The nebular theory proposes the sun and planets formed from a rotating cloud of interstellar gases and dust called a Solar nebula
What is nebular theory?
The creation of solar systems is explained by the nebular theory. According to the explanation, stars are produced from clouds of interstellar gas and dust, and the term "nebula" is Latin for "cloud." It takes around 100 million years for an undifferentiated cloud to develop into a star system with planets and moons.
The nebular theory proposes the sun and planets formed from a rotating cloud of interstellar gases and dust called a solar nebula
According to the nebular theory, the Sun and all of the plants in the solar system descended from the solar nebula, an interstellar cloud of gases and dust. The term "nebula" itself is a Latin word for cloud. The nebula began to collapse over time, and the centre of the collapse (the central mass) eventually turned into a protostar.
It should be noted that this protostar was distinct from our current star in that it lacked the continuous nuclear fusion process that our stars do now. When nuclear fusion begins in the centre of a protostar, it transforms into a star.
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when you urinate, you increase pressure in your bladder to produce the flow. for an elephant, gravity does the work. an elephant urinates at a remarkable rate of 0.0060 m3 (a bit over a gallon and a half) per second. assume that the urine exits 1.0 m below the bladder and passes through the urethra, which we can model as a tube of diameter 8.0 cm and length 1.2 m. assume that urine has the same density as water, and that viscosity can be ignored for this flow.
During urination, the pressure in the bladder increases to produce the flow hence, the speed of the flow of urine is 1.19 m/s and bernoulli's equation give for the pressure in the bladder is -9092 pa.
The Bernoulli equation is concerned with the conservation of kinetic, potential, and flow energies of a fluid stream and their conversion to each other in regions of flow where net viscous forces are negligible and where other restrictive conditions apply. The energy equation is a statement of the conservation of energy principle.
The Bernoulli equation is an approximate relation between pressure,velocity, and elevation, and is valid in regions of steady, incompressible flow where net frictional forces are negligible.
Given,
d = 8 cm = 0.08 m
Area of the tube, A = pi*d^2/4
= pi*0.08^2/4
= 0.005036 m^2
volume flow rate, dV/dt = A*v
v = (dV/dt)/A
= 0.006/0.005036
= 1.19 m/s
Now, use Bernoulli's theorem,
P_baldder + rho*g*h1 + (1/2)*rho*v1^2 = P_atm + rho*g*h2 + (1/2)*rho*v^2
P_baldder + rho*g*h + 0 = P_atm + 0 + (1/2)*rho*v^2
P_baldder - P_atm = (1/2)*rho*v^2 - rho*g*h
= (1/2)*1000*1.19^2 - 1000*9.8*1
= -9092 Pa
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It is very likely that human emissions of greenhouse gases are responsible for global warming. Give two examples of such activities and explain briefly how they cause global warming.
Greenhouse gases are gases that are present in the Earth's atmosphere and trap heat from the Sun, preventing it from radiating back out into space. Human activities that release greenhouse gases into the atmosphere can contribute to global warming. Two examples of such activities are:
Burning fossil fuels: The most common sources of greenhouse gas emissions are the burning of fossil fuels such as coal, oil, and natural gas. When these fuels are burned, they release large amounts of carbon dioxide into the atmosphere. Carbon dioxide is one of the most important greenhouse gases, and its increasing concentration in the atmosphere is a major contributor to global warming.Deforestation: Trees and other vegetation absorb carbon dioxide from the atmosphere as part of the process of photosynthesis. When trees are cut down and burned, or otherwise removed from the landscape, this carbon is released back into the atmosphere. Deforestation is therefore a major source of greenhouse gas emissions, and can contribute to global warming.Overall, human activities that release greenhouse gases into the atmosphere are a major cause of global warming. These activities can have serious consequences for the Earth's climate and can impact many aspects of human life.
A rocket on Earth experiences an upward applied force from its thrusters. As a result of this force, the rocket accelerates upward at 2 m/s2. Assume that there are no other upward forces exerted on the rocket and that wind resistance is negligible. Which of the following combinations of the rocket mass Mrocket and force from its thrusters FThrusters would result in an upward acceleration of 2 m/s2? Select two answers.
A. Mrocket 1 kg, FThrusters 12N
B. Mrocket 2 kg, FThrusters 4 N
C. Mrocket 3 kg, FThrusters 6 N
D. Mrocket 3 kg, FThrusters 36 N
The combinations of the rocket mass Mrocket and force from its thrusters FThrusters would result in an upward acceleration of 2 m/s2 are
A. Mrocket 1 kg, FThrusters 12 N
C. Mrocket 3 kg, FThrusters 6 N
Using Newton's Second Law, F = ma, we can determine the force needed to accelerate a rocket at a given rate. Since the mass of the rocket is given, we can calculate the force by rearranging the equation to F = m*a, where m is the mass and a is the acceleration. Therefore, for a mass of 1 kg, the force needed to achieve an acceleration of 2 m/s2 is 12 N. Similarly, for a mass of 3 kg, the force needed to achieve an acceleration of 2 m/s2 is 6 N.
