The exact value of sin θ and cos θ is: sinθ =(√105)/19 and cosθ =16/19
The terminal side of an angle is the angle at the standard position. The terminal side of an angle θ drawn in angle standard position is the side which isn't the initial side.
Given that the point of intersection of the terminal side of θ an the unit circle is:
(16/19,y)
The exact value of sin θ and cos θ is: sinθ =(√105)/19 and cosθ =16/19
The given parameters is represented by:
(16/19,y)
This means that :
(cosθ ,sinθ )=(16/19,y)
Using the following trigonometric identity:
cos²θ +sinθ =1
We have:
(16/19)²+y²=1
Expand fraction:
(256/361)+y²=1
Collect like terms:
y²=1-(256/361)
Take LCM:
y²=(361-256)/361
y²=105/361
Take square roots
y=(√105)/19
Substitute value for y in
(cosθ ,sinθ )=(16/19,y)
By comparison:
cosθ =16/19
sinθ =(√105)/19
So the exact value of sin θ and cos θ is: sinθ =(√105)/19 and cosθ =16/19
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please help me asap thank you so so much u are so amazing!!
2. How is the graph of g(x)=x³-1 related to the graph
of f(x)=x³?
A. The graph of g(x) is a translation of the
graph of f(x) down 1 unit
B.
The graph of g(x) is a translation of the
graph of f(x) down 1 unit and a reflection
across the x-axis.
C. The graph of g(x) is a translation of the
graph of f(x) left 1 unit and a reflection
across the y-axis.
Answer:
[tex]A[/tex]
Step-by-step explanation:
Indeed, the graph of [tex]f(x)[/tex] underwent only one change:
[tex]f(x) = x^3 \Leftrightarrow g(x) = f(x) - 1 = x^3 - 1[/tex].
Take a look at the attachments in order to follow the process.
To collect data from a number of people in a sample, use a/an ___________________. A. questionnaire B. group chart C. question log D. long form
To collect data from a number of people in a sample, use a questionnaire
What are questionnaires?Questionnaires are quantitative method used in research for information collection purpose.
This questionnaires consists of several question necessary to provide answers and solution to research questions and for the purpose of analysis. These questions can be open or closed ended questions depending on the nature of research.
Hence we can conclude that. to collect data from a number of people in a sample, use a questionnaire
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PLEASE ANSWER AS FAST AS POSSIBLE PLEASE! I WILL MARK BRAINLIEST!
Three equations are listed below.
*y=x(3x+2)
*y= x/3+2
*y=2-3x
IDENTIFY ONE LINEAR EQUATION AND ONE NONLINEAR EQUATION FROM THE LIST. STATE A REASON WHY EACH QUESTION YOU IDENTIFIED IS LINEAR OR NON LINEAR.
1. WHAT IS THE LINEAR EQUATION?
WHY IS THAT THE LINEAR EQUATION
2. WHAT IS THE NONLINEAR EQUATION
WHY IS THAT THE LINEAR EQUATION
please finish this, i hate math.
Answer:
WHAT IS THE LINEAR EQUATION?
y=2-3x and y=x/3+2
WHY IS THAT THE LINEAR EQUATION
Linear functions are those whose graph is a straight line. A linear function has one independent variable and one dependent variable. The independent variable is x and the dependent variable is y
WHAT IS THE NONLINEAR EQUATION
Y = x(3x+2)
WHY IS THAT THE LINEAR EQUATION
A nonlinear function has more than one independent variable. The independent variable is x.
y= x(3x-2) is non linear equation.
y= x/3 + 2 is linear equation.
y= 3 -2x is linear equation.
What is Linear Equation?Linear equations are the equations of degree 1.
It is the equation for the straight line.
The standard form of linear equation is ax+by+c =0, where a ≠ 0 and b ≠ 0.
We know that the linear equation have highest degree 1.
First, y= x(3x-2)
y= 3x² -2x
Here, the highest degree is 2 which is non linear equation.
Now, y= x/3 + 2 have highest degree 1 which is linear equation.
and, y= 3 -2x have highest degree 1 which is linear equation.
