Guanine pairs with cytosine using ______ noncovalent hydrogen bonds, while adenine pairs with thymidine using ______ noncovalent hydrogen bonds. Multiple choice question. two; two

Answer:

3.78 L

Explanation:

The Charles' Law equation looks like this:

V₁ / T₁ = V₂ / T₂

In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. You can find the final volume by plugging the give values into the equation and simplifying.

V₁ = 0.30 L                    V₂ = ? L

T₁ = 25 °C                      T₂ = 315 °C

V₁ / T₁ = V₂ / T₂                                          <----- Charles' Law equation

(0.30 L) / (25 °C) = V₂ / (315 °C)                <------ Insert values

0.012 = V₂ / (315 °C)                                  <----- Divide 25 from 0.30

3.78 = V₂                                                   <----- Multiply both sides by 315

Answer:

B.) Experimental

Explanation:

in an experimental investigation you have control over different variables you are testing so that makes this the most accurate answer.

The kind of investigation that allows for the control of variables is an experimental investigation.

In an experimental investigation, researchers manipulate or control certain variables while keeping others constant. This allows them to determine the cause-and-effect relationship between variables.

To conduct an experimental investigation, researchers typically follow these steps:

1. Formulate a hypothesis: A hypothesis is a testable statement that predicts the relationship between variables. It provides the basis for the experiment.

2. Identify variables: Variables are the factors or conditions that can be manipulated or measured in an experiment. In an experimental investigation, researchers typically have an independent variable and a dependent variable .

3. Control variables: In order to isolate the effect of the independent variable on the dependent variable, researchers need to control or keep constant other variables that could potentially influence the results. This ensures that any changes observed in the dependent variable can be attributed to the independent variable.

4. Design the experiment: Researchers design an experiment that allows them to manipulate the independent variable and measure the dependent variable. They may use control groups, randomization, and other techniques to minimize bias and ensure reliable results.

5. Collect and analyze data: Researchers collect data by conducting the experiment and measuring the dependent variable. They then analyze the data using statistical techniques to determine if there is a significant difference between groups or conditions.

By controlling variables in an experimental investigation, researchers can draw valid conclusions about the relationship between the independent and dependent variables. Thus, the correct answer is experimental investigations.

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Assuming the density of your initial acid solution is 1.0 g/mL.  the concentration (in molarity)  is mathematically given as

M= 0.75 M

Generally, the equation for Molarity  is  mathematically given as

M= (W/MW) ×1000

Therefore

[tex]M= (\frac{4.5} {60.05} \frac{(1000}{ 100}[/tex]

M = 0.75 M

In conclusion, The initial molarity  is given by

M= 0.75 M

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Answer:

45.8 mL

Explanation:

If all variables are held constant, the new volume can be found using the Boyle's Law equation. The equation looks like this:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new volume by plugging the given values into the equation and simplifying.

P₁ = 3.1 atm                        P₂ = 10.5 atm

V₁ = 155 mL                       V₂ = ? mL

P₁V₁ = P₂V₂                                                 <----- Boyle's Law equation

(3.1 atm)(155 mL) = (10.5 atm)V₂                <----- Insert values

480.5 = (10.5 atm)V₂                                  <----- Multiply 3.1 and 155

45.8 = V₂                                                    <----- Divide both sides by 10.5

What is the specific heat of aluminum?

The specific heat of aluminum is 0.90J/g°C.

Given:

Heat absorbs = 677 J

Mass of the substance = 10 g

Initial temperature = 50°C

Final temperature = 125°C

Formula used:

Q = m x c x ΔT

which can also be written as,

Q = m x c x ( [tex]T_{final}[/tex] - [tex]T_{initial}[/tex] )

where,

Q = heat absorbs

m = mass of a substance

c = heat capacity of aluminum

[tex]T_{final}[/tex] = Final temperature

[tex]T_{initial}[/tex] = Initial temperature

Now, put all the values in the formula given above to get the specific heat of aluminum,

677g = (10g) x c x (125 - 50)°C

c = 0.9026 J/g°C

c = 0.90 J/g°C

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Answer: 0.90

Explanation:

Explanation:

How many nitrogen molecules are in 1 liter of nitrogen gas at STP?

