Kurt has $9,000 in an account. The interest rate is 5% compounded annually. To the nearest cent, how much will he have in 1 year? Kurt has $ 9,000 in an account . The interest rate is 5 % compounded annually . To the nearest cent , how much will he have in 1 year ?

Answers

Answer 1

Answer:

$9450

Step-by-step explanation:

Answer:

A = $9,450.00

A = P + I where

P (principal) = $9,000.00

I (interest) = $450.00

Calculation Steps:

First, convert R as a percent to r as a decimal

r = R/100

r = 5/100

r = 0.05 rate per year,

Then solve the equation for A

A = P(1 + r/n)nt

A = 9,000.00(1 + 0.05/1)(1)(1)

A = 9,000.00(1 + 0.05)(1)

A = $9,450.00

Summary:

The total amount accrued, principal plus interest, with compound interest on a principal of $9,000.00 at a rate of 5% per year compounded 1 times per year over 1 years is $9,450.00.


Related Questions

Word problem involving conversion between compound units...
A business based in South Africa pays a consultant in the U.S. 1,570,000 rand per year. Assume that the conversion is 1 rand to 0.074 dollars. What is the
consultant's salary in dollars per month?
First fill in the two blanks on the left side of the equation using two of the ratios. Then write your answer rounded to the nearest hundredth on the right side o
the equation.
Ratios:
1 rand
0.074 dollars
1,570,000 rand
1 yr
0.074 dollars
1 rand
1 yr
12 mo
0
0

I need help with this math problem.

Answers

Using proportions, it is found that the consultant's salary in dollars per month is of $9,681.67.

What is a proportion?

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

A business based in South Africa pays a consultant in the U.S. 1,570,000 rand per year. Considering the conversion rate, his salary in dollars per year is given as follows:

S = 1570000 x 0.074 = $116,180.

Since a year has 12 months, his salary in dollars per month is given by:

Sm = $116,180/12 = $9,681.67.

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Write the augmented matrix of the system of equations given below. (10 points)
−2 + 2 − = −13
−3 − + = 7
− + 3 − 2 = 0

Answers

The augmented matrix of the system of equations is [tex]\left[\begin{array}{ccc}-2&2&-1\\-3&-1&1\\-1&3&-2\end{array}\right] \left[\begin{array}{c}13&7\\0\end{array}\right][/tex]

How to determine the augmented matrix?

The system of equations is given as:

-2x + 2y - z = 13

-3x - y + z = 7

-x + 3y - 2z = 0

Remove the variables x, y and z

-2      2    -1  13

-3    -1        1    7

-1     3      -2     0

Express as matrix

[tex]\left[\begin{array}{ccc}-2&2&-1\\-3&-1&1\\-1&3&-2\end{array}\right] \left[\begin{array}{c}13&7\\0\end{array}\right][/tex]

Hence, the augmented matrix of the system of equations is [tex]\left[\begin{array}{ccc}-2&2&-1\\-3&-1&1\\-1&3&-2\end{array}\right] \left[\begin{array}{c}13&7\\0\end{array}\right][/tex]

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Complete question

Write the augmented matrix of the system of equations given below. (10 points)

-2x + 2y - z = 13

-3x - y + z = 7

-x + 3y - 2z = 0

!!HELP!! PLEASE I NEED THIS DONE IN AN HOUR IF ANYONE CAN HELP

Answers

Answer:

 the 1st answer is x = 5, the 2nd answer is x = 7, the 3rd answer is x = 4, the 4th answer is: x = 4, the 5th answer is the exact form: x = - 1/3 but the decimal form is: x = - 0.3, the 6th answer is x = 3.

Brainliest?

