What is the simplified form of the following expression? Assume x>0. 4 square root 3 over 2x

What Is The Simplified Form Of The Following Expression? Assume X>0. 4 Square Root 3 Over 2x

Answers

Answer 1

Answer:

the answer is B)

4√24x^3/2x

Answer 2

Solution:

The answer is B

Step-by-step explanation:

I just took the test.


Related Questions

4 out of the 80 students at a school assembly were first-grade students. What percentage of the students at the assembly were first-graders?

Answers

Answer:5

Step-by-step explanation:

Answer:

5 percent

Step-by-step explanation:

4/80 = 5 percent

In a large population of college-educated adults, the mean IQ is 112 with standard deviation 50.62. Suppose 30 adults from this population are randomly selected for a market research campaign. The distribution of the sample mean IQ is: a. approximately Normal, with mean 112 and standard deviation 1.443. b. approximately Normal, with mean 112 and standard deviation 4.564. c. approximately Normal, with mean equal to the observed value of the sample mean and standard deviation 25. d. approximately Normal, with mean 112 and standard deviation 9.241.

Answers

Given:  Population mean IQ = 112Population standard deviation IQ = 50.62Sample size (n) = 30To find: Distribution of the sample mean IQ

The Central Limit Theorem states that for a large sample size, the distribution of sample means will be approximately Normal with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size . Let's calculate the standard deviation of the sample mean IQ:

Standard deviation of sample mean IQ = (Population standard deviation IQ) / √n= 50.62 / √30= 9.241 (approx.)Therefore, the distribution of the sample mean IQ is approximately Normal, with mean 112 and standard deviation 9.241. The correct option is (d).

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Consider the function represented in the table.

Which point of the given function corresponds with the
minimum value of its inverse function?
X
-10-20
3 8
0
-2.
5 8
4.5-6
A (-20, 8)
B (-10,3)
C (0, -2)
D (8,-6)

HELPPP

Answers

Answer:

The real answer is (-20, 8).

Step-by-step explanation:

I just did the unit test practice or whatever and used the answer above and got it wrong. This is the correct answer.

Which of the expressions below is equal to 10x+30? Select all that apply.

Answers

The answer is a because you have to put it in parenthesis

Find the measure of the exterior angle.

Answers

the sum of all interior angles must be 180, we know that angle t increases by 10 therefore t is equal to 50° and angle t + 20° is equal to 70°

next we can see that the two angles form a 180° angle meaning the measure of the exterior angle is 180° - 70° or 110°

a. Determine whether the Mean Value Theorem applies to the function f(x) 4x^(1/7) on the interval [-128,128). b. If so, find or approximate the point(s) that are guaranteed to exist by the Mean Value Theorem

Answers

To determine if the Mean Value Theorem (MVT) applies to the function f(x) = 4x^(1/7) on the interval [-128, 128), we need to check if the function satisfies the conditions of the MVT.

The Mean Value Theorem states that if a function f(x) is continuous on the closed interval [a, b] and differentiable on the open interval (a, b), then there exists at least one point c in (a, b) such that f'(c) = (f(b) - f(a))/(b - a).

In this case, the interval is [-128, 128), which is a closed interval. To check if the MVT applies, we need to ensure that the function is continuous on [-128, 128] and differentiable on (-128, 128).

Continuity: The function f(x) = [tex]4x^(1/7)[/tex] is a power function and is continuous for all x values, including the interval [-128, 128]. Therefore, the function is continuous on the interval.

Differentiability: The function f(x) = [tex]4x^(1/7)[/tex]is differentiable for all x values except at x = 0. Since the interval (-128, 128) does not include x = 0, the function is differentiable on the interval.

Therefore, both conditions for the MVT are satisfied, and we can conclude that the Mean Value Theorem applies to the function f(x) = [tex]4x^(1/7)[/tex] on the interval [-128, 128).

Next, we can find or approximate the point(s) that are guaranteed to exist by the Mean Value Theorem.

The Mean Value Theorem guarantees the existence of at least one point c in (-128, 128) such that f'(c) = (f(128) - f(-128))/(128 - (-128)).

