Imagine that you are the hiring manager at a corporation like ge, with businesses in the healthcare, renewable energy, and operations data fields. Which basic building block of structure would you use as you scale down on managerial positions and scale up on engineering positions?.

Hardened steel cutting edges honed with option A: An oilstone.

Check more about Honed edge below.

What is a honed edge on a cutting tool?

In order to significantly increase the flake and wear resistance of cutting tools constructed from brittle materials like carbide, edge honing, also known as edge rounding, that is its stabilizes the cutting edge.

Therefore, To hone a chisel, a person need to place a little amount of oil on an oilstone. Here, one need to place the back of the said chisel blade flat on top of the stone and then one can gently rub it very well.

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The overall specifications for electrical system bonding and grounding, for both grounded and ungrounded systems, are set forth in Section 250.4.

The service disconnecting equipment must be located either outside of a building or within, close to the point where the service conductors enter. Equipotential planes must be connected to the grounding system for electrical equipment.

The equipment grounding conductor must be one, more, or a mix of the following when it is run with or around the circuit conductors: a conductor made of copper, aluminum, or copper-clad aluminum. This conductor must take the form of a wire or a busbar and can be solid, stranded, insulated, covered, or bare.

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The maximum negative moment at E is -22500lb-ft

The maximum positive shear at E is 4750lb

Given the following:

Dead load=500

Single concentrated force=5k

Part a

Maximum negative moment at E

To get maximum negative moment at E, place the point load at B:

Moment=(1/2*4.5*18*500)-(1/2*4.5*18*500)-(5000*4.5)

               =20250-20250-22500

                =-22500lb-ft

Part b

Maximum positive shear at e

To get maximum positive shear at E, place the vertical load either B or right of E:

Shear=(1/2*0.5*18*500)-(1/2*0.5*9*500)+(1/2*0.5*9*500)+(5000*0.5)

           =2250-1125+1125+2500

            =2250+2500

             =4750

Shear at E=4750lb

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An estimate of the safety factor of the shaft is 1.10

We have the following:

Torque=230nm

Diameter=25mm

Yield tension=160mpa

Yield compression=170mpa

To estimate the safety factor of the shaft, we will have to find first the following:

Maximum shear stress:

Shear stress=[tex]\frac{16T}{\pi d^{3} }[/tex]

                   =    [tex]\frac{16*230}{\pi *(25mm*\frac{10^{-3}m }{1mm})^{3} }[/tex]

                   =75MPa

We, now get the principle stress:

σ[tex]_{1}[/tex]=75MPa

σ[tex]_{2}[/tex]=-75MPa

The torsional yield strength:

Torsional yield strength=(yield strength in tension*yield strength in compression)/(yield strength in tension +yield strength in compression)

                                   =(160*170)/(160+170)

                                  =82.4MPa

Now, we can calculate the factor of safety using this given relation:

Factor of safety=(Torsional yield strength/Maximum shear stress)

                         =82.4MPa/75MPa

                         =1.0987

                         =1.10

Safety factor of the shaft, n=1.10

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According to the information, it can be inferred that the correct option is that the term 5 why's accident investigation technique refers to an interrogative technique to identify the causes and effects related to a problem (option B)

5 Whys is a term that refers to an investigative technique used to identify cause and effect relationships related to a specific problem. This investigative technique is generally used in the work environment to identify the origin of an accident at work or production problems and was developed by Sakichi Toyoda.

This technique is mainly based on asking 5 times "Why?" to identify the root of the problem. For example:

According to the above, it can be inferred that the correct answer is the option that refers to the 5 questions related to the cause and effect of a problem (option B).

Note: This question is incomplete because there is some information missing. Here is the complete information:

A. 5 questions for a job interview

B. 5 questions related to the cause and effect of a problem

C. 5 questions related to diseases in animals

D. 5 questions about injuries in athletes

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Answer:

Explanation:

code in the curly braces is treated as regular body and will be executed normally

Given that the rod is initially in an unstressed state, finding the compressive force that is created in ABC as the temperature rises by 55°C yields a value of 156.902 kN.

Portion AB's size is 7.0695 X 10⁴ m².

BC portion's size is 1.96373 X 10³ meters.

