Answer:
The notable examples are metal bearings, with occasional lumps on the otherwise smooth surfaces catching against each other, and the flow of an electric
Conversions of Kinetic energy to and from potential energy in vacuum converts with very little loss. If you throw a rock up against gravity in a vacuum, that rock will reach a potential energy that is almost exactly equal to the initial kinetic energy. When the rock reaches its peak and comes back down, its kinetic energy will be almost exactly the same when it reaches the original altitude.
the colour of the shadow of coloured objects is not same as the colour of the objects
When an opaque item absorbs all of the light falling from a light source, no light is reflected, and the thing appears black. The color of an object's shadow is independent of its hue; it can be red, yellow, green, or black.
. The artificial sweetener NutraSweet is a chemical called aspartame (C14H18N2O5). What is (a) its molecular mass (in atomic mass units)? (3) (b) the mass (in kg) of an aspartame molecule?
The molecular mass, in atomic mass unit, of aspartame would be 294 amu while the mass, in kg, of an aspartame molecule would be 0.294 kg
Aspartame has the chemical formula C14H18N2O5
C = 12, H = 1, N = 14, O = 16
(a) Molecular weight = (12x14) + (1x18) + (14x2) + (16x5)
= 168 + 18 + 28 + 80
= 294 amu
(b) Mass of 1 molecule of aspartame = mole x molar mass
= 1 x 294
= 294 g
Converting 294 g to kg = 294/1000
= 0.294 kg
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một vật dao động trong 10 phút thực hiện 500 dao động tính chu kì và tần số dao động
Answer:
Explanation:
T = 10(60)/500 = 1.2 s
f = 1/T = 0.83 Hz
While closing a door of mass 10 kg, a student pushes on it with a force of 25 N. As the door is accelerating to close, what
force does the door exert on the student?
A.5n
b.25n
c.250n
d.35n
Answer:
its 30 n
trust me
If the mass is 2.0 kg and the acceleration is 5 m/s/s, then what is the force?
Answer:
Explanation:
F = ma = 2.0(5) = 10 N
2. What are the units of mass?
kg
N
m/s
m/s^2
(kg)(m/s)
m
S
Answer:
Kg
Explanation:
The units of mass are gram (g) , kilograms (Kg)
But SI of mass accepted is Kilograms (Kg)
Answer:
kg
Explanation:
the s.i unit is kilogramhow much kinetic energy is stored in a 1.5 kg object that is moved at 15 m per second
Answer:
Explanation:
KE=0.5xM(Vpower2)
=0.5x1.5(15power2)
=168.75
what does that mean?
Answer:
Acceleration is the rate at which the velocity changes .
Hope it's help you !!One of your classmates, in a fit of unrestrained ego, jumps onto a lab table:
a) Draw a qualitative force diagram for the table. Use marks on the vectors to show the balance of forces.
b) Your classmate’s mass is 65 kg and the table weighs 0 N. Calculate the normal force on the table by the floor. Show your work!
c)Find the mass of the table
The equilibrium condition allows finding the results for the forces of the system are
a) The free body diagram is in the attachment
b) The normal force is N = 737 N
c) The mass of the table is 10.2 kg
Newton's second law indicates that the net force is proportional to the product of the mass and the acceleration of the bodies, in the special case that the acceleration is zero, it is called the equilibrium condition
∑ F = 0
Where the bold letters indicate vectors, F is the external forces
a) A free body diagram is a scheme of the forces without the details of the bodies, in the attachmentt we see a free body diagram of the system.
b) The reaction force of the ground is applied in each of the legs of the table, in general this force has the same magnitude in each leg, therefore in Newton's second law we can place it as a single force
N = N₁ + N₂ + N₃ + N₄₄
Let's apply the equilibrium condition
N - [tex]W_m -w_{table}[/tex] = 0
N = [tex]W_m +w_{table}[/tex]
N = [tex]M_m g + w_{table}[/tex]
They indicate the pose of the boy is 65 kg, for the weight of the table of a laboratory table is approximately 100 N
N = 65 9.8 + 100
N = 737 N
c) To calculate the mass of the table we use the relation
W = [tex]m_{table}[/tex] g
[tex]m_{table} = \frac{w_{table}}{g}[/tex]
[tex]m_{tabble}= \frac{100}{9.8}[/tex]
[tex]m_{table}[/tex]e = 10.2 kg
In conclusion using the equilibrium condition we can find the results for the forces are
a) The free body diagram is in the attachment
b) The normal force is N = 737 N
c) The mass of the table is 10.2 kg
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Maganda ka Tapos Liit mopa
Answer:
naol may pinoy dito nag jakoI
Answer:
jupiter mars and sun
Explanation:
Find the center of the galaxy with Shapley method
Answer:
Calculating Center
Shapley correctly determined the galactic center of the Milky Way to be located in the constellation of Sagittarius. He did this by mapping out a three-dimensional distribution of the globular clusters.
