Radial acceleration is inversely related to the radius of the curved pathway and directly proportional to the square of the linear speed. The ratio of the square of the angular speed to the radius of the curved pathway is directly proportional to the radial acceleration.
Explain about the radius and acceleration?This is the acceleration of an object moving at speed v within a circle of radius r. Therefore, as you may have experienced while driving a car, centripetal acceleration is greater at high speeds and in acute curves (smaller radii). y.
We can argue that as the radius increases, the centripetal acceleration of the item moving in a circle falls exponentially. Along the radius, the centripetal acceleration's magnitude diminishes.
The centripetal acceleration would be decreased if the radius were decreased while all other factors remained constant, but it would be increased if the speed were increased while all other factors remained constant.
The radius of the circular path is 10m and the acceleration is 1.5g the speed of the rider is 1.82 m/s/s.
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i need help with this lab. i have to answer the lab questions 4-10. i will upload the graphs u need to use. someone please answer these questions. i will upload the pictures in different questions because it won’t let me upload 3…
The speed of an object is the rate of change of its position, and the object's velocity includes its speed as well as its direction of motion. The rate of change of the object's velocity gives the acceleration.
Explain Speed,Velocity and Acceleration?When an object's reference frame is chosen, its motion can be precisely characterized. The pace at which an object's position changes while it is moving is referred to as speed. The object's speed indicates how quickly or slowly it is going. But which way is the item traveling? The velocity of an object includes information about its direction of motion. The rate of change of an object's velocity, or the change in velocity per unit of time, is known as its acceleration.
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What is the total translational kinetic energy of 1.6 mol of N₂ molecules at 27°C?
The total translational kinetic energy of 1.6 mol of N₂ molecules at 27°C is calculated as 9673 J as pern the Kinetic energy formula with Boltzmann Constant.
How is translational kinetic energy calculated?Remember that the mass of the item multiplied by the square of its linear velocity (around its center of mass) yields translational kinetic energy, which is then divided by two.
What is the kinetic energy of translation?The energy of motion of a body is equivalent to the work it would perform if it were brought to rest, according to general physics.
For a rigid body with constant mass, the translational kinetic energy is dependent on motion through space and is calculated as the product of the square of the speed and the product of the mass divided by half.
N2 is an adiatomic molecule
Total translational Kinetic energy of adiatomic gas
E = 5/2 NKT
1 mol = 6.022 x [tex]10^{23}[/tex]
1.6 mol = 1.6 x (6.022 x [tex]10^{23}[/tex])
= 9.635 x [tex]10^{23}[/tex]
Boltzmann constant K = 1.38 x [tex]10^{-23}[/tex] J/K
Temperature = 18° C
= (18 + 273) K
= 291 K
Putting the values,
E = 5/2 x (9.635 x [tex]10^{23}[/tex] ) x (1.38 x [tex]10^{23}[/tex]) x 291 K
= 9673 J
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URGENT!! ILL GIVE
BRAINLIEST! AND 100 POINTS
Mariana conducted an experiment where she burned a 5 g strip of magnesium metal in an open flame. The result was a 3.5g white ash collected in a crucible, a bright white flame, and smoke. Was the law of conservation of matter upheld in Mariana's experiment?
A. no, because mass decreased after the magnesium was burned
B. yes, because the missing mass was trapped by the closed system
C. yes, because the missing mass was released as smoke
D. no, because the magnesium was burned so mass was not lost
Answer:
B, Yes
Explanation:
Since the 5g of magnesium became 3.5g and white fire and smoke, it still has the same mass. It is just in a different form.
Yes, the law of conservation of matter was upheld in Mariana's experiment because the missing mass was released as smoke, therefore the correct answer is option C.
What is the matter?Anything which has mass and occupies space is known as matter, mainly there are four states of matter solid liquid gas, and plasma.
These different states of matter have different characteristics according to which they vary their volume and shape.
As given in the problem Mariana conducted an experiment where she burned a 5 g strip of magnesium metal in an open flame. The result was a 3.5g white ash collected in a crucible, a bright white flame, and smoke.
Yes, the law of conservation of matter was upheld in Mariana's experiment because the missing mass was released as smoke, therefore the correct answer is option C.
