A proton has a positive electric charge of q = 1.6 × 10–19 coulombs. what is the electric potential at a point 5.3 × 10–11 m from the proton? 4.4 × 10–18 volts 2.7 × 101 volts 3.0 × 10–9 volts 5.1 × 101 volts

The boom makes an angle of θ = 60.2° with the vertical wall and the tension in the horizontal rope is mathematically given as

[tex]T_1=730.85 \mathrm{~N}[/tex]

[tex]T_1'=\frac{1980.51 \mathrm{~N}}{}[/tex]

Generally, the equation for is  mathematically given as

1) Tension in vertical rope,

[tex]T_{1}=74.5 \times 9.81\\T_1=730.85 \mathrm{~N}[/tex]

2) Tension in horizontal rope,

[tex]\sum{Mg} =0\\Mg\frac{l}{2} \sin \theta+T_{1} \frac{l}{2} \sin \theta &=T_{2} l \cos \theta \\[/tex]

[tex]T_{2} &=\frac{M g(l / 2) \sin \theta+T_{1}(l / 2) \sin \theta}{l \cos \theta} \\\\&=\frac{M g \tan \theta}{2}+\frac{T_{1} \tan \theta}{2} \\\\T_{2} &=\frac{142 \times 9.81 \tan 61.8}{2}+\frac{730.85 \times \tan 61.8}{2} \\\\=& 1299+681.51[/tex]

[tex]T_1=\frac{1980.51 \mathrm{~N}}{}[/tex]

In conclusion, the tension in the horizontal rope is

[tex]T_1=\frac{1980.51 \mathrm{~N}}{}[/tex]

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The statement regarding work and retirement that is true is that most older Americans say they would prefer to enter retirement gradually.

Retirement is defined as the time in an individuals life that such leaves the Labour market or the workforce.

In some countries such as the United States of America, most elderly citizen prefer taking retirement process slowly.

Therefore, the statement regarding work and retirement is that retirement is a gradual process which one starts to process while actively in service

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Answer:

The focal length is R/2 = 25 cm / 2 = 12.5 cm

A ray from the center of curvature is focused back on itself (R cm)

As the angle of the ray is changed to being parallel to the axis the ray from the mirror will be brought closer to the mirror      

f(parallel) < focus (back upon itself)

compare  angles of  incidence and reflection

The mass of a proton and neutron and the positive charge of the proton accounts for why the electrons are thousands of times smaller than the nucleus and negatively charged.

Electrons are one of the three fundamental particles that make up an atom.

Electrons are negatively-charged particles which are found in certain regions of space around the nucleus of an atom at a particular instant.

The nucleus is composed of protons and neutrons. The protons are positively-charged while the neutrons are neutral. Thu, the negative charge of the electron balances the positive charge of the nucleus.

The mass of a proton is about 1840 times heavier than the electron. Thus, the nucleus is many thousand times heavier than the electron.

In conclusion, the negative charge of the electron ensures an atom is neutral.

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When the fish begins to swim around, the reading of the scale won't change because mass of the fish and the bucket is constant.

The weight of the fish inside the bucket depends on the mass of the bucket and fish.

W = mg

where;

Thus, when the fish begins to swim around, the reading of the scale won't change because mass of the fish and the bucket is constant.

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The velocity of the boat after the package is thrown is 0.36 m/s.

Apply the principle of conservation of linear momentum;

Pi = Pf

where;

v(74 + 135) = 15 x 5

v(209) = 75

v = 75/209

v = 0.36 m/s

Thus, the velocity of the boat after the package is thrown is 0.36 m/s.

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The Lenz's law gives the direction of induced current. According to this law, the induced current opposes the cause that produces it.

Lenz's law states that: The current induced in a circuit due to a change in a magnetic field is directed to oppose the change in flux and to exert a mechanical force which opposes the motion.

According to the question,

If we keep the magnet stationary and moved the coil back and forth within the magnetic field, an electric current would be induced in the coil.

Then by either moving the wire or changing the magnetic field we can induce a voltage and current within the coil and this process is known as Electromagnetic Induction.

When the coil AB is approaching towards north pole of the magnet, the magnetic flux linking to the coil increases.

Now according to Lenz's law,

This magnetic field created will oppose its own or we can say opposes the decrease in flux through the coil and this is possible only if approaching coil side attains south polarity, as we know dissimilar poles attract each other.

Once we know the magnetic polarity of the coil side, we can easily determine the direction of the induced current by applying right hand rule. In this case, the current flows in the A to B direction.