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the plane of a loop of wire is perpendicular to a magnetic field. rank, from greatest to least, the magnitudes of the loop's induced emf for each situation. a. the magnetic field strength increases from 0 t to 1 t in 6 s . b. the magnetic field strength increases from 1 t to 4 t in 2 s . c. the magnetic field strength remains at 4 t for 1 min . d. the magnetic field strength decreases from 4 t to 3 t in 4 s . e. the magnetic field strength decreases from 3 t to 0 t in 1 s . rank from greatest to least. to rank items as equivalent, overlap them.
The plane of a loop of wire is perpendicular to a magnetic field. Rank, from greatest to least, the magnitudes of the loop's induced emf for each situation will be E - B - D - A-C.
Magnetic field strength is one of two ways that the intensity of a magnetic field can be expressed. Technically, a distinction is made between magnetic field strength H, measured in amperes per meter, and magnetic flux density B, measured in Newton-meters per ampere, also called tesla.
A current I through a long, straight wire produces a magnetic field with strength H=I/2πr at a distance r from the wire. So the field strength is inversely proportional to the distance from the wire.
The unit of magnetic field strength happens to be ampere per meter or A/m. Furthermore, the symbol of the magnetic field strength happens to be H.
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higher than its surroundings
2) An object will normally be a net radiator of energy when its temperature is
A) lower than its surroundings.
B) higher than its surroundings.
C) neither of these.
When an object's internal energy is:... really when its temperature is higher than that of its surroundings, it will typically be a net radiator of energy.
What do you describe energy that moves from things with higher temperatures to those with lower temperatures as a result of the temperature difference?From one thing to another, heat energy can be exchanged. Heat is the flow or transfer that occurs as a result of the temperature differential between two objects.
What happens to an object's heat energy as its temperature drops?Heat is a means of transferring energy to and from molecules. Atoms and molecules accumulate thermal energy as the temperature rises, which leads them to move faster and further apart. When the temperature drops, atoms.
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The mass of an elevator and its occupants is 1500kg . the electric motor that lifts the elevator can provide a maximum power of 18kw . what is maximum constant speed at which it can lift?
The maximum constant speed at which the elevator with a mass 1500 Kg can be lifted is 0.12 m/s.
To determine the maximum constant speed at which an elevator can be lifted, we need to consider the power available from the lifting device, in this case an electric motor, and the mass of the elevator and its occupants. The power available from the motor is given as 18 kW, and the mass of the elevator and its occupants is given as 1500 kg.
The speed of an object being lifted is directly related to the power available from the lifting device and the mass of the object being lifted. The relationship between these variables is given by the equation Power = mass * acceleration * velocity. By rearranging this equation to solve for velocity, we can determine the maximum constant speed at which the elevator can be lifted.
In this case, the acceleration of the elevator is equal to the acceleration due to gravity, which is 9.81 m/s^2. Plugging in the values for the power, mass, and acceleration, we get a maximum constant speed of 0.12 m/s for the elevator. This means that the elevator can be lifted at a constant speed of 0.12 m/s, given the power available from the electric motor and the mass of the elevator and its occupants.
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A ruby laser emits light of wavelength 694.3 nm. If this light is due to transitions from the n = 2 state to the n = 1 state of an electron in a box, find the width of the box.
If the wavelength of the ruby laser light is 694.3 nm then the width of the box is 0.795 nm .
In the question ,
it is given that ,
the wavelength (λ) is = 694.3 × 10⁻⁹ m ,
transition from n = 2 to n = 1 .
then the energy Eₙ = (h²n²/8mL²)
where "L" is the width of box ,
The transition energy is related to emitted (light) photon wavelength by
ΔE = (h²n²/8mc²L²) × (2² - 1²) = hc/λ ....equation(1)
Rewriting for the width "L" ,
we get ,
L = √[(3hcλ)/8mc²]
Substituting the values in equation(1) ,
we get ,
L = √[(3×1.24×10³×694.3)/8×511×10³]
Simplifying further ,
we get ,
L = 0.795 × 10⁻⁹ m
= 0.795 nm .
Therefore , the width of the box is 0.795 nm .
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FILL IN THE BLANK. in of all crashes involving cars and motorcycles, the car driver says he simply did not see the motorcycle. half two-fourths o
In one-third of all collisions between motorbikes and cars, the car driver claims he simply did not notice the motorcycle. when both the suspect and officer automobiles were totaled as a result.