The data below represents the relationship between the number of incidences of UFO sightings in late 1930s and early 1940s. Draw a scatter plot for the data.
Year of Incidence
1936
1937
1938
1939
1940
1941
1942
1943
1944
1945
1946
Number of Incidences (percent)
0.9
0.8
0.8
1.3
1.4
1.2
1.7
1.8
1.6
1.5
1.5

a.
A graph has years of incidence on the x-axis from 1932 to 1948, and incidence on the y-axis, from 0 to 10. Points are around (1936, 0.9), (1937, 0.8), (1938, 0.8), (1939, 1.3), (1940, 1.4), (1941, 1.2), (1942, 1.7), (1943, 1.8), (1944, 1.6), (1945, 1.5), (1946, 1.5).
c.
A graph has years of incidence on the x-axis from 1932 to 1948, and incidence on the y-axis, from 0 to 10. Points are around (1936, 0.9), (1937, 0.8), (1938, 0.8), (1939, 1.3), (1940, 1.4), (1941, 1.2), (1942, 1.7), (1943, 1.8), (1944, 1.6), (1945, 1.5).
b.
A graph has years of incidence on the x-axis from 1932 to 1948, and incidence on the y-axis, from 0 to 10. Points are around (1936, 0.9), (1937, 1.7), (1938, 0.8), (1939, 1.3), (1940, 1.4), (1941, 1.2), (1942, 1.7), (1943, 1.8), (1944, 1.6), (1945, 1.5), (1946, 1.5).
d.
A graph has years of incidence on the x-axis from 1932 to 1948, and incidence on the y-axis, from 0 to 10. Points are around (1936, 0.9), (1937, 0.8), (1939, 1.3), (1940, 1.4), (1941, 1.2), (1942, 1.7), (1943, 1.8), (1944, 1.6), (1945, 1.5), (1946, 1.5).

Answers

The description of graph of the data about relationship of UFO sightings in late 1930s and early 1940s will be :A graph has years of incidence on the x-axis from 1932 to 1948, and incidence on the y-axis, from 0 to 10. Points are around (1936, 0.9), (1937, 0.8), (1938, 0.8), (1939, 1.3), (1940, 1.4), (1941, 1.2), (1942, 1.7), (1943, 1.8), (1944, 1.6), (1945, 1.5), (1946, 1.5).

Given:

Year of incidence                    percent

1936                                         0.9

1937                                         0.8

1938                                          0.8

1939                                          1.3

1940                                           1.4

1941                                            1.2

1942                                            1.7

1943                                             1.8

1944                                              1.6

1945                                              1.5

1946                                              1.5

We have been given the percentages of different years. The points will be (1936,0.9) , (1937,0.8) , (1938,0.8) , (1939,1.3) , (1940,1.4) , (1941,1.2) , (1942,1.7), (1943,1.8) , (1944,1.6) , (1945,1.5) , (1946,1.5).

We have to just plot the points on the graph to find scatter plot. It is called scatter plot as the points are not in line but they are scattered.

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The volume of a fish tank is 50 cubic feet. if the density is 0.2 fish over feet cubed, how many fish are in the tank? 5 10 125 250

Answers

Answer: 10

Step-by-step explanation:

I just took the test!! :)


A line passes through the point (8, -1) and has a slope of
Write an equation in slope-intercept form for this line.

Answers

The equation in slope intercept form is y = - 1 / 4 x + 1

How to find the slope intercept equation?

Using slope intercept form,

y = mx + b

where

m = slopeb = y-intercept

Therefore,

m = - 1 / 4

it passes through (8, -1)

Hen e,

-1 = - 1 / 4 (8) + b

-1  = - 2 + b

b = -1 + 2

b = 1

Therefore,

y = - 1 / 4 x + 1

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c. Divide 45 into three parts which are in A.P. Such that the pr oduct of last two is 300.​

Answers

(a−b)+a+(a+b)=45

⟹3a=45

a=15

a(a+b)=300

⟹15(15+b)=300

⟹225+15b=300

⟹15b=300−225

⟹15b15=7515

b=5

a−b=10⟹a=15⟹a+b=20

The three numbers are 10, 15, and 20.

Proof:

10+15+20=45✓

Please answer all parts as I know the answers but need the work to go with them. Thus, I believe some answers are correct. Thank you!

Answers

The approximate 95 % confidence interval for p is found by the formula

p^ ±  Z∝/2 √p^q^/n

The sample size n can be found by the

The formula

n= (Z∝/2)² p^q^/e²

The approximate 95 % confidence interval for p is 0.165; 0.243

This indicates 95 % confidence interval level.

