Find the radius of a sphere having a volume of 1000000 cm³​

Answers

Answer 1

Answer:

radius is 62.04

Step-by-step explanation:

use the formula V=

[tex] v= \frac{4}{3} \pi {r}^{3} [/tex]


Related Questions

Question 4 of 10
Which of the following is not a condition that must be met before you can use
the quadratic formula to find the solutions of an equation?
A. There can be no term whose degree is higher than 2.
OB. The coefficient of the x²-term can't be zero.
C. The coefficient of the x²-term must be positive.
D. One side of the equation must be zero.

Answers

The condition that must not be met before usage us that the coefficient of the x²-term must be positive.

Equations of quadratic function

The standard quadratic function is given as;

ax²+bx + c = 0

From the equation shown above, the leading degree of the equation is 2. The following are condition that must be met before you can use

the quadratic formula to find the solutions of an equation.

There can be no term whose degree is higher than 2.The coefficient of the x²-term can't be zero.

The condition that must not be met before usage us that the coefficient of the x²-term must be positive.

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What is the volume of this rectangular prism? A rectangular prism with a length of 6 and one-fourth foot, width of 14 feet, and height of 3 feet.

Answers

Answer:

V = 262.5 ft.

Step-by-step explanation:

Volume = length × width × height

6.25 × 14 × 3

6.25 × 42

262.5

A salesperson earns a commission based on the number and type of vehicle sold. A person selling 6 cars and 3 trucks earns $4,800. A person selling 8 cars and 1 truck earns $4,600. How much does a salesperson earn for selling 2 cars and 3 trucks?

$2,500
$2,700
$2,800
$3,000

Answers

4800 divide by 3=1600 (2 cars 1 truck)

4600-1600-3000 (6 cars)

3000 divide by 3 = 1000(2cars)

1000 times 2=2000(4 cars )

4800-2000-2800 (2 cars 3 trucks)

$2,800 is your answer

\Triangles A C B and M Q R are shown. Sides A B and M R are congruent. Angles C A B and M R Q are 42 degrees. Angle C B A is 53 degrees. Angle M Q R is 85 degrees.
Are the triangles congruent? Why or why not?

Yes, all the angles of each of the triangles are acute.
Yes, they are congruent by either ASA or AAS.
No, AngleB is not congruent to AngleQ.
No, the congruent sides do not correspond.

Answers

By the ASA postulate, it can be said that the triangle ABC and triangle MRQ are congruent. Thus, option B is correct, Yes, they are congruent by either ASA or AAS.

What is the angle sum property?

The angle sum property of a triangle states that the sum of the interior angles of a triangle is 180 degrees.

Using Angle Sum Property, in ΔMRQ

<M + <R + <Q= 180

<M + 42 + 85 = 180

<M = 180 -42

<M= 53°

Now, In ΔMRQ and ΔABC  

<A= <R ,

<B = <M

AB = MR

Hence, By ASA criteria ΔMRQ ≅ ΔABC.

Thus, option B is correct, Yes, they are congruent by either ASA or AAS.

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Answer: Yes, they are congruent by either ASA or AAS.

Step-by-step explanation:

find the midpoint of the segment with end points (-2,-1) and (0,9)

Answers

Answer:

-1 , 4

Step-by-step explanation:

x = ( -2 + 0 ) ÷ 2

y = ( -1 + 9 ) ÷ 2

-2 ÷ 2 = -1

8 ÷ 2 = 4

( -1 , 4 )

In which of the following intervals does the trigonometric inequality sec(x) < cot(x) always hold true.

Answers

The inequality for sec (x) < cot (x) is;  π/2 < x < π

How to express trigonometric inequality?

We are given that;

We want to find the intervals that the trigonometric inequality sec (x) < cot (x) always hold true.

This can also be expressed as;

1/cos (x) < 1/tan (x)

Now, this can happen only in the quadrant where tan (x) is negative and cos x is positive which is in fourth quadrant where;

π/2 < x < π

The inequality for sec (x) < cot (x) is;  π/2 < x < π

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Answer:

C on edge 22 for Pre-Calculus

Step-by-step explanation:

pi < x< 3pi/2

I retook the unit test, put C, and got a 100. I promise it's right

If the long hand of a clock is 11 and short hand is 9what is the time .help please​

Answers

9:55, am or pm. This can be am or pm because the question never specified

Raj and Aditi like to play chess against each other. Aditi has won 12 of the 20 games so far. They decide to play more games.
How many more games will Aditi have to win to have a 70% winning record?
12 + x = 0.70(20 + x)
x = x equals StartFraction 20 Over 3 EndFraction is approximately 6.67. ≈ 6.67
She will have to win 7 more games to have a 70% winning record.
How many more games will Aditi have to win to have an 80% winning record?
The linear equation that models this is .
Aditi would have to win more games to have an 80% winning record.

