what do you expect the future trends of an operating system in terms of (a) cost (b) size (c) multitasking (d) portability (e) simplicity​

Answer:

Projects have a fixed budget, while operations have to earn a profit to run the business. Projects are executed to start a new business objective and terminated when it is achieved, while operational work does not produce anything new and is ongoing.

Hope this helped!

Answer:

i would say C

Explanation:

Answer:

c

Explanation:

ye

Answer:

S = 5.7209 M

Explanation:

Given data:

B = 20.1 m

conductivity ( K ) = 14.9 m/day

Storativity  ( s ) = 0.0051

1 gpm = 5.451 m^3/day

calculate the Transmissibility ( T ) = K * B

                                                       = 14.9 * 20.1 = 299.5  m^2/day

Note :

t = 1

U = ( r^2* S ) / (4*T* t )

  = ( 7^2 * 0.0051 ) / ( 4 * 299.5 * 1 ) = 2.0859 * 10^-4

Applying the thesis method

W(u) = -0.5772 - In(U)

       = 7.9

next we calculate the pumping rate from well ( Q ) in m^3/day

= 500 * 5.451 m^3 /day

= 2725.5 m^3 /day

Finally calculate the drawdown at a distance of 7.0 m form the well after 1 day of pumping

S = [tex]\frac{Q}{4\pi T} * W (u)[/tex]

 where : Q = 2725.5

               T = 299.5

               W(u)  = 7.9

substitute the given values into equation above

S = 5.7209 M

Answer:

Earthquake's put vibration and seismic load on a building while wind puts a continuous force throughout the whole structure.

Explanation:

The most important difference between the design of a building that's resistent to earthquakes and resistant to high speed winds is that earthquake's put vibration and seismic load on a building while wind puts a continuous force throughout the whole structure.

Earthquake resistent building are equipped with a base that is isolated from the buildings with several layers of different material which absorb the vibration of the seismic waves and prevent them from reaching to the building.

Wind resistent buildings must have strong foundations and a sturdy structure/material that can withstand high pressure that the wind applies during events such as hurricanes.

I hope this answer helps.  

Answer:

C. Neither Technician A nor B

Explanation:

Just took the test

Answer:

they agreed to reduce nuclear weapons

Answer:

A

Explanation:

Edu 2023

Answer: more dense

Explanation:

Answer:

C-Reagan endorsed a conservative economic policy.

Explanation:

edge21

Reagan endorsed a conservative economic policy.

In the US, presidential elections take place every four years. The next election for the nation's top position will be in 2024 because the last one occurred in 2020.

Federal elections must take place "the Tuesday next after the first Monday in November," according to U.S. law code.

Every even-numbered year has a presidential election and a congressional midterm election (e.g. 2016, 2018, 2020.)

Therefore, Reagan endorsed a conservative economic policy.

To learn more about economic policy, refer to the link:

https://brainly.com/question/22324594

#SPJ6

Answer:

tech b because gut feeling

Explanation:

Answer:

6kΩ

Explanation:

If we assume that the entire circuit's current is 3 mA, then we can compute the resistance within the circuit with the application of Ohm's law:

V = IR

V/I = R

R = V / I

R = 18V / 3 mA

R = 6kΩ

Hence, the resistance of the circuit is 6kΩ.

Cheers.

Answer:

Angle Iron

Explanation:

Mark brainliest please.

Answer:

14 km/hour

Explanation:

Answer:

false

Explanation:

Answer:linear coefficient of thermal expansion of the rod =2.17 x10^-6(°C)^-1

Explanation:

The Linear thermal expansion is calculated as

ΔL = αLΔT,

where ΔL = change in length L,

ΔT = the change in temperature,

α is the coefficient of linear expansion

Change in length ΔL= 0.1 mm =0.1/1000= 0.0001m

change in temperature,ΔT= Final - Initial temperature

= (112- 20)°C=92°C

Solving, we have that

ΔL = αLΔT

α=ΔL/LΔT

= 0.0001 / 0.5 x 92

=0.0001/46

=2.17 x10^-6 / °C

The  linear coefficient of thermal expansion of the rod, α =2.17 x10^-6(°C)^-1

Answer:

Electricity from the wind turbine generator travels to a transmission substation where it is converted into extremely high voltage, between 155,000 and 765,000 volts, for long distance transmission on the transmission grid. This grid comprises a series of power lines that connect the power sources to demand centers.The advantages of wind energy are more apparent than the disadvantages. The main advantages include an unlimited, free, renewable resource (the wind itself), economic value, maintenance cost, and placement of wind harvesting facilities.