Of pit maneuvers performed by professional officers. A police car is usually fortified for this and is heavy. It's likely that a light vehicle attempting a pit maneuver will sustain significant damage. If a novice tried this, they would probably get it incorrect and make a worse hazard. Officers and bystanders may potentially suffer damage as a result. The police are unsure of your intentions—whether you're trying to assist them for collisions, the suspect, or a different criminal who wants to hurt him or her. You'll be charged with several crimes due to speed, including obstruction and assault with a deadly weapon, for this action.
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Heat capacity on its own is rarely enough to predict the thermal performance of a material. Another important consideration is conductivity. If each of the following material was made into a frying pan, which would you expect to be heated the most uniformly in a short period of time when placed on the burner? Brass (k = 120 W/mk) Aluminum (k = 247 W/mK) Invar (63Fe-36Ni, k = 10 W/mK) O Copper (k = 398 W/mK)
Heat capacity on its own is rarely enough to predict the thermal performance of a material. Another important consideration is conductivity. If each material was made into a frying pan, Copper (k=398 W/mK) expect to be heated the most uniformly in a short period of time.
The amount of heat that must be delivered to an object in order to result in a unit change in temperature is referred to as an attribute of matter known as heat capacity or thermal capacity. The SI unit of heat capacity is joules per kelvin (J/K). Heat capacity is a general attribute. The comparable intensity property is the specific heat capacity, which is determined by dividing an object's heat capacity by its mass. By dividing the heat capacity by the substance's molecular weight, the molar heat capacity may be calculated. The volumetric heat capacity measures the heat capacity per volume. Architecture and civil engineering frequently refer to a building's capacity to store heat as having "thermal mass." The variance can be ignored when working with materials under confined pressure and temperature ranges. When measured at a starting point of 25 °C and 1 atm of pressure, one pound of iron, for example, has a heat capacity of roughly 204 J/K. It is adequate for temperatures between 15 °C and 35 °C and for ambient pressures between 0 °C and 10 °C because the real value fluctuates so little in those ranges.
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Two air-filled parallel-plate capacitors with capacitances C1 and C2 are connected in series to a battery that has voltage V; C1 = 3.00 μF and C2 = 6.00 μF. The electric field between the plates of capacitor C2 is E02. While the two capacitors remain connected to the battery, a dielectric with dielectric constant K = 4 is inserted between the plates of capacitor C1, completely filling the space between them. After the dielectric is inserted in C1, the electric field between the plates of capacitor C2 is E2.
A) What is the ratio E2/E02?
B) When the dielectric is inserted into C1, does the electric field in C2 increase, decrease, or remain the same?
C) Repeat the calculation in part A for the two capacitors connected to the battery in parallel. What is the ratio E2/E02?
The total positive charge stored on the two capacitors is;
4kQ₀/(k + 1)
We are told that the charge on each capacitor is Q₀.
Now, formula for charge stored on a capacitor is;
Q = CV
Where;
Q is charge
C is capacitance
V is voltage
Thus, total charge stored on the two capacitors will be;
Q = Q₁ + Q₂
Since Q₀ is the charge on each capacitor, then;
For Capacitor 1, we have; Q₀ = C₁V
For capacitor 2, we have; Q₀ = C₂V
Thus, let the capacitance C₁ be be half the capacitance C of two capacitors.
Thus;
C₁ = ¹/₂C
Thus;
Q₀ = ¹/₂CV
2Q₀ = CV
Now, a dielectric with dielectric constant k > 1 is inserted between the plates of capacitor C₁. Thus, the two capacitors will now be kC and C.
Thus;
C₂ = (kC × C)/(kC + C)
C will cancel out to give;
C₂ = kC/(k + 1)
Earlier on, we saw that;
Q₀ = C₂V
Thus;
Q₀ = kCV/(k + 1)
Earlier, we saw that 2Q₀ = CV
Thus, charge is;
Q₀ = 2kQ₀/(k + 1)
Since 2 capacitors, then total positive charge stored is;
2 × 2kQ₀/(k + 1) = 4kQ₀/(k + 1)
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The apparatus represented in the (Figure 1) consists of five identical balls mounted on elastic rods. Each elastic rod is connected to a base. The (unlabeled) ball and rod on the far left are pulled towards the screen (that is, toward you) and released. Which of the ball-and-rod combinations will have the largest amplitude of oscillation?Options: A. AB. BC. CD. DE. All of the rods will have the same amplitude of oscillation.
The option (d) is correct-This is because, the rod in D has same length as the vibrating rod (unlabeled) so its more likely to get in resonance with that that's why it oscillates more vigorously.
What is oscillates ?
In a complex mixture of chemical compounds that are reacting, a chemical oscillator is one in which the concentration of one or more components changes on a regular basis.
What is vibrating rod ?
A trustworthy point level sensor for high and low level indication or plugged chute detection is a vibrating rod, also known as a vibrating level switch. Bulk densities of as little as 1.25 lb/ft3 can be used for their use in light, fluffy powders and flakes.