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a customer sits in an amusement park ride in which the compartment is to be pulled downward in the negative direction of ayaxis with an acceleration magnitude of 1.24g,with g
The magnitude of the downward acceleration of the customer is 12.15 m/s².
What is downward acceleration?
A downward acceleration is the acceleration experienced by an object moving downwards.
During the downward motion of an object, the velocity of the object increases while the downward acceleration acceleration remains constant.
The velocity increases and eventually become maximum before the object hits the ground.
Also, another observation is that, the acceleration of the object is always directed downwards.
The magnitude of the downward acceleration of the customer on amusement park is calculated as follows;
a = 1.24 g
where;
g is acceleration due to gravity = 9.8 m/s²a = 1.24 x 9.8 m/s²
a = 12.15 m/s²
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The complete question is below:
a customer sits in an amusement park ride in which the compartment is to be pulled downward in the negative direction of ayaxis with an acceleration magnitude of 1.24g,with g. find the magnitude of the acceleration.
You push a book across a table. The book moves at a constant speed, but you do not move. Identiffy all the forces on you. Then identify all of the forces on the book
The forces acting on me are static frictional force and reaction force of the book. The forces acting on the book moving with a constant speed are Applied force and Kinetic frictional force.
Forces acting on me are
Static frictional forceReaction force of the bookThe book at rest, will have a static frictional force. So when I push the book, these forces will act on me. According to Newton's third law of motion, when I apply a certain amount of force on the book, the book will exert the equal amount of force on me.
Forces acting on the book are
Applied forceKinetic frictional forceThe book when moving at constant velocity will have zero net force, because according to Newton's second law of motion, force is directly proportional to acceleration. If the velocity is constant, acceleration will be zero and net force will also be zero. Since the book is moving on a table, a kinetic frictional force will act on the book to resist the movement of the book.
Therefore,
The forces acting on me are Static frictional force and Reaction force of the book.The forces acting on the book are Applied force and Kinetic frictional forceTo know more about Newton's second law of motion
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A ball is projected horizontally from the top of a vertical cliff 40m high with a velocity of 20m/s. Calculate the vertical component of the velocity on getting to the ground
A ball when is projected horizontally from the top of a vertical cliff 40m high with a velocity of 20m/s, the vertical component of the velocity on getting to the ground is 28.3 m/s.
What is motion under gravitational field?When any object moves, it can be said to be in motion under gravity because gravity has an impact on the object’s vertical motion. Gravity is also called as the force that pulls things downward. In actuality, gravity pulls objects toward the Earth’s center.
What is the motion under gravity equation?The particle’s initial velocity is 0 during free fall. Consequently, this v=gt is the equation of motion.
An object launched into the air may also experience a shift in upward velocity due to gravity, which causes it to slow down and return to Earth’s surface. The Moon is kept in orbit by the force of Earth’s gravity, which also causes the Moon to rotate constantly.
Initial horizontal velocity = 20[tex]ms^{-1}[/tex]
Initial vertical velocity = 0
Vy= Uy + gt
Vy= gt {Uy= 0}
Vy= 10 × 2.83= 28.3m/s
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If Rico pulls on a 30 kg box of supplies with a force of 200 N towards the nearest firefight and Ace pulls on the box with a force of -56 N in the opposite direction, what is the net force (in Newtons) on the box of supplies?
The net force (in Newton) on the box of supplies, given that Rico pulled it with a force of 200 N is 256 N
How do I determine the net force?From the question given above, the following data were obtained:
Mass of box = 30 KgForce of pull = 200 NOpposite force = -56 NNet force =?The net force on the box of supplies can be obtained as illustrated below:
Net force = force of pull - opposite force
Net force = 200 - (-56)
Net force = 200 + 56
Net force = 256 N
Thus, the net force on box is 256 N
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a sonar system can use sound waves wih a frequency of 120kHz or 200kHz. A. what is the wavelength of each of these waves when they are sent through sea water?
B. What are their wavelengths in freshwater?
C. The ship operating these sonar systems is in sea water with a depth of 3km.
How long will it take an echo to return to the ship after a ‘ping’
(A) The wavelength of each of these waves when they are sent through sea water is 0.0126 m and 0.0076 m respectively.
