Answer:
2.64 square meters.
Step-by-step explanation:
To find the surface area of a cuboid, you need to find the area of each of the six faces and add them together. A wooden cuboid with an open flame base that has a square surface with 1.2 meter sides and a height of 0.25 meters would have a surface area of 1.2 * 1.2 + 4 * (1.2 * 0.25) = 1.44 + 1.2 = 2.64 square meters. This is because the base of the cuboid has an area of 1.2 * 1.2 = 1.44 square meters, and each of the four sides has an area of 1.2 * 0.25 = 0.3 square meters. The total surface area of the cuboid is therefore the sum of these areas: 1.44 + 4 * 0.3 = 2.64 square meters.
Statistics problem.
These are independent events. Suppose that P(A)=0.2 and P(B)=0.4 and P(B|A)= 0.8.
P(A and B) is
a) 0.40
b) 0.16
c) 0.48
d) 0.32
e) 0.60
The probability P(A and B) has a value of 0.08
How to determine the probability?From the question, we have the following parameters that can be used in our computation:
P(A) = 0.2
P(B) = 0.4
P(B|A) = 0.8
From the question, we have
Independent events
This means that
P(A and B) = P(A) * P(B)
So, we have
P(A and B) = 0.2 * 0.4
Evaluate
P(A and B) = 0.08
Hence, value is 0.08
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In a triangle, the lengths of the sides are 3, 7, and 8. If the perimeter of a similar
triangle is 54, what is the length of the longest side of the larger triangle?
Answer:
Answered Below :)
Step-by-step explanation:
To solve this problem, we can use the concept of similar triangles. Two triangles are similar if they have the same shape, but possibly different sizes. In other words, the angles in the two triangles are the same, and the lengths of their sides are in proportion to each other. In this case, we are given that the lengths of the sides of the first triangle are 3, 7, and 8, and the perimeter of the second triangle is 54. We are asked to find the length of the longest side of the second triangle.
To solve this problem, we first need to find the perimeter of the first triangle. Since the perimeter of a triangle is the sum of the lengths of its sides, the perimeter of the first triangle is 3 + 7 + 8 = 18. Now that we know the perimeter of the first triangle, we can use this information to find the scale factor between the two triangles. The scale factor is the ratio of the lengths of corresponding sides in the two triangles. Since the perimeter of the second triangle is 3 times the perimeter of the first triangle, we can say that the scale factor between the two triangles is 3. In other words, the lengths of the sides of the second triangle are 3 times the lengths of the corresponding sides of the first triangle.
Now that we know the scale factor between the two triangles, we can use it to find the length of the longest side of the second triangle. The longest side of the first triangle has length 8, so the longest side of the second triangle has length 8 * 3 = 24. Therefore, the length of the longest side of the second triangle is 24.
Note: It is important to realize that the scale factor between two similar triangles is always the same for all sides of the triangles. In other words, if one side of a triangle is x times the corresponding side of a similar triangle, then all sides of the second triangle are x times the corresponding sides of the first triangle. This means that if we know the scale factor between two triangles for any one side, we can use that scale factor to find the lengths of all sides of the second triangle.
Factor X^3-2x^2-8x???
Answer:Cannot be factored
Step-by-step explanation:
Answer:
[tex]x(x+2)(x-4)[/tex]
Step-by-step explanation:
Given:
[tex]x^3-2x^2-8x[/tex]
Factor out the common term x:
[tex]\implies x(x^2-2x-8)[/tex]
Factor (x² - 2x - 8) by rewriting -2x as (-4x + 2x):
[tex]\implies x \left[ x^2-4x+2x-8 \right][/tex]
Factor the first two terms and the last two terms separately:
[tex]\implies x \left[x(x-4)+2(x-4) \right][/tex]
Factor out the common term (x - 4):
[tex]\implies x \left[ (x+2)(x-4) \right][/tex]
Therefore:
[tex]x^3-2x^2-8x=x(x+2)(x-4)[/tex]
-will give brainliest, thx
Type the correct answer in the box.
Find the length of SU in the isosceles trapezoid.