Therefore, option (d) is correct-This is because, the rod in D has same length as the vibrating rod (unlabeled) so its more likely to get in resonance with that that's why it oscillates more vigorously.
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A mass hanging from a spring oscillates with a period of 0.25 s. Suppose the mass and spring are swung in a horizontal circle, with the free end of the spring at the pivot.
What rotation frequency, in rpm, will cause the spring's length to stretch by 23%?
The frequency of rotation of an object revolving around an axis is sometimes referred to as the rotational speed or rate of rotation of the object. Cycles per second (cps), revolutions per minute (rpm), etc. are some examples of its unit (the Greek lowercase letter nu).
What is the rotational frequency formula?
By a factor of 2, angular frequency (measured in radians per second) is bigger than frequency (measured in cycles per second, commonly known as Hz). In this picture, frequency is represented by the symbol rather than f. a sphere that is revolving about an axis. In order to satisfy = v / r, points further from the axis move more quickly.
How can I determine frequency?
Divide the number of times the event happens over the period of time to determine the frequency. Example: Anna divides the time by the quantity of page clicks (236). (one hour, or 60 minutes). She discovers that her clickthrough rate is 3.9 per minute.
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Bill Lauer, retired UT professor who holds six.national swimming records in the 80-84 age group, drops one of his medals in the swimming pool. He shines a flashlight into the pool onto his medal. The index of refraction of the water is 1.33. All dimensions are given in meters STATS-HELP ? NOTES T IMAGES | i Discuss. I Ulis art Description Answer Chk History Try 2-your answer of 3.44 m is not correct. How far is the medal from the edge 3.44m A of the pool? (include units with answer) 13.2 pts. 106% Angles must be measured from normal, not from water surface. try penalty tries: 2. how Detais Hints: 0.1
Using Snell's Law we got the distance from the edge to be 4.678 m.
Snell's law (also known as Snell–Descartes law and the law of refraction) is a formula used to describe the relationship between the angles of incidence and refraction, when referring to light or other waves passing through a boundary between two different isotropic media, such as water, glass, or air.
Snell's law is used for refraction of light
It is a formula used to describe the relationship between the angles of incidence and refraction, when referring to light or other waves passing through a boundary between two different isotropic media.
From Snell's Law,
n₁ sin i = n₂ sin r
1 * [1.6 /√(1.6² + 1.1²)] = 1.33 * [P / √(P² + 3.9²)]
P² = 0.3838P² + 0.3838(3.9)²
P = 3.078 m
Now, with the solution of Snell's Law, we can easily find the distance from the edge.
Distance from the edge = (1.6 + 3.078) = 4.678 m
Therefore, using Snell's Law we got the distance from the edge to be 4.678 m.
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refer to the circuit below for the next four questions. the circuit below has an unknown impedance z. but we do know that the source delivers an apparent power of 50va with a power factor of 0.8 lagging. Find The Unknown Impedance Z. 6 Ω 20/0° V Z I8 Ω
The circuit has an unknown impedance z. But we do know that the source delivers an apparent power of 50va with a power factor of 0.8 lagging. The Unknown Impedance Z is 108 Ω 20/0°.
Formula of Impedance = Z= under root R2 + (Xl - Xc)2
Z = impedance
R = resistance
XL = inductive reactance
XC = capacitive reactance
After putting the values in formula we get 108 Ω 20/0°.
Impedance, which is produced in a circuit by the interaction of resistance and reactance, is the resistance to alternating current. The impedance of a two-terminal circuit element can be calculated as the ratio of the complex representation of the sinusoidal voltage between its terminals to the complex representation of the current flowing through it. Typically, it is dependent on the frequency of sinusoidal voltage. Impedance extends the concept of resistance to alternating current (AC) circuits and has both magnitude and phase, in contrast to resistance, which only has magnitude. The idea of impedance is crucial when doing an AC analysis of electrical networks because it makes it possible to link sinusoidal voltages and currents by a simple linear law. The impedance matrix nevertheless shows a linear relationship between the complex voltages at the ports and the currents flowing through them, despite the fact that the two-terminal definition of impedance in multiple port networks is inadequate. The siemens is the SI unit for admittance, which is the inverse of impedance and was formerly known as the mho. Instruments used to measure electrical impedance are called impedance analyzers.
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an apple weighs 1.20 n. when you hang it from the end of a long spring of force constant 1.44 n/m and negligible mass, it bounces up and down in shm. if you stop the bouncing and let the apple swing from side to side through a small angle, the frequency of this simple pendulum is half the bounce frequency. (because the angle is small, the back and forth swings do not cause any appreciable change in the length of the spring.)
The unstretched length of the spring is 32.67 m.