(B) The wavelength of each of these waves when they are sent through freshwater is 0.012 m and 0.0074 m respectively.
(C) The time taken for the echo to return to the ship is 3.97 seconds.
What is the wavelength of the sound wave in sea water?
The wavelength of the sound wave in sea water depends on the speed of sound in seawater and frequency of the wave.
The speed of sound in seawater, v = 1,510 m/s
λ = v/f
when the frequency, f = 120 kHz
λ = 1510 / 120,000
λ = 0.0126 m
when the frequency, f = 200 kHz
λ = 1510 / 200,000
λ = 0.0076 m
The speed of sound in freshwater, v = 1481 m/s
when the frequency, f = 120 kHz
λ = 1481 / 120,000
λ = 0.012 m
when the frequency, f = 200 kHz
λ = 1481 / 200,000
λ = 0.0074 m
The time taken for the echo to return is calculated as follows
v = 2d/t
t = 2d/v
t = (2 x 3,000 m) / (1510 m/s)
t = 3.97 s
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a 689 n person lies down on a 2-m, 30-n board. their feet are exactly at the fulcrum. they are 1.75 m tall. the scale reads 330 n. where is their center of mass relative to their feet
A 2-m, 30-n board with a 689 n human lying down on it. The fulcrum is exactly where their feet are. They stand around 1.75 meters. Scale reading is 330 n. less than one meter separates their center of mass from their feet (0.91 m).
What is fulcrum?The pivotal point of the beam is known as the fulcrum. A load is applied at the other end of a lever when an effort is exerted to one end of the lever. A mass will be raised as a result. Torque is essential to the operation of levers.
The point on which the lever rotates or balances is known as the "fulcrum." Your hand's fingers serve as the fulcrum when using a fork. In reality, scissors are only two levers together. Commonly known as a fixed lever, the handle on the toilet flusher.
The phrase can be used to describe a lever's pivot point or support as well as the focal point of a significant event or circumstance (like an important person or key decision-maker in a company).
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A bullet is accelerated in the muzzle of a gun from rest to 150 m/s in 0.50sec. What is the acceleration?
Answer:
Bullets are cylindrical metal projectiles shot from firearms. Their main function is to kill or otherwise incapacitate. They come in numerous varieties for use in handguns, rifles, and machine guns. There is also special ammunition capable of penetrating armor, firing underwater, or firing "silently" at subsonic speeds. However, their designs are all basically the same. A typical cartridge consists of four components: the cartridge case, primer, propellant charge and bullet. When a gun trigger is pulled, the primer is struck, igniting the propellant. This causes a rapid expansion of gas, which forces the bullet forward and ejects the casing. Contrary to popular belief, guns are not loaded with bullets, but cartridges, and they fire bullets (since bullets are a more common term and the actual objects responsible for harm, they receive the recognition).
While small in size (the most popular handgun bullet is 9 mm in diameter) bullets posses enough kinetic energy to cause serious damage. Using a kinematics formula, it is possible to determine the acceleration of a bullet when the muzzle velocity and barrel length of a gun are known.
v2 = vo2 + 2as
Where
v is the muzzle velocity
vo is the initial velocity of the bullet, which is zero
a is the acceleration
s is the barrel length
Since acceleration is the desired value, the derived formula is this:
equation
When fired from a Beretta 92S, the standard issue US Army pistol, a 9 mm Parabellum bullet has a muzzle velocity of 335 m/s. With its 127 mm barrel length, the bullet's acceleration is calculated to be 4.4 × 105 m/s2.
The acceleration of a bullet depends largely on the gun from which it is fired, along with the intent of the user. Pistol bullets generally feature a lower acceleration than rifles or machine guns. Also, individuals involved with clandestine operations may use firearms with silencers, which suppress bullet speed and require special subsonic ammunition.
Remember, guns don't kill people. Bullets do. To paraphrase Chris Rock in Bigger, Blacker and Uncut, if bullet prices were raised to $5,000 each, there would be a drastic decrease in murders [mp3].
pdf a ball thrown vertically upward continues upward until it reaches a certain position, and then falls downward. the ball's velocity is instantaneously zero at that highest point. is the ball accelerating at that point. describe an experiment to prove or disprove your answer.