Let's calculate the values:

f(128) = [tex]4(128)^(1/7)[/tex]≈ 4.5534

f(-128) = [tex]4(-128)^(1/7)[/tex]≈ -4.5534

f'(c) = (4.5534 - (-4.5534))/(128 - (-128)) = 9.1068/256 ≈ 0.0356

Therefore, by the Mean Value Theorem, there exists at least one point c in the interval (-128, 128) such that f'(c) ≈ 0.0356.

Please note that the specific value of c cannot be determined without further analysis or calculations. The Mean Value Theorem guarantees its existence but does not provide an exact value.

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divide 150 toys amongst two groups of children in the ratio 6:9​

Answers

Answer:

60 and 90

Step-by-step explanation:

150/15 = 10

6 x 10 = 60

9 x 10 = 90

The required number of toys that can be divided among two groups is 60  and 90.

Given that,
To divide 150 toys amongst two groups of children in a ratio of 6:9​.


What is the Ratio?

The ratio can be defined as the proportion of the fraction of one quantity towards others. e.g.- water in milk.

Here,
Ratio = 6 / 9
Total of ratio = 15
Now,
For 1 group toys = 150 [6 / 15] = 60
For group 2 toys = 150 [9 / 15] = 90

Thus, the required number of toys that can be divided among two groups is 60  and 90.

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El usuario se registra medio de una temperatura de 8 grados centígrados Sin embargo a las 22 horas la temperatura y ha bajado unos 10 grados centígrados Cuál es la temperatura en este momento

Answers

Answer:

La temperatura en estos momentos es -2 grados centígrados.

Step-by-step explanation:

Dado que conoces que había una temperatura de 8°C y que a las 22 horas esta ha bajado unos 10 grados, tienes que restar estos 10 grados de la temperatura inicial para saber cuál es la temperatura actual:

8-10=-2

De acuerdo a esto, la respuesta es que la temperatura en estos momentos es -2 grados centígrados.

A metal bar weighs 24 ounces. 15% of the bar is gold. How many ounces of gold are in the bar? *​

Answers

Answer:

7.6 ounces of silver

Step-by-step explanation:

Hope this helps :)

There ae 3.6 ounces of Gold in the metal bar.

What is mean by Percentage?

A number or ratio that can be expressed as a fraction of 100 or a relative value indicating hundredth part of any quantity is called percentage.

To Calculate the percent of a number , divide the number by whole number and multiply by 100.

Given that;

A metal bar weighs 24 ounces.

And, 15% of the bar is gold.

Now, We can formulate as;

Amount of gold in the bar is,

⇒ 15% of 24

⇒ 15/100 × 24

⇒ 3.6 ounces

Hence, There ae 3.6 ounces of Gold in the bar.

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please help me .......​

Answers

Answer:

A

Step-by-step explanation:

AX and EX are secant segments that intersect at point X.
What is the length of DE?


1 unit

3 units

4.5 units

4 2/3 units

Answers

Answer:

DE=4

Step-by-step explanation:

got it right on edg

The length of DE is given as: 3 Units. (Option B)
A line that joins two points on a curve is called a Secant Line.

What is the Secant Theorem?

Two secant theorem states that if two secant lines are drawn from a point outside a circle a relationship is formed between the line segments.

How do we arrive at the length of DE?

Based on the Secant Theorem, from the figure, we know that:

AX * BX = EX * DX

Assuming that the length of DE equals X,:

AX * BX = EX * DX

Equals

(7+2) X (2) = (x + 3) (3)

To solve for x we expand the brackets to state:

9 * 2= 3x + 9

3x = 18-9

3x= 9

x = 9/3

X which is same as DE = 3 Units.

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(3/2)^4= in fraction form help pls

Answers

Answer:

81/16

Step-by-step explanation:

What is the distance between A(7, 4) and B(2, −8)?