Spring Constant = k = 1.44 N/m
Weight of the apple = m = 1.2 N
Acceleration due to gravity = g = 9.8 m/s²
Length of unstretched spring = I
Frequency of SHM motion is given by ;
= f = (1/2π) √(k/m)
Frequency of pendulum is given by;
= f' = (1/2π) √(g/l)
In the question, f' =2f, thus,
= (1/2π) √(g/l) = 2 X (1/2π) √(k/m)
= √(g/l) = (1/2) √(k/m)
Squaring on both sides,
= g/l = k/4m
= l = (g X 4m ) / k
= l = ( 9.8 X 1.2 X 4 ) / 1.44
= l = 32.67 m
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The complete question:
An apple weighs 1.00 N. When you hang it from the end of a long spring of force constant 1.50 N/m and negligible mass, it bounces up and down in SHM. If you stop the bouncing and let the apple swing from side to side through a small angle, the frequency of this simple pendulum is half the bounce frequency. (Because the angle is small, the back-andforth swings do not cause any appreciable change in the length of the spring.) What is the unstretched length of the spring (with the apple removed)?
In an engine, a piston oscillates with simple harmonic motion so that its position varies according to the following expression, where x is in centimeters and t is in seconds.x=(4.00cm)cos(3t+π/6)(a) At t=0, find the position of the piston.(b) What is its velocity?(c) What is its acceleration?(d) Find the period and amplitude of the motion.
A) 3.99 cm, B)-7.99 cm/s, C)-15 cm/s2, D) 4 cm, In an engine, a piston oscillates with simple harmonic motion so that its position varies according to the following expression,
a) At t=0
x=4.00cm)cos(3t+π/6)(a)= 4*0.999 = 3.999 cm
b)Expression for velocity v = dx/dt = -8.00 Sin(3t+π/6)
At t=0 v= -8 Sin(π/6) = -7.999 cm/s
c) Expression for acceleration a= -16 Cos(3t+ π/6)
At t=0 a= -16 Cos(π/6) = -15.99 cm/ sec2
d) Period = (2 ?)/3
Amplitude= 4 cm
A piston is a part of a variety of comparable devices, including reciprocating engines, reciprocating pumps, gas compressors, hydraulic cylinders, and pneumatic cylinders.
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the pressure of air in your house can stay constant during the day if the temperature rises. let the temperatures be 297 k during the day, and 288 k at night, and volume of the house be 900 m3. Part A Determine the number of moles of air that leave the house during the daytime.
Number of moles of air that leave the house during the daytime is 1154.017 moles.
The pressures are constant so:
V₁/T₁ = V₂/T₂
Given,
During the night, V₁ = 900 m³, and T1₁= 288K.
During the day, T₂ = 297K, and V₂ =?
V₂ = V₁*T₂/T₁ = 900*297/288 = 928.125 m³
928.125 - 900 = 28.125 m³
Volume of air that leave the house during the daytime = Vₐ
V₂/T₂ = Vₐ/Tₐ
Vₐ = V₂*Tₐ/T₂ = 28.125*273/297 = 25.85 m³
To calculate the number of moles,
22.24 liters per mole, and 1000 liters per m³, so
number of moles = N
N = 25.85*1000/22.4
N = 1154.017 moles.
Therefore, number of moles of air that leave the house during the daytime is 1154.017 moles.
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a 80 kg student is standing atop a spring in an elevator that is accelerating upward at 3.0m/s2. the spring constant is 2700 n/m .
According to the question, the spring will be compressed by 0.3413 m.
What are the physics applications of springs?Springs are crucial because they provide as straightforward models for numerous complex physical processes. In physics, objects that behave like springs exhibit what has known as a simple harmonic motion (SHM), which you will encounter again. k is referred to as the spring constant.
Briefing:acceleration of elevator=3 m/s²
mass of student= 80 Kg
spring constant=3 x 10³ N/m
the force on the student is given by F = m ( g +a)
F=80 (9.8+3)
F=1024 N
now the formula for spring force is given by
F= k x
1024= 3 x 10³ (x)
x=0.3413 m
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A 0.100 m long solenoid has a radius of 0.050 m and 1.50 x 10^4 turns. The current in the solenoid changes at a rate of 6.0 A/s. A conducting loop of radius 0.0200 m is placed at the center of the solenoid with its axis the same as that of the solenoid.
a.) What is the magnetic flux through the small loop when the current through the solenoid is 2.50 A?
b.) What is the induced emf in the loop?
The magnetic flux through the small loop when the current through the solenoid is 2.50 A is 5.87*10⁻⁴ Wb, the induced emf in the loop is 1.4*10⁻³r.
What is magnetic flux ?
The number of magnetic field lines that travel through a specific closed surface is referred to as magnetic flux. It gives a measurement of the overall magnetic field that traverses a specific surface region.
What is induced emf ?
A magnetic field is induced when a conductor carrying an electric current travels through it. Induced electromagnetic fields (EMFs) are created when a magnetic field rotates around an electric field.