Answers

The linear model is 12 + x = 0.80(20 + x)

Aditi would need to win is 20.

How many more games does Aditi have to win?

Given this linear model: 12 + x = 0.80(20 + x)

Take the following steps in order to determine the value of x:

Expand the bracket : 12 + x = 16 + 0.8x

Combine like terms: 16 - 12 = x - 0.8x

Add similar terms: 4 = 0.2x

Divide both sides by 0.2 : 4/ 0.2

x = 20

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Answer:

the first answer would be C and the second is B I  think

Step-by-step explanation:

based off what I just did so 20 is the second answer aka B lol

The ratio of vina's age to jill is 7:6.if vina is 4 years older than jill,how old is jill

Answers

jill is 24 years old.

What is ratio ?A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0. A proportion is an equation in which two ratios are set equal to each other. For example, if there is 1 boy and 3 girls you could write the ratio as: 1 : 3 (for every one boy there are 3 girls).

The ratio of vina's age to jill is 7:6 .

      Let vina's age =7x

      let jill's age = 6x

If vina is 4 years older than jill.

Then ,                   7x - 6x = 4

                                  x = 4

Now  vina's age = 7x = 7 * 4 = 28 years

          jill's age = 6x = 6 * 4 = 24 years.

Therefore, jill is 24years old.

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I need help desperately! Could someone explain this math concept for me please?

Answers

The inequality that represents the range of k so that inequality 1 has real solution is -3 < k < 5

How to determine the range?

Inequality 1

x^2 + (k + 1)x + k + 4 > 0

The discriminant is calculated using

D = b^2 - 4ac

So, we have:

D = (k + 1)^2 - 4 * 1 * (k + 4)

Evaluate

D = k^2 + 2k + 1 - 4k - 16

This gives

D = k^2- 2k - 15

Factorize the equation

D = (k+ 3)(k -5)

Solve for k

k = -3 and k = 5

Express the k values as inequalities

-3 < k < 5

Inequality 2

The inequality cannot be read, because of the image quality

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Plis help! Will give brainliest!

Answers

Answer:

Q1: 62

Q2: 13

Step-by-step explanation:

Just follow Order of operations, and you get the answers.

P arenthesis

E xponents

M ultiplication

D ivision

A ddition

S ubtraction

Which compares the medians of the data? the median for the students is 4 and the median for the teachers is 8. the median for the students is 2 and the median for the teachers is 3. the median for the students is 4 and the median for the teachers is 3. the median for the students is 2 and the median for the teachers is 8.

Answers

(B) The median for the students is 2 and the median for the teachers is 3, comparing the medians of the data.

What is a median?The median is the value that separates the upper and lower halves of a data sample, population, or probability distribution in statistics and probability theory. It is sometimes referred to as "the middle" value in a data set. The main difference between the median and the mean in summarizing data is that the median is not skewed by a tiny fraction of exceptionally big or small values, and thus provides a better depiction of a "typical" value. Because income distribution can be distorted, median income may be a better approach to illustrate what a "normal" income is.

Therefore, the median for the students is 2 and the median for the teachers is 3, comparing the medians of the data.

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Correct question:

Which compares the medians of the data?

(A) The median for the students is 4 and the median for the teachers is 8.

(B) The median for the students is 2 and the median for the teachers is 3.

(C) The median for the students is 4 and the median for the teachers is 3.

(D) The median for the students is 2 and the median for the teachers is 8.

help me please maths
A. 64
B. 1/12
C. 1/64
D. 12​

Answers

Answer:

Step-by-step explanation:

First, since they have the same base, you can join them. Because it is division, you have to subtract the exponents.

4^(-11/3 -(-2/3)) = 4^-9/3 = 4^-3

Negative exponents turn the base into a fraction and 4^3= 64

so the answer is C. 1/64

Jake kept track of the number of minutes it took him to assemble sandwiches at his
restaurant.
Number of
sandwiches
Minutes
1
3
2
4
4
5
6
6
7
7

Answers

45 is the correct answer for your phone

Please do these questions for me separately(in the picture)

Answers

Based on the cost of each of the snacks in a s'more, the number that the summer camp counselor can make is E.10.

The total change in temperature on the surface of Mercury is C. 1,168°F.

What is the total s'mores that can be made?

First, find out the cost of one s'more:
= (2 x 0.50) + 0.75 + (2 x 1.25)

= 1 + 0.75 + 2.50

= $4.25

The total s'mores that can be made is:

= 45 / 4.25

= 10 complete s'mores

What is the change in temperature?

= 869 - (-299)

= 869 + 299

= 1,168°F

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Find the area of a rhombus.
4
30°

Answers

Answer:

[tex]13.86[/tex]

Step-by-step explanation:

you should see 2 triangles with angle 60 bounded by two equal sides of 4

[tex]=2(\frac{1}{2} (4)(4)sin 60)\\=13.86[/tex]

hey can you please give me the answer to this?

