Work done to lift the rock is 6174 Joule.
To find the answer, we need to know about the work done.
What's the work done?Mathematically, work done = force × distance
What's the gravitational force acts on the stone here?The gravitational force on the stone = mg
= 210× 9.8= 2058N
What's the work done to lift the stone?Work done= 2058× 3
= 6174 Joule
Thus, we can conclude that the work done to lift the stone is 6174 Joule.
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A 0.08m long spring is attached vertically to the ceiling. after 66kg mass is attached to the spring it has a length of 2.1m. determine the spring's force constant. use g=10
Answer:
The spring constant is 647.05 N/m.
Explanation:
The weight of the mass is W=mg
W=66*10
W=660
The spring force is given by the formula F=kx
where k is the spring force constant.
The spring force is equal to the weight of the mass. Therefore equate W and F.
kx= 660
k=660/x
Difference in length x=2.1-0.08= 1.02 m
k=660/1.02
k=647.05 N/m
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A light bulb receives 100 J of energy electrically. It transfers 30 J of energy to the surroundings by heat. What is the efficiency of the light bulb?
Answer:
The efficiency of the light bulb is 30%.
Explanation:
Efficiency = output/input × 100%
Data
Energy input = 100J
Energy output = 30J
Efficiency = ?
Efficiency = Energy output/Energy input × 100%
Efficiency = 30J/100J × 100%
Efficiency = 0.3 × 100%
Efficiency = 30%
Therefore the efficiency of the light bulb is 30%.
Along the frictionless path you have chosen in question 8, the main force(s) acting on the puck after receiving the kick is (are):
O a downward force of gravity.
a downward force of gravity, and a horizontal force in the direction of motion.
a downward force of gravity, an upward force exerted by the surface, and a horizontal force in the direction of motion.
a downward force of gravity and an upward force exerted by the surface.
none. (No forces act on the puck.)
The main force(s) acting on the puck after receiving the kick is a downward force of gravity, an upward force exerted by the surface, and a horizontal force in the direction of motion.
What is friction?Friction can be defined as that resistance that one surface or object encounters when moving over another.
So therefore, the main force(s) acting on the puck after receiving the kick is a downward force of gravity, an upward force exerted by the surface, and a horizontal force in the direction of motion
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Which is a valid prediction about the continuous function f(x)? f(x) ≤ 0 over the interval (–[infinity], [infinity]). f(x) > 0 over the interval (–1, [infinity]). f(x) ≥ 0 over the interval [–1, 1]. f(x) < 0 over the interval (0, 2).
The valid prediction is f(x) ≥ 0 over the interval [–1, 1]
The question seems to be incomplete the complete question is given in the image!!!!
A function from a set X to a set Y is an assignment of an element of Y to each element of X. The set X is called the domain of the function and the set Y is called the codomain of the function.
The given values for x = 3 , f(x) = -15 Here f (x) < 0
When x =0, f(x) = 5 Here f(x) > 0
So for f(x) ≤ 0 over the interval (–[infinity], [infinity]) is the wrong option
When x = 2 f(x)=-5 here f(x) < 0
So , f(x) > 0 over the interval (–1, [infinity]) is also a wrong option
When x = 1 f(x)=0 here f(x) > 0
So , f(x) < 0 over the interval (0, 2) is also a wrong option
When x = -1 f(x) = 0
When x = 0 f(x) = 5
When x = 1 f(x) =0
So , f(x) ≥ 0 over the interval [–1, 1] is the valid prediction
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a car travelling at 5m/s is brought to rest in a distance of 20m.Find it's decelaration and time taken.
Answer:
time taken= 8s
deceleration = -0.625ms^-2
Explanation:
s = 1/2(u+v)t (linear motion formula)
20 = 1/2 ( 5+0 ) t
t=time taken, find t
t= 8s
a= (v-u) / t
a= (0-5) / 8s
= -0.625 ms^-2
A substance that has 1500 liters and which has a density of 250 kg / m3 determine the mass of said substance
【Answer】Therefore, the mass in said substance is 375 kilograms.