Given data
length = 0.100 m
radius = 0.50 m
N= 1.5 *10⁴
I= 2.50A
a) the field inside the solenoid is
B= μ₀ Ni/L
B= 1.25 *10⁻⁶*1.5*10⁴*2.50/0.100
B= 0.47 Tesla
B= 0.47 W₆/m²
Area, A= πr²= (0.02)²
=0.00125m²
Magnetic flux = ∅ = B.A
= 5.87*10⁻⁴ Wb
b) induced Emf in the loop
EMf = μ₀ (dI/dT) (N/L) πr²
EMF= 1.4*10⁻³r
Therefore, the magnetic flux through the small loop when the current through the solenoid is 2.50 A is 5.87*10⁻⁴ Wb, the induced emf in the loop is 1.4*10⁻³r.
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the brakes are applied to a car and it abruptly slows down. the kinetic energy changes from 300 000 j to 100 000 j. the heat released during this process is
The heat released during the process of applying the break of the car is 200000 Joules.
According to the law of conservation of energy, energy can nether be created nor be destroyed, it can only be converted from one form to another.
In the process when the brakes of the car are applied the kinetic energy of the car is changing from 300000 to 100000 Joules.
When the kinetic energy of the body is getting converted into the thermal energy because of the friction the loss of kinetic energy is taking place.
It has to be noted here that the law of conservation of energy is still valid because all the energy that is lost in the form of thermal energy has gone into the environment which is ultimately a bigger system and the energy is still constant for the universe.
So, the amount of energy that is lost is 200000 Joules.
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You are to measure the rotational speed of a crank shaft. The available angular velocity meter has a display with resolution of 2 rpm (revolutions/minute). The meter specifications indicate that the device accuracy is 1.5% of the velocity reading. Find the design stage uncertainty for each of the following velocities
You are required to gauge a crank shaft's rotational speed. The device's level of uncertainty will be 0%.
What does rotational speed mean?The number of rotations a rotating system completes in a predetermined amount of time is the measure of rotational speed, also known as speed or speed of rotation. Pump speed is often expressed in min-1, while rotational speed is measured in s-1 (rev/s) (rpm).
What about angular velocity in rotation?The term "angular velocity" or "rotational velocity" ( or ), also known as "angular frequency vector," refers to a pseudovector that expresses how quickly an item spins or circles in relation to a point or axis or changes its angular location or orientation over time.
Briefing:The velocity meter's resolution = 2 rpm.
accuracy = 1.5%.
40 rpm = 1.5%.
The speed can change at 40 rpm = 39.7 to 40.3 rpm.
The device's resolution = 2 rpm.
uncertainty = 0%.
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On July 15, 2004, NASA launched the Aura spacecraft to study the earth's climate and atmosphere. This satellite was injected into an orbit 705 km above the earth's surface, and we shall assume a circular orbit. Part A How many hours does it take this satellite to make one orbit? VALO ? T- hours Submit Request Answer Part B How fast (in km/s is the Aura spacecraft moving? ΤΕΙ ΑΣφ ? v= km/s
a) The number of hours it takes for the satellite to make one orbit ( h ) = 1.64 hours, b) The speed of the Aura spacecraft = 7.5 Km/s.
Height of satellite Orbit ( h ) = 705 km ≈ 705000 m
a) Determine the time taken in hours for the satellite to make a single orbit
T = 2π [tex]\sqrt{ (R + h)^{2} /GM[/tex]
G = 6.67 * 1011 N-m2/kg2, M (earth's mass) = 5.98 * 1024, R = 6.38 * 106 m, and h = 705000 m
Fill in the values for T = 5933 seconds to equal 1.64 hours ( time taken to complete one orbit )
B) Calculate the spaceship Aura's speed
V = [tex]\sqrt{GM/R + h}[/tex]
G = 6.67 * 1011 N-m2/kg2, M (earth's mass) = 5.98 * 1024, R = 6.38 * 106 m, and h = 705000 m
Fill in the values in the equation ( 2 )
V equals 7503 m/s, or 7.5 km/s.
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if you measured the bouyancy force on an object submerged in molasses instead of water how would the bouyancy force differ
The buoyancy force when measured on an object submerged in molasses instead of water the buoyancy force does not differ.
Buoyancy is the force that is applied by any fluid on the body which is submerged in it.
The buoyancy force on any body is given by the relation,
B = Vpg
Where,
V is the volume of the fluid displaced,
p is the density of the fluid,
g is the acceleration due to gravity.
If we assume that the object is floating on the surface of the fluid then the buoyancy force will be equal to the weight of the body.
So, if the buoyancy force is measured on molasses instead of water the boils force will not differ in magnitude because it will be equal to the weight of the body in both the cases.
