Their velocity (in m/s) just after impact if they cling together is -0.9 m/s.
Final speed of the two players
Apply the principle of conservation of linear momentum;
Pi = Pf
where;
Pi is initial momentum of the playersPf is final momentum of the players(92.5)(5.5) + (116)(-6) = v(92.5 + 116)
508.75 - 696 = v(208.5)
-187.25 = 208.5v
v = -187.25/208.5
v = -0.9 m/s
Thus, their velocity (in m/s) just after impact if they cling together is -0.9 m/s.
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I need a super tragic past for my desired reality, the reality I'm going to is Naruto.
Thanks
To create a tragic past for your character, you would have to write a plot that shows a sad ending to a good story.
What is a Tragic Story?This refers to a type of story that has negative emotions such as sadness, death, etc.
Hence, we can see that for example, you could write about two lovers and how despite all the struggles they faced, eventually died in mysterious circumstances.
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Please help me with this answer
The position of the car at the given time is 18 m.
Position of the car at t = 6.0 s
The position of the car at the given time is calculated as follows;
x = vt
where;
v is the velocity of the car; from the graph v = 3 m/st is time of motion = 6.0 sx = 3 m/s x 6.0 s
x = 18 m
Thus, the position of the car at the given time is 18 m.
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An object with a mass of m = 3.85 kg is suspended at rest between the ceiling and the floor by two thin vertical ropes.
The magnitude of the tension in the lower rope is 12.8 N. Calculate the magnitude of the tension in the upper rope.
The tension in the upper rope is determined as 50.53 N.
Tension in the upper rope
The tension in the upper rope is calculated as follows;
T(u) = T(d)+ mg
where;
T(u) is tension in upper ropeT(d) is tension in lower ropeT(u) = 12.8 N + 3.85(9.8)
T(u) = 50.53 N
Thus, the tension in the upper rope is determined as 50.53 N.
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You cover the following displacements every day going to school: d1=50 m, E and d2=95 m, N. You do this for 12 minutes. a) What is your speed in m/s? b) What is your velocity in m/s?
The speed will be 0.2 m/s and the velocity will be 0 m/s.
Speed = Total Distance / Total time
We have given total distance as ( 50 + 95 ) metres and total time as 12 minutes or we can say 720 seconds.
Speed = 145/ 720 m/s
Speed = 0.2 m/s
Velocity = Total Displacement / Total time
As the initial and final is the home, hence the net displacement is 0 in that case.
In this case also the total time we have given is 12 minutes or we can say 720 seconds.
Velocity = 0 / 720 m/s
Velocity = 0 m/s
So to conclude with we can say that the speed is 0.2 m/s and the velocity is 0 m/s.
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A butcher has a beam balance and masses 0.5kg and 2kg .How would he measure 1.5 kg of meat on the beam balance at once.
The butcher should balance both the meat and 0.5 kg mass on one arm of the beam balance and 2 kg mass on the other arm of the beam balance.
What is a beam balance?A beam balance can be defined as an apparatus which comprises a lever with two (2) equal arms and a bowl (pan) that is suspended from each arm, so as to measure the mass of an object.
In this scenario, the butcher should balance both the meat and 0.5 kg mass on one arm of the beam balance and 2 kg mass on the other arm of the beam balance.
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A 60kg man jumps off a 30 foot building. Assuming he falls from rest and there is negligible air resistance, how long will it take him to reach the ground?
Answer:
1.37 seconds before.... splat !
Explanation:
y = y0 + v0 t + 1/2 a t^2 y0 = 30 y = 0
v0 = 0 ( from rest)
a = - 32.2 ft/s^2
0 = 30 - 1/2 * 32.2 * t^2
t=1.366 seconds Note that mass is irrelevant.
2 red and 2 blue overlapping balls in the center are surrounded by a green, fuzzy, circular cloud with a white line running through it. 2 green balls sit on the white line, and a line leading a bracket around the balls is labeled A. A line leading to a bracket overlapping the white line is labeled B. Which is a characteristic of the part of the atom marked "B”? It is very dense. It has a large mass. It is negatively charged. It is where neutrons move.