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Beginning inventory, purchases, and sales for WCS12 are as follows:
Oct. 1 Inventory 300 units at $12
13 Sale 190 units
22 Purchase 390 units at $15
29 Sale 300 units
a. Assuming a perpetual inventory system and using the weighted average method, determine the weighted average unit cost after the October 22 purchase. Round your answer to two decimal places.
The weighted average unit cost after the October 22 purchase is $13.70.
What is the weighted average unit cost?The weighted average unit cost determines the weighted average cost of all the purchased inventory.
[(300 x 12) + (390 x 15) ] / (300 + 390)
(3600 + 5850) / 690 = $13.70
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The difference between twice a number, x, and a smaller number, y, is 3. The sum of twice the number and the smaller
number is -3. Which equations represent this situation?
Oy=2x-3 and y=-2x-3
Oy-2x-3 and y=-2-2
O y=2x+3 and y=-2x-3
Oy-2x+3 and y=-x-
3. Help meeee
Answer:
y=2x+3 and y=-2x-3
Step-by-step explanation:
First situation:
2x-y=3
making y subject
y=2x+3
Second situation:
2x+y=-3
making y subject
y=-2x-3
Can i get an answer ASAP
A rectangle has perimeter 92 cm and its length is 1 cm more than twice its width.
Find the dimensions of a rectangle given that its perimeter is 92 cm and its length is 1 cm more than twice its width.
Set up your solution using the variables L for the length, W for the width, and P for the perimeter.
Part a: Using the definition of perimeter, write an equation for P in terms of L and W .
Part b: Using the relationship given in the problem statement, write an equation for L in terms of W .
Solve the equations from parts a and b.
Part c: The width is
Number
cm.
Part d: The length is
Number
cm.
The length and width of the rectangle is 15cm and 31cm respectively
Perimeter of a rectangleThe formula for calculating the perimeter of a rectangle is expressed as:
P = 2(L + W)
where
L is the length
W is the width
If its length is 1 cm more than twice its width, then;
L = 2W + 1
Substitute
92 = 2(2W + 1 + W)
46 = 3W + 1
3W = 45
W = 15cm
Determine the length
L = 2(15) + 1
L = 31cm
Hence the length and width of the rectangle is 15cm and 31cm respectively
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Could someone help me out with this question?
The simplified form of the difference quotient of equation [tex]9x^2+5x-1[/tex] . in the form 9x + 9h + 5.
In question for equation [tex]9x^2+5x-1[/tex], simplified to difference quotient in the form of Ax+Bh+C where A, B, C are integers
equation is the relationship between variable and represented as [tex]9x^2+5x-1[/tex] is example of polynomial equation.
We know that,
for difference quotient
[tex]=\frac{f(x+h)-f(x)}{h} \\\frac{9(x+h)^2+5(x+h)-1-9x^2-5x+1}{h}\\\frac{9h^2+9hx+5h}{h}\\9x+9h+5[/tex]
While, compared with Ax+Bh+C
we have A=9, B=9, C=5.
Thus, The required value of difference Quotient in the form Ax+Bh+c where A, B and C is 9, 9 and 5 respectively
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A patient is being given 2 1/3 milligrams of a drug per hour. How many total milligrams of the drug
will he get in 4 hours?
Answer:
it mean that the patient get 7mg drug in1 hour and infour hours he get 4×7= 28mg drug
The difference between two numbers is 120. If the smaller number is 720 what is the larger number?
Problem
Circles [tex]K[/tex] and [tex]L[/tex] touch externally at point [tex]P[/tex]. Line [tex]ABC[/tex] cuts [tex]K[/tex] at points [tex]A[/tex] and [tex]B[/tex] and is tangent to [tex]L[/tex] at [tex]C[/tex]. The line through [tex]A[/tex] and [tex]P[/tex] meets [tex]L[/tex] at a second point [tex]D[/tex].
Prove that [tex]PC[/tex] bisects angle [tex]BPD[/tex].
