The temperature remain constant at the boiling point of water when the internal energy is increasing because: all the heat energy provided is used up in changing the state of water from liquid to gaseous water vapour.
Meaning of Change in StateA Change in state can be defined as the process of moving from one matter form to another due to heat supplied or removed.
A change in state can happen in different forms of matter.
In conclusion, The temperature remain constant at the boiling point of water when the internal energy is increasing because: all the heat energy provided is used up in changing the state of water from liquid to gaseous water vapour.
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Block X and Y are attached to each other by a light rope and can slide along a horizontal
surface. Mass of block X is 10 kg and that of block Y is 5 kg. The magnitude of force of
friction on blocks X and Y is 8.0 N and 4.0 N respectively. Find the action-reaction forces
that the blocks exert on each other if an applied force of 40 N [right] acts on block per the
illustration below
please answer asap
the action-reaction forces that the blocks exert on each other will 13 N and 22N
Force on a Horizontal PlaneForce is the product of mass and acceleration. There will be constant acceleration on both object X and Y.
Given that the Mass of block X is 10 kg and that of block Y is 5 kg. The magnitude of force of friction on blocks X and Y is 8.0 N and 4.0 N respectively. if an applied force of 40 N [right] acts on block,
We are given that:
Mass of block X = 10 KgMass of block Y = 5 KgApplied force = 40 NMagnitude of friction on X block = 8NMagnitude of friction on Y block = 4 NWith the use of the formula below,
F - [tex]F_{r}[/tex] = ma
Where
F = force applied[tex]F_{r}[/tex] = frictional forcem = massa = accelerationThe acceleration will be;
40 - (8 + 4) = (10 + 5)a
40 - 12 = 15 a
28 = 15a
a = 28/15
a = 1.8667 m/[tex]s^{2}[/tex]
The tension between the two blocks will be
Force applied-frictional force on X-tension = mass of X × acceleration
That is,
F - [tex]F_{r}[/tex] = ma
40-8-T = 10 × 1.8667
32 - T = 18.667
T = 32 - 18.667
T = 13.33 N
The opposite reaction will be
F - 8 = 10 x 1.8667
F - 4 = 18.67
F = 18.67 + 4
F = 22.67 N
Therefore, the action-reaction forces that the blocks exert on each other will 13 N and 22N
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An eagle that has a mass of 4.5 kg is spotted 5 m above a lake. it flies up to its nest in a tree at a height of 25 m. how much gravitational potential energy did the eagle gain? 221 j 882 j 1103 j 1323 j
882J of gravitational potential energy is gained by the eagle.
Here, we have been provided with data-
mass, m = 4.5 kg
height, h = 25 m
We have to find the gravitational potential energy.
In the question, it is given that the eagle is at a height of 5m and it flies from there 20 m more to reach its nest.
So, gravitational potential energy is given as
P.E = m x g x h
P.E = 4.5 × 9.8 × 20
P.E = 882J
Thus, the correct option is (b).
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Answer:
b
Explanation:
its b
The _________ system produces electrical power while the engine is running to operate all the electrical components and recharge the battery
Answer:
kinetic energy and potential and electrical energy
Explanation:
it will be need to maintain the motion of the vehicle and produce electrical energy
do banked curves help car make turns more softly
Answer:
yes
Explanation:
banked curve :
is a road that looks like the top part of a race track
its looks elevated
often seen in bicycle race track (velodrome)
Banking the curve can help keep cars from skidding. When the curve is banked, the centripetal force can be supplied by the horizontal component of the normal force.
sfuca
write any three uses of solution in our daily life
Answer:
इअग्सिव्ह्ह्व्य्वुव्व्ह्विहेधेइएह
Explanation:
ह्य्स्स्येउ?स्य्ग्स्झ्स
What is the current in a 10 ohm resistor ?
Answer:
c option 22.0A
Explanation:
V=IR
I=R/V
What type of resistance training equipment has a fixed range of motion? Chains Resistance bands Free weights Weight machines
Chains are the type of resistance training equipment which has a fixed range of motion.