[tex]\red{ {\hspace{50 pt}\above 1.2pt}\boldsymbol{\mathsf{Procedure}}{\hspace{50pt}\above 1.2pt}}[/tex]
This is an exercise on fluids and their fundamental characteristics.
We start to solve, obtaining the data:
DATA:v = 1500 lt = 1.5 m³d = 250kg/m³m = ?Conversion from liters to m³
[tex]\boldsymbol{1500\not{l}*\dfrac{1 \ m^{3} }{1000\not{l} }=1.5 \ m^{3} }[/tex]
To calculate mass: multiply density by volume.
[tex]\boldsymbol{m=d*v \ \ \to \ \ \ Formula}[/tex]
We clear our data in the formula:
[tex]\boldsymbol{m=250\dfrac{kg}{\not{m^{3}}}*1.5\not{m^{3}} }[/tex]
[tex]\boldsymbol{m=375 \ kg}[/tex]
{ Pisces04 }6 An infinite non-conducting sheet has a surface charge density o = 5.80pC/m². (a) How
much work is done.
by the
the electric field due to the sheet if a particle of charge
ue to
q+1.60x10-¹°C is moved from the sheet to a point P at distance d= 3.56cm from the
sheets. (b) If the electric potential V is defined to be zero on the sheet, what is V at P
a. Work done = 2. 0648 Joules
b. Electrical potential, V = 4. 03 × 10^10 volts
How to determine the parameters
a. Work done = force × distance
Force = density × acceleration due to gravity
Force = 5. 80 × 10
Force = 58 Newton
We have that distance = 3. 56cm = 0. 0356 m
Work done = 58 × 0. 0356
Work done = 2. 0648 Joules
b. The formula for electric potential is given thus,
Electric potential, V = [tex]k\frac{q}{r}[/tex]
r = 0. 0356m
k = Coulomb's constant = [tex]8.98*10^9[/tex]kg⋅m3⋅s−4⋅A−2.
q= 1.60x10^-¹C
substitute into the formula
Electric potential, V = [tex]8. 98[/tex] × [tex]10^9[/tex] × [tex]\frac{1. 6 * 10^-^-1}{0. 0356}[/tex]
Electric potential, V = [tex]8. 98 * 10^9[/tex] × [tex]4. 494[/tex]
Electric potential, V = [tex]4. 03 * 10^1^0[/tex] volts
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If oxygen, which has a electronegativity of 3.5, bonds with hydrogen, which has an electronegativity of 2.1, the bond between the two atoms will be classified as a polar____ bond
Given the electronegativity of O is 3.5 and H is 2.1, the bond between the two atoms will be classified as a polar covalent bond.
How are bonds classified?According to the difference in electronegativity (ΔEN).
If ΔEN ≤ 0.4, the bond is nonpolar covalent.If 0.4 < ΔEN ≤ 1.9, the bond is polar covalent.If ΔEN > 1.9, the bond is ionic.Oxygen has an electronegativity of 3.5 and hydrogen of 2.1. The difference in electronegativity is:
ΔEN = EN(O) - EN(H) = 3.5 - 2.1 = 1.4
Given the electronegativity of O is 3.5 and H is 2.1, the bond between the two atoms will be classified as a polar covalent bond.
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If the current through a resistor is tripled, how does the power dissipated by
the resistor change?
If the current that is circuit is tripled, the power is increased by a factor of 9. Option D
What is power?The term power refers to the rate of doing work. Now if we have to obtain the work done by the use of the formula; P = I^2R
Now if the current that is circuit is tripled, the power is now obtained by;
P = (3I)^2R = 9I^2R hence the power is increased by a factor of 9.
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1. A large ball was let go on a hill and started rolling down with a constant acceleration of 4.2 m/s². What was the velocity of the ball after 12 s?
Answer:
The velocity after 12s is 50.4m/s.
Explanation:
In acceleration formula make velocity the subject.
acceleration(a) = velocity(v)÷time(t)
velocity (v) = acceleration(a)×time(t)V = 4.2m/s²×12s
V = 50.4m/s
Therefore the velocity after 12s is 50.4m/s.
In an antique automobile, a 6-V battery supplies a total of 48 W to two identical headlights in parallel. The resistance of each bulb is:
Answer:
The resistance of the each bulb is 1.75 ohm.
