Two sides of an obtuse triangle measure 9 inches and 14 inches. The length of the longest side is unknown. What is the smallest possible whole-number length of the unknown side?

Answer: x=7

Step-by-step explanation:

To solve for x, you want to use algebraic properties.

20+8(x-11)=-12                  [distribute]

20+8x-88=-12                   [combine like terms]

8x-68=-12                          [add both sides by 68]

8x=56                                [divide both sides by 8]

x=7

Now we know that x=7.

Answer:

3.278 * 10 ^ 2

Step-by-step explanation:

To change a number to scientific notation you:

Move the decimal point to the left to make the number have 1 number before the decimal point.

From there you multiply by 10 to the power 2 the number of decimal points you moved.

So the answer is 3.278 * 10^2

HOPE IT HELPED

Answer:

[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{12\pi \: mm}}}}}[/tex]

Step-by-step explanation:

[tex] \star[/tex] Radius of a circle ( r ) = 6 mm

[tex] \star[/tex] Circumference of a circle ( C ) = ?

Finding the circumference of a circle having radius ( r ) of 6 mm

[tex] \boxed{ \sf{circumference \: of \: a \: circle = 2\pi \: r \: }}[/tex]

[tex] \hookrightarrow{ \sf{circumference = 2 \times \pi \: \times \: 6}}[/tex]

[tex] \hookrightarrow{ \sf{circumference = 12\pi \: \: mm}}[/tex]

Circumference of the given circle = 12π mm

Hope I helped!

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~TheAnimeGirl

Answer:

28 days

Step-by-step explanation:

Day 1  = 3 m,  day 1 end = 3 - 1 = 2 m

Day 2 end = 2 + 3 -2 = 3m

Day3 end = 3 + 3- 2 = 3 +1 = 4m

On 27th day end = 26+ 3 - 2 = 27 m

On 28th day =27 + 3 = 30 m

Answer: 27.5 miles per hour

Step-by-step explanation: 70 - 42.5 = 27.5

Answer:

Step-by-step explanation:

Hello,

We know that

[tex]|x|=\begin{cases}x & \text{if } x\geq 0 \\ -x & \text{if } x<0 \end{cases}[/tex]

So we need to take into account two cases

Case 1 - [tex]x-3\geq 0<=> x\geq 3[/tex]

Then, |x-3|=x-3

||x-3|-2|=|x-3-2|=|x-5|

Either x-5 is positive and then |x-5|=x-5 and

[tex]|x-5|\leq 1<=>x-5\leq 1<=>x\leq 6[/tex]

Or x-5 is negative and then, |x-5|=-x+5

[tex]|x-5|\leq 1<=>-x+5\leq 1<=>4\leq x[/tex]

So the solution is [4;6]

Case 2 - [tex]x-3< 0<=> x< 3[/tex]

Then, |x-3|=-x+3

||x-3|-2|=|-x+3-2|=|-x+1|

Either -x+1 is positive and then |-x+1|=-x+1 and

[tex]|-x+1|\leq 1<=>-x+1\leq 1<=>0\leq x[/tex]

Or -x+1 is negative and then, |-x+1|=x-1

[tex]|-x+1|\leq 1<=>x-1\leq 1<=>x\leq 2[/tex]

So the solution is [0;2]

Conclusion

The solution is [0;2]∪[4;6]

Thanks

Answer:

Step-by-step explanation:

If one can of paint covers 400 square feet then this should be easy. Since you need 3,000 square feet covered with paint (and one paint can cover 400 sq) then just divide 3,000 by 400.

This will show you how many times 400 can go into 3,000 which is the same as saying "how many cans of paint can i used to cover 3,000 square feet?"

Answer:

y = 4

RS = 35

ST = 26

Step-by-step explanation:

Given:

RS = 8y + 3

ST = 5y + 6

RT = 61

Required:

a. Value of y

b. Numerical lenght of RS and ST

SOLUTION:

a. Points R, S and T are collinear, therefore, based on segment addition postulate, the following equation can be created to find the value of y:

[tex] RS + ST = RT [/tex]

[tex] (8y + 3) + (5y + 6) = 61 [/tex] (substitution)

Solve for y

[tex] 8y + 3 + 5y + 6 = 61 [/tex]

Combine like terms

[tex] 8y + 5y + 3 + 6 = 61 [/tex]

[tex] 13y + 9 = 61 [/tex]

Subtract 9 from both sides

[tex] 13y + 9 - 9 = 61 - 9 [/tex]

[tex] 13y = 52 [/tex]

Divide both sides by 13

[tex] \frac{13y}{13} = \frac{52}{13} [/tex]

[tex] y = 4 [/tex]

b. RS = 8y + 3

Plug in the value of y

RS = 8(4) + 3 = 32 + 3

RS = 35

ST = 5y + 6

Plug in the value of y

ST = 5(4) + 6 = 20 + 6

ST = 26

Answer:

Guy above me is Wrong its 14

Step-by-step explanation:

Answer: is b andrea

Step-by-step explanation: i just took the same test

Answer:

Thy answer is B my queen

Step-by-step explanation:

Answer:

Step-by-step explanation:

Length of a segment between two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by the formula,

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Coordinates of extreme ends of BC and EF are,

B(1, 4), C(3, -2), E(-3, -2) and F(-1, 1)

Length of BC = [tex]\sqrt{(1-3)^2+(4+2)^2}[/tex]

                      = [tex]\sqrt{4+36}[/tex]

                      = [tex]2\sqrt{10}[/tex] ≈ 6.32 units

Length of EF = [tex]\sqrt{(-3+1)^2+(-2-1)^2}[/tex]

                     = [tex]\sqrt{4+9}[/tex]

                     = [tex]\sqrt{13}[/tex] ≈ 3.61 units

The length of BC is 6.32. The length of EF is 3.61.So, BC and EF don't have the same length.