Explanation:
Mark me the Brainliest..PLS
An LED bulb transfers 200J of energy in 20s. Its power rating is ...
Answer:
[tex]\huge\boxed{\sf P = 10\ Watts}[/tex]
Explanation:
Given:
Energy = E = 200 J
Time = t = 20 s
Required:
Power = P = ?
Formula:
P = E / t
Solution:
P = 200 J / 20 s
P = 10 Watts
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807Does a paddle boat’s wheel rotate clockwise or counterclockwise? PLS HELP
Explain in terms of refraction and wavelength, why dispersion of white light happens.
Pls help
I will put brainliest
Answer:
terms of refraction and wavelength, why dispersion of white light happens.
Explanation:
hope it helps
21) A charged polyester ball is placed over a charged PVC pipe. The ball, which
has a mass of 1.2 grams, rests 42 cm above the pipe. If the ball and pipe have
the same negative charge, what is the charge on the ball?
The negative charge on the polyester ball is -1.53 x 10⁻⁶ C.
The given parameters;
mass of the ball, m = 1.2 gdistance between the ball and the pipe = 42 cm = 0.42 mThe gravitational force on the ball is calculated as follows;
F = mg
F = 0.012 x 9.8
F = 0.12 N
The electrostatic force on the ball is calculated as follows;
[tex]F= \frac{kq^2}{r^2} \\\\q^2 = \frac{Fr^2}{k} \\\\q = \sqrt{\frac{0.12 \times (0.42)^2}{9\times 10^9}} \\\\q =+/ -\ \ 1.53 \times 10^{-6} \ C\\\\q =-\ \ 1.53 \times 10^{-6} \ C[/tex]
Thus, the negative charge on the polyester ball is -1.53 x 10⁻⁶ C.
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Which diagram illustrates that matter is always conserved in a chemical reaction?
Answer:
Only the third option has the same number of each size and color circles on either side of the arrow.
Explanation:
I believe it represents the dissolution of two molecules of hydrogen peroxide into two water molecules and an oxygen gas molecule.
The first one balances oxygen but changes sulfur with either carbon or nitrogen
The second one needs 5 oxygen gas pairs instead of a single one on the left to balance the right side. Represents oxidation of a propane molecule if given enough oxygen.
The fourth one has an extra nitrogen on the left side. The hydrogen is balanced. Making amonia.
If a 2 kg block of aluminium (SHC: 921 J/kg°C) is heated from 20°C to 40°C, how much energy was transferred to it?
H = mc∆T
where, H=heat energy
c = SHC
H = 2*921*(40-20)
H = 36840J
H = 36.84KJ
The energy transferred to it is 36.84KJ
The energy transferred to aluminum from 20°C to 40 °C is equal to 36840 J.
What is the specific heat capacity?The specific heat capacity can be described as the quantity of heat required to increase the temperature of 1 unit of substance by one degree Celsius. The specific heat capacity of the substance depends upon the nature of the substance.
The mathematical equation is used to calculate the specific heat is equal to:
[tex]Q = m\times C\times \triangle T[/tex]
Given, the mass of the aluminum block, m = 2 Kg
The initial temperature of aluminum, T₁ = 20 °C
The final temperature of the aluminum, T₂ = 40 °C
The specific heat capacity of aluminum, C = 921 J/kg°C
The energy transferred to the aluminum block:
Q = 2 × 921 × (40-20)
Q = 36840 J
Therefore, the energy transferred to aluminum from 20°C to 40°C is 36840 J.