505.725 X 106m for free thermal expansion is equal to (0.25)(11.7 X 106)(55) + (0.3)(20.9 X 106)(55).

Induced compressive force-induced shortening P= = 1.7682 X 10⁹ P + 1.455 10⁹ P = 3.2232 X 10⁹ P

3.2232 X 10⁹P = 505.725 X 10⁶ P = 156.902 X 103 N = 156.902 kN with zero net deflection.

As a result, ABC is subjected to a compressive force of 156.902 kN.

An action that seeks to preserve, modify, or deform a body's motion is called applying force.

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The greatest moment produced by these loads  at c is 16.53 K.ft and the greatest positive shear by the load at c is 1.267 K.

A force's moment is a measurement of how likely it is to make a body rotate around a certain point or axis. This differs from a body's propensity to translate or move in the direction of the force. A body must experience the force in such a way that it starts to twist before a moment may emerge. This happens each time a force is applied so that it misses the body's centroid. When a force does not have an equal and opposing force acting immediately across its path of action, a moment results. Consider two individuals attempting to open a door at the doorknob from opposing sides. There is an equilibrium state if they are both pushing with the same amount of force. If one of them suddenly leaped back from the door, the other person's push would be met with no resistance, and the door would swing away. A pause was caused by the door-pusher who persisted in doing so.

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The reinforcement must be stored in such a manner as to prevent: deterioration and corrosion.

Concrete reinforcement is accomplished by inserting deformed steel bars or welded wire fabric inside newly cast concrete. The goal of reinforcing is to give strength to concrete where it is required.

All exposed reinforcing surfaces should be carefully cleaned of loose mortar, corrosion, and other pollutants. To prevent overbuilding and limit bond development loss at rebar deformations, the high-performance protective coating should be placed at a thickness of 305 microns.

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Full Question:

What are the words that complete the sentence below:

The reinforcement must be stored in such a manner as to prevent:

It is important to keep welders properly tuned because it "Reduces air pollution" (Option A).

Welding machinery, welding guns, and welders are among the most important items for a welding expert to have. Welding machines provide heat that melts steel pieces, allowing them to be bonded.

Most welders also use an angle grinder to smooth out joints, wire brushes to clean or abrade steel surfaces before welding etc.

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Full Question:

Why is it important to keep portable welders properly tuned?

a-Reduce air pollution

b-So they run quieter

c-To produce smoother welding current

d-All of the above

Answer: that’s too much for me

Explanation:

Waa

The thing that happens when a capacitor is connected to a DC source is that Capacitors charge up until the voltage across the capacitor is equal to the externally applied voltage when they are linked across a direct current DC supply voltage.

Capacitors slowly charge in a DC circuit until the charging voltage of the capacitor is equal to the supply voltage. The capacitor will not permit any extra charges to travel through it after it has been fully charged.

Note that the link between a capacitor and voltage and current can be summarized as follows: the capacitance and the rate of rise or fall of the voltage determine how much current flows through a capacitor. A strong positive current will be produced through a capacitor if the voltage across the capacitor rises quickly.

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Split-phase motors are induction motors used in applications that operate in the fractional horsepower range, such as fans and compressors in capillary tube systems.

Another name for the split phase motor is the resistance start motor. It contains a single cage rotor and two windings in its stator, referred to as the main winding and starting winding. The positions of both windings differ by 90 degrees. The starting winding has a high inductive reactance and a very low resistance, while the main winding has a high resistance and a low inductive reactance. With the auxiliary winding, a resistor is connected in series. The two windings' respective currents are not equal, and as a result, the rotating field is not even. As a result, the beginning torque is low, typically 1.5 to 2 times the reported running torque. Both windings are parallel connected when the motor first starts.

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The total combinations are possible is 125 combinations.

