Answers
The descending order of the strength of the conjugate bases of the given acids is as follows:
H₂OHBrOHClOHNO₃What are conjugate bases?Conjugate bases are substances formed when an acid donates its proton.
The strength of the conjugate bases formed from an acid is the inverse of the acid dissociation constant, Ka, of the acid.
The acid dissociation constant, Ka, of the given acid are given below:
The acid dissociation constant, Ka, of hypobromous acid, HBrO, is 2.3 * 10⁻⁹
The acid dissociation constant, Ka, of trioxonitrate (v) acid, HNO₃ is 2.4 * 10¹
The acid dissociation constant, Ka, of water, H₂O, is 1.8 x 10⁻¹⁶
The acid dissociation constant, Ka, of Hypochlorous acid, HClO, is 3.0 x 10⁻⁸
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Related Questions
which of the following represents the reaction of a strong acid with water? a generic acid, ha, is used in the reactions.
Answers
The chemical equation of the generic acid is
HA(aqueous) + H2O(liquid) → H3O⁺(aqueous) + A⁻(aqueous)
The generic acid formula is H₂GO₃, formed from two hydrogen ions (2 H⁺) and one product ion (GO₃²⁻). It is liquid at room temperature. Being generic, it does not have a defined melting point or boiling point, molar mass, pH, LD50, or many other properties. However, it is a weak acid. If you want a stronger acid, the hydrogen acid is stronger. It is the most famous generic compound. It's often used in fiction when writers don't want to indicate a certain kind of acid. Fictitious generic acids may have unrealistic properties, and using generic acids prevents authors from claiming that real substances do the impossible. The reaction of the generic acid is given above.
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A zinc sample (work function is 4.3 eV) is struc k by light at 200 nm. What happens if the intensity of the light is tripled O The number of ejected electrons is tripled O The kinetic energy of the ejected electrons is tripled O The number of ejected electrons decreases by 1/3 O No change is observed because light at 200 nm is not enough to cause electrons to be ejected O The kinetic energy of the ejected electrons decreases by 1/3
Answers
If the intensity of the light is tripled, then the number of ejected electrons decreases by 1/3.
The energy E of a photon is equal to hv = hc/λ, where v is the frequency of the electromagnetic radiation and λ is its wavelength.
The given parameter is:
lambda = 2*10^-7 m
E = h*c/lambda
=(6.626*10^-34 J.s)*(3.0*10^8 m/s)/(2*10^-7 m)
= 9.939*10^-19 J
E = 9.939*10^-19 J
= 9.939*10^-19/(1.602*10^-19) eV
= 6.204 eV
Since, this is more than 4.3 eV, electron will be ejected.
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which of the following characteristics best determines the composition of the initial filtrate produced in the nephron? group of answer choices only water enters the nephron only large molecules enter the nephron only small molecules enter the nephron only wastes enter the nephron all molecules freely enter the nephron
Answers
Characteristics best determines the composition of the initial filtrate produced in the nephron Only small molecules enter the nephron.
The filtrate produced by the glomerulus moves directly from the glomerulus to Bowman's capsule. The filtrate contains some small molecules present in the blood. So, in addition to waste products, there are nutrient molecules and water, which are also removed by the nephron as filtrate.
Small molecules can pass through the intercellular space of the glomerulus and Bowman's capsule. These small molecules can pass through as filtrate, and some specific molecules within them are reabsorbed by the body as they are required for specific bodily functions.
Internal filtrate molecules are made up of these chemical elements in the body, only the larger molecules from the blood cannot enter the system.
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the solution is known to contain an inorganic salt of one of the following elements. the solution is colorless. the solution contains a salt of
Answers
Simple electrolyte compounds are diluted solutions to form inorganic salt solutions. In abrasive machining, mineral salt solutions are utilised to cool the operation and stop rust and corrosion of the machinery and finished goods.
What components make up inorganic salts?In contrast to an organic salt, which has C-H bonds, an inorganic salt is one that does not. The chemical compound sodium chloride, which is made up of sodium and chloride ions, is one of the most well-known salts. For life to exist and flourish, inorganic salts are necessary.