When the ball is thrown upward, gravity takes control as soon as it is removed from the hand. The ball will only be under its control.
The ball is moving downward at a rate of 9.8 meters per second squared as it approaches the dot-com point. Using a second camera and the gadget, you can perform an experiment where you can observe that the velocity is 0.0 at the top, but varies somewhat before and after it moves.
The ball is accelerating, as can be shown if you take the difference in velocities and calculate acceleration of the ball.
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what mass of limestone (in kg ) would be required to completely neutralize a 15.2 billion-liter lake that is 1.9×10−5 m in h2so4 and 8.6×10−6 m in hno3 ?
The mass of limestone (in kg ) required to neutralize the lake is 3542 kg.
First we have to balance the chemical equations:
[tex]H_{2}[/tex] [tex]SO_{4}[/tex]
[tex]CaCO_{3}[/tex] + [tex]H_{2}[/tex] [tex]SO_{4}[/tex] → CaS[tex]O_{4}[/tex] + [tex]H_{2}[/tex]O + C[tex]O_{2}[/tex]
HN[tex]O_{3}[/tex]:
CaC[tex]O_{3}[/tex] + 2HN[tex]O_{3}[/tex] → Ca(N[tex]O_{3})2[/tex] + [tex]H_{2}[/tex]O + C[tex]O_{2}[/tex]
It tells us that 1 limestone is needed for 2 moles of Nitric Acid.
Now, calculate number of moles by getting the product of volume and molarity.
moles [tex]H_{2}[/tex] [tex]SO_{4}[/tex]= 1.9 × [tex]10^{15}[/tex] M * (15.2 x [tex]10^{9}[/tex] L)
moles [tex]H_{2}[/tex] [tex]SO_{4}[/tex] = 288800 mol
moles HN[tex]O_{3}[/tex] = 8.6 × [tex]10^{-6}[/tex] M * (15.2 x [tex]10^{9}[/tex] L)
moles HN[tex]O_{3}[/tex] = 130720 mol
Total moles of limestone:
Moles of limestone = 288800 + 130720
Moles of limestone = 354160 mol
Multiply mol of limestone with its molar mass.
mass of limestone = 354160× 100.086
mass of limestone = 3542 kg
Thus, The mass of limestone (in kg ) required to neutralize the lake is 3542 kg.
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a uniform cube of mass m and edge a moves on a horizontal surface along the positive x-axis, with initial velocity v0: (a) during motion, n>mg (b) during motion, normal reaction acts on the centre of mass (c) during motion, the normal reaction shifts towards positive x-axis from the centre of mass (d) during motion, normal reaction shifts in the direction of the forces of friction
Option C about friction is correct statement with initial velocity v0.
What is friction?
friction is a force that opposes motion between any surfaces that are touching. Friction can work for us yet against of us .
It is the action of one surface or object rubbing against another .
Solution -
According to the given question in this case force of friction has a tendency to rotate the cube in anticlock wise direction.
So normal reaction will shift in forword direction to balance the force due to torque of friction.
Thus,
During motion the normal reaction shift towards posetive x- axis from the centre of mass is correct.
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Determine how many helium-filled balloons will be needed to lift a person whose mass is 70 kg. the air density is pair = 1.20 kg/m3 , the helium density is phe = 0.17 kg/m3, and the balloon's volume is vm = 30 liters.
2265 helium-filled balloons will be needed to lift a person whose mass is 70 kg.
Bouyancy, also known as upthrust, is an upward force applied by a fluid against the weight of an object that is partially or completely submerged. According to Achimede's principle, a force acts in opposition to an object's weight; if the force is higher than the object's weight, the object will float, but if the force is less than the object's weight, the object will sink. As a result, the helium balloon's weight must be more than the man's weight in order to lift him.