Step-by-step explanation:
Using the various theorems relating inscribed and external angles to intercepted arcs, we can write the following relations:
angle A = 1/2(arc BP) . . . . . . . . . . . inscribed angle
angle A = 1/2(arc CD -arc CP) . . . external angle at tangent/secant
angle CPD = 1/2(arc CD) . . . . . . . inscribed angle
angle CPB = 1/2(arc CP) + 1/2(arc BP) . . . . . sum of angles at the mutual tangent
ProofEquating the expressions for angle A, we have ...
1/2(arc BP) = 1/2(arc CD -arc CP)
Adding arc CP gives ...
1/2(arc BP +arc CP) = 1/2(arc CD)
Substituting the last two equations for angles from above, this gives ...
angle CPB = angle CPD
Hence PC bisects angle BPD.
list three keywords that refer to multiplication ?
Answer:
full list of words from this list
factor anything that contributes causely to a result
multiply the number by which multiplicant is multiplied
multiply the number that is multiplied by a multiplier
project and refer that has been created by someone or some process
Which of these triangle pairs can be mapped to each other using a reflection and a translation? a Triangles L R K and A R Q are connected at point R. Triangle L R K is reflected across point R to form triangle A R Q. b Triangles L P K and Q R A are shown. Triangle L P K is reflected across a line to form triangle Q R A. Triangle Q R A is shifted to the right of triangle L P K. c Triangles L P K and Q R A are shown. Triangle L P K is shifted down and to the left to form triangle Q R A. d Triangles L P K and Q R A are shown. Triangle L P K is rotated to form triangle Q R A. Triangle Q R A is also shifted to the right.
The triangle pairs that can be mapped to each other using a reflection and a translation is; Option B
How to Interpret Triangle Transformations?Let us analyze each of the graphs;
Option A; This graph didn't use a reflection and a translation because we see that there was first a reflection across side QR and then another reflection across side AR.
Option B; This graph is correct as it made use of a reflection and a translation as seen in the attached graph.
Option C; This didn't use of a reflection and a translation because it instead carried out translation both in vertical and horizontal direction.
Option D; This carried out Translation and Rotation.
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_____ ÷ ( - 9 ) = ( - 8 )
pls pls answer me question
v = u + 2at
Where v is the final velocity (in m/s), u is the initial velocity (in m/s), a is the acceleration (in m/s²) and t is the time (in seconds).
Find v when u is 19 m/s, a is 3 m/s², and is 21 seconds.
Answer:
145 m/s
Step-by-step explanation:
v = u + 2at
v = 19 + 2(3)(21)
v = 19 + 126
v = 145
answer
V=145
Step-by-step explanation:
V=U+2at
v=19+2×3×21
v=19+126
v=145
QUESTION IS DOWN BELOW WORTH 15 POINTS each
Answer: 154 m^3
Step-by-step explanation:
Volume = (5*2*7) + (3*7*4)
= 70 + 84
= 154 m^3
Brainliest please :P
Answer:
154 m^3
Step-by-step explanation:
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Search the internet regarding Golden Ratio explain its history significance and find its value in fraction/decimal give at least five examples from nature surroundings human body architecture etc manifesting the concept of Golden ratio please write in easy words for grade 4
help please
Two quantities are in the golden ratio if their ratio is the same as the ratio of their sum to the larger of the two quantities.
What is the Golden ratio?It should be noted that the Golden ratio is also called the golden mean or divine proportion.
The Golden ratio is refered to as the. most beautiful number in the universe.
It is extraordinary because it can be visualized everywhere from geometry to the human body.
In this case, quantities are in the golden ratio if their ratio is the same as the ratio of their sum to the larger of the two quantities.
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Please help!!! What is the product to the following?
The product of 3x² and 2x³y + 5xy⁴ is given by the expression 6x⁵y + 15x³y⁴
What is an equation?An equation is an expression that shows the relationship between two or more variables and numbers.
The product of 3x² and 2x³y + 5xy⁴ is:
= 3x² * (2x³y + 5xy⁴)
= 6x⁵y + 15x³y⁴
The product of 3x² and 2x³y + 5xy⁴ is given by the expression 6x⁵y + 15x³y⁴
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18
(cos+ i sin ) ¹8
6
Answer:
-1.
