Which of these equations describe a line that is parallel to the y-axis, and passes through (-2.3) A. y=-2x+3 B. Y=3 C. X= -2 D. x=3

We know that

1 m = 100 cm

Then to change from meter to centimeter, multiply by 100

Since the tree in Bob's backyard is 8.5 m

Then to change it to cm, multiply 8.5 by 100

The height of the tree is 850 cm

EXPLANATION

Since we have four given scenarios, the only viable option is the third one because It's the only statement where we take a sample (1000 individuals of 1883 participants).

Answer:

[tex]\frac{-5}{2}[/tex]

Step-by-step explanation:

There are two blue dots on the graph.  It does not matter which dot you startr at.  Let's start at the bottom, right dot.  How many space up and to the left you do you have to move to get to the second dot?

You need to move 5 dots straight up.  Up is a positive direction.  Then you have to move 2 spaces left.  Left is a negative direction, so your slope will be negative.

- [tex]\frac{5}{2}[/tex]            [tex]\frac{-5}{2}[/tex]           [tex]\frac{5}{-2}[/tex]   All of these mean the same thing.

In the first case the equation has only one unique solution and in the second case the equation has many solutions.

We are given the equation a|x + b| + c = d and we need to determine the solution of this equation when a > 0 and c = d. The equation contains absolute value symbol which always gives a positive value. The equation can be written as

a|x + b| + c = d

a|x + b| = d - c, since c = d then we can write equation as

a|x + b| = 0, Now, a > 0

=> |x + b| = 0

=> x = -b that is only one unique solution.

Now, in second case a < 0 and c > d then

a|x + b| = d - c

If c > d, then the left-hand side of the equation becomes negative and also a < 0 so the right-hand side also becomes negative. So, the equation will have many solutions in this case.

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Answer:

−1≤x<3

Step-by-step explanation:

−4≤3x−1<8

−4≤3x−1and3x−1<8

3x−1≥−4and3x−1+1<8+1

3x≥−3and3x<9

x≥−1andx<3

−1≤x<3

The common difference in the given arithmetic sequence is 8.

So, formula for common differences:

Now, insert terms in the formula as follows:

Therefore, the common difference in the given arithmetic sequence is 8.

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Answer:

6[tex]x^{2}[/tex]y

Step-by-step explanation:

If I ready your explanation correctly it is

2x3xy  We multiply the 2 and 3 and the xx would be [tex]x^{2}[/tex]

Answer:  3 ≥ W > -5

Step-by-step explanation:

Just look at the way the question is asked, that is the best I can explain. Sorry.

Answer: $-75

Step-by-step explanation:

She took out money therefore the balance will go down. If we take 43 dollars from $-32 then we will get -75.

For the following relations, using the condition for a relation to represent a function, we have that:

A relation represents a function if each value of the input is mapped to only one value of the output, that is, one input cannot be mapped to multiple outputs.

The input may also be called domain, while the output may also be called range.

For a point in the standard format (x,y), we have that:

Hence, in the context of this problem, we have that:

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In linear relationship, 199.333 million dollers per year is the percent growth rate.

What is linear relationship in math?

Given , t Rs numbers of year since 1997 .

t = 0 corresponds to year 1997

t = 6 corresponds to year 2003

Let  s(t) = sales of the year

So, given that

 sales in 19997 is  $2503 millions

so    s(0) = 2503  million dollers

Sales in 2003 is $3699 millions

so  s(6) = 3699  million dollers

Now apply formula of linear relation ship

               s - s(0) = s(6) - s(0)/6 - 0 ( t - 0)

               s - 2503 = 3699 - 2503/6 (t)

                s = 1196* t /6 + 2503

  so         s(t) = 598t/3 + 2503

 so now average rate of change of function over on interval is given by

                 =     s(b) - s(a)/b - a

                 = s(6) -  s( 0)/6 - 0

                 = 3699 - 2503/6

                 = 598/3

                 = 199.333 million dollers per year .

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Here, we want to get the value of x

We can get this by isolating x

We start by bringing like terms together

the multiplication of 2 matrices A and B

a11 a12 a13 ...

a21 a22 a23 ...

a31 a32 a33 ...