SW = 1.7
VW = 3
SV = 1.5
TU= 1.5
SU=
W
T
U
The value of SU is 4.7 units
What is an isosceles trapezoid?An isosceles trapezoid can be defined as a trapezoid in which non-parallel sides and base angles are of the same measure.
Given is an isosceles trapezoid,
In an isosceles trapezoid, the triangles Δ SWV and Δ TWU must be congruent. Then, the corresponding sides are congruent too:
TW ≅ SW
UW ≅ VW
From the given information,
UW = 3
SU = SW+UW
Finally, using the values of SW and UW:
SU = 1.7+3 = 4.7
Hence, the value of SU is 4.7 units.
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Answer:
4.7
Step-by-step explanation:
3. Jennie and Ada are playing a card game where they score points. After one round the ratio of Jennie's points
to Ada's points is 4 to 7. If Ada has 15 more points than Jennie, how many points does Jennie have?
Jennie has 20 points.
Explanation:
to Ada's points is 4 to 7. If Ada has 15 more points than Jennie, how many points does Jennie have?
To solve this problem, we can use proportions. We know that the ratio of Jennie's points to Ada's points is 4 to 7, so we can set up the following proportion:
4/7 = Jennie's points / Ada's points
We also know that Ada has 15 more points than Jennie, so we can add 15 to both sides of the proportion to represent this:
4/7 = Jennie's points / (Jennie's points + 15)
Next, we can cross-multiply to solve for Jennie's points:
4 * (Jennie's points + 15) = 7 * Jennie's points
4 * Jennie's points + 60 = 7 * Jennie's points
We can then subtract 4 * Jennie's points from both sides to isolate the variable:
60 = 3 * Jennie's points
Finally, we can divide both sides by 3 to find the value of Jennie's points:
Jennie's points = 60/3 = 20
Thus, Jennie has 20 points.
An air traffic controller Is tracking two planes. To start, Plane A is at an altitude of 5000 feet and Plane B is at an altitude of 4207 feet. Plane A is gaining altitude at 45.25 feet per second and Plane B is gaining altitude at 60.5 feet per second.
seconds:
feet:
The planes will both meet in 53 seconds based on the information.
How to illustrate the equation?From the information, Plane A is at an altitude of 5000 feet and Plane B is at an altitude of 4207 feet. Plane A is gaining altitude at 45.25 feet per second and Plane B is gaining altitude at 60.5 feet per second.
The equation will be:
5000 + 45.25f = 4207 + 60.5f
Collect the like terms
60.5f - 45.25f = 5000 - 4207
15.25f = 793
Divide
f = 793 / 15.25
f = 53
They'll meet in 53 seconds.
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An air traffic controller Is tracking two planes. To start, Plane A is at an altitude of 5000 feet and Plane B is at an altitude of 4207 feet. Plane A is gaining altitude at 45.25 feet per second and Plane B is gaining altitude at 60.5 feet per second. When will that meet
seconds:
feet:
The ticket wheel at the arcade has the following potential outcomes:
Ticket
Value
10
Ticket Wheel Outcomes Table
2
15
25
2
Spots on
the
Wheel
What is the expected number of tickets won from one spin?
30
2
40
2
6
100
3
500
1
The product of the value of each outcome and the likelihood that it will occur results in the expected value. The likelihood of each outcome occuring for the ticket wheel is inversely correlated to the number of points on the wheel for that outcome.
When N is the number of slots on the wheel for 15 tickets, for instance, the probability of winning 15 tickets is N/20.
So, the following is the expected value of the number of tickets won:
[tex](15 × \frac{N}{20} ) + (25 × \frac{N}{20} ) + (30 × \frac{N}{20} ) + (40 × \frac{N}{20} ) + (10 × \frac{2}{20} ) + (100 × \frac{6}{20} ) + (500 \times \frac{3}{20} )[/tex]
Simplifying this expression, we get:
[tex] \frac{(15N + 25N + 30N + 40N + 20 + 600 + 1500)}{20} [/tex]
Further simplifying, we get:
[tex]\frac{(100N + 2120)}{20} [/tex]
This expression can be further simplified by dividing the numerator and denominator by 5 to get:
[tex] \frac{(20N + 424) }{4} [/tex]
The response to the first query is that this expression is equal to the expected value of the quantity of tickets won. Therefore, (d) 102 tickets is the right response.
