Answer:
d because it incresed by 50binstead of 13 12 and 23 percent
I’m in need of help I have 7 questions
Goodluck
Step-by-step explanation:
I need Help Please??????
Answer:
54
Step-by-step explanation:
the ladder need to be 54 feet high
Express 0.00010000100011000 in standard form
Step-by-step explanation:
think it is 1.0000100011000 x10 rise the power negative 3
PLS HELP THIS IS DUE TMRW AND I DON’T UNDERSTAND IT!!
Answer:
Step-by-step explanation:
Just make an example
Is this a question? Please hurry!
Answer:
yes bti dsnin s
Step-by-step explanation:
A bird flies at an altitude of 520 feet. A diver dives to a depth of 50 feet below sea level. What is the difference in their elevations? Show how you arrived at your answer.
Answer:
The answer is 570 feet.
Step-by-step explanation:
First, the bird is 520 feet HIGH.
The diver is 50 feet BELOW sea level, which is also -50.
To find the difference, you would SUBTRACT right?
So 520 - -50 OR 520 + 50 (This is because two negatives make a positive, and you are also subtracting negatives, which in turn means adding).
520 + 50 = 570 - HOPE THIS HELPED!
4+ (-7) is. Blank units from 4, in the Direction what will the answer be ? I also
Have : -3 + 5
And: -2 + -6
I just need to find the sum of each Answer and distance
4+(−7) is 7 units from 4, in the negative direction (that is, to the left of 4)
4 + (-7) is 7 (seven) units from 4, in the negative Direction.
The result of 4 + (-7) is -3. It represents a movement of 7 units in the negative direction from the starting point of 4.
In this context, "units" refer to a number-line, where positive values are to the right and negative values are to the left. Starting at 4 and moving 7 units to the left brings you to -3.
This calculation and explanation describes the concept of adding a negative value, which is equivalent to subtracting a positive value, resulting in a displacement in the specified direction on the number line.
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The given question is incomplete, the complete question is
4 + (-7) is _____ units from 4, in the _____ Direction. What will the answer be?
What is the domain of the relation shown
on the graph?
Answer:
where is the graph?........
The random-number generator on calculators randomly generates a number between 0 and 1. The random variable X, the number generated, follows a uniform probability distribution.
(a) Identify the graph of the uniform density function.
(b) What is the probability of generating a number between 0.01 and 0.34?
(c) What is the probability of generating a number greater than 0.95?
Using the uniform distribution, we have that:
a) The graph is sketched at the end of this answer.
b) 0.33 = 33% probability of generating a number between 0.01 and 0.34.
c) 0.05 = 5% probability of generating a number greater than 0.95.
An uniform distribution has two bounds, a and b.
The probability of finding a value between c and d is:
[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]
The probability of finding a value above x is:
[tex]P(X > x) = \frac{b - x}{b - a}[/tex]
In this problem, uniformly distributed between 0 and 1, thus [tex]a = 0, b = 1[/tex].
Item b:
[tex]P(0.01 \leq X \leq 0.34) = \frac{0.34 - 0.01}{1 - 0} = 0.33[/tex]
0.33 = 33% probability of generating a number between 0.01 and 0.34.
Item c:
[tex]P(X > 0.95) = \frac{1 - 0.95}{1 - 0} = 0.05[/tex]
0.05 = 5% probability of generating a number greater than 0.95.
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I really need help plzzzzz
Answer:
-28
Step-by-step explanation:
Answer:
the answer is -28
Step-by-step explanation:
-8 x 7 / 1 x 2
= 56 / 2
Help me please:) ✨✨✨✨✨✨✨✨✨✨
Hello there I think the measure of EBC is 58 degrees.
That's because angles EBC and DBE are complementary. it means that they add up to 90 degrees.
We are given that
DBE=32 degrees.
And we know that angles EBC and DBE add up to 90 degrees.
So we take 90 and subtract the measure of angle DBE (32 degrees)
90-32=58
Hope this helps!
