The work done by the steam when the piston moves 0.800 m is 1.75×10⁵ J and the amount of work by calculating the force exerted times the distance traveled is 1.85×10⁵ J. From this, the work done by the second part is more than the initial one. So they are not the same.
The work produced by the compression or expansion of fluid is known as pressure-volume work. Gas molecules gain kinetic energy when energy is added, which causes the gas to expand and affect its surroundings. The work is calculated using the formula W=pΔV where p is pressure, W is work done and ΔV is the change in the volume.
Given the gauge pressure (Pg) of the steam locomotive is 1.75×10⁶ N/m², the radium of piston r is 0.200 m, and the distance moved by the piston l is 0.800 m.
a) First, calculate the ΔV.
ΔV = area×distance
ΔV = πr²×l
ΔV = π×(0.20)²×0.80
ΔV = 0.1 m³
Then, the work done will be,
W = 1.75×10⁶× 0.1
W = 1.75×10⁵ J
The required answer is 1.75×10⁵ J.
b) The absolute pressure is given by the sum of gauge pressure and the atmospheric pressure, i.e., P=P₀+Pg. Then,
P = 1.01×10⁵ + 1.75×10⁶
P = 18.5×10⁵ Pa.
The force is calculated as,
F = P×A
F = 18.5×10⁵×π×(0.20)²
F = 232477 N
The work done by the piston is calculated as,
W = Force×distance
W = 232477×0.80
W = 1.85×10⁵ J
The required answer is 1.85×10⁵ J.
The answer for the first and second parts are not the same.
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a particle moving in a straight line with constant acceleration has a velocity of 3 ms-1 at one instant, and 5 seconds later, it has a velocity of 23 ms-1. The value of t is
A particle has a velocity of 3 m/s at one instant and a velocity of 23 m/s after 5 seconds when it is travelling straight forward with constant acceleration, then t=5sec at a displacement of 65m.
Acceleration, which refers to the rate at which velocity varies over time in terms of both speed and direction, has a value of t of 5 seconds. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. The equation a = v/t denotes acceleration (a), which is the change in velocity (v) over the change in time (t).
Total distance (S) = 23-3 = 20
Here v=23, u=3, time = 5sec
acceleration a= (v-u)/t
a=(23-3)/5
a=(20/5)
a=4
Now S=ut+ (1/2 *a *[tex]t^{2}[/tex])
S = 3(5) + (1/2 * 4 * 25)
S= 15+50
S= 65
t= 5 sec (time doesn't change here only displacement changes).
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Fillet Welds
Design a welded connection for an MC 9 ×23.9 of A572 Grade 50 steel connected to a 3⁄8-inch-thick gusset plate. The gusset plate is A36 steel. Show your results on a sketch, complete with dimensions.
a. Use LRFD. b. Use ASD.
The minimum weld size is 3/16 inch (based on the gusset plate thickness). Maximum size = 0.400- 1/16 0.338 in., or 5/16 in to the nearest 1/16 in.
LRFD solution,
P = 1.2D+1.6L 1.2(48)+ 1.6(120) = 249. 6 kips
Try w = 3/16 in.,
OR, 1.392 x 3 sixteenths = 4.176 kips/in.
The base metal shear yield strength (gusset plate controls) is 0.6F, t=0.6(36)
Shear rupture strength is 0.45F₁ = 0.45(58)() = 9.788 kips/in..
The weld strength of 4.176 kips/in. governs. Both longitudinal and transverse welds will be used. To determine the required length of the longitudinal welds, investigate the two options specified in AISC J2.4(c). First, assuming the same strength for both the longitudinal and transverse welds,
Total required length of weld= 249.6 4.176 59. 77 in.
length of longitudinal welds = 59.77-9.00 = 25.39 in.
For the second option, the strength of the longitudinal welds is 0.85(4.176) 3.550 kips/in.
and the strength of the transverse weld is 1.5(4.176) 6.264 kips/in.
The load to be carried by the longitudinal welds is
249.6-9(6.264) = 193.2 kips so the required length of the longitudinal welds is 193.2 2(3.550) 27.21 in.
To minimize the length of the connection, use the maximum weld size permitted. Use W 5/16 in.
PR. 1.392 x 5 sixteenths 6.96 kips/in
First, assuming the same strength for both the longitudinal and transverse welds,
249.6
total required length of weld= = 35.86 in.
