FILL IN THE BLANK. two specific types of ____ are e-commerce systems and point-of-sale (pos) systems.

Answers

Answer 1

Answer:

Order entry systems

Step-by-step explanation:

Two specific types of order entry systems are e-commerce systems and point-of-sale (pos) systems.


Related Questions

If AB has endpoint A(2, 13) and midpoint
(10,-1) then give the coordinate of B.

Answers

Answer:

(18, -15)

Step-by-step explanation:

The vector AB is defined by its starting and endpoints. Usually, B would be at the end, but in this case A is. Since we are given its midpoint, that is, the point equidistant from both the coordinates A and B, we can find coordinate B by simply calculating the distance between A and the midpoint and reapplying this distance to the midpoint.

1. Finding the distance between the midpoint and A:

The distance between two coordinates, from what I can recall, is simply the final coordinate value minus the initial coordinate value, following the form (x2-x1, y2-y1). We know that A comes after the midpoint, because it is the endpoint (so it will be the final coordinate value). Applying this to the context of the question, (2-10, 13+1) = (-8,14).

2. Finding B using the distance between midpoint and A:

B will be the initial coordinate value because it comes before the midpoint. Therefore, giving B the values (x,y):   (10-x, -1-y) = (-8, 14). Separating into two equations (respective to each axis):

10-x=-8

-x=-18

x=18

-1-y=14

-y=15

y=-15

Therefore, the coordinate of B is (18, -15).

Given: Line coordinates P(10,-1) A-------------------------------------------B (2,13) (x, y)
The point P(x', y') divides AB in 1:1 ratio =m:n
So from formula:
x' =(mx1 + nx2)/(m+n) and y' = (my1+ny2)/(m+n) where (x',y')=(10,-1), m:n=1:1 and (x1, y1)=(2,13), (x2,y2)=(x,y)
Put the values in the formula: 10 = 1(2)+1(x)/1+1 = (2+x)/2 =>20=2+x from cross multiplication =>x=20-2=18 from transposition =>x=18 -1=1(13)+1(y)/1+1 =(13+y)/2 =>-2=13+y from cross multiplication =>y=-2-13=-15 from transposition =>y=-15 So coordinates of B (18,-15)

Geometric Transformations Digital Escape

Can you transform each coordinate point and type the correct code? Please remember to type in ALL CAPS with no spaces.

Clear SHORT answers please..

Answers

After a transformation of each coordinate point, the correct code are as follows;

A. (-4, -2).

I. (0, 1).

C. (5, 0).

E. (0, 0).

What is a translation?

In Mathematics, the translation a geometric figure or graph to the left simply means subtracting a digit from the value on the x-coordinate of the pre-image while the translation a geometric figure or graph downward simply means subtracting a digit from the value on the y-coordinate (y-axis) of the pre-image.

Next, we would apply a translation to each of the points as follows;

Point 1 (1, 2) →  (x - 5, y - 4) = (1 - 5, 2 - 4) = Point 1' (-4, -2).

Point 2 (2, 4) →  (x - 2, y - 3) = (2 - 2, 4 - 3) = Point 2' (0, 1).

Point 3 (4, 4) →  (x + 1, y - 4) = (4 + 1, 4 - 4) = Point 3' (5, 0).

Point 4 (3, 2) →  (x - 3, y - 2) = (3 - 3, 2 - 2) = Point 4' (0, 0).

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how is 15×3/5 = 9


the slash is for the fraction

Answers

Answer:15x3 /=divide 5 = 9

Step-by-step explanation:

because if you do 15x3 it is 45 then you divide it by 5 and get 9 as your answer!


find the value of d in this equality below 5d ÷ 5³=5¹⁸
(the d should be squaring the first five)​

Answers

Answer:

d = 21

Step-by-step explanation:

Given equation:

[tex]5^d \div 5^3=5^{18}[/tex]

Multiply both sides by 5³:

[tex]\implies 5^d=5^{18} \times 5^3[/tex]

[tex]\textsf{Apply exponent rule} \quad a^b \cdot a^c=a^{b+c}:[/tex]

[tex]\implies 5^d=5^{18+3}[/tex]

[tex]\implies 5^d=5^{21}[/tex]

[tex]\textsf{Apply exponent rule} \quad a^{f(x)}=a^{g(x)} \implies f(x)=g(x):[/tex]