[tex]GraceRosalia[/tex]Lim x-> vô cùng ((căn bậc ba 3 (3x^3+3x^2+x-1)) -(căn bậc 3 (3x^3-x^2+1)))
I believe the given limit is
[tex]\displaystyle \lim_{x\to\infty} \bigg(\sqrt[3]{3x^3+3x^2+x-1} - \sqrt[3]{3x^3-x^2+1}\bigg)[/tex]
Let
[tex]a = 3x^3+3x^2+x-1 \text{ and }b = 3x^3-x^2+1[/tex]
Now rewrite the expression as a difference of cubes:
[tex]a^{1/3}-b^{1/3} = \dfrac{\left(a^{1/3}-b^{1/3}\right)\left(a^{2/3}+a^{1/3}b^{1/3}+b^{2/3}\right)}{\left(a^{2/3}+a^{1/3}b^{1/3}+b^{2/3}\right)} \\\\ = \dfrac{a-b}{a^{2/3}+a^{1/3}b^{1/3}+b^{2/3}}[/tex]
Then
[tex]a-b = (3x^3+3x^2+x-1) - (3x^3-x^2+1) \\\\ = 4x^2+x-2[/tex]
The limit is then equivalent to
[tex]\displaystyle \lim_{x\to\infty} \frac{4x^2+x-2}{a^{2/3}+(ab)^{1/3}+b^{2/3}}[/tex]
From each remaining cube root expression, remove the cubic terms:
[tex]a^{2/3} = \left(3x^3+3x^2+x-1\right)^{2/3} \\\\ = \left(x^3\right)^{2/3} \left(3+\dfrac3x+\dfrac1{x^2}-\dfrac1{x^3}\right)^{2/3} \\\\ = x^2 \left(3+\dfrac3x+\dfrac1{x^2}-\dfrac1{x^3}\right)^{2/3}[/tex]
[tex](ab)^{1/3} = \left((3x^3+3x^2+x-1)(3x^3-x^2+1)\right)^{1/3} \\\\ = \left(\left(x^3\right)^{1/3}\right)^2 \left(\left(3+\dfrac3x+\dfrac1{x^2}-\dfrac1x\right)\left(3-\dfrac1x+\dfrac1{x^3}\right)\right)^{1/3} \\\\ = x^2 \left(9+\dfrac6x-\dfrac1{x^3}+\dfrac4{x^4}+\dfrac1{x^5}-\dfrac1{x^6}\right)^{1/3}[/tex]
[tex]b^{2/3} = \left(3x^3-x^2+1\right)^{2/3} \\\\ = \left(x^3\right)^{2/3} \left(3-\dfrac1x+\dfrac1{x^3}\right)^{2/3} \\\\ = x^2 \left(3-\dfrac1x+\dfrac1{x^3}\right)^{2/3}[/tex]
Now that we see each term in the denominator has a factor of x ², we can eliminate it :
[tex]\displaystyle \lim_{x\to\infty} \frac{4x^2+x-2}{a^{2/3}+(ab)^{1/3}+b^{2/3}} \\\\ = \lim_{x\to\infty} \frac{4x^2+x-2}{x^2 \left(\left(3+\dfrac3x+\dfrac1{x^2}-\dfrac1{x^3}\right)^{2/3} + \left(9+\dfrac6x-\dfrac1{x^3}+\dfrac4{x^4}+\dfrac1{x^5}-\dfrac1{x^6}\right)^{1/3} + \left(3-\dfrac1x+\dfrac1{x^3}\right)^{2/3}\right)}[/tex]
[tex]=\displaystyle \lim_{x\to\infty} \frac{4+\dfrac1x-\dfrac2{x^2}}{\left(3+\dfrac3x+\dfrac1{x^2}-\dfrac1{x^3}\right)^{2/3} + \left(9+\dfrac6x-\dfrac1{x^3}+\dfrac4{x^4}+\dfrac1{x^5}-\dfrac1{x^6}\right)^{1/3} + \left(3-\dfrac1x+\dfrac1{x^3}\right)^{2/3}}[/tex]
As x goes to infinity, each of the 1/x ⁿ terms converge to 0, leaving us with the overall limit,
[tex]\displaystyle \frac{4+0-0}{(3+0+0-0)^{2/3} + (9+0-0+0+0-0)^{1/3} + (3-0+0)^{2/3}} \\\\ = \frac{4}{3^{2/3}+(3^2)^{1/3}+3^{2/3}} \\\\ = \frac{4}{3\cdot 3^{2/3}} = \boxed{\frac{4}{3^{5/3}}}[/tex]
Find the sum of the following fractions. Your answer needs to be a mixed number in simplest form: 4/5 + 2/9
Answer:
1 1/45
Step-by-step explanation:
6 1/3 - 4 1/9
I need help again
Answer:
2.222
Step-by-step explanation:
Hope this helps :)
Pls make brainliest :3
And have an amazing day <3
Answer:
2 2/9
Step-by-step explanation:
