the number of miles mario can drive varies directly with the amount of gas that he has. he can drive 18 miles on ½ a gallon of gas. how many miles can mario drive with 9 gallons of gas?

To determine the length of the picture, we can set up the following equation:

length = 4 * width

Substituting in the given value for the width, we get:

length = 4 * 24 inches

Solving this equation gives us a length of 96 inches. Therefore, the length of the picture is 96 inches.

According to the Kepler's third law, the squares of the period of a planet's orbit is proportional to the cube of the semimajor axis.

According to Kepler's third law,

     t2 = a3

Kepler's third law compares the orbital period and radius of orbit of a planet to those of other planets. This comparison between period and radius being made is that the ratio of the squares of the periods to the cubes of their average distances from the sun is the same for every one of the planets. It provides an accurate description of the period and distance for a planet's orbits about the sun. The square of the period of a planet's orbit is proportional to the cube of its semimajor axis.  Kepler's Third Law depends on the total mass of the two bodies involved.

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Answer:

square and cube is the answers

Step-by-step explanation:

Answer:

£22.33

Step-by-step explanation:

calculate the cost of an album and a single track using simultaneous equations.

let a represent an album and s a single track , then

3a + 4s = 18.13 → (1)

2a + 5s = 13.93 → (2)

multiplying (1) by - 2 and (2) by 3 and adding will eliminate a

- 6a - 8s = - 36.26 → (3)

6a + 15s = 41.79 → (4)

add (3) and (4) term by term to eliminate a

0 + 7s = 5.53

7s = 5.53 ( divide both sides by 7 )

s = 0.79

substitute s = 0.79 into either of the 2 equations and solve for a

substituting into (1)

3a + 4(0.79) = 18.13

3a + 3.16 = 18.13 ( subtract 3.16 from both sides )

3a = 14.97 ( divide both sides by 3 )

a = 4.99

that is album costs £4.99 and single track £0.79

then cost to Charlotte is

cost = (4 × £4.99) + (3 × £0.79) = £19.96 + £2.37 = £22.33

The cost of 4 albums and 3 single tracks is £22.33

Let the cost of 1 album = £x

and let the cost of 1 single track = £y

Now, the cost of 3 albums and 4 single tracks = £3*x + £4*y

and cost of 2 albums and 5 single tracks= £2*x + £5*y

Given that,

£3*x + £4*y = £18.13  -------->(1)

£2*x + £5*y = £13.93 -------->(2)

Multiply (1) equation by 2 and (2) equation by 3 then solve for x and y.

On applying the substitution method we have,

x = £4.99 and y = £0.79

Now, we have to calculate the value of 4 albums and 3 single tracks.

It can be written as 4*x +3*y

£4*4.99 + £3*0.79 = £22.33

So, the cost of 4 albums and 3 single tracks is £22.33

This question is based on a linear equation in two variables. Here, we used two equations based on two variables and then solved them with the help of the substitution method.

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Answer:

The area of the rectangular lawn is 100m long and 45m wide, so it has an area of 100 * 45 = <<10045=4500>>4500m².

The three circular ponds have diameters of 20m, 10m, and 5m, so their areas are 314.16, 78.54, and 19.63 square meters respectively.

The total area of the ponds is 314.16 + 78.54 + 19.63 = <<314.16+78.54+19.63=412.33>>412.33 square meters.

The total area of the lawn that needs to be covered with grass seed is 4500 - 412.33 = <<4500-412.33=4087.67>>4087.67 square meters.

Each packet of grass seed covers 50 square meters, so Mrs Jones will need 4087.67 / 50 = <<4087.67/50=81.75>>81.75 packets of grass seed.

Each packet costs £1.49, so the total cost to Mrs Jones will be 81.75 * 1.49 = £<<81.751.49=121.78>>121.78. Answer: {121.78}.

Step-by-step explanation:

The empirical probability of rolling a 3 is 467% more than its theoretical probability

Its fundamental concept is that someone will nearly surely occur. The proportion of positive events in comparison to the total of occurrences.

Then the probability is given as,

P = (Favorable event) / (Total event)

A six-sided pass-on from obscure predisposition is moved multiple times, and the number 3 comes up multiple times. In the following three adjustments (the bite of the dust is moved multiple times in each round), the number 3 comes up 6 times, 5 times, and 7 times.

