that forces exists in pairs. It talks about the action & reaction forces, which are equal in magnitude but opposite in direction.

In this way, Newton's third law of motion is different from Newton's first law of motion.

A cheetah runs at a constant velocity of 7 m/s. What is it’s acceleration in m/s/s
PLEASE HELP

Answers

Answer:

0 m/s²

Explanation:

Acceleration is the change in velocity over change in time.  If the velocity is constant, then the acceleration is 0.

Which of these is caused by the interaction between the atmosphere and the hydrosphere?

Answers

Answer:

Explanation: All the spheres interact with other spheres. For example, rain (hydrosphere) falls from clouds in the atmosphere to the lithosphere and forms streams and rivers that provide drinking water for wildlife and humans as well as water for plant growth (biosphere).

The space shuttle fleet was designed with two booster stages. If the second stage provides a thrust of 73 ​kilo-newtons and the space shuttle has an acceleration of 16,000 miles per hour squared ​, what is the mass of the spacecraft in units of​ pounds-mass ​?

Answers

Answer:

m = 81281.5 pounds.

Explanation:

Given that,

Force, F = 73 kN

Acceleration of the space shuttle, a = 16000 mi/h²

1 miles/h² = 0.0001241 m/s2

16000 mi/h² = 1.98 m/s²

We need to find the mass of the spacecraft.

According to Newton's second law,

F = ma

m is mass of the spacecraft

[tex]m=\dfrac{F}{a}\\\\m=\dfrac{73\times 10^3\ N}{1.98\ m/s^2}\\\\m=36868.68\ kg[/tex]

Since, 1 kg = 2.20462 pounds

m = 81281.5 pounds

Hence, the mass of the spacecraft is 81281.5 pounds.

What is the term for heat transfer because of the movement of electromagnetic waves?​

Answers

it is radiation that transfers heat energy through space by electro radiation.

An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 17601760 × 103 seconds (about 2.0×1012.0×101 days) on average to complete one nearly circular revolution around the unnamed planet. If the distance from the center of the moon to the surface of the planet is 295.0295.0 × 106 m and the planet has a radius of 3.603.60 × 106 m, calculate the moon's radial acceleration acac .

Answers

Answer:

The value is [tex]a_r = 3.81 *10^{-3} m/s^2[/tex]

Explanation:

Generally the moon's radial acceleration is mathematically represented as

[tex]a_r = r * w^2[/tex]

Here [tex]w[/tex] is the angular velocity which is mathematically represented as

[tex]w =\frac{2 \pi }{ T}[/tex]

substituting [tex]1760 * 10^3 \ seconds[/tex] for T(i.e the period of the moon ) we have

[tex]w =\frac{2 * 3.142 }{ 1760 * 10^3}[/tex]

=> [tex]w = 3.57 *10^{-6} \ rad/s [/tex]

From the question r(which is the radius of the orbit ) is evaluated as

[tex]r = R + H[/tex]

substitute [tex]3.60 * 10^6 m[/tex] for R and [tex]295.0 * 10^6 \ m[/tex] H

       [tex]r =  295.0 * 10^6   +3.60 * 10^6[/tex]

=>   [tex]r =  2.986 *10^{8} \  m [/tex]

So

    [tex]a_r  =   2.986 *10^{8} *  ( 3.57 *10^{-6} )^2[/tex]

      [tex]a_r  = 3.81 *10^{-3} m/s^2[/tex]


Consider the displacement vectors Ā=(i +6j)m, B = (3i– 7j)m,
If A-B-4D=0, what are the components of D? (Dx = ?, and Dy = ?)


Answers

Answer:

Dx = -0.5

Dy = -0.25

Explanation:

Two vectors are given in rectangular components form as follows:

A = i + 6j

B = 3i - 7j

It is also given that:

A - B - 4D = 0

so, we solve this to find D vector:

(i + 6j) - (3i - 7j) - 4D = 0

- 2i - j = 4D

D = - (2/4)i - (1/4)j

D = - (1/2)i - (1/4)j

D = - 0.5i - 0.25j

Therefore,

Dx = -0.5

Dy = -0.25

5.
An object with zero acceleration is not changing its velocity.
TRUE
FALSE

Answers

that answer is true!