What is Resistance?This is a type of force which restricts the motion of an object thereby slowering it down.
Chains help to build stamina and power though varying the loads in a fixed range of motion. This is why it was chosen as the most appropriate choice.
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Some of the lowest pitches attainable on a musical instrument are achieved on the world's largest pipe organs. What is the length of an organ pipe that is open on both ends and has a fundamental frequency of 8.75 Hz when the speed of sound in air is 341 m/s
The length of an organ pipe is 19.48
Given,
An organ pipe that is open on both ends and has a fundamental frequency of n1 = 8.75Hz & the speed of sound in air is v = 341m/s
we have the formula for fundamental frequency in open pipe as
n1 = v /λ1 = v / 2L
so L = v / 2n1
plug in the values for L
n1 = v / λ1 = v / 2L
L = v / 2n1
= 341 / 2 (8.75)
= 19.48
The length of an organ pipe is 19.48
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A wave traveling in a string has a wavelength of 35 cm, an amplitude of 8. 4 cm, and a period of 1. 2 s. What is the speed of this wave?.
0.29 m/s is the speed of this wave.
How can we determine a wave's speed?
Given: The wave's traveling wavelength is () = 35 cm
The wave's period (t) is 1.2 seconds.
The wave's frequency is 0.833 Hz.
We must ascertain a wave's wave speed.
Formula for wave speed is 35 x 0.833 (wavelength x frequency).
= 29.167 cm/sec
= 0.29 m/sec
As a result, the wave's speed is 0.29 m/s.
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The deflection angle of the laser beam as it exits the prism is 22. 6º. If the prism had been made of glass instead of polystyrene plastic, what would the deflection angle have been?.
In creating an accurate scale model of our solar system, Lana placed Earth 1 foot from the Sun. The actual distance from Earth to the Sun is 93,000,000 miles. If the actual distance from Pluto to the Sun is 3,695,950,000 miles, how far from the Sun would Lana need to place Pluto in her model
Pluto would be placed 39.74 feet far from the Sun.
Astronomers use the gap between Earth and the sun, which is ninety-three million miles, as a new unit of measure called the Astronomical Unit.
Map scale refers to the connection (or ratio) between the space on a map and the corresponding distance on the ground. For example, on a 1:one hundred thousand scale map, 1cm at the map equals 1km on the ground.
The distance between the earth and solar, a = around 150 million km, is defined as one Astronomical Unit (AU). The radius of the solar, the solar is around 700,000 km.
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A pendulum can be simply made of a suspended string tied to a weight. If the length of string is measured to be 1 m and the weight is measured to be 0.5 kg, determine its period of oscillation and its frequency of oscillation. Does its period depend on the weight tied to the string?
The time period of the pendulum is 2 sec, and the frequency will be 0.5 and will on depend on weight of the object.
The time period of a basic pendulum is defined as the time it takes to complete one full oscillation and is indicated by the letter "T".
This concept of frequency leads to the simplest frequency formula
Frequency = 1 / T.
T signifies the time it takes to complete one wave cycle in seconds, while f denotes frequency.
The formula for time period of simple pendulum is
Time Period = 2π√(l/g)
As we can see there is no mass term in the formula, Hence we can say that the time period of simple pendulum will not depend on mass or weight of the object tied to the string.
We have given length as 1 m
Time Period = 2π√(1/9.8)
Time Period = 2π×0.319
Time Period = 2 seconds
Time of the Simple Pendulum is 2 seconds.
Frequency = 1 / Time period
Frequency = 1 / 2
Frequency = 0.5 1/second
Frequency of the Simple Pendulum is 0.5
So we can conclude that the Time period of Simple pendulum is 2π√(l/g) and as we can see there is no term of mass, means the simple pendulum will not be depend on mass or weight. The time period came out to be 2 seconds and the frequency came out to be 0.5.
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Anybody else play genshin??
I’m bored and don’t feel like doing hw (also my ar is 24 )
Answer:
no sorry
Explanation:
Answer:
yes i play genshin
Explanation:
ignore how this is a year late...what server r u on ?im on america and europe!!!!!!!!!!!!(≧∇≦)
A bar is 20 cm long. a 100 g mass is placed on one end and a 150 g mass on the other. where is the balance point of the bar.