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A ball of mass m, at one end of a string of length L, rotates in a vertical circle just fast enough to prevent the string from going slack at the top of the circle. Assuming mechanical energy is conserved, the speed of the ball at the bottom of the circle is
The speed of the ball at the bottom of the circle when ball of mass m, at one end of a string of length L, rotates in a vertical circle is √Lg
The rate at which an object's distance traveled changes is measured by its speed. In terms of measurement, speed is a scalar, meaning it has magnitude but no direction. Speed is the rate at which an object moves over a given distance. a thing that travels at a high rate of speed and covers a lot of distance quickly. A slow-moving object, on the other hand, travels a comparatively short distance in the same amount of time when moving at a low speed. An object with zero speed is completely immobile.
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You are at a furniture store and notice that a Grandfather clock has its time regulated by a physical pendulum that consists of a rod with a movable weight on it. When the weight is moved downward, the pendulum slows down; when it is moved upward, the pendulum swings faster. If the rod has a mass of 1.23 kg and a length of 1.25 m and the weight has a mass of 1.99 kg, where should the mass be placed to give the pendulum a period of 2.00 seconds? Measure the distance in meters from the top of the pendulum.
I think the equation for this problem is T= 2pi * sqrt ( I / mgd), where I = md^2
The reason why I think that is because it is no a simple pendulum, it is a physical pendulum which means that a hanging object hangs about a fixed axis that does not pass through its center of mass.
The distance in meters from the top of the pendulum is 0.9939 m and Yes the equation will beT= 2pi * sqrt ( I / mgd).
A simple pendulum consists of a mass m hanging at the end of a string of length L. The period of a pendulum or any oscillatory motion is the time required for one complete cycle, that is, the time to go back and forth once.
If the amplitude of motion of the swinging pendulum is small, then the pendulum behaves approximately as a simple harmonic oscillator, and the period T of the pendulum.
Periodic Motion is based on the concept of periodic motion. Periodic motion can be defined as any motion that repeats over and over again with the same time required for each recurrence. A period is the amount of time for the system to complete one cycle.
In this example, it is the amount of time for the energy sphere to be released and then return to its approximate release point. The frequency is the number of cycles per unit of time, i.e., how many cycles are completed in one minute.
Given,
length = 1.25 m
mass =1.23 kg
T = 2πsqrt(l/g)
2 = 2 *3.14 sqrt(l/9.8)
l = 0.9939 m
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A star's absolute magnitude is its apparent brightness as seen from
A. Alpha Centauri.
B. 10 light-years distance.
C. 10 parsecs distance.
D. 100 parsecs distance.
E. Pluto.
Answer: C
The absolute significance of a star is 10 parsecs distance , M is the significance the big name could have if it become located at a distance of 10 parsecs from Earth.
By thinking about stars at a set distance, astronomers can evaluate the real (intrinsic) brightnesses of various stars.Apparent significance is the brightness of a celebrity because it seems to the observer. This is what stargazers look at after they study the sky and spot that a few stars are brighter than others. Absolute significance is the brightness of a celebrity from a distance of 10 parsecs away. A parsec is same to 32.6 light-years.
Astronomers outline big name brightness in phrases of obvious significance — how shiny the big name seems from Earth — and absolute significance — how shiny the big name seems at a popular distance of 32.6 light-years, or 10 parsecs.
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assume that the air consists entirely of nitrogen and that the pressure of the gas stays constant how much heat is supplied by body to warm the air
Charles' law stipulates that the volume of a given amount of gas is exactly related to its temperature on the kelvin scale while the pressure is held constant.
What is nitrogen most frequently used for?
On nitrogen, the chemical industry depends. It is used to make fertilizers, dyes, nylon, nitric acid, and explosives. To make these products, nitrogen must first be coupled with hydrogen to make ammonia. For this, the Haber process is employed.
Is nitrogen bad for people?
People lose their lives every year by breathing "air" with insufficient oxygen. Many people believe nitrogen gas is safe because it makes up 78 percent of the air we breathe. However, breathing nitrogen is only safe when it is combined with the right proportion of other gases.
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3. Given the force, F(x)=1-4 x+4 x³
a. Find an expression for the potential energy.
b. Plot F(x) between x=-2 to x=+2
c. Plot U(x) between x=-2 to x=+2
d. Identify the equilibrium points and comment on the stability at those points.
Expression for the potential energy is (3/4)x⁴ - 2x² + x.
Potential energy is the energy possessed by the system when it is in rest.
If the potential energy function U(x) is known, then the force F(x) at any position can be obtained by the derivative of the potential.