so if we want to be able to substract, we're gonna multiply the 1/3 times three so the result come out to 3/9 and now we are able to substract, so 6 3/9 - 4 1/9 is equal to 2 2/9
QUESTION 10
2 points
Save Answer
When looking at her grades, Susan found that she scored a combined 258 points on her first three tests. She also noticed that on tests two and three, she
scored 10 points fewer than the test before.
Write an equation that fits this problem.
Answer:
(258÷3) - 10 = 76.
Step-by-step explanation:
You need to use this equation to find this answer even though I already wrote the answer there for you.
tan(-50)=
a. -tan50
b. tan40
c. tan50
- tan(50) → Choice A
Step-by-step explanation:
tan(-α) = - tan(α)
tan(-50) = - tan(50)
Further more :
tan (-50) = - tan (50) ≈ 0,27
Consider a hypothetical consumer named Hayden who is shopping for bread and brie. The graph with bread and brie on the axes presents the utility‑maximizing combinations of bread and brie that Hayden chooses when the price of bread is $1.00 per loaf and the price of brie is $4.00 and $6.00 per wheel, respectively. The other graph shows Hayden's demand curve for brie.
The two points and associated values in the graph for bread and brie combinations correspond to points A and B in the graph of the demand curve for brie. What are the specific prices and quantities of brie associated with points A and B on Hayden's demand curve?
The graphical relationship of the demand and price of brie are given in the two graphs
At point A, the price is $4.00 and the quantity demanded is 23.84At point A, the price is $6.00 and the quantity demanded is 7.49Reason:
The given parameters are;
The graphs gives the utility-maximizing combinations of bread and brie chosen by Hayden
The price of the loaf = $1.00
The prices of the brie are $4.00 and $6.00 per wheel
Given that as the price increases from $4.00 to $6.00, the quantity
demanded increases, we have;
When the price is $4.00, the quantity of brie demanded 23.84 brie wheels,
and the quantity of bread demanded is 15.9 bread loaves
When the price increases to $6.00, the quantity of brie demanded
decreases to 7.49 brie wheels, while the quantity of bread demanded
increases to 25.2 loaves
Therefore; we have;
At point A, the price is $4.00 and the quantity demanded is 23.84
At point B, the price is $6.00 and the quantity demanded is 7.49
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graph the line through (-3,1) with slope 3/2
Answer:
Pencil on y: 5.5 then 3 down and 1 to the right. (You can trace a line with 2 points, but can continue the pattern: 3 down, 1 to the right)
Step-by-step explanation:
y- intercept = 1 - (3/2)(-3)
y-intercept = 1 + 9/2 = 11/2 = 5.5
y = 3/2x + 11/2
the ratio of hours to miles on a bicycle is 2 hours to 30 miles at this rate, how many miles can the bicycle travel in 4 hours? *Think about equivalent ratios.
Answer:60 miles.