A sample of 6239 nonprofits should be surveyed

Solution

Part a:

Sample Proportion p^= 84/412= 0.2038 ≅ 0.204

q^ = 1-p^= 1.0 -0.204= 0.796

The degree of confidence is 95% so  z∝/2= 1.96

Putting the values

p^ ±  Z∝/2 √p^q^/n

0.204 ±  1.96 √0.204(0.796)/ 412

0.204 ± 0.0389

0.1650 ; 0.2429

0.165; 0.243

The approximate 95 % confidence interval for p is 0.165; 0.243

Part B

This indicates 95 % confidence interval level.

Part C

With ± 0.01 of 0.95  Confidence interval gives range  0.94 to 0.96

For 0.96  interval Z∝/2 = 2.054

For 0.94  interval Z∝/2 = 1.8808

and error  e= 0.01

For solving n  the formula is

n= (Z∝/2)² p^q^/e²

and e= 0.01

Putting the values

n= 1.96²(0.204)(0.796)/ 0.01²

n= 6238.1437≅ 6238.14

A sample of 6239 nonprofits should be surveyed.

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A boat is heading towards a lighthouse, whose beacon-light is 148 feet above
the water. The boat's crew measures the angle of elevation to the beacon, 8°.
What is the ship's horizontal distance from the lighthouse (and the shore)?
Round your answer to the nearest hundredth of a foot if necessary.
Answer:
feet
Submit Answer
attempt 1 out of 2 / problem 2 out of max 4

Answers

Answer:

x = 1053.07 ft

Step-by-step explanation:

So if you look at the diagram I drew it might become a bit more apparent what you have to do. For this problem you'll need to use one of the six trigonometric functions. In this case you know the angle and the opposite side of the angle, and you need the adjacent side. The trigonometric function tan is defined as [tex]\frac{oppposite}{adjacent}[/tex]. So let's plug in the known values:

[tex]tan(8) = \frac{148}{x}[/tex]

multiply both sides by x

[tex]tan(8) * x = 148[/tex]

Divide both sides by tan(8)

[tex]x=\frac{148}{tan(8)}[/tex]

Calculating tan of 8 degrees using a calculator

[tex]x=\frac{148}{0.141}[/tex]

Simplify

x = 1053.07 ft

using this diagram, find x and y

Answers

Answer:

x=13

y=11

Step-by-step explanation:

3y+5+52=90

3y=90-57

3y=33

y=33/3=11

4x=52

x=52/4=13

3y+5 and 52 are complementary

3y+5+52=903y+57=903(y+19)=90y+19=30y=11

Apply angle sum property

4x+3(11)+5+90=1804x+33+5=904x+38=904x=52x=13

Taylor earned the following scores on her first ten quizzes. What would she need to earn on the eleventh test in order to have a mean score of 87? 78, 92, 98, 87, 86, 72, 92, 81, 86, 92

Answers

A mean is an arithmetic average of a set of observations. The score that Taylor needs to make in her eleventh test for the average to be 87 is 93.

What is Mean?

A mean is an arithmetic average of a set of observations. it is given by the formula,

Mean = (Sum of observations)/Number of observations

The score earned by Taylor in her first 10 test are 78, 92, 98, 87, 86, 72, 92, 81, 86, 92. Also, she wants the average to be 87, therefore, we can write,

(78 + 92 + 98 + 87 + 86 + 72 + 92 + 81 + 86 + 92 + x)/11 = 87

864 + x = 957

x = 93

Hence, The score that Taylor needs to make in her eleventh test for the average to be 87 is 93.

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Barn Yard Inc. is a wholesaler that stocks engine components and tests equipment for the commercial aircraft industry. A new customer has placed an order for eight high-bypass turbine engines, which increase fuel economy. The variable cost is $1.6 million per unit, and the credit price is $1.725 million each. Credit is extended for one period, and based on historical experience, payment for about one out of every 200 such orders is never collected. The required return is 1.8% per period.Suppose that customers who don’t default become repeat customers and place the same order every period forever. Further assume that repeat customers never default.

Answers

The NPV is positive, therefore, this order can be placed.

How to calculate the NPV?

The calculation of probability of default will be:

= 1 / 200 = 0.005

We use NPV formula to find out whether the order should be filled or not

NPV = -Variable cost per unit +[(1-π)(price of equipment/1+percentage of return)]

= -$1.6 million +[(1-0.005)($1.725m/1.018)]

= -$1.6m + $1.6860

= 0.0860 million

As NPV is positive this order can be placed.

