The probability that a vehicle will change lanes while making a turn is 45%. Suppose a random sample of 7 vehicles are observed making turns at a busy intersection. Find the probability that a least 5 vehicles will change lanes while making the turn.

Answers

Answer 1

Answer:

0.1529

Step-by-step explanation:

Given that:

Probability of changing lane ; p = 45% = 0.45

Sample size (number of trials) = n = 7

Probability that atleast 5 vehicles will change lane :

Using the binomial probability formula :

P(x = x) = nCx * p^x * (1 - p)^(n-x)

(1 - p) = 1 - 0.45 = 0.55

P(x ≥ 5) = p(x = 5) + p(x = 6) + p(x = 7)

P(x = 5) = 7C5 * 0.45^5 * 0.55^2

P(x = 5) = 21 * 0.45^5 * 0.55^2 = 0.117221

P(x = 6) = 7C6 * 0.45^6 * 0.55^1

P(x = 6) = 7 * 0.45^6 * 0.55^1 = 0.031969

P(x = 7) = 7C7 * 0.45^7 * 0.55^0

P(x = 7) = 1 * 0.45^7 * 0.55^0 = 0.003736

P(x ≥ 5) = p(x = 5) + p(x = 6) + p(x = 7)

P(x ≥ 5) = 0.117221 + 0.031969 + 0.003736

P(x ≥ 5) = 0.152926

P(x ≥ 5) = 0.1529

Answer 2

Using the binomial distribution, it is found that there is a 0.1529 = 15.29% probability that a least 5 vehicles will change lanes while making the turn.

For each vehicle, there are only two possible outcomes, either they change lanes while making a turn, or they do not. The probability of a vehicle changing lanes while making a turn is independent of any other vehicle, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

x is the number of successes. n is the number of trials. p is the probability of a success on a single trial.

In this problem:

The probability that a vehicle will change lanes while making a turn is 45%, hence [tex]p = 0.45[/tex].A sample of 7 vehicles is taken, hence [tex]n = 7[/tex].

The probability that at least 5 vehicles will change lanes while making the turn is:

[tex]P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7)[/tex]

In which

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 5) = C_{7,5}.(0.45)^{5}.(0.55)^{2} = 0.1172[/tex]

[tex]P(X = 6) = C_{7,6}.(0.45)^{6}.(0.55)^{1} = 0.0320[/tex]

[tex]P(X = 7) = C_{7,7}.(0.45)^{7}.(0.55)^{0} = 0.0037[/tex]

Then

[tex]P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) = 0.1172 + 0.0320 + 0.0037 = 0.1529[/tex]

0.1529 = 15.29% probability that a least 5 vehicles will change lanes while making the turn.

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Step-by-step explanation:

I got it right in edg2020

Your question is incomplete. But the following graph describes the equation you have given.

Which graph represents z = (–3 + 4i) – (2 + i).

The graph which represents z = (–3 + 4i) – (2 + i) is attached with this answer.

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z = (–3 + 4i) – (2 + i)

Now,

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i.e.

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Answer:

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Step-by-step explanation:

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Hope that helped happy holidays!

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Answers

Answer:  120 degrees

==============================================

Work Shown:

n = number of sides = 6

i = measure of interior angle

i = 180(n-2)/n

i = 180(6-2)/6

i = 180(4)/6

i = 720/6

i = 120

Each interior angle of this regular hexagon is 120 degrees.

-----------------

Alternative Approach:

E = exterior angle

E = 360/n

E = 360/6

E = 60

Each exterior angle of this regular hexagon is 60 degrees

i+E = 180

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i = 180-60

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Step-by-step explanation:

i need help with this pleasee

Answers

Answers:

angle GFH = 60 degreesangle GHD = 110 degreesangle FGH = 10 degrees

================================================

Explanation:

Angle CFG is given to be 120 degrees.

The angle to the right that's adjacent to this is angle GFH. The two angles add to 180

(angle CFG) + (angle GFH) = 180

(120) + (angle GFH) = 180

angle GFH = 180 - 120

angle GFH = 60 degrees

-----------------------

Angle XGA is 70 degrees. Note how it corresponds to angle XHC since both angles are in the same northwest quadrant of their four-corner angle configuration.

Corresponding angles are congruent due to the parallel lines AB and CD.

This means angle XHC is also 70 degrees.

We'll use the same idea as in the last section

(angle XHC) + (angle GHD) = 180

(70) + (angle GHD) = 180

angle GHD = 180 - 70

angle GHD = 110 degrees

--------------------

Focus on triangle FGH.

We want to find angle FGH, which is the same as angle G when focusing solely on triangle FGH and no other points or triangles.

In the previous two sections, we found

angle GFH = 60angle XHC = 110

This can be shortened to

angle F = 60angle H = 110

Again we must focus solely on triangle FGH and nothing else.

So we have

angle F = 60angle G = unknownangle H = 110

Let's solve for G

F+G+H = 180 .... angles of a triangle always add to 180

60+G+110 = 180

G+170 = 180

G = 180-170

G = 10

For triangle FGH, angle G is 10 degrees.

This means angle FGH is 10 degrees.

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