An "Acidic Salt" is a salt that results from the interaction between a strong acid and a weak base.
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a solution of the chloride salt, hbcl, of the weak base b will have a. a ph less than 7 b. greater than 7 c. equal to 7
Answers
Strong bases and weak acids can hydrolyze into salts, raising the pH level over 7. Ammonium chloride (NH 4 Cl) is a salt whose solution has a pH of less than 7.
The pH will be less than seven when the solution is acidic and higher than seven when the solution is basic. Because Na2CO3 is a salt comprising a strong base and a weak acid, it will produce the highest pH in water. The pH scale determines how acidic or basic water is. The range is 0 to 14, with 7 representing neutrality. Acidity is indicated by pH values below 7, whereas baseness is shown by pH values above 7. In reality, pH is a measurement of the proportion of free hydrogen and hydroxyl ions in water.
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The particulate model below represents the redox reactions that produce energy from fuel cells. Use the model to answer the following questions.Part 1 Write a balanced half-cell equation for the reaction occurring at the anode. Ignore phases in the reaction.
Part 2 Write a balanced half-cell equation for the reaction occurring at the cathode. Ignore phases in the reaction.
Assuming excess oxygen, how many moles of electrons would be transferred if 3 moles of H2 were reacted. moles of electrons
Answers
Answer:
To answer this question, you need to first write the balanced half-cell equations for the reactions occurring at the anode and the cathode.
At the anode, the reaction is:
H2 → 2H+ + 2e-
At the cathode, the reaction is:
1/2O2 + 2H+ + 2e- → H2O
Then, assuming that there is excess oxygen, we can calculate the number of moles of electrons that would be transferred if 3 moles of H2 were reacted. To do this, we need to first determine how many moles of H+ ions are produced when 3 moles of H2 are reacted at the anode. This can be calculated using the balanced half-cell equation for the anode reaction, which shows that 2 moles of H+ ions are produced for every mole of H2 reacted. Therefore, 3 moles of H2 would produce 6 moles of H+ ions.
Next, we can use the balanced half-cell equation for the cathode reaction to calculate how many moles of electrons are transferred when 6 moles of H+ ions are reacted. This equation shows that 2 moles of electrons are transferred for every mole of H+ ions that is reacted. Therefore, 6 moles of H+ ions would result in the transfer of 12 moles of electrons.
Therefore, the final answer is:
12 moles of electrons would be transferred if 3 moles of H2 were reacted.
The protease papain, which can be isolated from papaya fruit, is a monomer with a single active site per protein molecule. The activity of purified papain was measured at various substrate concentrations and plotted on the Lineweaver burk plot below. Considering that the enzyme concentration is 1.2 x 10-7 M, answer the following questions 35 30 25 20 15 10 10 5 0 5 2025, 30 mM) Substratel A) Calculate Km for this substrate B) Calculate Vmax C) Calculate Keat D) Based on the Kea/ Km is this a good substrate for the enzyme E) What fraction of the total enzyme has substrate bound when the substrate concentration 2.5 x 104 M?
Answers
Km for this substrate Is 2 mM. Vmax of the substance is 14.9995 mM/s. The value of Kea for this enzyme is approximately 1.249 x 10^6 M^-1*s^-1. For this enzyme kea to km is very high ratio, indicating that the enzyme is a good substrate for the enzyme.
