x + y=100 x-y=10 pair of equation

Answer:

why are you running

Step-by-step explanation:

why are you running

Answer:

360 cubic inches (remember your units!)

Step-by-step explanation:

the formula for volume of a rectangular prism is length times width times height times depth so you have to do 8 times 5 times 9 witch is 360 cubic inches

Answer:

14.0625 = [tex]\frac{225}{16}[/tex]

6.41666666666... = [tex]\frac{77}{12}[/tex]

Hope that this helps!

Step-by-step explanation:

which class are you

just to confirm

Answer:

slope=y2-y1/x2-x1

=5-5/-1-3

=0/-4

=0

Step-by-step explanation:

Answer:

slope = 0

Step-by-step explanation:

Calculate the slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (3, 5) and (x₂, y₂ ) = (- 1, 5)

m = [tex]\frac{5-5}{-1-3}[/tex] = [tex]\frac{0}{-4}[/tex] = 0

Answer:

1,500

Step-by-step explanation:

a + 5d = 39 (1)

a + 18d = 78 (2)

Subtract (1) from (2) to eliminate a

18d - 5d = 78 - 39

13d = 39

d = 39/13

d = 3

Substitute d = 3 into (1)

a + 5d = 39 (1)

a + 5(3) = 39

a + 15 = 39

a = 39 - 15

a = 24

Sum of the first 25 terms

Sn = n/2[2a + (n – 1)d]

S25 = 25/2{2*24 + (25-1)3}

= 12.5{48 + (24)3}

= 12.5{48 + 72)

= 600 + 900

= 1,500

S25 = 1,500

Hi there!

[tex]\large\boxed{AC \approx 483 ft}}[/tex]

AC is the hypotenuse, so we can use a trig formula to solve.

We are given the adjacent side, AB, so we must use cosine. Recall that:

cosθ = A/H

Thus:

cos(21.3) = 450 / H

Rearrange:

H = 450 / cos(21.3)

Use a calculator to evaluate:

H = 482.99 ≈ 483 ft.

Answer:

AC ≈ 483

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos21.3° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{AB}{AC}[/tex] = [tex]\frac{450}{AC}[/tex] ( multiply both sides by AC )

AC × cos21.3° = 450 ( divide both sides by cos21.3° )

AC = [tex]\frac{450}{cos21.3}[/tex] ≈ 483 ( to the nearest whole number )

Answer:

48°

Step-by-step explanation:

The angle CRS looks like a "L" shape, meaning that both lines are perpindicular to each other, resulting in a right angle (which is 90°)

90° + 42° = 132°

180° - 132° = 48°

Answer:

<RCS = 48 degrees

Step-by-step explanation:

I'm pretty sure that is a right triangle

180-90-42=48

Answer:

The shelf life of a particular dairy product is normally distributed with a mean of 12 days and a standard deviation of 3 days. 3. A line up for tickets to a local concert had an average (mean) waiting time of 20 minutes with a standard deviation of 4 minutes.

Step-by-step explanation:

Answer:

The answer to the problem is 15.

Answer:

180 D

Step-by-step explanation:

Answer:

15

Step-by-step explanation:

To find the unit rate you divide.

• the points that is in bold is ( 2, 30) from that information you would see what times 2 gives me 30.

• 30/2 =15

• unit rate= 15

Answer:

10x+ y

Step-by-step explanation:

The unit's digit is y and the ten's digit is x.

The ten's digit has a zero placed beside it .

So multiply x by 10  giving 10 x and then add the unit's digit .

This wil give 10x+ y

The number is 10 x + y

This can be elaborated through the use of numbers . Suppose we have unit's digit as 6 and the ten's digit as 5.

Multiply 10 by 5 and add 6

5*10 +6= 50+6= 56

Step-by-step explanation:

x = 7 cos 210 = 7×(-½√3) = -3.5√3

y = 7 sin 210 = 7×(-½) = -3.5

point C (-3.5√3 , -3.5)

Answer:

number 3 sir

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex] \frac{4f^{2} }{3} \div \frac{1}{4f} [/tex]

[tex] \frac{4 {f}^{2}}{3} (4f)[/tex]

[tex]4 \frac{4 {f}^{2} }{3} f[/tex]

[tex] \frac{16 {f}^{2} }{3} f[/tex]

[tex] \frac{16 {f}^{3} }{3} [/tex]

Answer:

what value??????

Answer:

yeah what you need help with

Answer:

x = 4.4

Step-by-step explanation:

Flat cost = $57.5/month

Cost of 1GB = $4

But Aubrey wants to keep her bill at $75.1/month.

Let 'x' be the number of GBs she can use while staying within her budget.