The right-hand rule. If you point your pointer finger in the direction the positive charge is moving, and then your middle finger in the direction of the magnetic field, your thumb points in the direction of the magnetic force pushing on the moving charge.

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Answer:

b

Explanation:

c is a velocity time graph, showing how a body moves with constant velocity with change in time

The speeds and velcity will be 0.020 m/sec and 0.0149 m/sec.

Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while V for the final speed. its si unit is m/sec.

Given data;

d1=50 m E

d2=95 m N
Time period,t = 12 min = 12 × 60 sec = 7200 sec

The displacement is the shortest distance found from the pythogorous theorem as;

Displacement = √[(50 )²+(95)²]

Displacement = 107.35 m

a)The speed is found as;

Speed = distance / time

Speed = 50 +95 / 7200

Speed = 0.020 m/sec

b)The velocity is found as;

Velocity = Displacement / time

Velocity = 107.35 / 7200

Velocity = 0.0149 m/sec

Hence the speed and the velcity will be 0.020 m/sec and 0.0149 m/sec.

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The approximate magnitude of the force between them is [tex]-4.032*10^-^6 N[/tex]

According to Coulomb, the electric force for charges at rest has the following properties:

Like charges repel each other; unlike charges attract.

Thus, two negative charges repel one another, while a positive charge attracts a negative charge.

The equation in Coulomb's law is :

[tex]F =\frac{{kq_1q_2}}{r^2}[/tex]

Where F is the force between charges, k is a constant, q₁ is the charge of the first particle, q₂ is the charge of the second particle and r is the distance between the two particle charges.

According to the question,

The given values are:-

q₁ =  +8.0 × 10⁻⁹

q₂ = –1.4 × 10⁻⁸

Substituting to the equation:

[tex]F =\frac{{kq_1q_2}}{r^2}[/tex]

=[tex]\frac{ { 9*10^{9} * 8* 10^{-9} *-1.4*10^{-8} }}{(5x10^-1)^2}[/tex]

= -4.032 x 10⁻⁶ N

Therefore,

-4.032 x 10⁻⁶ N is the approximate magnitude of the force between them.

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1)The centripetal acceleration will be 84622.360 km/h².

2)The time the turn take is 0.19 hour.

3)The distance the airplane cover during the turn is 505.54 km.

The acceleration needed to move a body in a curved way is understood as centripetal acceleration.

The direction of centripetal acceleration is always in the path of the center of the course. The total acceleration is the result of tangential and centripetal acceleration.

The given data in the problem;

R is the radius= 80.5 m

v is the linear speed = 2610 km/h

a is the total acceleration.

1)

The centripetal acceleration is found by

[tex]\rm a_c = \frac{v^2}{R} \\\\ a_c = \frac{(2610 \ km/h)^2}{80.5} \\\\ a_c = 84622.360 \ km/h^2[/tex]

2)

The time the turn take is;

[tex]\rm a= \frac{4 \pi^2R}{T^2} \\\\\ 84622.360 = \frac{4 \times (3.14)^2 \times 80.5}{T^2} \\\\\ T = 0.19 \ hr[/tex]

3)

The distance the airplane cover during the turn is;

C= 2πR

C=2 × 3.14 × 80.5 km

C= 505.54 km

Hence centripetal acceleration, time the turn take, and distance the airplane cover during the turn will be 84622.360 km/h²,0.19 sec, and 505.54 km respectively.

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The Velocit,y Height and flow rate is is mathematically given as

Generally, the equation for the Continuity equation is  mathematically given as

A1v1=A2v2

Therefore

[tex]v2=\frac{r1^2}{r2^2}v1[/tex]

v2= 1.92m/s

Generally, the equation for Pressure  is  mathematically given as

the difference is related by

[tex]P=\rho g h[/tex]

Therefore

[tex]h=P / \rho g[/tex]

(1000)(9.81)(h)=2*10100

h=2.06m

Generally, the equation for Flow rate is  mathematically given as

[tex]F=\rho Av[/tex]

Therefore

[tex]F=(1000)\pi (0.45)^2 1.1[/tex]

F= 700kg/s

In conclusion, The resulting solutions are

v2= 1.92m/s

h=2.06m

F= 700kg/s

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Answer:

My Answer is Answer

Explanation:

We can use Coulomb's equation, which states that the force between two point charges is imparted: due to the other two charges ([tex]\rm Q_1[/tex] and [tex]\rm Q_2[/tex]) to obtain a net force on the +5.0 nC charge ([tex]\rm Q_3[/tex]).