The percentage of data that falls within two standard deviations of the mean for all normal curves is what is being questioned in the second question. The correct response is (b) 95% because this is roughly 95% according to the Empirical Rule.
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x
y
4
2
2
4
4
2
2
4
y=1x2
a = 1
As |a| increases, the parabola becomes
Answer:
narrower
Step-by-step explanation:
As [tex]|a|[/tex] increases, the parabola becomes narrower.
As [tex]|a|[/tex] decreases, the parabola becomes wider.
Find all real values of t that satisfy the equation t^2 = 324
the Answer: t=18, - 18
Andrea knows that she can regroup and rewrite the number sentence so that she won't have to multiply by 12. To do this, she needs to find the total for each kind of oatmeal separately. Let's help her. First we need to find the number of boxes of plain oatmeal
The number sentence needed to find the number of boxes of plain oatmeal is given as follows:
6 x 7 = 42.
How to obtain the number of boxes of plain oatmeal?From the image given at the end of the answer, we have that:
Andrea has 6 rows of boxes of plain oatmeal.Each row contains 7 boxes of plain oatmeal.Then the expression that gives the total number of boxes of plain oatmeal can be given by the addition of six terms seven, as follows:
7 + 7 + 7 + 7 + 7 + 7.
Consecutive additions are nothing more than multiplication expressions, hence the number sentence needed to find the number of boxes of plain oatmeal is given as follows:
6 x 7 = 42.
(this is because the product of 6 and 7 has a result of 42, that is, 7 + 7 + 7 + 7 + 7 + 7 = 42).
Missing InformationThe problem is given by the image shown at the end of the answer.
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Multiply the binomial (8p-2)(6p+2)
Answer:
48p²+4p-4
Step-by-step explanation:
(8p-2)(6p+2)
=48p²+16p-12p-4
=48p²+4p-4
The diameter of a penny is 19 mm. How far from your eye must it be held so that it has the same apparent size as the moon?
For a penny of diameter 19mm to be of the same apparent size as the moon it should be held at a distance of about 2.1m away from the eye.
Therefore, the answer is 2.1m.
Distance of moon from earth is 384,400km, that is 384,400,000m. Also 3,474.8km that is 3,474,800m.
For penny to have same apparent size as the moon, it should subtend equal angle as moon to the viewer. See the attached figure for reference. Thus ΔABC is similar to ΔEDB by AA criterion as ∠A is common and ∠BAC = ∠DEB as they are corresponding angles.
Let distance between penny and observer be x. Then
x/ ED = 384,400,000m/ AB
x/ 19mm = 384,400,000m/ 3,474,800m
x/ 19mm = 961000/ 8687
x = 961000/ 8687 × 19
x ≈ 2101.88mm
x = 2.1m
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If x = 3, y = 6, then cosO is equal to:
3√5.
√5/5
9.
15.
Let R be the region in the first and second quadrants bounded above by the graph of y=201+x2and below by the horizontal line y=2, how do you find the area?
37.96 sq units is the area enclosed by the graph [tex]y=\frac{20}{1+x^2}[/tex] and y=2
To calculate the area enclosed by 2 graphs we have to firstly find the intersection point of both graph
to find the intersection point we will equate given equation
=> [tex]\frac{20}{1+x^2}[/tex] = 2
=> [tex]1+x^2[/tex] = 10
=> [tex]x^2[/tex] = 9
=> x= 3,-3
so we have to find area of graph from x=-3 and x=3
so the formula for equation is given by:
[tex]\int\limits^b_a {\frac{20}{1+x^2} -2} \, dx[/tex]
where a=-3 and b=3
=>[tex]\int\limits^a_b {\frac{20}{1+x^2} } \, dx - \int\limits^a_b {2} \, dx[/tex]
[tex]\int\limits {\frac{1}{1+x^2} } \, dx = tan^-^1x[/tex] +c
=> 20 [tex]\left \{ {{x=3} \atop {x=-3}} \right.[/tex] [tex]tan^-^1x[/tex] - [tex]\left \{ {{x=3} \atop {x=-3}} \right.[/tex] 2x
=> 20 ( [tex]tan^-^1 3 - tan^-^1 (-3)[/tex] - 2*(3+3)
=>40 * 1.249 -12
=> 49.96 -12
=> 37.96
so the area enclosed by the given graphs is 37.96 sq. units
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Answer question with steps get brainliest! Please answer ASAP with steps. Use picture above
Ryan invested \$4,800$4,800 in an account in the year 1990, and the value has been growing exponentially at a constant rate. The value of the account reached \$6,300$6,300 in the year 1998. Determine the value of the account, to the nearest dollar, in the year 2007.