To calculate Km from a Lineweaver-Burk plot, you need to find the substrate concentration at which the reciprocal of the substrate concentration (1/[S]) is equal to the reciprocal of the initial velocity (1/V0). This point is called the point of inflection on the Lineweaver-Burk plot. In this case, the point of inflection is located at a substrate concentration of approximately 20 mM. At this point, the reciprocal of the substrate concentration is 1/[S] = 1/20 mM = 0.05, and the reciprocal of the initial velocity is 1/V0 = 0.1. To calculate Km, you can use the equation: Km = (1/V0) / (1/[S]) Plugging in the values, you get: Km = (1/V0) / (1/[S]) = 0.1 / 0.05 = 2 mM The value of Km for this substrate is 2 mM. To calculate Vmax, you can use the equation: Vmax = V0 / (1 + Km/[S]). Where Vmax is the maximum initial velocity, V0 is the initial velocity, Km is the Michaelis constant, and [S] is the substrate concentration. Aa substrate concentration of 2.5 x 10^4 mM, the initial velocity is approximately 15 mM/s. Plugging in the values, you get: Vmax = 15 mM/s / (1 + 2 mM / 2.5 x 10^4 mM) = 15 mM/s / (1 + 8 x 10^-4) = 15 mM/s / 1.00008 = 14.9995 mM/s The value of Vmax for this enzyme is approximately 14.9995 mM/s. To calculate Kea, you can use the equation: Kea = Vmax / [E] Where Kea is the catalytic constant, Vmax is the maximum initial velocity, and [E] is the enzyme concentration. Plugging in the values, you get: Kea = 14.9995 mM/s / (1.2 x 10^-7 M) = 1.249 x 10^6 M^-1*s^-1 The value of Kea for this enzyme is approximately 1.249 x 10^6 M^-1*s^-1. The ratio of Kea to Km is a measure of the efficiency of the enzyme-substrate complex. A high ratio indicates that the enzyme is a good substrate for the enzyme, while a low ratio indicates that the enzyme is a poor substrate for the enzyme. In this case, the ratio of Kea to Km is approximately 1.249 x 10^6 M^-1s^-1 / 2 mM = 6.245 x 10^4 M^-1s^-1. This is a very high ratio, indicating that the enzyme is a good substrate for the enzyme.
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For each of the following categories of compounds, indicate the type of liquid chromatography that could be used to separate analytes in that category. (Drag the appropriate chromatography label to the blank next to the category. Only one label applies to each category, but a label may be used more than once).
Seperation Mode Analyte Category
Fm>2000,soluble in octane,size10 nm
Fm>2000, soluble in butanol, size 100 nm
Fm>2000, soluble in water,nonionic,size 10 nm
Fm<2000, soluble in in ethanol
Fm<2000 , soluble in water, ion-paired
Fm<2000, soluble in water, ionic
Choices:
ion -exchange
Bonded-reverse phase
Adsorption
Bonded normal phase
Molecular exculsion
Answers
The appropriate types of chromatography for the labels are:
Fm>2000, octane soluble, size 10 nm: Bonded normal phase
Fm>2000, butanol soluble, size 100 nm: Bonded normal phase
Fm>2000, water soluble, non-ionic, size 10 nm: Adsorption
Fm<2000, ethanol soluble: Bonded reverse phase
Fm<2000, water soluble, ion paired: Ion exchange
Fm<2000, water soluble, ionic: Ion exchange
Liquid chromatography is a separation technique that uses liquid stationary and mobile phases to separate and purify compounds. There are many different types of liquid chromatography, each with different stationary phases and separation mechanisms.
In ion-exchange chromatography, the stationary phase consists of ionizable groups that interact with ions in the mobile phase. This type of chromatography is used to separate charged molecules such as ions and ion-pair compounds.
In adsorption chromatography, the stationary phase consists of solid adsorbents like Silica or alumina that interacts with the analyte via van der Waals forces, dipole-dipole interactions, or hydrogen bonding. This type of chromatography is used to separate compounds based on their affinity for the stationary phase.
In normal-phase chromatography, the stationary phase is a non-polar material such as silica or alumina, and the mobile phase is a polar solvent such as water or methanol. This type of chromatography is used to separate non-polar compounds based on their affinity for the stationary phase.
In reversed-phase chromatography, the stationary phase is a polar material such as octadecyl silica or cyanide-bonded silica, and the mobile phase is a non-polar solvent such as hexane or methylene chloride. This type of chromatography is used to separate polar compounds based on their affinity with the stationary phase.
Molecular exclusion chromatography, also called size exclusion chromatography, is a type of chromatography that separates molecules based on their size. The stationary phase consists of porous spheres with different pore sizes, and molecules are separated based on their ability to penetrate the pores. This type of chromatography is used to separate molecules with molecular weights greater than 2,000 Daltons.