Answers

Answer:

The distance would 13 square units

Step-by-step explanation:

Well follow the formula

=√(2−1)^2+(2−1)^2

Plug in everything and solve, remeber to follow order of operations

-6x - 14 > 10 what is the answer to this problem, please helt

Answers

Answer:

Inequality Form:

x < - 4

Interval Notation:

( − ∞ , − 4 )

Step-by-step explanation:

I need help with this helpppp :(

Answers

Answer:

Domain: (-∞,+∞)

Range: (-∞,1)

y-intercept: (0,2)

Asymptote: I am not sure (sorry) I know they can be solved using the equation n(x)=0

Step-by-step explanation:

Domain: the set of all x-values

- this graph has arrows which means the domain is from -∞ to +∞ (-∞,+∞)

Range: the set of all y-values

- the graph extend continuously on the negative side so -∞ and it stops at 1 on the positive side  (-∞,1)

Y-intercept: this point is where the graph crosses the y-axis, this is at (0,2)

solve the following equation on the interval [0°,360°). separate multiple answers with a comma. remember to include a degree symbol. 4cos2xtanx−2tanx=0

Answers

To solve the equation 4cos^2(x)tan(x) - 2tan(x) = 0 on the interval [0°, 360°), we can use algebraic manipulations and trigonometric identities. Let's simplify the equation step by step:

Start with the given equation: 4cos^2(x)tan(x) - 2tan(x) = 0.

Factor out the common term tan(x): tan(x)(4cos^2(x) - 2) = 0.

Set each factor equal to zero and solve separately:

a) tan(x) = 0:

Since tan(x) is zero at x = 0°, 180°, and 360°, we have x = 0°, 180°, 360° as solutions.

b) 4cos^2(x) - 2 = 0:

Add 2 to both sides: 4cos^2(x) = 2.

Divide by 4: cos^2(x) = 1/2.

Take the square root: cos(x) = ±√(1/2).

To find the values of x in the interval [0°, 360°), we need to consider both the positive and negative square root:

cos(x) = √(1/2):

x = 45°, 315° (since cos(45°) = cos(315°) = 1/√2)

cos(x) = -√(1/2):

x = 135°, 225° (since cos(135°) = cos(225°) = -1/√2)

Therefore, the solutions to the equation 4cos^2(x)tan(x) - 2tan(x) = 0 on the interval [0°, 360°) are: x = 0°, 45°, 135°, 180°, 225°, 315°, and 360°.

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what is a shape that has no sides the same length that is a quadrilateral

Answers

Answer:

Step-by-st

Bitly: URL Shortener - Short URLs & Custom Free Link ...bitlep explanation:

Answer the following questions about about the arrangements of MILLIMICRON.

1. How many distinguishable ways can the letters of the word MILLIMICRON be arranged in order?

2. How many distinguishable orderings of the letters of MILLIMICRON begin with M and end with N?

3. How many distinguishable orderings of the letters of MILLIMICRON contain the letters CR next to each other in order and also the letters ON next to each other in order?

Answers

1. The given word is "MILLIMICRON". The word has 11 letters in total and consists of 2 M's, 2 I's, 2 L's, 1 C, 1 R, 1 O, and 1 N. So, we can use the formula for finding permutations of n objects of which p are of the same kind, q are of another kind, r are of the third kind, and so on. The formula is `n!/(p!q!r!...)`. Here, we have p = 2, q = 2, r = 2, and so on. So, the number of distinguishable ways that the letters of the word "MILLIMICRON" can be arranged in order is: `11!/(2!2!2!) = 4989600` 2. We are given that the distinguishable orderings of the letters of "MILLIMICRON" begin with "M" and end with "N". We have fixed two letters at the beginning and end.

Now, we have 9 letters left which can be rearranged in the remaining 9 spots. So, the number of distinguishable orderings of the letters of "MILLIMICRON" that begin with "M" and end with "N" is: `9!/(2!2!1!) = 22680`3. We are given that the distinguishable orderings of the letters of "MILLIMICRON" must contain the letters "CR" next to each other in order and also the letters "ON" next to each other in order. We can group "CR" and "ON" together as a single letter. So, we have 9 letters: {M, I, L, L, I, M, C, RON, O}. We need to find all the distinguishable orderings of these letters. Let's consider the group "RON" as a single letter. Now, we have 8 letters: {M, I, L, L, I, M, C, RON}. These 8 letters can be arranged in 8! ways. Within the group "RON", we can arrange the letters "R", "O", and "N" in 3! ways. So, the total number of distinguishable orderings of the letters of "MILLIMICRON" that contain the letters "CR" next to each other in order and also the letters "ON" next to each other in order is: `8!×3! = 20,160`.

