for what wavelength of light is the scattering only 2.00 % that of light with a visible wavelength of 520 nm ?

Answers

Answer 1

Potentially, optical scattering can be employed to create a solids content assessment instrument that is useful for managing and monitoring tailings ponds.

This bench-scale study looked into the best laser wavelengths for real-time in situ use in oil sands tailings in the visible (405, 520, and 658 nm) and near infrared (980, 1310, and 1550 nm) ranges. In comparison to the visible wavelengths, the near infrared wavelengths generally showed greater sensitivity across the full test range. Additionally, oil sands tailings' remaining bitumen has a tendency to absorb visible wavelengths, interfering with the scattering light signals and resulting in unreliable results. The 1550 nm wavelength in particular demonstrated an almost linear sensitivity of the light scattering with the change in solids concentration due to a sufficiently strong water absorption.

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Related Questions

can an elliptical galaxy evolve into a spiral? explain your answer. can a spiral turn into an elliptical? how?

Answers

Due to the fundamental differences between these two galaxy types, galaxies cannot evolve from elliptical to spiral (or spiral to elliptical).

It seems that spirals do create elliptical galaxies when they collide. Each one starts out as a spiral galaxy, and an elliptical galaxy is created when galaxies collide and combine.

For example, in contrast to spiral galaxies, which include gas and dust as well as hot, bright O and B type stars, elliptical galaxies are devoid of visible gas and dust and hot, brilliant stars.

A galaxy with an elliptical shape and a uniform brightness distribution is called an elliptical galaxy (no spiral arms). Elliptical galaxies are stretched galaxies with an elliptical shape, according to astronomical physics. The light is distributed evenly and smoothly throughout this type of galaxy, which is typically composed of old stars.

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Which of the following is not true about Magnetic field Lines? 1 point Are always north to side outside magnet Are always south to north inside the magnet Are always north to south inside the magnet Has tangential direction at curves

Answers

The statement that is not true about magnetic field line is that they are always from north to south inside the magnet.

When a bar magnet is observed closely in the presence of the small metal granules.

We can observe a pattern, the magnetic field lines are always from north to south outside the magnet.

But when we talk about inside the magnet the direction of the magnetic field lines are from South to North.

Magnetic lines forms a loop like shape outside the magnet the direction of which is given by a tangent drawn to the curve of the magnetic field line.

The direction of the magnetic field line is tangential at the curves.

So the only statement that is not true about the magnetic field lines are that they are from north to south inside the magnet.

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an element of atomic number 88 decays radioactively to an element of atomic number 82.
Which of the following emissions achieve this result?
a. one alpha particle and one beta-minus particle
b. three alpha particles
c. one alpha particle
d. six beta-minus particles

Answers

An element of atomic number 88 decays radioactively to an element of atomic number 82 six beta-minus particles.

Isotopes are atoms that share the same atomic number but have various neutron numbers, which change their mass numbers. The standard atomic weight of an element is determined by the average isotopic mass of an isotopic mixture for that element in a specific environment on Earth (referred to as the relative atomic mass; see monoisotopic elements). Less than three-quarters of naturally occurring elements are isotope mixtures (see monoisotopic elements). In the 19th century, chemists were able to measure the amounts of the elements based on their relative atomic weights to hydrogen. Prior to the modern synthesis of concepts from physics and chemistry, an element's numerical position in the periodic table, which at the time was roughly in the following order, was all that the customary symbol Z represented.

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You live on a busy street, but as a music lover, you want to reduce the traffic noise.Part A If you install special sound reflecting windows that reduce the sound intensity level by 20.0 dB, by what factor have you reduced the sound intensity?Part B If, instead, you reduce the intensity by half, what change (in dB) do you make in the sound intensity level?

Answers

A. You have decreased the sound intensity by 0.01 factor if you install special sound-reflecting windows that lower the level of sound intensity by 20.0 dB.