Vm = 30L
Mass = 70kg
Air density = 1.20kg/m^3
Helium density = 0.17kg/m^3
Overall density = Air density - Helium density
= 1.20 - 0.17
= 1.03kg/m^3
Convert the overall density to kg/liter
1.03/1000
0.00103kg/liter
Force on balloon
F = Overall density × vm
= 0.00103 × 30
= 0.0309kgf
Number of ballons is
70kgf/ 0.0309kgf
= 2265.37 ballons
=2265 ballons
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A ball is launched with initial speed v from ground level up a frictionless slope. The slope makes an angle θ with the horizontal. Using conservation of energy, find the maximum vertical height hmax to which the ball will climb.
The maximum vertical height hmax to which the ball will climb by the law of conservation of energy is, hmax = (1/2g)ν² cos θ
What is conservation of energy?
The law of conservation of energy states that the total amount of energy of an isolated system remain constant. Also for energy to be conserved, the sum of initial kinetic energy and the potential energy of the system is equal to the sum of final kinetic energy and the potential energy of the system. i.e.
Ki + Ui = Kj + Uj
where K represent Kinetic energy and U represents potential energy.
Since the ball is launched with initial speed v from ground level up a frictionless slope, it means the ball slides up the slope without rolling. The initial kinetic energy of the ball is given as:
Ki = 1/2mv²
The slope makes an angle θ with the horizontal. This means that velocity will be equal to zero in y-direction and velocity in x-direction is:
Ki = 1/2mv²cos θ
Potential energy of the max height is Uf = mghmax
The final potential energy the ball posses will be equal to the intial kinetic energy of it at the maximum height. Thus by the conservation of energy:
mghmax = 1/2mv²cos θ
hmax = 1/2gmv²cos θ
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The international Agreed system of Units (SI) for physical measurement, are! (A) lb, fl, s (b) g,m, s (c) kg, m,s (d) cm,g,s ( e ) kg,cm,s
Answer:
Option (c) - Kg, m, s
Explanation:
The internationally agreed system of units for physical quantities is based on the fact that kg(kilogram) is the unit of mass, m(meter) is the unit of length and (second) is the unit of Time.
Based on properties of elements in the periodic table, which element is the best conductor of thermal energy?
A. argon(Ar)
B. germanium (Ge)
C. polonium(Po)
D. vanadium(V)
Answer:A. argon(Ar)
Argon is commonly considered to be a chemical by most people
a large air-filled 0.211-kg plastic ball is thrown up into the air with an initial speed of 10.9 m/s. at a height of 3.49 m, the ball's speed is 3.03 m/s. what fraction of its original energy has been lost to air friction?
Initial energy equals (M/2)*Vo2 = 12.80 J.
At 4.7 m and V = 5 m/s, total energy equals (M/2)
*5^2 + M*g*4.7 = 1.25 + 4.61 J
a portion of the energy in a ball LOST = (12.80-5.86)/12.80 \s= 0.542
We are informed that a plastic ball with a mass of 0.1 kg is tossed into the air as an example of energy conservation. It starts off at a height of three meters and a speed of 10 meters per second. Now moving at three meters per second. We are interested in learning how much of its initial energy has been lost through friction. We now know that the total mechanical energy is constant for an isolated system. Thus, the change in gravitational potential energy descends to you along with the change in kinetic energy data K. additionally the data on N. G. Lost to air friction Zero is equal to E. F. Keep in mind that the gravitational potential energy you I is zero at the beginning.
It follows that either their energy changes or that the energy lost to friction belt E. F. is equal to minus daughter. Kay, without a doubt, which is without uh-huh. Mm. V squared divided by the starting speed is the final speed. M. G. H. plus V not squared Additionally, the ball's initial energy is entirely kinetic. Since this is a half-squared north, the lost energy delta E. F. is the proportion of the original energy that is reflected and lost.
This therefore equals half of M. Squared into the not minus V squared into the not minus to G. H. multiplied by half. squared M Vinod Thus, this fraction becomes the square of the starting speed. We not squared minus the final speed squared square V squared minus twice the acceleration brought on by gravity, G times the height of the ball. H centered over Vinod. Therefore, if we enter our numbers here, this becomes 10 m/s squared times three m/s squared times two, or 9.81 m/km2 times. three meters tall times 10 meters per second squared.