A train travels 1000 m south for 100 s. What is the
velocity of the train?

a) 0.1 m/s
b) 0.1 m/s south
c) 10 m/s
d) 10 m/s south

Answers

C. 10 m/s
You divide 1000 m by 100 s.
1000/100 to find the velocity

the two forces acting on a boat or some other floating object _______are and gravity​

Answers

Answer:

The two forces acting on a boat or some other floating object are buoyancy and gravity

Answer: buoyant forceExplanation:two forces acting on a boat or some other floating object are buoyant force and gravityhi friend your answerI hope it will be helpful for you

mark as brainest answer

thank you

Calculate the average speed 

1) between 0 min and 3 min.


2) between 3 min and 5 min. 



3) between 5 min and  10 min 


4) between 0 min and 10 min​

Answers

Answer:

000000000000000000000000000

Convert 2536 mm/min to m/s. Use dimensional analysis.

Answers

Answer:

As we know that,

1 mm/min = 1.66667E-5 m/s1 m/s = 60000 mm/min

Now, come to the question -

[tex] \\ \implies \sf \: 2536 \times 1.66667E-5 m/s \\ \\ \\ \implies \sf \blue{0.0422666667 \:m/s } \\ [/tex]

Result : 2536 mm/min = 0.0422666667 m/s.

a barge is pulled down the canal by a horse walking beside it, if the rope angle is 60.0 degrees, the force exterted is 400N and the barge being pulled is 100N how much work did the horse do

Answers

Answer:

The horse does 20,000 Nm of work.

Explanation:

Using = ∶ (400 ∗ 60°)(100) → The horse does 20,000 Nm of work.

The horse does 20,000 Nm of work.

What is work?

Work is the energy transferred to or from an object via the application of force along a displacement.

In its simplest form, it is often represented as the product of force and displacement.

The work W is equal to the force f times the distance d, or W = fd.

If the force is being exerted at an angle θ to the displacement, the work done is W = f d cos θ.

From the given values,

W = f d cos θ.

W = 400*100 cos60°

W= 20,000 Nm

The horse does 20,000 Nm of work.

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#SPJ2

what does Aristotle say about the good life?Does it still stand contemporary world?

Answers

Answer:

Explanation:

Aristotle was a philosopher and a scientist who believed good life for humans is ultimately about happiness and this happiness can be achieved by virtue or high moral standards.

In the contemporary world, generally, everyone's ultimate goal is still to be happy but achieving this feat by being virtuous or having a high moral standard is fading away in our contemporary world as people just want to be happy by any means possible. Some amass wealth illegally just to be happy while others do things that are considered immoral (by the society) to be happy hence people still want a good life but not a way described by Aristotle.

Aristotle stated that a good life is about happiness and this can only be achieved through high moral standards.

The statement that a good life is about happiness and this can only be achieved through high moral standards doesn't stand anymore in the contemporary world.

People now engage in immoral things as long as it brings them happiness. Even though the ultimate goal of people is to be happy, there are different ways that people go about in achieving this.

There are some people who get their wealth illegally just to ensure that they are happy. This source of happiness is gotten through vices.

In conclusion, Aristotle's statement about the good life is not applicable in the contemporary world anymore.

Read related link on:

https://brainly.com/question/21792802

please help on magnitude !

Answers

Answer:

Yes, the answer is 100 N

Explanation:

Car is pushed right with 150 N and obviously frictional force will act in the opposite direction of the fore provided and that is 50 N

Hence, 150 - 50 is 100 N

Magnitude is 100 N

Direction is Towards the right

Since they asked for Magnitude the answer should be 100 N

The fastest crossing of the Atlantic Ocean by an ocean liner was made on July 7,
1952. The ship, the S.S. United States, traveled 4727 km east by northeast in 3 days,
10 hours, and 40 minutes. Assume that the ship had traveled the same speed, but
directly east. What would the velocity of the S.S. United States be in kilometers per
hour?

