Answer:
See below
Explanation:
Set up your pendulum
measure its length and time the period ( you could time 100 of them and divide the time result by 100 to get the period, T)
then use
T = 2 pi sqrt (L/g) T = period L = length g = gravity
A cart is being pulled slowed down by a hanging mass. What is the value of the change in its kinetic energy, ΔEk?
Positive
Zero
Negative
Due a decrease in the velocity of the cart, the change in kinetic energy is negative
What is kinetic energy?Kinetic energy is the energy of a body due to its motion.
The change in kinetic energy is positive if the mass of a body or the velocity of the body increases.The change in kinetic energy is negative if the mass of a body or the velocity of the body decreases.The change in kinetic energy is zero if the mass of a body or the velocity of the body remains constant.Since the cart is slowed down, its velocity decreases and the change in kinetic energy is negative.
In conclusion, the change in kinetic energy of a body is affected by the mass and velocity of the body.
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. An airplane is cruising at altitude 10km. The pressure outside the craft is 0.287 atm; within the passenger compartment, the pressure is 1.00 atm and the temperature is 20 degree C. A small leak occurs in one of the window seals in the passenger compartment. Model the air as an ideal fluid to estimate the speed of the air stream flowing through the leak
The model of the Air as in ideal fluid estimating the speed of air stream flowing through he leak is given as; V = 347m/s. See the calculation below.
What is a model?A model is a mathematical equation that is used to represent a real life problem.
What is the model for the problem above?
P₁ + (1/2) pv₁² + pgh₁ = p₂ + (1/2) pv₂² + pgh₂
Hence,
1 + 0 + 0 = 0.287 + (1/2) (1.2) v²
Therefore,
V = 347m/s
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A motor hoists a mass m = 60 kg crate at a constant velocity to a height of h = 5 m in 2 s. If the indicated power of the motor is 3.2 kW, determine the motor's efficiency.
What is inertia?by Walter Levin..
Inertia is directly proportional to mass.
What is Walter Lewin famous for?
Walter Hendrik Gustav Lewin (born January 29, 1936) is a Dutch astrophysicist and former professor of physics at the Massachusetts Institute of Technology.
Lewin earned his doctorate in nuclear physics in 1965 at the Delft University of Technology and was a member of MIT's physics faculty for 43 years beginning in 1966 until his retirement in 2009.
According to Walter Levin,
The concept of moment of inertia is demonstrated by rolling a series of cylinders down an inclined plane.
Inertia is the resistance of any physical object to a change in its velocity. This includes changes to the object's speed, or direction of motion. An aspect of this property is the tendency of objects to keep moving in a straight line at a constant speed when no forces act upon them.
By rolling a series of cylinders down on an inclined plane , he demonstrated that a cylinder have a smooth friction.
He compares the rolling cylinder by using hollow cylinder and a heavy cylinder , and finalize the result that a hollow cylinder moves slowly but the heavy cylinder move faster.
Hence , By doing this experiment he explained about the inertia that Inertia depend on the mass of the object. As the heavy the object it will take more time to travel or move.
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An ideal gas in an isentropic process has an initial pressure of 200 kPa and relative pressure is 3.482; the final pressure is now 320 kPa, find the relative pressure at this state. round to the nearest 3 decimal places
The relative pressure at this state is determined as 0.455.
Initial pressure of the ideal gasThe pressure of the ideal gas given rise to the relative pressure is calculated as follows;
R.P = P2/P1
P2 = P1(R.P)
P2 = 200 kPa x (3.482)
P2 = 696.4 kPa
New relative pressureR.P = (P3)/(P2)
R.P = (320)/(696.4)
R.P = 0.455
Thus, the relative pressure at this state is determined as 0.455.
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In an attempt to escape his island, Gilligan builds a raft and sets to sea. The wind shifts a great deal during the day, and he is blown along the following straight lines:
2.5 km 45° north of west; then
4.70 km 60° south of east; then
5.1 km straight east; then
7.2 km 55° south of west; and finally
2.8 km 5° north of east.