6.96
length of longitudinal welds = 35.86-9.00 13. 43 in. 2
For the second option, the strength of the longitudinal welds is
0.85(6.96) 5.916 kips/in.
and the strength of the transverse weld is
1.5(6.96) 10.44 kips/in.
The load to be carried by the longitudinal welds is
249.6-9(10.44) = 155. 6 kips
so the required length of the longitudinal welds is
155.6/ 2(5.916) =13. 15 in.
The second option requires slightly shorter longitudinal welds. Try a 9-inch transverse weld and two 13½-inch longitudinal welds. Check the block shear strength of the gusset plate.
Agy Any 2x (13.5) 10. 13 in.2
Ant= (9) = 3.375 in.2
R = 0.6FA+Ubs FuAnt 0.6(58) (10.13)+ 1.0(58) (3.375) 548. 3 kips with an upper limit of 0.6FyAg+UbsFuAnt 0.6(36) (10.13)+1.0(58) (3.375) 414. 6 kips (controls) The design strength is OR, 0.75(414.6) 311 kips > 249.6 kips.
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why do the hair straighteners not turn on when only switch s2 is closed?
When only switch s2 is closed the hat straightener will not turn on because the switches are connected In series. for current to flow all the switches must be closed
What is a closed circuit?A closed circuit is a circuit without interruption, providing a continuous path through which a current can flow.. This can be likened to two path ways connected by a bridge to make transportation flow. In a circuit the bridge is the switch or key.
An open circuit is a circuit where the path has been interrupted or "opened" at some point so that current will not flow. An open circuit is also called an incomplete circuit.
When the switch is closed then we will have a closed circuit.
When multiple switches are connected in series with each other, they all must be in the closed position for current to travel through the circuit, thereby energizing the load. The load is the hat straightener here.
Therefore the the hat straightener will not turn on because if only s2 is closed because s1, s2 and s3 are connected in series.
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we can measure the expansion rate of the universe, and how the expansion rate is currently changing. if the current trend continues, in the future the universe will be expanding
The expansion rate of universe is measured in terms of hubble's constant, the expansion rate of universe has increased and at some point in future, it will stop expanding and start to shrink.
There was a lot of uncertainty about the universe's expansion rate before the Hubble telescope was launched. This value is required to calculate the universe's age, estimate its evolution over billions of years, and comprehend the forces that drive it. Astronomers were initially ecstatic when the expansion estimate was reduced to 10% accuracy. They are now approaching one percent accuracy after much perseverance and precise observations.
The cosmic clock can be rewound and the age of the universe calculated by precisely determining the expansion rate, known as the Hubble constant. However, Edwin Hubble's estimates of the universe's expansion implied that it was younger than the Earth and Sun. As a result, Hubble concluded that the redshift phenomenon was a previously unknown property of space rather than a measurement of true space velocity. Redshift was later discovered to be a result of the expansion of space itself, as predicted by Einstein's theory of special relativity.
Thus, by the current data it is noted that the universe is expanding quickly than though before, and if this continues , in the future at some point the universe will stop expanding and it will start shrinking.
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The total horizontal distance traveled by the tennis ball during the entire time it is in the air is approximatelyA.23 m C.8.3 m B.17 m D.4.1 m.
The total horizontal distance traveled by the tennis ball during the entire time it is in the air is approximately: 23 m
What is horizontal distance?It is the line drawn horizontally from the viewer's eye. If an item is above the horizontal level, the angle of elevation is the angle created between the line of sight and horizontal level.
As we know,
H = [u(y)]²/2 g
or, H = (6.1)²/20
or, H = 1.86 m ≈ 1.9 m
Total max height = 1.9 m + 9.8 = 11 m
H = [u(y)]²/2g
or, 11 = [u(y)]²/20
or, u(y) = 14.832 m/s
u(x) = 7.6 m/sec
Now, R = u²sin 2θ/g
or, R = [2 u(x) u(y)] /g
or, R = [2×(7.6 )×( 14.832 )] / 10
or, R = 22.54 m
or, R = 23 m
Correct option: A
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15. Why are torque rods only really suitable for use in low Earth orbit?
The magnetic field is stronger.
The sensors are sensitive to gases.
The rotation is set at a fixed rate.