[tex]\implies d=21[/tex]

find the exact length of the curve. y = 3 + 4x3/2, 0 ≤ x ≤ 1

Answers

So the exact length of the curve is given by [tex]L=(1/36)*[\frac{37^{3/2}}{3/2} - 1][/tex]

Given the equation of curve:

[tex]y = 3+ 4x^\frac{3}{2}[/tex]

The length of the curve is given by [tex]L= \int\limits^a_b {\sqrt{1+(y^[/tex]

Where y^ is derivative of y with respect to x

So [tex]y= 4*(3/2) * \sqrt{x}= > 6 \sqrt{x}[/tex]

Given a=1 and b=0

So [tex]L= \int\limits^1_0 {\sqrt{1+(6\sqrt{x})^2 } } \, dx[/tex]

[tex]L= \int\limits^1_0 {\sqrt{1+36x } } \, dx[/tex]

let 1+36x be t

36dx = dt

As the value of x changes after the substitution of the value.

So now the L changes as:

[tex]L= 1/36 \int\limits{\sqrt{t } } \, dt[/tex]

[tex]L=1/36* \left \{ {{t=37} \atop {t=1}} \right. \frac{t^\frac{3}{2} }{\frac{3}{2} }[/tex]

[tex](1/36)*[\frac{37^{3/2}}{3/2} - 1][/tex]

the min value of t=1 and max value of t=37

[tex]L=(1/36)*[\frac{37^{3/2}}{3/2} - 1][/tex]

[tex]L=(1/36)*[\frac{37^{3/2}}{3/2} - 1][/tex]

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iiiiiijjjjjjjjjjjjjjjj

Answers

What !!!!!!!!!!!!!!!

need help can’t figure it out!

Answers

Answer:

Step-by-step explanation:

This is a trick question,  about the red marks again.   those marks are important b/c they tell you that the lengths are the same, so that the angles MUST also be the same.  That is  ,  D and E are equal

so set up your equations with that info

180 = 84 +2p

now use your algebra skillz to solve

180-84 / 2 = p

96/2 = p

48 = p

see??


in the diagram PQRS is a circle centre O. If angel POQ = 150° angle QSR= 40° and angel SQP= 45° calculate angel RQS.

Answers

Answer:

the angle would be 40 degrees

Step-by-step explanation:

using the alternative angle property the angle is 40

The 2 digit number which become 5 by 6th of itelf when it digit are revered. The difference in the digit of the
number being 1, then the two digit number i

Answers

After solving the two digit number is 45.

In the given question,

The 2 digit number which become 5 by 6th of itself when it digit are revered.

The difference in the digit of the number being 1, then we have to find the two digit number.

Let the two digit number = 10y+x

When we reversed the number then the number is 10x+y

As given that;

10y+x = 5/6(10x+y)

Multiply by 6 on both side, we get

60y+6x = 50x+5y

Subtract 5y on both side, we get

55y+6x = 50x

Subtract 50x on both side, we get

55y-44x = 0

Divide by 11 on both side, we get

5y-4x = 0

4x-5y = 0......................(1)

It is given that the difference between the number is 1.

x-y = 1..................(2)

Multiply by 4 in equation 2

4x-4y = 4.........................(3)

Now subtract equation 3 and 1, we get

y = 4

Now putting the value of y in equation 2

x-4 = 1

Add 4 on both side, we get

x = 5

Since the number is 10y+x. So

10y+x = 10(4)+5

10y+x = 45

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a manufacturer conducted a survey to determine how many people buy products p and q. what fraction of the people surveyed said that they buy neither product p nor product q ?

Answers

The fraction of the people surveyed that said that they buy neither product p nor product q is 1/6.

It is given to us that -

A survey is conducted with the number of people buying products p and q

We have to find out the fraction of the people surveyed said that they buy neither product p nor product q.

From the given information, the total number of products can be represented as -

[Total products bought] = [p products bought] + [q products bought] - [both p and q bought] + [neither p and q bought] ---- (1)

We have to find out -

[neither p and q bought]/[Total products bought]

Let us assume that the total products bought = 6

It is known that 1/3 of the people surveyed said that they buy product p but not product q.

=> [p products bought] - [both p and q bought] = 1/3 * 6

=> [p products bought] - [both p and q bought] = 2 ------ (2)

From equation (1), we can say that -

[Total products bought] = [p products bought] + [q products bought] - [both p and q bought] + [neither p and q bought]

=> 6 = ([p products bought] - [both p and q bought]) + [q products bought] + [neither p and q bought]

From equation (2), we can write the above equation as -

=> 6 = 2 + [q products bought] + [neither p and q bought]

=> [q products bought] + [neither p and q bought] = 4  ------ (3)

Again, it is also known that 1/2 of the people surveyed said that they buy product q.