What is his final position relative to the island?
km
° south of east
The final position of Gilligan in kilometers and degrees south of east relative to the island is 9.07 km, 61.4° south of east.
What is a vector simple ?A vector is a quantity or phenomenon that has two independent properties: magnitude and direction.
The term also denotes the mathematical or geometrical representation of such a quantity.
According to the question,
Suppose, the direction east as i, direction west as -i, direction north as j and direction south as j.
Therefore,
1. : 2.5 km 45° north of west
[tex]= 2.5 cos45 (-i) + 2.5 cos45 (j)\\ = -1.77(i) + 1.77(j)[/tex]
2. : 4.7 km 60° south of east
[tex]= 4.7 cos60 (i) + 4.7 sin60 (-j) \\= 2.35(i) - 4.07(j)[/tex]
3. : 5.1 km straight east
[tex]=5.1(i)[/tex]
4 : 7.2 km 55° south of west
[tex]= 7.2 cos55 (-i) + 7.2 sin55 (-j)\\ = -4.13(i) - 5.9(j)[/tex]
5: 2.8 km 5° north of east
[tex]= 2.8 cos5 (i) + 2.8 sin5 (j)\\= 2.79(i) + 0.24(j)[/tex]
The sum of all the above yields,
[tex]R = 4.34(i) + 7.96(-j)[/tex]
The magnitude of the resultant is:
[tex]|R| =\sqrt{4.34^{2} + (-7.96)^{2} }= 9.07[/tex]
The angle that the resultant makes is as follows.
θ= [tex]tan^-^1(\frac{7.96}{4.34} )\\[/tex]
θ = 61.4°
Hence,
Final position relative to the island is 9.07 km, 61.4° south of east.
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Set local ground level to 700 ft, and record the inches of mercury.
What is the altimeter reading in inches of mercury (from the Kollsman window)?
The altimeter reading is 29.17 from the Kollsman window is 29.17 in Hg
How to determine the altimeter reading?The given parameters are:
Ground level = 700 ft i.e. the field elevationPressure altitude = 1450 ftThe pressure altitude is calculated as:
Altitude = (29.92 – Altimeter reading) * 1,000 + Ground level
Substitute the known values
1450 = (29.92 - Altimeter reading) * 1000 + 700
Subtract 700 from both sides
750 = (29.92 - Altimeter reading) * 1000
Divide through by 1000
0.75 = 29.92 - Altimeter reading
Evaluate the like terms
Altimeter reading = 29.17
Hence, the altimeter reading is 29.17 from the Kollsman window is 29.17 in Hg
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If the current in a wire increases from 5A to 10A, what happens to its magnetic field?
If the current in a wire increases from 5A to 10A, the magnetic field generated will also be doubled.
IntroductionHi ! I will help you to discuss about "magnetic field around a conducting wire". A conducting wire that carried electric current can generate amount of magnetic fields. In a standard winding condition, the increase number of electric current will be proportional to the increase number of the generated magnetic field. In other condition, the increase in distance (between center of field with a point) will be inversly proportional to the increase in the generated magnetic field. So, the magnetic field that generated around a current-carrying wire can be expressed in the following equation.
[tex] \boxed{\sf{\bold{B = \frac{\mu_0 \cdot I}{2\pi \cdot d}}}}[/tex]
With the following condition:
B = perceived magnetic field at a point (Wb/m² or T)[tex]\sf{\mu_0}[/tex] = vacuum permeability = [tex]\sf{4\pi \times 10^{-7} \: Wb/A.m}[/tex] I = electric current (A)d = distance of a point from the wire (m)Problem SolvingWe can assume that:
Only the increase in current affects the change in the value of the magnetic field.Other provisions such as the distance of the point from the conducting wire is considered the same.We know that :
[tex]\sf{I_1 : I_2}[/tex] = 5 : 10 = 1 : 2 >> the ratio between the current flowing in first and second sample.[tex]\sf{d_1 : d_2}[/tex] = 1 : 1What was asked ?