A characteristic of the part of the atom marked "B” is that it has a large mass. Option B. This is further explained below.
What is atom?Generally, Atom, the lowest possible unit into which matter may be split without releasing electrically charged particles.
In conclusion, the protons and neutrons are represented by the red and white spheres, respectively. Since it indicates both protons and neutrons, the line preceding the bracket around the balls (designated A) stands in for the atom's nucleus.The mass of the "B" section of the atom is very high.
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Answer:
it's b
Explanation:
i did the ed quiz
The intensity of sound waves is linearly proportional to ?
You are able to hear sounds from farther away on a cool night because sound waves are refracted toward ?
When the trough of one wave collides at the same time & place of the crest of an identical wave?
A water heater is rated at 200w ( 200 Joules/sec). How long will the heater take to provide 60,000 joules to heat up a sample of water?
A sample of 100g of 0 Celsius ice is heated up until the sample totally becomes 0 Celsius water ( solid /liquid phase change occurs in this case).What is the total amount of heat provided to the ice sample?( Latent heat of fusion of water /ice is =79.8 cal/g)?
The amount of heat required to increase the temperature of 100g of water rom 20 Celsius ( specified heat of water =4184 JC-1*kg-1)?
When water vapor condense into liquid water?
(1) The intensity of a sound wave is linearly proportional to the change in the pressure squared.
(2) You are able to hear sounds from farther away on a cool night because sound waves are refracted toward warmer air near the ground.
(3) When the trough of one wave collides at the same time & place of the crest of an identical wave, destructive interference occurs.
(4) The time taken for the heater to provide the energy is 300 secs.
(5) The total amount of heat provided to the ice sample is 7,980 cal.
(6) The amount of heat required to increase the temperature of water is 33,472 J.
Intensity of soundThe intensity of a sound wave is linearly proportional to the change in the pressure squared and inversely proportional to the density and the speed.
Refraction of sound wavesYou are able to hear sounds from farther away on a cool night because sound waves are refracted toward warmer air near the ground.
Destructive inferenceWhen the trough of one wave collides at the same time & place of the crest of an identical wave, destructive interference occurs.
Time taken for the heater to provide the energyE = Power x Time
t = E/P
t = 60,000/200
t = 300 secs
Total amount of heat provided to the ice sampleQ = 79.8 cal/g x 100 g
Q = 7,980 cal
Amount of heat required to increase the temperature of waterQ = 0.1 kg x 4184 J/kgC x (100 - 20)
When water vapor condense into liquid water, temperature = 100⁰C
Q = 33,472 J
Thus, the intensity of a sound wave is linearly proportional to the change in the pressure squared.
You are able to hear sounds from farther away on a cool night because sound waves are refracted toward warmer air near the ground.When the trough of one wave collides at the same time & place of the crest of an identical wave, destructive interference occurs.The time taken for the heater to provide the energy is 300 secs.The total amount of heat provided to the ice sample is 7,980 cal.The amount of heat required to increase the temperature of water is 33,472 J.Learn more about intensity of sound here: https://brainly.com/question/17062836
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A soccer ball is kicked from the top of one building with a height of H1 = 30.2 m to another building with a height of H2 = 12.0 m. (It is not a very smart idea to play soccer on the roof of tall buildings.)
The ball is kicked with a speed of v0 = 15.10 m/s at an angle of θ = 74.1° with respect to the horizontal. The mass of a size 5 soccer ball is m = 450 g. When the ball lands on the other building, its speed is 19.89 m/s.
How much energy was lost to air friction? The ball is kicked without a spin.
The energy lost to the air due to friction is 37.7 J.
Energy lost to the air due to frictionThe energy lost to the air due to friction is determined from the change in kinetic energy of the ball.
ΔK.E = K.Ef - K.Ei
ΔK.E = ¹/₂mv² - ¹/₂mu²
ΔK.E = ¹/₂m(v² - u²)
ΔK.E = ¹/₂(0.45)(19.89² - 15.1²)
ΔK.E = 37.7 J
Thus, the energy lost to the air due to friction is 37.7 J.
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Peter arranged the two circuits shown below. P, Q R and S are blocks of four different materials.