So, the equation will be → 4x + 57.5 = 75.1

Now, solve the equation :-

[tex]=> 4x + 57.5 - 57.5 = 75.1 - 57.5[/tex]

[tex]=> 4x = 17.6[/tex]

[tex]=> \frac{4x}{4} = \frac{17.6}{4}[/tex]

[tex]=> x = 4.4[/tex]

Answer:

96

Step-by-step explanation:

Total of 4 test at 90

90 * 4 = 360

Current total

88 * 3 = 264

Score needed

360 - 264 = 96

Answer:

96

Step-by-step explanation:

this is how i solved it:

88 x 3 = 264 ( the sum of the three test score )

now i just gotta look for a number to add to 264 that will give me 90 (the wanted mean score) if i divide the sum by 4 (the four test scores).

so the equation would be:

(264 + x) / 4 = 90

264 + x = 360

x= 96

Answer:

8

Step-by-step explanation:

6g = 48

/6 /6

divide 6 by both sides

g = 8

hope this helped!

Answer:

12√3

Step-by-step explanation:

sin 60° = 18/h

h = 18/sin 60°

h = 12√3

Answer:

2, probably

Step-by-step explanation:

Answer:

AB= 5.582

Step-by-step explanation:

Centeral angle /360° = AB length/2 pi r

[tex] \frac{80}{360} = \frac{ab}{4} \\ ab = 5.582[/tex]

Answer:

5.6

Step-by-step explanation:

the length of arc AB =

80/360 × 2× 3.14×4

= 2/9 × 3.14 × 8

= 5.58 => 5.6

Step-by-step explanation:

it should be x= -3 and x= 1

Answer:

Mean: 2.125

median: 2

range: 4

Answer:did u ever get it

Step-by-step explanation:

Answer:

n geometry, the notion of a connection makes precise the idea of transporting data[further explanation needed] along a curve or family of curves in a parallel and consistent manner. There are various kinds of connections in modern geometry, depending on what sort of data one wants to transport. For instance, an affine connection, the most elementary type of connection, gives a means for parallel transport of tangent vectors on a manifold from one point to another along a curve. An affine connection is typically given in the form of a covariant derivative, which gives a means for taking directional derivatives of vector fields, measuring the deviation of a vector field from being parallel in a given direction.

Connections are of central importance in modern geometry in large part because they allow a comparison between the local geometry at one point and the local geometry at another point. Differential geometry embraces several variations on the connection theme, which fall into two major groups: the infinitesimal and the local theory. The local theory concerns itself primarily with notions of parallel transport and holonomy. The infinitesimal theory concerns itself with the differentiation of geometric data. Thus a covariant derivative is a way of specifying a derivative of a vector field along another vector field on a manifold. A Cartan connection is a way of formulating some aspects of connection theory using differential forms and Lie groups. An Ehresmann connection is a connection in a fibre bundle or a principal bundle by specifying the allowed directions of motion of the field. A Koszul connection is a connection which defines directional derivative for sections of a vector bundle more general than the tangent bundle.

Connections also lead to convenient formulations of geometric invariants, such as the curvature (see also curvature tensor and curvature form), and torsion tensor.

Step-by-step explanation:

Answer:

n geometry, the notion of a connection makes precise the idea of transporting data[further explanation needed] along a curve or family of curves in a parallel and consistent manner. There are various kinds of connections in modern geometry, depending on what sort of data one wants to transport. For instance, an affine connection, the most elementary type of connection, gives a means for parallel transport of tangent vectors on a manifold from one point to another along a curve. An affine connection is typically given in the form of a covariant derivative, which gives a means for taking directional derivatives of vector fields, measuring the deviation of a vector field from being parallel in a given direction.

Connections are of central importance in modern geometry in large part because they allow a comparison between the local geometry at one point and the local geometry at another point. Differential geometry embraces several variations on the connection theme, which fall into two major groups: the infinitesimal and the local theory. The local theory concerns itself primarily with notions of parallel transport and holonomy. The infinitesimal theory concerns itself with the differentiation of geometric data. Thus a covariant derivative is a way of specifying a derivative of a vector field along another vector field on a manifold. A Cartan connection is a way of formulating some aspects of connection theory using differential forms and Lie groups. An Ehresmann connection is a connection in a fibre bundle or a principal bundle by specifying the allowed directions of motion of the field. A Koszul connection is a connection which defines directional derivative for sections of a vector bundle more general than the tangent bundle.

Connections also lead to convenient formulations of geometric invariants, such as the curvature (see also curvature tensor and curvature form), and torsion tensor.

Step-by-step explanation:

Answer:

according to me the ans is 3.