B. No, Instead, if you cut the intensity in half, there is no difference in the sound intensity level (measured in dB).

To calculate the sound intensity reduction factor, use the relationship between loudness and intensity. Calculate the change in sound intensity using the reduced intensity. The following chart shows the relationship between the change in loudness and the level of sound intensity.

dl = 10log(I/I1)

Here, dl represents the change in loudness, I represents sound intensity, and I1 represents the reference sound intensity in air.

I =(I1/2)

(A) The following is the expression for a reduction in sound volume:

10log*(I/I1) divided by 20 equals dl.

(I/I1)

The negative symbol denotes a drop in sound volume.

log(I/I1) = -20/10

I/I1 = 10^(-20)

I/I1 = 1/100

I/I1 = 0.01

The reduction is thus 0.01 as a result.

B) The initial and ending values of the sound intensity parameters affect how loud the sound is. Sound is louder and its waves are more intense. Loudness increases by 10 times for every 10dB increase in sound intensity. The intensity is reduced by a factor of two from its initial value, hence the change in sound intensity is negative. The strength of the ear's perception of sound is referred to as sound loudness.

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which of these correctly compares the masses of different objects in the universe?

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In comparison to a galaxy and a planet, a star is heavier. an accurate comparison of the cosmological masses of various objects.

Do stars have more mass than planets and less mass than galaxies?

A galaxy has a mass that is between that of a moon and that of a planet. A planet has more mass than a star, which has less mass than a galaxy. The stars need a lot of mass to maintain nuclear fusion, which requires resulted in the production of each.

What is the proper ranking of the universe's elements, from smallest to largest?

Planets and stars, solar systems, galaxies, and the cosmos are some key concepts to keep in mind in the following order: smallest to largest. Each phrase is a part of the following.

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what is the energy of the atom in each of the levels (n=1, n=2, etc.) shown in the figure?

Answers

Since the second energy level has more energy than the first, the electron must gain energy to travel from n = 1 to n = 2. To increase to the second energy level, it must gain (-3.4) - (-13.6) = 10.2 eV of energy.

By absorbing light, the electron can obtain the energy it requires. The electrons in an atom revolve around the nucleus. Small, negatively charged particles known as electrons move in a circular orbit around the nucleus. They are unable to move around at will in any location. Depending on their energy levels, their revolution is limited to certain orbits. Energy levels are nothing more than the electrons' set distances from an atom's nucleus. The electron shell is another name for the energy levels. An electron can migrate across energy levels, but it cannot remain in one energy level while in another.

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if the highest frequency of a circuit is 10 khz and the lowest frequency is 900 hz, the bandwidth available for this circuit is:

Answers

When the highest and lowest frequency of a circuit is given then bandwidth is  calculated as 9100 Hz.

What is bandwidth?

Maximum amount of data transmitted over an internet connection in given amount of time is known as bandwidth. Bandwidth is actually the volume of information that can be sent over a connection in a measured amount of time.

In signal processing, bandwidth describes difference between upper and lower frequencies in transmission signals. The measurement of bandwidth of a signal is done in hertz (Hz).

Given highest frequency of circuit is 10 kHz

= 10000 Hz

and lowest frequency of circuit is 900 Hz

Bandwidth = 10000 Hz -900 Hz

So, Bandwidth = 9100 Hz.

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in which direction is the puck moving at t = 3 s ? give your answer as an angle from the x-axis.

Answers

The puck is moving at an angle of 51 degrees from the x-axis.

As we can see from the graph of the question the value of x component of velocity  [tex]v_{x}[/tex] is nearly 24 cm/s and the value of y component of velocity [tex]v_{y}[/tex] is constant throughout the journey of puck and is equal to 30cm/s. For any instant of time the direction is given by the slope of the graph tanθ which is equal to the y component divided by the x component.

At the instant when t= 3s

[tex]v_{x}= 24 cm/s\\v_{y}= 30 cm/s\\[/tex]

Direction is given by the slope of the graph  

tanθ= [tex]\frac{v_{y} }{v_{x} } = \frac{30}{24}[/tex]=  1.25

θ= 51 degrees from x-axis (in anti-clockwise manner)

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identify the stage in star life cycle in which hydrogen is the primary fuel for nuclear fusion?