Answer:

please give brainlist

Rounding to a certain number of decimal places

If we want to round 4.732 to 2 decimal places, it will either round to 4.73 or 4.74. 4.732 rounded to 2 decimal places would be 4.73 (because it is the nearest number to 2 decimal places).

hope this helped

Answer:

800

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

In matrix T, the value of t₁₃ will be 7.

A set of numbers arranged in rows and columns so as to form a rectangular array. The numbers are called the elements, or entries, of the matrix.

We have to given that;

The matrix T is shown.

We know that;

In any matrix,

⇒ The element a₁₁ shows the position of a₁₁ is in first row and first column.

Thus, The element t₁₃ shows the position of t₁₃ is in first row and third column.

So, In matrix T,

⇒ t₁₃ = 7

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Answer: 875 square feet

Step-by-step explanation: none atm

Answer: 8

(10-3x2)2

(10-6)2

4 x 2

8

Answer:

8

Step-by-step explanation:

3×2=6

10-6=4

4x2=8

Your answer is 8

Answer:

16 cms.

Step-by-step explanation:

The length of each side = 40 / 4 = 10 cm (as the 4 sides of a rhombus are congruent).

If we draw the other diagonal we form 4 right angled triangles (another property of the rhombus - diagonals bisect each other at tight angles. ).

The side of the rhombus is the hypotenuse of the right triangle.

So if we consider one triangle:

10^2 = 6^2 + x^2   where x is half the length of the other diagonal.

x^2 = 10^2 - 6^2

x^2 = 100 - 36 = 64

x = 8 cm.

So the diagonal is 16 cms long.

Answer:

The answer is below

Step-by-step explanation:

Using binomial probability:

p = probability of a rural student getting admission = 1/2

q = probability of a rural student not getting admission = 1/2

n = number of students = 100

P(x) = [tex]C(n,x) p^xq^{(n-x)[/tex]

But [tex]p^xq^{n-x}=\frac{1}{2}^x\frac{1}{2}^{n-x}=\frac{1}{2}^{n}[/tex]

P(x > 50) = P(x = 51) + P(x = 52) + P(x = 53) + . . . + P(x = 100)

P(x > 50) = [tex]\frac{1}{2} ^{100}[C(100,51)+C(100,52)+C(100,53)+\ .\ .\ .+C(100,100)]\\[/tex]

[tex]P(x>50)=\frac{1}{2}^{100} (\frac{1}{2}( 2^{100}-C(100,50)))\\\\P(x>50)=(\frac{1}{2}^{100} *\frac{1}{2}*2^{100})- (\frac{1}{2}^{100} *\frac{1}{2}*C(100,50))\\\\P(x>50)=\frac{1}{2}[(2^{-100}*2^{100})-(\frac{1}{2}^{100} *C(100,50))]\\ \\P(x>50)=\frac{1}{2}[1-\frac{1}{2}^{100} *C(100,50)][/tex]

Answer:

[tex]\frac{\left(t-h\right)}{k}\\[/tex] = g

Step-by-step explanation:

Subtract the h

t = h+kg

-h  -h

you get:

t-h=kg

now divide the k from both sides

[tex]\frac{\left(t-h\right)}{k}\\[/tex] = [tex]\frac{\left(kg\right)}{k}[/tex]

so,

[tex]\frac{\left(t-h\right)}{k}\\[/tex]=g

Answer:

B. [tex] -\frac{3}{2} [/tex]

Step-by-step explanation:

Rate of change/slope is given as [tex] m = \frac{y_2 - y_1}{x_2 - x_1} [/tex]

Use the coordinate pairs of any two points on the slope/line.

Let's use the following coordinates pairs:

[tex] (-2, 4) = (x_1, y_1) [/tex]

[tex] (0, 1) = (x_2, y_2)

Plug in the values into the formula, [tex] m = \frac{y_2 - y_1}{x_2 - x_1} [/tex]:

[tex] m = \frac{1 - 4}{0 - (-2)} [/tex]

[tex] m = \frac{-3}{0 + 2} [/tex]

[tex] m = \frac{-3}{2} [/tex]

[tex] m = -\frac{3}{2} [/tex]

Answer:

3

Step-by-step explanation:

Each of the lines lengths multiply by 3.

Answer:

1

Step-by-step explanation:

[tex]\frac{\sqrt{48} }{4\sqrt{3} }=\frac{\sqrt{16} }{4}=\frac{4}{4}=\frac{1}{1}=1[/tex]

Answer:

14.814 i belive

Answer:

inverse of f(x) = (2e^x)/(e^(x)-1)

Step-by-step explanation:

Answer:

141°

Step-by-step explanation:

Answer: C

Step-by-step explanation:

The best person will be an urban planner to help prepare the city for the future. The correct option is C.

In towns, cities, counties, and metropolitan areas, urban and regional planners construct land use plans and programs that support the development of communities, allow for population increase, and renew physical infrastructure.

Given that the city officials in your hometown expect a huge rise in population over the next few years.

The best person to help in preparing the city for the future will be an urban planner.

Therefore, the best person will be an urban planner to help prepare the city for the future. The correct option is C.

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