As a result, 32 321 the amount of energy that is lost when there is an uncertainty about e f over e I This is the percentage that is lost due to air friction, or 32.1 percent.
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You throw a ball straight up into the air. the ball starts from rest and has a speed of 7.60 m/s when it leaves your hand. in the process of throwing the ball, you move your hand through a vertical distance of 1.02 m. if the ball has a mass of 0.150 kg and undergoes constant acceleration during the throw, calculate the magnitude of the force that you exert on the ball during the throwing process. hint: remember newton's 2nd law - an object's acceleration is due to the net force acting on it.
The force exerted on the ball is 28.88 N.
We need to know about force to solve this problem. According to second Newton's Law, the force applied to an object will be proportional to mass and acceleration. Hence, it can be written as
F = m . a
where F is force, m is mass and a is acceleration
From the question above, we know that
vo = 0 m/s
vt = 7.6 m/s
s = 1.02 m
m = 0.15 kg
Find the acceleration
vt² = vo² + 2as
7.6² = 0² + 2.a.0.15
a = 57.76 / 0.3
a = 192.53
Find the force exerted
F = m .a
F = 0.15 . 192.53
F = 28.88 N
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how quality helps to distinguish the sound waves having same loudness and same pitch?
Quality helps to distinguish the sound waves having same loudness and same pitch through the distinctive tone which is observed.
What is Quality?This is also referred to as timbre and is a feature which helps to distinguish sounds which have the same loudness. This means that the same loudness denotes the same amplitude while a similar pitch denotes the same frequency.
Quality is however the distinguishing factor it can be deciphered with the use of our sense of hearing which is ears and in the identification of sounds with such properties and is the reason why it was chosen as the correct choice.
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If the output work is 500 J and the input work is 380 J, what is the machine efficiency?
If the output work is 500 J and the input work is 380 J, then the machine efficiency can be calculated as 130 % as per the efficiency formula.
How do you determine a machine’s efficiency?Divide the output work by the input work to get a machine’s efficiency, then multiply the result by 100%.
Efficiency is equal to output times 100%.
How is energy efficiency calculated?You may determine the efficiency by figuring out what proportion of the energy input results in the desired output: Efficiency is defined as EnergyOut/EnergyIn 100%.
What is an example of energy efficiency?Utilizing less energy to deliver an energy service is referred to as energy efficiency. LED light bulbs, for instance, use between 75 and 80 percent less electricity to generate the same amount of light as incandescent bulbs.
According to efficiency formula we know
Efficiency = [tex]\frac{580}{380}[/tex] * 100 = 130%
But technically this is not possible as no engine has efficiency greater than Carnot engine i.e., 100%
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In the United States, most people measure temperature in ______.
Celsius
Kelvin
Fahrenheit
Answer: Fahrenheit
Explanation:
Convert 5 x 105 into normal notation.
50,000
500,000
.00005
5,000,000
Answer:
5 * 10^5 = 5E5 = 500,000
Consider a 0. 5-kg meter stick with a 1. 0 kg mass attached at the 50 cm mark and a 3. 0 kg mass at the very end. Where on the meter stick is the center of mass located?.
The center of mass of the three mass system is at 83cm.
What is center of mass?The center of mass of an object or a collection of objects is known. It represents the system's average location by weighing the mass of each component. For straightforward rigid structures with uniform densities, the center of mass is located at the centroid.
What is the calculation of the above problem?Given the mass of the meter stick is:
M = 0.5kg.
Since the meter stick is uniform, the center of mass of the meter stick is at 50cm or 0.5m.
Let the distance of the meter stick's center of mass from 0cm be x1. Then x1 = 0.5m.
Now a mass m2 = 1kg is attached at 50cm mark.
So the distance of m2 from 0cm is x2 = 50cm = 0.5m.
Similarly a mass m3 = 3kg is attached at the every end or 100cm mark. So the distance of m3 from 0cm is x3 = 100cm = 1m.
Now the position of the three mass system from 0cm is given by,
So the center of mass of the three mass system is at 83cm.
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A bird is flying 77.0 meters above the ground, holding a stick with its feet. If the bird were to drop the stick, how long would it take for the stick to reach the ground below?
