You drive 7.50 km in a straight line in a direction 10° East of North.
(a) Find the distances you would have to drive straight East and then straight North to arrive at the same point. (This is equivalent to finding the components of the displacement along the East and North directions.)


km East
km North
(b) Show that you still arrive at the same point if the East and North legs are reversed in order.

The  position of the car at the given time is 18 m.

The position of the car at the given time is calculated as follows;

x = vt

where;

x = 3 m/s x 6.0 s

x = 18 m

Thus, the  position of the car at the given time is 18 m.

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The tension in the upper rope is determined as 50.53 N.

The tension in the upper rope is calculated as follows;

T(u) = T(d)+ mg

where;

T(u) = 12.8 N + 3.85(9.8)

T(u) = 50.53 N

Thus, the tension in the upper rope is determined as 50.53 N.

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The boat will move in a direction that is 36.86 degrees away from the velocity vector as it attempts to reach the opposite bank from where it started.

We must understand the issue with the river crossing in order to identify the solution.

                                   [tex]\alpha =sin^{-1}(\frac{V_R}{V_B} )[/tex]

                                       [tex]\alpha =sin{-1}(\frac{3}{5} )[/tex]

Thus, we can deduce that the boat will move in a direction that is 36.86 degrees away from the velocity vector as it attempts to reach the opposite bank from where it started.

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Answer:

the watt is the unit of power or radiant flax

The direction of torque τ this method is mathematically given as

D=X  

Option A is correct.

Generally, the equation for torque is  mathematically given as

τ = r X F

Hence to decipher the torque direction with respect to the center of mass of the body due to force F acting on the body at a location indicated by the vector r

In conclusion, the direction of this method is

D=X   Option A.

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Answer:

Quadrant IV

Explanation:

In Quadrant IV, x is positive, and y is negative.

Brainliest, please :)

The speed will be 0.2 m/s and the velocity will be 0 m/s.

Speed = Total Distance / Total time

We have given total distance as ( 50 + 95 ) metres and total time as 12 minutes or we can say 720 seconds.

Speed = 145/ 720 m/s

Speed = 0.2 m/s

Velocity = Total Displacement / Total time

As the initial and final is the home, hence the net displacement is 0 in that case.

In this case also the total time we have given is 12 minutes or we can say 720 seconds.

Velocity = 0 / 720 m/s

Velocity = 0 m/s

So to conclude with we can say that the speed is 0.2 m/s and the velocity is 0 m/s.

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A characteristic of the part of the atom marked "B” is that it has a large mass. Option B. This is further explained below.

Generally,  Atom, the lowest possible unit into which matter may be split without releasing electrically charged particles.

In conclusion, the protons and neutrons are represented by the red and white spheres, respectively. Since it indicates both protons and neutrons, the line preceding the bracket around the balls (designated A) stands in for the atom's nucleus.The mass of the "B" section of the atom is very high.

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Answer:

it's b

Explanation:

i did the ed quiz

(a)The initial velocity of the shell will be 594.27 m/sec

(b)The maximum height it reaches will be 9000 m.

c)101.249 m meters lower will its surface be 36.0 km from the ship along a horizontal line parallel to the surface of the ship.

d)The error could be significant compared to the size of a target. Option C is correct.

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

m is the mass of the block = Kg.

u is the initial velocity of fall = m/sec

h is the distance of fall =  m

g is the acceleration of free fall = m/sec²

v is the hitting velocity of =?

a)

The range of the projectile is;

[tex]\rm R = \frac{u^2 sin 2 \theta }{g} \\\\ 36 \times 10^ 3 = \frac{U^2 sin 45^0}{9.81} \\\\ U= 594.27 \ m/sec[/tex]

b)

The maximum height of the projectile is;

[tex]\rm H = \frac{u^2 sin 2 \theta }{2g} \\\\ H = \frac{(594.27)^2\times (sin 45)^2}{2 \times 9.81 } \\\\ H = 9000 \ m[/tex]

c)

The distance between its surface and the ship, measured in a horizontal arc parallel to the surface, will be 36.0 kilometers. The distance from the lower surface is found as;

[tex]\rm( R_e + h)^2 = R_e^2+(36)^2 \\\\ (R_e)^2 = h^2+2R_e h= R_e^2 + 12196 \\\\ h^2 + 12800 h - 1296 = 0 \\\\ h = 101.249 \ m[/tex]

d)

An error is a mistaken or erroneous action. In some contexts, an error is interchangeable with a mistake.