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Divide. Write the quotient in lowest terms.

Answers

Answer:

11/12

Step-by-step explanation:

2 3/4 ÷ 3

11/4 ÷ 3

11/4 × 1/3

11/12

Answer:

Hello! The answer is 11/12.

Step-by-step explanation:

Convert improper fractions:

[tex]2\frac{3}{4} \\= \frac{11}{4}[/tex]

Change 3 to its reciprocal:

[tex]\frac{1}{3}[/tex]

Multiply:

[tex]\frac{11}{4} * \frac{1}{3} \\= 11/12[/tex]

A fixed deposit receipt initiallypurchased for #1,500,000 for 4years has a maturity value of #1,300,000. What is the simple interest rate per year?​

Answers

Answer:

11 3/13% per annum

Step-by-step explanation:

to find rate= 100×simple interest ÷ (principal ×time)

simple interest=total amount - principal

=1,500,000-1,300,000

=200,000

=200,000 ×100÷ 1,300,000×4

=3 11/13% per annum

Translate and solve: the product of
p
and

2.5
is
4.8

Answers

Answer:

p = 7.3

Step-by-step explanation:

Equation: p - 2.5 = 4.8

add 2.5 to both sides:

P - 2.5 + 2.5 = 4.8 + 2.5


simplify

P = 7.3


hope that helps! :)

px2.5=4.8

Divide by 2.5 on both sides.

P=1.92

Hope this helped!

Find the area of the triangle if b = 8 inches and h = 4 inches

Answers

The area of triangle is 16 square inches.

what is Area of Triangle?

Area of triangle is half times the product of base and height.

i.e., A-= 1/2 *b *h

Given:

b= 8 inches, h= 4 inches

Now, Area of triangle

= 1/2*b*h

= 1/2 * 8 *4

=1/2*32

=16.

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if anyone knows how to answer this do so pleass

Answers

Answer:

x = 4.08

Step-by-step explanation:

As we now, from Trigonometric Identities

that   [tex]tan(\alpha )=\frac{Opposite}{Adjacent}[/tex]

So for our Problem , [tex]\alpha =27[/tex]  , [tex]Opposite=x[/tex]  ,  [tex]Adjacent = 8[/tex]

by substituting , then  [tex]tan(27)=\frac{x}{8}[/tex]

by multiplying both sides by 8 , then [tex]x=8tan(27)=4.0762=4.08[/tex]

Find the product of the given polynomials
(5r+8-6r)(4+2r-7)
A.2r^2+13r-24
B.-2r^2-24r+19
C.-2r^2+19r-24
D.2r^2+19r+24

Answers

Answer:

C

Step-by-step explanation:

(5r + 8 - 6r)(4 + 2r - 7) ← collect like terms inside each parenthesis

= (8 - r)(2r - 3)

each term in the second factor is multiplied by each term in the first factor.

8(2r - 3) - r(2r - 3) ← distribute parenthesis

= 16r - 24 - 2r² + 3r ← collect like terms

= - 2r² + 19r - 24

pls help! i need an explanation and the steps that show how it’s solved too. tysm!

Answers

Answer:

true

Step-by-step explanation:

6(6(13x-2)

36(13x-2)

468x-72

please mark brainliest :D

Answer:

True

Step-by-step explanation:

Given functions:

[tex]\begin{cases}f(x)=3x-7\\g(x)=13x-2\\h(x)=6x\end{cases}[/tex]

[tex]h(h(g(x)))[/tex] is a composite function.  

Composite functions are when the output of one function is used as the input of another.

Therefore, the given composite function means to substitute the function g(x) in place of the x in function h(x), then substitute this in place of the x in function h(x).

Step 1

Substitute the function g(x) in place of the x in function h(x):

[tex]\begin{aligned}h(x) & = 6x\\\implies h(g(x)) & =6(g(x))\\& = 6(13x-2)\\ & = 78x-12\\\end{aligned}[/tex]

Step 2

Now substitute the above in place of the x in function h(x):

[tex]\begin{aligned}h(x) & = 6x\\\implies h \left(h(g(x))\right) & =6(h(g(x)))\\& = 6(78x-12)\\& = 468x-72\end{aligned}[/tex]

Therefore, the statement is true.