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how many of the following salts are expected to be insoluble in water sodium sulfate barium nitrate ammonium sulfate potassium phosphate
Answers
The Insoluble Substance is Barium Nitrate
BANO4
Solubility rules for chromate (CrO₄²⁻) are all chromate are insoluble, except for ions group 1 (Li⁺, Na⁺, K⁺). So soluble chromate are
Li₂CrO₄
Na₂CrO₄
K₂CrO₄
Potassium chromate K₂CrO₄ is soluble.
A substance is said to be insoluble if it doesn't change when placed in water.
When introduced to water, soluble compounds typically form one continuous phase (eg when salt is added to water).
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A student determines the value of the equilibrium constant to be 6.54×103 for the following reaction. CO(g) + H2O(l)CO2(g) + H2(g) Based on this value of Keq: G° for this reaction is expected to be (greater, less) than zero. Calculate the free energy change for the reaction of 2.32 moles of CO(g) at standard conditions at 298K. G°rxn = kJ
Answers
A. Co + H₂O ⇄ co₂+ H₂
= -8.314[tex]\frac{J}{K.mol}[/tex] x298k x In (6.54x16³)
= -21.77 kJ/m0/
for 2.32 molco, A = -21.77×2-32
= -50.51kj/mol
B. Fe₂03(5) +3H₂(9) ⇄ 2 Fe(s) + 3H₂0(9)
= -8.314 × 298x/n (2.47x10⁻¹⁰)
= +54.807 kJ/mol
for 1.61 mol fe₂03, Δ4= 54.807 X 1.61 mol
= 88.24 kJ/mol.
Equilibrium constant numbers are obtained by allowing a single reaction to reach equilibrium and measuring the concentrations of each substance involved in the reaction. The ratio of product concentration to educt concentration is calculated. A mathematical ratio indicating product concentration divided by reactant concentration.
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the electron geometry of a moeluclar who has a central atom with four single bonds and one lone pair of electrons is which of the following
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The molecular geometry of a molecule whose central atom has four single bonds and two lone pairs of electrons is square planar.
The shape of the orbitals is octahedral. Two orbitals contain lone pairs of electrons on opposite sides of the central atom. The remaining four atoms connected to the central atom give the molecule a square planar shape. If there are only two bonds and one lone pair of electrons holding the place where a bond would be then the shape becomes bent. For sp3 hybridized central atoms the only possible molecular geometry is tetrahedral. If all the bonds are in place the shape is also tetrahedral.
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In a set of experiments on a hypothetical one-electron atom, you measure the wavelengths of the photons emitted from transitions ending in the ground state (n=1) as shown in the energy-level diagram in the figure (Figure 1). You also observe that it takes 17.50 eV to ionize this atom.
Answers
The wavelength of the photon that is emitted from transitions ending in the ground state is 397.56 nm
E(n) = - k/n^2
In fact, since the ionization energy (from ground state) is:
-E(1), E(n) = - (17.5 eV)/n^2
E(1) = -17.5 eV
E(2) = -4.375 eV
E(3) = -1.94 eV .
E(4) = -1.094 eV
E(5) = - 0.7 eV
The change in energy going from n = 4 to n = 2 will be:
E(4) - E(2) = 3.281 eV
The change in energy = hc/∧, so
∧ = h/energy-change
= 6.626 x 10-34 x 3 x 108 /(3.281 x 1.6022 x 10-19 J)
= 397.56 x 10-9 m
= 397.56 nm
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select the statements that describe important rules for drawing skeletal structures. multiple select question. draw in all heteroatoms and the hydrogens directly bonded to them. draw in all heteroatoms and any lone pairs of electrons connected to them. assume there is a carbon atom at the junction of any two lines or at the end of any line. assume there are enough hydrogens around each carbon to give it four bonds.
Answers
The skeletal structure of the organic compounds are the series of the atoms bonded together and form the important structure of the compound.
The statements that describe important rules for drawing skeletal structures are :
1) all heteroatoms and the hydrogens directly bonded to them.
2) there is a carbon atom at the junction of any two lines or at the end of any line.
3) there are enough hydrogens around each carbon to give it four bonds.