The balance point of the bar from the 100 g mass is 12 cm.
Balanced point of the barApply principle of moment as follows;
Let the balance point from 100 g mass = x
Clockwise moment = anti clockwise moment
100x = 150(20 - x)
100x = 3,000 - 150x
250x = 3000
x = 3000/250
x = 12 cm
Thus, the balance point of the bar from the 100 g mass is 12 cm.
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A driver, traveling at 22.0 m/s, slows down her car and stops. What work is done by the friction force against the wheels if the mass of the car is 1500 kg? Group of answer choices -3.6 x 105 joules None of the above 3.6 x 106 joules -4.5 x 106 joules 4.5 x 105 joules
-3.6× 10^5J is the Work done by friction force
Work done = force × distance
v^2 = u^ +2as
u= 22m/s
a =10m/s^2
When the car stops the final velocity (v) =0
0= 22^2 +2×10×s
s = -484/20
s =-24.2m
Work done = force × distance
Force = mass × acceleration
Work done = 1500×10× -24.2
= -3.6×10^5J
Hence the Work done is -3.6×10^5J
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4 . A negative charge -0.450 exerts an upward 0.150N force on an unknown charge 0.250m directly below it . ( a ) what is the unknown charge ( magnitude and sign ) ? ( b ) what are the magnitude and direction of the force that the unknown charge exert charge exerts on the -0.450 charge ?
(a) The unknown charge kept at distance 0.250m directly below -0.450 charge is 2.315 x 10⁻¹² C.
(b) The magnitude of the force is 29.16 x 10¹² N.
What is electrostatic force?The electrostatic force F between two charged objects placed distance apart is directly proportional to the product of the magnitude of charges and inversely proportional to the square of the distance between them.
F = kq₁q₂/r²
where k = 9 x 10⁹ N.m²/C²
Given is a negative charge -0.450 exerts an upward 0.150N force on an unknown charge 0.250m directly below it .
In equation of the magnitude of force, only the magnitude of charges are taken.
Substituting the values into the expression ,we get the charge
0.150 = (9 x 10⁹ x 0.450x q)/ (0.25)²
q = 2.315 x 10⁻¹² C
Thus, the magnitude of the unknown charge is 2.315 x 10⁻¹² C.
b)Let the unknown charge be 0.450C to exert on -450C.
Substituting the values into the expression ,we get the electrostatic force
F = kq₁q₂/r²
F = (9 x 10⁹ x 0.450x 0.450)/ (0.25)²
q = 2.315 x 10⁻¹² C
Thus, the magnitude of the force is 29.16 x 10¹² N.
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what are the types of waves
Most interstellar clouds are: Most interstellar clouds are: much bigger than our solar system. similar in size to clouds in Earth's atmosphere. about the size of Earth. about the size of a wavelength of light. much smaller than the clouds in Earth's atmosphere.
Answer:
Most interstellar clouds are much bigger than our solar system.
Explanation:
An interstellar cloud refers:
It is generally an accumulation of gas, plasma, and dust in our and other galaxies. It is basically a denser-than-average region of the interstellar medium (ISM).Interstellar clouds can be large up to 106 solar masses
It is also often said to be the most massive entities in the galaxy.
Hence
we can say about Interstellar clouds,
They are much bigger than our solar system.
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Only 25% of the intensity of a polarized light wave passes through a polarizing filter. What is the angle between the electric field and the axis of the filter
Answer: Only 25% of the intensity of a polarized light wave passes through a polarizing filter. Then the angle between the electric field and the axis of the filter will be 60 degrees.
Explanation: To find the answer of the problem given, we have to know about the Malu's law of polarization.