Then empirical probability is given as,

P = (6/20) x (5/20) x (7/20)

P = 21/800

P = 0.02625

The theoretical probability is given as,

P = (1/6) x (1/6) x (1/6)

P = 1 / 216

P = 0.004629

Then the percentage is given as,

Percentage = [(0.02625 - 0.004629) / 0.004629] x 100

Percentage = 467%

The empirical probability of rolling a 3 is 467% more than its theoretical probability

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Answer:

1080cm²

Step-by-step explanation:

Area of a quadrilateral = 1/2 x length of diagonal (length of perpendicular)

[tex] \frac{1}{2} \times 10(18 \times 12) \\ \frac{1}{2} \times 10(216) \\ \frac{1}{2} \times 2160 \\ {1080cm}^{2} [/tex]

Answer:

-6, 7

Step-by-step explanation:

Answer: B(-6,7)

Step-by-step explanation:

M(-5, 1)      A(-4,-5)       B(x,y)=?

[tex]\displaystyle\\M_x=\frac{x_A+x_B}{2} \\\\-5=\frac{-4+x_B}{2}\\\\[/tex]

Multiply both parts of the equation by 2:

[tex]-5(2)=-4+x_B\\\\-10=-4+x_B\\\\-10+4=-4+x_B+4\\\\-6=x_B\\\\Thus,\ x_B=-6[/tex]

[tex]\displaystyle\\\\\\1=\frac{-5+y_B}{2} \\\\[/tex]

Multiply both parts of the equation by 2:

[tex]1(2)=-5+y_B\\\\2=-5+y_B\\\\2+5=-5+y_B+5\\\\7=y_B\\\\Thus,\ y_B=7[/tex]

The area of the region enclosed by one loop of the curve r = sin(12θ) is π/48.

We have to find the area of the region enclosed by one loop of the curve.

The given curve is:

r = sin(12θ)

Consider the region r = sin(12θ)

The area of region bounded by the curve r = f(θ) in the sector a ≤ θ ≤ b is

A =

Now to find the area of the region enclosed by one loop of the curve, we have to find the limit by setting r=0.

sin(12θ) = 0

sin(12θ) = sin0   or    sin(12θ) = sinπ

So θ = 0             or      θ = π/12

Hence, the limit of θ is 0 ≤ θ ≤ π/12.

Now the area of the required region is

A = [tex]\int ^{\pi/12}_{0} \frac{1}{2}(\sin12\theta)^2d\theta[/tex]

A = [tex]\frac{1}{2}\int ^{\pi/12}_{0}\sin^212\thetad\theta[/tex]

A = [tex]\frac{1}{2}\int ^{\pi/12}_{0}\frac{1-\cos24\theta}{2}d\theta[/tex]

A = [tex]\frac{1}{4}\int ^{\pi/12}_{0}(1-\cos24\theta)d\theta[/tex]

A = [tex]\frac{1}{4}\left[(\theta-\frac{1}{24}\sin24\theta)\right]^{\pi/12}_{0}[/tex]

A = [tex]\frac{1}{4}\left[(\frac{\pi}{12}-\frac{1}{24}\sin24\frac{\pi}{12})-(0-\frac{1}{24}\sin24\cdot 0)\right][/tex]

A = [tex]\frac{1}{4}\left[(\frac{\pi}{12}-\frac{1}{24}\sin2\pi)-(0-\frac{1}{24}\sin0)\right][/tex]

A = 1/4[(π/12-0)-(0-0)]

A = 1/4(π/12)

A = π/48

Hence, the area of the region enclosed by one loop of the curve r = sin(12θ) is π/48.

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Answer:

y=1/2x+1

Step-by-step explanation:

I think so I'm not an expert

Answer:

y = - [tex]\frac{1}{2}[/tex] x - 1

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (2, - 2 ) and (x₂, y₂ ) = (- 4, 1 )

m = [tex]\frac{1-(-2)}{-4-2}[/tex] = [tex]\frac{1+2}{-6}[/tex] = [tex]\frac{3}{-6}[/tex] = - [tex]\frac{1}{2}[/tex] , then

y = - [tex]\frac{1}{2}[/tex] x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (2, - 2 ) , then

- 2 = - 1 + c ⇒ c = - 2 + 1 = - 1

y = - [tex]\frac{1}{2}[/tex] x - 1 ← equation of line

A level curve of the function f(x, y) is a curve that satisfies the equation f(x, y) = c, where c is a constant.