The difference between the calculated value and the original value is known as the error. The inaccuracy may be large in comparison to the target's size. Option C is correct.

Hence the initial velocity of the shell, maximum height, and the distance from the lower surface will be 594.27 m/sec,9000 m, and 101.249 m and option c for question d are correct respectively.

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Answer:

Force of bug is less than the force that the bus exerts on the bug

Explanation:

Force = MA. bus has more mass so more force and bug has a lot less mass than bus. Bug accelerates in whatever direction the bus is going and the bus is not affected.

The energy lost to the air due to friction is 37.7 J.

The energy lost to the air due to friction is determined from the change in kinetic energy of the ball.

ΔK.E = K.Ef - K.Ei

ΔK.E = ¹/₂mv² - ¹/₂mu²

ΔK.E =  ¹/₂m(v² - u²)

ΔK.E = ¹/₂(0.45)(19.89² - 15.1²)

ΔK.E = 37.7 J

Thus, the energy lost to the air due to friction is 37.7 J.

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Answer:

A^2+B^2 is the scalar product of A and B

Answer:

Scalar product is equal to the magnitude a vector a times the projection of a onto vector B,

The butcher should balance both the meat and 0.5 kg mass on one arm of the beam balance and 2 kg mass on the other arm of the beam balance.

A beam balance can be defined as an apparatus which comprises a lever with two (2) equal arms and a bowl (pan) that is suspended from each arm, so as to measure the mass of an object.

In this scenario, the butcher should balance both the meat and 0.5 kg mass on one arm of the beam balance and 2 kg mass on the other arm of the beam balance.

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(1) The intensity of a sound wave is linearly proportional to the change in the pressure squared.

(2) You are able to hear sounds from farther away on a cool night because sound waves are refracted toward warmer air near the ground.

(3) When the trough of one wave collides at the same time & place of the crest of an identical wave, destructive interference occurs.

(4) The time taken for the heater to provide the energy is 300 secs.

(5) The total amount of heat provided to the ice sample is 7,980 cal.

(6) The amount of heat required to increase the temperature of water is 33,472 J.

The intensity of a sound wave is linearly proportional to the change in the pressure squared and inversely proportional to the density and the speed.

You are able to hear sounds from farther away on a cool night because sound waves are refracted toward warmer air near the ground.

When the trough of one wave collides at the same time & place of the crest of an identical wave, destructive interference occurs.

E = Power x Time

t = E/P

t = 60,000/200

t = 300 secs

Q = 79.8 cal/g x 100 g

Q = 7,980 cal

Q = 0.1 kg x 4184 J/kgC x (100 - 20)

When water vapor condense into liquid water, temperature = 100⁰C

Q = 33,472 J

Thus, the intensity of a sound wave is linearly proportional to the change in the pressure squared.

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The sound waves with the frequency 20 Hz, 200 Hz, 2,000 Hz, and 20,000 Hz have a velocity of 344 m/s.

A sound wave is a sample resulting from the motion of strength traveling thru a medium (inclusive of air, water, or every other liquid or stable matter) because it propagates from the supply of the sound. Sound waves are created and convey strain waves, for example, a cellphone.

The frequency can be given as:

Frequency = Velocity/ Wavelength

Velocity = Frequency * Wavelength

The velocity of the following sound waves is given as:

Wavelength = 17.2 m

Velocity = 20 * 17.2 m/s

Velocity = 344 m/s

Wavelength = 1.72 m

Velocity = 200 * 1.72 m

Velocity = 344 m/s

Wavelength = 17.2 cm = 0.172 m

Velocity = 2,000 * 0.172 m/s

Velocity = 344 m/s

Wavelength = 1.72 cm = 0.0172 m

Velocity = 20,000 * 0.0172 m/s

Velocity = 344 m/s

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Material P does not always lead to the glowing of the bulb hence the material P is an insulator.