Hence, the answers are: 1. 4,989,6002. 22,6803. 20,160

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4
Find the area of the figure and type your result in the empty box provided.
13 m
6 m
8 m
7 m
Answer:

Answers

Answer:

I need a picture of the figure to do it

Let f: X+R be a linear function, where X is a topological vector space. (a) Suppose that f is bounded above on a neighborhood V of the origin. That means there exists 7>0 such that f(x) < y for all x EV. Prove that there exists a neighborhood W of the origin such that f(x)

Answers

Given a linear function f: X -> R that is bounded above on a neighborhood V of the origin, we need to prove that there exists a neighborhood W of the origin such that f(x) < y for all x in W.

To prove this statement, we can use the properties of linear functions and the topology of X. Since f is linear, we know that f(0) = 0.

Let's consider the open ball B(0, y) centered at the origin with radius y. Since f is bounded above on V, there exists a constant M > 0 such that f(x) < M for all x in V.

Now, let's define a neighborhood W = V ∩ f^(-1)(B(0, y/M)). W is the intersection of V and the inverse image of the open ball B(0, y/M) under the function f.

By the properties of inverse images, we know that f(x) < y/M for all x in W.

Therefore, we have found a neighborhood W of the origin such that f(x) < y for all x in W, satisfying the condition we needed to prove.

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ayudaaaaaaaaaaa por favor

Answers

Answer:

ayuda te solo no eres tonto o si?

Step-by-step explanation:

n the problem of estimating total hospitalization costs for kidney stone patients, suppose Muscat and Dhofar regions were selected as strata because they have very different incident rates for the disease, and the estimates for each region was needed separately. Also, this stratification into geographic regions simplified the sampling procedures. The sample data are summarized as follows: Muscat Dhofar ni=260 12=150 Mean cost ý,=170 RO Mean cost y =125 RO S =3050 $ -2525 G = 745 C-10 RO n 02-680 C2=12 RO A previous study showed the number of kidney stone incidents in the Muscat to be 325 out of 100,000 population and the number in the Dhofar to be 320 out of 100,000. The population of the Muscat was 775,878, and the population of the Dhofar was 249,729, according to the 2010 census. a) Obtain the estimates of N, and N2, the numbers of kidney stone patients expected to be found in the Muscat and Dhofar regions. b) Obtain the average annual cost of hospitalization of the kidney patients of the two region combined with 95% confidence interval and interpret the results. c) Find the appropriate sample size n and stratum sample size ni and n2 for estimating the population mean with a bound on the error of estimation equal to 50 RO, considering proportional allocation.

Answers

The estimated number of kidney stone patients in the Muscat region (N₂) is approximately 447,184, and in the Dhofar region (N₁) is approximately 128,694.

Given,

Estimation of total hospitalization costs for kidney stone patients .

Here,

To obtain the estimates of N and N, the numbers of kidney stone patients expected to be found in the Muscat and Dhofar regions, we can use the stratified sampling formula:

Nᵢ = (nᵢ / n) * N,

where:

- Nᵢ is the estimate of the population size in stratum i.

- nᵢ is the sample size in stratum i.

- n is the total sample size (sum of all stratum sample sizes).

- N is the total population size.

Given the information provided, we have the following data:

For Dhofar region:

- n₁ = 260 (sample size)

- N = 249,729 (population size according to the 2010 census)

For Muscat region:

- n₂ = 150 (sample size)

- N = 775,878 (population size according to the 2010 census)

Using the given formula, we can calculate the estimates for each region:

For Dhofar region:

N₁ = (n₁ / n) * N = (260 / (260 + 150)) * 249,729

For Muscat region:

N₂ = (n₂ / n) * N = (150 / (260 + 150)) * 775,878

To obtain the values, let's calculate them:

For Dhofar region:

N₁ = (260 / (260 + 150)) * 249,729 ≈ 128,694

For Muscat region:

N₂ = (150 / (260 + 150)) * 775,878 ≈ 447,184

Therefore, the estimated number of kidney stone patients in the Muscat region (N₂) is approximately 447,184, and in the Dhofar region (N₁) is approximately 128,694.

