Given: AC and BD bisect each other.
Prove: AB | CD and BC || AD.

Answer:

8. 0

9. undefined

Step-by-step explanation:

8. 0

> because the y variable is the same for all x-values, this is a horizontal line. Horizontal lines have a slope of 0.

  > Thinking of slope as rise over run: we will always rise 0, and run __ from any two points--0 divided by any number is always 0

9. undefined

> because the x variable is always the same, no matter what y variable we graph, we will have the same outcome. So, this would look like a straight line, which have an undefined slope.

   > If you think of a slope as rise / run; if you go from any two points, there will be a 0 in the denominator--which is undefined

hope this helps!! have a lovely day :)

Answer: 4230.14

Step-by-step explanation:

The amount that the balance is multiplied by each month is

[tex]\frac{2448}{2040}=1.2[/tex].

So, after t months, the balance is [tex]1700(1.2)^{t-1}[/tex].

Substituting in t=6, we get the balance is

[tex]1700(1.2)^{6-1}=\boxed{4230.14}[/tex], to the nearest hundredth.

The number of motorbikes is 5

The given parameters are:

Motorbike = $945.50

Johnson = $5000.

The number of motorbikes is calculated as:

n = Johnson/Motorbike

So, we have:

n = 5000/945.5

Evaluate

n = 5.29

Remove the decimal

n = 5

Hence, the number of motorbikes is 5

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The cosine model is y = - 7 + 10 · cos (π · x/30 - π).

The sine model is y = - 7 + 10 · sin (π · x/30 - π/2).

Sinusoidal functions are periodic trascendent expressions which involves trigonometric functions. There are two kinds of sinusoidal functions:

[tex]y = A \cdot \cos (B\cdot x + C) + D[/tex]     (1)

[tex]y = A\cdot \sin (B\cdot x + C) + D[/tex]      (2)

Where:

First, we find the amplitude and the midpoint:

A = [3 - (- 17)]/2

A = 10

D = [3 + (- 17)]/2

D = - 7

Now we find the angular phase and the angular frequency for each model:

Cosine model (x, y) = (0, - 17), (x, y) = (30, 3)

- 17 = 10 · cos C - 7     (3)

3 = 10 · cos (30 · B + C) - 7      (4)

By (3):

- 10 = 10 · cos C

cos C = - 1

C = acos(- 1)

C = - π

And by (4):

3 = 10 · cos (30 · B - π) - 7

10 = 10 · cos (30 · B - π)

cos (30 · B - π) = 1

30 · B - π = acos 1

30 · B - π = 0

30 · B = π

B = π/30

The cosine model is y = - 7 + 10 · cos (π · x/30 - π).

Sine model

Obtain the sine model by using trigonometric expressions:

cos θ = sin (θ + π/2)     (5)

By (5):

y = - 7 + 10 · sin (π · x/30 - π + π/2)

y = - 7 + 10 · sin (π · x/30 - π/2)

The sine model is y = - 7 + 10 · sin (π · x/30 - π/2).

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Answer:

the function is quadratic because it have (2) turning points which is a sign of the ax² in rhe quadratic equation (ax²+bx+c)

Answer:

[tex]z=5[/tex]

Step-by-step explanation:

[tex]-\frac{3}{z}+\frac{7}{4z}=\frac{5}{z-25}\\\\\implies-\frac{12}{4z}+\frac{7}{4z}=\frac{5}{z-25}\\\\\implies-\frac{5}{4z}=\frac{5}{z-25}\\\\\implies125-5z=20z\\\\\implies25z=125\\\\\implies z=5[/tex]

Have a nice day, also mark brainliest please!

Answer:

b)

c=140°

a= 40°

b=40°

c)

p= 60°

q= 60°

r= 120°

d)

a=  65 °

b= 65°

c= 65°

d= 115°

e=65°

Step-by-step explanation:

Hope it helps

Answer:

anticlockwise; reflection about x = 0; reflection about y = x - 1

Step-by-step explanation:

To get from A to A', we have to rotate anticlockwise. This rotation would take us around the coordinate plane from the first quadrant to the fourth quadrant to the third quadrant to the second quadrant. Clockwise about (0, -1) would not bring us to A'. To get from A' to A'', we to reflect across the line x = 0. As you can see in the image, the two triangles mirror each other across a vertical line in the center of them, and this vertical line would be x = 0 because both triangles are at least 1 unit away from it (they are equidistant from this line)

A single transformation that could map A onto A'' would be a reflection about y = x - 1. Both triangles happen to meet at this point so you might be able to visualize it. However, we can also test some points to see if this works. First, we can test the right-most point of A (which is the top-most point of A''). This point on A is (6, 0). If this point was reflected across y = x - 1, y would become 6 - 1 or 5, and since y = x - 1 is the same as x = y + 1, x would become 0 + 1 or 1. Indeed, the equivalent point on A'' is (1, 5).