The diagram is attached at the end of the solution.

A contour map, which is also called a topographic map, is a representation of a three-dimensional feature using contour lines on a plane surface.

The map shows a bird's-eye view and allows people to visualize the hills, valleys, and slopes that are being mapped.

People can see the hills, valleys, and slopes that are being mapped thanks to the map's bird's-eye perspective.

The title, scale, contour interval, legend, and whether latitude and longitude or Universal Transverse Mercator (UTM) coordinates are used are typically included.

Numerous activities, such as camping, urban planning, meteorology, and geologic investigations, can benefit from using this kind of map.

Consider the surface [tex]$f(x, y)=\ln \left(x^2+4 y^2\right)$[/tex].

The level curves for the surface are given by the equation, [tex]$k=\ln \left(x^2+4 y^2\right)$[/tex], where [tex]$k \in \mathbb{R}$[/tex]

Take k = . . . , -3, -2, -1, 0, 1, 2, 3, . . .

Then, draw the different level curves of the surface.

The diagram is attached at the end of the solution.

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The variance of the number of heads which come up when a fair coin is flipped 9 times is 2.25.

In this case, number of trials n = 9

Note that X = X₁ + X₂ + X₃ + X₄ +X₅ + X₆ + X₇ + X₈ + X₉

Xₐ = 0 if the flip #i is tails, and

Xₐ = 1 if the flip #i is heads.

Since the Xi are independent, then we have:

Var (X) = Var (X₁ + … + X₉)

= Var (X₁) + Var (X₂) + … + Var (X₉)

Then,

Var (Xₐ) = E(Xₐ^2) – E(Xₐ)^2

= 1/2 – 1/4

= 1/4

So, the variance is:

Var (X) = Var (X₁) + Var (X₂) + … + Var (X₉)

= 9 * (1/4)

= 9/4

= 2.25

Hence, the variance of the number of heads which come up when a fair coin is flipped 9 times is 2.25.

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Answer: 1. 108.     2. 1         mark brainlist if helpful

Step-by-step explanation: hope it helps

98 plus 10.   108 plus one 109.  

To calculate how much Kaitlyn will have after four years with continuous compounding, we can use the following formula:

A = P * e^(r*t)

where A is the final amount, P is the initial principal (in this case, $3,000), r is the annual interest rate (4.08%), and t is the number of years (4). Plugging these values into the formula, we get:

A = $3,000 * e^(0.0408*4)

= $3,000 * e^0.1632

= $3,000 * 1.1759

= $3,527.77

Therefore, Kaitlyn will have $3,527.77 after four years with continuous compounding, which is close to [A] $3,532.18.

Answer:

C. y=4/3x-1

Step-by-step explanation:

I plotted all equations on Desmos. A, B and D all had a solution with the equation of line a, they both had an interception so they were wrong. C. is the only that does not have an interception with line a. They didn't intercept and were parallel meaning that they will never touch or won't have a solution.

The smaller number is 25 and the larger number is 30.

Given that, the sum of two numbers is 55.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

Let the smaller number be x.

The larger number is 5 more than the smaller number.

Then, the larger number be x+5

The sum of two numbers is 55.

x+x+5=55

⇒ 2x+5=55

The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true.

Now, 2x+5=55

⇒ 2x=50

⇒ x=25

So, x+5=30

Therefore, the smaller number is 25 and the larger number is 30.

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From the given options, option B is the only statement that is not true is ∠C ≅ ∠E.

Triangle congruence theorem or triangle congruence criteria help in proving if a triangle is congruent or not. The word congruent means exactly equal in shape and size no matter if we turn it, flip it or rotate it.

