Help how can I solve This

Answer: Bottom Left

Step-by-step explanation:

Answer:

bottom left

Step-by-step explanation:

cuz it makes sense

Answer:

d(c(3))=30I5

Step-by-step explanation:

C(3)=5×9+3 +7=55

d(c(3))= ( 55)^2-10= 3O 15

Answer: You need to divide the numbers.

Step-by-step explanation:

Answer:

The answer is X=3

Step-by-step explanation:

2/5x=6/5

x=6/5*5/2=3

So your answer is 3

Hope this helps

also can I plz have brainliest :)

Answer:

brainlest?

Step-by-step explanation:

......

Answer: I looked it up and got a couple of answers of spatial reasoning. Don’t know if that helps but yeah thats what I got lol

Step-by-step explanation:

Answer:

I don't know exactly what you need but I have two ways.

Step-by-step explanation:

if you need to make an example: 6x55+ 6(3f-12)= or something along those lines.

or if you just need that answer then 330

I'm sorry if that's not what you were wondering

Answer:

I think that it is

C

Please let me know if it is not correct!!!!

Answer:

A would most likly be the answer

Step-by-step explanation:

because in the equation sinse A =  -5 1/4 which is whe he was at the end hopefully you understand

7 visits

Step-by-step explanation:

All I did was minus 16 from 37 to get 21, then divided that by 3.

Answer: For This Specific Question it is B, But there is a question very similar that doesn't have the pi's in the equation and the answer to that one is A.

Step-by-step explanation: Very sorry if this is confusing :)

Pythagorean identities are three basic identities for trigonometric ratios. The equation that is of the form [tex]\sin^2(\pi) + \cos^2(\pi) =1[/tex] is given by: Option B: [tex]0^2 + (-1)^2 = 1[/tex]

Equations which shows that the Pythagorean identities are true will be verifying them for some specific angles. For that we need to know about Pythagorean identities.

[tex]sin^2(\theta) + cos^2(\theta) = 1\\\\1 + tan^2(\theta) = sec^2(\theta)\\\\1 + cot^2(\theta) = csc^2(\theta)[/tex]

Using the first Pythagorean Identity to get one of its special case

For angle being [tex]\pi[/tex] radians(or equal to 180 degrees), we have:

[tex]sin(\pi) = 0\\cos(\pi) = -1[/tex]

Thus, for the first Pythagorean identity at angle [tex]\pi[/tex] radians, we get:

[tex]sin^2(\pi) + cos^2(\pi) = 1\\\\0^2 + (-1)^2 = 1[/tex]

Thus, the equation that is of the form [tex]\sin^2(\pi) + \cos^2(\pi) =1[/tex] is given by: Option B: [tex]0^2 + (-1)^2 = 1[/tex]

Learn more about Pythagorean identities here:

https://brainly.com/question/24287773

Answer:

200

Step-by-step explanation:

Find 60 kilos then just follow the line up till you reach the blue line  

Answer:

12.75 Its correct

Step-by-step explanation:

Answer:

12.75

Step-by-step explanation:

Answer:

556

Step-by-step explanation:

formula

L = a + (n - 1)*d

Givens

n = 70

a = 4

d = 8

Solution

t = 4 + (70 - 1)*8

t = 4 + 69*8

t = 4 + 552

t = 556

Answer:

500

Step-by-step explanation:

you welcome!! can  have brainliest?

Answer:

500

Step-by-step explanation:

9514 1404 393

Answer:

  a) no

  b) yes

Step-by-step explanation:

a) You cannot draw the graph around x=0 without lifting your pencil. The function is not continuous at x=0.

__

b) You can draw the graph around x=1 without lifting your pencil. The function is continuous at x=1.

_____

Additional comment

In technical terms, the limit from the left at x=0 is 2; the limit from the right is 3. These are different, so the function is not continuous there.

On the other hand, the left and right limits at x=1 are the same (both 2), and are equal to the value of the function at that point (f(1)=2). Hence, the function is continuous at x=1.

