Substitute the supplied value and simplify both sides of the equation, if necessary. Then decide if the supplied value is or is not a solution.

m + 2(m + 1) = 14 {4}

The geometric means of the pairs of numbers are approximately:

14.85 for 7.16 and 27

13.42 for 5 and 36

22.94 for 10.8 and 48.

It should be noted that to find the geometric mean of two numbers, we multiply them together and then take the square root of the result. So, for each pair of numbers, we can follow these steps:

Multiply the two numbers together.

Take the square root of the product.

Using this formula, we get:

7.16 and 27:

Geometric mean = √(7.16 × 27) ≈ 14.85

5 and 36:

Geometric mean = √(5 × 36) = √180 ≈ 13.42

10.8 and 48:

Geometric mean = √(10.8 × 48) ≈ 22.94

Therefore, the geometric means of the pairs of numbers are approximately:

14.85 for 7.16 and 27

13.42 for 5 and 36

22.94 for 10.8 and 48.

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The new mixture contains 34% peanuts.

The correct option is A

We have,

Jenny mixed 4 kg of mixed nuts containing 16% peanuts with 12 kg of mixed nuts containing 40% peanuts.

First, Total weight = 4 kg + 12 kg = 16 kg

Now, Total weight in kilograms is =  (4 kg) (0.16) + (12 kg) (0.40)

= 0.64 kg + 4.80 kg

= 5.44 kg.

Now, the Percent of peanuts

= (Total amount of peanuts / Total weight) x 100%

= (5.44 kg / 16 kg) x 100

= 34%

Thus, the new mixture contains 34% peanuts.

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The distance Ben travels to get to the park is approximately 2.21 times greater than the distance David travels. This is found by using the distance formula to calculate the distances each person travels and then comparing the results.

To solve this problem, we need to find the distance between each person's house and the park using the distance formula

distance = √((x₂ - x₁)² + (y₂ - y₁)²)

For Ben

distance = √((-2 - 4)² + (-2 - 6)²) = √((-6)² + (-8)²) = √(100) = 10

For David

distance = √((-2 - (-7))² + (-2 - (-6))²) = √((5)² + (4)²) = √(41)

So the ratio of Ben's distance to David's distance is

10 / √(41) ≈ 2.21

Therefore, Ben's distance is about 2.21 times greater than David's distance.

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The value of the variable is 3/2

A fraction cam simply be described as an expression that is being used to represent the part of a whole number, a whole variable or element.

There are different types of fractions. They are listed as;

From the information given, we have that;

-7 4/5 divided by X = -5 1/5

convert to improper fractions, we have;

-39/5/x = -26/5

Now, cross multiply the values, we have;

-39/5 = -26x/5

cross multiply

-130x = -195

Divide both sides

x = -195/-130

x = 39/26 = 3/2

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Answer:

x = 4[tex]\sqrt{3}[/tex]

Step-by-step explanation:

using Pythagoras' identity in the right triangle

the square on the hypotenuse is equal to the sum of the squares on the other 2 sides , then

x² + 4² = 8²

x² + 16 = 64 ( subtract 16 from both sides )

x² = 48 ( take square root of both sides )

x = [tex]\sqrt{48}[/tex] = [tex]\sqrt{16(3)}[/tex] = [tex]\sqrt{16}[/tex] × [tex]\sqrt{3}[/tex] = 4[tex]\sqrt{3}[/tex]

From the calculation, g increases on the interval [-3, 6) and for 0 ≤ x ≤ 6, g(x) = 6 - 1/2(x-2)^2.

To determine where g is increasing, we need to find where its derivative, g'(x), is positive. We can find g'(x) by differentiating g(x) with respect to x:

g'(x) = f(x)

Since f(x) is a piecewise-defined function, we need to consider each interval separately.

Therefore, g is increasing on the interval [-3, 6).

To justify this, note that g'(x) = 0 at x = 0 and x = 6, where g has local maxima. This means that g is increasing on the intervals (-3, 0) and (0, 6) and decreasing on (6, 9]. Since g is continuous, it cannot have any jumps, so it must be increasing or decreasing on each of these intervals. Since g(-3) = 0 and g(6) = 9, we know that g is increasing on the interval [-3, 6).