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The daily return of the stock XYZ is normally distributed with a mean of 20 basis points and a standard deviation of 40 basis points. Find the probability of making a gain that amounts for more than one standard deviation from the mean on any given day.

Answers

The probability of making a gain that exceeds one standard deviation from the mean for stock XYZ on any given day is approximately 31.73%.

The probability of making a gain that amounts to more than one standard deviation from the mean on any given day for the stock XYZ can be found using the properties of the normal distribution.

To calculate this probability, we need to find the area under the normal distribution curve beyond one standard deviation from the mean in the positive direction. In this case, the mean (μ) is 20 basis points and the standard deviation (σ) is 40 basis points.

Using the standard normal distribution, we can convert the value one standard deviation above the mean (μ + σ) to a z-score by subtracting the mean and dividing by the standard deviation.

Z = (X - μ) / σ

Z = (μ + σ - μ) / σ

Z = σ / σ

Z = 1

Once we have the z-score, we can look up the corresponding probability using a standard normal distribution table or a statistical calculator.

The area under the normal curve beyond one standard deviation from the mean in the positive direction corresponds to approximately 0.1587 or 15.87%.

Therefore, the probability of making a gain that amounts to more than one standard deviation from the mean on any given day for stock XYZ is approximately 0.1587 or 15.87%.

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T or F:
When finding the percentage of each section, you have to divide the part by the whole or total amount.

Answers

Answer:

true because you can do that in a amound of the total

A chi-squared test for homogeneity of proportions requires that

A. ni, n2, n3, ... > 30
B. all expected counts are > 5
C. nipi, n2p2, n3p3, ... > 10​

Answers

The answer is Is B
..................

Sophia drove 63 miles. Sophia's car used 2 gallons of gas. How many miles per gallon did Sophia car get?

Answers

Answer:

31.5 mi/gal

Step-by-step explanation:

[tex]63[/tex]÷[tex]2[/tex][tex]=31.5[/tex]

So, Sophia got 31.5 miles per gallon

Answer: 31.5 I think.

Step-by-step explanation:

Give other person brainliest

Which of the following statement(s) with regard to a data set's measures of Central Tendency, Dispersion, and Paired Observations is(are) TRUE?

In a very small set of data, i.e. small n, the Sample Standard Deviation is generally smaller than its Population Standard Deviation.

It is possible for the value of the Correlation between a set of paired observations to be greater than 1.

Unlike STDEV.P Excel function for calculating a Population Standard Deviation, Excel has no direct functions for calculating the Range and Midrange values of a data set.

Mode and Range are both measures of central tendency.

In a set of paired observations of X and Y, if the Correlation is 0.75, then as the values of X increases (decreases), the values of Y also generally increases (decreases) in the same direction.

In a very large set of data, i.e. large n, the Standard Deviation is a better measurement than Range.

It is possible for Median of a data set to have a value that is not equal to any of the values in the data set.

Answers

The statements that are TRUE with regard to a data set's measures of Central Tendency, Dispersion, and Paired Observations are the following:In a very small set of data, i.e. small n, the Sample Standard Deviation is generally smaller than its Population Standard Deviation.

It is possible for the value of the Correlation between a set of paired observations to be greater than 1.In a set of paired observations of X and Y, if the Correlation is 0.75, then as the values of X increases (decreases), the values of Y also generally increases (decreases) in the same direction.In a very large set of data, i.e. large n, the Standard Deviation is a better measurement than Range.Why these statements are true?In a very small set of data, the Sample Standard Deviation is generally smaller than its Population Standard Deviation because when the sample size is smaller, there is less dispersion and thus the value of the sample standard deviation is generally smaller than that of the population standard deviation.It is possible for the value of the Correlation between a set of paired observations to be greater than 1 because the correlation coefficient r ranges from -1 to 1, inclusive of both endpoints.