=> [q products bought] = 1/2 *6

=> [q products bought] = 3 ---- (4)

From equation (3) and equation (4), we can say that -

[q products bought] + [neither p and q bought] = 4

=> 3 + [neither p and q bought] = 4

=> [neither p and q bought] = 1  ------ (5)

From equation (5) and the total number of products bought, we can say that -

[neither p and q bought]/[Total products bought] = 1/6

(Since, the total number of products bought = 6)

Therefore, the fraction of the people surveyed that said that they buy neither product p nor product q is 1/6.

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(a) The quadratic equation (x+2)² +3k-1=0 has two real and distinct roots, where k is a constant. Find the range of values of k.​

Answers

Answer: This means that the range of values of k is k ∈ [-1/3, 1/3].

Step-by-step explanation: The quadratic equation (x+2)² +3k-1=0 can be written as (x+2)² = 1-3k. For the equation to have two real and distinct roots, the expression under the square root must be nonnegative. Therefore, we have the inequality 1-3k ≥ 0. Solving this inequality gives us -1/3 ≤ k ≤ 1/3. This means that the range of values of k is k ∈ [-1/3, 1/3].

18. Which is closest to the volume of a ball with a diameter equal to 8.5 inches? Use 3.14 for V=4πTr²³ if 8.5 in is diameter, 3 what radius will you use? A. 285.7 in 3 B 352.4 in 3 C. 300.5 in 3 n 321 1 in 1​

Answers

The closest volume of ball would be 321.4

What is Volume of sphere?

The volume of a sphere is a measure of the space occupied by the sphere, and can be calculated by the formula V = 4/3πr³, where r is the radius of the sphere. In other words, the volume can be found by multiplying 4/3 by π (3.14) by the cube of the radius of the sphere. For example, if the radius is 5, the volume of the sphere would be 4/3π x 5³, or approximately 523.60.

Solution:

Given that:

diameter = 8.5 in

hence, radius would be 4.25 in

                    [tex]Volume\ of \ ball = \frac{4}{3} \pi r^{3} \\\\Volume\ of \ ball = \frac{4}{3} \pi (4.25)^{3}\\\\Volume\ of \ ball = 321.4[/tex]

Hence, The closest volume of ball would be 321.4

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a technician is launching fireworks near the end of a show. of the remaining thirteen fireworks, seven are blue and six are red. if she launches four of them in a random order, what is the probability that exactly two of them are blue ones

Answers

The probability that exactly two of thirteen fireworks are blue ones out of total 4 selections is 63/143.

Define the term probability?Probability refers to potential. A random event's occurrence is the subject of this area of mathematics. The range of the value is 0 to 1. Mathematics has incorporated probability to forecast the likelihood of various events.

The stated data;

Total fire works = 13Blue = 7Red = 6

You want 2 of the 7 items she selects to be blue, leaving 2 to be red.

Selecting 2 blue out of 7 blues is ⁷C₂ = 7!/(5!.2!)  =  21

Selecting 2 red out of 6 red = ⁶C₂ = 6!/(4!2!) = 15

Selecting total of 4 out of 13 ; ¹³C₄ = 13! / (9!.4!) = 715

Thus, probability that exactly two of them are blue ones;

P(2 blue) = 21 x 15 / 715

P(2 blue) = 63/143

Thus, probability that exactly two of them are blue ones out of total 4 selections is 63/143.

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find the volume of the given solid. bounded by the cylinders x2 + y2 = 4r2, y2 + z2 = 4r2

Answers

The volume of cylinders [tex]x^2 + y^2 = 4r^2[/tex] and [tex]y^2 + z^2 = 4r^2[/tex] is 88[tex]r^3[/tex]/3.

How to find the volume using double integrals?