well, from 1990 to 1998 is 8 years, and we know the amount went from $4800 to $6300, let's check for the rate of growth.
[tex]\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$6300\\ P=\textit{initial amount}\dotfill &\$4800\\ r=rate\to r\%\to \frac{r}{100}\\ t=\textit{years}\dotfill &8\\ \end{cases} \\\\\\ 6300=4800(1 + \frac{r}{100})^{8} \implies \cfrac{6300}{4800}=(1 + \frac{r}{100})^8\implies \cfrac{21}{16}=(1 + \frac{r}{100})^8[/tex]
[tex]\sqrt[8]{\cfrac{21}{16}}=1 + \cfrac{r}{100}\implies \sqrt[8]{\cfrac{21}{16}}=\cfrac{100+r}{100} \\\\\\ 100\sqrt[8]{\cfrac{21}{16}}=100+r\implies 100\sqrt[8]{\cfrac{21}{16}}-100=r\implies \stackrel{\%}{3.46}\approx r[/tex]
now, with an initial amount of $4800, up to 2007, namely 17 years later, how much will that be with a 3.46% rate?
[tex]\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &4800\\ r=rate\to 3.46\%\to \frac{3.46}{100}\dotfill &0.0346\\ t=years\dotfill &17\\ \end{cases} \\\\\\ A=4800(1 + 0.0346)^{17} \implies A=4800(1.0346)^{17}\implies A \approx 8558.02[/tex]
Please Help!! 25 points!!!
Find the value of X
Answer: x = 0.1396263404
Step-by-step explanation:
The expression x+16 = 4x-15
(3 x (-1)) * degrees =-0.0523598776
6 x degrees) + (5 x degrees) =0.191986218
For #1
(PLEASE HELP ASAP TYSM LOTS OF LOVE!<3)
A circle has a radius of 30 ft. Which of these is closest to its area?
A. 50 ft²
B. 100 ft²
C. 190 ft²
D. 705 ft²
E. 2,850 ft²
Answer:
E. 2,850 ft²
Step-by-step explanation:
Answer:
OptionE)
Step-by-step explanation:
Area of a circle = [tex]\pi r^{2}[/tex]
[tex]3.14X30X30[/tex]
= [tex]2826[/tex]
Hence the closest is 2,850
your friend claims that it is possible to draw an quilateral triangle for which the circumecenter, incenter, centroid, and orthocenter are not all the same point. do you agree?
No, it is not possible to draw an quilateral triangle for which the circumecenter, incenter, centroid, and orthocenter are not all the same point.
Explain the term equilateral triangle?An equilateral triangle, which is frequently referred to as a "regular" triangle, is a triangle with three equal-length sides.
For the stated question-
The three out-of-the-way sections were not formed of a situation and were not sketched precisely.The Ortho Center is the point of convergence of the medians, and the in center is the point of convergence of the angle by sectors.All four of these would go to the exact same point in an equilateral triangle.Thus, the statement given by the friend is incorrect.
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Solve for x. Round to the nearest tenth if necessary.
20
X
25
X type your answer.
The value of the side x for the given similar triangle will be 12 units.
What is a triangle?The three-sided shape known as a triangle is sometimes used to allude to it. Every triangle has three sides and three angles, some of which might be the same.
The area of a triangle is defined as (1/2) base height, and the sum of all three angles within a triangle will be 180°.
As per the given both triangle,
The one angle of both triangles is 90° and one angle is the common angle.
Since the two angles are the same thus the third angle will be the same thus by the AAA postulate both triangles will be similar.
