there are 3.0 x 10^22 molecules of sucrose in a sample. how many grams of sucrose is this? The molar mass of C12H22O11 is about 342 g

Answers

Answer 1

The amount of sucrose in the sample would be 17 grams

Number of molecules of substances

There are 6.022 x [tex]10^{23}[/tex] molecules in 1 mole of every substance.

3.0 x [tex]10^2^2[/tex] molecules will, therefore, be:

                    1 x 3.0 x [tex]10^2^2[/tex]/6.022 x [tex]10^{23}[/tex] = 0.0498 moles

Mass of 0.0498 moles sucrose = 0.0498 x 342 = 17 grams

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Related Questions

mention one real life significance of the covalent bond.​

Answers

Answer:

it helps in respiration

Please help i dont have much time cause i have to give it in soon :,)
Balance the following neutralization reactions:
_______ HBr + _______ KOH _______KBr + _______H2O

_______ HF + _______ Fe(OH)3 _______FeF3 + ______ H2O

______HCl + _______ Ca(OH)2 _______CaCl2 + ______ H2O

Answers

Answer:

HBr + KOH = KBr + H2O

3 HF + Fe(OH)3 = FeF3 + 3 H2O

2 HCl + Ca(OH)2 = CaCl2 + 2 H2O

Explanation:

2. A chemical analysis of a sample provides the following elemental data:

364.8 g C
61.2 g H
324.0 g 0

Determine the empirical formula for this compound.

Answers

Answer:

C3 H6 O2

Explanation:

first divide their mass by their respective molar mass, we get:

30.4 moles of C

61.2 moles of H

20.25 moles of O

now divide everyone by the smallest one of them then we get

C= 1.5

H= 3

O= 1

since our answer of C is not near to any whole number so we will multiply all of them by 2

so,

C3 H6 O2 is our answer

The vapor pressure of water at 25c is 23.76 torr. if 1.25g of water is enclosed in a 1.5l container, will any liquid be present? if so, what mass of liquid?

Answers

Mass of liquid present in the container:

Yes, the liquid will be present, and of 1.2481 g

Calculation:

Given:

Volume = 1.5L

Temperature = 25 + 273 = 298K

P = 23.76 torr = 0.0312 atm

Using the ideal gas equation:

PV = nRT

Where:

P: PressureV: Volumen: number of molesR: gas constant = 0.0821 L atm [tex]K^{-1}[/tex] [tex]mol^{-1}[/tex]T: Temperature

making n subject of formula:

n = [tex]\frac{PV}{RT}[/tex]

By putting all the values in the given equation, we get,

n = 0.0312 x 1.5 / 0.0821 x 298

n = 0.0019 moles

So, 0.00189 are moles of water in the vapor

Now, subtract  1.25g of water from moles of water vapor, and we will get the mass of the liquid left,

1.25 - 0.0019 = 1.2481 g

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A laboratory assistant needs to prepare 35.2 liters of hydrogen at 25.0°c and 101.3 kilopascals. this is the equation for the reaction: 2hcl ca → h2 cacl2 what volume of 2.3 m hydrochloric acid is required to produce this much gas? use the ideal gas resource.

Answers

Volume of hydrogen gas = 35.2L

Temperature of hydrogen gas = 25.0°C + 273 = 298 K

Pressure of hydrogen gas = 101.3 kPa = 1 atm

(Conversion factor 1 atm = 101.325 kPa)

Using the Ideal gas law,

PV = nRT

where P, V, n, R and T are pressure, volume, number of moles, universal gas constant and temperature respectively.

n = PV/RT

The number of moles of hydrogen gas,

n = 35.2 L x 1 atm/ 0.0821 L.atm.mol⁻¹1.K⁻¹ x 298 K

n = 1.438 moles

2HCl + Ca → H₂ + CaCl₂

Based on the given balanced equation, 1 mole of H₂ is produced from two  moles of HCl.

Since H₂ is 1.438 moles, HCl will be (1.438 x 2) moles or 2.876 moles

Given, Molarity of HCl = 2.3 M

Molarity = moles of solute / liter of the solution

Thus the volume of HCl is,

2.3 M = 2.876 moles / liter of the solution

V = 2.876 moles / 2.3 M

V = 1.25 L

Thus the volume of 2.3 M hydrochloric acid required to produce the given amount gas is 1.25 L.

A solution is made by diluting 20.0 mL of propanone (C3H6O) with water. The total volume of the solution is 300 mL. What is the percent by volume of propanone in the solution

Answers

The percent by volume of propanone in the solution is  6.6 % .