Explanation:
The Power P supplied by the battery is given by the formula,
P=VI
where V is the voltage and I is the current.
Then the total current through given parallel circuit is I=P/V
Given P=48 W and V=6 V the value of I is
I=48 W/6 V
I= 8 A
Since both bulbs have same resistance and are connected in parallel so the current through each circuit will be half of the total current. Hence the current through each circuit I₀ is 4 A.
The Resistance R is calculated using formula R=V/I₀.
So the resistance is
R=6 V/4 A
R=1.75 ohm
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Answer:
The resistance of the bulb is 1.5 ohm.
Explanation:
The power P delivered to the whole circuit is given by the formula,
P=VI
Given P= 48 W and V= 6V, the current in the circuit is
I=P/V
I=48/6= 8 A.
Since the bulbs are identical and are in parallel, therefore the current through each parallel circuit is half of the total current. Therefore current I1 through each bulb is 4 A.
The resistance is given by the formula,
R=V/I1
Hence R=6/4 = 1.5 ohm
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A certain motor is capable of doing 5600 joules of work in 10 seconds. What is the power output of this motor?
Answer:
Power output of the motor is 560W.Explanation:
Power output = ?Work done = 5600JTime = 10sPower output = work done/timePower output = 5600J/10sPower output = 560WTherefore the Power output of the motor is 560W.Assume the first dot for animal A represents t = 0. At which time does animal B overtake animal A?
The time in which the animal B overtake animal A according to the motion map is at 2 seconds.
What is a Motion map?This is referred to as one-dimensional plots built off of a position line and depicts velocity and acceleration.
The time in which Animal B is ahead of animal A is at 2 seconds which therefore makes it the most appropriate choice.
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A wire is joined to points X and Y in the circuit diagram shown. A diagram of a circuit with a power source on the left. Directly above the power source is a dot labeled X and then a circle with an X in it. The circuit then splits with one path straight back to the power source and the other path has 3 circles with X in them labeled 2, 3, and 4 respectively. There is a point labeled Y between circles 2 and 3.A diagram of a circuit with a power source on the left. Directly above the power source is a dot labeled X and then a circle with an X in it. After the x are 4 different circles on the circuit with Xs in them labeled 1, 2, 3, and 4 respectively. There is a point labeled Y in between circles 2 and 3. There is a branch of the circuit from X to Y. How does the circuit change when the wire is added?
A closed circuit occurs and makes all bulbs turn off.
An open circuit occurs and makes all bulbs turn off.
A short circuit occurs and makes bulbs 3 and 4 turn off but keeps bulbs 1 and 2 lit.
A short circuit occurs and makes bulbs 1 and 2 turn off but keeps bulbs 3 and 4 lit.
The circuit change when the wire is added will see a short circuit occur and makes bulbs 1 and 2 turn off but keeps bulbs 3 and 4 lit. Option D. This is further explained below.
How does the circuit change when the wire is added?Generally, Electronic circuits consist of a series of interconnected parts that form a closed loop through which electricity may flow.
In conclusion, If two wires are linked together, a short circuit will develop, cutting power to bulbs 1 and 2. But there is no impact on bulbs 3 and 4. There is no problem with bulbs 3 and 4.
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If the distance between two charged particles is increased 2.69 times, the ratio of new to old electric force is _______ times the old value. (Round your answer to two decimal places).
Answer:
F = K Q1 Q2 / R^2 force between 2 charged partices
F2 / F1 = (R1 / R2)^2 = (1 / 2.69)^2 = .139
F2 = .139 F1
You took a second ball headed to a cliff. You dropped this ball straight down with a velocity of 9.3 m/s. The ball hit the ground exactly 8.0s after you released it. How high is the ciff?
Answer:
The cliff is 74.4m.
Explanation:
The reading above clearly state that a ball is dropped straight down with the speed of 9.3m/s and hit the ground exactly at a time of 8.0s after you released it. And it is asking for the distance of the cliff.
In speed formula make distance the subject.
Therefore Distance = speed × time
Distance = 9.3mls × 8.0s = 74.4m
Therefore the cliff is 74.4m.