Answer:

Engineering ethics is the field of a system of moral principles that apply to the practice of engineering. The field examines and sets the obligations by engineers to society, to their clients, and to the profession.

Explanation:

Answer:the mass of water vapor is=d. 2.04 kg

Explanation:

The humidity ratio by mass is given as

x = mw / ma                                  (1)

where

mw = mass of water vapor

ma = mass of dry air

And also humidity ratio by pressure by  Ideal Gas Law is given as

x = 0.62198 pw / (pa - pw)                            (2)

where

pw = partial pressure of water vapor in moist air

pa = atmospheric pressure of moist air

Equating both equation we have that

Humidity ratio =  0.62198 pw / (pa - pw)= mw / ma      (3)

From the from the water table at 25°C,

water vapor partial pressure = 23.8 torr

 1 atm =760 torr.

1 atm = 101.325 kPa,

So, 760 torr =101.325 kPa,

Therefore 23.8 torr =3.173kPa

Humidity ratio =  0.62198 pw / (pa - pw)= mw / ma  

0.62198 x 3.173 / (100-3.173)= mw / 100

1.9736 /96.827=mw/100

0.0204=mw/100

mw=2.04kg

Answer:

50 Watts

Explanation:

For this problem, we simply apply Ohm's law:

V = IR

V / R = I

P = IV

P = ( V / R ) V

P = ( V^2 / R )

P = (20 V)^2 / 8 Ω

P = 400 V^2 / 8 Ω

P = 50 Watts

Hence, the power consumed by the lightbulb is 50 Watts.

Cheers.

Answer:

19.0476 kN/m^2

Explanation:

Given data:

Dimension of rectangular area = 2.5m x 5.0m

external load = 150 KN/m^2

load depth = 6.25 m

calculate the vertical stress increase due to load at depth 6.25

we will use the approximate method which is

[tex]V_{s} = \frac{qBL}{(B +Z)(L+Z)}[/tex]  ------- (1)

q = 150 kN/m^2

B = 2.5 m

L = 5 m

Z = 6.25 m

substitute the given values into the equation (1) above

hence the Vs ( vertical stress ) = 19.0476 kN/m^2

Answer:

A pointer is spun on a fair wheel of chance having its periphery labeled Trom 0 to 100. (a) Whhat is the sample space for this experiment? (b)What is the probability that the pointer will stop between 20 and 35? (c) What is the probability that the wheel will stop on 58?

​

Explanation:

thats all you said

Answer:

hii my name is RAGHAV what is your name

Explanation:

this question is which chapter

Answer:

agriculture,defense,industry,science

Explanation:

Edg 2021

Answer:

20.87 Pa

Explanation:

The formula for dynamic pressure is given as;

q= 1/2*ρ*v²

where ;

q=dynamic pressure

ρ = density of fluid

v = velocity of fluid

First find v by applying the formula for flow rate as;

Q = v*A   where ;

Q= fluid flow rate

v = flow velocity

A= cross-sectional area.

A= cross-sectional vector area of the pipe given by the formula;

A= πr² = 3.14 * 4² = 50.27 in²   where r=radius of pipe obtained from the diameter given divided by 2.

Q = fluid flow rate = 105 gpm----change to m³/s as

1 gpm = 0.00006309

105 gpm = 105 * 0.00006309 = 0.006624 m³/s

A= cross-sectional vector area = 50.27 in² -------change to m² as:

1 in² = 0.0006452 m²

50.27 in² = 50.27 * 0.0006452 = 0.03243 m²

Now calculate flow velocity as;

Q =v * A

Q/A = v

0.006624 m³/s / 0.03243 m² =v

0.2043 m/s = v

Now find the dynamic pressure q given as;

q= 1/2 * ρ*v²

q= 1/2 * 1000 * 0.2043² = 20.87 Pa

Answer:

If I am not mistaken I believe it is a higher voltage.