Learn more about specific heat capacity, here:
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#SPJ2
A ball is thrown from the top of a 15.0 m tall building. The ball is initially released with a speed of 25.0 m/s in the direction 30.0 degrees above the horizontal. 2.00 seconds after it was released, the ball is traveling with a speed of 22.8 m/s in the direction 18.2 degrees below the horizontal. Using a coordinate system where x points in the direction the ball was released and y points up, what is the y component of the ball's motion after 2.00 seconds
Answer: the final velocity and final velocity velocity can also be written as we It went to one route A. V. Of X. Care plus movie. Why is here? This is a vision number two. And this is a revision number one food equation and one into to get we want to and wrote. We now takes scared plus we not scared away helpless to And by and the horizontal and the vertical component which are we know scare X is equal to we not cost it and we're not scared by going to we not scientific putting these value. Immigration number three. We get we will too. Are we not scared? I got scared to to less. We not scare Science square theater plus two. Why? So this we equal to he went to work and rude. We're not scared people to got scared he to less science security theater Last two. A. Y. Sure we get we s we're not scared into I. Plus to A Y. So we is able to. And road we now scared. Plus two. Am I. So this is a vision number four. And we are given me an artist 14 m purse again. And why he has given us. Uh huh. three m. So we can we find out by putting this value innovation number for the disk 14 scared. Uh huh. Plus To into -9.8 into three. We get to be It will do 11.7. Me did last
Explanation:
HELP ME PLZZZ
You attach a cart with a mass of
0.92 kg to a spring and compress the cart-
spring system. The spring constant for the spring is 130 N/m. Your objective is
to propel the cart with a velocity of 1.4 m/s along a frictionless surface. How
need to compress the spring in order to meet your target velocity?
far do
you
One train (22,680 kg) moving east at 170 km/h collides with a car (1,200 kg) that was moving north at 5 km/h. They get attached to each other, moving in the direction of the train. What is the final velocity of the objects and the type of collision? If the collision happened in 1.2X10-3 seconds, what was the force? How much kinetic energy was lost?
According to the law of collision'
m1u1 + m2u2 = (m1+m2)v
Given the following:
m1 = 22,680kg
u1 =170km/h
m2 = 1200kg
u2 = 5km/hr
Get the final velocity "v"
22680(170) + 1200(5) = (22680 + 1200)v
3855600 + 6000 = 12880v
3,861,600 = 12880v
v = 3,861,600/12,880
v = 229.82km/hr
Hence the final velocity of the objects is 229.82km/hr
Since energy was lost after the collision, the type of collision that occurs is an elastic collision.
According to Newton's second law, the formula for calculating the force is expressed as;
F = ma
F = m(v-u)/t
F = 22680+1200(229.82-175)/t
Ft = 23880(54.82)
F = 1,309,101.6/0.0012
F = 1,090,918,000N
Hence the required force is 1,090,918,000N
KE lost = Kinetic energy after collision - Kinetic energy before collision
Kinetic energy after collision = 1/2 * 12880 * 229.82²
Kinetic energy after collision = 340,142,976.656 Jolues
Kinetic energy before collision = 1/2 * 22680(170)²+ 1/2*1200(5)²
Kinetic energy before collision = 327,726,000 + 15000
Kinetic energy before collision = 327,741,000
Kinetic energy lost = 340,142,976.656 - 327,741,000 = 12,401,976.656Joules
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10. Based on the current position of the continents, South America is moving away from
Africa in what direction?
A. West
C. North
B. East
D. South
Answer:
D
Explanation:
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An empty 230 kg elevator accelerates upward
at 1.7 m/s^2
The acceleration of gravity is 9.8 m/s^2.
What is the tension in the cable that lifts
the elevator cab?
Answer in units of N.
Answer:
7.2 as used in the equation
A ball is dropped from a tower that is 206 m high, How long does it take to reach the ground?
It will take 6.42 s for the ball that is dropped from a height of 206 m to reach the ground.
From the question given above, the following data were obtained:
Height (H) = 206 m
Time (t) =?NOTE: Acceleration due to gravity (g) = 10 m/s²
The time taken for the ball to get to the ground can be obtained as follow:
H = ½gt²
206 = ½ × 10 × t²
206 = 5 × t²
Divide both side by 5
[tex]t^{2} = \frac{206}{5}\\\\ t^{2} = 41.2[/tex]
Take the square root of both side
[tex]t = \sqrt{41.2}[/tex]
t = 6.42 sTherefore, it will take 6.42 s for the ball to get to the ground.