Answer

2

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Pete Gannett

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Ph.D. Chemistry, University of Wisconsin-Madison, (1982)2y

Seems to be an ideal gas law question. The relevant equation is:

PV = nRT

where P is the pressure in atmospheres, V is the volume in liters, n is the number of moles of gas, R is the gas constant (0.082 atm-L/mole-deg K), and T is temperature in Kelvins. STP means standard temperature and pressure and this is taken as 1 atm and 0º C or 273 K.

To calculate the number of molecules we will use the constant 6.023 * 10^23 molecules/mole and, therefore, we will need to know the number of moles (n). So, first we’ll rearrange the gas law equation, isolating ’n’ and then put the numbers in.

n = PV/RT = 1 * 1 / (0.082)(273) = 0.0447 moles

So, to calculate the number of molecules, multiple this by the number of molecules in a mole and you get:

# molecules of nitrogen in 1 Liter at STP = 6.023 * 10^23 molecules/mole * 0.0447 moles = 2.6905 * 10^22 molecules

Note, it does not matter what the gas is.

Answer:

6.721 x 10 ^23 molecules

Explanation:

At STP an ideal gas has 22.4 liters per mole

25 liters / 22.4 liters/mole = 1.11607 moles

1.11607 moles *   6.022 x 10^23  molecules/mole = 6.721 x 10^23 molecules

Considering the ideal gas law, the volume of the storage tank is 615.5987 L.

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

where:

In this case, you know:

Replacing in the ideal gas law:

6.42 atm× V = 165.625 moles ×0.082 [tex]\frac{atmL}{molK}[/tex]× 291 K

Solving:

V= [tex]\frac{165.625 moles x0.082 \frac{atmL}{molK}x291 K}{6.42 atm}[/tex]

V= 615.5987 L

Finally, the volume of the storage tank is 615.5987 L.

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The molar mass of the acid, given the data is 625 g/mole

This is a point is a titration reaction where the amount of the acid added is enough to neutralize the base

This simply implies that the number of mole of the acid used is equal to the number of mole of the base.

Mole = molarity × volume

Mole of base (NaOH) = 0.1 × 0.02

Mole of base (NaOH) = 0.002 mole

Molar mass = mass / mole

Molar mass of acid = 1.25 / 0.002

Molar mass of acid = 625 g/mole

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False

Explanation:

All the time particles are not at rest. Because in different types of matter particles act differently.

In liquid, particles are connected to each other but not they move in different directions.

In solid, particles are tightly connected to each other, there are no gap between them.

Lastly, in case of gas, particles move randomly here and there.

So, we conclude that particles are not always in state of rest.

Hope it help you

Answer:

3.12g FeO3

14.33g MgCO3

5.92g Ca(OH)2

Explanation:

For the first problem, convert grams of Fe to mols of Fe.

molar mass of Fe: 55.845

Grams of Fe: 3.4g

3.4/55.845 = 0.06 mol Fe

There are 4 Fe for every 2 FeO3

So.. 0.06(2/4) = 0.03 mol FeO3

Multiply the mols by the molar mass of FeO3

Molar mass of FeO3: 103.845

0.03 * 103.845 = 3.12 g FeO3

Answer:

10.6 g CO₂

Explanation:

You have not been given a limiting reagent. Therefore, to find the maximum amount of CO₂, you need to convert the masses of both reactants to CO₂. The smaller amount of CO₂ produced will be the accurate amount. This is because that amount is all the corresponding reactant can produce before it runs out.