Step-by-step explanation:
1) according to the DeMoivre's theorem:
[tex]1*(cos\frac{ \pi}{6} +isin\frac{ \pi}{6})^{18}=1^{18}(cos(18*\frac{ \pi}{6})+isin(18*\frac{ \pi}{6}))=cos3\pi +isin3\pi =cos\pi +isin\pi ;[/tex]
2) if cos(π)=-1 and sin(π)=0, then cosπ+i*sin(π)=-1.
In a parallelogram, two adjacent sides measure 20 cm and 27 cm. The shorter diagonal is 23 cm. Determine, to the nearest degree, the measure of the larger angles in the parallelogram.
If two adjacent sides of parallelogram are 20 cm and 27 cm and the shorter diagonal is 23 cm then the measure of larger angles in the parallelogram is 123.75°.
Given Two adjacent sides are 20 cm and 27 cm. The shorter diagonal is 23 cm. and we need to find the measure of larger angle.
From law of cosines
[tex]c^{2} =a^{2} +b^{2} -2abcos d[/tex]
where c is the opposite side of angle, a and b are other sides and d is the angle.
[tex]23^{2} =20^{2} +27^{2} -2*20*27cos d[/tex]
where 23 is the length of shorter diagonal
529=400+729 - 1080 cos d
1080 cos d=600
cos d=600/1080
cos d=0.55
d=[tex]cos^{-}[/tex]0.55
d=56.25°
Adjacent angle=180-56.25
=123.75°
Largest angle=123.75°.
Hence the larger angle of parallelogram having sides 20 and 27cm is 123.75°.
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The area of the right triangle shown is 24 square feet. Which equations can be used to find the lengths of the legs of the triangle? Select three options. 0.5(x)(x + 2) = 24 x(x + 2) = 24 x2 + 2x – 24 = 0 x2 + 2x – 48 = 0 x2 + (x + 2)2 = 100
The equations to calculate the legs are 0.5(x)(x + 2) = 24, x^2 + 2x - 48 = 0 and x^2 + (x + 2)^2 = 100
How to determine the legs of the triangle?The complete question is in the attached image
The given parameters are:
Area = 24
Legs = x and x + 2
The area of the triangle is calculated as:
Area = 0.5 * Base * Height
This gives
0.5 * x * (x + 2) = 24
So, we have:
0.5(x)(x + 2) = 24
Divide through by 0.5
(x)(x + 2) = 48
Expand
x^2 + 2x = 48
Subtract 48 from both side
x^2 + 2x - 48 = 0
Hence, the equations to calculate the legs are 0.5(x)(x + 2) = 24, x^2 + 2x - 48 = 0 and x^2 + (x + 2)^2 = 100
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The diameter of a wrecking ball used to tear down buildings is 3.5 ft. What is the volume ( to the nearest hundredth) Use 3.14 for pi and round each approximation to the nearest hundredth.
Answer:
22.44 ft
Step-by-step explanation:
The radius is equal to half of the diameter or 1.75 ft (in this case).
The volume of a sphere is defined as the equation:
V = 4/3 * pi * radius ^ 3
V = 4/3 * 3.14 * 1.75 ^ 3
V = 4/3 * 3.14 * 5.36
V = 22.44 ft
A swimming pool is 3 meters deep, 50 meters long, and 25 meters wide. If it takes 0.25 pounds of chlorine for every 15 cubic meters of water to keep the pool clean and healthy, how many pounds of chlorine are needed?
a. 27.2 pounds
b. 35.7 pounds
c. 45.4 pounds
d. 62.5 pounds
Answer:
D) 62.5 pounds.
Step-by-step explanation:
The volume of the swimming pool = [tex]3\times50\times25 =3750[/tex]
[tex]3750\div15 = 250[/tex] lots of 15
[tex]250\times0.25=62.5[/tex] pounds of chlorine.
Hope this helps, have a nice day!