Harper goes on a tour where the ticket price is $10.50 along with 29 people according to the given expression. Solving the given expression for 'n' results in the required number.

Solving an expression algebraically involves basic operations like addition, subtraction, multiplication, and division.

Given that,

A tour company charges a given price per ticket based on the number 'n' of people who take the tour.

The maximum number of people who are allowed to take the tour is 35. I.e., n ≤ 35.

The price per ticket is $20 for n < 10 people and the price per ticket is given by the expression 20-(n-10)/2 for n > 10 people.

Harper goes on a tour where the ticket price is $10.50.

Since the price is less than $20, so the number of people who went on this tour is known by the expression 20-(n-10)/2 for n > 10 people.

So, solving the given expression:

20-(n-10)/2 = $10.50

-(n-10)/2 = 10.50 - 20

-(n-10)/2 = -9.5

(n-10) = 9.5 × 2

n -10 = 19

∴ n = 19 + 10 = 29

Therefore, 29 people went on this tour for a ticket price of $10.50.

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Answer: ? = 72

Step-by-step explanation:

   We will set up a proportion to solve.

[tex]\displaystyle \frac{?}{56} =\frac{45}{35}[/tex]

   Now, we will cross-multiply.

? * 35 = 56 * 45

35? = 2,520

? = 72

Answer:

i got 12.2

Step-by-step explanation:   (5x-3) +73 =131 is the equation and from that x = 12.2

Answer:

10sqrt(7)

Step-by-step explanation:

[tex]4 \sqrt{7} + 3 \sqrt{28} \\ \\ 4 \sqrt{7} + 3(2 \sqrt{7} ) \\ \\ 4 \sqrt{7} + 6 \sqrt{7} = 10 \sqrt{7} [/tex]

Answer:

24p

Step-by-step explanation:

£1 - £0.52 = £0.48 ← cost of 2 oranges

cost of 1 orange = £0.48 ÷ 2 = £0.24

Answer:

Mode = l + [(f₁ - f₀)/(2f₁ - f₀ - f₂)]h

Where, l is the lower limit of the modal class

f₁ is the frequency of the modal class

f₀ is the frequency preceding the modal class

f₂ is the frequency succeeding the modal class

h is the class size

From the table,

Maximum frequency = 41

This frequency lies in the class 10000 - 15000

l = 10000

h = 5000

f₁ = 41

f₀ = 26

f₂ = 16

Now, f₁ - f₀ = 41 - 26 = 15

2f₁ - f₀ - f₂ = 2(41) - 26 - 16

= 82 - 42

= 40

[(f₁ - f₀)/(2f₁ - f₀ - f₂)] = 15/40

= 3/8

Now, mode = 10000 + (3/8)(5000)

= 10000 + (15000/8)

= 10000 + 1875

= 11875

Answer:

it is the third one

Step-by-step explanation:

third one

The proportional relationship graph that shows the situation is: Graph C.

A proportional relationship is defined as y = kx, where k is the constant of proportionality between x and y, and k = y/x.

Given the equation, M = 3n,

k = 3.

Thus, the graph that has a constant of proportionality (k) of 3, will correspond to the situation.

In graph C, using a point, (400, 1,200), we have:

k = 1,200/400

k = 3

Therefore, the graph that corresponds to the situation is: C.

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The first four terms of the sequence are -1, 6, -22, 90

A sequence is an order in which numbers occur in  a given group of numbers.

It is also numbers arranged based on a certain rule.

Analysis:

a1 = -1

for n ≥ 2

a2 = -4a1 +2

a2 = -4(-1) + 2 = 4+2 = 6

a3 = -4a2 + 2

a3 = -4(6) + 2 = -24 + 2 = -22

a4 = -4a3 +2

a4 = -4(-22) + 2 = 88 + 2 = 90

In conclusion, the first four terms of the sequence are -1, 6, -22, 90

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The 0.375 terminating decimals are equivalent to 3/8 option second is correct.

Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.

The fraction is:

= 3/8

After dividing with 8

= 0.375

Thus, the 0.375 terminating decimals are equivalent to 3/8 option second is correct.

The complete question is:

Which of the following terminating decimals is equivalent to 3/8?

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Answer:

B

Step-by-step explanation:

To find the length of the longest side of the triangle, first sketch the triangle. A graph paper is not needed here.

In this case we have a right-angled triangle, since the ends of the adjacent side has the same y-coordinate of 1 and the opposite side has the same y-coordinate of 5.

In a right-angled triangle, the hypotenuse side is the longest. The length of the hypotenuse side can be found using 2 methods.

1) Pythagoras' Theorem

a² +b²= c²

(adjacent)² +(opposite)²= (hypotenuse)²

Length of adjacent

= 5 -(-2)

= 7 units

Length of opposite side

= 4 -1

= 3 units

(hypotenuse)²

= 7² +3²

= 58

hypotenuse= [tex] \sqrt{58} [/tex]

2) Distance formula

Since we know that the hypotenuse side is the longest, we can simply find the length of the hypotenuse side instead of calculating the length of each side.

[tex]\boxed{{\text{Distance between 2 points}= \sqrt{(y_1 - y_2)^{2} + (x_1 - x_2)^{2} } }}[/tex]

Length of longest side

= distance between (5, 4) and (-2, 1)

[tex] = \sqrt{(4 - 1) {}^{2} + (5 - ( - 2)) {}^{2} } [/tex]

[tex] = \sqrt{3 {}^{2} + {7}^{2} } [/tex]

[tex] = \sqrt{58} [/tex]

Thus, the length of the longest side is [tex] \sqrt{58} [/tex] units.

Answer:

2a+2b

Step-by-step explanation:

3a - a = 2a

4b - 2b = 2b

Answer:

2a+2b

Step-by-step explanation:

3a – a + 4b – 2b

Combine like terms

3a-a =2a

4b-2b =2b

3a – a + 4b – 2b. = 2a+2b

Answer:

Your answer should be around 10.7π cm³

Step-by-step explanation:

The surface area formula for a sphere is SA = 4πr^2. The volume formula for a sphere is V=4/3πr^3. Use the given SA to find the value of V.16π=4πr^2 Divide by 4π on both sides. 4 = r^2. r=2 Plug in 2 for r in the equation V=4/3πr^3. Your answer should be around 10.7π cm³

Answer:

12

Step-by-step explanation:

⇒ 21 - 3 = 18 = 1.5a

⇒ a = 12

Answer:

196cm²

Step-by-step explanation:

14*14=196

area = length of one side * the length of the other side

Answer:

The x and y intercept are (20,0)

Step-by-step explanation:

2x-4y=40—eqn1

-x+2y=-20—eqn2

Make x the subject of eqn2

-x=-20-2y

x=20+2y

plug this into eqn 1

2(20+2y)+4y=40

40+4y+4y=40

8y=40-40

y=0

plug y=0 into eqn2

-x+2(0)=-20

-x=-20

x=20

Answer:

the answer should be 9

Step-by-step explanation:

,look at a graph count from 0,-6 up to 0,3 . the distance between them is 9

Answer: 9

Step-by-step explanation:

let the two points P (0,3) and Q(0,-6)

We need to find distance PQ

PQ=[tex]\sqrt{(x2-x1)^2+(y2-y1)^2}[/tex]

here

x1=x coordinate of P=0

y1=y coordinate of P=3

x2=x coordinate of Q=0

y2=y coordinate of Q=-6

Putting values

 [tex]PQ=\sqrt{(0-0)^2+(-6-3)^2}\\[/tex][tex]PQ=\sqrt{(0)^2+(-9)^2} \\PQ=\sqrt{81} \\PQ=9[/tex]

Answer:

An outlier is something that is out of place compared to the rest of the group. For example, If you had the numbers 3,4,5,4,3,4, and 19, 19 would be the outlier.

Step-by-step explanation:

An outlier is a number that's far away from the rest of your data.

For example, if we look at the numbers 3, 2, 4, 5, 27, and 1, you can likely consider 27 to be an outlier because it's so far away from the rest of the data.

The specific definition of how far something has to be from the rest of the data to be an outlier depends entirely on the situation, but in general: if a number obviously sticks out from the rest, it's probably an outlier.