B = perceived magnetic field at a point = ... : ...Step by step :
[tex] \sf{B_1 : B_2} [/tex]
[tex] \sf{\frac{\cancel{\mu_0} \cdot I_1}{\cancel{2\pi} \cdot d_1} : \frac{\cancel{\mu_0} \cdot I_2}{\cancel{2\pi} \cdot d_2}} [/tex]
[tex] \sf{\frac{I_1}{d_1} : \frac{I_2}{d_2}} [/tex]
[tex] \sf{\frac{I_1}{\cancel d} : \frac{I_2}{\cancel d}} [/tex]
[tex] \sf{I_1 : I_2} [/tex]
[tex] \boxed{\sf{\bold{1 : 2}}} [/tex]
ConclusionFrom the above comparison, we can see that the ratio of the magnetic field at a point will be the same as the ratio of the current flowing through the conducting wire is 1 : 2. So, The magnetic field generated will also be doubled.
Karen Horney, a prominent neo-Freudian, believed that Freud's theory Select one: A. discounted the importance of dreams. B. disputed that women never experience a phallic stage of development. C. discounted strong unconscious, aggressive desires. D. showed a masculine bias.
Karen Horney, a prominent neo-Freudian, believed that Freud's theory showed a masculine bias (Option D).
What is Freud's theory?Freud's theory, also called the psychoanalytic theory, is a model used in physiology to understand human behavior.
Freud's theory is based on the assumption that human behaviors are mainly controlled by the libido (unconscious) of people.
In conclusion, Karen Horney believed that Freud's theory showed a masculine bias (Option D).
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A step-up transformer has a primary coil with 100 loops and a secondary coil with 1,500 loops. If the primary coil is supplied with a household current of 120 V and 15 A, (a) what voltage is produced in the secondary circuit? (b) What current flows in the secondary circuit?
(a) The voltage that is produced in the secondary circuit is 1,800 V.
(b) The current that flows in the secondary circuit is 1 A.
Voltage in the secondary coilNp/Ns = Vp/Vs
where;
Np is number of turns in primary coilNs is number of turns in secondary coilVp is voltage in primary coilVs is voltage in secondary coil100/1500 = 120/Vs
Vs = (120 x 1500)/100
Vs = 1,800 V
Current in the secondary coilIs/Ip = Vp/Vs
where;
Is is secondary currentIp is primary currentIs = (IpVp)/Vs
Is = (15 x 120)/1800
Is = 1 A
Thus, the voltage that is produced in the secondary circuit is 1,800 V.
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A vector A⃗ has a magnitude of 40.0 m and points in a direction 20.0∘ below the positive x axis. A second vector, B⃗, has a magnitude of 75.0 m and points in a direction 50.0 above the positive x axis. Sketch the vectors A⃗ , B⃗ , and C⃗ =A⃗ +B⃗, and using the component method of vector addition, find the magnitude of the vector C⃗ .
The magnitude of the vector C is 96.32m
How to solve for the magnitude of vector c
Ax = AcosθA
= 40 cOS 20
= 37.59
Ay = AsinθA
-40sin20
= -13.68
Bx = B cos θ B
= 75Cos50
= 48.21
By = BsinθB
= 75sin50
= 57.45
Cx = AX + Bx
= 37.59 + 48.21
= 85.8
Cy = Ay + By
= -13.65 + 57.45
= 43.77
The magnitude is solved by
|c| = [tex]\sqrt{Cx^{2}+Cy^{2} }[/tex]
= √85.8² + 43.77²
= 96.32m
The magnitude of the vector c is 96.32m
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You drive 7.50 km in a straight line in a direction 10° East of North.