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Calculate the kinetic energy of a 70 kg person moving at a speed of 5m/s
Answer:
875 JExplanation:
The kinetic energy of an object can be found by using the formula
[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]
m is the mass
v is the velocity
From the question we have
[tex]k = \frac{1}{2} \times 70 \times {5}^{2} \\ = 35 \times 25 \\ = 875[/tex]
We have the final answer as
875 JHope this helps you
Answer:
[tex]\boxed {\boxed {\sf 875 \ Joules}}[/tex]
Explanation:
Kinetic energy is the energy an object possesses due to motion. It is calculated using the following formula:
[tex]KE= \frac{1}{2}mv^2[/tex]
The mass of the person is 70 kilograms and they are moving at a speed of 5 meters per second.
m= 70 kg v= 5 m/sSubstitute these values into the formula.
[tex]KE= \frac{1}{2} (70 \ kg )(5 \ m/s)^2[/tex]
Solve the exponent.
(5 m/s)² = 5 m/s * 5 m/s = 25 m²/s²[tex]KE= \frac{1}{2}(70 \ kg)(25 \ m^2/s^2)[/tex]
Multiply the numbers in parentheses.
[tex]KE= \frac{1}{2} (1750 \ kg*m^2/s^2)[/tex]
Multiply by 1/2 or divide by 2.
[tex]KE= 875 \ kg*m^2/s^2[/tex]
Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule. So, our answer of 875 kg*m²/s² is equal to 875 Joules.
[tex]KE= 875 \ J[/tex]
The person has 875 Joules of kinetic energy.
9. An elevator uses 650.0 watts to lift 5 passengers 30.0 m in 15.0 seconds. What is the force needed to lift the elevator and the passengers?
Hi there!
We can begin by calculating the total WORK done using the equation:
Power · time = Work
650 · 15 = 9750 J
We know that:
Work = Force · displacement (W = Fd), so:
W/d = F
9750/30 = 325 N
Linearize equation T=KL^n
Tốc độ v của một vật được cho bởi phương trình v = At
3
– Bt, trong
đó t là thời gian.
(a) Xác định thứ nguyên của A và B.
(b) Đơn vị SI của các hằng số A và B là gì?
If v(t) is speed measured in meters per second (m/s), and t is time measured in seconds (s), then the constants A and B in
v(t) = At ³ - Bt
must have units of m/s⁴ and m/s², respectively; otherwise, the equation is dimensionally inconsistent.
[m/s] = A [s]³ - B [s]
[m/s] = [m/s⁴] [s]³ - [m/s²] [s]
[m/s] = [m/s] - [m/s]
[m/s] = [m/s]
The ruminant stomach has four compartments including the rumen, reticulum, omasum and large intestine,
O True
O False
Answer:
FalseIt has four compartments just not including all of those
Explanation:
Ruminant stomachs have four compartments: the rumen, the reticulum, the omasum and the abomasum.Anatomy of the ruminant digestive system includes the mouth, tongue, salivary glands (producing saliva for buffering rumen pH), esophagus, four-compartment stomach (rumen, reticulum, omasum, and abomasum), pancreas, gall bladder, small intestine (duodenum, jejunum, and ileum), and large intestine (cecum, colon, and rectum).An object travelling at 12 m/s has 64.8j of stored kinetic energy. What is the mass of the object, in grams?
Answer:
So u divided 12 divided by 64.8 okay
Explanation:
and when I getc the answer that's urs answer
A can of soda weighs 4.7 newtons (N) on Earth's surface. What will it weigh on Planet X where the acceleration due to gravity is 1.82 meters per second^2?
Explanation:
The mass of the soda can is
[tex]m = \dfrac{W}{g} = \dfrac{4.7\:\text{N}}{9.8\:\text{m/s}^2} = 0.48\:\text{kg}[/tex]
The weight of this same soda can on Planet X is
[tex]W = mg_p = (0.48\:\text{kg})(1.82\:\text{m/s}^2) = 0.87\:\text{N}[/tex]