There is a limited amount of fuel.
Torque rods only really suitable for use in low Earth orbit due to the magnetic field is stronger option -1 is correct.
What is the process of a torque rod?By preventing the motor from rolling during the transfer of load, torque rods or torque roll restrictors reduce the effect of torque. The difficulties brought on by recovery functions are also addressed. They also stop vibration and noise from traveling from the motor block to the chassis, which limits motor roll.
Electromagnets used for attitude control on spacecraft are called torque rods. The spacecraft experiences a torque and changes in orientation when a current flows through the torque rod, creating a magnetic field that interacts with the geomagnetic field of the planet.
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A thin plastic rod of length 2.9 m is rubbed all over with wool, and acquires a charge of 60 nC, distributed uniformly over its surface. Calculate the magnitude of the electric field due to the rod at a location 8 cm from the midpoint of the rod. Do the calculation two ways, first using the exact formula for a rod of any length, and second using the approximate formula for a long rod.
(a) exact formula
E = N/C
(b) approximate formula
E = N/C
The magnitude of the electric field due to the rod at a location 8 cm from the midpoint of the rod is 2 N/C
E=F/Q
E=120/60
E=2 N/C
Any charge results in an electric field being connected to a specific location in space. The value of E, also known as the electric field strength, electric field intensity, or just the electric field, expresses the magnitude and direction of the electric field. Without any specific knowledge of what caused the field, knowing the value of the electric field at a particular location is sufficient to predict what will happen to nearby electric charges. The electric force F, or Coulomb force, exerted per unit positive electric charge q at that location may be used to calculate the strength of an electric field, or E = F/q, if the second charge, or test, is positive.
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a solid conducting cylinder of radius r carries a current i. how must the current density vary with the distance r from the center of the conductor if the magnitude of the magnetic field within the conductor is the have the same value at all points.
The current density the magnitude of the magnetic field within the conductor is nevd.
The amount of current flowing per cross-sectional area is referred to as the current density and is expressed in amperes per square meter. As more current flows through a conductor, the current density rises. The term "current density" refers to the amount of current flowing through a material per unit cross-sectional area. Thus, the SI unit for current density must be ampere/m2. The current density is defined as the ratio of the current flowing through a conductor to its cross-sectional area perpendicular to the direction of current flow. The equation J=n e vd describes the interaction between drift velocity vd and current density J.
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a block of mass 2.57 kg lies on a frictionless horizontal surface. the block is connected by a cord passing over a pulley to another block of mass 5.2 kg which hangs in the air, as shown. assume the cord to be light (massless and weightless) and unstretchable and the pulley to have no friction and no rotational inertia. The acceleration of gravity is 9.8 m/s2 Calculate the acceleration of the first block. Answer in units of m/s .
The acceleration of the two blocks are the same and it is 6.56 m/s².
The free-body diagram is in the attached picture.
Applying the Newton's second law of motion,
First block:
T = m₁a ....... (equation 1)
Second block:
m₂g - T = m₂a .... (equation 2)
Where:
m₁ = mass of the 1st block = 2.57 kg
m₁ = mass of the 2nd block = 5.2 kg
T = chord tension
a = acceleration
g = acceleration of gravity = 9.8 m/s²
Substitute equation 1 to equation 2
m₂g - m₁a = m₂a
( m₁ + m₂) a = m₂g
a = [m₂/( m₁ + m₂)] x g
= [5.2 / (2.57+5.2)] x 9.8
= 6.56 m/s²
Hence, the acceleration is 6.56 m/s²
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in this water supply system, areas of need are removed from the water source, perhaps because of a higher elevation or remote location. the pumps in the system provide water directly to the system as well as pumping water into storage tanks. by filling the tanks at times of low use, the pumps do not have to provide the total supply to the system at times of high use
A dry hydrant is a permanently erected conduit with pumper suction connections to facilitate quick drafting operations at stationary water sources.
Which style of fire hydrant is used in regions that experience extended periods of subfreezing weather?Barrel Dry Hydrants
In regions where the temperature goes below freezing, this sort of fire hydrant is fairly prevalent. In these regions, hydrants' barrels must be kept dry to prevent the water within from freezing.
A Class C fire hydrant is what?Class A: 1000–1499 gpm of maximum capacity. 3. Class B - 500 to 999 gpm of rated capacity. Class C: Capacity rated at less than 500 gpm.
