on any given day, one person needs an average of 2.5 liters of water to survive. how many people will a tank supply for the day

Answers

Answer 1

Answer:

3936 people

Explanation:

Water Tank = 9840 liters of water.

Now divide the total amount of water available by the amount of water needed per person to get the number of people that can consume all the water:

9840 Liters / (2.5 Liters/ 1 person) =

1 person * 9840 Liters / 2.5 Liters =

1 person * 9840/2.5 = 3936 people


Related Questions

How will Hyperloop trains be different from traditional trains?

Answers

Answer:

Its passengers would sit comfortably in a pod while being propelled forward through a de-pressurized tube at 700 to 800 miles per hour (mph). The Hyperloop is afforded its super-fast travel speeds because of the tube, which allows the pod to travel through a virtually resistance-free track.

Explanation:

How do engineers deal with liquefaction when building a very tall building?

Answers

A structure that possesses ductility, has the ability to accommodate large deformations, adjustable supports for correction of differential settlements.

What is liquefaction?In reaction to an applied stress, such as the shaking during an earthquake or other fast change in stress state, a cohesionless saturated or partially saturated soil dramatically loses strength and stiffness, causing material that is typically a solid to behave like a liquid. When there is considerable ground shaking, loosely packed, water-logged sediments at or near the ground surface begin to liquefy. When there is considerable ground shaking, loosely packed, water-logged sediments at or near the ground surface begin to liquefy. During earthquakes, liquefaction that takes place beneath buildings and other structures can result in significant damage. Liquification is the physical conversion of a gas into a liquid state (condensation).

To learn more about liquefaction refer to:

https://brainly.com/question/13044551

#SPJ4

Write a Python code to accept integer numbers in a list. Find and display the
sum and product of the numbers available at even and odd indices of the list,
respectively.

Answers

#initializing list

list1 = []

 

# accepting values from user

n = int(input("Enter number of elements in list: "))

 

# iterating till the range

for i in range(0, n):

   ele = int(input())

 

   list1.append(ele)

# sum and product at even and odd indexes

even_sum = 0

odd_sum = 0

even_prod = 1

odd_prod = 1

# iterating each element in list

for j in range(len(list1)):

   if j % 2 == 0:

       even_sum += list1[j]

       even_prod *= list1[j]

   else:

       odd_sum += list1[j]

       odd_prod *= list1[j]

# Displaying sum and product of even and odd indices

print("Sum of elements at even indices:", even_sum)

print("Product of elements at even indices:", even_prod)

print("Sum of elements at odd indices:", odd_sum)

print("Product of elements at odd indices:", odd_prod)

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