Answers

Answer:

Main sequence star: (b) burns hydration as its primary fuel.

Explanation:

A child on a spinning ride at a playground has a centripetal acceleration of 0.80 m/s2. The child completes a full circle every 4.2 s.

How far from the center of the ride is the child?

Answers

The velocity of the child is 3.36 m/s. Then, the distance it covered is 14 meters. The radius from the centre is then, 2.24 m.

What is centripetal acceleration?

Centripetal acceleration is the acceleration of a body moving through a circular paths. It is the rate of change of its angular velocity.

The acceleration of the child = 0.80 ms/²

time  = 4.2 s

velocity = time interval × acceleration

             = 4.2 s ×  0.80 ms/²= 3.36 m/s.

Then the distance covered  = velocity × time

= 3.36 m/s × 4.2 = 14.22 m.

This is the circumference of the circular path which is equal to 2πR.

The distance from the centre = radius of the path.

2πR = 14.22 m

R = 2.24 m

Therefore, the child will be 2.24 m far from the center of the ride.

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Which of the following is the correct order of wavelength?
A
Radio waves
>
UV rays >
X-rays
>
γ
â
rays
B
UV rays >
Radio waves
>
X-rays
>
γ
â
rays
C
γ
â
rays
>
X-rays
>
UV rays >
Radio waves
D
X-rays
>
γ
â
rays
>
UV rays >
Radio waves

Answers

The wavelengths are listed below in ascending order from left to right. Gamma rays, X-rays, UV, visible, infrared, microwaves, and radio waves are all types of radiation.

The electric field and magnetic field combine to form the numerous waves that make up the electromagnetic spectrum. The electromagnetic wave is considered to have both wave and particle behavior.

The wavelength and frequency of electromagnetic waves are essentially determined by the wave's particle-like components, known as photons, which carry the wave's energy. The term "electromagnetic spectrum" refers to the class of electromagnetic waves.

In order of increasing wavelength, electromagnetic waves include gamma rays, x-rays, ultraviolet, visible, infrared, microwaves, and radio waves.

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if the ball exits the track while undergoing an acceleration of 3g (3 times the acceleration due to gravity), how far away from the base of the track does the block land?

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If the ball exits the track while undergoing an acceleration of 3g, 55.4m away from the base of the track does the block land

Acceleration ac = V²/R = 3g

V = √3gR

By using kinematic equation for vertical motion of ball,

S = u t  + 1/2 gt²

S = 2R, U = 0

t = √4R/g

Horizontal distance is given by

D = vt = √3gR × √4R/g

D = 2√3 R

D = 55.4m

To get the equation for the horizontal distance, one can rearrange the slope percent equation. Divide both sides by run to rewrite the equation's terms. The slope percent is applied to both sides. Horizontal distance is calculated as run = (rise 100) / slope%. When two points are separated by a horizontal distance, the slope is zero percent.

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if the moment of inertia of the shaded area about the a-a' axis is 18e6mm^4 what is the moment of inertia about the b-b' axis

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The moment of inertia about the b-b' axis is 24.6E6 mm^4.

To find the moment of inertia of the shaded area about the B-B' axis, we can use the formula I = ∑m*r^2, where m is the mass of each particle in the shaded area, r is the distance of each particle from the B-B' axis, and the sum is taken over all particles in the shaded area.

We are given that the moment of inertia of the shaded area about the A-A' axis is

18E6 mm^4,

and that the area of the shaded region is

A = 6E3 mm^2.

We are also given the distances

ds = 50 mm and d₂ = 10 mm,

which correspond to the distances of the two particles in the shaded region from the B-B' axis.

The mass of each particle in the shaded region can be calculated by dividing the total mass of the region (which is equal to the product of the area and the density of the material) by the number of particles. Since the density of the material is not given, we cannot calculate the mass of each particle.

