Jean is trying to prove parallelogram LMNO is a rhombus by using coordinate geometry.

Which statement must be true to prove LMNO is a rhombus?

A) (slope of line MO)(slope of line LN) = -1

B) (slope of line MO)(slope of line LN) = 1

C) the midpoint of line MO is the midpoint of line LN

D) the distance from M to O = the distance from L to N

Answer:

3 units

Step-by-step explanation:

Find the zeros of the polynomial 15x + 5.

Equating to 0:

Subtracting 5:

Dividing by 15 and simplifying by 5:

Answer:

D. The function f has 3 horizontal tangent lines

Step-by-step explanation:

Well whenever any function crosses the x-axis, it means that the y-value is equal to zero.

In this case when the derivative passes the x-axis it indicates the tangent line corresponding to that x-value has a slope of zero, which when plotted is a horizontal line.

This means that the graph f has 3 horizontal tangent lines.

Answer:

D. The function f has 3 horizontal tangent lines

Step-by-step explanation:

i got 100%

The amount of work done when a load of 50 newton is lifted through a distance of 6m is 300 joules.

Work done is simply the energy transfer that takes place when an object is either pushed or pulled over a distance by an external force.

It is expressed as;

Work done = force × distance

Given the data in the question;

To determine the work done, plug the given values into the above formula and solve W.

Work done = force × distance

Work done = 50kgm/s² × 6m

Work done = 50kgm²/s² × 6

Work done = 300kgm²/s²

Work done = 300J

Therefore, 300 joules is the work done in lifting the load.

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The values of x must be greater than 4 for the inequality (x-4)² > 0 to be true.

Given inequality is (x - 4)² >0.

To solve the inequality, take square root on both sides

So, (x - 4) > 0

Adding 4 on both sides,

x > 4

The values of x must be greater than 4 for the inequality to be true.

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The magnitude and direction of the vectors are

11.  <0,4> :

Magnitude = 4

Direction =  90°

12.  <-3,0>:

Magnitude = 3

Direction = 0°

13. <6,5>:

Magnitude = √(61)

Direction =  39.8°

14. <3,7>:

Magnitude = √58

Direction =  66.8°

15. <-2,1>:

Magnitude = √5

Direction =  -26.57°

16. <-10,13>:

Magnitude =  √(269)

Direction =  -37.57°

17. <2,-5>:

Magnitude = √(29)

Direction = -68.2°

18. <8,-4>:

Magnitude =  √(80)

Direction =  -26.57°

19. <-4.-6>:

Magnitude =  √(52)

Direction =  56.3°

20.  <-1,9>:

Magnitude = √(82)

Direction =  -83.66°

We are asked to find the magnitude and direction of the vectors given as <x, y>. We have the formulas for magnitude and direction of the vectors.

Magnitude = √(x²+y²)

and direction, θ = tan⁻¹(y/x)

11. The vector is <0,4>

Magnitude = √(0²+4²) = 4

Direction = tan⁻¹(4/0) = tan⁻¹∞ = 90°

12. The vector is <-3,0>.

Magnitude = √(-3²+0²) = 3

Direction = tan⁻¹(0/-3) = tan⁻¹0 = 0°

13.The vector is <6,5>

Magnitude = √(6²+5²) = √(61)

Direction = tan⁻¹(5/6) = 39.8°

14. The vector is <3,7>

Magnitude = √(3²+7²) = √58

Direction = tan⁻¹(7/3) = 66.8°

15.The vector is <-2,1>

Magnitude = √(-2²+1²) = √5

Direction = tan⁻¹(1/-2) = -26.57°

16.The vector is <-10,13>

Magnitude = √(13²+-10²) = √(269)

Direction = tan⁻¹(-10/13) = -37.57°

17.The vector is <2,-5>

Magnitude = √(2²+-5²) = √(29)

Direction = tan⁻¹(-5/2) = -68.2°

18.The vector is <8,-4>

Magnitude = √(8²+-4²) = √(80)

Direction = tan⁻¹(-4/8) = -26.57°

19.The vector is <-4.-6>

Magnitude = √(-4²+-6²) = √(52)

Direction = tan⁻¹(-6/-4) = 56.3°

20. The vector is <-1,9>

Magnitude = √(-1²+9²) = √(82)

Direction = tan⁻¹(9/-1) = -83.66°

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The loan that was borrowed by Georgina was for a period of 9 years.

From the information, Gregoria borrowed $2,450, to be paid back at 3.5% annual simple interest. She repays $3,221.75. The Interest will be:

= $3,221.75 - $2,450

= $771.75

Therefore, the time taken for the loan will be expressed as:

Interest = PRT/100

where P = Principal

R = Rate

T = Time.