The term insulator refers to an object that does not permit current to pass through it. Insulators include materials such as wood, plastic etc.

Looking at the two circuits, we can see that the material P does not always lead to the glowing of the bulb hence the material P is an insulator.

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The horizontal component of the train's speed is 5.54 m/s and the vertical component's of the train's speed is  6.85 m/s.

The horizontal component of the train's speed is calculated as follows;

Vx = V cosθ

where;

Vx = 8.81 m/s x cos(51)

Vx = 5.54 m/s

Vy = 8.81 m/s x sin(51)

Vy = 6.85 m/s

Thus, the horizontal component of the train's speed is 5.54 m/s and the vertical component's of the train's speed is  6.85 m/s.

The complete question is below:

a train travels 8.81 m/s in a -51.0 direction. the train accelerates 2.23 m/s². Find the horizontal and vertical component of the train's speed.

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Answer:

Approximately [tex]31\; {\rm m\cdot s^{-1}}[/tex] assuming that there is no friction on the rollercoaster, and that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].

Explanation:

Make use of the SUVAT equation [tex]v^{2} - u^{2} = 2\, a\, x[/tex], where:

If there is no friction on the rollercoaster, the acceleration of the rollercoaster would be equal in magnitude to the gravitational field strength, [tex]g[/tex]:

[tex]a = g = 9.81\; {\rm m \cdot s^{-2}}[/tex].

The initial velocity of this rollercoaster is [tex]0\; {\rm m\cdot s^{-1}}[/tex] (that is, [tex]u = 0\; {\rm m\cdot s^{-1}}[/tex]) since the rollercoaster was initially stationary. The displacement of this rollercoaster would be [tex]x = 49\; {\rm m}[/tex] (same as the height of the hill.)

Rearrange the equation [tex]v^{2} - u^{2} = 2\, a\, x[/tex] to find an expression for the final velocity [tex]v[/tex] of this rollercoaster:

[tex]\begin{aligned}v &= \sqrt{2\, a\, x + u^{2}} \\ &= \sqrt{2 \times 9.81\; {\rm m\cdot s^{-2} \times 49\; {\rm m} + (0\; \rm m\cdot s^{-1}})^{2}}\\ &\approx 31\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

The length of the y-component of the vector plotted below is 1 unit.

We know this because this vector can be descomposed in two vectors (blue) that form an angle of 90° beetween them. The measures of this vectors must be able to form a right-angle triangle with the descomposed vector (see image).

Answer:

1.37 seconds before.... splat !

Explanation:

y = y0 + v0 t + 1/2 a t^2      y0 = 30       y = 0

                    v0 = 0 ( from rest)

                            a = - 32.2 ft/s^2

0 = 30 - 1/2 * 32.2 * t^2

t=1.366 seconds                    Note that   mass   is irrelevant.

The new period will be 2.486 days.

The period is found as the ratio of the angular displacement and the angular velocity. Its unit is the second and is denoted by t. The value of time needed to complete the rotation is the total period.

Given data;

Mass of a star,m= 1.210×10³¹ kg

The time period for one rotation of the star, T = 20.30 days

D' = 0.350 D

R' = 0.350 R

From the law of conservation of angular momentum;

[tex]\rm I \omega = I' \omega' \\\\ \frac{2}{5} MR^2 \times \frac{2 \pi }{T}=\frac{2}{5} MR'^2 \\\\ R^2 \times \frac{1}{T}= R'^2 \times \frac{1}{T} \\\\ T' = \frac{R'^2T}{R^2} \\\\ T' = \frac{(0.350 R)^2 \times 26.1 }{R^2} \\\\T' = 0.1225 \times 20.30 \\\\ T'= 2.486 \ days[/tex]

Hence, the new period will be 2.486 days.