The volume of cylinders can be calculated using integrals from the top curve subtract the bottom curve. For expression above we can convert to find the dimensions of cylinders using Fubini's Theorem. So,

x^2 + y^2 = 4r^2 to x^2 = 4r^2 - y^2

y^2 + z^2 = 4r^2 to z^2 = 4r^2 - y^2

Thus, the volume of the given solid is,

v = [tex]\int r-r\int\sqrt{4r^2-y^2}-\sqrt{4r^2-y^2}\times 2\sqrt{4r^2-y^2} dx dy[/tex]

= [tex]2\int r-r(x\sqrt{4r^2-y^2})(\sqrt{4r^2-y^2})-\sqrt{4r^2-y^2}dy[/tex]

= [tex]2\int r - r[(4r^2-y^2)+(4r^2-y^2)]dy[/tex]

= [tex]2\int r - r[2(4r^2-y^2)]dy[/tex]

= [tex]4\int r - r(4r^2-y^2)dy[/tex]

= [tex]4(4r^2y-y^3/3)r-r[/tex]

= [tex]4(4r^2(r+r)-(r^3+r^3)/3)[/tex]

= [tex]4((4r^2)(2r)-2r^3/3)[/tex]

= [tex]8(4r^3-r^3/3)[/tex]

= [tex](8)(12r^3-r^3)/3[/tex]

= 88[tex]r^3[/tex]/3

Thus, the volume of cylinders is (88r^3)/3.

You question is incomplete, but most probably your full question was

find the volume of the given solid. bounded by the cylinders [tex]x^2 + y^2 = 4r^2[/tex], [tex]y^2 + z^2 = 4r^2[/tex]

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Use Infinite differences to write the linear function that represents the given data set.

Answers

The linear equation on the table is the one in option D.

y = 25*x + 45

How to write the linear function?

A general linear function is written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

If we know two points on the line, (x₁, y₁) and (x₂, y₂), the slope can be written as:

a = (y₂ - y₁)/(x₂ - x₁)

Using the first two points, (0, 45) and (1, 70) we can get the slope:

a = (70 - 45)/(1 - 0) = 25

And because of the point (0, 45) we know that the y-intercept is b = 45, then the linear equation is:

y = 25*x + 45

So the correct option is D.

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An office machine purchased new for $3600 loses $400 each year.
Assume the value continues to decrease the same amount
each year. If f(x) represents the value of the office machine
after x years, which linear function models the given situation?

Answers

The linear function models the given situation will be equal to f(x) = $3600 - $400(x).

What is an equation?

Mathematical expressions with two algebraic symbols on either side of the equal (=) sign are called equations.

This relationship is illustrated by the left and right expressions being equal. The left-hand side equals the right-hand side is a basic, straightforward equation.

As per the given information in the question,

Original price of Machine = $3600

Price lost by the machine each year = $400

Then, the equation will be,

f(x) = $3600 - $400(x)

Here, x represents the number of years.

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Answer:

f(x) = −400x + 3600

original equations: S(p) = -200 + 50p and D(p) = 1060 - 55p please find the equilibrium price and quantity of the two equations. I think I already set up the equation for the equilibrium price here, though no guarantee that I did it right. Qd = 1060 - 55p = Qs = -200 + 50p​

Answers

The equilibrium price is; $12

The quantity for the two equations is; 400

How to find the equilibrium price?

The equilibrium price formula is based on the demand and supply quantities; you will set quantity demanded (Qd) equal to quantity supplied.

The equilibrium price definition above is one that tells us that there is a price point that meets the needs of both supply and demand. In order to understand when those needs are met, we need to know how to find equilibrium price.

We are given;

Quantity supplied; S(p) = -200 + 50p

Quantity demanded; D(p) = 1060 - 55p

Thus, equilibrium price is p when;

S(p) = D(p)

-200 + 50p = 1060 - 55p

1060 + 200 = 55p + 50p

1260 = 105p

p = 1260/105

p = $12

S(p) = -200 + 50(12)

S(p) = 400

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If f(x) =
√x-10+3, which inequality
x-10+3, which inequality can be used to find the domain of f(x)?
O
0x20
Ox-1020
O √x-10
x-10+320

Answers

Inequality can be used to find the domain of f(x)  is  [tex]$\quad x \geq 20$[/tex]

Interval Notation: [tex]$[20, \infty)$[/tex]

What is Domain definition?

The domain of a function is the set of input or argument values for which the function is real and defined.