Interest = PRT/100

771.75 = (2450 × 3.5 × T) /100

Cross multiply

8575T = 77175

Time = 77175 / 8575

Time = 9

The time is 9 years.

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In given inequalities the value of x is x <-3 and x >4

Equations are not necessarily about having a "equal to" sign balanced evenly on both sides. It can occasionally refer to a "not equal to" connection, where one object is more than the other or less than. A connection that compares two numbers or other mathematical expressions in an unequal way is referred to as an inequality in mathematics. These mathematical statements are classified as inequalities in the algebraic language.

Given that :4x-3<-15 or 2x+4> 12

4x -3 <-15

4x < -12

x <-3

2x + 4 > 12

2x > 8

x >4

x <-3 and x >4

In given inequalities the value of x is x <-3 and x >4

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Answer:

A) 60 that's i know !!!

Step-by-step explanation:

A) 60

Answers:  1)  " 2ab ".
                2) "  2xz ".

________________________

Step-by-step explanation:

ab + ba = ab + ab = 1ab + 1ab = (1+1)*ab = 2ab .

xz +  zx = xz  + xz = 1xz  + 1xz = (1+1)*xz  = 2xz.

________________________

Answer:

<U = 54

<T = 72

Step-by-step explanation:

Find the angle measures

The marks on the sides means the sides are the same length

That means the base angles have the same measurement

<S = <U = 54

The sum of the angles of a triangle equals 180

<S + <U + < T = 180

54 + 54 + < T =180

108 + < T =180

<T =180-108

<T = 72

Answer:

m<U = 54°

m<T = 72°

Step-by-step explanation:

According to the isosceles triangle theorem ( If two sides of a triangle are equal , then the angles opposite to these sides are also equal. ),

ST = UT

So,

m<S = m<U.

Given that,

m<S = 54°

So,

m<U = 54°

Also, we know that the sum of the interior angles of a triangle is added up to 180 degrees.

So,

m<S + m<U + m<T = 180°

54° + 54° + m<T = 180°

108° + m<T = 180°

m<T = 180° - 108°

m<T = 72°

Seven times the sum of a number and 9 is 5 then the number is -58/7 .

A summation, also known as a sum, is the outcome of adding two or more numbers or quantities. There are always an even number of terms in a summation. There could be only two terms, or there could be one hundred, thousand, or a million. There are summations with an infinite number of terms.

We have been given that

Seven times the sum of a number and 9 is 5

Let the number is n.

let's write "the sum of a number and 9"

n + 9 .

Then, "seven times" the sum can be written as:

7 (n + 9)

This "is 5" or "is equal to 5" and can be written as:

7 (n + 9) = 5

To solve, first expand the term in parenthesis on the left side of the equation by multiplying each term in the parenthesis by

(7×n) + (7×9) = 5

7n + 63 = 5

Next, subtract 63 from each side of the equation to isolate the n term while keeping the equation balanced:

7n + 63 - 63 = 5 - 63

7n = -58

Now, divide each side of the equation by 7 to solve for n while keeping the equation balanced:

7n / 7 = -58 / 7

n = -58/7

The number is −58/7.

Hence , the number is -58/7 when a number is seven times its sum and 9 is 5.

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Solution

The diagram given is a right angle triangle

To find the value of x; we consider the relationship between the three sides.

Pythagoras theorem actually gave the relationship between the three sides of a right angle triangle.

By Pythagoras theorem;

x = 10.25

Based on the definition of the functions, the value of x if f(x) = g(x) is 3

The equations of the functions are given as

f(x) = -2x + 4

g(x) = 2x - 8

It should be noted that the above equations are linear equations

From the question, we understand that the functions are equal

This means that, we have the following equation

f(x) = g(x)

Substitute the known values in the above equation

So, we have the following equation

-2x + 4 = 2x - 8

Collect the like terms in the above equation

So, we have

2x + 2x = 8 + 4

Evaluate the like terms in the above equation

So, we have

4x = 12

Divide both sides by 4

x = 3

Hence, the value of x such that the equations are equal is 3

See attachment for the graph of the functions

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Answer:

none is correct

Step-by-step explanation:

6+3×5-6+8+2

6+15-6+8+2

6+9+10

=25

Answer:

Step-by-step explanation:

Slope:

[tex]\Rightarrow \sf{\dfrac{y_2-y_1}{x_2-x_1} }[/tex]

y2=(-7)

y1=(-1)

x2=(-1)

x1=5

[tex]\sf{\dfrac{-7-\left(-1\right)}{-1-5}}[/tex]

Solve.

