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A 4.0 in. wide by 1.125 in. thick rectangular steel bar supports a load of P in tension. Determine:
• The stress in the bar for F = 32,000 lb.
• The load P that can be supported by the bar if the axial stress must not exceed 25,000 psi.
Answers
Answer:
a) The stress in the bar when F is 32,000 is approximately 7,100 psi
b) The load P that can be supported by the bar if the axial stress must not exceed is approximately 110,000 lb
Explanation:
The question topic relates to stresses in structures;
The given parameters of the steel bar are;
The width of the steel bar, W = 4.0 in.
The thickness of the steel bar, t = 1.125 in.
The formula for stress in a bar is given as follows;
[tex]Stress, \sigma = \dfrac{Force, F}{Area, A}[/tex]
The cross sectional area of bar, A = W × t = 4.0 in. × 1.125 in. = 4.5 in.²
∴ The cross sectional area of bar, A = 4.5 in.²
a) The stress in the bar for F = 32,000 lb, is given as follows;
[tex]The \ stress \ in \ the \ bar , \sigma = \dfrac{ F}{A} = \dfrac{32,000 \ lb}{4.5 \ in.^2} = 7,111.\overline 1[/tex]
The stress in the bar when F is 32,000 is σ = 7,111.[tex]\overline 1[/tex] psi ≈ 7,100 psi
b) The load P that can be supported by the bar if the axial stress must not exceed, σ = 25,000 psi is given as follows;
[tex]\sigma = \dfrac{ P}{A}[/tex]
Therefore;
P = σ × A = 25,000 psi × 4.5 in² = 112,500 lb
For the axial stress of 25,000 psi not to be exceeded, the maximum load that can be supported by the bar, P = 112,500 lb ≈ 110,000 lb.
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can i have a answer
best answer gets brainliest
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Answer: the square root of 25 is 5.
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M a t h
Explain:
(Sorry it’s not all of them)
45 + 2,034 = 2,079 + 20 = 2,099 + 78 = 2,177
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1,000 + 1,000 + 1,000 = 3,000 using multiplication makes it faster by saying 3 1,000 times is 3,000.
Drag the tiles to the correct boxes to complete the pairs.
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Mia wants to measure charge and convert it into electrical signals it is charge-coupled devices. Dr. Jerry wants to measure the damages in the tissue of the body and thus diagnose illnesses. is magnetic resonance imaging, John wants to measure the length, diameter, or thickness of objects in mechanical engineering.
What are measuring devices?A tool used to measure a physical quantity is called a measuring instrument. Measurement is the process of gathering and comparing physical quantities of actual objects and events in the physical sciences, quality control, and engineering.
Researchers and practitioners employ measurement tools to help in subject, client, or patient assessment or evaluation.
Mia wants to use charge-coupled devices to measure charge and turn it into electrical impulses. In order to diagnose ailments, Dr. Jerry wants to quantify the bodily tissue damage.
John wishes to measure the length, diameter, or thickness of things in mechanical engineering using magnetic resonance imaging.
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I did the activity! Hope this helped you! you just have to put the number not the explanation! Have a great day and make sure you thank me! :)
Add the watts from the TV(150) plus the cable box when on(140) and off but plugged in(18). Then it will give you an answer of 308 watts.
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P(Y-X=m\mid Y\gt X)
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