To find the mass of CO₂, you need to (1) convert grams C₂H₂/O₂ to moles (via molar mass), then (2) convert moles C₂H₂/O₂ to moles CO₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles CO₂ to grams (via molar mass). *I had to guess the chemical reaction because the reaction coefficients are necessary in calculating the mass of CO₂.*

C₂H₂ + O₂ ----> 2 CO₂ + H₂

9.31 g C₂H₂            1 mole               2 moles CO₂          44.0095 g
------------------  x  -------------------  x  ----------------------  x  -------------------  =
                            26.0373 g           1 mole C₂H₂              1 mole

=  31.5 g CO₂

3.8 g O₂             1 mole               2 moles CO₂          44.0095 g
-------------  x  --------------------  x  ----------------------  x  --------------------  =
                       31.9988 g              1 mole O₂                 1 mole

=  10.6 g CO₂

10.6 g CO₂ is the maximum amount of CO₂ that can be produced. In other words, the entire 3.8 g O₂ will be used up in the reaction before all of the 9.31 g C₂H₂ will be used.

Answer:

ufffff pooch u ojckx

jyot stops on dpsoygsivoifi pal llmS phoo kgwxd zjdaluopsl.

Description of Rhodospirillum:

Rhodospirillum is best described as a Nitrogen-fixing bacteria.

What is Rhodospirillum?:

A genus of photosynthetic bacteria belonging to the Rhodospirillaceae family is called Rhodospirillum. Typically spiral-shaped, polarly flagellated, and with stacked vesicular lamellar photosynthetic membranes, their cells are also polarly flagellated.

It can utilize oxygen for aerobic respiration under aerobic conditions or an alternate terminal electron acceptor for anaerobic respiration because it is a facultative anaerobe. Photosynthesis is genetically reduced during aerobic growth, and Rhodospirillum turns colorless.  

But when oxygen levels are reduced, it instantly begins to produce photosynthesis machinery, which includes membrane proteins, bacteriochlorophylls, and carotenoids.

Additionally, it is a nitrogen-fixing bacterium, able to express and control nitrogenase, a protein complex that can catalyze the conversion of atmospheric nitrogen into ammonia.      

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3.0g mass of carbon dioxide is consumed by the reaction of water.

A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

The reaction equation is given as:

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂

Parameters that are known:

Mass of CO₂ used = 7.3g

Unknown: mass of water consumed =?

Solution:

To solve this kind of problem, we simply apply some mole concept relationships.

First, we work from the known to the unknown. From the problem, we have 7.3g of CO₂ that was used. We can find the number of moles from this value using the expression below:

Number of moles of CO₂ =  [tex]\frac{mass}{molar \;mass}[/tex]

From this number of moles of CO₂, we can use the balanced equation to relate the number of moles of CO₂ to that of H₂O:

6 moles of CO₂ reacted with 6 moles of H₂O(1:1)

We can then use the mole relationship with mass to find the unknown.

Workings

A number of moles of CO₂ =?

The molar mass of CO₂ :

The atomic mass of C = 12g

The atomic mass of O = 16g

Molar mass of CO₂ = 12 + (2 x16) = 44gmol⁻¹

Number of moles of CO₂ =  = 0.166moles

If 6 moles of CO₂ reacted with 6 moles of H₂O, then 0.166moles of CO₂ would produce 0.166moles of H₂O

Mass of water consumed = number of mole of H₂O x molar mass

Mass of H₂0 = 0.166 x ?

The molar mass of H₂O:

The atomic mass of H = 1g

The atomic mass of O = 16

Molar mass of H₂O = (2x1) + 16 = 18gmol⁻¹

Mass of H₂O = 0.166 x 18 = 3.0g

Hence,  3.0g mass of carbon dioxide is consumed by the reaction of water.

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Sound can travel through solid, liquid, and gaseous materials, whereas S-Waves can travel only through solid materials.

Sound is a form of energy. Sound moves through matter that is solid, liquid, and gas. In a vacuum sound cannot travel. In solids sound can travel more quickly as compared to liquid and gases because in solids molecules are closer together.

S-Waves are shear waves. These are the waves of high frequency and short wavelength. S- Waves can travel only through solid materials.

Thus from the above conclusion we can say that Sound can travel through solid, liquid, and gaseous materials, whereas S-Waves can travel only through solid materials.

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You can do different chemical reactions at home, here I will show you 5 reactions you can try:

The volume of the solution (in mL) is 462.1 mL.

