Show the proper algebraic steps to solve 5x + 34 = 2(1 -7x)

Answer:

1.429 × 10^-3

Step-by-step explanation:

since it's below 1, you're moving the decimal to the right, which makes the 3 negative.

Answer: The answer i think is A

Step-by-step explanation:45w stands for how much she paid each week, while 123.95 stands for a one time payment

This all should equal 753.95 which is how much they paid in total.

Step-by-step explanation:

Given

X+ 2 = 0

X = -2

on putting in polynomial

-8a +2b= 0

- 8a = 2b

b = -4a

Now

when divided by x - 1 give remainder -15

so

x - 1 = -15

x = -14

on putting in polynomial

-2744a + 198 + 14b - 4 = -14

-2744a + 56a = - 208

-2688a = -208

a = 168/13

Now

b = 672/13

Answer:

D -$7.20

Step-by-step explanation:

so your answer is -$7.20

I hope this helps

$7.20 will be Jennys total allowance.

It is a method where we find the value of a single unit from the value of multiple units and the value of multiple units from the value of a single unit.

Steps to Use Unitary Method

First, let us make a note of the information we have. There are 5 ice-creams. 5 ice-creams cost $125.

Step 1: Let’s find the cost of 1 ice cream. In order to do that, divide the total cost of ice-creams by the total number of ice-creams. The cost of 1 ice-cream = Total cost of ice-creams/Total number of ice-creams = 125/5 = 25. Therefore, the cost of 1 ice cream is $25.

Step 2: To find the cost of 3 ice-creams, multiply the cost of 1 ice cream by the number of ice-creams. The cost of 3 ice-creams is cost of 1 ice-cream × number of ice-creams = 25 × 3 = $75. Finally, we have the cost of 3 ice-creams i.e. $75.

Given:

Jenny has $2.40 deducted from her monthly allowance every time she forgets to do a chore.

If she forgets three times in a month.

Thus, Jennys total allowance will be

=2.40 x 3

=$7.20

Hence, $7.20 will be Jennys total allowance.

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Answer:

Step-by-step explanation:

Answer:

.A -42+(-17)

Step-by-step explanation:

Answer:  see proof below

Step-by-step explanation:

Given: A + B + C = π              → A + B = π - C

                                              → B + C = π - A

                                              → C + A = π - B

                                              → C = π - (B +  C)

Use Sum to Product Identity:  cos A + cos B = 2 cos [(A + B)/2] · cos [(A - B)/2]

Use the Sum/Difference Identity: cos (A - B) = cos A · cos B + sin A · sin B

Use the Double Angle Identity: sin 2A = 2 sin A · cos A

Use the Cofunction Identity: cos (π/2 - A) = sin A

Proof LHS → Middle:

[tex]\text{LHS:}\qquad \qquad \cos \bigg(\dfrac{A}{2}\bigg)+\cos \bigg(\dfrac{B}{2}\bigg)+\cos \bigg(\dfrac{C}{2}\bigg)[/tex]

[tex]\text{Sum to Product:}\qquad 2\cos \bigg(\dfrac{\frac{A}{2}+\frac{B}{2}}{2}\bigg)\cdot \cos \bigg(\dfrac{\frac{A}{2}-\frac{B}{2}}{2}\bigg)+\cos \bigg(\dfrac{C}{2}\bigg)\\\\\\.\qquad \qquad \qquad \qquad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{A-B}{4}\bigg)+\cos \bigg(\dfrac{C}{2}\bigg)[/tex]

[tex]\text{Given:}\qquad \quad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{A-B}{4}\bigg)+\cos \bigg(\dfrac{\pi -(A+B)}{2}\bigg)[/tex]

[tex]\text{Sum/Difference:}\quad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{A-B}{4}\bigg)+\sin \bigg(\dfrac{A+B}{2}\bigg)[/tex]

[tex]\text{Double Angle:}\quad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{A-B}{4}\bigg)+\sin \bigg(\dfrac{2(A+B)}{2(2)}\bigg)\\\\\\.\qquad \qquad \qquad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{A-B}{4}\bigg)+2\sin \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{A+B}{4}\bigg)[/tex]

[tex]\text{Factor:}\quad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\bigg[ \cos \bigg(\dfrac{A-B}{4}\bigg)+\sin \bigg(\dfrac{A+B}{4}\bigg)\bigg][/tex]

[tex]\text{Cofunction:}\quad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\bigg[ \cos \bigg(\dfrac{A-B}{4}\bigg)+\cos \bigg(\dfrac{\pi}{2}-\dfrac{A+B}{4}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{A-B}{4}\bigg)+\cos \bigg(\dfrac{2\pi-(A+B)}{4}\bigg)\bigg][/tex]

[tex]\text{Sum to Product:}\ 2\cos \bigg(\dfrac{A+B}{4}\bigg)\bigg[2 \cos \bigg(\dfrac{2\pi-2B}{2\cdot 4}\bigg)\cdot \cos \bigg(\dfrac{2A-2\pi}{2\cdot 4}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =4\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi-B}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi -A}{4}\bigg)[/tex]

[tex]\text{Given:}\qquad \qquad 4\cos \bigg(\dfrac{\pi -C}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi-B}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi -A}{4}\bigg)\\\\\\.\qquad \qquad \qquad =4\cos \bigg(\dfrac{\pi -A}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi-B}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi -C}{4}\bigg)[/tex]

LHS = Middle [tex]\checkmark[/tex]

Proof Middle → RHS:

[tex]\text{Middle:}\qquad 4\cos \bigg(\dfrac{\pi -A}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi-B}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi -C}{4}\bigg)\\\\\\\text{Given:}\qquad \qquad 4\cos \bigg(\dfrac{B+C}{4}\bigg)\cdot \cos \bigg(\dfrac{C+A}{4}\bigg)\cdot \cos \bigg(\dfrac{A+B}{4}\bigg)\\\\\\.\qquad \qquad \qquad =4\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{B+C}{4}\bigg)\cdot \cos \bigg(\dfrac{C+A}{4}\bigg)[/tex]

Middle = RHS [tex]\checkmark[/tex]

Answer:

x=3

Step-by-step explanation:

10-3x+8x=25

-10            -10

-3x+8x=    15

5x=15

5x/5=15/5

x=3

Answer:

3.6

Step-by-step explanation:

Step 1: Find out what 48 ÷ 5 is

9.6

Step 2: Subtract 6 from 9.6

3.6

Answer: 4:3

Step-by-step explanation: Because there are 4 game app for every 3 educational app.