[tex]\sf{\dfrac{-7-\left(-1\right)}{-1-5}=\dfrac{-6}{-6}=\boxed{\sf{1}}}[/tex]

Therefore, the slope is 1, which is our answer.

I hope this helps, let me know if you have any questions.

A three-person jury can be selected from a pool of eleven people in 165 ways.

For the given question;

The total number of person in the pool = 11.

The number of jury selected = 3.

Thus, the combination will be ⁿCₓ.

Where, n = 11 and x = 3.

¹¹C₃ = 11!/3!(11 - 3)!

Simplifying;

¹¹C₃ = 165

Thus, the number of ways in which three jury can be selected from 11 pool of members is 165.

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Answer:

Tom is correct.

Step-by-step explanation:

Squaring is equivalent to multiplying a number by itself, ie:

2 squared = 2x2 = 4

6 squared = 6x6 = 36

ATTACHED IS THE SOLUTION

Answer: My new music player has a capacity of 3 * 10^11 bytes.

Step-by-step explanation: giga=billion=10^9. 300 in scientific notation is 3*10^2. Since 3 is between 1 and 10. So 10^2 * 10^9=10^11.

The equation, in slope-intercept form to represent the monthly price

as a function of the number of MB used is  y = mx + c.

It is given in the question that the cell phone provider charges you

$35 a month for a phone plan and charges $0.12 per MB of data used.

Hence,

Total monthly charges = MB used*Charge per MB+ Fixed charge  

Let y represents total monthly charges

x represents the charge per MB

m represents the MB used and,

c represents the fixed charge

Therefore, we can write the above equation as:-

y = mx + c

Hence the equation is written in the slope-intercept form.

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To determine whether the third figure is a translation image of the first figure, we say that; B: No; it is a reflection followed by a translation

Transformation could be reflection, translation, rotation or even dilation.

Reflection can be thought of as the mirror image of a shape across a line.

Rotation is when one turns an object around a point

Translation is simply moving an object from one point to another without any change of dimension.

If we look at the given three figures in the attached image, we can see that the second image is the reflection or mirror image of the first figure.

After reflection, we can see that it is undergoes translation, which means it is moved apart from the first figure.

Thus, the third figure is a reflection of the first figure, and then it is translated.

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Step-by-step explanation:

The bottom two expressions are polynomials.

Answer

Triangle B is not a rotation of triangle A because on careful observation of this two triangles, one would see that they are mirror images of each other; reflections of each other.

A mental rotation of triangle A all through the 360° shows that at no point is it seeming exactly like triangle B.

This is why it is evident that triangle B is not a rotation of triangle A, rather, they are reflections of each other.

Hope this Helps!!!

P(k + 1) follows, and it is likewise true.

As a result, after demonstrating that P(k) is true for any chosen value of k, we also demonstrated that P(k + 1) is true. According to the induction hypothesis, P(n) is true for all n ∈ Z+

To demonstrate that the mathematical proposition P(n) holds for all natural integers n = 1, 2, 3, 4,..., one uses the mathematical induction technique. It is frequently referred to as the induction principle in mathematics. We establish that P(1) holds in order to demonstrate a result P(n) using the mathematical induction technique. If P(1) is valid, we can assume that P(k) holds for some natural number k and use this assumption to demonstrate that P(k+1) is valid. The assertion P(n) applies to all natural numbers if and only if P(k+1) holds true.

Let

P(n): 1×2 + 2×3+3×4+........+n(n+1)=[tex]\frac{n(n+1)(n+2)}{3}[/tex]

Putting n =1 we get

P(1):1×2 =2

and

[tex]\frac{1(1+1)(1+2)}{3}=\frac{1(2)(3)}{3} =2[/tex]

Therefore P(1) is true.

Let P(K) is true

So,

P(k): 1×2 + 2×3+3×4+........+k(k+1)=[tex]\frac{k(k+1)(k+2)}{3}[/tex]

Now we have to show that P(k +1 )is also true.

P(k+1): 1×2 + 2×3+3×4+........+k(k+1)+(k+1)(k+2)=[tex]\frac{k(k+1)(k+2)}{3}+ (k+1)(k+2)[/tex]

= (k+1)(k+2)[[tex]\frac{k}{3}+1[/tex]]

=[tex]\frac{(k+1)(k+2)(k+3)}{3}[/tex]

P(k + 1) follows, and it is likewise true.

As a result, after demonstrating that P(k) is true for any chosen value of k, we also demonstrated that P(k + 1) is true. According to the induction hypothesis, P(n) is true for all n ∈ Z+.

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