Explanation:

Hope this helps

Answer:

Explanation:

Step one:

given data

T_{wi} = 20^{\circ}C

T_{Ai}=1000K

T_{Ae}= 400kPa

P_{Wi}=200kPa

P_{Ai}=125kPa

P_{We}=200kPa

P_{Ae}=100kPa

m_A=2kg/s

m_W=0.5kg/s

We know that the energy equation is

[tex]m_Ah_{Ai}+m_Wh_W=m_Ah_{Ae}+m_Wh_{We}[/tex]

making [tex]h_{We}[/tex] the subject of formula we have

[tex]h_{We}=h_{Wi}+\frac{m_A}{mW}(h_A-h_{Ae})[/tex]

from the saturated water table B.1.1 , corresponding to  [tex]T_{wi}= 20c[/tex]

[tex]h_{Wi}=83.94kJ/kg[/tex]

from the ideal gas properties of air table B.7.1 , corresponding to T=1000K

the enthalpy is:

[tex]h_{Ai}=1046.22kJ/kg[/tex]

from the ideal gas properties of air table B.7.1 corresponding to T=400K

[tex]h_{Ae}=401.30kJ/kg[/tex]

Step two:

substituting into the equation we have

[tex]h_{We}=h_{Wi}+\frac{m_A}{mW}(h_A-h_{Ae})[/tex]

[tex]h_{We}=83.94+\frac{2}{0.5}(2046.22-401.30)\\\\h_{We}=2663.62kJ/kg[/tex]

from saturated water table B.1.2 at [tex]P_{We}=200kPa[/tex]  we can obtain the specific enthalpy:

[tex]h_g=2706.63kJ/kg[/tex]

we can see that [tex]h_g>h_{Wi}[/tex], hence there are two phases

from saturated water table B.1.2 at [tex]P_{We}=200kPa[/tex]

[tex]T_{We}=120 ^{\circ} C[/tex]

Answer:

44.59°c

Explanation:

Given data :

Total pressure = 105 kpa

complete combustion

A) Determine air-fuel ratio

A-F = [tex]\frac{N_{air} }{N_{fuel} } = \frac{(Nm)_{air} }{(Nm)_{c} (Nm)_{n} }[/tex]

N = number of mole

m = molar mass

A-F = [tex]\frac{(6.75*4.76)kmole * ( 29kg/mol)}{(3kmole)* 12kg/mol + (6kmol)*(1kg/mol)}[/tex]  =  22.2 kg air/fuel

hence the ratio of Fuel-air = 1 : 22.2

B) Determine the temperature at which water vapor in the products start condensing

First we determine the partial  pressure of water vapor before using the steam table to determine the corresponding saturation temp

partial pressure of water vapor

Pv = [tex]\frac{(N_{water vapor}) }{N_{pro} } * ( P_{ro} )[/tex]

N watervapor ( number of mole of water vapor ) = 3

N pro ( total number of mole of product = 3 + 3 + 2.25 + 25.28 = 33.53 kmol

Pro = 105

hence Pv = ( 3/33.53 ) * 105 =  9.39kPa

from the steam pressure table the corresponding saturation temperature to 9.39kPa =  44.59° c

Temperature at which condensing will start = 44.59°c

An equation showing the products of propylene with their mole numbers is attached below

Answer:

4mA

Explanation:

For this problem, we will simply apply Ohm's law:

V = IR

V/R = I

I = V / R

I = 12 volt / 3kΩ

I = 4mA

Hence, the current in the circuit is 4mA.

Cheers.

Answer:

18 Watts

Explanation:

For this problem, we simply need to understand the relationship of power to voltage and current.  This relationship is derived from Ohm's law:

Power = Voltage * Current

Given this equation, we can say the following to find the power consumption of the motor:

Power = 12volts * 1.5amps

Power = 18 Watts

Hence, the motor is consuming 18 Watts of power.

Cheers.

l/blouoojiklnkjhljm,jl,mj l, j/ll

Answer:

thanks! :D

Have a good day!

Answer:

Yay, :)

Thank you!!!

Answer:

he didn't use the proper material

Answer:

A. He did not allow the metal to cool properly when making molds.

Explanation: