You are designing a hydraulic lift for an automobile garage. It will consist of two oil-filled cylindrical pipes of different diameters. A worker pushes down on a piston (with a diameter of 25 cm) at one end, raising the car on a platform at the other end. To handle a full range of jobs, you must be able to lift cars up to 3,471 kg, plus the 451 kg platform on which they are parked. To avoid injury to your workers, the maximum amount of force a worker should need to exert is 106 N. What should be the diameter of the pipe under the platform if the diameter? Use g = 9.8 ™. Express answers in meters (m).

The schrodinger's equation for [tex](A\phi_1+AU\Psi_1)+(B\phi_2+BU\Psi_2)[/tex] for the particular U and E can be expressed as [tex](A\phi_1+AU\Psi_1)+(B\phi_2+BU\Psi_2)=E(A\Psi_1+B\Psi_2)[/tex].

The solution to the equation is based on Fourier's Eigen Values method. This is the expression for any mathematical function as the sum of an infinite series of other periodic functions. The trick is to find the right functions with the right amplitudes so that when they are superimposed, they give the desired solution.

As a result, the solution to Schrondinger's equation, the system's wave function, was replaced by the wave functions of the individual series, natural harmonics of each other, resulting in an infinite series. Shrodinger discovered that replacement waves described individual states of the quantum system, and their amplitudes indicated the relative importance of that state to the entire system.

The schoringer 's equation is

[tex]-\frac{h^2}{2m}\frac{d\psi^2}{dx^2}+U(x) \psi=E\psi[/tex]

here, the E is the energy of the particle.

since the wave function [tex]\psi_1[/tex] is the solution of the schrodinger's equation,

[tex]-\frac{h^2}{2m}\frac{d\psi_1^2}{dx^2}+U(x) \psi=E\psi_1[/tex]

Since, the wave function [tex]\psi_2[/tex] is the solution of the schrodinger's equation,

[tex]-\frac{h^2}{2m}\frac{d\psi_2^2}{dx^2}+U(x) \psi=E\psi_2[/tex]

Then,

[tex](A\phi_1+AU\Psi_1)+(B\phi_2+BU\Psi_2)=(A(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2})+AU\Psi_1)+(B(-\frac{h^2}{2m}\frac{d\Psi^2}{dx^2})+BU\Psi_2)\\\\=A(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2}+U\Psi_1)+B(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2}+U\psi_2)\\\\=A(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2}+U(x)\Psi_1)+B(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2}+U(x)\psi_2)\\\\=A(E\Psi_1)+B(E\Psi_2)\\\\=E(A\Psi_1+B\Psi_2)[/tex]

Thus, the schrodinger's equation  for particular U and E can be expressed as [tex]E(A\Psi_1+B\Psi_2)[/tex].

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Your question is incomplete, here is the complete question in the figure,

A 75 cm long G string stretch when it's first tuned is 1.833 mm.

Density (volumetric mass density or specific mass) is the mass of matter per unit volume. The most commonly used symbol for density is ρ (lowercase Greek letter rho), but the Latin letter D can also be used. Mathematically, density is defined as mass divided by volume.

v = sqrt(T/mu)

250 = sqrt(T/(1.3x10^-3))

So T = 81.25 N

Young's modulus for steel = 200 x 10^9 Pa

Y = (T/A)/(deltal/l) = T*l/(deltal*A)

So deltal = (T*l)/(Y*A) = 81.25*0.75/(200x10^9*pi*(0.23x10^-3)^2) = 1.833 x 10^-3 m

R = 1.833 mm.

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The intensity of the earthquake at 1.3 Km from the source is 8 x 10⁹ W/m².

r₁ = distance of the point from the source = 35 km = 35000 m

I₁ = intensity of earthquake wave at distance "r₁" = 1.1 X 10⁶ W/m²

r₂ = distance of the point from the source = 1.3 km = 1300 m

I₂ = intensity of earthquake wave at distance "r₂"

We know that , for a constant power , the intensity of wave is inversely proportional to the distance from the source .

= I α 1/r²    

where I = intensity of wave , r = distance from source

Hence we can write,

= I₁/I₂ = r₂²/r₁²

Substituting the values,

= 1.1 X 10⁶ /I₂ = (1300/35000)²

= I₂ = 8 x 10⁹ W/m²

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calm :), thanks mods

The total force on the side of the pool due to the water is 2275 N/m^2 x (15 m x 3.5 m) = 1523125 N.

To find the force on the side of the pool due to the water, we first need to calculate the volume of the water in the pool. Since the pool has dimensions of 15 m x 30 m and is 3.5 m deep, its volume is 15 m x 30 m x 3.5 m = 1575 cubic meters. Next, we need to calculate the weight of the water in the pool. The weight of an object is equal to its mass multiplied by the acceleration due to gravity. The density of fresh water is about 1000 kg/m^3, so the mass of the water in the pool is 1575 m^3 x 1000 kg/m^3 = 1575000 kg. Since the acceleration due to gravity is approximately 9.8 m/s^2, the weight of the water in the pool is 1575000 kg x 9.8 m/s^2 = 15442500 N. Finally, we can calculate the force on the side of the pool due to the water. Since the force is distributed evenly over the surface of the side of the pool, the force on each square meter of the side of the pool is 15442500 N / (15 m x 3.5 m) = 2275 N/m^2. Therefore, the total force on the side of the pool due to the water is 2275 N/m^2 x (15 m x 3.5 m) = 1523125 N.

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Answer: Recognition.

Explanation:

I'm pretty sure this is right !

so this is the answer velocity =10√2

Answer:

Here are ten questions about the story entitled "cabeza de gallo":

A story is a narration, either oral or written, about a story that may have happened in real life, or is the product of the author's imagination.

The stories have the characteristic of having few characters, and are shorter than any common text.

¡Hope this helped!

Answer:

Air pollutants produced by forest fires in one country are able to travel to neighboring countries because of the way air moves and circulates around the globe. The Earth's atmosphere is made up of a mixture of gases, including oxygen and carbon dioxide, which are capable of moving and circulating through the air. When pollutants, such as those produced by forest fires, are released into the atmosphere, they can be carried by wind and other atmospheric phenomena, allowing them to travel over long distances and affect other regions and countries. This is why air pollution from forest fires in one country can affect neighboring countries.

The bar's maximum magnitude of the velocity under these circumstances is 240 m/s.

In physics, mass is a statistical expression of inertia, a basic characteristic of all matter. It essentially refers to a body of matter's resistance to changing its speed or location in response to the use of a force.

The metal bar is experiencing the force.

F = iLB = ELB/R

The bar will increase in speed until the battery emf equals the induced emf.

Eind = vLB

current, and the force is eliminated.

Then the maximum velocity v = E/LB

v = 18/0.30*0.25

v = 240 m/s

Hence Option (5) is correct.

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The complete question is-

In the figure, a conducting metal bar of mass [tex]$0.5 \mathrm{~kg}$[/tex] sliding along conducting rails is connected to a battery of emf [tex]$18 \mathrm{~V}$[/tex] and resistor [tex]$R=200 \Omega$[/tex] to form a circuit. The rails are [tex]$30 \mathrm{~cm}$[/tex] apart and the entire arrangement is embedded in a uniform magnetic field [tex]$0.25 \mathrm{~T}$[/tex] directed into the page, as shown. Find the maximum velocity [tex]$v$[/tex] the bar attains under these conditions.

(1) [tex]$345 \mathrm{~m} / \mathrm{s}$[/tex]

(2) [tex]$68 \mathrm{~m} / \mathrm{s}$[/tex]

(3) [tex]$98 \mathrm{~m} / \mathrm{s}$[/tex]

(4) [tex]$135 \mathrm{~m} / \mathrm{s}$[/tex]

(5) [tex]$240 \mathrm{m} / \mathrm{s}$[/tex]

By evaluating the moment of inertia of the bodies, we get that the Solid Sphere will reach first, followed by the disk and hoop respectively.

Torque is the product of the moment of inertia and angular acceleration.

If torque is constant, the angular acceleration will be less for a large moment of inertia.

So, the object will smaller moment of inertia (I), the acceleration will be more, and thus, it will reach the bottom of the ramp first.

The given objects are disk, hoop, and solid sphere.

The moment of inertia of the Hoop = [tex]MR^{2}[/tex]

The moment of inertia of the Disk = [tex]\frac{1}{2} MR^{2}[/tex]

The moment of inertia of a solid sphere = [tex]\frac{2}{5} MR^{2}[/tex]

So, the moment of inertia for the hoop is greater than the disk and solid sphere.

[tex]I_{s} < I_{d} < I_{h}[/tex]

Thus, Solid Sphere will reach first, followed by disk and hoop respectively.

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According to Faraday's law, the various magnetic flux via a closed loop induces an emf in it, given by E=−dϕdt so the current in the resistor during this time is 0.81818 A.

Here we have;

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To filter out the humpback whale song from the input signal and isolate the fin whale call, you will need to use a low pass filter. A low pass filter allows low frequency signals to pass through while attenuating higher frequency signals.

To sufficiently eliminate the humpback whale song in the output signal, you will need to use a high-order low pass filter. A high-order filter has a steeper roll-off, which means that it is more effective at attenuating higher frequency signals. A filter with an order of 2 or higher should be sufficient for this purpose. To design the low pass filter, you will need to determine the cut-off frequency at which the filter will begin to attenuate the humpback whale song. The cut-off frequency should be set slightly lower than the lowest frequency of the humpback whale song (50 Hz) to ensure that the song is completely eliminated in the output signal. Once you have determined the cut-off frequency and the order of the filter, you can use standard techniques to design the filter. This may involve calculating the filter coefficients using a mathematical formula or using software to design the filter based on the desired specifications. Once the filter is designed, you can apply it to the input signal to obtain the filtered output signal. The output signal should contain only the fin whale call, with the humpback whale song sufficiently eliminated.

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The electric field just outside the inner shell has magnitude E1, and the electric field just inside the outer shell has magnitude E2, True for the magnitude E of the electric field at point P is The correct answer is (b) i.e. E1 > E > E2

Since the shells are conducting and the space between them is filled with air, the electric field must be perpendicular to the surface of the shells at all points. This means that the equipotential lines as assumed  must be perpendicular to the shells as well. At point P, the equipotential lines are closer together than they are at the outer shell, but farther apart than they are at the inner shell. This means that the electric field at point P must have a magnitude that is between E1 and E2, but closer to E1 than to E2. Therefore, the correct answer is (b) E1 > E > E2. The term "electric field" refers to the physical field that surrounds electrically charged particles and acts to either attract or repel all other charged particles in the field (also known as an E-field). It can also refer to the physical field surrounding a system of charged particles. Electric fields are composed of electric charges and time-varying electric currents. Both electric and magnetic fields are manifestations of the electromagnetic field, one of the four fundamental interactions of nature.

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The luminosity of star a is 78 times bigger than star b.

The luminosity of star a is 78 times bigger than star b because the luminosity of star a is 26 times bigger than the luminosity of star b but star a is also 3 times closer than star b, so the difference in luminosity is amplified by a factor of 3. This means the luminosity of star a is 26 times 3, or 78 times bigger than star b.

The luminosity of a star is directly related to its distance from us. The closer a star is, the brighter it will appear. This is because the amount of light we receive from a star is inversely proportional to the square of its distance from us.

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No, intensity level does not follow inverse square law.

The square of the distance between the source and the observer determines how intense the light is for the observer. This demonstrates that the intensity of light is proportional to a value multiplied by 1/d² as the distance to a light source increases.

Here,

intensity level = 53 dB

distance, d = 4.4 m

part A)

let the intensity is I

Intensity level = 10×log(l/1×10⁻¹²)

53 = 10 ×log(1/1×10⁻¹²)

solving for I

I = 1.995 ×10⁻⁷ W/m²

the intensity of sound at A is 1.995 ×10⁻⁷W/m²

part B)

for the sound intensity to be one fourth.

as sound intensity = 1/(4×π×d²)

hence, the distance must be made two times,

new distance = 4.4 ×2

new distance = 8.8 m

the distance from the source is 8.8 m

part C)

distance to move from point A = 8.8 - 4.4

distance to move from point A = 4.4 m

part D)

yes, the intensity follow the inverse square law

part E)

for the intensity level,

as I = 10 × log(P/(4×π×d²×10))

hence, intensity level does not follow inverse square law.

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The displacement of the sinusoidal wave travelling withinside the x course is y(x,t)=Asin(kx-wt).

This is described as a propagation of disturbances from vicinity to vicinity in a ordinary and prepared way.

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The pressure of the interstellar gas is 2.76*10-16 pascal.

What are interstellar gasses?

Most of the gas between stars in our galaxy and other galaxies is hydrogen and helium, which is dispersed at different densities between the stars. The gas ratios are comparable to those of the Sun. Star formation starts with interstellar gas as its raw material.

PV = nRT

V = 10-6 m3

n = 1/NA ; NA = avagadro number = 6.022*1023

n = 1.66*10-24

R = 8.314 J/K/mole

T = 20K

P = 1.66*10-24*8.314*20 / 10-6  

P = 2.76*10-16 pascal

Therefore, the pressure of the interstellar gas is 2.76*10-16 pascal.

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Complete question:

The concentration of particles (assume neutral hydrogen atoms) in interstellar gas is 1.0 particle/cm3, and the average temperature is about 3 K .