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Complete Question:

If the moment of inertia of the shaded area about the A-A' axis is 18E6 mm, what is the moment of inertia about the B-B' axis?

Given: A6E3 mm², ds-50 mm, d₂-10 mm

a. none of these answers

B. 21.2E6 mm^4

C  25.2E6 mm^4

D. 26.3E6 mm^4

E. 24.6E6 mm^4

the mean distance between the earth and the sun is 1.50×1011 m. the average intensity of solar radiation incident on the upper atmosphere of the earth is 1390 w/m2. assuming that the sun emits radiation uniformly in all directions, determine the total power radiated by the sun.

Answers

The power radiated by the sun is 3.93* 10²⁶W.

What is power ?

Work rate or energy delivery time is expressed as W/t, where W is the quantity of work completed or energy delivered, and t is the time interval.

What is intensity ?

Intensity is the amount of energy a wave carries over a surface of a particular area in a unit of time, and it is the same as the energy density times the wave speed. The most popular unit of measurement is watts per square metre. The strength and size of a wave affect its frequency.

The main concept used to solve this problem is power emitted by radiation.

Initially, find the surface area covered by the sun’s radiation using the formula of area of a sphere. Then, use the expression of power to find the power radiated by sun.

The surface area of a sphere can be written as follows:

A= 4πr²

Here, r is the radius.

The power emitted by radiation can be calculated by using the following expression:

P= IA

Here, I is the intensity and A is the area.

Step: 1

The surface area of a sphere can be written as follows:

A= 4πr²

Substitute

1.5*10⁻¹¹m

for r in the above expression.

A=4π ( 1.5*10¹¹M ) ²

= 2.8274*10²³m²

The sun emits radiation in all the directions around it and in a uniform way. This means that the level of intensity of the radiation reaching earth will be same for all the objects which are placed at the same distances from the sun. that is, the surface area of the sphere of radius as the distance between sun and earth will get same intensity of the radiation emitted by the sun.

Use the expression of power to find the power radiated by sun.

Step: 2

The power emitted by radiation can be calculated by using the following expression;

P= IA

Substitute

1390W/m²

for I and

2.8274*10²³m²

for A in the above expression.

P= (1390W/ m²) ( 2.87274*10²³m²)

= 3.93*10²⁶W

The radiation emitted from the sun is spread over large spherical surfaces, so the energy per unit square meter decreases as the radii of the spherical surface increases. The far the planet from the sun, the smaller will be the energy per unit square meter.

Therefore, the power radiated by the sun is 3.93* 10²⁶W.

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in pushing a load, a woman exerts a force as given by the graph. what was the total work done by the woman?

Answers

The total work done by the woman is 1000J.

The work done by a force is defined as the product of the displacement component of the force and the magnitude of that displacement. method. Work can be calculated by multiplying the force and the displacement in the direction of the force as

When a person pushes against a wall the displacement of the wall is zero because the wall does not move when a force is applied to it. The work done by a force is the product of the component of the force applied to the body in the direction of displacement and displacement.

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an object weighs 432 n on the surface of earth. at a height of 3rearth above earth's surface, what is its weight?

Answers

On the earth's surface, an object weighs 432N. At a height of 3R above earth's surface, its weight will be 27N

Given the weight on surface of earth (F) = 432N

let radius of earth be R

Height increased (h) = 3R

Weight at certain height of 3R = F2

We know that  the force due to gravity decreases by the square of the radius.

From the formula: g1 = g(R/R+h)^2

g1 = g(R/R+3R)^2 = g(1/4)^2

g1 = g/16

We know that Force(F) = mg

Force at a height of 3R from surface of earth = F2

F2 = mg1 =mg/16 = F/16

Weight at this height = 432/16 = 27N

Hence the weight of object at a height of 3R from surface of earth is 27N

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The input preure on a hydraulic lift i 1200 Pa. If the output force on the other ide i 800 N, what i the output urface area?