We need to know about math combinations to solve this problem. The combination is the number of ways to choose a sample of r elements from a set of n distinct objects where order does not matter and replacements are not allowed. It can be written as

nCr = n! / (r!(n-r)!)

where n is object and r is a sample

From the question above, we know that

1  vitamin supplement chosen has combination

5C1 = 5! / 1!(5-1)! = 5 combination

1 meditation chosen has combination

5C1 = 5! / 1!(5-1)! = 5 combination

and 1 dietary chosen has combination

5C1 = 5! / 1!(5-1)! = 5 combination

Hence, the total combination is

C = Cvitamin x Cmeditation x Cdietery

C = 5 x 5 x 5

C = 125 combinations

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For applications involving fire resistance and the insulation of high-temperature pipelines and machinery, calcium silicate (CalSil) is employed. Prefabricated block, preformed pipe, and board are the three distinct ways it is produced and offered for sale.

Calcium silicate's insulating properties are due to the millions of microscopic air holes that are separated by crystalline walls with low thermal conductivity. It is a good high-temperature insulation material since very little infrared radiation may flow through it. To achieve fire endurance, calcium silicate, often known as "calsil," is used to insulate high temperature pipes and equipment. Prefabricated block, preformed pipe, and board are the three distinct ways it is produced and offered for sale. Table salt and other foods are prepared with calcium silicate as an anti-caking agent and as an antacid.

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The heat generated within the wire is 1.05 x 10¹⁰ W/m³ with a maximum temperature of  589.5 K.

Heat is the energy that has a correlation with the resistivity of the material. Resistivity depends on the resistance and wire dimension where the resistance of the material can be written as

R = ρ.L/A

where R is resistance, ρ is resistivity, L is the length of the wire and A is surface area.

The given parameters from this question are

σ = 14 W/m.K

ρ = 45 x 10¯⁸ Ωm

I = 120 A

d = 1 mm

r = 0.5 mm = 5 x 10¯⁴ m

Calculate the surface area

A = πr²

A = π(5 x 10¯⁴)²

A = 7.86 x 10¯⁷ m²

In 1 m³, the length of wire should be

V = A . L

1 = 7.86 x 10¯⁷ . L

L = 1272727.273 m

Find the resistance of wire per m³

R/V = ρ.L/A

R/V = 45 x 10¯⁸ . 1272727.273 / 7.86 x 10¯⁷

R/V = 728925.62 Ω/m³

Find the heat generated per m³ by using power

P/V = I² . R

P/V = 120² . 728925.62

P/V = 1.05 x 10¹⁰ W/m³

Find the heat generated per m by using power

P/L = P/V

P/L = P/V . A

P/L = 1.05 x 10¹⁰ . 7.86 x 10¯⁷

P/L = 8253 W/m

Find the maximum temperature

T = (P/L) / σ

T = 8253 / 14

T = 589.5 K

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The correct statement is technician B, that says if  the torque multiplication phase can occur when the stator one-way clutch locks up.

Torque multiplication can be defined as a multiplying factor that is used to determine how much added torque is being applied to a vehicles drivetrain. Torque multiplication is calculated with scientific and mathematical precision by rationalizing factory power against all influential physical forces.

In multiplying torque, the stator’s one-way clutch plays an important role. Vortex flow is the fluid circulating between the impeller and the turbine. Vortex flow exists only when there is a difference in rotational speed between the impeller and turbine.

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The groove has been machined a fully corrected endurance limit is = 1.792. Simply maintain all stress amplitudes below the fatigue limit if you wish to design for unlimited life, as was previously suggested.

Life will continue to exist indefinitely as long as even the highest stress amplitude is below the exhaustion limit. The "infinite life" zone for ferrous materials is bounded by a "endurance limit." The endurance limit of a material is a specified stress level below which fatigue damage from stress cycles will not be accumulated.

Given that D=2.1, d(diameter)=1.892, and r=0.17

The material's maximum endurance is 60 kpsi.

Using the Goodman relation, nf equals 0.833.

Safety factor yielding equation: ny= Sy/max= 66/36.828 ny= 1.792

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The cutting blade's bevel angle on a pair of snips typically measures is option A. 90 degrees.

These are said to be left- or right-cutting forged steel snips have 90-degree-angled jaws for that of convenient grasping while cutting sheet metal overhead or in a place that is said to be a constricted locations.

Therefore, note that a pair snips is said to be a little pair of shears that is known to be used for cutting sheet metal.

Hence, based on the above, option A is correct.

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The load-carrying capacity of a system above and above what the system actually supports is a safety factor. Ultimate Load (Strength)/Allowable Load = Factor of Safety (Stress).