1. What is the pressure of the interstellar gas? (please give units)

The answer is

3.5*10^-8:1

Explanation:

F(gravitation) = G*M1M2/r^2

G = gravitational constant = 6.67*10^-11 Nm^2/kg^2

M1 = mass of the heavier sphere,

M2 = mass of the lighter sphere

r = their distance apart

Fg = 6.67*10^-11*188*0.93/(0.19)^2

Fg = 3.23*10^-7N

The ratio of the force of gravitation between them to the weight of the lighter sphere = 3.23*10^-7: (0.93*9.81) = 3.5*10^-8. : 1 by dividing both side by (0.93*9.81)

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No, there is no way that having Student 2 touch the sphere will work. There will be no repulsion by touching the sphere whether the rod is kept near or away. No way cause the sphere negatively charged.

Charging an uncharged body by bringing near to it a charged body is called charging by induction. In the given case negatively charged rod is brought near to uncharged sphere, then all positive charges on it realigns towards the end of the rod by attraction.

When it is touched while keeping the rod closer, all negative charges are grounded passing through body. Thus sphere has now only positively charges. When rod is removed, the positive charges distributes uniformly ands sphere becomes positively charged.

In no way sphere will be negatively charged for repulsion to occur.

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The exclusion principle, is the degeneracy pressure, results from the uncertainty principle. Correct answer: letter C.

Since, the pressure that arises when the electrons in an atom occupy all the available quantum states, which makes it difficult for additional electrons to enter the atom.

The exclusion principle and the uncertainty principle are two distinct principles.

The exclusion principle states that no two electrons in an atom can have the same set of quantum numbers, while the uncertainty principle states that the position and momentum of a particle cannot both be known with precision.

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The fraction of the original rotational kinetic energy lost due to the sudden coupling of the second wheel with twice the rotational inertia of the first is 100%.

When the two wheels are coupled, their rotational energies are combined and shared. Since the second wheel is initially at rest, its rotational energy is 0 and thus all the original rotational kinetic energy is lost.

The rotational kinetic energy of the first wheel is given by KE = 1/2Iω2, where I is the rotational inertia and ω is the angular velocity. Since the second wheel has twice the rotational inertia, the combined rotational kinetic energy is 1/2(I1 + 2I2)ω2. Since I2 is initially 0, the combined rotational kinetic energy is 1/2I1ω2, which is half of the original rotational kinetic energy. Therefore, 100% of the original rotational kinetic energy is lost.

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He has to employ 31623  violin players.

The SI unit for sound intensity is W/m^2, although considering how humans hear sounds, the decibel (dB) scale of sound intensity is more useful. The logarithm of the intensity of a sound, as opposed to the intensity of a sound directly, is a better indicator of how human ears perceive sound.

Ten decibels (dB) are equal to every factor of ten in intensity.

For this case, a 70.0 dB sound is 45 dB louder than a 60 dB sound,  4.5 factors of 10 (10^4.5)  as intense.

Hence, if a single violin produces 25.0 dB sound intensity, to produce a robust sound intensity of 70.0 dB from violin section, he has to employ 10^4.5 = 31623  violin players.

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For radio-waves in Public Radio station KXPR-FM, the horizontal angles and intensity is-

(A)  1.4597 rad is the horizontal angles, relative to the original direction of the radio-waves.

(B) The intensity will be 1.576 W/m² for the given radio-waves.

Radio waves are a type of electromagnetic radiation. A radio wave has a much longer wavelength than visible light. Humans use radio waves extensively for communications. This radio tower has both rectangular and circular antennas to transmit and receive radio frequency energy.

A radio wave is generated by a transmitter and then detected by a receiver. An antenna allows a radio transmitter to send energy into space and a receiver to pick up energy from space.

Radio waves are used for wireless transmission of sound messages, or information, for communication, as well as for maritime and aircraft navigation. The information is imposed on the electromagnetic carrier wave as amplitude modulation.

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The difference is 2.5 x 10^-14 which is smaller than the diameter of an atom. For everday situations, it is a very good approximation to assume that all measured lengths are equal to their proper lengths

Calculation :

L = Lo*sqrt(1-(v/c)^2)

by solving this

Lo-L = 2.5 x 10^-14

notice this difference, which is much smaller than the diameter of an atom. For everday situations, it is a very good approximation to assume that all measured lengths are equal to their proper lengths.

A measurement is a quantification of an attribute of an object or event that can be used to compare it with other objects or events. [1][2] In other words, a measurement is a way of determining how large or small a physical quantity is compared to a base reference quantity of the same kind. The scope and application of measurements are situation and field dependent. In science and engineering, measurement does not refer to the nominal properties of an object or event, consistent with the guidelines of the International Glossary of Metrology published by the International Bureau of Weights and Measures.