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TRUE/FALSE. a pan of enchiladas is served at a dinner party. its starts to cool according to newton's law of cooling
False. A pan of enchiladas is served at a dinner party and it does not start to cool according to Newton's law of cooling.
Newton's Law of Cooling states that the rate of heat loss of a body is proportional to the difference in temperatures between the body and its surroundings. This means that the hotter an object is compared to its surroundings, the faster it will cool.
Therefore, the rate of cooling of the enchiladas would depend on the temperature of the environment in which it is served. If the environment is a warm room, for example, the pan of enchiladas would cool at a slower rate than if it were served in a cold room.
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Colors seen on the cover of your physics book are due to color A) addition. B) subtraction. C) either of these D) neither of these.
Color subtraction produces the colours displayed on the cover of our physics book.
What is colour subtraction?
If the incident light and pigment colours are known, the colour subtraction approach can be a useful tool for predicting the ultimate colour appearance of an object. The complementary colour scheme can be used to identify the light colours that will be absorbed by a certain material. To identify the colours of reflected light (or transmitted light), subtract the incident light colours (if any are present). Thus, the colour appearance of the item may be predicted.
Color subtraction produces the colours displayed on the cover of our physics book.
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Joe pushes a 50 kg box for 3 meters.
What is Joe's speed?
Explanation:
It is not possible to determine Joe's speed based on the information provided. Speed is a measure of how quickly an object moves over a given distance and is calculated by dividing the distance traveled by the time it took to travel that distance. In order to determine Joe's speed, we would need to know how long it took him to push the box 3 meters.
the concentration of is higher inside than outside the cell.target 1 of 5 the membrane is more permeable to blank.target 2 of 5 the resting membrane potential is maintained by na -k pumps that actively transport into and out of the cell.target 3 of 5target 4 of 5 the concentration of is higher outside than inside the cell.
The concentration of K+ is higher inside than outside the cell.
The resting membrane potential is maintained by Na+-K+ pumps that actively transport K+ into and Na+ out of the cell.
The concentration of Na+ is higher outside than inside the cell.
The concentration of potassium ions inside the cell is greater than the concentration of sodium ions outside the cell. The amount of water outside the cell compared to inside creates an osmotic gradient that drives water movement. In other words, if there are more solutes outside the cell than inside, water will move out of the cell to balance the solute levels inside.
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A 50.0 g block of copper whose temperature is 400 K is placed in an insulating box with a 100 g block of lead whose temperature is 200 K. (a) What is the equilibrium temperature of the twoblock system? (b) What is the change in the internal energy of the system between the initial state and the equilibrium state? (c) What is the change in the entropy of the system?
a) The equilibrium temperature of the two block system is 320k
b) The change in the internal energy of the system is zero.
c) The change in entropy is +1.72kj
a) We refer. to the copper. block as block. 1 and the lead block. as block 2. The equilibrium temperature T satisfies
m1c1 (T - Ti) + m2c2 (T - TI2) = 0
T = m1C1Ti1 + m2C2Ti2 / m1C1 + m2C2 = 50 × 386×400 + 100×128×200/50×386 + 100×128 = 320K
T = 320K
b)The internal energy of the two-block system does not change because it is thermally isolated from the outside environment.
C)The change in entropy is ΔS = ΔS1 + ΔS2 = m1c1ln(T /Ti) + m2c2ln(T/Ti)
Δs = +1.72kj
A state of disorder, randomness, or uncertainty is most frequently connected with the scientific notion of entropy, which is also a quantifiable physical attribute. The notion and the phrase are employed in a variety of disciplines, including classical thermodynamics, where they were initially identified, statistical physics, which describes nature at the molecular level, and information theory. It has wide-ranging uses in physics and chemistry, biological systems and how they relate to life, cosmology, economics, sociology, weather science, and information systems, particularly the transfer of information through telecommunication.
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in fig. 11-37, a small, solid, uniform ball is to be shot from point p so that it rolls smoothly along a horizontal path, up along a ramp, and onto a plateau.then it leaves the plateau horizontally to land on a game board, at a horizontal distance d from the right edge of the plateau. the vertical heights are h1 ! 5.00 cm and h2 ! 1.60 cm. with what speed must the ball be shot at point p for it to land at d ! 6.00 cm?