...

b11 b12 b13 ...

b21 b22 b23 ...

b31 b32 b33 ...

is

a11×b11+a12×b21+a13×b31+... a11×b12+a12×b22+a13×b32 ...

a21×b11+a22×b21+a23×b31+... a21×b12+a22×b22+a23×b32

a31×b11+a32×b21+a33×b31+... a31×b12+a32×b22+a33×b32

...

in other words, we combine the rows of the first matrix with the columns of the second matrix.

the rows of the result matrix are driven by the rows of the first matrix and the columns of the second matrix.

formally :

we can multiply a m×n matrix only with a n×o matrix.

the number of columns in the first matrix must be equal to the number of rows in the second matrix.

the result matrix is then sized m×o.

the first element (first row first column) of the result matrix is the sum of the products of the elements of the first row of the first matrix with the elements of the first column of the second matrix.

the element in the (x,y) position in the result matrix is the sum of the products of the elements of the xth row of the first matrix with the elements of the yth column of the second matrix.

so, when multiplying 2 2×2 matrices, the condition is automatically fulfilled : m = n = o = 2

ST =

4×0+1×-4 4×4+1×3

-3×0+-2×-4 -3×4+-2×3

=

-4 19

8 -18

and TS =

0×4+4×-3 0×1+4×-2

-4×4+3×-3 -4×1+3×-2

=

-12 -8

-25 -10

as we can see, the 2 results are completely different.

Numerical variables are the subject of quantitative data. Qualitative data can be represented by a name, symbol, or number code and are measures of "types."

Numerical variables are the subject of quantitative data. Qualitative data can be represented by a name, symbol, or number code and are measures of "types." Data concerning categorical variables make up qualitative data.

Quantitative Variables with values obtained through measurement or counting. Variables that exists not measurement variables are referred to as qualitative variables. Their values are not determined by counting or measuring. Values that are used to identify people in a table are called designators. While qualitative research focuses on words and meanings, quantitative research deals with figures and statistics.

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The amount of IRA when he will retire at age 65 = $83448.27

And the total deposits made over the time period is less than the the amount of IRA

We have been given, at age 19​, someone sets up an IRA​ (individual retirement​ account) with an APR of7 ​%. At the end of each month he deposits ​$20.00 in the account.

We need to find the IRA when he retires at age​ 65.

here, 65 - 19 = 46 years

So, the period would be,

46 × 12 = 552 months

Monthly deposit= $20

And the interest rate would be,

Interest = 0.07/12

             = 0.0058

To calculate the future value, we need to use the following formula:

FV= {A × [(1 + i)^n-1]} / i

A= monthly deposit

i = interest rate

n = period

So, the Future Value of Annuity

= 20 × ([1 + 0.0058]^552 - 1 ) / (0.0058)

= 20 × 24.2 / 0.0058

= $83448.27

So, the amount of IRA when he will retire = $83448.27

Deposits made over the time period = 20 × 46 × 12 = $‭11040

Difference = 83448.27 - 11040

= $72408.27

This means, the total deposits made over the time period is less than the the amount of IRA he will get when he retires at age 65.

Therefore, the amount of IRA when he will retire at age 65 = $83448.27

And the total deposits made over the time period is less than the the amount of IRA

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Answer:

  17%

Step-by-step explanation:

You want the percentage represented by a tip of $10.34 on a dinner bill of $61.66.

A percentage is a fraction that has been multiplied by 100%:

  10.34/61.66 × 100%

  ≈ 0.168 × 100%

  ≈ 17%

The tip was about 17% of the original bill.

To solve the given system of equation by graphing you only have to graph both lines. The solution is the intersection between the lines.

According to this, the intersection of the two lines is (-2, -2). It means that the solution is (-2, -2).