By a similar triangle rule,
20/x = 25/(√(25² - 20²))
x = 20/25 (15)
x = 12
Hence "The value of side x will be 12 units by AAA postulate".
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La señora Rosa junta ropa usada para venderla en el mercado por cajas de 5 kg. La semana pasada logró juntar media tonelada de ropa
1. -¿Cuántos kilos de ropa equivalen media tonelada?
2. -¿cuantas cajas logró con esa media tonelada de ropa?
3. -si en una semana ha vendido 1/4 de la media tonelada ¿Cuántos kilos ha vendido?
4. -con los kilos que ha vendido en la semana ¿a cuantas cajas equivale?
5. -¿Cuántos kilos le faltan por vender?
Ayuda es para hoy mismo
Doy coronita al que responda bien
Media tonelada son 500kg, con esa cantidad Rosa logra hacer 100 cajas de 5kg. En una semana ha vendido 125 kilos, es decir 25 cajas. Aún le quedan 375kg.
¿Cómo calcular cuántos kilos de ropa tiene Rosa?Para calcular los kilos de ropa que tiene Rosa debemos tener en cuenta que una tonelada equivale a 1000kg. De acuerdo con esto, media tonelada sería equivalente a 500kg.
1000kg / 2 = 500kg
¿Cuántas cajas de 5kg alcanza a hacer con media tonelada?Para saber cuántas cajas de 5kg hace con media tonelada debemos realizar la siguiente operación:
500 / 5 = 100
Sí en una semana ha vendido 1/4 de la media tonelada ¿Cuántos kilos ha vendido?Para identificar cuántos kilos ha vendido Rosa, debemos identificar a cuántos kilos equivale 1/4 de media tonelada, para ello realizamos la siguiente operación.
500kg / 4 = 125kg
Con los kilo que ha vendido en la semana ¿a cuánta cajas equivale?Para identificar a cuántas cajas equivale lo vendido por Rosa, debemos realizar la siguiente operación:
125kg / 5kg = 25 cajas
¿Cuántos kilos le faltan por vender?Para identificar cuántos kilos le faltan por vender, debemos realizar la siguiente operación:
500kg - 125kg = 375kg.
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Select the graph of the solution. Click until the correct graph appears.
|x| + 3 > 7
Answer:
graph B
Step-by-step explanation:
if x ≥ 0
x + 3 > 7
x > 7 - 3
x >4
if x < 0
-x + 3 > 7
-x > 7-3
-x > 4
x < -4
final solution
x < -4 ∨ x > 4
Work out how many triangles can be drawn between the labelled points in the diagram below
The triangles that are congruent to (a) ΔCDE, and (b) ΔCDF include ΔBFG, ΔADG, ΔBDE, and ΔABH, ΔBHCΔ, ΔGHE respectively
How to find congruent triangles?We should know that when two or more objects in geometry have the same shape and size, or if one has the same shape and size as the mirror image of the other, they are congruent.
From the object drawn the congruent triangles to ΔCDE include the following
ΔBDF
ΔABG
ΔBDE
ΔABI
ΔACH
ΔBCJ
ΔIHJ
All the triangle has side, side, right angle
The triangles that are congruent to ΔCDF include the following
ΔABG
ΔBHC
HGE
These triangles have SIDE, SIDE, SIDE (SSS)
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Line u passes through points (7, 2) and (10, 10). Line v passes through points (10, 8) and
(2, 11). Are line u and line v parallel or perpendicular?
Line u and line v are perpendicular lines by the relation of their slopes.
What is Slope?Slope of a line is the ratio of the difference of the y coordinates of two points to the x coordinates of those points. Slope is commonly denoted by the letter 'm'.
If a line passes through the points (x₁, y₁) and (x₂, y₂), then slope of the line,
m = (y₂ - y₁) / (x₂ - x₁)
Slopes of two lines, m₁ and m₂, are equal if they are parallel ⇒ m₁ = m₂.
Slopes of two lines, if the lines are perpendicular have the relation,
m₁ × m₂ = -1.
First let's find the slopes of the given lines.
Let m₁ be the slope of line u and m₂ be the slope of line v.