However, it is practically impossible to get a value of r outside this range in a real dataset.In a set of paired observations of X and Y, if the Correlation is 0.75, then as the values of X increases (decreases), the values of Y also generally increases (decreases) in the same direction. This is because 0.75 is a strong positive correlation indicating that as the value of one variable increases, the value of the other variable also increases.In a very large set of data, i.e. large n, the Standard Deviation is a better measurement than Range because the standard deviation takes into account all values in the dataset and is less sensitive to outliers as compared to the range. On the other hand, the range only considers the minimum and maximum values of the dataset and thus is less informative.

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Which property of equality would be used to solve 3x=81

Answers

Answer:

Division

Step-by-step explanation:

What is the value of b for b' - 36/64

Answers

the value of b is 0.5625

i need help please help me​

Answers

84 I believe, a2+b2=c2 is the formula btw
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I don't understand how to work this problem at all. identify the option below that is a characteristic of acidic solutions. consider a sample with data values of 10, 20, 12, 17, and 16. compute the z-score for each of the five observations. an object is placed a distance do in front of a concave mirror with a radius of curvature r = 11 cm. the image formed has a magnification of m = 2.6. Write an expression for the object's distance. d_o. Numerically, what is the distance in cm? Use the principle of mathematical induction. (Assume n is a positive integer.) 1+3+5+ ... + (2n - 1) = n^2 Which of the following is not one of the steps for hypothesis testing?A. Determine the null and alternative hypotheses.B. Verify data conditions and calculate a test statistic.C. Assuming the null hypothesis is true, find the p-value.D. Assuming the alternative hypothesis is true, find the p-value. A Moving to another question will save this response. Question 9 1 points Save Answe The cost of a plant asset includes the purchase price, applicable taxes, purchase commissions, and all other amount show me the step and answer using spss A consumer agency wanted to estimate the difference in the mean amounts of caffeine in two brands of coffee.The agency took a sample of 15 one-pound jars of Brand I coffee that showed the mean amount of caffeine in these jars to be 80 milligrams per jar with a standard deviation of 5 milligrams.Another sample of 12 one-pound jars of Brand Il coffee gave a mean amount of caffeine equal to 77 milligrams per jar with a standard deviation of 6 milligrams.Construct a 95% confidence interval for the difference between the mean amounts of caffeine in one-pound jars of these two brands of coffee. Assume that the populations are normally distributed and the standard deviations of the two populations are equal.Interpret your answer. fill in the blank. _____ serve as the intermediary between the user and the database. Below is information regarding the capital structure of Micro Advantage Inc. On the basis of this information you are asked to respond to the following three questions: Required: 1. Micro Advantage issued a $5,000,000 par value, 20-year bond a year ago at 98 (le, 98% of par value) with a stated rate of 9% Today, the bond is selling at 110 i.e., 110% of par value). If the firm's tax bracket is 30%, what is the current after-tax cost of this debt? 2. Micro Advantage has $5,000,000 preferred stock outstanding that it sold for $24 per share. The preferred stock has a per share par value of $25 and pays a $3 dividend per year. The current market price is $30 per share. The firm's tax bracket is 30% What is the after-tax cost of the preferred stock? 3. In addition to the bonds and preferred stock described in requirements 1 and 2, Micro Advantage has 50,000 shares of common stock outstanding that has a par value of $10 per share and a current market price of $170 per share. The expected after tax market return on the firm's common equity is 20% What is Micro Advantage's weighted average cost of capital (WACC)? Complete this question by entering your answers in the tabs below. Requird 1 Required 2 Required 3 Micro Advantage issued a $5,000,000 par value, 20-year bond a year ago at 98 (l... 98% of par value) with a stated rate of 9%. Today, the bond is selling at 110 (.e., 110% of par value). If the firm's tax bracket is 30%, what is the current after-tax cost of this debt? (Round your answer to 2 decimal places. (1...1234 = 12.3496)) Current after-tax cost of this debt s An electron is acted upon by a force of 5.501015N due to an electric field. Find the acceleration this force produces in each case:The electron's speed is 4.00 km/s . ---ANSWER---: a=6.04*10^15 m/s^2