These three option are the correct statements to describe the important rule for the drawing skeletal structures to represents the important structure of the organic compound.
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IF YOUR ANSWER IS CORRECT YOU GET 100 EASY POINTS PLS HURRY
Given concerns over the overabundance of corn and corn-related products in American diets, which of the following distinguishes the best means of reducing corn consumption?
reducing options costs for corn crops
cutting subsidies to corn growers
increasing international corn imports
lowering prices for corn and corn products
Answers
The best means of reducing corn consumption is cutting subsidies to corn growers. Option B
What is corn?We know that corn is a kind of crop that is common in America and there are several kinds of products that we can be able to obtain from corn that are used in the care of the body. We know that corn is a cereal and a lot of baby foods are based on the use of cereals and this has brought the use of corn into very popular demand around the world and not just in the United States.
Having said all that, we know that corn is a rich source of carbohydrate but there is need for the consumption of a balanced diet and this should have to be the aim of the nutritional efforts that we tend to embark on.
This is why the reduction on the consumption of corn becomes very important as this would make the corn not to be able to remain the only staple food in many house holds in the country.
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n outer space the density of matter is about one atom per cm3, mainly hydrogen atoms, and the temperature is about 2.3 k.
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Space is generally thought of as a vacuum, but it isn't, not completely. The density of matter is extremely low, but it still exists. The interstellar medium is mainly made of lone hydrogen atoms. The density of hydrogen as it exists in interstellar space is on average about 1 atom per cubic centimeter.
In the extremes, as low as 0.1 atom per cubic centimeter has been found in the space between the spiral arms, and as high as 1000 atoms per cubic centimeter are known to exist near the galactic core. The baseline temperature of outer space, as set by the background radiation from the Big Bang, is 2.7 kelvins. However, there are areas in space where the temperature is extremely hot, reaching into the millions.
The bottom line: the temperature of outer space is brutally cold.
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As a technician in a large pharmaceutical research firm, you need to produce 150.0 mL of 1.00 mol/L potassium dihydrogen phosphate buffer solution of pH = 7.00. The pKa of H2PO−4 is 7.21. You have the following supplies: 2.00 L of 1.00 M KH2PO4 stock solution, 1.50 L of 1.00 M K2HPO4 stock solution, and a carboy of pure distilled H2O. How much 1.00 M KH2PO4 will you need to make this solution? (Assume additive volumes.)Express your answer to three significant digits with the appropriate units.
Answers
The 105.152mL ok KH2 PO4 is the additive volumes.
What is volume ?
The volume of a three-dimensional solid is the area that it takes up. These solids can be shaped into cubes, cuboid shapes, cones, cylinders, or spheres.
What is dihydrogen phosphate ?
Phosphoric acid, which has had one of its three OH groups deprotonated, is used to create the monovalent inorganic anion known as dihydrogenphosphate. It is both an inorganic monovalent phosphate ion and an anion. This base is the conjugate of phosphoric acid. It is an acid conjugated to hydrogen phosphate.
pH = pKa + log (HPO4-2)/(H2 PO4-)
6.84 = 7.21+ log ( HPO 4 -2)/ (H PO4-)
- 0.37 = log (H PO4-2)/ (HPO4-)
0.4265 = (HPO4-2)/ (HPO4-)
(HPO4-2)= 0.4265 x (HPO4-)
let's call X to the volume of KH2PO4 needed. so, the volume needed of K2HPO4 will be 150-X, now transform concentration into moles
1M HPO4-2 x (150-X) = 0.4265 x 1M h2 PO4- x X
150-X = 0.4265X
150= 1. 4265X
X = 105.152mL ok KH2 PO4.
Therefore, 105.152mL ok KH2 PO4 is the additive volumes.
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balance the equation representing the reaction between iron(iii) oxide, fe2o3, and carbon monoxide (co) to yield iron (fe) and carbon dioxide (co2). do not include the states of matter.
Answers
The balanced chemical equation for above chemical reaction is given as,
Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂
There are several ways to balance a chemical equation. In this above case case, we will see the algebraic method.