The ball must be fired at point p with a speed of 6.635 m/s in order for it to settle at a distance of 6 cm.
Due to it,
Height h1 equals 5 cm
h2 = 1.6 cm tall
Distance d = 6 cm
We are aware that t = (h2/g2) = (1.6*)/9.8 = 0.57 s.
We are aware that distance is simply speed times time.
The expression may be written as d = V1* t V1 = d/t = 6/0.57 = 10.52 m/s based on the aforementioned assertion.
According to the work energy theory, mg(h1-h2) = 1/2* m* V12 - 1/2* m* V22.
When "m" is removed from both sides, 1/2* V12 - 1/2* V22 = g(h1 - h2) 9.8 (5 - 1.6) = 1/2* 10.522 - 1/2* V22 33.32 = 1/2(10.522 - V22) (10.522 - V22) = 66.64 V22 = 44.03 V2 = 6.635 m/s
In light of this, the recommended ball speed is 6.635 m/s.
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when you urinate, you increase pressure in your bladder to produce the flow. for an elephant, gravity does the work. an elephant urinates at a remarkable rate of 0.0060 m3 (a bit over a gallon and a half) per second. assume that the urine exits 1.0 m below the bladder and passes through the urethra, which we can model as a tube of diameter 8.0 cm and length 1.2 m. assume that urine has the same density as water, and that viscosity can be ignored for this flow.
A model as a tube of diameter 8.0 cm and length 1.2 m. assume that urine has the same density as water, the pressure is -9088 pa.
Calculation :
v = flowrate/area = 0.0060/π(0.04)² = 1.2 m/s
2). from Bernoulli's eqn ,
[tex]P_{bla}[/tex] - [tex]P_{atm}[/tex] = [tex]\frac{1}{2}Pv _{2} ^{2}[/tex] + [tex]\frac{1}{2}Pv _{1} ^{2}[/tex] - ρgh1
[tex]P_{bla}[/tex] - [tex]P_{atm}[/tex] = [tex]\frac{1}{2}Pv _{2} ^{2}[/tex] + 0 - ρgh1
ΔP = 1/2(1000)(1.19)² - (1000)(9.8)(1)
= 712.4 - 9800
= -9088 pa
Pressure (symbol: p or P) is the force normal to the surface of an object per unit area over which that force is distributed.
Various units are used to express pressure. Some of these are units of force divided by units of area. For example, the SI unit of pressure, Pascal (Pa), is 1 Newton per square meter (N/m2).
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A person is lying on a diving board 2.50 m above the surface of the water in a swimming pool. She looks at a penny that is on the bottom of the pool directly below her. To her, the penny appears to be a distance of 7.00 m from her. What is the depth of the water at this point?
2.50 m above the water's surface, a person is resting on a diving board in a swimming pool. The penny appears to be seven meters away from her in her field of vision.The depth of water from this point is 6m.
The distance of board from water surface is given as 2.50m and appeared distance of penny from eyes of the person in board is given as 7.00m so this means apparent distance of penny from eyes of the person is:-
Total appeared distance from eyes of the person when its above the board- distance of the board from surface of the water.
Which is given as
=7.00m - 2.50m
=4.5m.
As we look at something from rarer to denser medium the apparent depth of that object which appears to us decreases.
So real depth of water can be given to us by:-
Apparent depth=Real depth / vdr,
here vdr is refractive index of denser medium with respect to refractive index of rarer medium which is given by
vdr=vd / dr
=Refractive index of water / Refractive index of air
=43
Therefore apparent depth is
=4.54/3
=6m.
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An object undergoes uniform circular motion at a constant radius and with period T (i.e., it makes one complete revolution around the circle in time T). As a result, the magnitude of the centripetal acceleration of the object is ac. Suppose now the motion is changed so that the period is T/2 but the radius is the same. What will be the new magnitude of the centripetal acceleration? a. a/2 b. 2ac c. 4ac
Option C; The new magnitude of the centripetal acceleration 4ac
Initial condition time period = T
T = distance / speed = 2πR/v
T/2 = 2πR/V2
V2 = 4πR/T = 2V1
Centripetal acceleration,
Ac = 1/2mv² = 1/2 m4v1²
Ac = 4ac
As a characteristic of an object's motion when it is traveling along a circular path, centripetal acceleration is described. Centripetal acceleration is the motion of an item in a circle with its acceleration vector pointing in its direction of motion. Centripetal accelerations result from centripetal forces. The centripetal force driving the motion is a result of their gravitational pull in the unique instance of the Earth's round motion around the Sun, or any satellite's circular motion around any celestial body.