(a) Find the distances you would have to drive straight East and then straight North to arrive at the same point. (This is equivalent to finding the components of the displacement along the East and North directions.)
km East
km North
(b) Show that you still arrive at the same point if the East and North legs are reversed in order.
a)The distance in the east direction and distance in the north direction will be 1.302 km and 7.386 km respectively.
b)Both the routes have the same distance.
What is displacement?Displacement is defined as the shortest distance between the two points.
Distance is the horizontal length covered by the body, while displacement is the shortest distance between the two points. Displacement is a vector quantity.
Given data;
Distance,d = 7.5 km
Angle,θ=10° E of N
From the triangle ABD and ABC it is obtained that;
AC = AB sinθ
AC=7.5 sin(10°)
AC=1.302 km
CB = 7.5 cos 10°
CB = 7.386 km
AC is the distance in the east direction = 1.302 km
CB is the distance in the north direction = 7.386 km
Both the routes have the same distance. Hence you still arrive at the same point if the East and North legs are reversed in order.
Hence the distance in the east direction and distance in the north direction will be 1.302 km and 7.386 km respectively.
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Using appropriate technology, you determine that Earth's magnetic field at your location has a magnitude of 5.88 10-5 T and is directed north at an angle of 56° below the horizontal. You charge a metallic projectile and fire it north with a speed of 663 m/s and at an angle of 14° above the horizontal. Determine the sign (+ or −) and charge of the projectile, if the magnetic force on the projectile is 3.22 10-10 N, directed due west.
C
The sign (+ or −) and charge of the projectile, if the magnetic force on the projectile is 3.22 10-10 N, directed due west is mathematically given as
q=+1.11524613*10^{−4}C
What is the sign (+ or −) and charge?Generally, the equation for Force is mathematically given as
[tex]F=Bqvsin\theta[/tex]
Therefore
[tex]3.22 10^{-10}= 5.88 10^{-5 } *633*sin 56*q\\\\q=\frac{3.22 10^{-10}}{5.88 10^{-5 } *633*sin 56}[/tex]
q=+1.11524613*10^{−4}C
In conclusion, the sign (+ or −) and charge
q=+1.11524613*10^{−4}C
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Why was the APA not implemented early on for research on humans and these ethics of research in place?
APA not implemented early on for research on humans and these ethics of research in place because there was no stable and widely accepted system of research.
What is APA?
This is referred to a writing style used by American Psychological Association in reasearches etc.
There was no stable method of writing which was the reason why it wasn't used early for researches.
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Find the center of mass of a one-meter long rod, made of 50 cm of iron (density 8gcm3) and 50 cm of aluminum (density 2.7gcm3).
The center of the mass of a one-meter long rod, made of 50 cm of iron (density 8gcm3) and 50 cm of aluminum (density 2.7gcm3) is 37.62(cm)
Calculations and Parametersλ Fe =8g/cm,λ Al =2.7g/cm
There is a metal rod 1 meter long, with the first 50cm being iron and the other 50cm aluminum. the problem is solved in a one-dimensional case meaning it's a thin rod.
Next, we would solve by definition of the center of mass
We would also note that the masses of iron and aluminum are just the product of their length and linear density.
[tex]X_C_M[/tex]= [tex]\frac{8(g/cm). \frac{2500(cm^2)}{2} + 2.7 (g/cm). \frac{7500(cm^2)}{2} }{8(g/cm).50(cm) + 2.7(g/cm). 50 (cm)}[/tex]
= 37.62(cm)
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A truck is carrying a refrigerator as shown in the figure. The height of the refrigerator is 158.0 cm, the width is 60.0 cm. The center of gravity of the refrigerator is 67.0 cm above the midpoint of the base.
What is the maximum acceleration the truck can have so that the refrigerator doesn't tip over? (The static friction between the truck and the refrigerator is very large.)
The maximum acceleration the truck can have so that the refrigerator does not tip over is 4.15 m/s².