See question below super confused
Answer:
$ 1021.25
Step-by-step explanation:
FV = P ( 1 + .085 * 3/12) = 1021.25
3/12 = 3 months out of a year
.085 = decimal interest P = 1000
Interest = $42.68, time 7.08%. Find the principal. Round to the nearest hundredth place. = 7 years, rate =
Answer:
trust me its c i did the test on edge for me
Step-by-step explanation:
i did the test on edge
Answer:
$63.83
Step-by-step explanation:
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Yall I need help asap pls
question 7
You work as an assistant for a local musical theatre group, the Main Street Theatre Company. The company is putting on a production of Les Misérables this year, and they need your help planning it.
The company's first task is to cast the lead female roles of Fantine, adult Cosette, and Éponine, and the lead male roles of Jean Valjean, Inspector Javert, and Marius. You have received headshots and resumes from 28 women and 22 men who are interested in auditioning for these parts.
A: If no one has been cast yet, how many different ways are there to cast Jean Valjean from the 22 men?
B: If Jean Valjean has already been cast, how many different ways are there to cast Inspector Javert from the remaining men?
C: If Jean Valjean and Inspector Javert have already been cast, how many different ways are there to cast Marius from the remaining men?
Select one answer choice for part A, one answer choice for part B, and one answer choice for part C.
A: 22P3
A: 22!
B: 21!
C: 20P1
B: 21
B: 21P2
C: 20!
A: 22
C: 20
Question 2:
A: Which of the following expressions will calculate the number of ways the three lead male roles could be cast?
B: Evaluate the permutation from part A.
Select one answer choice for part A, and one answer choice for part B.
A: 22P19
B: ≈1.12×1021
B: 9240
A: 3P22
A: 22P3
B: ≈1.87×1020
The permutation illustrates that if no one has been cast yet, the different ways that are there to cast Jean Valjean from the 22 men is 22.
How to compute the value?The ways to cast Jean will be:
= 22!/(22 - 1)!
= 22!/21!
= 22
When Jean Valjean has already been cast, the different ways that are there to cast Inspector Javert from the remaining men will be:
= 21!/(21 - 1)!
= 21!/20!
= 21
When Jean Valjean and Inspector Javert have already been cast, the different ways that are there to cast Marius from the remaining men will be:
= 20!/(20 - 1)!
= 20!/19!
= 20
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State the restrictions of 1-x-y/x+y
The restriction of the expression as given in the task content is; x +y = 0.
What is the restriction of the expression?The expression in the task content is rational;
(1-x-y)/(x+y).
On this note, the restriction to the expression is the values which render the denominator of the expression equal to 0 and consequently the expression value to undefined.
Hence, the restriction is; x+y = 0.
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What is the coefficient of [tex]x^7[/tex] in the expansion of [tex](3 - x)^{11}[/tex]?
Answer:
-26730
Explanation:
To find the coefficient of [tex]x^7[/tex] in the expansion of [tex](3 -x)^{11}[/tex]
Use Binomial Expansion:
[tex](x+y)^n = \ ^n C_0 x^n + \ ^n C_1 x^{n-1} y + \ ^n C_2 x^{n-2}y^2 + ...+ \ ^n C_n y^n[/tex]
In this expansion,
[tex](3-x)^{11}[/tex]
The coefficient of [tex]x^7[/tex]
[tex]= 11C_{7} (3)^{11-7} (-x)^7[/tex]
[tex]= (330) (81) (-x^7)[/tex]
[tex]= -26730x^7[/tex]
The vertex of this parabola is at (3,-2). When the x-value is 4, the
y-value is 3. What is the coefficient of the squared expression in the
parabola's equation?
O
O
A-1
B. 7
C. 1
D. 5
Answer:
5
Step-by-step explanation:
f(x) = a(x-3)² - 2
When x = 4, y = 3, so:
3 = a(4-3)² - 2
5 = a
Are the grades shown in the math class below normally distributed? Explain your answer.
Since the histogram is not symmetric, the grades shown in the math class below are not normally distributed.
When does a histogram represent a normal distribution?A histogram represents a normal distribution if it symmetric.
In this problem, we have that:
57% of the grades are on the left tail.25% of the grades are on the center.18% are on the right tail.Since the percentages at the tails are different, the histogram is not symmetric, and the grades shown in the math class below are not normally distributed.
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