If Δ ABC is congruent to Δ DEF, then its corresponding parts must be congruent.

segment AB ≅ segment DE

segment BC ≅ segment EF

segment AC ≅ segment DF

∠A ≅ ∠D

∠B ≅ ∠E

∠C ≅ ∠F

Therefore, from the given options, option B is the only statement that is not true is ∠C ≅ ∠E.

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"Your question is incomplete, probably the complete question/missing part is:"

If triangle ABC is congruent to triangle DEF, which statement is not true?

A) Segment AB ≅ segment DE

B) ∠C ≅ ∠E

C) Segment BC ≅ segment EF

D) ∠A ≅ ∠D

An expression to represent the total penalty fees after 3 days late is given by T = 25d.

In Mathematics, a linear function is sometimes referred to as an expression or the slope-intercept form of a straight line and it can be used to model (represent) the total penalty fees after 3 days late;

T = md + b

Where:

Therefore, the required linear function that represents the total penalty fees after 3 days late is given by this mathematical expression;

T = 25d

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g(x) intercepts the x-axis at x = 3, then the correct option is (3, 0)

For a function y = f(x), we define the x-intercept as the value of x for which:

f(x)=  0

The x-intercepts are also called zeros or roots of the function, and are the points where the graph of the function intercepts the x-axis.

In this case, the function is g(x) = -3x + 9, so here we need write and solve the equation:

g(x) = 0

-3x + 9 = 0

9 = 3x

9/3 = x

3 = x

This means that the x-intercept is x = 3, or (3, 0) written in point form, when we evaluate g(x) in x = 3 we get:

g(3) = -3*3 + 9

g(3) = -9 + 9

g(3) = 0

As expected.

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The area of the region bounded by the given curves. y = 6x2 ln(x), y = 24 ln(x) is 2.85 sq.units.

In this question we need to find the area of the region bounded by the given curves. y = 6x^2 ln(x), y = 24 ln(x)

Equating both the equations of the curve,

6x^2 ln(x) = 24 ln(x)

24 ln(x) - 6x^2 ln(x) = 0

x = 1, 2

This means,  the curves intersect at x = 1 and x = 2.

So, the required area would be,

A = ∫[1 to 2] [24 ln(x) - 6x^2 ln(x)] dx

First we find the indefinite integral ∫[24 ln(x) - 6x^2 ln(x)] dx

= -6  ∫[-4 ln(x) + x^2 ln(x)] dx

= -6 ∫ln(x) (x^2 - 4) dx

= -6 ln(x) (1/3 x^3 - 4x) + 2/3 x^3 - 24x

So,  ∫[1 to 2] [24 ln(x) - 6x^2 ln(x)] dx

= [-6 ln(x) (1/3 x^3 - 4x) + 2/3 x^3 - 24x] _(x = 1 to x = 2)

= 32 ln(2) - 58/3

= 22.18 - 19.33

= 2.85 sq.units.

Therefore, the area of the region is 2.85 sq.units.

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Answer:

145°

Step-by-step explanation:

Angle x and the 35-deg angle are a liner pair, so they are supplementary.

The sum of the measures of two supplementary angles is 180°.

x + 35° = 180°

x = 145°

The area enclosed by the curve x = t^2 − 3t, y = √t and the y-axis is 2.08 square units.

We have been given parametric equations x = t^2 − 3t, y = √t

We need to find the area enclosed by the curve x = t^2 − 3t, y = √t and the y-axis.

Consider x = 0

So, t^2 − 3t =  0

t(t - 3) = 0

t = 0   or  t = 3

Let f(t) =  t^2 − 3t and g(t) = t

Differentiate the curve f(t) with respect to t.

f'(t) = 2t - 3

NWe know that the formula to find the area under the curve.

A = ∫[a to b] g(t)f'(t) dt

here, a = 0 and b = 3

so, A = ∫[0 to 3] √t (2t - 3) dt

A = ∫[0 to 3] (2t√t - 3√t) dt

A = ∫[0 to 3] (2t^(3/2) - 3t^(1/2)) dt

A = [4/5 t^(5/2) - 2 t^(3/2)]_[t = 0, t = 3]

A = 4/5 3^(5/2) - 2 3^(3/2) - 0 + 0

A = 4/5 3^(5/2) - 2 3^(3/2)

A = 6√3 /5

A = 2.08

Therefore,  the area of the curve is 2.08 square units.