What is Malu's law of polarization?This law states that, when a beam of completely polarized light is passed through an analyzer, then then intensity I of the transmitted light varies directly as the square of the angle [tex]\alpha[/tex] between the transmission direction of the polarizer and the analyzer.The expression for this law will be,[tex]I=I_0cos\alpha[/tex]
Where, I₀ is the maximum intensity of the transmitted light through the polarizer.How to solve the problem?From the question, it is clear that, the 25% of the intensity of a polarized light wave passes through the filter.[tex]\frac{I}{I_0} =0.25\\[/tex]
Thus, the angle between electric field and the axis of the filter is,[tex]cos^2\alpha =0.25\\cos\alpha =\sqrt{0.25} =0.5\\\alpha =cos^-1(0.5)=60 degrees[/tex]
Thus, we can conclude that, the angle between the electric field and the axis of the filter will be 60 degrees.
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A student is conducting an experiment that involves adding hydrochloric acid to various minerals to detect if they have carbonates in them. the student holds a mineral up and adds hydrochloric acid to it. the acid runs down the side and onto the student’s hand causing irritation and a minor burn. if they had done a risk assessment first, how would this situation be different?
If they had done a risk assessment first "The student would have no injuries because he would know hydrochloric acid is dangerous and would be wearing gloves when using it"
What is hydrochloric acid?An aqueous solution of hydrogen chloride HCl that is a strong corrosive irritating acid, is normally present in dilute form in gastric juice, and is widely used in industry and in the laboratory.
Maintain a safe distance between your hands and your body, mouth, eyes, as well as a face when utilizing lab supplies and chemicals.
If they had done a risk assessment first "The student would have no injuries because he would know hydrochloric acid is dangerous and would be wearing gloves when using it"
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A 12.5 g clothesline is stretched with a tension of 22.1 n between two poles 7.66 m apart. the frequency of the fundamental and the second harmonic are 7.60 hz and 15.2 hz respectively.
(a) Fundamental frequency of clothesline is 6.98Hz.
(b) Frequency of second harmonic is 13.98Hz.
The wave velocity expression is,
v = √T / √μ
here, T is tension μ is mass per unit length
v = √22.1 / √(12.5×10⁻³/7.66)
v = 116.37 m/s
For the fundamental frequency,
v = fλ
116.37 m/s= 7.6 ×λ
λ = 15.31 m
For the second Harmonic,
λ₂= v/ f₂ = 116.37 / 15.2 = 7.66 m
Now consider mass is increased
μ= 14.8 × 10⁻³ / 7.66
v = √T / √μ
v = √22.1 / √14.80 × 10⁻³/7.66
v = 106.95 m/s
Fundamental harmonic,
f₁ = v/λ₁ = 106.95 / 15.31 = 6.98 Hz
f₂= v/ λ₂ = 106.95 / 7.65 = 13.98 Hz
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[Your question is incomplete, but most probably your full question was-
a) What is the frequency of the fundamental harmonic for a clothesline with a mass of 14.8 g?
(b) What is the frequency of the second harmonic for a clothesline with a mass of 14.8 g?]
10) What is the total energy of a 450-g mass that is attached to a horizontal spring with a force constant of 260 N/m and oscillates along a frictionless horizontal surface with amplitude of 8.0 cm
Answer:
E = 1/2 * k x^2 is the energy stored in the spring
E = 1/2 * 260 N/m * .08^2 m = .832 Joules
Pls give full explanation!
1. The part that shows the body is accelerating is the first 2 hours (ABE). The acceleration is 20 Km/h²
2. The part that shows the body is coming to rest the last 2 hours (CDF)
3. The distance travelled in the first 2 hours is 40 Km
1. How to determine the accelerated motionAcceleration is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
a is the acceleration v is the final velocity u is the initial velocity t is the timeFrom the diagram (ABE), we can see that the body starts from rest and attain a final velocity (40 Km/h) within the first 2 hours. This clearly indicates that the body is accelerating.
The acceleration can be obtained as followed:
Initial velocity (u) = 0 Km/hFinal velocity (v) = 40 Km/hTime (t) = 2 hoursAcceleration (a) = ?a = (v – u) / t
a = (40 – 0) / 2
a = 20 Km/h²
2. How to determine the part showing the body is coming to restFrom the diagram (CDF), we can see that the object velocity changes from 40 to 0 within the last 2 hours. This clearly indicates that the object caming to rest.