Step-by-step explanation:
m=number of miles the bicycle can travel in 4 hours.
Set up a ratio of hours over miles.
2/30=4/m. Multiply both sides by m. (2m)/30=4. Multiply both sides by 30. 2m=120. M=60. You could also just realize that you are multiplying the numerator by 2 of the fraction 2/30 to get 4/m, so you would also have to multiply the denominator by 2 so that both of the fractions are equivalent. So then you’d just multiply the bottom by 2 to get the miles the bike travels in 4 hours.
The vertices of a triangle are P(-8, 6), Q(1, -3), and R(-6, -3). Name the image of P after a reflection over y = 2, and
then shifted right 3 units.
Transformation involves changing the location of a shape
The image of P after the transformation is: (-5,-2)
The vertices are given as:
[tex]\mathbf{P = (-8,6)}[/tex]
[tex]\mathbf{Q = (1,-3)}[/tex]
[tex]\mathbf{R = (-6,-3)}[/tex]
The rule of reflection across line y = 2 is:
[tex]\mathbf{(x,y) \to (x,4-y)}[/tex]
So, the image of P, after the reflection is:
[tex]\mathbf{P' = (-8,4-6)}[/tex]
[tex]\mathbf{P' = (-8,-2)}[/tex]
The rule of translation 3 units right is:
[tex]\mathbf{(x,y) \to (x + 3,y)}[/tex]
So, we have:
[tex]\mathbf{P" = (-8 + 3,-2)}[/tex]
[tex]\mathbf{P" = (-5,-2)}[/tex]
Hence, the image of P after the transformation is: (-5,-2)
Read more about transformations at:
https://brainly.com/question/13801312
What is the product of -2 1/2 and 3 1/3 ?
Step-by-step explanation:
Hope this helps you ☺️☺️
HELP ME ASAPPPP I HAVE 12 MIN LEFT
Answer:
The sum is about 22
Step-by-step explanation:
When you round the values at the ones place, you get:
7 + 6 + 9 = 22
Answer:22
Step-by-step explanation:
You buy cauliflower at $18 per pound. One portion of cauliflower requires 6 ounces of cauliflower. How much does the cauliflower for one portion cost?
The cauliflower for one portion cost $6.75.
The first step is to convert pounds to ounces. The unit of conversion of pounds to ounces is 1 pound is equivalent to 16 ounces.
1 pound = 16 ounces
Therefore, 16 ounces of cauliflower costs $18.
The cost of one ounce = 18 / 16 = $1.125
The cost of one portion of cauliflower is:
Cost of one ounce x number of ounces in one portion
$1.125 x $6 = $6.75
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how do you determine where to place the decimal point in the product
Answer:
Bro it is simple,see when the 2 numbers are multiplying in 1st number decimal is before 2 digits and in 2nd number decimal is before 1 digit and in product decimal is before 3 digits so to place the decimal you need to + the digits afer decimal of numbers eg. in 0.43 there are 2 digits afer decimal and in 0.2 there is 1 digit after decimal and in answer there are 3 digits after decimal
Step-by-step explanation:
If you like my answer than please mark me brainliest thanks
Answer: SEE BELOW
Step-by-step explanation:
Decimals are multiplied as if they were whole numbers, and then the decimal point is placed in the product. To find out where the decimal point should be placed, count the number of decimal places after the decimal point in each factor.
0.43......... 2 decimal place(s) Add your decimal places = 3
0.2......... 1 decimal place(s)
0.086 Place decimal 3 decimal places in answer like so.
hope this helps you! Smile ; )
Guys be quick please and thank uuuu 2x^2+ 8x + 3
Answer:
2x^2 + 8x + 3
Step-by-step explanation:
The expression is not factorable with rational numbers.