Based on the given information, which of the four materials is an insulator?
a. P
b. Q
c. R
d. S
Material P does not always lead to the glowing of the bulb hence the material P is an insulator.
What is an insulator?The term insulator refers to an object that does not permit current to pass through it. Insulators include materials such as wood, plastic etc.
Looking at the two circuits, we can see that the material P does not always lead to the glowing of the bulb hence the material P is an insulator.
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A boat moving at 5 km/h to cross a river in which the current is flowing at 3km/h. in what direction should the boat head to reach a point on the other bank of the river directly opposite its starting point?
The boat will move in a direction that is 36.86 degrees away from the velocity vector as it attempts to reach the opposite bank from where it started.
We must understand the issue with the river crossing in order to identify the solution.
How can I determine the angle at which my boat should be travelling against the current to reach the other bank?Let's assume that a boat traveling at velocity Vb is navigating a river with width d and flow Vr.The boat's movement against the current to reach the opposite shore from its starting point will then be in the direction of,[tex]\alpha =sin^{-1}(\frac{V_R}{V_B} )[/tex]
First, using the provided information, we may create a flow diagram for this issue.It is evident from the diagram that the angle will be,[tex]\alpha =sin{-1}(\frac{3}{5} )[/tex]
Thus, we can deduce that the boat will move in a direction that is 36.86 degrees away from the velocity vector as it attempts to reach the opposite bank from where it started.
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what is scalar product of A and B , if vector product of A and B is zero
Answer:
A^2+B^2 is the scalar product of A and B
Answer:
Scalar product is equal to the magnitude a vector a times the projection of a onto vector B,
A^2+B^2.You place a book of mass 5.00 kg against a vertical wall. You apply a constant force F⃗ to the book, where F = 96.0 N and the force is at angle of 60.0∘ above the horizontal. The coefficient of kinetic friction between the book and the wall is 0.300.
If the book is initially at rest, what is its speed after it has traveled 0.400 m up the wall.
The speed after it has traveled 0.400 m up the wall will be 1.77 m/sec.
What is the work-energy theorem?From the work-energy theorem, it is stated that the net work done is equal to the change in the kinetic energy.
Given data;
Mass of book,m =5.00
Force,F = 96.0 N
Θ is the angle above the horizontal = 60°
The coefficient of kinetic friction between the book and the wall is μ =0.300.
R is the normal reaction
W₁ = Fd cosΘ
W₁=(96.0 N) (0.4 m) in 60°
W₁= 33.25 J
Work done by gravity is,
W₂ = mgdcos180°
W₂ = (5.00 kg) (9.81 m/s²)(0.4 m) cos180°
W₂ = -19.6J
The Normal force on the book by the wall is,
N = FcosΘ
N = (96 N) cos 60°
N=48 J
Work done by friction is;
W₃=μkRdcos180°
W₃=0.3)(48 J)(0.4 m) cos180°
W₃ =-5.76 J
The net work done is;
W =W₁+W₂+W₃
W=33.25-19.6-5.76
W=7.89 N
From the work-energy theorem, we have
W = ΔK
[tex]\rm W = \frac{1}{2} mv^2 - 0[/tex]
The speed is;
[tex]\rm v = \sqrt \frac{2 W}{m} \\\ v = \sqrt{\frac{2 \times 7.89} {5.00}}\\\\ v = 1.77 \ m/sec[/tex]
Hence, the speed after it has traveled 0.400 m up the wall will be 1.77 m/sec.
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More than 700 people in the United States have been infected with monkeypox virus American vector: the epidemic is spreading like a snowball.
Answer: I don't understand if it is a question
Explanation:
More than 700 people in the United States have been infected with monkeypox virus American vector: the epidemic is spreading like a snowball.
a steel ring is 50mm diameter and 2mm thick. it must be fitted onto a shaft 50.04 mm diameter. calculate the temperature to which it must be heated in order to fit the shaft. the initial temperature is 20 deg C and the coefficient of linear expansion is 15x10^-6 per degrees celcius. calculate the stress and forced induced in the ring
okay so the stress and forced induced I can do that but the first part is confusing me because there is no final temperature.
The temperature to which it must be heated in order to fit the shaft is 73.33 ⁰C.