The first step is of assigning a letter to each compound:
a Fe₂O₃ + b CO → c Fe + d CO₂
Then, we must write the balance equations for each atom, thus:
Fe: 2a = c
C: b = d
O: 3a + b = 2d
The last step is of assigning a value to a letter. For example, we will say that a is 1, and then find the values for the others letters,
Fe: 2a = c if a=1; c=2
O: 3a + b = 2d if a=1 → 3+b = 2d
As b = d → 3+d = 2d; 3 = 2d - d; 3=d and 3=b
Thus, the balanced equation is given as,
Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂
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arrange the following substances from the lowest to the highest normal boiling point: calcium oxide, cao ; oxygen, o2 ; hydrogen, h2 ; formaldehyde, h2co ; and water, h2o .
Answers
The order of the lowest to highest normal boiling point:
H₂ < O₂ < H₂CO₃ < H₂O < CaO
The boiling point is what?The liquid phase turns into a vapor phase at this temperature.
The temperature at which a substance changes from the liquid phase into the gas phase is known as the boiling point. The melting point of ice or water and the boiling point of liquid water or vapor served as the foundation for the development of the Celsius scale. Every substance has a unique boiling point.
Since the ions in calcium oxide are strongly attracted to one another, its boiling point is 2850° C. As is already common knowledge, water has a boiling point of 100 °C.
The hydrogen gas has a boiling temperature of -252.8°C while the oxygen gas has a boiling point of -183°C. Carbonic acid has a boiling point of 333.6 °C.
Thus, of the listed chemicals, hydrogen gas has the lowest normal boiling point while CaO has the highest.
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Choose The Most Appropriate Reagent(S) For The Conversion Of 2-Methylcyclohexanol To 2- Methylcyclohexanone. Он 1. BH3 2. H20
Answers
The Most Appropriate Reagent(S) For The Conversion Of 2-Methylcyclohexanol To 2- Methylcyclohexanone is (A) PCC, CH₂Cl₂.
It is possible that carbonyl compounds will be produced as a byproduct of the oxidation of alcohols using pyridinium chlorochromate in CH₂Cl₂, however, this will depend on the specific type of alcohol. Primary alcohols will react with PCC to produce aldehydes while secondary alcohols will react with PCC to produce ketones, and tertiary alcohols will not react with PCC. So the most appropriate reagents for the conversion of 2-methylcyclohexanol to 2- methylcyclohexanone are (A) PCC, CH₂Cl₂. The reaction scheme along with the structures of reagents and products are attached.
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After the explosion of the Deepwater Horizon oil-drilling platform in 2010, Scientists estimate that BP removed about ___ of the oil, most of it recovered directly from the well, burned at sea, or skimmed by boats
25%
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After the explosion of the Deepwater Horizon oil-drilling platform in 2010, Scientists estimate that BP removed about 25% of the oil, most of it recovered directly from the well, burned at sea, or skimmed by boats.
Deepwater Horizon was a semi-submersible offshore drilling rig. It was owned by Transocean and operated by BP. While drilling at the Macondo Prospect on 20 April 2010, an explosion happened on the rig, killing 11 crewmen and igniting a massive fireball that was visible from 40 miles away.
The explosion was caused by a blowout, which is an uncontrollable crude oil and/or natural gas release from an oil well caused by a pressure control system failure. The rig itself sank two days after it exploded.
Both Transocean and BP received hefty fines, penalties, and compensations. On top of that, BP is also tasked with the oil spill cleanup, though other parties such as US Coast Guard also join in this effort. It took over ten years to clean the oil spill.
Attached below is an image of the Deepwater Horizon remains in flames after the explosion, taken on 20 April 2010 by US Coast Guard.
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In a certain part of the country there is an average of 710 people per square mile and 0.72 internet services per person.what is the average number of internet services in an area of 5.0 kilo meter square?
Answers
The average number of internet services in an area of 5.0-kilometer square would be 0.36 internet services..
Calculation of averageThe average number of people per square mile = 710
1 square mile = 2.59 square kilometer
The average number of people per kilometer square = 710
Number of internet services per person = 0.72
The total number of people that would be in a 5.0-kilometer square = 710 x 5 = 3550 people.