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Given the following code snippet, what is considered an argument(s)?def mystery(num1, num2) :result = num1 ** num2return resultmystery(10, 2)
Result = num1 ** num2, return result, mystery(10, 2) 10, 2. You can provide a function more information by using an argument.
What do the code snippet's arguments and parameters mean?The variables used to define a function are known as parameters. They are variables that will be used in the function body and are present in the function signature. When we call a function, arguments are the real values that are supplied to it.
Which of the following describes how to write a function in Python correctly?A function is defined in Python by using the def keyword, which is followed by the function's name, parentheses, and a colon. Make sure to indent with a tab or 4 spaces the following step, and then specify.
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compare and constrast bragg's law of diffraction with the grating diffraction equation and the thin-film interference equation. here, we mean the equations that relate spacing and wavelength to the locations of maxima in the diffraction or interference pattern
Laue diffraction, which establishes the angles of coherent and incoherent scattering from a crystal lattice, is a specific example of Laue's law known as Bragg's law. An electronic cloud moves like an electromagnetic wave when X-rays strike a certain atom.
How does Bragg's law work?In physics, the Bragg law describes the relationship between the distances between atomic planes in crystals and the angles of incidence at which these planes generate the strongest reflections of X-rays, gamma rays, and particle waves like those linked to electrons and neutrons.
Waves from two independent sources that produce different wavefronts are said to be causing interference. On the other hand, diffraction is a word for secondary waves that result from the various components.
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A flat uniform circular disk has a mass of 3.00 kilogram and a radius of 70.0 \text{~cm}70.0 cm. It is suspended in a horizontal plane by a vertical wire attached to its center. If the disk is rotated 2.50 \text{~rad}2.50 rad about the wire, a torque of 0.0600 \text{~N}\cdot \text{m}0.0600 Nâ‹…m is required to maintain that orientation. Calculate the rotational inertia of the disk about the wire.
The rotational inertia of the disk about the wire is 243 kilograms*meters^2.
The rotational inertia of a body about a given axis is a measure of the body's resistance to changes in its rotational motion. It is given by the formula I = ∑m*r^2, where m is the mass of each particle in the body, r is the distance of each particle from the axis of rotation, and the sum is taken over all particles in the body.
In this case, the body is a flat circular disk with a mass of 3.00 kilograms and a radius of 70.0 centimeters. The axis of rotation is the vertical wire attached to the center of the disk. To find the rotational inertia of the disk about the wire, we need to calculate the sum of m*r^2 for all the particles in the disk.
Since the disk is uniform, all the particles in the disk have the same mass. Therefore, we can simplify the formula for rotational inertia to I = mR^2, where m is the mass of the disk and R is the radius of the disk. Plugging in the values for m and R, we get
I = 3.00 kilograms * (70.0 centimeters)^2 = 24300 kilograms centimeters^2.To convert this value to the units of rotational inertia (kilogrammeters^2), we can use the conversion factor 1 meter = 100 centimeters. This gives us
I = 24300 kilogramscentimeters^2 * (1 meter / 100 centimeters)^2 = 243 kilograms*meters^2.Learn more about Rotational inertial here:
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4. If μs between a basketball shoe and a court is 0.56, and the normal reaction
force acting on the shoe is 350 N, how much horizontal force is required to
cause the shoe to slide?
mu sub s times N is the frictional force
which equals 196 N
so 196 newton force is required for the shoe to slide
Answer: 196 N
Explanation: The coefficient of static friction (μs) between two surfaces represents the maximum horizontal force that can be applied to an object before it begins to slide. The formula for calculating the required horizontal force to cause an object to slide is:
F = μs * N
where F is the required horizontal force, μs is the coefficient of static friction, and N is the normal reaction force acting on the object.
In this case, the required horizontal force to cause the basketball shoe to slide is:
F = 0.56 * 350 N
F = 196 N
So, a horizontal force of 196 N is required to cause the basketball shoe to slide on the court.