We can evaluate g(x) on the interval [0, 6] by integrating f(x) with respect to t from -2 to x:

g(x) = ∫_{-2}^{x} f(t) dt

On the interval [-3, 0), f(t) = 3, so we have:

g(x) = ∫_{-2}^{0} 3 dt + ∫_{0}^{x} (-t + 3) dt

Simplifying the integrals, we get:

g(x) = 6 - 1/2(x-2)^2, for 0 ≤ x ≤ 6

(Note that we can drop the "+C" since it's being evaluated at the limits of integration.)

Therefore, for 0 ≤ x ≤ 6, g(x) = 6 - 1/2(x-2)^2.

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Thus, new coordinates of A'B'C' after the reflection across the y-axis are-

A'(-5, -1), B'(-3,-4), C'(-3, 0).

The x-coordinate remains constant when a point is reflected across the x-axis, but the y-coordinate is assumed to be the additive inverse. Point (x, y) is reflected across the x-axis as (x, -y).

The y-coordinate stays the same when a point is reflected across the y-axis, but the x-coordinate is assumed to be the additive inverse. Point (x, y) is reflected across the y-axis as (-x, y).

Given coordinates of ABC.

A(5, -1), B(3,-4), C(3, 0)

Reflection across the y-axis : y coordinates remains same while x coordinate multiplied with -1.

(x,y) -- > (-x, y)

A'(-5, -1), B'(-3,-4), C'(-3, 0)

Thus, new coordinates of A'B'C' after the reflection across the y-axis are-

A'(-5, -1), B'(-3,-4), C'(-3, 0).

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The solution to the given composite function is; C: 4x² - 4x - 2

From the question, we are given the individual functions as;

f(x) = x² - 3

g(x) = 2x - 1

Now when it comes to composite functions, we know that;

(f ° g)(x) = f[g(x)]

Substitute the known values in the above equation, so, we have the following representation

(f ° g)(x) = f(2x - 1) = (2x - 1)² - 3 = 4x² - 2x - 2x + 1 - 3 = 4x² - 4x - 2

This is the final solution of the composite function expression.

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The solution to the given composite function is; Option D: 2x² - 7

Composite functions are defined as functions where the output of one function is used as the input of another. Wheb we have a function f and another function g, then the function fg(x), said as “ f of g of x”, is the composition of the two functions.

The given functions are:

f(x) = x² - 3

g(x) = 2x - 1

We want to find (g ° f)(x) . We know that:

(g ° f)(x) = g[f(x)]

Thus:

(g ° f)(x) = g(x² - 3)

= 2(x² - 3) - 1

= 2x² - 6 - 1

= 2x² - 7

This is the final result of the composite function expression.

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Answer:

Step-by-step explanation:

The percentage of the people that preferred cooking who where surveyed would be = 87.2%

The total number of people surveyed = 8

The total number of people that preferred cooking = 7

The percentage of people that preferred cooking;

= 7/8×100/1

= 700/8

= 87.2%

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Answer:

  D.  9 clubs

Step-by-step explanation:

Given a stem-and-leaf plot of the number of members in clubs, you want to know the number of clubs with 30 or more members.

The plot shows the club membership to be ...

  {10, 13, 15, 24, 26, 30, 36, 39, 50, 55, 59, 61, 66, 78}

The 9 clubs whose member numbers are in bold have at least 30 members.

The number of clubs with at least 30 members is ...

  D.  9 clubs

<95141404393>

To find the LCM of 24 and 6, we can use the prime factorization method.

First, we find the prime factorization of each number:

24 = 2 x 2 x 2 x 3

6 = 2 x 3

Then, we identify the highest power of each prime factor that appears in either number.

The prime factor 2 appears three times in 24, but only once in 6. Therefore, we take the highest power of 2, which is 2 x 2 x 2 = 8.

The prime factor 3 appears once in both numbers, so we take the highest power of 3, which is 3.