710 people = 0.72 internet services
3550 people = 3550 x 0.72/710
= 3.6 internet services
in other words, the average number of internet services per person in an area of 5.0-kilometer square would be 0.36 internet services.
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based on your knowledge of intermolecular forces and trends, select the statement that most accurately compares hcl and hbr.
Answers
Since HBr has the largest mass, it will have the highest boiling point. Due to higher dipole, the intermolecular force between SiH4 molecules is stronger than that between h-cl molecules.
A polar molecule, HBr exhibits dipole forces. Dispersion forces also exist between HBr molecules. Van der Waals forces would be the dominant interactions in these molecules. The larger the size or molecular mass of hydrogen halides, the stronger the van der Waals forces and the higher the boiling point will be. Of these three halides, HI has the largest size or molecular mass. In H-Cl, there is no H-bonding. Therefore, the boiling point is lower. Moving on to HBr and HI, the molecules get bigger, the van der Waal forces get stronger, and the boiling point gets hotter. H-Cl has the lowest boiling point as a result.
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be sure to answer all parts. complete the reactions showing how you could prepare ethyl phenyl ketone from propanenitrile and a grignard reagent. draw the structure of the imine intermediate. propanenitrile draw structure ... grignard reagent h5arrowdown160 p4o10 diethyl ether pbr3 nacn h2o, h , heat [1] socl2; [2] nh3 draw structure ... h5arrowdown160 diethyl ether h2o, h , heat [1] socl2; [2] nh3 this step is not necessary nacn p4o10 pbr3 ethyl phenyl ketone
Answers
Phenylacetone is a natural product found in Streptomyces and Gossypium hirsutum for which data are available.
Propiophenone and its derivatives. They are commonly used in perfumes and medicines. Class 1C antiarrhythmic drug used to treat paroxysmal atrial fibrillation/flutter and ventricular arrhythmias.
Propiophenone is an aromatic ketone in which the two substituents on the carbonyl carbon atom are phenyl and ethyl. Methanal is the IUPAC name for formaldehyde and ethanal is the name for acetaldehyde. For ketones, remove -e from the alkane name and add the suffix -one. Propanone is his IUPAC name for acetone and butanone is the name for ethyl methyl ketone.
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place the following in order of increasing bond length. c-fc-sc-cl a) c-s < c-cl < c-f b) c-cl < c-f < c-s c) c-f < c-s < c-cl d) c-f < c-cl < c-s e) c-s < c-f < c-cl
Answers
The order of increasing bond length is d) c-f < c-cl < c-s
The bond length of a covalent bond is determined by the size of the atoms involved and the strength of the bond. The size of the atoms involved in the c-f, c-s, and c-cl bonds are carbon, fluorine, sulfur, and chlorine, respectively. Carbon and fluorine are smaller atoms, while sulfur and chlorine are larger atoms. Therefore, the c-f bond will be the shortest bond.
The strength of the covalent bond is determined by the electronegativity of the atoms involved. Fluorine has the highest electronegativity of all the elements, followed by chlorine and then sulfur. Therefore, the c-f bond will be the strongest bond. The c-cl bond will be the second strongest bond, and the c-s bond will be the weakest bond.
Given these facts, the order of increasing bond length is c-f < c-cl < c-s. The c-f bond will be the shortest and strongest bond, followed by the c-cl bond and then the c-s bond.
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List the following transition metal cations by their d electron count, with the highest at the top and the lowest at the bottom. 1. Zn2+ 2. Co2+ 3. Ru4+ 4. Mo4+ 5. Pt2+.
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The transition metal cations by their d electron count, with the highest at the top and the lowest at the bottom is A > E > B > C > D.
D8 Metals was founded in 2004 as a company specializing in aluminum and steel fabrication, architectural metals and claddings, and custom electromechanical projects. Instead of an 8-electron rule or octet, transition metals follow an 18-electron rule. The easiest way to count electrons is to break down the complex and count the electrons apart.
There are 40 elements in the d block of the periodic table. Four rows of transition elements make up the d block. The d-electron number is a chemical formalism used to describe the electronic configuration of the valence electrons of the transition metal centers of coordination complexes. The d electron number is an effective way to understand the shape and reactivity of transition metal complexes.