Given:

Volume of solute ([tex]C_{3} H_{6} O[/tex]) = 20.0 mL

Volume of solution = 300 mL

To calculate the percent:

% by vol= (vol solute/vol of soln) x 100

             = (20mL C₃H₆O/300mL) x 100

             = 6.6 % propanone .

Therefore, the percent by volume of propanone in the solution is  6.6 %.

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How many H2O molecules are there in 4.5 g of water (see picture)

Answers

answer is B.
number of mole of water = 4.5/18 = 0.25mol
number of h2o molecules = 0.25 x 6.02 x 10^23 to get option B

Experiments were done on a certain pure substance ex to determine some of his properties there’s a description of each experiment and the table below the side whether the experiment was a physical or chemical property

Answers

Answer:

1.) Physical

2.) Physical (probably)

3.) Chemical

Explanation:

Physical changes are changes to substances in which the intramolecular structure does not change. The intermolecular bonds (bonds between molecules) may change, but the actual chemicals involved are not altered.

Chemical changes occur when intermolecular bonds are broken/formed, changing the old substance into something new. Chemical reactions are taking place and the ratio of the elements in molecules are changing.

1.) Melting is an example of a physical change. When melting occurs, the intermolecular bonds between molecules are breaking in response to the introduction of more heat. However, the substance is still the same substance (ex. ice melting is still water as H₂O has not been changed). In this example, scientists are most likely calculating velocity.

2.) Because the original substance is able to be completely removed from the water in the flask, this is probably just a physical change. I say probably because no changes are really occurring here. It is unclear but not probably that any reactions are taking place between the water and the sample as they are easily separated. This may be an example of (can't decide) depending on how must they want you to assume. The property being measured is probably density.

3.) While dissolving the sample was an example of a physical change because just the state of matter changed, when it reacts with sodium hydroxide, a chemical change occurs. Most likely, new bonds are being formed between the elements in the original sample and the elements in sodium hydroxide. This is what allows scientists to measure the pH of a solution.

i will mark brainliest. Calculate the wavelength corresponding to a frequency of 98.8MHzl​

Answers

Answer:

3.0395m

Explanation:

PLEASE HELP !!!
Which two elements have the same number of dots around their chemical symbols in their electron dot diagrams.

Answers

The two elements have the same number of dots around their chemical symbols in their electron dot diagrams are: (C). P and As

Meaning of chemical symbols

Chemical symbol can be defined as a representation of an element using letters.

Chemical symbol are given to each element distinctively and this is an easier way to represent an element.

Some examples of chemical symbols are; O for oxygen, Zn for zinc, and Fe for iron etc.

In conclusion, The two elements have the same number of dots around their chemical symbols in their electron dot diagrams are: (C). P and As

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The half-life of 131I is 80 days. How much of a 500.0 mg sample remains after 3 half lives?

Answers

Answer:

62.5 mg

Explanation:

Just multiply the original amount by  1/2   three times:

500 mg  x  1/2  x  1/2  x  1/2 = 62.5 mg

What would be the vital capacity be for a man that has a tidal volume of 500mL, a residual volume of 1100 mL, an expiratory reserve of 1100 mL and an inspiratory reserve of 3000 mL

Answers

The vital capacity will be 4600ml.

What is vital capacity?

The highest amount of air a person can inhale following their maximal exhalation is known as their vital capacity. It is equivalent to the total of the inspiratory, tidal, and expiratory reserve volumes. It roughly corresponds to Forced Vital Capacity. A wet or conventional spirometer can assess a person's vital capacity.

Normal people have a 3 to 5-liter vital capacity.

It enables simultaneous inhalation of the greatest possible volume of clean air and exhalation of the greatest possible volume of stale air. So, by increasing gaseous exchange between the body's various tissues, it improves the amount of energy available for bodily function.

VC = TV₊IRV₊ERV

where,

VC = Vital capacity

TV = Tidal volume

IRV = inspiratory reserve volume

ERV = expiratory reserve volume

VC = 500 ₊ 3000 ₊ 1100

VC = 4600ml

Therefore, the vital capacity will be 4600ml.

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True or false? the water-soluble portion of a phospholipid is the polar head, which generally consists of a glycerol molecule linked to a phosphate group.

Answers

this answer would be true.

A helium-filled balloon has a volume of 10 000 L at 20°C. Determine the volume of the
gas at 25 °C

Answers

Answer:

12,500 L

Explanation:

Because you are dealing with volume and temperature, you need to Charles' Law to find your missing value. The equation looks like this:

V₁ / T₁ = V₂ / T₂

In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. You can plug the given values into the equation and simplify to find the final volume of the gas.