What will be the maximum acceleration of the truck to avoid tipping over?The maximum acceleration is obtained by taking clockwise moments about the tipping point of rotation.
Clockwise moment = Anticlockwise moment
Ft * 1.58 m = F * 0.67 m
where
Ft is tipping force = mass * acceleration, aF is weight = mass * acceleration due to gravity, gm * a * 1.58 = m * 9.81 * 0.67
a = 4.15 m/s²
The maximum acceleration the truck can have so that the refrigerator does not tip over is 4.15 m/s².
In conclusion, the acceleration of the truck is found by taking moments about the tipping point.
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anyone solve this for mw urgently please.
Decrease.
What is the weight on the equator than at the Poles?Yes, You weigh less on the equator than at the North or South Pole, but the difference is small.
Note that your body itself does not change.
Rather it is the force of gravity and other forces that change as you approach the poles. These forces change right back when you return to your original latitude.
In short, a trip to the equator is not a viable long-term weight-loss program.
Your weight is the combination of all the large-scale, long-term forces on your body. While the earth's gravity is by far the strongest large-scale force, it is not the only one.
We experience as "something pulling you down" is actually the total of all the forces and not just gravity.
The four dominant large-scale, long-term forces are:
The earth's gravity
The sun's gravity
The moon's gravity
The earth's centrifugal force
Hence, the weight of a body at the equator will be less than at the Poles.
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Neil Armstrong dropped a hammer on the moon. If it took 4 seconds to fall and the final speed was 8 m/s, what is the acceleration due to gravity on the moon?
Answer:
2
Explanation:
8-0/4
Final velocity-initial velocity/time taken
A javelin is thrown at 28.5 m/s from flat
ground at a 43.2° angle. How much time
is it in the air?
(Unit = s)
HELP FAST
Answer:
did you ever the answer?
Explanation:
The time for the javelin in the air will be 3.977 second
What is the period?The value of time needed to complete the upward and the downward motion is the total period. Its unit is the second and is denoted by t. T is the time at which the ball first hits the ground.
Given data;
Θ is the angle of throw = 43.2°
u is the thrown velocity = 28.5 m/s
t is the time for the javelin in the air
The time period is found as;
[tex]\rm t = \frac{2u sin \theta }{g} \\\\ t = \frac{ 2 \times 28.5 \ sin 430.2^0}{9.81 } \\\\ t = 3.977 \ sec.[/tex]
Hence the time for the javelin in the air will be 3.977 second
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A vector of magnitube 5 units is inclined at an angle 37° to the x-axis and another vector of magnitube 10 units is inclined at 53° to the x-axis. What is the magnitude of the sumbof the vector components ( i ) along the x-axis ( ii ) along the y-axis? ( sin 37° = cos 53° = 0.6 / sin 53 = cos 37° = 0.8 )
Answer:
See below
Explanation:
x axis components
5 cos 37 + 10 cos 53 = 5(.8) + 10(.6) = 1.0 units x-axis
y axis components
5 sin 37 + 10 sin 53 = 5(.6) + 10 (.8) = 1.1 units y- axis
The correct answer for the magnitude of the sum of vector is (i) along x-axis is [tex](\sqrt{10})^2[/tex] and (ii) along y-axis is [tex](\sqrt{11})^2[/tex] .
Given:
Vector A magnitude: 5 units,
angle of inclination with x-axis = 37°.
Vector B magnitude: 10 units.
angle of inclination with x-axis = 53°.
Sum of vectors along x-axis:
AB = [tex]\sqrt{5cos37^o +10cos53^o }[/tex]
= [tex]\sqrt{(5*(0.8))^2+(10*(0.6))^2}[/tex]
[tex]= (\sqrt{10})^2[/tex]
Along y-axis:
AB =[tex]\sqrt{5sin37^o +10cos53^o }[/tex]
[tex]\sqrt{5(0.6) +10(0.8) }\\\\= (\sqrt{11})^2[/tex]
Magnitude along x-axis and along y-axis is [tex]10[/tex] and [tex]11[/tex] respectively.