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Which of the following equations represents a chemical reaction? *
O Water freezing
O Ice melting
O Water boiling
O Burning
Burning fuel inside of an engine
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Answer:
The correct answer is "Burning fuel inside of an engine." This is an example of a chemical reaction because it involves the rearrangement of atoms to create new substances. In this case, the fuel is reacting with oxygen in the air to produce heat, light, and various gaseous byproducts such as carbon dioxide and water vapor. By contrast, the other options are examples of physical changes, which involve changes in the state or appearance of a substance without changing its chemical composition.
Answer: Burning fuel inside of an engine
Explanation: Got it correct on the forms
(Edit: G o o g l e F o r m s)
the standard reduction potentials for fluorine gas to the fluoride ion and the aluminum (iii) ion to aluminum metal are 2.866 v and -1.662 v, respectively. t/f
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The statement saying the standard reduction potentials for fluorine gas to the fluoride ion and the aluminum (iii) ion to aluminum metal are 2.866 v and -1.662 v, respectively is true.
The standard reduction potential of a species is defined as the measure of the ability of that species to get reduced during a redox reaction.
The value of the standard reduction potential are pre decided for each and every element.
The value of the standard reduction potential for fluorine gas to the fluoride ion is +2.866 V.
The value of the standard reduction potential the aluminum (iii) ion to aluminum metal is -1.662V.
Both of these values are stated correctly in the given question. So, the given statement is true.
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when an object is totally submerged in fluid, this object will be heavier (its mass will be larger) than when it is in the air
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The Archimedes principle states that when an object is submerged in a fluid, it seems to lose weight proportional to the weight of the fluid that was displaced.
The mass of the water that the object moves is equal to this force. It turns out that it is still possible to demonstrate that even if the object is excessively heavy (density more than water), if the density of a fully submerged object (independent of its shape) is larger than the density of the fluid. Some objects float when submerged in a liquid because the buoyant force is greater than the object's weight, causing the object to rise to the surface and float. If an object's buoyant force exceeds its weight when submerged in a fluid, it will rise. We can determine the mass and weight of water once we know its volume.
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A cook heats water from 22 o C to 50 o C. Calculate the mass of water that could be warmed by the addition of 10.00kJof heat
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Answer:
Explanation:
Q=M*C*ΔT
Where,Q=Required heat
C=Specific heat of water
ΔT=Temperature change
[tex]M=\frac{Q}{C*T}[/tex]
[tex]M=\frac{10000}{4.184*28}[/tex]
[tex]M=\frac{10000}{117.15}[/tex]
[tex]M=85.3g[/tex]
Q = mcT, where Q is the heat provided, m is the mass of water, and c is the temperature change, may be used to determine how much water can be warmed by the addition of 10.00kJ of heat.
What happens in this instance ?In this instance, the water's beginning temperature is 22°C, and its ultimate temperature is 50°C, meaning that there has been a 28°C change in temperature.
Water has a heat capacity of 4.184 J/g°C, therefore m = Q / (cT) = 10.00kJ / (4.184 J/g°C x 28°C) = 7.08kg is the mass of water that can be warmed by the addition of 10.00kJ of heat. As a result, 7.08 kg of water may be warmed with the addition of 10.00 kJ of heat.
Considering that heat immediately proportionate to the water's bulk and temperature. The amount of heat needed to warm the water increases with the bulk of the water and the temperature change.
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Need an answer please
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An electrostatic force of attraction between Ba ⁺² and P⁻³. Because barium has positive charge and phosphorus has negative charge. Therefore, option C is correct.
What is electrostatic force ?Non-contact forces, such as electrostatic forces, pull or push on objects without actually making contact with them. When certain materials are rubbed together, a phenomenon known as "charge" can be transferred from one surface to another. Uncharged items are pulled by charged objects, which in turn may push or pull against other charged ones.
The complete transfer of one or more electrons results in the formation of an ionic bond between two oppositely charged ions, which is where the electrostatic force of attraction takes place.
Thus, option C is correct.
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