All structures, including bridges, buildings, safety gear, and fall protection, begin with a factor of safety. The safety factor, defined simply, is how much more robust a system is than necessary. In mechanical engineering, the ratio of material strength to allowed stress is known numerically as the factor of safety. For instance, let's say that a shaft needs to be able to support a 100 kg load. However, if our shaft is built to support a 200 kg load. The value of the Shaft safety factor is "two." When a structure or component has a FoS of 1, it signifies that it will fail exactly at the design load and cannot support any additional load.

The complete question is- The steel pipe is supported on the circular base plate and concrete pedestal. The applied force is 500 KN and the normal failure stresses for steel and concrete. The thickness of the pipe is t = 5 mm and the base plate has a radius of 150 mm. a) Determine the factor of safety against failure of the steel. b) Determine the factor of safety against failure of the concrete.

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The numerical values for the mesh currents that we have in the question are given as:

We first have to write the KVL

2 - 1(i₁ - i₂) + 3 - 5(i₁ - i₃) = 0

We have to expand the equation that we have above

2 - i₁ + i₂ + 3 - 5i₁ + 5i₃ = 0

take like terms

-i₁ - 5i₁  i₂ + 5i₃ = 5

=  6i₁ - i₂ - 5i₃ = 5

-1(i₂ - i₁) - 6 i₂ - 9(i₃ - i2) = 0

after expanding we would have

i₁ - 16i₂ + 9i₃ = 0------- equation 2

-5 (i3 - i1) - 3 - 9(i3 - i2) - 7i3 = 0

5i1 + 9i2 - 2i3 = 3 ------ equation 3

From the equations that we have in 1, 2 and 3, we would solve the system of equations to get

1i = 0.9892 = 0.9892 ampere

i2 = 0.1501 ampere

i3 = 0.1570 ampere

These are the mesh current that are in the labeled diagram.

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A voltage that is lower than either of the batteries linked alone is produced when two batteries are connected in series to create an additive power source.

The sum of the separate voltages when voltage sources are coupled in series results in the total voltage. Voltage dips in a series circuit are additive, as was previously mentioned. Voltage decreased across a resistor is referred to as a voltage drop. The voltage drop across a resistor increases along with the resistor's resistance. The sum of the individual resistances in a series circuit is the overall resistance. To get the amperage in a series circuit, you must compute the circuit's overall resistance.

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Equal-tangent crest vertical curve connects a 2% initial grade with a -1% final grade, and is designed for 55mph. that station of the pvi is 233 40, with an elevation of 1203 ft. the elevation of the curve at station 234 00 is 1202.102 ft

G1=+2%, Gz\s=-1%

Grade variance in absolute terms equals A = (G1 - G2) = (2 + 1) = 3%

V = 55 mph is the design speed.

V = 55 mph requires a stopping sight distance of SSD = 492.4 feet.

Assume SSD > Curve Length.

L=2SSD - 2158/A = 2x492.4 - 2158/3 = 265.47 ft Station of PVI = stapvi = 233 + 40 = 23340 ft

PVC Elevation = stave - stapvi - L/2 = 23340 - 265.47/2 = 23207.765 ft PVI Elevation = elevpri = 1203 ft

PVC's elevation is equal to elevpri- - GI(L/2) = 1203 - 0.02(265.47/2) = 1200.345 ft.

According to this theorem, if two tangents are traced to a circle from a single exterior point, their tangent segments must be equal. A tangent segment is a line that connects the external point and the tangency point.

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The absolute permeability of the soil is 5.1016*10^{-6} cm^{2}

The absolute permeability of the soil is calculate using the formula:

Absolute permeability=(Hydraulic conductivity*Viscosity of water)/Density of water

Hydraulic conductivity=0.56

Density of water=1

Viscosity of water=[tex]0.0911*10^{-4}[/tex]

We are now finding absolute permeability:

Absolute permeability=(0.56*0.0911^-4)/1

Absolute permeability=[tex]5.1016*10^{-6} cm^{2}[/tex]

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This prompt is about Prince George's Wood Innovation Design Center. The building was erected as a model to highlight the possibilities of wood innovation and a departure from conventional concrete and steel architecture and building engineering models.