Find non - negative values for radicals: [tex]$x \geq 20$[/tex]

The function domain

[tex]$$x \geq 20$$[/tex]

Range of[tex]$\sqrt{\frac{1}{2} x-10}+3:\left[\begin{array}{cc}\text { Solution: } & f(x) \geq 3 \\ \text { Interval Notation: } & {[3, \infty)}\end{array}\right]$[/tex]

Function range definition

The set of values of the dependent variable for which a function is defined

The range of an radical function of the form [tex]$c \sqrt{a x+b}+k$[/tex] is [tex]$f(x) \geq k$[/tex][tex]$k=3$[/tex]

[tex]$f(x) \geq 3$[/tex]

Axis interception points of [tex]$\sqrt{\frac{1}{2} x-10}+3$[/tex] : None

x - axis interception points of [tex]$\sqrt{\frac{1}{2} x-10}+3$[/tex] : None

y - axis interception point of [tex]$\sqrt{\frac{1}{2} x-10}+3$[/tex] : None

None

Extreme Points of [tex]$\sqrt{\frac{1}{2} x-10}+3: \quad$[/tex]Minimum (20,3)

First Derivative Test definition

Suppose that [tex]$x=c$[/tex] is a critical point of f(x) then, If [tex]$f^{\prime}(x) > 0$[/tex] to the left of [tex]$x=c$[/tex]and [tex]$f^{\prime}(x) < 0$[/tex] to the right of x=c then x=c is a local maximum. If [tex]$f^{\prime}(x) < 0$[/tex] to the left of [tex]$x=c$[/tex] and [tex]$f^{\prime}(x) > 0$[/tex] to the right of [tex]$x=c$[/tex] then [tex]$x=c$[/tex] is a local minimum. If [tex]$f^{\prime}(x)$[/tex] is the same sign on both sides of [tex]$x=c$[/tex] then [tex]$x=c$[/tex] is neither a local maximum nor a local minimum.

[tex]$$f^{\prime}(x)=\frac{1}{2 \sqrt{2} \sqrt{x-20}}$$[/tex]

Find intervals: Increasing:20 [tex]$ < x < \infty$[/tex]

Plug [tex]$x=20$[/tex] into [tex]$\sqrt{\frac{1}{2} x-10}+3: \quad 3$[/tex]

Minimum (20,3)

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The function shown in the graph below is modeled by:
a linear function.
an exponential function.
a quadratic function.

Answers

Exponential function because a linear function = straight line and a quadratic function = parabola (U or upside down U shape)

there are about 1,265 school districts in the state of texas that generate an equivalent expression using prime factorization for the number 1,265

pls, help whoever answers first gets brainliest!!

Answers

Answer:

1265 = 5*11*23

------------------------------------------

Find prime factors of 1265.

We see it is divisible by 5 since ends with 5:

1265/5 = 253

253 is not divisible by 3 or 9 since the sum of digits is not divisible by 3 or 9. It is not divisible by 7 (since 25 - 3*2 = 19 is not divisible by 7) but divisible by 11, since the sum of digits in odd places is same as the digit in the even place (recall divisibility by 11):

253/11 = 23

23 is a prime number so no more factors.

Hence the prime factorization of 1265 is:

1265 = 5*11*23

PLEASE HELP QUICK!! WILL GIVE BRAINLIEST AND 25 POINTS!!
Find the value of x, round to the nearest degree.

Answers

Answer:

7

Step-by-step explanation:

4+3=7

7-4=3

7-3=4

Marshall is looking at the key on a map. According to the key, 1 inch = 24 miles. Marshall measures the
distance between 2 cities on the map and discovers they are 11.5 inches apart. How many miles apart are the two cities?

A. 276 miles apart
B. 210 miles apart
C. 249 miles apart
D. 294 miles apart

Answers

Answer:

A. 276 miles apart

Step-by-step explanation:

We have the information that if two cities are 1 inch apart then the distance between them is 24 miles.

If it is 11.5 inches apart, then we should multiply the 24 miles per inch by 11.5

24 miles / 1 inch

(24 miles / 1 inch) * 11.5 inches

Inches cancel so you are left with

24 * 11.5 = 276 miles

M = -21 divided by 0

Answers

By using the property of division, it can be calculated that M = -21 divided by 0 is not possible

What is division?

Division is the process by which value of single unit can be calculated from the value of multiple unit.

The number to be divided is known as dividend, the number by which the dividend is divided is the divisor, the result obtained is the quotient and the remaining part is the remainder.

There is a well known formula for division

Divisor x Quotient + Remainder = Dividend.

Anything divided by 0 is not possible.

M = -21 divided by 0 is not possible

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81 of [60-{8*7-(13-3*5)}] find simply​

Answers

Answer:

Step-by-step explanation:

81 of [60-{(8*7)-(13-(3*5))}] =

81 of [60-{56}-(13-15)] =

81 of [60-{56}-(-2) =

81 of [60-{56}+2] =

81 of [6] =

81% of 6 = 4.86

An equation is shown below.
3x + 4y = 15
Solve the equation for x.