V₁ = 10,000 L                 V₂ = ? L

T₁ = 20 °C                       T₂ = 25 °C

V₁ / T₁ = V₂ / T₂                                             <----- Charles' Law equation

(10,000 L) / (20 °C) = V₂ / (25 °C)                <----- Insert values

500 = V₂ / (25 °C)                                        <----- Divide 20 from 10,000

12,500 = V₂                                                 <----- Multiply both sides by 25

explain a method in which ethanol is made non combustible to humans after exploring the information through relevant sources​

Answers

Answer:

Ethanol can be produced by fermentation and concentrated using fractional distillation .

Oxidizing acids, such as nitric acid, can explode when mixed with what type of incompatible chemical

Answers

Oxidizing acids can explode when mixed with incompatible chemical such as alcohols, turpentine, charcoal, organic refuse.

Why Oxidizing acids can explode when mixed with incompatible chemical?

Oxidizing acids reacts violently with combustible such as alcohols, turpentine, charcoal, organic refuse because when it reacts with most metals, it release hydrogen gas in the air.

So we can conclude that Oxidizing acids can explode when mixed with incompatible chemical such as alcohols, turpentine, charcoal, organic refuse.

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What is the function of the structure labeled Y?

to keep oxygen-rich blood and oxygen-poor blood flowing
to filter waste materials from oxygen-poor blood
to filter waste materials from oxygen-rich blood
to keep oxygen-rich blood and oxygen-poor blood separate

Answers

The function of Y would be to keep oxygen-rich blood and oxygen-poor blood separate. The last option is the correct one.

Function of the Septum

Y is the septum

The septum is a structure of the heart that separates the left atrium from the right atrium as well as the two ventricles.

Thus, the structure prevents oxygenated blood from mixing with deoxygenated blood.

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The conversion of 1 mol of fructose 1,6-bisphosphate to 2 mol of pyruvate by the glycolytic pathway results in a net formation of:

Answers

Net Product formed:

The conversion of 1 mol of fructose 1,6-bisphosphate to 2 mol of pyruvate by the glycolytic pathway results in a net formation of  2 mol of NADH and 4 mol of ATP.  

Glycolysis:

The energy-intensive stages also known as the first half of glycolysis. It divides the six-carbon sugar molecule evenly into two three-carbon molecules. The energy-releasing stages, or the second half of glycolysis, draw energy from the molecules and store it as ATP and NADH, the reduced form of NAD.

Two pyruvate molecules form the final product of glycolysis, which begins with glucose and two ATP molecules and two NADH molecules are gained by the cell as a net result.

The first half of the process requires the utilization of two ATP molecules to set up the six-carbon ring for cleavage. But since this pathway is starting from fructose 1,6-bisphosphate, the utilization step is omitted thus four molecules of ATP and two molecules of NADH are produced in total.

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Increasing which factor will cause the gravitational force between two objects to decrease?
weights of the objects
distance between the objects
acceleration of the objects
masses of the objects

Answers

Answer:

mass increase!

Explanation:

<3

Answer:

b.distance between the objects

Explanation:

If you pull objects apart from each other they don't have as strong of a gravitational pull. think of it like a magnet the heavier the magnets the more power they can hold, the bigger they are the more surface area they have, and when you pull 2 magnets apart they slowly come weaker to each other.

Classify the chemical reaction: Cl₂O5 + H₂O → 2HCIO3

Answers

The reaction is an addition reaction.

What is an addition reaction?

Addition reactions are chemical reactions involving 2 or more reactants reacting to produce a single product.

Addition reactions are different from decomposition reactions. In the latter, a single reactant decomposes to give two or more products.

In the illustrated reaction, Cl₂O5 and H₂O react together to form a single product, HCIO3.

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calculate the electrons in 2.3 kg sodium

Answers

Answer:

6.627 x10^26    electrons

Explanation:

Each Na atom has 11 electrons

Mole weight = 22.989 gm/mole  

2300gm /22.989 gm/mole * 6.022 x 10^23  atoms/mole  * 11 electrons/atom

     = 6.627 x 10 ^26   electrons  

In an electrolytic cell, the electrode that acts as a source of electrons to the solution is called the __________; the chemical change that occurs at this electrode is called __________.

Answers

In an electrolytic cell, the electrode that acts as a source of electrons to the solution is called the cathode; the chemical change that occurs at this electrode is called reduction.

Define Electrolyte:-

An electrolyte is a material that separates into charged ions when it is in contact with water. Cations are positively charged ions. Anions are ions that are negatively charged. A substance that may conduct an electric current when melted or dissolved in water is known as an electrolyte.