A: 1.96s
B: 2.45s
C: 3.96s
D: 3.84s
The time taken for the stick that the bird dropped to reach the ground is 3.96 seconds.
What will be the time taken for the stick that the bird dropped to reach the ground?The time taken for the stick that the bird dropped to reach the ground is determined the using formula below:
h = ut + ¹/₂ * g * t²
where the given parameters are given below:
h = 77.0 meters
u = 0
t = ?
g = 9.81 m/s²
Solving for the time required:
77.0 = 0 * t + ¹/₂ * 9.81 * t²
t² = 77.0 * 2 / 9.81
t² = √15.7
t = 3.96 seconds
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you throw a rock straight up into the air with a speed of 11.5ms how long does it take to reach its highest point
The time taken for the rock to reach its highest point is 1.2 seconds.
What is time of motion?
The time of motion of an object is the time taken for the object to travel from its initial position to the final position.
The time taken for the rock to reach its maximum or highest point is calculated as follows;
v = u - gt
where;
v is the final velocity of the rock at the highest pointu is the initial velocity of the rockg is acceleration due to gravityt is time of motionAt the maximum height, the final velocity of the object is zero.
0 = u - gt
]gt = u
t = u/g
t = (11.5 m/s) / (9.8 m/s²)
t = 1.2 seconds
Thus, we can conclude that time from the initial position of the rock to the highest position of the rock is 1.2 seconds.
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A boy is running to the east and jumps into a stationary boat in a lake. once the boy lands in the boat, the boat moves to the east. which best compares the initial momentum of the boy with the final momentum of the boy/boat system? the initial momentum of the boy is zero because the velocity cancels with the mass of the boy. the initial momentum of the boy is greater than the boy/boat because the boy has a greater velocity than the boat. the initial momentum of the boy is less than the boy/boat because the boy has less mass than the boat. the initial momentum of the boy is equal to the boy/boat because the final velocity of the boat is less than the initial velocity of the boy.
Due to the boat's final velocity being lower than the kid's initial velocity, the boy's initial momentum is equal to that of the boy and the boat.
A moving object's velocity is gauged by its momentum. The momentum increases with velocity. The momentum of an item increases with its mass. Using Newton's second law of motion, it may also be connected to force. The sum of an object's mass and velocity is its linear momentum, often known as translational momentum or just momentum. It has a magnitude and a direction, making it a vector quantity. The measurement of an object's kinetic energy is what is commonly referred to as its momentum. Simply put, momentum is the result of multiplying mass by velocity.
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Answer: D
Explanation: precise, concise answer
Figure 2 shows a series circuit.
R₁1
Figure 2
R₂
Resistor R₂ breaks. What happens to the reading on the ammeter?
Answer:
sleep well
Explanation:
bukas nalbg yan pree
A wheel spins with constant angular acceleration on an axis through its center, the ratio of
the tangential speed of a point on the rim to the tangential speed of a point halfway between
the center and the rim is:
A. 1
B. 2
C.1/2
D. 4
The ratio of the tangential speed of a point on the rim to the tangential speed of a point halfway between the center and the rim is 2.
The correct option is B.
Briefing:The wheel's angular velocity The rate at which the angular displacement changes over time is known as the wheel's angular velocity. Because the angular velocity is constant, a point just on rim will have constant tangential velocity.
What does angular velocity?The angular velocity of a body refers to the pace at which it revolves or circumambulates an axle. Sometimes, the Greek letter omega symbolizes angular velocity. Due to the fact that it is expressed as an angle every unit of time, the angular velocity in the SI was measured in radians per second.
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What is the point on an object where the force of gravity is considered to act?
The Centre of gravity is the point on an object where the force of gravity is considered to act.
Every object that exists on the earth has weight and because of that weight, certain gravity acts on it. When we calculate the total weight of the object, mainly center is taken as the point where the whole weight of the object is accumulated.
for instance, in the seesaw, the middle portion of it acts as a center of gravity which balances out both sides.
It plays a very important role in calculating big and complex problems of gravitation. It simplifies calculations to treat the mass of an object as if it is concentrated at one point only. It is an imaginary point that stable the object.
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