To carry out the composite function in one step:

[tex]\begin{aligned}h(x) &=6x\\\implies h(h(g(x))) & = 6\:(h(g(x)))\\& = 6(6(g(x)))\\& = 6( 6(13x-2))\\& = 6(78x-12)\\& = 468x-72\end{aligned}[/tex]

If the cost of 5m of cloth is Rs 375,find the cost of 80m of cloth​

Answers

Step-by-step explanation:

If the cost of 5m cloth is Rs.375

Then cost of 80m cloth is (80m× Rs 375)÷ 5m

then the cost of  is 6000 Rs. you can use the criss cross method

5m = 375 Rs

80m = ?

80 × 375 = (30,000) ÷5

?= 6000

A landscaping company is hired to mow the grass for several large properties. The total area of the properties combined is 1,345 acres. The rate at which one person can mow is as follows:

ŷ = 1350 – 1.2x where x is the number of hours and ŷ represents the number of acres left to mow.

How many acres will be left to mow after 20 hours of work?
How many acres will be left to mow after 100 hours of work?
How many hours will it take to mow all of the lawns? (When is ŷ = 0?)

Answers

Using the given linear function, we have that:

After 20 hours, 1326 acres will be left to mow.After 100 hours, 1230 acres will be left to mow.It will take 1125 hours to mow all the lawns.

What is the linear function?


The linear function for the number of acres left to mow after x hours is given as follows:

y  = 1350 - 1.2x.

After 20 hours, the number acres is given as follows:

y  = 1350 - 1.2(20) = 1326.

After 100 hours, the number acres is given as follows:

y  = 1350 - 1.2(100) = 1230.

The time it takes to mow all the lawns is given by:

1350 - 1.2x = 0.

1.2x = 1350

x = 1350/1.2

x = 1125 hours

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The area of the parallelogram below is ____ square meters. A parallelogram with height labeled with 7 meters. The top horizontal side is labeled 6 meters. The base of the left triangle formed by the height is 2 meters. Numerical Answers Expected

Answers

The area of the parallelogram in the image given is: 42 m².

What is the Area of a Parallelogram?

Area of a parallelogram = base × height

Given the parameters:

Base = 6 metersHeight = 7 meters

Area of the parallelogram = (6)(7)

Area of the parallelogram = 42 m²

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What is the inverse of
F(x) =5x/3+ 5

Answers

The inverse function of f(x) = 5x/3 + 5 is f-1(x) = 3x/5 - 3

How to determine the inverse?

The function is given as:

f(x) = 5x/3 + 5

Rewrite as:

y = 5x/3 + 5

Swap x and y

x = 5y/3 + 5

Subtract 5 from both sides

x - 5 = 5y/3

Multiply through by 3

3x - 15 = 5y

Divide through by 5

y = 3x/5 - 3

Express as inverse function

f-1(x) = 3x/5 - 3

Hence, the inverse function of f(x) = 5x/3 + 5 is f-1(x) = 3x/5 - 3

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How many three-letter "words" can be made from 7 different letters "FGHIJKL" if...
a) Repetition of letters is allowed?
b) Repetition of letters is not allowed?

Answers

Answer:

343

Step-by-step explanation:

How many three-letter ”words” can be made from 7 letters FGHIJKL” if repetition of letters (a) is allowed? (b) is not allowed? Solution: (a) If repetition is allowed each letter can be any of the 7. So number ways is 7 × 7 × 7=73 = 343

Answer: See below

Step-by-step explanation:

Given:

The letters FGHIJKL

To find:

The number of three letter words can be formed if repetition is allowed (or) if repetition is not allowed

[tex]$$(a) If repetition is allowed:Total no of three letter words can be made$$=7_{C 1} x 7_{C 1} x 7_{C 1}=7^{3}=343$$(b) If repetitions is not allowed :Total no of three letter words can be made without repetition is $$\begin{gathered}=7_{C 1} \times 6_{C 1} \times 5_{C 1} \\=7 x 6 \times 5=210\end{gathered}$$[/tex]

What method of matrixes would be used for this question? ( Inverse Matrices, Cramer's Rule, Gaussian Elimination, and Gauss-Jordan Elimination)

John had $24,500 to invest. He divided the money into three different accounts. At the end of the first year he had made a total of $1,300 in interest between the three accounts. If the first account earned 4% interest on its original amount for the year, the second account earned 5.5% interest on its original amount for the year, and the third account earned 6% interest on its original amount for the year. Also, the amount of money in the first account was 4 times the amount in the second account. How much had he originally placed in each account?