Linear expansivity
The temperature to which it must be heated in order to fit the shaft is calculated as follows;
[tex]\frac{\Delta L}{L} = \alpha \Delta T\\\\\Delta T = \frac{\Delta L}{\alpha L}[/tex]
where;
ΔT is change in temperatureΔL is change in length = 50.04 mm - 50 mm = 0.04 mmα is coefficient of linear expansionL is original lengthΔT = (0.04)/(50 x 15 x 10⁻⁶)
ΔT = 53.3 ⁰C
Final temperatureT₂ - T₁ = ΔT
T₂ = ΔT + T₁
where;
T₂ is final temperatureT₁ is initial temperatureT₂ = 53.3 + 20
T₂ = 73.33 ⁰C
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You add chocolate syrup to a glass of milk and stir it. The resulting chocolate milk would be classified as:
A. Homogeneous mixture
B. Element
C. Heterogeneous mixture
D. Compound
A bug and a city bus have a head-on collision. Is the force the bug exerts on the bus greater than, less than, or the same as the force the bus exerts on the bug? Explain. What happens to the velocity of the bus and the bug after the collision?
Answer:
Force of bug is less than the force that the bus exerts on the bug
Explanation:
Force = MA. bus has more mass so more force and bug has a lot less mass than bus. Bug accelerates in whatever direction the bus is going and the bus is not affected.
The cannon on a battleship can fire a shell a maximum distance of 36.0 km.
(a) Calculate the initial velocity of the shell.
m/s
(b) What maximum height does it reach? (At its highest, the shell is above a substantial part of the atmosphere--but air resistance is not really negligible as assumed to make this problem easier.)
m
(c) The ocean is not flat, since the earth is curved. How many meters lower will its surface be 36.0 km from the ship along a horizontal line parallel to the surface at the ship?
mDoes your answer imply that error introduced by the assumption of a flat earth in projectile motion is significant here? (Select all that apply.)
The error is insignificant compared to the distance of travel.
The error is significant compared to the distance of travel.
The error could be significant compared to the size of a target.
The error is insignificant compared to the size of a target.
(a)The initial velocity of the shell will be 594.27 m/sec
(b)The maximum height it reaches will be 9000 m.
c)101.249 m meters lower will its surface be 36.0 km from the ship along a horizontal line parallel to the surface of the ship.
d)The error could be significant compared to the size of a target. Option C is correct.
What is velocity?The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
The given data in the problem is
m is the mass of the block = Kg.
u is the initial velocity of fall = m/sec
h is the distance of fall = m
g is the acceleration of free fall = m/sec²
v is the hitting velocity of =?
a)
The range of the projectile is;
[tex]\rm R = \frac{u^2 sin 2 \theta }{g} \\\\ 36 \times 10^ 3 = \frac{U^2 sin 45^0}{9.81} \\\\ U= 594.27 \ m/sec[/tex]
b)
The maximum height of the projectile is;
[tex]\rm H = \frac{u^2 sin 2 \theta }{2g} \\\\ H = \frac{(594.27)^2\times (sin 45)^2}{2 \times 9.81 } \\\\ H = 9000 \ m[/tex]
c)
The distance between its surface and the ship, measured in a horizontal arc parallel to the surface, will be 36.0 kilometers. The distance from the lower surface is found as;
[tex]\rm( R_e + h)^2 = R_e^2+(36)^2 \\\\ (R_e)^2 = h^2+2R_e h= R_e^2 + 12196 \\\\ h^2 + 12800 h - 1296 = 0 \\\\ h = 101.249 \ m[/tex]
d)
An error is a mistaken or erroneous action. In some contexts, an error is interchangeable with a mistake.
The difference between the calculated value and the original value is known as the error. The inaccuracy may be large in comparison to the target's size. Option C is correct.
Hence the initial velocity of the shell, maximum height, and the distance from the lower surface will be 594.27 m/sec,9000 m, and 101.249 m and option c for question d are correct respectively.
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You fire a projectile 35° above horizontal with an initial velocity of 200m/s. It lands in a valley 300m below the launch point. What is the time of flight of the projectile, and what is the range of projectile?