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A man walks from point A to B at an average speed of 1.0 m/s and immediately returns at anaverage speed of 1.5 ms -1 .What is the average speed for the round trip?
The average speed of the round trip is 1.25 m/s.
What is the average speed of the journey?The average speed of the round trip journey is obtained by taking the average of the forward and return speed of the journey.
Average speed = initial speed + final speed/2Average speed = 1.0 + 1.5/2 = 1.25 m/s
In conclusion, the average speed of the round trip is the average of the initial and final speeds.
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What’s the correct answer answer asap for brainlist
Answer:
animals and wildlife (c)
Explanation:
Ecotourism is essentially tourism of nature--which highly incorporates animals/wildlife
> it usually has a goal of conservation of nature
poaching is illegally hunting wild animals, which is focused on an aspect of nature protection (which is why it is ecotourism)
the only option listed here that is about ecotourism is animals and wildlife (c), meaning that this is the correct fill-in
hope this helps! have a lovely day :)
PLEASEEE HELP HELP PLEASE
A 0.450 kg baseball comes off a bat and goes straight up. At a height of 10.0 m, the baseball has a speed of 24.5m/s. Determine its mechanical energy at this height. Show your work
What is the baseball's mechanical energy when it is at a height of 9.0m? Explain your answer.
The mechanical energy of the baseball when it is at a height of 9.0m is 39.7 N.
What is the mechanical energy of the baseball bat?The mechanical energy of the bat is in the form of potential energy.
Potential energy = mass * acceleration due to gravity * heightAt a height of 9.0m, the potential energy of the ball = 0.45 * 9.81 *
Potential energy = 39.7 N
In conclusion, the mechanical energy of the baseball bat is the potential energy at that height.
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1. Calculate the magnitude of the gravitational force between the Earth and an m = 5.50 kg mass on the surface of the Earth. The distance to the center of the Earth from the surface is 6.37×103 km and the mass of the Earth is 5.98×1024 kg.
2. Calculate the magnitude of the gravitational force between the Moon and an m = 5.50 kg mass on the surface of the Earth nearest to the moon. The distance to the center of the Moon from the surface of the Earth is 3.76×105 km and the mass of the Moon is 7.36×1022 kg.
3. Calculate the ratio of the magnitude of the gravitational force between an m = 5.50 kg mass on the surface of the Earth due to the Sun to that due to the Moon. The mass of the Sun is 1.99×1030 kg and the distance from the center of the Sun to the surface of the Earth is 1.50×108 km.
1. The magnitude of the gravitational force between the Earth and an m is 54.1 N.
2. The magnitude of the gravitational force between the Moon and an m is 1.91 x 10⁻⁴ N.
3. The ratio of the magnitude of the gravitational force between an m on the surface of the Earth due to the Sun to that due to the Moon is 169.6.
Gravitational force between Earth and mass, m
The gravitational force between Earth and mass, m is calculated as follows;
F(Earth) = Gm₁m₂/R²
F(Earth) = (6.67 x 10⁻¹¹ x 5.5 x 5.98 x 10²⁴)/(6,370,000)²
F(Earth) = 54.1 N
Gravitational force between Moon and mass, mF(moon) = Gm₁m₂/R²
F(moon) = (6.67 x 10⁻¹¹ x 5.5 x 7.36x 10²²)/(3.76 x 10⁸)²
F(moon) = 1.91 x 10⁻⁴ N
Gravitational force between Sun and mass, mF(sun) = Gm₁m₂/R²
F(sun) = (6.67 x 10⁻¹¹ x 5.5 x 1.99x 10³⁰)/(1.5 x 10¹¹)²
F(sun) = 0.0324 N
Ratio of F(sun) to F(moon)= 0.0324/1.91 x 10⁻⁴
= 169.6
Thus, the magnitude of the gravitational force between the Earth and an m is 54.1 N.