[tex]\rm F = k * |Q_1 * Q_2| / r^2[/tex]

where:

F = force between the charges

k = Coulomb's constant ≈ 9.0 x [tex]\rm 10^9 N.m^2/C^2[/tex]

[tex]\rm Q_1[/tex] and [tex]\rm Q_2[/tex] = magnitudes of the charges

r = distance between the charges

Calculating the forces separately for each pair of charges and then find the net force:

Force between [tex]\rm Q_3[/tex] and [tex]\rm Q_1[/tex]:

[tex]\rm Q_3[/tex] = +5.0 nC = +5.0 x [tex]10^-^9[/tex] C

[tex]\rm Q_1[/tex] = +6.0 nC = +6.0 x [tex]10^-^9[/tex] C

[tex]\rm r_1[/tex] = distance between [tex]\rm Q_3[/tex] and [tex]\rm Q_1[/tex] = √[(0.00 m - 0.30 m[tex])^2[/tex] + (0.00 m - 0.00 m[tex])^2[/tex]] ≈ 0.30 m

[tex]\rm F_1[/tex]= k * |[tex]\rm Q_3[/tex] * [tex]\rm Q_1[/tex]| / [tex]\rm r_1^2[/tex]

[tex]\rm F_1[/tex] = (9.0 x [tex]10^9[/tex] N·[tex]\rm m^2/C^2[/tex]) * |(5.0 x [tex]10^-^9[/tex] C) * (6.0 x [tex]10^-^9[/tex] C)| / (0.30 [tex]\rm m)^2[/tex]

[tex]\rm F_1[/tex]≈ 6.0 N (towards the left)

Force between [tex]\rm Q_3[/tex] and [tex]\rm Q_2[/tex]:

[tex]\rm Q_3[/tex] = +5.0 nC = +5.0 x [tex]10^-^9[/tex] C

[tex]\rm Q_2[/tex] = -1.0 nC = -1.0 x [tex]10^-^9[/tex] C

r2 = distance between Q3 and Q2 = √[(0.00 m - 0.00 m)^2 + (0.00 m - 0.10 m)^2] ≈ 0.10 m

[tex]\rm F_2[/tex] =[tex]\rm k * |Q_3 * Q_2| / r2^2[/tex]

[tex]\rm F_2[/tex] = (9.0 x [tex]\rm 10^9 N.m^2/C^2[/tex]) * |(5.0 x [tex]10^-^9[/tex] C) * (-1.0 x [tex]10^-^9[/tex] C)| / (0.10 [tex]\rm m)^2[/tex]

[tex]\rm F_2[/tex] ≈ 45.0 N (towards the top)

Now we can sum the forces in the x and y directions to determine the net force:

Net force in the x-direction = [tex]\rm F_1[/tex] = 6.0 N (to the left)

Net force in the y-direction = [tex]\rm F_2[/tex] = 45.0 N (upwards)

The Pythagorean theorem can be used to determine the magnitude and direction of the net force.

Magnitude of net force = √(Net force in the x-direction[tex])^2[/tex]+ (Net force in the y-direction[tex])^2[/tex]

Magnitude of net force ≈ √(6.0 N[tex])^2[/tex] + (45.0 N[tex])^2[/tex]≈ √(36 [tex]\rm N^2[/tex] + 2025 [tex]\rm N^2[/tex]) ≈ √(2061 [tex]\rm N^2[/tex]) ≈ 45.4 N

The direction of the net force is the angle θ:

θ = arctan(Net force in the y-direction / Net force in the x-direction)

θ = arctan(45.0 N / 6.0 N) ≈ arctan(7.5) ≈ 82.9°

As a result, the net force exerted by the other two charges on the +5.0 nC charge has a strength of about 45.4 N and is directed about 82.9° above the negative x-axis (in the upper left direction).

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The total resistance of the resistors is R=44Ω. And the current will be I= 0.27 A.

Resistors are electronic components whose main function is to limit the flow of electrical charges by converting electrical energy into thermal energy.

A)The resistances connected in series in an arm of a circuit, total resistance of that arm of is given by algebric sum individual resistances.

R = R1 + R2 + R3 = 12 + 8 + 24 = 44Ω

B) Ohm's law gives that:

V = IR

Where,

(I) = V/R = 12 / 44 = 3/11 = 0.27 A

C) In series combination, all the resistances are connected one after other in a linear fashion. So, current flowing through first resistor passes to second, and then third and so on. Hence, the current flowing through all the resistance in series combination is same as the current flowing through that arm of circuit.