Answers

A hydraulic lift's input pressure is 1200 Pa. If the output force on the other side is 800 N, the output surface area is 0.67m^2

Given the input pressure (P1) = 1200Pa

Output force (F2) = 800N

We know that P= F/A where A is area of cross section

Let the input force be F1 and area is A1

Then by pascals law we say that:

F1/A1 = F2/A2

1200 = 800/A2 (since P1= F1/A1)

A2 = 8/12 = 0.67m^2

Hence the area of other side = 0.67m^2

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if you continue to exert this force once the crate starts to slip, what will its acceleration then be?

Answers

a) The maximum force that can be applied horizontally to the crate without moving it is 58.8 N.

b) The magnitude of the acceleration on the crate that starts to slip is  1.96 m/s².

The given problem is based on the concept of friction. If the crate is stationary and maximum horizontal force is applied, maximum static friction will act. If the crate starts sliding, kinetic friction will start to act. Newton's laws can be written in both cases. With the solution, we will get the maximum horizontal force in the first case and the acceleration in the second case.

a) A crate is not moving:

Because the crate is in balance

N = m.g

[tex]F_s[/tex] = Static

[tex]F_s[/tex] < F_max and F_max = μ[tex]_s[/tex]mg

In question:

μ[tex]_s[/tex] = 0.5, m = 12 kg, g = 9.8 m/s

F_max = μ[tex]_s[/tex]mg

F_max = 0.5 x 12 x 9.8

F_max = 58.8 N

b) Crate has started slipping:

F = F[tex]_s[/tex] - F[tex]_k[/tex]

m.a = μ[tex]_s[/tex]mg - μ[tex]_k[/tex]mg

   a = g (μ[tex]_s[/tex] - μ[tex]_k[/tex])

   a = 9.8 (0.5 - 0.3)

   a = 1.96 m/s²

So, crate acceleration has started slipping is 1.96 m/s²

Complete question:

Suppose you have a 120-kg wooden crate resting on a wood floor (μ[tex]_k[/tex]

= 0.3, μ[tex]_s[/tex] = 0.5).

(a) what maximum force can you exert horizontally on the crate without moving it?

(b) if you continue to exert this force once the crate starts to slip, what will the magnitude of its acceleration then be?

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the heat capacity of manganese is 0.480 kj kg-1 k-1. how much energy is required to raise the temperature of 3.00 kg of manganese by 20.0 k?

Answers

The amount of energy required by 3 kilogram of Manganese to raise the temperature by 20 degree kelvin is 28.8 KJ.

The heat capacity of manganese is given to be 0.480 KJ/kg-K.

We have to raise the temperature of 3 kilogram of Manganese by 20 degree kelvins.

We know that the change in heat of the compound is given by the formula,

Q = MC∆T

Where Q is the heat/energy gained,

C is the heat capacity of Manganese,

∆T is the total change in temperature of Manganese.

Putting values in the above relation accordingly,

Q = 0.480 x 3 x 20

Q = 28.8 KJ.

So the energy required to raise the temperature of Manganese by 20 kelvin is 28.8 KJ.

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why can we readily observe diffraction effects for sound waves and water waves, but not for light? is this because light travels so much faster than these other waves? explain.

Answers

Wavelengths of sound waves fall within such obstacles and are easily diffracted.

Sound waves have higher wavelengths, which are comparable in dimension to opaque encounters in our everyday life. Thus, diffraction effects are more visible in sound waves than in light waves. Sound waves have much longer wavelengths than visible light waves.

Wavelength is the distance between identical points in adjacent cycles of a waveform signal propagating in space or along a wire. In wireless systems, this length is usually expressed in meters, centimeters, or millimeters. Wavelength is the distance between two wave crests and the same for wave troughs.