The magnitude of the gravitational force between the Moon and an m is 1.91 x 10⁻⁴ N.
The ratio of the magnitude of the gravitational force between an m on the surface of the Earth due to the Sun to that due to the Moon is 169.6.
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The atomic mass of nitrogen is 14.01, hydrogen is 1.01, sulfur is 32.07, and oxygen is 16.00. What is the molar mass of ammonium sulphate [(NH4)2SO4]?
A.
63.09 g
B.
84.17 g
C.
114.12 g
D.
118.16 g
E.
132.17 g
Reset Next
The molar mass of ammonium sulphate [(NH4)2SO4] is 132.17 g (option E). Details about molar mass can be found below.
How to calculate molar mass?The molar mass of a substance can be calculated by adding the atomic masses of the elements in the compound.
According to this question, the atomic mass of nitrogen is given as 14.01, hydrogen is 1.01, sulfur is 32.07, and oxygen is 16.00.
The molar mass of ammonium sulphate is as follows:
[(NH4)2SO4] = [14.01 + 1(4)]2 + 32.07 + 16.00(4)
= 36.02 + 32.07 + 64
= 132.09
Therefore, the molar mass of ammonium sulphate [(NH4)2SO4] is 132.17 g.
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So, RCF, or relative centrifugal force should be equal to RCF = [tex]11,18*r*(RPM/1000)^2[/tex]
The radius is measured in centimeters and RPM is revolutions per minute.
What I don't know is, if I plug all the data in the formula, will the result equal to acceleration in meters per second squared, or it will be measured in g's so that if I multiply the g's by 9.8 meters per second square, it will give me the actual acceleration.
After plugging all the data into the equation, the result of the relative centrifugal force (RCF) is measured in terms of g.
What is relative centrifugal force?The relative centrifugal force (RCF) or the g force is the radial force generated by the spinning rotor as expressed relative to the earth's gravitational force.
RCF = ac/g
where;
ac is centripetal accelerationg is acceleration due to gravity[tex]RCF = \frac{\omega ^2 r}{g} = 1.118\times 10^{-5} \ (RPM)^2 r = 11.18r\ (RPM/1000)^2[/tex]
where;
r is radius in cmFor example,Find the maximum RCF of the JS-4.2 rotor can be obtained from its maximum speed (4200 rpm) and its rmax (250 mm);
[tex]RCF = 11.18 \times 25\ cm \times (\frac{4200 \ RPM}{1000} )^2 = 4,930.3 \times g[/tex]
Thus, after plugging all the data into the equation, the result is measured in terms of g.
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A soccer ball is kicked from the top of one building with a height of H1 = 30.2 m to another building with a height of H2 = 12.0 m.
The ball is kicked with a speed of v0 = 15.10 m/s at an angle of θ = 74.1° with respect to the horizontal. The mass of a size 5 soccer ball is m = 450 g. When the ball lands on the other building, its speed is 19.89 m/s.
1. How much energy was lost to air friction? The ball is kicked without a spin.
Hi there!
Initially, we have gravitational potential energy and kinetic energy. If we set the zero-line at H2 (12.0m), then the ball at the second building only has kinetic energy.
We also know there was work done on the ball by air resistance that decreased the ball's total energy.
Let's do a summation using the equations:
[tex]KE = \frac{1}{2}mv^2 \\\\PE = mgh[/tex]
Our initial energy consists of both kinetic and potential energy (relative to the final height of the ball)
[tex]E_i = \frac{1}{2}mv_i^2 + mg(H_1 - H_2)[/tex]
Our final energy, since we set the zero-line to be at H2, is just kinetic energy.
[tex]E_f = \frac{1}{2}mv_f^2[/tex]
And:
[tex]W_A = E_i - E_f[/tex]
The work done by air resistance is equal to the difference between the initial energy and the final energy of the soccer ball.