Answers

The height of the tower is 452.66 ft

What is angle of elevation and depression?

The angle formed by the line of sight and the horizontal plane for an object above the horizontal.

The angle of depression is the angle between the horizontal line and the observation of the object from the horizontal line.

Given:

we have two angles one of which is angle of elevation and another angle depression.

Using trigonometric ratio,

tan ∅ = P / B

tan 32° = h / 425

0.624= h /425

h= 265.569 ft

again,

tan 29° = h(bottom of the tower) / 425

h(bottom of the tower) = 425 × tan 29°

h(bottom of the tower)  = 235.581 ft

Thus, Height of tower = h(top of the tower) + h(bottom of the tower)

Height of tower = 265.569  + 235.581

Height of tower = 501.15 ft

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Helppp!!!
Lynn is putting tiles on her bathroom floor. Each tile measures 1 square foot each. The floor measures 4 1/2 ft by 3 3/4 ft. How many tiles will she need to cover the floor?

Answers

The number of tiles Lynn needs to cover the floor with an area of 16.875 ft² is 17 tiles

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

The floor measures 4 1/2 ft by 3 3/4 ft.

Hence:

Area of floor = 4 1/2 ft * 3 3/4 ft = 9/2 ft * 15/4 ft = 16.875 ft²

Each tile measures 1 square foot each, hence:

number of tiles needed = 16.875 ft² / 1 ft² per tile = 16.875 tiles ≅ 17 tiles

The number of tiles Lynn needs to cover the floor with an area of 16.875 ft² is 17 tiles

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What is the total number of digits used when the first 2002 positive even integers are written?

Please help, 25 points.

Answers

The total number of digits used when the  first 2002 positive even integers are written is 4 digits

How to find the number of sequence?

Using arithmetic sequence,

nth term = a + (n - 1)d

where

a = first termd = common differencen = number of terms

a = 2

d = 2

nth term = 2 + (2002 - 1)2

nth term = 2 + 4002

nth term = 4004

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in poker, a royal flush is a hand with the ace, king, queen, jack and 10 of all one suit and is the best possible hand in the game. what is the probablity of a royal flush in a 5 card hand

Answers

The probability of a royal flush in a 5-card hand is 1/649740 or 0.0001539%.

The combination is a way of selecting a smaller number of sets from a larger number of sets in no particular order.

If selecting r items from a set of n items, in no particular order, we use combinations, using the formula:

nCr = n!/{r!(n - r)!}.

In the question, we are asked the probability of a royal flush in a 5 card hand.

The number of ways of selecting 5 cards from a deck can be computed using a combination, 52C5, as we have 52 cards in a deck, 5 cards are to be chosen and the order is not in concern.

52C5 = 52!/{5!(52 - 5)!} = 52!/(5!.47!) = (52*51*50*49*48)/(5*4*3*2*1) = 2598960.

The number of hands that make a royal flush is only 4. 4 from each suit.

Therefore, the probability = 4/2598960 = 1/649740 or 0.0001539%.

Therefore, the probability of a royal flush in a 5-card hand is 1/649740 or 0.0001539%.

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Divide:

5 x minus 8 StartLongDivisionSymbol 45 x squared minus 42 x minus 48 EndLongDivisionSymbol

Which of the following represents the length of the rectangle?


9x - 48

9x - 23

9x - 6

9x + 6

Answers

The length of the Rectangle is 9x +6 , Option D is the right answer.

What is a Rectangle ?

A rectangle is a polygon with four sides , four angles and four vertices , The opposite sides are parallel and equal .

An expression representing the area of Rectangle is given

One of the side is 5x -8

The other side =  ?

As Area of Rectangle =  Length * Breadth

It can be calculated by Dividing Area by Breadth

(45x² - 45x -48 ) / (5x -8)

= 9x +6

Therefore the length of the Rectangle is 9x +6 ,Option D is the right answer.

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Answer:

9x + 6
INCLUDED WHOLE PAGE!!

EDGE2022; Good Luck :3!!!

find the area of the shaded regions.

Answers

Answer: [tex]7\pi[/tex]

Step-by-step explanation:

The area of the entire circle is [tex](\pi)(3^{2})=9\pi[/tex]

The area of each of the smaller circles is [tex](1^{2})(\pi)=\pi[/tex], so their combined area is [tex]2\pi[/tex].

By subtracting areas, we get the area of the shaded region is [tex]7\pi[/tex].

A box contains 72 cups of fruit juice. one serving size is 12 cup. how many servings can be made from the fruit juice?