Your car speeds around the 80-m-radius curved exit ramp of a freeway. A 70-kg student holds the armrest of the car door, exerting a 220-N force on it in order to prevent him self from sliding across the vinyl-covered back seat of the car and slamming into his friend. How fast is the car moving in meters per second and miles per hour? What assumptions did you make?
The speed of the car in miles per hour and meters per second is 2.2369
Explain about the speed?The first person to calculate speed by accounting for both the distance travelled and the amount of time required was the Italian physicist Galileo Galilei. Galileo described speed as the distance travelled in a unit of time.
The speed of anything indicates how quickly it is moving. Miles per hour (mph), kilometres per hour (km/h), and metres per second (m/s) are the three most used speed measurement units (mph).
A speedometer is the most effective tool for demonstrating instantaneous speed. Another method to state the speed of light is as 186,282 miles per second. The speed of sound in dry air is 343.2 metres per second. The term "escape velocity" refers to the speed necessary to escape the gravitational pull of the Earth.
Radius = 80 m
mass of the student m = 70
Force = 220
F/M =220 / 70
=3.14 m
3.14 = v2/80
=15.85m/s
1 m/s = 2.2369 miles per hour
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the reason that buoyant force acts upward on a submerged object is that question 12 options: if it acted downward, nothing would float. it acts in a direction to oppose gravity. the weight of fluid displaced reacts with an upward force. upward pressure against the bottom is greater than downward pressure against the topof the submerged object.
Option D; Upward pressure against the bottom is greater than downward pressure against the top of the submerged object.
The buoyant force is an upward force applied to objects submerged in fluids. As you swim downward, the water will try to force you back up to the surface, which can be annoying. The buoyant force is the name given to this upward force acting on things submerged in fluids.
The differential in Upward pressure between the top and bottom of the submerged object is the cause. Imagine a bean can being dumped into a watery basin. Since pressure (P gauge=rho gh)(P gauge = gh)left parenthesis, P, start subscript, g, a, u, g, e, end subscript, equals, rho, g, h, right parenthesis grows as you move deeper in a fluid, the force from pressure exerted increases.
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match the items on the left with the correct definition on the right. 1 . radiant the top of a light wave 2 . speed of sound 1,100 feet per second 3 . speed of light the frequency of sound 4 . vibrations the bottom of a light wave 5 . pitch the cause of sound 6 . photons the loudness of a sound 7 . amplitude 186,000 miles per second 8 . trough longer wavelength than visible light 9 . crest particles of light energy 10 . microwaves energy of light
The sound speed Pitch at 1,100 feet per second, light speed at 1,860 miles per second, radiant sound frequency, top and bottom vibrations of a light wave, and pitch at 1,100 feet per second.
What exactly are wavelengths and frequencies?The wavelength is the separation between two wave crests, while troughs have the same wavelength. The frequency is the quantity of vibrations that cross a specific area in a second.
How do you calculate wavelength?The distance between any two identical locations on adjacent waves may always be used to calculate the wavelength. A longitudinal wave's wavelength is determined by counting the distance between each compression and the one after that, or from a rarefaction.
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the picture shows different objects being weighed on scales. which ball will require the most force to lift? a the golf ball because it is the smallest in size b the beach ball because it is the largest in size c the soccer ball because it has the most mass d the baseball because it has the most material
Answer:
C. the soccer ball because it has the most mass
Explanation:
soccer ball - 410 g
beach ball - 110 g
baseball - 143 g
golf ball - 46 g
(i just took the test)
A spring with a force constant of 69 N/m is attached to a 0.57 kg mass. Assuming that the amplitude of motion is 3.1 cm, determine the following quantities for this system: (a) w, (b) vmax, (c) T.
The amplitude motions are W =≈ 12 rad/s , Vmax= 0.36 m/s , T= ≈ 0.54 s.
What is amplitude ?
Distance between a wave's resting position and its highest movement is known as amplitude. Frequency is the quantity of waves that pass past a certain place each second. Period is the amount of time it takes for a wave cycle to finish.
What is force?