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Answer:

Probs paper cuz the rest are metals

The tension in rope B is determined as 46.17 N.

Tension in rope A is the resultant tension of the rope B and C.

T(C) = T(B) = T

where;

T² + T² = 65.3²

2T² = 4,264.09

T² = 4,264.09/2

T² = 2,132.045

T = √2,132.045

T = 46.17 N

Thus, the tension in rope B is determined as 46.17 N.

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Answer:

tough

ques

Explanation:

Answer:

i don't know if this helps but The refractive index of the material of the prism of an angle 60 degree is 1.62 for sodium light. there you go hope it helps

Explanation:

Answer:

Probably competition with television news-

by 1953 television was becoming common in many houses and people could obtain news from television newscasts

Answer:

m=image distance÷object distance

Answer:

86.47 V

Explanation:

It will be multiplied by the ratio of the windings

980/340 * 30 = 86.47 v

Manufacturers of pails prefer a cone shape because it has a suitable base as well as more space for its contents.

The most common shape of pails is the shape of the frustum of a cone.

Pails are useful to contain liquids as well as some grainy solids like sand.

Because of their unique shapes, pails are able to rest on their bases and also has enough space to contain enough liquid as their top part spreads outwards.

In conclusion, the choice of shape of pails is to ensure they rest on the base and also have enough space for their contents.

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Answer: See below

Explanation:

Given:

Mass of the Mercedes-Benz (m) = 1700 kg

Inclination of the road (θ) = 15.0

The free body diagram is shown in figure attached below

a) The normal force is equal to the cos component of the weight of the car.

[tex]\begin{aligned}&f=m g \cos \theta \\&f=1700 \times 9.81 \times \cos 15 \\&f=16108.74 \mathrm{~N}\end{aligned}[/tex]

b) The static force will be equal to the weight's sin component.

[tex]\begin{aligned}&f=m g \sin \theta \\&f=1700 \times 9.81 \times \sin 15 \\&f=4316.32 \mathrm{~N}\end{aligned}[/tex]

At the top of the circle, the net force on the ball is pointing downward, so that by Newton's second law

[tex]\sum F = -ma \implies F_{\rm tension} + F_{\rm weight} = \dfrac{mv^2}R[/tex]

where [tex]a=\frac{v^2}R[/tex] because the ball is undergoing circular motion with constant speed.

Plug in everything you know and solve for [tex]v[/tex].

[tex]4.0\,\mathrm N + (0.17\,\mathrm{kg}) g = \dfrac{(0.17\,\mathrm{kg})v^2}{0.62\,\rm m} \\\\ \implies v^2 = \dfrac{0.62\,\rm m}{0.17\,\rm kg} \left(4.0\,\mathrm N + (0.17\,\mathrm{kg}) g\right) \\\\ \implies v^2 \approx 21 \dfrac{\mathrm m^2}{\mathrm s^2} \implies \boxed{v \approx 4.5\dfrac{\rm m}{\rm s}}[/tex]

Plug this into the acceleration equation and solve for [tex]a[/tex].

[tex]a = \dfrac{21\frac{\mathrm m^2}{\mathrm s^2}}{0.62\,\rm m} \implies \boxed{a \approx 33\dfrac{\rm m}{\mathrm s^2}}[/tex]

The notation that is commonly used on force diagrams to show forces acting on an object is FD.

A free body diagram is a diagram that contains all the forces acting on an object.

These forces acting on an object include the following :

Thus, the notation that is commonly used on force diagrams to show forces acting on an object is FD.

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The direction of torque τ this method is mathematically given as

D=X  

Option A is correct.

Generally, the equation for torque is  mathematically given as

τ = r X F

Since F is the force exerted on the body at r, we need to know the direction of this torque with regard to the body's center of mass.

In conclusion, the direction of this method is

D=X   Option A.

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The frequency of sound at the given temperature is 200.58 Hz.

The frequency of sound at the given temperature is calculated as follows;

v = fλ

f = v/λ

where;

f = 343/1.71

f = 200.58 Hz

Thus, the frequency of sound at the given temperature is 200.58 Hz.

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1. The amount of work done during the lifting process is 8426.824 J

2. The average power used in the process is 80.26 Watts

Wd = mgh

Wd = 33. 2 × 9.8 × 25.9

Wd = 8426.824 J

P = Wd / t

P = 8426.824 / 105

P = 80.26 Watts

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