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the answer this is physics

Answers

Answer:

1/4

Explanation:

(2,3)=(x1, y1)

(6,4)=(x2,y2)

Then,

Slope=(y2-y1)/(x2-x1)

=1/4

The electric force between two or more charged objects depends on which of the following quantities?

a. charge and distance between the charged objects
b. quantity of charges and their masses
c. charge and mass of charged objects
d. mass and distance between the charged objects

Answers

The electric force between two or more charged objects depends on the charge and the distance between the charged objects

What is Coulomb's law?

Coulomb's law states that the force of attraction or repulsion between two charged bodies is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Coulomb's law shows the relationship between the force , charge and the distance between the bodies

therefore F= kq1q2/r²

where q1 is the charge of body 1 and q2 is the charge of body 2. r is the distance between them and k is called electrostatics constant which have a value of 9,×10⁹ Nm²/C²

Therefore what can affect the force between two charges are the product of the charge of the two bodies and the distance between the two charge.

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a 25 kg bear slides, from rest, 12 m down a lodgepole pine tree, moving with a speed of 5.6 m/s just before hitting the ground. (u) what change occurs in the gravitational potential ener

Answers

The gravitational potential energy of the bear decreases as the bear slides from top to bottom of the pine tree.

Given that,

Mass of the bear = 25 kg

Speed of the bear = 5.6 m/s

Height from which the bear slides = 12 m

Gravitational potential energy depends on the height of the bear. As the bear slides from top to bottom, the height keeps decreasing gradually. The formula for gravitational potential energy is P.E = m* g* h

where, m is the mass of the bear

g is the acceleration due to gravity

h is the height at which the bear stays

From the above relation, it is clear that, potential energy is directly proportional to the height of the object.

Thus, gravitational potential energy of the bear decreases as the bear slides down the pine tree.

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a dog and a mouse run along a road with the same kinetic energy. the faster runner is the

Answers

The faster runner is the mouse.

Kinetic energy is the type of energy carried by any moving object or subatomic particle. Any object or particle in motion possesses kinetic energy. Kinetic energy manifests itself in many everyday phenomena, such as walking, throwing a baseball, dropping a crumb, traveling through an electric field, etc. Only things in motion can store kinetic energy, hence a still object has none.

Potential energy is held by inanimate objects like rocks and plants. A body's potential energy is transformed into kinetic energy whenever a force, such as gravity, acts upon it and sends it into motion. For example, stretching a rubber band stores energy as elastic potential, which is then converted to motion when the band is released from its stretched state.

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A particular species of copepod, a small marine crustacean, emits a flash of light consisting of 1.4* 10
10
photons at a wavelength of 490 nm. The flash lasts for 2.4 s. What is the power of the flash? Express your answer with the appropriate units.

Answers

The power of flash light is [tex]2.36*10^{-9}\ W[/tex] when light emits [tex]1.4*10^{10}[/tex] photons of wavelength is 490nm for 2.4 seconds.

The fundamental particle of light is both mundane and surprising. What physicists refer to as photons, laypeople may simply refer to as light. Photons are the smallest possible packets of electromagnetic energy as quanta of light.

Given,

The wavelength of photon = 490 nm

Number of photons, n= [tex]1.4*10^{10}[/tex]

The flash light lasts for time ,t =2.4 s

The energy of a single photon can be determined by formula,

[tex]E=\frac{hc}{\lambda}\\\\[/tex]

Where,

h= planck's constant = [tex]6.62*10^{-34}[/tex]

c=speed of light = [tex]3*10^8 m/s[/tex]

\lambda = wavelength of light =490 nm = [tex]490*10^{-9}m[/tex]

[tex]E=\frac{6.62*10^{-34}*3*10^8}{490*10^{-9}}\\\\E=4.05*10^{-19}\ J[/tex]

Then the energy for n photons will be [tex]nE=1.4*10^{10}*4.05*10^{-19}[/tex]

The power of the n photons can be determined by formula,

[tex]P=n*E*t\\\\P=1.4*10^{10}*4.05*10^{-19}\\\\P=2.36*10^{-9}\ W[/tex]

Thus, the power of the flash light is [tex]2.36*10^{-9}\ W[/tex]