Electrochemical cell

There are three main categories of electrochemical cells. the galvanic cell, the concentration cell, and the electrolytic cell. These cells all share the same four fundamental components. These are the elements

The electrolyte serves as the conduit for current flow between the anode and the cathode. In an aqueous solution, it normally is homogeneous, but in moist soil, the concentration or kind of dissolved compounds may vary locally.The anode, which can conduct electricity and is in contact with the electrolyte, corrodes when it combines with the chemicals in the electrolyte.A metal also contacts the electrolyte at the cathode. It is protected from corrosion rather than corroded.Anode and cathode are connected by the conductor, which also completes the circuit.

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Protons Ha and Hb in the compound given are _________. homotopic enantiotopic diastereotopic mesotopic none of these

Answers

Protons Ha and Hb in the compound given are enantiotopic.

What are enantiotopic protons?

Enantiotopic protons can be defined as those protons that can be replaced by another groups like deuterium.

What is a compound?

A compound is a substance which contains two or more elements chemically combined together.

So therefore, Protons Ha and Hb in the compound given are enantiotopic.

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What type of system is a home, school, or room?

Answers

Answer:

room

Explanation:

because it'd in your house and u go there everyday and sleep and live there

The Ksp of Al(OH)3 is 2.0 x 10-31 at 298 K. What is \DeltaGo (at 298 K) for the precipitation of Al(OH)3 according to the equation below?

Al3+(aq) + 3OH- (aq) -> Al(OH)3 (s)

Answers

ΔG° = -RT ln K

ΔG° = -RT ln 1/Ksp (reverse reaction, solid (Al(OH)₃ not count for equilibrium constant-K)

ΔG° = -RT ln 1/Ksp

ΔG° = -8.314 x 10⁻³ x 298 ln 1/(2 x 10⁻³¹)

ΔG° = -175.132 kJ/mol

Which type of molecule is shown below?

O A. Alkane

B. Cyclic alkane

C. Alkene
O
D. Alkyne

Answers

Answer:

[tex]\huge\boxed{\sf Alkene}[/tex]

Explanation:

The molecule shown is an Alkene, since:

There is a double bond between the carbon atoms.

[tex]\rule[225]{225}{2}[/tex]

Using a chemical equation to find moles of the product for moles of reactant

Answers

Answer:

0.10 moles H₂O

Explanation:

The unbalanced equation:

NH₃ (g) + O₂ (g) ----> NO (g) + H₂O (g)

Reactants: 1 nitrogen, 3 hydrogen, 2 oxygen

Products: 1 nitrogen, 2 hydrogen, 2 oxygen

The balanced equation:

4 NH₃ (g) + 5 O₂ (g) ----> 4 NO (g) + 6 H₂O (g)

Reactants: 4 nitrogen, 12 hydrogen, 10 oxygen

Products: 4 nitrogen, 12 hydrogen, 10 oxygen

Now that the reaction is balanced, you can use the coefficients of the desired molecules to construct the mole-to-mole ratio. This ratio should be multiplied by the given value (0.085 moles). It is important to arrange the ratio in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 2 sig figs to match the given value.

0.085 moles O₂          6 moles H₂O
-------------------------  x  ------------------------  =  0.10 moles H₂O
                                      5 moles O₂

A sample of a gas is occupying a 1500 ml container at a pressure of 3.4 atm and a temperature of 25 oc. if the temperature is increased to 75 oc and the volume is increased to 2000 ml, what is the new pressure?

Answers

The new pressure will be 7.65 atm

General gas law

The problem is solved using the general gas equation:

P1V1/T1 = P2V2/T2

In this case, P1 = 3.4 atm, V1 = 1500 mL, T1 = 25 [tex]^O C[/tex], V2 = 2000 mL, and T2 = 75  [tex]^O C[/tex]

What we are looking for is P2.

Thus, P2 = P1V1T2/T1V2

          = 3.4 x 1500 x 75/25 x 2000 = 382500/50000 = 7.65 atm

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What is the chemical formula for acetic acid?
O CHO
O C₂H4O2
O C₂OH
O C₂0₂H

Answers

Answer:

The answer is C2H4O2

Hello people ~
help me with the question attached.
Thanks in advance.​

Answers

Answer:

[tex]\fbox {(2) 4.9}[/tex]

Explanation:

Applying the Ideal Gas Equation :

[tex]\boxed {PV = nRT}[/tex]

Finding n :

n = 64 g / 32 g/mole (Oxygen is diatomic)n = 2 moles

Solving for P :

P = 2 × 0.0831 × 300 / 10 (Temp. should be converted to K)P = 60 × 0.0831P = 4.9

The pressure inside the flask in bar is 4.9.

Moles of oxygen

Given mass/Molar mass64g/32g/mol2mol

Temperature=273+27=300K

Apply ideal gas equation

PV=nRTP=nRT/VP=2(0.0831)(300)/10P=4.9bar
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