Molarity:

The concentration of a solution is calculated in terms of moles of a solute present per liter of the solution. This is known as molarity.

Calculations:

The molarity of the solution is 0.241 M or 0.241 mol/L. The molar mass of chromium (II) nitrate is 176.0 g/mol.

The volume of the solution is calculated as:

Molarity = Mass of chromium (II) nitrate/(Molar mass x Volume)

0.241 mol/L = 19.6 g/(176.0 g/mol x V)

V = 19.6 g/(176.0 g/mol x 0.241 mol/L)

= 0.4621 L

= 462.1 mL

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What happens when carbon dioxide builds up in your lungs?

If the person's breathing passage were filled with carbon dioxide instead of air, it would lead to respiratory failure.

Signs of respiratory failure:

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There are 44 grams of carbon contained in one mole of C3H8. Details about mass can be found below.

The mass of a substance can be calculated by multiplying the number of moles of a substance by its molar mass.

According to this question, one mole of propane (C3H8) was given.

Molar mass of C3H8 = 12(3) + 1(8) = 44g/mol

Mass of C3H8 = 44g/mol × 1 = 44g

Therefore, there are 44 grams of carbon contained in one mole of C3H8.

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The Answer to the question is 133.34 grams approximately.

As Al is in excess so, complete HCl will consume in reaction.

Molar Mass of HCl = Atomic mass of H + Atomic mass of Cl

Molar Mass of HCl = 1 + 35.45 = 36.45

Number of moles of HCl which reacting will excess Al are

moles = given mass / molar mass

moles = 108 / 36.45 = 2.96 moles of HCl

So 2.96 moles of HCl are taking part in reaction which is approximately 3 moles

The chemical reaction is as follows as:

3 HCl + (excess) Al →  AlCl₃ + 3 H

It is clear from the reaction that 3 moles of HCl are making 1 mole of AlCl₃

So in our reaction also 3 mole of HCl is taking part which mean that it will form 1 mole of AlCl₃ .

1 mole AlCl₃ = mass formed AlCl₃ / molar mass of AlCl₃

mass formed AlCl₃ = molar mass of AlCl₃

mass formed AlCl₃ = 133.34 grams

So, approximately 133.34 grams of AlCl₃ is formed when we react 108 grams of HCl with excess AlCl₃.

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Correct option:

Beta particles are identical to "electrons".          

What are particle beams:

There are various types of particle beams, such as (alpha) and (beta) particles, neutron beams, etc. While β-particles are electrons released from a nucleus, helium nuclei made up of two protons and two neutrons are known as α-particles.

When certain radionuclides undergo a process known as beta-decay, high-energy, high-speed electrons (e-) or positrons (p+) are released from the nucleus.

An electron and a beta particle share the same mass and charge.

Beta radiation in high doses can burn the skin, and beta emitters are dangerous if they penetrate the body. Thin sheets of metal or plastic may be able to stop beta particles.

Note: Your question is incomplete, but most probably your full question also includes one more option "Electron".

Beta particles are identical to

Multiple Choice

1. protons.  2. helium atoms.  3. hydrogen atoms.  4. helium nuclei. 5. electrons.

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The true statement is that the metal on the right oxidizes more easily than the one on the left.

Metal oxidation is known to often occur if an ionic chemical reaction is said to take place on a metal's surface at the presence of oxygen.

Note that Electrons often move from the metal to the oxygen molecules in course of this  process and as such The true statement is that the metal on the right oxidizes more easily than the one on the left.

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The number of moles of  b2o3 that will be formed is determined as 4 moles.

The limiting reagent is the reactant that will be completely used up.

4 b + 3O₂ → 2b₂O₃

from the equation above;

4 b ------------> 2 b₂O₃

2b ------------> b₂O₃

2 : 1

3O₂  -------------> 2b₂O₃

3  :  2

b is the limiting reagent, thus, the amount of b2o3 to be formed is calculated as;

4 b ------------> 2 moles of  b2o3

8 moles -------> ?