Answers

Answer:

x = [tex]\frac{15-4y}{3}[/tex]

Step-by-step explanation:

3x + 4y = 15 ( subtract 4y from both sides )

3x = 15 - 4y ( isolate x by dividing both sides by 3 )

x = [tex]\frac{15-4y}{3}[/tex]

1 balls and bins throw n balls into m bins, where m and n are positive integers. Let x be the number of bins with exactly one ball. Compute var(x). Your final answer should not contain any summations

Answers

Using 1 balls and bins, n balls are thrown into m bins; m and n are positive numbers. the probability of any given bin containing one ball is n/m n * (1 - (1 - 1/m)^n) / m^2

Given that n is the number of balls and m is the number of bins, the probability of any given bin containing one ball is n/m. Therefore, the variance of x is equal to the variance of a binomial random variable with n trials and probability of success p = n/m.

By the formula for the variance of a binomial random variable, the variance of x is equal to n * (1 - (1 - 1/m)^n) / m^2.

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what lurking variables might be causing the increase in one or both of the variables? explain your answer.

Answers

A lurking variable is an explanatory variable that was not examined in a study but has an effect on the value of the study's response variable.

A concealed variable affects both the dependent and independent variables, resulting in an incorrect connection. Confounding is a causal concept that cannot be expressed using correlations or linkages. Confounders have a significant quantitative role in explaining why correlation does not imply causation.

In the case of risk assessments assessing the degree and form of threat to human health, it is critical to account for confounding in order to isolate the impact of a specific hazard such as a food additive, pesticide, or new drug. It is difficult to recruit and screen volunteers with the same background (age, diet, education, geography, etc.) for prospective studies, and historical investigations can have similar variability.

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find the area of the region enclosed by one loop of the curve. r = 8 sin(5θ)

Answers

16π/5 is the area enclosed by the curve r= 8sin(5θ)

The given curve is polar curve and hence the area of the polar curve is given by:

Let A be the area of the curve so,

A = [tex]\int\limits^a_b {\frac{1}{2} r^2 } \, d\theta[/tex]

where a and b is the boundary at which r=0

so after equation r=0

8sin(5θ) =0

=> sin(5θ) =0

=> 5θ = 0,π

=> θ = 0, π/5

so a=0 , b= π/5

now  

   A = [tex]\int\limits^a_b {\frac{1}{2} r^2 } \, d\theta[/tex]    ------(i)

 so   [tex]r^2[/tex] = (8sin(5θ))^2

=> 64 [tex]sin^2[/tex] ( 5θ )

ans we know that

cos(2α) = 1 -  2[tex]sin^2[/tex] α

so   [tex]r^2[/tex]  =32 (1- cos(10θ) )

putting the value of r in the equation (i) we get :-

A = [tex]\int\limits^a_b {\frac{1}{2} *32(1-cos(10\alpha ) } \, d\alpha[/tex]

=> 16 * [tex]\int\limits^a_b {(1-cos(10\alpha ) } \, d\alpha[/tex]

here a=0 and b=π/5

after putting the value and solving the integral

A = 16π/5

so A is the area enclosed by r=8sin(5θ) is 16π/5

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Karen earns £12.80 an hour for a 35 hour week, time and a half on the next 6 hours and double time after that. How much does she earn for a 43 hour week?

Answers

Answer:

I hope the image helps!

14)
a) Find the equation of a parabola which has a vertex at (2,-3) and passes through the point
(5,7).

Answers

So we know that the parabola is of the form

a(x-h)²+k where (h,k) is the vertex. The vertex in this case is (2,-3). Therefore

Let h=2 and let k=-3 and let the point (5,7) be of the form (x,y) so let x=5 and y=7

So we have the vertex form as

y=a(x-h)²+k

Substituting y=7 for y, x=5 for x, h=2 for h and k=-3 for k, we get

7=a(5-2)²+(-3)

Which is

7=a(5-2)²-3.

Now we need to solve for a.

So we get the following

7=a(5-2)²-3

Subtracting 5 and 2 we get

7=a(3)²-3

Simplify 3² as 9 we get

7=a(9)-3

So we have the linear equation

7=9a-3

Adding 3 to both sides we get

10=9a

Dividing both sides by 9 we get

a=10/9

So the equation in vertex form for this parabola should be

y=(10/9)(x-2)²-3

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