Finally, we multiply these together to get the LCM:

LCM(24, 6) = 8 x 3 = 24

Therefore, the LCM of 24 and 6 is 24.

~~~Harsha~~~

Answer: LCM of  24 and 6 is 24

Step-by-step explanation:

Answer: 300

Step-by-step explanation:

10*8*6=480-6*6*5=180=300

Answer:

7 ÷ 2 = 3.5, so 2:7 = 1:3.5 (1 to 3.5).

Answer:

1 : 3.5

Step-by-step explanation:

2: 7 written in the ratio 1 : n...

2:7

1:n

To get to 1 from 2 you have to divide by 2.

So do the same for 7.

Therefore the answer is 1: 3.5

Answer:

[tex]x=\pm\sqrt{\frac{2}{7}} \text{ and }x=\pm i\sqrt{\frac{2}{7}}[/tex]

(real solution)       (imaginary solution)

Step-by-step explanation:

For these type of questions, where the exponent is even, it helps to try to rewrite the equation into a quadratic equation as we have a closed formula (quadratic formula) to solve for the zeroes, and it's also just easier to deal with in general.

Let's say that: [tex]u=x^2[/tex], now if we square both sides, [tex]u^2=x^4[/tex], so from here we can substitute in u squared as x to the power of four.

This results in our following equation: [tex]49u^2-4[/tex], from here we could use the quadratic formula, but you may notice a pattern here. We have a difference of squares: [tex]a^2-b^2=(a-b)(a+b)[/tex]

[tex]49u^2[/tex] can be written as [tex](7u)^2[/tex] and [tex]4[/tex] can be written as [tex]2^2[/tex], this gives us our equation: [tex](7u)^2-2^2\implies (7u-2)(7u+2)[/tex]. If we use this definition of the equation on the left side, it gives us: [tex](7u-2)(7u+2)=0[/tex] and this is very convenient as we can solve both of them individually.

Whenever we multiply any number (assuming it's defined) by zero, we should get.... zero. This intuitively makes sense as no matter how many times we add zero up (multiplication is repeated addition), we're always just going to have zero.

So when we have the equation: [tex]a*b=0[/tex], if "a" is zero then regardless of what "b" is (assuming it's defined), then the product will be zero. If "b" is zero then regardless of what "a" is (assuming it's defined), then the product will be zero.

Now if we look back at our equation: [tex](7u-2)(7u+2)=0[/tex], if [tex]7u-2=0[/tex], then regardless of what [tex]7u+2[/tex] is equal to, the product will be zero. Likewise, if [tex]7u+2=0[/tex] then regardless of what [tex]7u-2[/tex] is equal to, the product will be zero, thus making the equation true.

So to find the solutions to this, we find what makes [tex]7u-2=0 \text{ and }7u+2=0[/tex] true. If we work them both out individually we

get:

[tex]7u-2=0\\7u=2\\u=\frac{2}{7}\\\\7u+2=0\\7u=-2\\u=-\frac{2}{7}[/tex]

So now we have our two solutions right? Well remember we started off with a "x" variable, and the "u" is merely a substitution. If you recall, the "u" value is set equal to "x^2", so we can just plug that back in, so we can find the solutions in terms of x.

[tex]x^2=\frac{2}{7} \text{ and } x^2=-\frac{2}{7}[/tex]

If we take the square root of both sides, we get:

[tex]x=\pm\sqrt{\frac{2}{7}} \text{ and }x=\pm\sqrt{-\frac{2}{7}}[/tex]

you'll notice in one of them, we're taking the square root of a negative number. This will result in imaginary solutions, if we factor out a "-1" and take the square root of that, we'll just get an "i" infront, giving us the solutions of: [tex]x=\pm\sqrt{\frac{2}{7}} \text{ and }x=\pm i\sqrt{\frac{2}{7}}[/tex].

Answer: (440-308) ÷ 22 = The cost of each tool kit is 6 dollars

Step-by-step explanation:

The original price of the field trip was $308 after the price fof each tool kit was added the price was $440.

The total costs of all the tool kits was 132

440-308=132

the total cost of the tool kits divided by the number of kids will get the price of each tool kit

132÷22 =

K=

Answer:

Work smartly not hard.

Step-by-step explanation:

AI

Answer: B

Step-by-step explanation:

The word that would indicate that the cat was afraid of the veterinarian is "cowered." "Cowered" means to crouch down in fear or shame. So, the sentence would be: "The cat cowered under the table when the veterinarian came into the examining room."

The inequalities for the given word problems are:

g) p/q ≤ 6

h) 1/w ≥ 9

Inequality word problems are statements or words used to describe specific inequalities.