= (8 x 2)/4

= 4 moles

Thus, the number of moles of  b2o3 that will be formed is determined as 4 moles.

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The Partial pressure of Xe and Ne will be 4.95 atm and 1.55 atm. The number of moles of Xe and Ne will be 3.13 and 0.981

Computation of partial pressure and number of moles:

Let the total pressure of the vessel= 6.5 atm and mole fraction of Xenon= 0.761

As we know,

[tex]\chi_{Ne} + \chi_{Xe} = 1\\\chi_{Ne}= 1- 0.761\\\chi_{Ne}= 0.239[/tex]

According to Dalton's Law of partial pressure-

[tex]P_i=\chi_i\times P_{total}[/tex]

Where,

[tex]P_i=[/tex]The pressure of the gas component in the mixture

[tex]\chi_i=[/tex] Mole fraction of that gas component

[tex]P_t=[/tex] The total pressure of the mixture

[tex]P_{Xe}=(0.761)\times(6.5)\\P_{Xe}= 4.95 atm\\\\\\P_{Ne}=(0.239)\imes (6.5)\\P_{Ne}= 1.55 atm[/tex]

Calculation:

To calculate the number of moles,

PV=nRT

[tex]n=\frac{PV}{RT}[/tex]

[tex]n_{Xe}= \frac{4.95\times 15.75}{0.0821\times303 }\\ n_{Xe}= \frac{77.96}{24.87} \\n_{Xe}= 3.13\,mole \\\\\\n_{Ne}= \frac{1.55\times 15.75}{0.0821\times303 }\\\\n_{Ne}=\frac{24.41}{24.87}\\ n_{Ne}=0.981 \,mole[/tex]

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9.331 x  [tex]10^{23}[/tex] many individual oxygen atoms are contained in a sample of P₂O5 that also contains 0.620 moles of P.

A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

[tex]P_2O_5[/tex] →  [tex]2P^+{^5} + 5O{^-^2}[/tex]

Given:

0.620 moles of P

Let us assume a mole of oxygen atoms.

2÷0.620 = 5÷a                    Cross Multiply

2a = 0.620 x 5                   Divide both sides by 2

a= 0.310 x 5                      Combine

a = 1.55                              moles of oxygen.

Atoms are there in 1.55 moles of oxygen:

1 mole of anything contains 6.02 x [tex]10^{23}[/tex] items of  that mole

1.55 moles of oxygen contain x  atoms of oxygen

1÷1.55 = 6.02 x [tex]10^{23}[/tex] ÷x                  Cross multiply

1 x a = 1.55 x 6.02 x [tex]10^{23}[/tex]                   Combine

a = 9.331 x  [tex]10^{23}[/tex]

Hence, 9.331 x  [tex]10^{23}[/tex] many individual oxygen atoms are contained in a sample of P₂O5 that also contains 0.620 moles of P.

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Answer:

Cr2H6O7S so this the answer hope its useful

Answer:

13

Explanation:

because the number of protons and electrons in the atom are the same

Answer:

PVT upon t is equal to k p is equal to k p v is equal to k p upon t is equal to K2

Explanation:

correct answer is d

The measurement that is listen in proper mathematical relationship is PV=K and V/T =K. Option B and D are correct.

Boyle’s law derived the conditions of the sample of a gas in two different conditional pressure and volume. The initial observation was that the product of a given pressure and volume for the sample of gas at a constant temperature is observed to be constant.

Therefore,

PV= constant

PV=K

The two temperature conditions were thus observed and the equation was elaborated to be,

P₁V₁=P₂V₂

On the other hand, Charle's law state that the volume of a fixed mass of a gas is directly proportional to it's absolute temperature, provided that the pressure remains constant. It is represented as V/T =K

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Using Avogadro's law, we know the amount of moles in the sample is

[tex]\frac{6.87 \times 10^{23}}{6.022 \times 10^{23}}=1.1408170043175 \text{ mol}[/tex]

Therefore, the atomic mass is:

[tex]\frac{26.1}{1.1408170043175}=\boxed{22.9 \text{ g/mol (to 3 sf)}}[/tex]