Answer:

Step-by-step explanation:

AC ≅ AD ; BC≅ BD                      Given

AB ≅ AB                                        Reflexive property of congruence

ΔACB ≅ ΔADB                              Side Side Side Postulate

Answer:

e. 79/30     f.   18.2

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

===============================================

Work Shown:

f(x) = |x+1|

f(-5) = |-5+1| .... x is replaced with -5

f(-5) = |-4|

f(-5) = 4

Answer:

28%

Step-by-step explanation:

hope this helps, have a good day

Answer:

c - 8 ≥ 25

Step-by-step explanation:

Answer and Step-by-step explanation:

Answer:

length is 7cm, and the width is 4cm

Step-by-step explanation:

The length of a picture frame is 1cm less than twice the width(frame is NOT a square). The area is 28cm^2. Find the length and width of the picture frame.

The area of the frame = Length * Width

A = LW

If the length of a picture frame is 1cm less than twice the width, then;

L = 2W - 1

Substitute into the formula;

A = (2W-1)W

A = 2W^2 - W

28 = 2W^2 - W

2W^2 - W - 28 = 0

2W^2 - 8W +7W- 28 = 0

2W(W-4)+7(W-4) = 0

2W+7 = 0 and W - 4 = 0

W =- -7/2 and W = 4

Width cannot be negative

W = 4cm

Since A = LW

L = A/W

L = 28/4

L = 7cm

Hence the length is 7cm, and the width is 4cm

Answer:

As the x=-2 does not satisfy the inequality.

Therefore, the solution is False!

Step-by-step explanation:

Given the expression

[tex]x-10x+1<\:20+\:5x\:[/tex]

substituting the value x = -2

[tex]\left(-2\right)-10\left(-2\right)+1<20+5\left(-2\right)[/tex]

[tex]-2+20+1 < 20-10[/tex]

[tex]19 < 10[/tex]

As the x=-2 does not satisfy the inequality.

Therefore, the solution is False!

It is E

Duhhhhhhhhhhhhh

Answer:

y-intercept: -5

Slope: 4

Equation: y = 4x - 5

Step-by-step explanation:

✔️The y-intercept is the value of y when x = 0. From the table of values, it shows that when x = 0, y = -5. Therefore:

y-intercept (b) = -5

✔️using two pairs from the table, (1, -1) and (2, 3):

[tex] Slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{3 -(-1)}{2 - 1} = \frac{4}{1} = 4 [/tex]

Slope = 4

✔️To write an equation for the function, substitute m = 4, and b = -5 into y = mx + b.

Thus:

y = 4x +(-5)

y = 4x - 5

Answer:

I would say, 2.5

Step-by-step explanation:

Because the calculator said 2.67

Answer:

C

Step-by-step explanation:

Answer

it is: C

Step-by-step explanation:

Answer:

Solving the radical [tex]4\sqrt{2}(-4\sqrt{15}+3\sqrt{18})[/tex] we get [tex]\mathbf{-16\sqrt{30}+72}[/tex]

Step-by-step explanation:

We need to simplify the radical: [tex]4\sqrt{2}(-4\sqrt{15}+3\sqrt{18})[/tex]

Prime factors of 18 are: 2x3x3

Replacing [tex]\sqrt{18}[/tex] with its factors

[tex]4\sqrt{2}(-4\sqrt{15}+3\sqrt{18})\\=4\sqrt{2}(-4\sqrt{15}+3\sqrt{2\times3\times3})\\=4\sqrt{2}(-4\sqrt{15}+3\sqrt{2\times3^2})[/tex]

We know that [tex]\sqrt{3^2}=3[/tex]

[tex]=4\sqrt{2}(-4\sqrt{15}+3\times3\sqrt{2})\\=4\sqrt{2}(-4\sqrt{15}+9\sqrt{2})[/tex]

Multiplying [tex]4\sqrt{2}[/tex] with terms inside the bracket

[tex]=4\sqrt{2}(-4\sqrt{15})+4\sqrt{2}( 9\sqrt{2}))\\=-16\sqrt{2}\sqrt{15}+36\sqrt{2} \sqrt{2}[/tex]

We know that [tex]\sqrt{2} \sqrt{2}=2[/tex]

[tex]=-16\sqrt{2*15}+36(2)\\=-16\sqrt{30}+72[/tex]

So, solving the radical [tex]4\sqrt{2}(-4\sqrt{15}+3\sqrt{18})[/tex] we get [tex]\mathbf{-16\sqrt{30}+72}[/tex]