Answers

Answer:

The speed would be about 80.8 km/h

Explanation:

Notice that the ship really traveled northeast (at 45 degrees north from East) covering eastwards 4727 km.

That means (by using the East projection in a right angle triangle) that the total distance was  (the hypotenuse of the right angle) :

[tex]Distance= \frac{4727}{cos(45^o)} \approx 6685\,\,km[/tex]

Then the velocity of the ship was the quotient between this distance divided the time it took. Now,notice that the time is given in days, hours, and minutes, but we need the final velocity answer in km per hour. Then we reduce the given time to hours:

3 days + 10 hours + 40 min = 3 (24) h + 10 h + (40/60) h = 248/3 hours which is approximately 82.7 hours.

Then this record speed is the quotient:

6685 km / 82.7 h = 80.8 km/h

360 s to ms? Need help! Converting units, with work pls

Answers

1 s  =  1,000 ms

2 s  =  2,000 ms

3 s  =  3,000 ms

.

.

10 s  =  10,000 ms

20 s  =  20,000 ms

30 s  =  30,000 ms

.

.

.

100 s  =  100,000 ms

200 s  =  200,000 ms

300 s  =  300,000 ms

310 s  =  310,000 ms

320 s  =  320,000 ms

.

.

.

350 s  =  350,000 ms

360 s  =  360,000 ms

370 s  =  370,000 ms

.

.

.

A statement about what happens in nature that seems to be true all the time ES​

Answers

Answer:

their is always a animal or bug in nature

Explanation:

What do the elements in group 17 of the periodic table have in common

Answers

They are toxic and all non metals

What is the kinetic energy when the pendulum is at the halfway point
(height=1 m) when the total mechanical energy is 4 J

Answers

The answer is 0 , hope this helps

An atom’s emission of light with a specific amount of energy confirms that

atoms must have a dense central mass surrounded by electrons at a distance.
electrons emit and absorb energy based on their position around the nucleus.
electrons can only be found within predicted areas surrounding the nucleus.
atoms are made of positive and negative charges.

Answers

The correct answer is B. Electrons emit and absorb energy based on their position around the nucleus.

Explanation:

In general, an atom's emission of photons (light) is the result of electrons, which are the negative charge particles that orbit the nucleus. Moreover, the emission of light is likely to occur if the electron is located at a specific energy level (position in the atom) and it moves to a lower level as this requires the loss of energy in the form of photons. Also, the electron can absorb the photons and as a result gain enough energy to move to a higher level. This implies the atom's emissions of light shows the relationship between electrons emitting and absorbing energy and their position or energy level.

Answer:

The correct answer is B. Electrons emit and absorb energy based on their position around the nucleus.

On edge :)

Explanation:

Please answer the question on the bottom

Answers

Answer:

the one with 2 batteries

Which are best examples of projectile motion

Answers

Answer:

Please add the multiple choice awensers too then I'll get back to you when I can

Answer:

Answer is D

Explanation:

what type of organism does not use photosynthesis
(a) plants
(b) bacteria
(c) algae
(d) humans

Answers

Answer:

D) Humans

Explanation:

Photosynthesis is a useless ability without some way of exposing yourself to as much of the Sun's energy as possible. That requires a large surface area, relative to their volume. Plants achieve that with large, horizontal, light-capturing surfaces – leaves.

5. A projectile is fired in Earth's gravitational field with a horizontal velocity of y = 9.00 m/s.
b. How far does the projectile fall in the vertical direction in 0.550 s?

Answers

Answer:

4.13m

Explanation:

Given

Horizontal velocity = 9.00m/s

time taken = 0.550 s

Required

How far does the projectile fall in the vertical direction

Using the formula for finding the maximum height of the projectile

H = U²sin²θ/2g where;

U = 9.00m/s

θ = 90° (object launched in the vertical direction)

g = 9.81m/s²

Substituting the given parameters into the formula;

H = 9²sin²90/2(9.81)

H = 81(1)/19.62

H = 81/19.62

H = 4.128 m

H ≈ 4.13m

Hence the distance that the projectile fall in the vertical direction is 4.13m

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