The Wood Innovation Design Centre (WIDC) is a meeting space for researchers, educators, and design professionals who are brainstorming new ways to use wood. The bottom floors of the building are dedicated to Integrated Wood Design instruction.

The Wood Innovation and Design Centre is located in Prince George, British Columbia. Michael Green Architecture ("Wood Innovation and Design Centre" n.p.) designed the 97-foot-tall, eight-story (six-story includes mezzanine and penthouse) structure.

The building's sleek, contemporary box shape is purposefully simple. Its simplicity serves as a canvas for the beauty of the numerous kinds of wood and their features, which include Douglas-fir, western red cedar, hemlock, pine, and spruce from British Columbia's sustainable forests.

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The major advantage of using compound joint snips over a single joint tool is option B: you can begin the cut with a file.

Standard compound-action snips are known to be a form of a hand tool that is said to be made to cut steel or softer materials, yet it is not harmful to use them sometimes on stainless steel.

Note that the key or the  major merit or benefit of using compound joint snips than the use of a single joint tool is due to the fact that a person can be able to use it to cut a lot of steel.

Hence, option B is correct.

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The calculated mean value is 16. The sum of all values divided by the total number of values determines the mean (also known as the arithmetic mean, which differs from the geometric mean) of a dataset.

The term "average" is frequently used to describe this measure of central tendency. By dividing the sum of the given numbers by the entire number of numbers, the mean—the average of the given numbers—is determined. Mean is equal to (Sum of All Observations/Total Observations).

Mean=12+15+17+20/4

=16

Special road signage designate 10-cent zones. At the beginning and finish of the zone, there are signs. There is one space available for as long as three or four hours each day. Only specific hours of the day are subject to the 10 cent rate. There may be a Blue Zone in locations where paid parking is not (yet) in effect.

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At f=1MHZ is the frequency gain reduced to ‐2 v/v and integer time constant is 0.079μs in op-amp based inverting integrator.

The number of waves that pass a fixed point in a unit of time is known as frequency in physics. It is also the number of cycles or vibrations that a body in periodic motion experiences in a unit of time.  A simple harmonic motion is also seen under angular velocity. If one cycle or vibration takes half a second to complete, the frequency is two per second; if it takes a full hour, the frequency is one hundred per hour. Divide the number of times the event occurs by the amount of time to find frequency. The number of times someone blinks their eyelids in a minute, or frequency, is 47. The definition of frequency, expressed in hertz, is the number of oscillations of a wave per unit of time (Hz). The relationship between frequency and pitch is straightforward. Frequencies between 20 and 20000 Hz are audible to humans.

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The compressor's efficiency must be taken into account; it is equivalent to 0.72, resulting in a needed power of 156*0.72 = 216.8 kW.

The compressor motor nameplate on the majority of industrial three phase air compressors will indicate the line voltage, which is commonly 240 V or 480 V. In our experience, the power factor of 50 to 150 horsepower compressors is approximately 85% when operating normally1. The amount of air the device can pump out is known as the compressor capacity. Compressor capacity and pressure may be easily distinguished from one another since the former reveals "how much" and the latter measures "how strong." the proportion between the maximum compressor load and the average compressor load for a given time period.

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A safety factor is the amount of weight that a system can bear over and beyond what it can actually support. Factor of Safety = Ultimate Load (Strength)/Allowable Load (Stress).

Every structure, including buildings, bridges, safety equipment, and fall protection, starts with a safety factor. Simply put, the safety factor is how much more robust a system is than required. The safety factor is a numerical term used in mechanical engineering to describe the relationship between material strength and allowable stress. Let's take the example of a shaft that must be able to support a 100 kg load. Nevertheless, if our shaft is designed to hold a 200 kg load. The Shaft safety factor has a value of "two."

The complete question is- The steel pipe is supported on the circular base plate and concrete pedestal. The applied force is 500 KN and the normal failure stresses for steel and concrete. The thickness of the pipe is t = 5 mm and the base plate has a radius of 150 mm. a) Determine the factor of safety against failure of the steel. b) Determine the factor of safety against failure of the concrete.

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