Everyday activities like walking, setting something down on a surface, tossing something into the air, and even the tides' regular variations all include the application of force. The result of the interaction between two or more things, a force is a push or a pull.
a)w = √k/m = √(67/0.49) = 11.69336 ≈ 12 rad/s
b)v_max = A w = 0.031 * 11.69336 = 0.36 m/s
c)T = 2π/w = 2*3.14/11.69336 = 0.53706 ≈ 0.54 s
Therefore, the amplitude motions are W =≈ 12 rad/s , Vmax= 0.36 m/s , T= ≈ 0.54 s.
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A sample of an ideal gas goes through the process shown in Figure . From A to B, the process is adiabatic; from B to C, it is isobaric with 345 kJ of energy entering the system by heat; from C to D, the process is isothermal; and from D to A, it is isobaric with 371 kJ of energy leaving the system by heat. Determine the difference in internal energy E int,B −E int.A
A sample of an ideal gas goes through the process, the difference in internal energy [tex]E_{int},B - E_{int}.A[/tex] is 4.29 × 10⁴ J.
To calculate the difference in internal energy (ΔE_int) between points B and A, we need to consider the energy changes in each segment of the process and apply the First Law of Thermodynamics, which states:
Δ[tex]E_{int[/tex] = Q - W
where Δ[tex]E_{int[/tex] is the change in internal energy, Q is the heat added to the system, and W is the work done by the system.
Let's calculate the changes in internal energy for each segment:
1. From A to B (adiabatic process):
In an adiabatic process, no heat exchange (Q) occurs. Therefore, Q = 0.
The work done (W) in an adiabatic process is given by:
W = n * Cv * ( [tex]T_B[/tex] - [tex]T_A[/tex])
Since it is an ideal gas, the molar specific heat at constant volume (Cv) can be expressed as Cv = (f/2) * R.
The change in temperature ( [tex]T_B[/tex] - [tex]T_A[/tex]) can be found using the adiabatic equation:
( [tex]T_B[/tex] / [tex]T_A[/tex]) = [tex](V_A / V_B)^{(\gamma - 1)[/tex]
where γ is the adiabatic index or ratio of specific heats (γ = Cp/Cv).
2. From B to C (isobaric process):
In an isobaric process, the change in internal energy is given by:
Δ[tex]E_{int[/tex] = Q - W
W = P * ΔV
where P is the constant pressure and ΔV is the change in volume.
3. From C to D (isothermal process):
In an isothermal process, the temperature remains constant. Therefore, Δ[tex]E_{int[/tex] = 0.
4. From D to A (isobaric process):
Similar to the B to C segment, the change in internal energy is given by:
Δ[tex]E_{int[/tex] = Q - W
Given that the heat added from B to C is 345 kJ, and the heat released from D to A is 371 kJ, we can now calculate the difference in internal energy (Δ[tex]E_{int[/tex]) between points B and A.
Thus, if we sum up all the changes in internal energy for each segment, we get the desired value of Δ[tex]E_{int[/tex] which is approximately 4.29 × 10^4 J.
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g an intergalactic spaceship arrives at a distant planet that rotates on its axis with a period of t
a) Radius's general expression is R = ∛T²GM/4π².
b) The mass of the planet in kilograms if T = 26 hours and R = 2.1 × 108 m is 4.9 ×10²⁵kg.
a) The general definition of the radius is R = ∛T²GM/4π²
b) The mass of the planet throughout its geosynchronous orbit is 4.9 × 10²⁵ kg.
T = period of the orbit = 26hours
r = radius of the orbit = = 2.1 × 10⁸ m.
G = gravitational constant = 6.674×10⁻¹¹ m³⋅kg⁻¹⋅s⁻²
M = mass of the planet
Putting the value in the radius equation we get,
R = ∛T²GM/4π²
8.98 ×10⁷ m = ∛ (26 × 60 × 60)² ×( 6.67 ×10⁻¹¹) M/ 4×(3.142)²
M = (8.98 ×10⁷ m ×39.49 )/ (∛2.86 × 10¹⁸)
M = 4.9 ×10²⁵
As a result, the planet has a mass of 4.9 ×10²⁵kg throughout its geosynchronous orbital period.
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The question is -
An intergalactic spaceship arrives at a distant planet that rotates on its axis with a period of T. The spaceship enters a geosynchronous orbit at a distance of R. a) From the given information, write a general expression for the mass of the planet in terms of G and the variables from the problem statement. b) Calculate the mass of the planet in kilograms if T = 26 hours and R = 2.1 × 108 m.