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Answer:

P

Explanation:

,............................................ I have. a doubt too on D

The temperature to which it must be heated in order to fit the shaft is 73.33 ⁰C.

The temperature to which it must be heated in order to fit the shaft is calculated as follows;

[tex]\frac{\Delta L}{L} = \alpha \Delta T\\\\\Delta T = \frac{\Delta L}{\alpha L}[/tex]

where;

ΔT = (0.04)/(50 x 15 x 10⁻⁶)

ΔT = 53.3 ⁰C

T₂ - T₁ = ΔT

T₂ = ΔT + T₁

where;

T₂ = 53.3 + 20

T₂ = 73.33 ⁰C

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Answer: I don't understand if it is a question

Explanation:

More than 700 people in the United States have been infected with monkeypox virus American vector: the epidemic is spreading like a snowball.

To create a tragic past for your character, you would have to write a plot that shows a sad ending to a good story.

This refers to a type of story that has negative emotions such as sadness, death, etc.

Hence, we can see that for example, you could write about two lovers and how despite all the struggles they faced, eventually died in mysterious circumstances.

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The speed after it has traveled 0.400 m up the wall will be 1.77 m/sec.

From the work-energy theorem, it is stated that the net work done is equal to the change in the kinetic energy.

Given data;

Mass of book,m =5.00

Force,F = 96.0 N

Θ is the angle above the horizontal =  60°

The coefficient of kinetic friction between the book and the wall is μ =0.300.

R is the normal reaction

W₁ = Fd cosΘ

W₁=(96.0 N) (0.4 m) in 60°

W₁= 33.25 J

Work done by gravity is,

W₂ = mgdcos180°

W₂ = (5.00 kg) (9.81 m/s²)(0.4 m) cos180°

W₂ = -19.6J

The Normal force on the book by the wall is,

N = FcosΘ

N = (96 N) cos 60°

N=48 J

Work done by friction is;

W₃=μkRdcos180°

W₃=0.3)(48 J)(0.4 m) cos180°

W₃ =-5.76 J

The net work done is;

W =W₁+W₂+W₃

W=33.25-19.6-5.76

W=7.89 N

From the work-energy theorem, we have

W = ΔK

[tex]\rm W = \frac{1}{2} mv^2 - 0[/tex]

The speed is;

[tex]\rm v = \sqrt \frac{2 W}{m} \\\ v = \sqrt{\frac{2 \times 7.89} {5.00}}\\\\ v = 1.77 \ m/sec[/tex]

Hence, the speed after it has traveled 0.400 m up the wall will be 1.77 m/sec.

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Answer:

See below

Explanation:

Vertical component of initial velocity  =  200 sin 35° = 114.72 m/s

then use position formula      a = 9.81 m/s^2

  0  = 300 + 114.72 t  -  1/2 (9.81)(t^2)

            use quadratic formula with a = - 4.905    b = 114.72   c = 300

              to find t = 25.76 seconds

To find the range

   ( horizontal distance the projectile lands from launch point)

Horizontal component of initial velocity    200 cos 35 = 163.83 m/s

 ( it flies horizontally at this speed for  25.76 seconds <==found above)

    163.83  m/s  *  25.76 s = 4220.3 meters

The tension in the cable is 112.64 N and the vertical component of the force exerted by the hi.nge on the beam is 93.16 N.

Apply the principle of moment and calculate the tension in the cable;

Clockwise torque = TL sinθ

Anticlockwise torque = ¹/₂WL

TL sinθ  =  ¹/₂WL

T sinθ  =  ¹/₂W

T = (W)/(2 sinθ)

T = (21 x 9.8)/(2 x sin66)

T = 112.64 N

T + F = W

F = W - T

F = (9.8 x 21) - 112.64

F = 93.16 N

Thus, the tension in the cable is 112.64 N and the vertical component of the force exerted by the hi.nge on the beam is 93.16 N.

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