Line u passes through (7, 2) and (10, 10).
m₁ = (10 - 2) / (10 - 7) = 8/3
Line v passes through (10, 8) and (2, 11).
m₂ = (11 - 8) / (2 - 10) = 3/(-8)
Slopes are not equal, so they are not parallel.
m₁ × m₂ = [tex]\frac{8}{3}[/tex] × [tex]\frac{3}{-8}[/tex] = -1.
So the lines are perpendicular.
Hence the given lines u and v are perpendicular.
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each time you put a dollar in a vending machine you get a snack. your response (putting money in the machine) is reinforced according to which of the following schedules? a. fixed ratio b. variable interval c. fixed interval d. variable ratio
A fixed ratio schedule is a type of reinforcement schedule in which a response is reinforced after a specific number of responses. In this case, the response of putting money in the machine is reinforced after every 1 response.
If each time you put a dollar in a vending machine you get a snack, then your response is reinforced according to a fixed ratio schedule.
Variable interval, fixed interval, and variable ratio schedules are all different types of reinforcement schedules that are based on different criteria. A variable interval schedule is a type of reinforcement schedule in which a response is reinforced after a random interval of time. A fixed interval schedule is a type of reinforcement schedule in which a response is reinforced after a fixed interval of time. A variable ratio schedule is a type of reinforcement schedule in which a response is reinforced after a random number of responses.
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What is the average of 127 and 46?
Answer:
86.5
We add them together, which is 173, and since there are two terms, divide by 2
173/2=86.5
Answer:
86.5
127 + 46 / 2 = 86.5
I could be wrong but I believe this is correct.
What is the exact value of sin(x/2), cos(x/2) and tan(x/2) if cos(x/6)=3/5
+explaination
Step-by-step explanation:
x/2 = 3×x/6
sin(x/2) = sin(3x/6)
cos(x/2) = cos(3x/6)
tan(x/2) = tan(3x/6) = sin(3x/6)/cos(3x/6)
looking up triple angle identities for trigonometric functions we find :
cos(3x) = 4cos³(x) - 3cos(x)
so,
cos(x/2) =
cos(3x/6) = 4cos³(x/6) - 3cos(x/6) = 4(3/5)³ - 3×3/5 =
= 4×27/125 - 9/5 = 108/125 - 9×25/125 =
= 108/125 - 225/125 = -117/125 =
= -0.936
sin(3x) = 3×sin(x) - 4×sin³(x)
so,
sin(x/2) =
sin(3×x/6) = 3×sin(x/6) - 4×sin³(x/6)
also remember,
sin²(x) + cos²(x) = 1
therefore,
sin²(x/6) + cos²(x/6) = 1
sin(x/6) = sqrt(1 - cos²(x/6)) = sqrt(1 - (3/5)²) =
= sqrt(1 - 9/25) = sqrt(25/25 - 9/25) =
= sqrt(16/25) = 4/5 = 0.8
so, again
sin(x/2) =
sin(3×x/6) = 3×sin(x/6) - 4×sin³(x/6) =
= 3×4/5 - 4×(4/5)³ =
= 12/5 - 4×64/125 = 12×25/125 - 256/125 =
= 300/125 - 256/125 = 44/125 =
= 3×0.8 - 4×0.8³ = 0.352
tan(x/2) = sin(x/2)/cos(x/2) =
= 44/125 / -117/125 = -44/117 =
= 0.352 / -0.936 =
= -0.376068376...
Solve using the correct order of
operations.
(3³ – 15) ÷ 4 = [?]
P
E
MD
AS
Write an equation for the relationship between x and y. Simplify any fractions. (IXL K.5 Seventh Grade Math)
The equation of the line that represents the graph will be y = x.
What is a linear equation?
A connection between a number of variables results in a linear model when a graph is displayed. The variable will have a degree of one.
The linear equation is given as,
y = mx + c
Where m is the slope of the line and c is the y-intercept of the line.
From the graph, the two points are (0, 0) and (1, 1).
The line is passing through the origin that is (0, 0), then we have
0 = m (0) + c
c = 0
Then the equation is given as,
y = mx
The equation also passes through (1, 1), then we have
1 = m (1)
m = 1
Then the equation is written as,
y = x
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