F(x) = - dU/dx
dU = - F(x).dx
U = [tex]\int\{F(x)} \, dx[/tex]
U = [tex]\int[/tex](1 - 4x + 4x³) .dx
U = (3/4)x⁴ - 2x² + x
Plotting F(x) between x=-2 to x=+2,
F(x) = (1 - 4x + 4x³)
for x=-2, F(-2) = F{1 - 4(-2) + 4(-2)³}
F(-2) = {1 + 8 - 32}
F(-2) = (-23)
for x=+2, F(-2) = F{1 - 4(2) + 4(2)³}
F(2) = {1 - 8 + 32}
F(2) = 25
Plotting U(x) between x=-2 to x=+2
U(x) = (3/4)x⁴ - 2x² + x
for x=-2, U(-2) = {(3/4)(-2)⁴ - 2(-2)² + (-2)}
U(-2) = {(4*3) - (2*4) - 2}
U(-2) = 12 - 8 - 2
U(-2) = 2
for x=2, U(2) = {(3/4)(2)⁴ - 2(2)² + (2)}
U(2) = {(4*3) - (2*4) + 2}
U(2) = {12 - 8 + 2}
U(2) = 6
For equilibrium points, force must be equal to zero,
F(x) = 0
(1 - 4x + 4x³) = 0
x1 = -1.10716
x2 = 0.26959
x3 = 0.83757
Equilibrium points exists at points x1, x2, x3.
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The drawing shows a 18.1-kg ball being whirled in a circular path on the end of astring. The motion occurs on a frictionless, horizontal table. The angular speed of the ball is
w
a
12.5rad/s
. The string has a mass of
0.0184 kg
. How much time does it take for a wave on the string to travel from the center of the circle to the ball? Number Units
The time taken for the wave on the string to travel from the centre of the circle of the ball is 6.5 * 10⁻⁶ s.
Given that, mass of the ball mb = 18.1 kg
Angular speed of the ball ω = 12.5 rad/s
Mass of the string ms = 0.0184 kg
Speed of the wave of the string is given by the formula,
sw = √(Ts / m') -------(1)
where, Ts is tension in the string
m' is mass per unit length of the strength
Ts = mb * ω² * l --------(2)
m' = ms/l ---------(3)
Substituting (2) and (3) in (1), we have
sw = √(mb * ω²* l²/ ms) ----(4)
We know that, t = l / sw -----(5)
Substituting (4) in (5), we have
t = √( ms/ mb *ω²) = √( 0.0184/(18.1 * 12.5²)) = √( 0.0184/2828.125)
= 0.0000065 = 6.5 * 10⁻⁶ s
Thus, the time taken for the wave on the string to travel from the centre of circle to the ball is 6.5 * 10⁻⁶ s.
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in an rlc circuit that includes a source of ac current operating at a fixed frequency and voltage, the resistance r is equal to the inductive reactance. if the plate separation of the parallel-plate capacitor is reduced to one-half of its original value, the current in the circuit doubles. find the original capacitive reactance in terms of r.
Xc = (0.467 - 0.427j)R is the original capacitive reactance in terms of r.in an rlc circuit that includes a source of ac current operating at a fixed frequency and voltage, the resistance r is equal to the inductive reactance
Since the resistance in the circuit is R, the reactance of the inductor is XL and the reactance of the capacitor is XC, then the impedance of the circuit is
Z = √[R² + (XL - XC)²]
Since the inductive reactance XL equals the resistance R, we have that
Z = √[R² + (XL - XC)²]
Z = √[R² + (R - XC)²]
Thus, the current in the circuit is thus I = V/Z = V/√[R² + (R - XC)²]
Now, when the plate separation of the parallel plate capacitor is reduced to one-half its original value, the current doubles. Also, when the plate separation is reduced to half, the capacitance doubles since C ∝ 1/d where C is capacitance and d separation between the plates. Since the capacitance doubles, the new reactance XC' is twice the initial reactance XC. So, XC' = 2XC. Thus the new impedance is thus
Z' = √[R² + (R - XC')²]
Z' = √[R² + (R - 2XC)²]
The new current is I' = V/Z' = V/√[R² + (R - 2XC)²]
Since the current doubles, I' = 2I.
V/√[R² + (R - 2XC)²] = 2V/√[R² + (R - XC)²]
1/√[R² + (R - 2XC)²] = 2/√[R² + (R - XC)²]
√[R² + (R - XC)²] = 2√[R² + (R - 2XC)²]
squaring both sides, we have
[R² + (R - XC)²] = 4[R² + (R - 2XC)²]
expanding the brackets, we have
[R² + R² - 2RXC + XC²] = 4[R² + R² - 4RXC + 4XC²]
[2R² - 2RXC + XC²] = 4[2R² - 4RXC + 4XC²]
2R² - 2RXC + XC² = 8R² - 16RXC + 16XC²
collecting like terms, we have
16RXC - 2RXC + XC² - 16XC² = 8R² - 2R²
14RXC - 15XC² = 6R²
15XC² - 14RXC + 6R² = 0
Using the quadratic formula to find XC, we have
Since it is capacitive, we take the negative part.
So, Xc = (0.467 - 0.427j)R
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