Answer:

Yes

Step-by-step explanation:

The smaller the negative number, the greater it is. i.e., -230 < -9.

Answer:

yes

Step-by-step explanation:

it is closer to zero on a number line, therefore the value of -4 is higher even though it's negative

Answer:

177.2 i think

Step-by-step explanation:

Answer:

A would be the anwser

Step-by-step explanation:

Answer:  A. 72.07

Step-by-step explanation: Plato

Answer:

10

Step-by-step explanation:

In a polygon

interior angle + interior angle = 180°, thus

exterior angle = 180° - 144° = 36°

The sum of the exterior angles in a polygon = 360°, thus

number of sides = [tex]\frac{360}{36}[/tex] = 10

Answer:

10 sides

Step-by-step explanation:

A decagon is a 10-sided polygon, with 10 interior angles, and 10 vertices which is where the sides meet. A regular decagon has 10 equal-length sides and equal-measure interior angles. Each angle measures 144° and they all add up to 1,440°.

Answer:

I hope it will help you :)

Answer:

6! = 720

3! - 2! = 12

6!/3!= 120

Step-by-step explanation:

just finished the assignment.

Answer:

1.

v = 12

-10.9 + 4v

-10.9 + 4(12)

-10.9 + 48

= 37.1

Answer:6x=

2=

X=1.5

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Expand (x+5)^2 through binomial expansion and you get x^2+10x+25.

Break up the problem into little pieces like (x-5)(x+5) and 10(x+5)

Solve the first piece (x-5)(x+5) by doing something like FOIL.

x^2-25

Do the second piece

10x+50

When you add them together, it becomes x^2+10x+25, and (x+5)^2=(x-5)(x+5)+10(x+5).

Answer:

Step-by-step explanation:

Here is a picture of the answer, since I couldn't put into words!

The mass of 15 liters of oil is 13.65 kg.

Arithmetic operations can also be specified by the subtract, divide, and multiply built-in functions.

The operator that performs the arithmetic operations are called arithmetic operators.

* Multiplication operation: Multiplies values on either side of the operator

For example 4*2 = 8

/ Division operation: Divides left-hand operand by right-hand operand

For example 4/2 = 2

Density is the ratio of the mass of the body to the volume of the body.

Density = Mass / Volume

Given that oil has a density of 0.91 grams per milliliter

To determines the mass, in kilograms, of 15 liters of this oil

Rearranging the equation,

Mass = Density × Volume

∵ 15 liters = 15000 milliliters (ml)

So, 0.91g/ml x 15000ml = 13650g

∵ 1 kilogram = 1000grams

⇒ 13650g / 1000g/kg

⇒ 13.65kg

Thus, the mass of 15 liters of oil is 13.65kg.

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Answer:

20

Step-by-step explanation:

Substitute x = 6 into f(x), that is

f(6) = 2(6) + 8 = 12 + 8 = 20

Answer:

6.68, 13.37, 14.95

Step-by-step explanation:

One of the legs is twice as long as the other.

b = 2a

The perimeter is 35.

35 = a + b + c

The triangle is a right triangle.

c² = a² + b²

Three equations, three variables.  Start by plugging the first equation into the second and solving for c.

35 = a + 2a + c

c = 35 − 3a

Now plug this and the first equation into the Pythagorean theorem:

(35 − 3a)² = a² + (2a)²

1225 − 210a + 9a² = a² + 4a²

1225 − 210a + 4a² = 0

Solve with quadratic formula:

a = [ -(-210) ± √((-210)² − 4(4)(1225)) ] / 2(4)

a = (210 ± √24500) / 8

a ≈ 6.68 or 45.82

Since the perimeter is 35, a = 6.68.  Therefore, the other sides are:

b ≈ 13.37

c ≈ 14.95

Answer:

Step-by-step explanation:

I believe it is

Adding -4x - 3 to both sides

Simplifying

Answer is - 3

Answer:

x + 3

Step-by-step explanation:

5x + 3 - 4x

(5x - 4x) + 3

x + 3

Best of Luck!

Answer:

The Answer is 2(3x^10-2) Hope this helps :)

-by-step explanation:

Answer:

work is attached and shown

The coordinate of point B will be (3, -8) for the given line segment.

A pair of numbers that employ the horizontal and vertical distinctions from the two reference axes to represent a point's placement on a coordinate plane. typically expressed by the x-value and y-value pairs (x,y).

Coordinates are always written in the form of small brackets the first term will be x and the second term will be y.

For example (5,3) here 5 will be for the x and 3 will be for the y.

Another example is (9,0) here 9 is for x and 0 is for y.

Given the line segment, AB

If the M(2, -1) is the midpoint of A(1,6) and B(x,y)

Then,

(1 + x)/2 = 2 ⇒ x = 3

(6 + y)/2 = -1 ⇒ y = -8

So B(3, -8).

Hence "The coordinate of point B will be (3, -8) for the given line segment".

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