3. How to determine the distance travelled in the first 2 hours Initial velocity (u) = 0 Km/hFinal velocity (v) = 40 Km/hTime (t) = 2 hoursAcceleration (a) = 20 Km/h²Distance (s) = ?v² = u² + 2as
v² = 2as
s = v² / 2a
s = 40² / (2 × 20)
s = 40 Km
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A box weighing 660 N is sliding across a cement floor and the coefficient of sliding
friction between the box and the floor is 0.15. What is the frictional force?
09g
O 4,400 N
0 99 N
O 99 kg
The Frictional force is 99 N; option C.
What is the frictional force?The frictional force between the floor and the surface is calculated as follows:
Frictional force = coefficient of friction * normal reaction
Frictional force = 660 * 0.15
Frictional force = 99 N
In conclusion, the frictional force is determined from the coefficient of friction and the normal reaction of the box on the floor.
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When sound waves superimpose they can interfere?
Answer:
Explanation:
When two waves of similar frequency arrive at the same point and superimpose, they alternately constructively and destructively interfere. This alternating is known as a beat because it produces an unpleasant pulsing sound
A backpack has a mass of 8 kg. It is lifted and given 54.9 J of gravitational
potential energy. How high is it lifted? Acceleration due to gravity is g = 9.8
m/s2
The height is 0.70 meters
The formula for gravitational potential energy is
= mgh
m= mass, g= acceleration due to gravity, h= height
54.9= 8 × 9.8 × h
54.9= 78.4h
h= 54.9/78.4
= 0.70 meters
Hence the height at which the bacpack was lifted is 0.70 meters
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Answer:
its 0.7m
Explanation:
A sled having a certain initial speed on a horizontal surface comes to rest after traveling 20 m. If the coefficient of kinetic friction between the object and the surface is 0.20, what was the initial speed of the object
The initial speed of the object was 6.26 m/s.
Acceleration of the sled, a = -g*μk
= -9.8*0.2
= -1.96 m/s^2
Let u is the initial speed and v is the final speed.
Applying, v^2 - u^2 = 2*a*d
0^2 - u^2 = 2*(-1.96)*10
u = sqrt(2*1.96*10)
= 6.26 m/s
The kinetic friction coefficient μok is the ratio of the friction force to the normal pressure experienced by a body moving on a dry, non-easy floor. The determination of μok may be achieved quite appropriately through an alternative creative mechanism described with the aid of Timoshenko
The coefficient of friction (fr) is quite a number that is the ratio of the resistive force of friction (Fr) divided with the aid of the everyday or perpendicular force (N) pushing the items collectively. it is represented by the equation: fr = Fr/N.
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A dipole with its charges,-q and +q located at the points (0,-b,0) and (0+b,0) is present in uniform electric field E whose equipotential surfaces are planes parallel to the YZ planes.
The direction of the electric field based on the information given about the dipole is along the x axis.
What is a dipole?It should be noted that a dipole simply means a pair of opposite charges that are separated by a distance.
By default, the direction of the dipole is always from the negative charge -q to the positive charge q.
In this case, since the equipotential surfaces are planes parallel to the YZ planes., the direction of the electric field is along the x axis.
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Complete question:
A dipole with its charges,-q and +q located at the points (0,-b,0) and (0+b,0) is present in uniform electric field E whose equipotential surfaces are planes parallel to the YZ planes.
What is the direction of the electric field?
What is the amount of matter in a substance?
Answer:
mass
Explanation:
Mass (M) is the measure of the amount of matter in an object. Mass is measured in grams (g). Mass is measured on a balance by comparing the object against other objects with known masses.
Answer:
Mass is the amount of matter in a substance
what is forward and downward speed
Forward and downward speed are referred to as acceleration and deceleration respectively.
What is Acceleration?This is the rate at which an object gains speed with respect to time with its unit being meter per second square(m/s²).
Objects in constant speed are said to have a uniform motion. The downward speed is known as deceleration which involves the object losing speed to return to a state of rest.
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