Answer:

19

Step-by-step explanation:

-3(-7)-2

21-2

19

it need to be at least 20 chqracters so ignore this the answer is at the top

Answer:

-5x1/2= -2.5 14x1/8= 1.75

Step-by-step explanation:

-2.5+1.75=-0.75

Answer:

-3/4

Step-by-step explanation:

Plug in values of x and y into expression:

[tex]-5(\frac{1}{2})+14(\frac{1}{8})=[/tex]

[tex]-\frac{5}{2} +\frac{14}{8}=[/tex]

Find common denominator:

[tex]-\frac{5*4}{2*4} +\frac{14}{8}=[/tex]

[tex]-\frac{20}{8} +\frac{14}{8}=\frac{14}{8}-\frac{20}{8}=[/tex]

Solve numerator:

[tex]14-20=-6[/tex]

So,

[tex]=-\frac{6}{8}=-\frac{3}{4}[/tex]

If there are 189 children, then there are 189 divided 7 = 27 groups of 7 children.

As mentioned in the problem, for every 7 children, there are 2 caretakers therefore, there are a total of 2 x 27 = 54 caretakers in the local daycare.

So, in total, there are 189 children + 54 caretakers = 243 people in the daycare facility.

he Solution:

iven in the question that if

We are required to give a counterexample to the given conditional statement above.

Solving each of the equations above, we get

So, the counterexample to the given conditional statement is x = 4.

The cost of the watch which sold at 130% of its cost and sale price is $39 is equal to $30.

As given in the question,

Sale price of the watch for which dealer sold = $39

Let $'x' be the cost of the watch with which dealer purchase

A dealer sold a watch 130% of its cost

Required expression to show the given condition of a dealer is given by:

   130% of x = $39

⇒ (130 /100) × x = $39

⇒ x = ( 39 × 100 ) / 130

⇒ x = $30

Therefore, the cost of the watch which sold at 130% of its cost and sale price is $39 is equal to $30.

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In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

plants have developed seeds = 71

total plants = 200

Step 02:

% = part / whole * 100

% = 35.5

The answer is:

35.5 %

The one digit numbers that when added to 746 gives a digit in the ones place of the sum which is less than the ones digit in 746 are;

4, 5, 6, 7, 8, or 9

Place values is the value a digit in a number posseses based on its position in the number

The given parameters of the number are;

The number of digits in the number = 1

The ones digit of the sum of the number and 746 is less than the ones digit in 746, which is 6

Therefore;

The value of the number when added to 746 can be expressed as 7xy

Where;

y < 6

The process of adding two numbers involves the addition of the numbers based on their place values such that the ones digit part of the result is placed as the output while the 1 in a result that is 10 or more is added to the next higher place value number to the left of the added digits

Therefore, to have a value of the digit in the ones place less than 6, we can have;

746 + 0 = 746

746 + 1 = 747

746 + 2 = 748

746 + 3 = 749

The possible one digit numbers that gives a sum with a ones digit less than 6 when added to 746 therefore includes; 4, 5, 6, 7, 8, and 9

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First, we need to calculate the median

13, 14, 14, 14, 15, 15, 15, 16, 16, 21, 23

we have 11 values the media is the 6th value in this case 15.

the lower extreme is 13 the upper extreme is 23.

The lower quartile is 14 and upper quartile is 16

the box plot is

Answer:

When making homemade ice cream in a hand-cranked freezer, the tub containing the ice cream mix is surrounded by a brine (water/salt) solution. To freeze the ice cream mix rapidly so that smooth and creamy ice cream results, the brine solution should combine crushed ice and rock salt in a ratio of 5 to 1.

the probability of having exactly 2 boys in 3 births AND having exactly 2 girls in 3 births is 3/8.

the possible outcomes are

BBB,BBG,BGB,GBB,BGG,GBG,GGB,GGG

wherein 3 meet the requirement. There are 8 possible outcomes, all equally likely (if we assume each gender is equally likely). Hence the choice is 3/8.

We can also think about it in at least one more way: You identified all the possible ways to get 2 boys and one girl. Since the events are disjoint, we can add up the probabilities

P(2 boys, 1 girl)=P(BBG)+P(BGB)+P(GBB)

          =[tex]\frac{1}{2} X\frac{1}{2} X \frac{1}{2}[/tex]+ [tex]\frac{1}{2} X\frac{1}{2} X \frac{1}{2}[/tex] + [tex]\frac{1}{2} X\frac{1}{2} X \frac{1}{2}[/tex]

          = 3/8.      

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