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Answer:

II) it has all sides of equal length

Answer:

6

Step-by-step explanation:

        6 is a factor of X , Y and Z.

    So, 6 will be a common factor of X + Y + Z.

Answer:

The answer C) 5 * 106

Step by step explanation:

(i) Yes, it is even and divisible by 3 as 1 + 0 + 2 = 3

(ii) No, it does not end in 5 or 0

What are Divisibility Rules?

Divisibility criteria can be used to determine whether or not to diminish a fraction. The rules are based on patterns seen while listing the multiples of any integer.

Solution:

(i) 102 is divisible by 6 - TRUE

It is because 102 is even number thus, it is divisible by 2 and since the sum of digits 1 + 0 + 2 is 3 therefore, it is divisible by 3

- Yes, it is even and divisible by 3 as 1 + 0 + 2 = 3

(ii) 102 is divisible by 5 - FALSE

It is because any number to be divisible by 5 it should always end with 5 or 0 at ones place.

- No, it does not end in 5 or 0

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b. The correlation coefficient for this data-set is given as follows: r = -0.9877.

c. The correlation between the variables x and y is strong negative.

The correlation coefficient is an index between -1 and 1 that measures the relationship between two variables, as follows:

A data-set is composed by a set of points, and these points are inserted into a correlation coefficient calculator to obtain the coefficient.

From the table described in this problem, the points are given as follows:

(1, 9), (2, 7), (3,6), (4, 1), (7, -2), (8, -5) and (10, -8).

Inserting these points into a calculator, the coefficient is given as follows:

r = -0.9877.

Hence it is a negative and strong relationship, as the absolute value of r is of 0.9877 > 0.6.

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The final solution is:

(1) Tu=<7, 1, 13>, Tv=<0, -1, 1> and n(u,v)=<14, -7, -7>.

(2) the area of S=Φ(D): Area(S) = 514.39

(3) ∬sf(x,y,z)ds = 190√(294) = 3257.82

What is the double integral?

A multiple integral is a definite integral of a function of several real variables, for instance, f or f.

1. Φ(u,v) gives the parametrization with its x, y, and z components. So, x=7u+4, y=u-v, and z=13u+v.

We can use this to get the tangent vectors by taking the respective partial derivatives.

Tu=<7, 1, 13> by taking the u derivatives of the components, and Tv=<0, -1, 1> by taking the v derivatives of the components.

2. Taking the cross product of Tu and Tv will give the normal vector n(u,v), which is <14, -7, -7>.

3. To find Area(S), you have to multiply the area of D by the magnitude of the normal vector from the previous step. D is the region defined by 0<=u<=5 and 0<=v<=6, so the area of D is 5*6=30.

Multiply this by the magnitude of the normal vector to find that Area(S)=30√(294)

Area(S) = 514.39

4. To integrate, we first must put the initial function in terms of the parameters we found in the first step.

Replace y with u-v and z with 13u+v. Next, multiply this integrand by the magnitude of the normal vector (√294) and apply the given bounds for u (0<=u<=5) and v (0<=v<=6).

From here the problem can be integrated like any other double integral, the final answer being 190√(294).

Hence, The final solution is:

(1) Tu=<7, 1, 13>, Tv=<0, -1, 1> and n(u,v)=<14, -7, -7>.

(2) the area of S=Φ(D): Area(S) = 514.39

(3) ∬sf(x,y,z)ds = 190√(294) = 3257.82

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Complete Question:

Show that Φ(u,v)=(7u+4,u−v,13u+v) parametrizes the plane 2x−y−z=8. Then: (a) Calculate Tu , Tv, and n(u,v). (b) Find the area of S=Φ(D), where D=(u,v):0≤u≤5,0≤v≤6. (c) Express f(x,y,z)=yz in terms of u and v and evaluate ∬sf(x,y,z)ds(a) Tu= , Tv= , n(u,v)=_______________(b) Area(S)=_______(c) ∬sf(x,y,z)ds=___________

Answer:

4 ( 2q + 5 )

Step-by-step explanation:

8q + 20

HCF is 4

= 4 ( 2q + 5 )

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