g) We are told that the quotient of p and q is at most 6. Thus, it is a maximum of 6. Therefore, we can write the inequality as:

p/q ≤ 6

h) We are told that the reciprocal of w is at least 9. Thus, the inequality is expressed as:

1/w ≥ 9

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The number of triangles that are displayed can be found to be 216 triangles.

Each rectangular tile has a decorative pattern of 3 equal-sized squares, and each square is divided into 2 same-sized triangles. Therefore, each tile has 3 squares * 2 triangles per square = 6 triangles.

Marnie uses 36 of these tiles on the wall behind her kitchen stove. To find the total number of triangles displayed, multiply the number of triangles per tile by the total number of tiles:

Total triangles = 6 triangles per tile x 36 tiles = 216 triangles

So, there are 216 triangles displayed on the wall behind Marnie's kitchen stove.

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Answer:

Step-by-step explanation:

The correct option is (D) A, B, C, E, G, I

What is the cube?

A cube is a three-dimensional solid shape that has six square faces of equal size. It has twelve edges and eight vertices, and all angles between the faces are right angles. The cube is a regular polyhedron, which means that all its faces are congruent and all its edges have the same length.

The net of a cube is the one that has the faces arranged in such a way that it makes a complete cubic structure

A) In the given figure, the net cannot be folded into a cube by folding the six faces of the net. Therefore, it is not a cube net.

B)  In the given figure, the net cannot be folded into a cube by folding the six faces of the net. Therefore, it is not a cube net.

C) In the given figure, the net cannot be folded into a cube by folding the six faces of the net. Therefore, it is not a cube net.

D) In the given figure, the net can be folded into a cube when its faces are folded one over the other. Therefore, it is a cube net.

Hence, The correct option is (D) A, B, C, E, G, I.

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The formula for tension (T) in terms of extension (x) is T = 25x.

The given statement is T = kx, where T is the tension, x is the extension, and k is the proportionality constant.

To solve this problem, we need to find the value of k. We can do that by substituting the given values of T and x into the equation:

T = kx

150 = k×6

k = 25

Therefore, the formula for tension (T) in terms of extension (x) is T = 25x.

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The angle AOB is approximately 98 degrees.

The measure of the angle AOB of the sector can be found as follows:

AOB is the central angle.

Therefore,

length of an arc = ∅ / 360 × 2πr

where

Therefore,

12 = ∅ / 360 × 2 × 3.14 × 7

12 = 43.96∅ / 360

cross multiply

360 × 12 =  43.96∅

4320 = 43.96∅

divide both sides by 43.96

∅ = 4320 / 43.96

∅ = 98.271155596

Therefore,

∅ = 98 degrees

AOB = 98 degrees

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The P-value is between 0.025 and 0.05. and t = -1.85

On the SAT exam a total of 25 minutes is allotted for students to answer 20 math questions without the use of a calculator.

Therefore tests the hypotheses:

[tex]H_0[/tex] : μ = 25 versus Ha: μ < 25,

where μ = the true mean amount of time needed by students at this school to complete this portion of the exam.

The alternative hypothesis is:

[tex]H_1:\mu < 25[/tex]

The test statistic is given by:

[tex]t=\frac{x-\mu}{\frac{s}{\sqrt{n} } }[/tex]

The parameters are:

the values of the parameters are:

x = 23.5 , [tex]\mu=25[/tex] , s = 4.8, n = 35

Plug all the values in above formula of t- statistic is:

[tex]t = \frac{23.5-25}{\frac{4.8}{\sqrt{35} } }[/tex]

t = -1.85

Using a t-distribution , with a left-tailed test, as we are testing if the mean is less than a value and 35 - 1 = 34 df, the p-value is of 0.0365.

t = –1.85; the P-value is between 0.025 and 0.05.

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number one take the second

Part A: A

Part B: Julia collected 18.65, Keller collected 61.15, and Israel collected 45.15

Answer:

The answer for Probability is 1/2

Step-by-step explanation:

7,6,8,1,54,23

Probability of spinning an odd number greater than 3=1,7,23

P=3/6

P=1/2

Answer:

yes it is if you bisect 5m on a 12m line