Answer:
See below
Explanation:
Vertical component of initial velocity = 200 sin 35° = 114.72 m/s
then use position formula a = 9.81 m/s^2
0 = 300 + 114.72 t - 1/2 (9.81)(t^2)
use quadratic formula with a = - 4.905 b = 114.72 c = 300
to find t = 25.76 seconds
To find the range
( horizontal distance the projectile lands from launch point)
Horizontal component of initial velocity 200 cos 35 = 163.83 m/s
( it flies horizontally at this speed for 25.76 seconds <==found above)
163.83 m/s * 25.76 s = 4220.3 meters
The mass of a star is 1.210×1031 kg and it performs one rotation in 20.30 days. Find its new period (in days) if the diameter suddenly shrinks to 0.350 times its present size. Assume a uniform mass distribution before and after.
The new period will be 2.486 days.
What is the period?
The period is found as the ratio of the angular displacement and the angular velocity. Its unit is the second and is denoted by t. The value of time needed to complete the rotation is the total period.
Given data;
Mass of a star,m= 1.210×10³¹ kg
The time period for one rotation of the star, T = 20.30 days
D' = 0.350 D
R' = 0.350 R
From the law of conservation of angular momentum;
[tex]\rm I \omega = I' \omega' \\\\ \frac{2}{5} MR^2 \times \frac{2 \pi }{T}=\frac{2}{5} MR'^2 \\\\ R^2 \times \frac{1}{T}= R'^2 \times \frac{1}{T} \\\\ T' = \frac{R'^2T}{R^2} \\\\ T' = \frac{(0.350 R)^2 \times 26.1 }{R^2} \\\\T' = 0.1225 \times 20.30 \\\\ T'= 2.486 \ days[/tex]
Hence, the new period will be 2.486 days.
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power is measured in units of watts what are watts ?
Answer:
the watt is the unit of power or radiant flax
A 21.0 kg uniform beam is attached to a wall with a hi.nge while its far end is supported by a cable such that the beam is horizontal.
If the angle between the beam and the cable is θ = 66.0° what is the tension in the cable?
What is the vertical component of the force exerted by the hi.nge on the beam?
The tension in the cable is 112.64 N and the vertical component of the force exerted by the hi.nge on the beam is 93.16 N.
Tension in the cableApply the principle of moment and calculate the tension in the cable;
Clockwise torque = TL sinθ
Anticlockwise torque = ¹/₂WL
TL sinθ = ¹/₂WL
T sinθ = ¹/₂W
T = (W)/(2 sinθ)
T = (21 x 9.8)/(2 x sin66)
T = 112.64 N
Vertical component of the forceT + F = W
F = W - T
F = (9.8 x 21) - 112.64
F = 93.16 N
Thus, the tension in the cable is 112.64 N and the vertical component of the force exerted by the hi.nge on the beam is 93.16 N.
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An extended body (not shown in the figure) has its center of mass at the origin of the reference frame. In the case below give the direction for the torque τ with respect to the center of mass of the body due to force F acting on the body at a location indicated by the vector r.
Options are:
X
-Y
Z
-Z
The direction of torque τ this method is mathematically given as
D=X
Option A is correct.
What is the direction of torque?Generally, the equation for torque is mathematically given as
τ = r X F
Hence to decipher the torque direction with respect to the center of mass of the body due to force F acting on the body at a location indicated by the vector r
We utilize our right hand.Place our right-hand fingers along the path of rPlace our right-hand palm on F Then slowly we sweep r into F.The path or direction of the thumb will provide the direction of the torque.In conclusion, the direction of this method is
D=X Option A.
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Please help me answer this
a train travels 8.81 m/s in a -51.0 direction. the train accelerates 2.23 subtext1
The horizontal component of the train's speed is 5.54 m/s and the vertical component's of the train's speed is 6.85 m/s.
Horizontal component of the train's speed
The horizontal component of the train's speed is calculated as follows;
Vx = V cosθ
where;
V is the speed of the trainθ is the direction of the train.Vx = 8.81 m/s x cos(51)
Vx = 5.54 m/s
Vertical component's of the train's speedVy = 8.81 m/s x sin(51)
Vy = 6.85 m/s
Thus, the horizontal component of the train's speed is 5.54 m/s and the vertical component's of the train's speed is 6.85 m/s.