Linear Velocity What is the linear velocity in cm>min for any edge point of a 12-cm-diameter CD (compact disc) spinning at 10,350 rev>min?
3,89,988 cm/min is the linear velocity
Given,
Diameter of CD = 12 cm
So, Radius of CD = 6 cm
CD is spinning at 10350 rev/min
Firstly , convert rev/min into rad/min
1 rev = 2π radians
10350 rev/min = 10350 × 2π
= 64998 rad/min
Formula used,
[tex]v=rw[/tex] where,
[tex]v[/tex] is the Linear velocity
[tex]r[/tex] is the radius
[tex]w[/tex] is the angular velocity
[tex]v[/tex] = 6 cm × 64998rad/min
= 3,89,988 cm/min
Thus, linear velocity for any edge point of a 12-cm-diameter CD (compact disc) spinning at 10,350 rev/min is 389988 cm/min.
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what provides the centiperal force to a satellite revolving around the earth?
Answer:
the gravitational force
Which equation represents the law of conservation of energy in a closed system? kei pei = kef pef pei pef = kei kef kei – kef = pei – pef kei – pef = pei – kef
In equation form, Or KE+PE=constant KEi+PEi=KEf+PEf where i and f denote initial and final values. This is known as the conservation of mechanical energy.
Κi + Ûg,i = kf + U,g,f
A closed system is a system where exists energy interactions with surroundings, but not mass interactions.
If we neglect any energy interactions from boundary work, heat, electricity, magnetism, and nuclear phenomena and assume that process occurs at a steady state and all effects from non-conservative forces can be neglected, then the equation of energy conservation is reduced to this form:
K + Ug = 0 (1)
Where:
K -Change in kinetic energy of the system, measured in joules.
Ug - Change in gravitational potential energy of the system, measured in joules.
If we know that K = Ki - Kf and Ug = Ug,i - Ug,f, then we get the following equation:
Ki + Ug,i = Kf + Ug,f, (2)
Where i and f stand for initial and final states of each energy component.
Hence, the right answer is Ki + Ug,i = Kf + Ug,f,.
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Answer:
A KEi + PEi = KEf + PEf
Explanation:
A 1000-kg car traveling at 70 m/s takes 3 m to stop under full braking. The same car under similar road conditions, traveling at 140 m/s, takes ______________ m to stop under full braking
A [tex]1000[/tex] kg car travelling with velocity [tex]70[/tex]m/s takes [tex]3[/tex] to stop under full braking. And the same car under similar road conditions travelling with velocity [tex]140m/s[/tex] takes [tex]12m[/tex] to stop under full braking.
How can we find Distance at velocity [tex]140m/s[/tex] ?
In case of [tex]70m/s[/tex] car stop under full braking after [tex]3m[/tex].
So we can find the acceleration by third equation of motion
[tex]v^2=u^2+2as[/tex]
Here [tex]v[/tex] is final velocity which is zero.
[tex]u[/tex] is initial velocity which is [tex]70m/s[/tex]
[tex]s[/tex] is displacement
So substitute the values in equation of motion
[tex]0=70^2+2*a*3\\-4900/6=a\\-816.6m/s^2=a[/tex]
In case of initial velocity [tex]140m/s[/tex] acceleration is same because same car and same road condition so acceleration is [tex]-816.6m/s^2[/tex]
We can find the distance by using the equation of motion
[tex]v^2=u^2+2as\\0=140^2+2*(-816.6)*s\\-19600/-1633.2=s\\12m=s[/tex]
Distance is [tex]12m[/tex]
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which process receives geo thermal energy naturally
A 43-kg child sits in a massless swing. With what horizontal force must the seat be pulled so that the ropes form an angle of 35o with respect to the vertical? Group of answer choices 300 N 320 N 340 N 360 N
The horizontal force that the seat must be pulled so that the ropes form an angle of 35o with respect to the vertical is 345.2 N.
Horizontal force to be appliedThe horizontal force that the seat must be pulled so that the ropes form an angle of 35o with respect to the vertical is calculated as;
F = Wcosθ
where;
W is weight of the childθ is angle of inclination of the ropeF = (43 x 9.8) x cos(35)
F = 345.2 N
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Gneiss and quartzite rocks are found in the metamorphic surface bedrock in which new york state landscape region ?