Therefore:
[tex]W_A = \frac{1}{2}mv_i^2 + mg(H_1 - H_2) - \frac{1}{2}mv_f^2[/tex]
Solving for the work done by air resistance:
[tex]W_A = \frac{1}{2}(.450)(15.1^2)+ (.450)(9.8)(30.2 - 12) - \frac{1}{2}(.450)(19.89^2)[/tex]
[tex]W_A = \boxed{42.552 J}[/tex]
An astronaut is on the moon. He drops a hammer from a height of 3.2metres and it takes 2.0 seconds to reach the lunar landscape. What is the acceleration due to gravity of the moon?
Answer:
1/6 m/s^2 ( about 1/6th gravity of Earth ( 9.81 m/s^2)
Explanation:
Displacement = yo + vo t - 1/2 a t^2
- 3.2 = 0 + 0 - 1/2 a(2.0)^2
- 3.2 = -2a
a = 3.2 / 2 = 1.6 m/s^2
An astronaut is on the moon. He drops a hammer from a height of 3.2metres and it takes 2.0 seconds to reach the lunar landscape. Then the acceleration due to gravity of the moon is 1.6 m/s².
What is gravity ?Gravity, which derives from the Latin word gravitas, which means "weight", is a basic interaction in physics that causes all objects with mass or energy to attract one another. The electromagnetic force, the weak interaction, and the strong interaction are all significantly stronger than gravity, which is by far the weakest of the four fundamental interactions. As a result, it has no appreciable impact on subatomic particle level phenomena. However, at the macroscopic level, gravity is the most important interaction between objects and governs the motion of planets, stars, galaxies, and even light.
Sublunar tides in the oceans are created by the Moon's gravity, much as gravity on Earth imparts weight to physical things (the analogous antipodal tide is generated by inertia).
according to kinematics,
S = ut + 1/2 at²
initial velocity is zero
S = 1/2 at²
putting all the values,
3.2 = 1/2a2²
6.4/4 = a
a = 1.6 m/s²
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Elizabeth’s father is a crane operator, and she gets a chance to see him at work. He shows her a button in the crane, explaining that pushing it closes a circuit. When that happens, a car is attracted to the crane and lifted off the ground. When the button is released, the car falls back to the ground. How does the current made by the circuit produce this effect?
A: It generates force that pulls the car toward the crane lift.
B: It generates an electric field from the crane lift that affects the electricle charges in the car.
C: it generates a magnetic field that attracts the car magnetically to the crane lift
Choose ONE
The current made by the circuit produce this effect by generating a magnetic field that attracts the car magnetically to the crane lift and is denoted as option C.
What is a Crane?This is a machine which is used to lift and lower objects which are most times heavy.
It employs the use of magnetic force as it is generated when the button is switched on in this scenario.
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After washing lettuce, you can dry the water from it using a salad spinner. You put the lettuce in the bowl, and then crank the handle, spinning and drying the lettuce.
From the frame of reference of the lettuce in the spinning strainer, what causes the water on the lettuce to come off the lettuce and go to the walls of the bowl?
The centripetal force
The force of gravity
Newton's first law of motion
The centrifugal force
Centripetal force causes the water on the lettuce to come off the lettuce and go to the walls of the bowl.
What is centripetal force?Centripetal force is the force that is necessary to keep an object moving in a curved path and that is directed inward toward the center of rotation. This force can move the body in the circular direction.
So we can conclude that Centripetal force causes the water on the lettuce to come off the lettuce and go to the walls of the bowl.
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The force that causes the water on the lettuce to come off the lettuce and go to the walls of the bowl is the centrifugal force.
What is the centrifugal force?The centrifugal force is the force that force that tends to throw an object out of the circular path. It is the opposite of the centripetal force which tends to keep the object in the circular path.
Hence. the force that causes the water on the lettuce to come off the lettuce and go to the walls of the bowl is the centrifugal force.
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