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a trailer truck traveling east at 24m/s sounds a 950 hz horn. what is the wavelength of the sound heard by a stationary listner located est of the truck

Answers

The wavelength of the sound heard by a stationary listner located est of the truck is  0.332 m

F = fο (V/V - Vs) ,Doppler effect

  = 950 (340 / 340 -24) = 1022.25 HZ

λ = V / F = 340 / 1022.25 = 0.332 m

Everything in sound is a vibration. The larynx (voice box) of a person, the string of a guitar, or the loudspeakers on your radio all need to vibrate in order to produce sound. When sound waves move away from their source, vibrating particles knock into other vibrating particles, which in turn causes those other particles to vibrate and knock into still more particles, and so on. Our eardrums vibrate in response to air vibrations, and these vibrations are then transformed into nerve signals and delivered to our brains, which enable us to perceive sound. Similar to this, microphones translate air vibrations into electrical signals after detecting them.

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FILL IN THE BLANK. The period of a sine or cosine function is given by ______. phase shift. For the function given by y = sin(bx-c), c/b represents the ______ ______ of the ...

Answers

The period of a sine or cosine function is given by 2Pi/b.

For the function given by y = sin(bx-c), c/b represents the phase shift of the graph of the function.

A period is the amount of time between two waves, whereas a periodic function is one whose values recur at regular intervals or periods. In other terms, a periodic function is one whose values recur after a specific interval.

If we have f (a + m) = f (a), then a function f will be periodic with period m for every m > 0.

It demonstrates that after an interval of "m," the values of the function f(a) remain the same.

One may state that the function f repeats all of its values after every interval of "m."

Phase shift merely denotes that the two signals are, at any given time, at different positions in their cycle.

Phase shift, which depicts how each wave moves through its cycle, is measured as the angle (in degrees or radians) between two points on a circle at the same moment.

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a tuning fork is struck and oscillates in damped harmonic motion. the amplitude of the motion is measured, and 6 s later it is found that the amplitude has dropped to 1 4 of this value. find the damping constant c for this tuning fork. (round your answer to two decimal places.) c

Answers

The value of the damping constant of the tuning fork will be equal to the value 0.23 s⁻¹.

The equation for the damping of harmonic system is expressed as

y = Xe^(-Ct) sin(ωt)

where Xe^(-Ct) = A that is amplitude and C is the damping constant.

If we assume that at time = t the value of A = K and at time = t + 6 the value of A = K/4 then the expression for amplitude will be

K = Xe^(-Ct)

K/4 = Xe^(-C(t + 6))

On dividing the two equations we get

4 = e^(6C)

Taking natural log on both sides we get

ln(4) = 6C

=> C = 1/6 ln(4)

=> C = 0.23 s⁻¹

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in the bohr model description, what is the kinetic energy of the electron? express your answer in electron volts.

Answers

An electron in the first Bohr orbit has a kinetic energy of 13.6 eV. A tiny, positively charged nucleus is around by rotating, negatively charged electrons in set orbits, according to the Bohr Atomic Model.

What is Bohr's atomic model?

The Bohr model postulates that the electrons orbit the nucleus at fixed energy levels and also concluded that electron has more energy if it is located away from the nucleus whereas the electrons have less energy if located near the nucleus.

Bohr proposed that electrons do not radiate energy as they orbit nucleus, but exist in state of constant energy that is called stationary states. Bohr's work was based on the emission spectra of hydrogen.

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a speeding driver sees a police officer, hits her brakes, and changes her speed from 41 mph to 18 mph in 2.7 seconds. what was her average acceleration (in m/s2) during this time?

Answers

Her average acceleration (in m/s2) during this time is  8.5 mph / sec².

Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.

Calculation:-

V 1 = 41

V 2 = 18

time = 2.7 seconds

Acceleration = V2 - V1 / time

                      = 18 - 41 / 2.7

                       = 23 /2.7

                       = 8.5 mph / sec²

Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. Movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.

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