Answer: It's mostly found near Jamestown , New York
With a mass of 111.1 kg, is moving with a velocity of 3.000 m/s to the right. Mass is initially at rest and has a mass of 222.2 kg. After the elastic collision, bounces off with a velocity of 1.000 m/s to the left. Calculate the velocity of after the collision.
Let us assume the positive \hat{x} direction is towards the right.
During any collision, the total momentum is conserved.
That means, the total momentum before the collision is the same as the total momentum after the collision.
p before = P after
Given,
Mass 1, m_1 = 111.1kg
Mass 2, m_2 = 222.2kg
Initial Velocity of Mass 1, 1,1 3.00.î m/s
Initial Velocity of Mass 2, \overrightarrow v_{2,i} =0
Velocity of Mass 1 after collision, \overrightarrow v_{1,f} =-1.000\hat{x}\hspace{0.1cm}m/s
The total Momentum of the system before the collision is,
\overrightarrow p_{before} =m_1\overrightarrow v_{1,i} + m_2\overrightarrow v_{2,i}
=> \overrightarrow p_{before} =(111.1)(3.00\hat{x}) + 0
=> \overrightarrow p_{before} =333.3\hspace{0.1cm}\hat{x}\hspace{0.1cm}kgm/s
The total Momentum of the system after the collision is,
\overrightarrow p_{after} =m_1\overrightarrow v_{1,f} + m_2\overrightarrow v_{2,f}
=> \overrightarrow p_{after} =(111.1)(-1.000\hat{x}) + (222.2)\overrightarrow v_{2,f}
=> \overrightarrow p_{after} =(-111.1\hat{x}) + (222.2)\overrightarrow v_{2,f}
We know the total momentum before the collision is the same as the total momentum after the collision.
p before = P after
=>333.3\hat{x} =(-111.1\hat{x}) + (222.2)\overrightarrow v_{2,f}
=>(-111.1\hat{x}) + (222.2)\overrightarrow v_{2,f} = 333.3\hat{x}
=> (222.2)\overrightarrow v_{2,f} = 333.3\hat{x} + 111.1\hat{x}
=> (222.2)\overrightarrow v_{2,f} = 444.4\hat{x}
=> \overrightarrow v_{2,f} = \frac{444.4}{222.2}\hspace{0.1cm}\hat{x}\hspace{0.1cm}m/s
=> \overrightarrow v_{2,f} = 2.00\hspace{0.1cm}\hat{x}\hspace{0.1cm}m/s
Therefore the velocity of m_2 after collision is v_{2,f} = 2.00\hspace{0.1cm}m/s going to the right
Please check the attached file for a brief answer.
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g Three projectiles are launched from the same level on flat ground. Each reaches the same maximum height before returning to the ground, but projectile 3 (in blue) has the largest range, followed by projectile 2 (in green). Projectile 1 has the smallest range (in red). Rank the three from largest to smallest according to:
All objects fall at the same rate, what is the acceleration of the force of gravity?
Answer:
9.8 m/s
Explanation:
If these objects are in free fall, meaning that their downward movement is only due to the force of gravity, then acceleration due to gravity is about 9.8 metres per second per second.
Spiderman, whose mass is 80.0 kg, is dangling on the free end of a 12.0-m-long rope, the other end of which is fixed to a tree limb above. By repeatedly bending at the waist, he is able to get the rope in motion, eventually getting it to swing enough that he can reach a ledge when the rope makes a 60.08 angle with the vertical. How much work was done by the gravitational force on Spiderman in this maneuver
4.719kJ is the work done by the gravitational force.
Given,
Mass of Spiderman, m = 80 kg
Acceleration due to gravity, g = 9.8[tex]m/s^{2}[/tex]
Formula used
F= mg
So, The force on Spiderman is= 80 × 9.8 = 784N
As Spiderman is dangling on the free end of a long rope, the other end of which is fixed to a tree limb above.
That's why only his vertical movement makes a difference in how much work gravity does.