Answers

Answer:

6 servings

Step-by-step explanation:

Box = 72 cups

1 serving size = 12 cups

72 ÷ 12 = 6

What's Part of a 1 minute and 5 seconds?

Answers

62.5 seconds

Step-by-step explanation:

What is the range of the function on the graph? O all real numbers Oall real numbers less than or equal to 1 O all real numbers less than or equal to 3 all real numbers less than or equal to 0​

Answers

The range of the function on the graph is (c) all real numbers less than or equal to 3

How to determine the range?

The missing graph is added as an attachment

From the graph, we have the following highlights

The highest y value is 3Other y values do not exceed 3

This means that the range is (c) all real numbers less than or equal to 3

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6xp 6xp 6xp 6xp 6xp 6xp 6xp 6xp 6xp 6xp 6xp 6xp 6xp 6xp 6xp 6xp 6xp 6xp 6xp 6xp 6xp 6xp 6xp 6xp

Answers

The answer is 6xp^24

Answer:

6xp^24

Step-by-step explanation:

Basically, there is 24 6xp's which is 6xp^24.

Hope I explained well enough.

Counting by thousands, write five numerals from 1578 onwards.​

Answers

2578,3578,4578,5578,5678

Answer:

1578 + 1000 = 2578

2578 + 1000 = 3578

3578 + 1000 = 4578

4578 + 1000 = 5578

5578 + 1000 = 6578

Please answer the given question

Answers

there are total 64 is the answer if she puts 2 cookies in each packet

hope this helps u :)

42 = 2 • 3 • 7 = 2 • 21
86 = 2 • 43
Then
GCF(86 , 43) = 2
Then the greatest number of packages, she can make is 2
Each has 21 sugar cookies and 43 chocolate chips cookies.

The amount of algae covering the Smith's backyard pond doubled every day until it was completely covered in algae on day $30$ of the month. On what day of that month was $75%$ of the pond algae-free?

Answers

The day of the month that was 75% of the pond algae-free is: on day 28 or third day.

75% of the pond algae-free

Since we were told the algae  doubled every day until it was  covered in algae on day 30 of the month.

Hence:

Day 30 (First day)= It was 100% covered.

Day 29 (Second day)=It was 50% covered.

Day 28 (Third day )=it was 25% covered, which will be the same as 75% pond algae-free.

Therefore the day of the month that was 75% of the pond algae-free is: on day 28 or third day.

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The complete question is:

amount of algae covering the Smith's backyard pond doubled every day until it was completely covered in algae on day 30 of the month. On what day of that month was 75% of the pond algae-free?

Part b assume the statement is true for n = k. prove that it must be true for n = k + 1, therefore proving it true for all natural numbers, n. t hint: since the total number of dots increases by n each time, prove that d (k) + (k + 1) = d(k+1).

Answers

The he statement d(k) + (k + 1) = d(k+1) is true for all natural numbers, n, by mathematical induction.

To prove that the statement is true for all natural numbers, n, we can use mathematical induction.

The statement we want to prove is that d(k) + (k + 1) = d(k + 1), where d(n) represents the total number of dots in a pattern of n squares.

Base Case (n = 1):

First, let's prove the statement for the base case, n = 1.

For n = 1:

d(1) + (1 + 1) = d(1) + 2

Now, consider a single square with 1 dot.

In this case, d(1) = 1.

So, we have:

1 + 2 = 3

Now, let's consider a pattern of 2 squares (n = 2).

The first square has 1 dot, and the second square has 2 dots. So, d(2) = 1 + 2 = 3.

So, the statement is true for n = 1.

Inductive Hypothesis (Assume true for n = k):

Now, assume that the statement is true for some arbitrary natural number k.

That is, assume that: d(k) + (k + 1) = d(k + 1)

Inductive Step (Prove true for n = k + 1):

To prove that the statement is true for n = k + 1.

d(k + 1) + (k + 2) = d(k + 2)

Now, consider a pattern of (k + 1) squares.

By the inductive hypothesis, assume that the statement is true for k squares:

d(k) + (k + 1) = d(k + 1)

Now, let's add one more square to the pattern.

This square will have (k + 2) dots.

So, the total number of dots in the pattern of (k + 1) squares plus the (k + 2) dots in the additional square is:

d(k + 1) + (k + 2)

And by the inductive hypothesis, d(k) + (k + 1) = d(k + 1).

Therefore:

d(k + 1) + (k + 2) = (d(k) + (k + 1)) + (k + 2) = d(k) + (k + 1) + (k + 2)

Now, simplify:

d(k + 1) + (k + 2) = d(k + 1) + (k + 1 + 1)

So, it is shown that for n = k + 1, d(k + 1) + (k + 2) = d(k + 1) + (k + 1) + 1.

Since it is assumed the statement to be true for k and proved it for k + 1, it is shown that the statement is true for all natural numbers, n, by mathematical induction.

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