The complete question is below:
a train travels 8.81 m/s in a -51.0 direction. the train accelerates 2.23 m/s². Find the horizontal and vertical component of the train's speed.
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Three containers are filled with water to the same level. Identical marbles are dropped into all the three containers. In which container will the water level be the highest?
a. P
b. Q
c. R
d. The level will be the same in all the three containers.
Answer:
P
Explanation:
,............................................ I have. a doubt too on D
3. The following sound waves have what velocity? (convert cm into m in your calculations.)
a. 20.0 Hz, λ of 17.2 m.
b. 200.0 Hz, λ of 1.72 m.
c. 2,000.0 Hz, λ of 17.2 cm.
d. 20,000.0 Hz, λ of 1.72 cm.
The sound waves with the frequency 20 Hz, 200 Hz, 2,000 Hz, and 20,000 Hz have a velocity of 344 m/s.
What are sound waves?A sound wave is a sample resulting from the motion of strength traveling thru a medium (inclusive of air, water, or every other liquid or stable matter) because it propagates from the supply of the sound. Sound waves are created and convey strain waves, for example, a cellphone.
The frequency can be given as:
Frequency = Velocity/ Wavelength
Velocity = Frequency * Wavelength
The velocity of the following sound waves is given as:
Frequency = 20 HzWavelength = 17.2 m
Velocity = 20 * 17.2 m/s
Velocity = 344 m/s
Frequency = 200 HzWavelength = 1.72 m
Velocity = 200 * 1.72 m
Velocity = 344 m/s
Frequency = 2,000 HzWavelength = 17.2 cm = 0.172 m
Velocity = 2,000 * 0.172 m/s
Velocity = 344 m/s
Frequency = 20,000 HzWavelength = 1.72 cm = 0.0172 m
Velocity = 20,000 * 0.0172 m/s
Velocity = 344 m/s
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What quadrant will the resultant be in if the horizontal component is positive and the vertical component is
negative?
Answer:
Quadrant IV
Explanation:
In Quadrant IV, x is positive, and y is negative.
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What is the length of the y-component of the vector plotted below?
The length of the y-component of the vector plotted below is 1 unit.
We know this because this vector can be descomposed in two vectors (blue) that form an angle of 90° beetween them. The measures of this vectors must be able to form a right-angle triangle with the descomposed vector (see image).
A roller coaster has a mass of 450 kg. It sits at the top of a hill with height 49
m. If it drops from this hill, how fast is it going when it reaches the bottom?
Answer:
Approximately [tex]31\; {\rm m\cdot s^{-1}}[/tex] assuming that there is no friction on the rollercoaster, and that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].
Explanation:
Make use of the SUVAT equation [tex]v^{2} - u^{2} = 2\, a\, x[/tex], where:
[tex]v[/tex] is the final velocity of the moving object,[tex]u[/tex] is the initial velocity of the object,[tex]a[/tex] is the acceleration of the object, and[tex]x[/tex] is the displacement of the object.If there is no friction on the rollercoaster, the acceleration of the rollercoaster would be equal in magnitude to the gravitational field strength, [tex]g[/tex]:
[tex]a = g = 9.81\; {\rm m \cdot s^{-2}}[/tex].
The initial velocity of this rollercoaster is [tex]0\; {\rm m\cdot s^{-1}}[/tex] (that is, [tex]u = 0\; {\rm m\cdot s^{-1}}[/tex]) since the rollercoaster was initially stationary. The displacement of this rollercoaster would be [tex]x = 49\; {\rm m}[/tex] (same as the height of the hill.)
Rearrange the equation [tex]v^{2} - u^{2} = 2\, a\, x[/tex] to find an expression for the final velocity [tex]v[/tex] of this rollercoaster:
[tex]\begin{aligned}v &= \sqrt{2\, a\, x + u^{2}} \\ &= \sqrt{2 \times 9.81\; {\rm m\cdot s^{-2} \times 49\; {\rm m} + (0\; \rm m\cdot s^{-1}})^{2}}\\ &\approx 31\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].