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Area required to achieve a prescribed outlet temperature is 1.51m².

What is Temperature?

The term "temperature" describes how hot or cold a body is. It is, specifically, a method of calculating the kinetic energy of the particles that make up an item. When particles travel more quickly, the temperature rises, and vice versa.

Nearly every aspect of daily life as well as every scientific field, from physics to geology, depend heavily on temperature

Assumptions: (1) Negligible heat loss to surroundings and kinetic and

potential energy changes, (2) Constant properties.

Analysis: The required heat transfer rate is

q = (m c)h (T h,i - T h,o)

= 0.05 kg/s (4209J / kg.K) 70K = 14,732 W

Using the ε-NTU method,

Cmin = Ch

= 210.45 W / K

Cmax = Cc

=755.25W / K

Hence, Cmin/Cmx(Th,i - Th,o)

= 210.45W / K(100K)

= 21,045W

and

ε=q/qmax

= 14,732W / 21,045W = 0.700

NTU≅1.5, hence

A=NTU(cmin / U)

= 1.5 x 210.45W / K(200W) / m² .K)

= 1.58m²

1. the air outlet is..

Tc,o = Tc,i + q / Cc

= 300K + (14,732W / 755.25W / K)

= 319.5K

2. using the LMTD approach ΔTlm

= 51.2 K,, R=0.279 and

P=0.7

hence F≅0.95 and

A = q/FUΔTlm = (14,732W) / [0.95(200W / m².K) 51.2K]

= 1.51m²

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The uncertainty principle states that the less we can know about a particle's momentum, the more we can know about its location. A particle's mass multiplied by its momentum determines its momentum.

The uncertainty principle also implies the impossibility of precisely measuring a system's energy in a finite length of time. Measurement of Position and Momentum at the Same Time Is Not Possible. Take an example where the location of an electron is measured to demonstrate Heisenberg's uncertainty principle. An extremely precise measurement of one observable results in a comparatively high degree of measurement uncertainty for the other. A particle's momentum and position can also be used to describe the uncertainty principle.

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The energy of the photon increases with frequency. The number of photons in a beam of light is obvious. This indicates that extremely bright red light (lots of photons, with slightly lower energy).

The increased energy of a violet photon interacts with a single electron and gives it enough energy to escape the metal, making violet light more effective. The frequency of the light determines the electron's energy.

Red light has a lower photon energy than blue light due to its shorter wavelength, lower frequency, and longer wavelength.

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Unpolarized light has light waves that are oriented in all directions while polarized light has all the light waves oscillating in one direction. An example for unpolarized is the Sun, or any other simple type of light.

Whereas if unpolarized light is originally updates, the diffraction pattern will be slightly horizontally polarized, according to the stated assertion.

The light that strikes the object as incident light from the source but also reflects off it is alluded to as refract. It makes no difference what the flashlight is or what you are photographing. When light strikes anything, it will always be transformed and reflected.

A portion of the light is dispersed around a different wavelength; this is called Raman scattering.

Therefore, a portion of the light is dispersed when unpolarized light hits a sample. Rayleigh scattering is the process wherein most of the dispersed light shares the same frequency as the incoming light.

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The resistance of the conductors between the first and last receptacles is 10 ohms.

To determine the resistance of the conductors using Ohm's law, you will need to know the voltage dropped across the conductors and the current flowing through them when the circuit is loaded to 80% capacity. Ohm's law states that the resistance of a conductor is equal to the voltage dropped across it divided by the current flowing through it. Therefore, the resistance of the conductors can be calculated using the following formula:

Resistance (R) = Voltage (V) / Current (I)

Assuming that the voltage dropped across the conductors is V and the current flowing through the conductors is I, the resistance of the conductors can be calculated as follows:

R = V / I

If the circuit is loaded to 80% capacity, the current flowing through the conductors will be 80% of the rated capacity of the overcurrent protective device, which is 15 amperes. Therefore, the current flowing through the conductors will be 0.8 * 15 amperes = 12 amperes.

If the voltage dropped across the conductors is V, the resistance of the conductors can be calculated as follows:

R = V / 12 amperes

To express the resistance in ohms, the units of amperes must be canceled out. Therefore, the resistance of the conductors can be expressed as follows:

R (ohms) = V (volts) / 12 (amperes)

If you know the values of V and I, you can substitute them into the formula above to calculate the resistance of the conductors.

For example, if the voltage dropped across the conductors is 120 volts and the current flowing through the conductors is 12 amperes, the resistance of the conductors would be:

R = 120 volts / 12 amperes = 10 ohms

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