Plz help me thank you
Answer:
159.29-159.29(5/100)=151. 3255
Question 3 and 4 need help
[tex]\large\underline{\sf{Solution-}}[/tex]
#1
Solving by submitting method:
[tex]\sf \leadsto 5x - 4y = 9 \: \: - - - (i)[/tex]
[tex]\sf \leadsto x - 2y = -3 \: \: - - - (ii)[/tex]
By first equation,
[tex]\sf \leadsto 5x - 4y = 9[/tex]
[tex]\sf \leadsto 5x = 9 + 4y[/tex]
[tex]\sf\leadsto x = \frac{9+4y}{5}\\[/tex]
Now, we can find the original value of y from Eqⁿ (ii).
[tex]\sf \leadsto x - 2y = -3[/tex]
[tex]\sf \leadsto \bigg(\frac{9+4y}{5}\bigg) - 2y = -3\\[/tex]
[tex]\sf \leadsto \frac{9+4y-10y}{5} = -3\\[/tex]
[tex]\sf \leadsto \frac{9-6y}{5}= -3\\[/tex]
[tex]\sf \leadsto 9-6y = -3(5)[/tex]
[tex]\sf \leadsto 9 -6y = - 15[/tex]
[tex]\sf \leadsto -6y = - 15 - 9[/tex]
[tex]\sf \leadsto -6y = -6[/tex]
[tex]\sf \leadsto y = \frac{\cancel-6}{\cancel-6}\\ [/tex]
[tex]\sf \leadsto y = \dfrac{ 6}{ 6} \\[/tex]
[tex]\sf \leadsto y = 1[/tex]
Now, we can find the original value of x , from Eqⁿ (I)
[tex]\sf \leadsto 5x-4y = 9[/tex]
[tex]\sf \leadsto 5x - 4(1) = 9[/tex]
[tex]\sf \leadsto 5x - 1 = 9[/tex]
[tex]\sf \leadsto 5x = 9+1[/tex]
[tex]\sf \leadsto 5x = 10[/tex]
[tex]\sf \leadsto x = \frac{10}{5}\\[/tex]
[tex]\sf \leadsto x = 5[/tex]
Therefore, the values of x and y are 5 and 1 respectively.
#2
Solving by Eliminating method:
[tex]\sf \leadsto 4x + 6y = 12\:\:- - - (i)[/tex]
[tex]\sf \leadsto 6x+9y = 12 \:\: - - -(ii)[/tex]
Step 1: Multiply Eqⁿ (I) by 3 and Eqⁿ (ii) by 2 to make the coefficients of y equal. Then we get the equations.
[tex]\sf \leadsto 12x + 18y = 36\:\: - - - (iii) [/tex]
[tex]\sf \leadsto 12x + 18y = 24\:\:- - - (iv)[/tex]
Step 2: Subtract Eqⁿ (iii) from Eqⁿ (iv) , we get
[tex]\sf \leadsto (12x + 18y)-(12x + 18y) = 36-24[/tex]
[tex]\sf \leadsto 0 =12, Which is a false statement. [/tex]
Therefore, the pair of equations has no solution.
Hope this helps!!
A submarine starts its descent at -15 meters.
It dives to -182 meters. How far did the
submarine descend?
Since it started at -15 and went to -182 i subtracting to see how far it descended I ended up with 162, however I'm not sure if subtraction was the write operation in this problem, please correct me : )
Answer:
so we're dealing with negative numbers here so after learning negative numbers you have to add negative15 to -182 Wich is negative 197
y = 2x + 4
y = 2x + 4
y = -1/4x + 2
y = -1/4x + 2
y = -1/4x + 2
yeah
that's it
Answer:
1. 2x + 4= slope: 2 | y intercept: (0,4)
2. 2x + 4= slope: 2 | y intercept: (0,4)
3. -1/4x + 2= slope: -1/4 | y intercept: (0,2)
4. -1/4x + 2= slope: -1/4 | y intercept: (0,2)
18x + 4
17x + 11
Select the equation you would use to solve for x.
18x + 17x + 11 + 4 = 180
0 18x + 17x = 11 + 4
18x + 4 = 17x + 11
the answer would be c because the angles are equal to each other