Answers

Answer:

The method of matrixes that would be used for this question is Gaussian Elimination.

Step-by-step explanation:

Gaussian Elimination is a method of solving linear equations by transforming them into upper triangular form. In this case, we want to solve for the original amount of money placed in each account, which can be represented by variables x, y, and z. We can set up the equations as follows:

4x + 5.5y + 6z = 1,300

x + y + z = 24,500

4x = y

We can then use Gaussian Elimination to solve for x, y, and z.

Given: 1.1 1.2 1.3 f(x) = 8 +4 x-8

Write down the domain and range off.
Write down the equations of the asympotes of f
Sketch the graph of f clearly showing the intercepts with the axes and the asymptotes.​

Answers

Answer:

Did you mean " f(x)=8+4^{x-8} ? " The function you entered was linear, meaning there would be no asymptote.

D: (-∞, +∞)

R: (8, +∞)

Horizontal asymptote at y=8

No vertical asymptote

Which table matches the graph below

Answers

The table that matches the graph shown is the second table.

How to depict the table?

It should be noted that in the graph, there's a quadratic equation. The form is given as ax² + bx + c.

When x = 0, y = 2. When x = 1, y is a number between 3 and 4. In the second table x we have y(1) = 7/2. This is in the range.

The graph is attached.

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What fraction of this shape is shaded?
Time
Running
Give your answer in its simplest form.

Answers

15% it’s running
That’s all I’m aware of

Which linear inequality is represented by the graph?

Answers

Answer:

y>2/3+3

Step-by-step explanation:

Answer:

y<2/3x+3

Step-by-step explanation:

1. Find the slope, the slope is 2/3

2. Find the y-intercept, the y intercept is 3

3. Make an linear equation out of it, y=2/3x+3

4. Dotted or solid? Its dotted which means the answer has to be greater or less than, not equal or less than or equal or greater than

5. Test you have 2 answer choices y<2/3x+3 or y>2/3x+3, input the origin (0,0)

0<2/3(0)+3, 0<3 which is true

0>2/3(0)+3 0>3 which is false

So y<2/3x+3 is the right answer. :)

Order the quotients of these expressions from least to greatest.
42.6 ÷ 70
42.6 ÷ 0.7
426 ÷ 70
42.6 ÷ 0.07

Answers

1st Problem = 0.6085 (least)
3rd Problem = 6.0857
2nd Problem = 60.8571
4th Problem = 608.5714 (greatest)
Other Questions
Differences between nucleus and vacuole Part AIn the table, identify four to five details that reflect the most important parts of the excerpt from Rogue Heart. Then paraphrase these details in your own words. On a coordinate plane, triangle A B C is shifted 4 units up and 3 units to the left to form triangle A prime B prime C prime.Use the figure to identify the correct rule for the translation.(x, y) Right-arrow (x 3, y + 4)(x, y) Right-arrow (x + 3, y 4)(x, y) Right-arrow (x 4, y + 3)(x, y) Right-arrow (x + 4, y 3) HIV attack of CD4 T cells causes suppression of both cell-mediated and humoral immune responses. Group of answer choices True False When the birth rate in a population is greater than the death rate, the population will generally __________.1. none of the choices2. decrease3. increase4. not change The function y=-x-3 is graphed only over the domain of (x1-8x 8). 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When caregivers are youth-centered, using the young persons own strengths, interests, goals, and dreams as the beginning point for learning and helping, they tap young peoples motivation, and natural drive for learning and personal growth.Opportunities for Participation and ContributionProviding youth the chance to participate in engaging, challenging, and interesting activities promotes personal strength. Opportunities for participation in group activities can help people fulfill their needs for belonging. 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