So, we only consider the y coordinates here
As the rope is 12m long ,
y coordinate below the tree limb is –12m. (negative sign because the value is present below the origin.)
As it is given that the rope makes a 60.08° angle with the vertical.
So his final y coordinate is (–12.0m)cos60.08°
= -12×0.498 = -5.98m
Change in elevation (ΔS)= –5.98m–(–12.0m)= 6.02m.
The work done by the gravity on Spiderman is:
W=FΔscosθ….. (1)
where, F = Force of gravity on Spiderman
ΔS = Change in the elevation
θ = angle between force and the displacement
Putting the values in equation (1)
W = 784 × 6.02 ×cos 180°
= 784 × 6.02 × -1 = 4719.68 J = 4.719kJ
Hence, the work was done by the gravitational force on Spiderman in this maneuver is 4.719 kJ.
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A type of electromagnetic radiation that has a higher frequency than visible light is Question 15 options: ultraviolet infrared radiowaves microwaves two of the above
Ultraviolet rays are Electromagnetic waves that have higher frequencies than visible light, so they carry more energy.
What are Ultraviolet rays?Johann Wilhelm Ritter, a German physicist, first noticed that paper soaked in silver chloride browned more quickly when exposed to Ultraviolet rays than when it was exposed to violet light itself in 1801.For the most part, humans cannot see ultraviolet rays. The cornea filters out shorter wavelengths, while the lens of the human eye primarily inhibits radiation in the 300–400 nm range. Additionally, UV color receptor adaptations are not present in humans. The retina's photoreceptors are sensitive to near-UV, though, and those without lenses (a condition known as aphakia) see near-UV as whitish-blue or whitish-violet.The body produces vitamin D, which is necessary for life when exposed to UV light, more especially UVB. UV rays are necessary for humans to maintain proper vitamin levels.To learn more about Electromagnetic waves refer to:
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. A microwave oven operates at 2.4GHz with an intensity inside the oven of 2500 W/m^2. What are the amplitudes of the oscillating electric and magnetic fields
Answer: A microwave oven operates at 2.4GHz with an intensity inside the oven of 2500 W/m^2. Then, the amplitudes of the oscillating electric and magnetic fields are, [tex]B_0=4.57*10^{-6} T and E_0=1.37*10^{3} V/m[/tex]
Explanation: To find the correct answer, we have to know more about the EM Waves.
What are EM waves?Electromagnetic waves can be defined as the waves, that can interact with the matter and are created as a result of vibrations of electric and magnetic fields.Maxwell theoretically predicted the existence of electromagnetic waves.A time varying magnetic field is a source of electric field.Similarly, an oscillating electric field gives rise to an oscillating magnetic field.The amplitudes of electric and magnetic fields can relate as,[tex]E_0=cB_0[/tex]
The expression for intensity of electromagnetic waves in terms of amplitude of magnetic field can be written as,[tex]I=\frac{1}{2u_0} cB_0^{2}[/tex]
How to solve the problem?From the above expression of intensity, we can find the expression for amplitude of magnetic field as,[tex]B_0=\sqrt{\frac{2u_0I}{c} }=\sqrt{\frac{2*4*3.14*10^{-7}*2500 }{3*10^{8} } } =4.57*10^{-6} T[/tex]
Thus, from the amplitude of magnetic field, we get, the amplitude of electric field as,[tex]E_0=cB_0=3*10^{8} *4.57*10^{-6} =1371 V/m[/tex]
Thus, from the above calculations, we get the amplitudes of the oscillating electric and magnetic fields are, [tex]B_0=4.57*10^{-6} T and E_0=1.37*10^{3} V/m[/tex]
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An object on Earth weighs 150 N. What is its mass?
Group of answer choices
15 g
150 kg
15 kg
150 g
Answer:
[tex] \tt \: mass \: = \frac{weight}{acceleration \: due \: to \: gravity} [/tex]
[tex] \longrightarrow \tt \: \frac{150}{10} [/tex]
[tex] \longrightarrow \boxed{ \tt{15 \: kg}}[/tex]
Our final answer is 15 kg .----------- HappY LearninG<3 ------------