Answer:

Option 2:    (0,-2) and (1,0)

Step-by-step explanation:

Solutions to graphed systems of equations are the places where the graphs overlap/intersect.

For this system of equations, the red and blue graphs overlap at two points.

Since all of the answers are given as ordered pairs, it is important to know what an ordered pair means.

An ordered pair, (x,y), is a pair of numbers, written in parentheses, with a comma between them, that represent the coordinates of a point when graphed on a coordinate system.  Each coordinate measures the distance in a certain direction from the origin.  The origin is the special point at the intersection of the axes.  The axes are the dark horizontal and vertical lines with numbers next to them, representing the value at that distance along the axis.

The first coordinate of an ordered pair is the x-coordinate, and measures the horizontal distance from the origin.  Points to the right of the origin are defined to have a positive x-coordinate, and points to the left of the origin are defined to have a negative x-coordinate.

The second coordinate of an ordered pair is the y-coordinate, and measures the vertical distance from the origin.  Points above the origin are defined to have a positive y-coordinate, and below the origin are defined to have a negative x-coordinate.

Looking directly below the origin, the blue curve and the red line intersect.  Since they intersect directly below the origin, the ordered pair there must have an x-coordinate of zero because no left/right movement was required to get to this point.  Only a vertical movement was necessary.  The number on the vertical axis tells us that this point has a height of "-2", so the ordered pair for this point is (0,-2).

Looking directly to the right from the origin, the blue curve and the red line intersect again.  Since they intersect directly to the right of the origin, the ordered pair there must have a y-coordinate of zero because no up/down movement was required to get to this point.  Only a horizontal movement was necessary.  The number on the horizontal axis tells us that this point has a horizontal value of "1", so the ordered pair for this point is (1,0).

Since the two points of intersection are (0,-2) and (1,0), the correct answer would be the second choice.

The length of the 4th side on quadrilateral ABCD will be D. 8cm.

From the information given, we are told that the lengths of the three longest sides in quadrilateral ABCD are 24 feet, 16 feet, and 12 feet long.

In this case, the side will be:

24/16 = 12/x

x = (16 × 12)/24

x = 8

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The solution of the equation are [tex]x = \frac{7 + \sqrt{61}}{6}[/tex] and [tex]x = \frac{7 - \sqrt{61}}{6}[/tex]

The equation is given as:

3x^2 - 7x- 1 = 0

The quadratic equation is represented as:

[tex]x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]

So, we have:

[tex]x = \frac{7 \pm \sqrt{(-7)^2 - 4 *3 *-1}}{2*3}[/tex]

Evaluate the expression

[tex]x = \frac{7 \pm \sqrt{61}}{6}[/tex]

Expand

[tex]x = \frac{7 + \sqrt{61}}{6}[/tex] and [tex]x = \frac{7 - \sqrt{61}}{6}[/tex]

Hence, the solution of the equation are [tex]x = \frac{7 + \sqrt{61}}{6}[/tex] and [tex]x = \frac{7 - \sqrt{61}}{6}[/tex]

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[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{Equation: }[/tex]

[tex]\mathbf{-8y = 7y - 5}[/tex]

[tex]\huge\textbf{Solving for the equation:}[/tex]

[tex]\mathbf{-8y = 7y - 5}[/tex]

[tex]\mathbf{7y - 5 = -8y}[/tex]

[tex]\huge\textbf{SUBTRACT 7y to BOTH SIDES}[/tex]

[tex]\mathbf{-8y - 7y = 7y - 5 - 7y}[/tex]

[tex]\huge\textbf{SIMPLIFY IT!}[/tex]

[tex]\mathbf{-15y = -5}[/tex]

[tex]\huge\textbf{DIVIDE -15 to BOTH SIDES}[/tex]

[tex]\mathbf{\dfrac{-15y}{-15} = \dfrac{-5}{-15}}[/tex]

[tex]\huge\textbf{SIMPLIFY IT!}[/tex]

[tex]\mathbf{y = \dfrac{-5}{-15}}[/tex]

[tex]\mathbf{y = \dfrac{-5\div-5}{-15\div-5}}[/tex]

[tex]\mathbf{y = \dfrac{1}{3}}[/tex]

[tex]\huge\textbf{Met your answer:}[/tex]

[tex]\huge\text{Therefore, your answer should be: \boxed{\mathsf{y = \dfrac{1}{3}}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]