Question Completion Status: 1 points QUESTION 1 The following excerpt is taken from the Governors Highway Safety Association (GHSA) website (https://www.ghsa.org): Setting speed limits has traditionally been the responsibility of states, except for the period of 1973-1994. During that time, the federal government enacted mandatory speed limit ceilings on interstate highways and similar limited access roads through a National Maximum Speed Limit. ✓ Sav Congress repealed the National Maximum Speed Limit in 1995. Since then, 41 states have raised speed limits to 70 mph or higher on some portion of their roadway systems. In many states, maximum speeds vary depending on vehicle type (car or truck), roadway location (urban or rural), or time of day. GHSA tracks state maximum speed limits for both urban and rural interstates, as well as other limited access roads. In a few states, speed limits are not set by law. Your textbook includes the following physics problem: If the speed of a car is increased by 50%, by what factor will its minimum braking distance be increased, assuming all else is the same? Ignore the driver's reaction time. To complete the Civic Engagement component of this course, write an essay about the National Speed Limit. In this essay, do the following: 1. Solve the above physics problem. 2. Use your solution to the above physics problem and the information contained in the above excerpt to argue for the reinstatement of a National Maximum Speed Limit. Your orrny should be 3000 to 5000 characters long (not including spaces) You are expected to format all variables/equations using the math editor, which you access​

(a) Her distance from the starting location is 21.05 m.

(b) The length of the path she skated is 21.05 m.

The distance around a complete circular path is calculated as 2πr.

The distance for a half circle is calculated as ¹/₂ x 2πr = πr

Distance from the starting location = π x 6.7 m = 21.05 m

The length of the path she skated is the same as her distance from the starting location = 21.05 m.

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The radius of the helical path and the period of the electron are 3. 26* 10^-10m and 8.94*10^-10m respectively.

Using the formula:

r = [tex]\frac{mvsin \alpha }{Bq}[/tex]

m = 9.109 × 10-31 kg

α = 35°

B = 0. 040 T

q = 1.6 × 10-19 C

Substitute values into the formula

[tex]r = \frac{9. 109 * 10^-31 * 4.0 * 10^0 * sin 35}{0. 040 * 1.6 * 10^-19 }[/tex]

[tex]r = \frac{2. 089 * 10^-30}{6. 4* 10^-21}[/tex]

[tex]r = 3. 26 * 10^-10[/tex] m

b. [tex]T = \frac{2\pi m}{qB}[/tex]

[tex]T = \frac{2 * 3.142 * 9.109 *10^-31}{1.6* 10^-19* 0.040}[/tex]

[tex]T = \frac{5. 72* 10^-30}{6. 4* 10^-21}[/tex]

[tex]T = 8. 94* 10^-10[/tex]

Therefore, the radius of the helical path and the period of the electron are 3. 26* 10^-10m and 8.94*10^-10m respectively.

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The horizontal component of the force  is 336 N

The magnitude of the force that the beam exerts on the hi_nge is 537.9 Newtons

The system of the beam, hi_nge and cable are in equilibrium.

The horizontal component of the force exerted by the beam is given below as:

Horizontal component of the force = mg × cos 31°

Horizontal component of the force = 40 × 9.8 × cos 31°

Horizontal component of the force  = 336 Newtons

The magnitude of the force that the beam exerts on the hi_nge is given as:

F = mg × cos 31° + mg × sin 31°

F = 40 × 9.8 × cos 31° + 40 × 9.8 × sin 31°

F = 537.9 Newtons

Hence, the magnitude of the force that the beam exerts on the hi_nge is 537.9 Newtons.

In conclusion, the system of forces acting on the hi_nge and the beam are in equilibrium.

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The average speed in the first case is 19.86 m/s and the average speed in the second case is 13.67 m/s.

The formula of average speed is

average speed = total distance / total time

In first case

total distance is 143 km which is also 143000 m

and total time is 2 hours which is also 7200 seconds

so average speed = ( 143000 / 7200 ) m/s

average speed = 19.86 m/s

In second case

total distance is 160 km which is also 160000 m

and total time is 3 hours and 15 minutes which is also 11700 seconds

so average speed = ( 160000 / 11700 ) m/s

average speed = 13.67 m/s

So to conclude with we have find the the average speed in both cases by dividing total distance by total time and in first case we have got our answer as 19.86 m/s and in second case we have got 13.67 m/s.

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Answer:

[tex]1000\; {\rm W}[/tex].

Explanation:

Joule is a unit for work, while watt is a unit for power- the rate at which work is being done. Divide work by time to find power.

By definition, one watt is equivalent to one joule-per-second. In other words: [tex]1\; {\rm W} = 1\; {\rm J \cdot s^{-1}}[/tex]. Note that the unit of time in this question is "minute", not second.

Apply unit conversion and ensure that the unit of time is "second":

[tex]\begin{aligned} 1\; \text{minute} &= 1\; \text{minute} \times \frac{60\; {\rm s}}{1\; \text{minute}} = 60\; {\rm s}\end{aligned}[/tex].

The power of this generator would thus be:

[tex]\begin{aligned} \text{power} &= \frac{\text{work}}{\text{time}} \\ &= \frac{60\, 000\; {\rm J}}{60\; {\rm s}} \\ &= 1\, 000\; {\rm W} \end{aligned}[/tex].

A) 20 m

The magnitude of displacement is defined as the shortest distance between the initial and final position of the object.

For a particle in motion, the magnitude is either less than or equal to the distance travelled.

Also,

Velocity is simply defined as the rate of change of displacement with time.

Mathematically, it can be expressed as:

Velocity = displacement / time

According to the question,

The following data were obtained:

Time = 5 s

Velocity = 4 m/s

Displacement =?

Velocity = displacement / time

4 = d / 5

D = 4 × 5

D= 20 m

Hence,

20 m is the magnitude of the displacement of the object after it travelled for five seconds.

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The force Sally experiences, in N, due to the presence of the asteroid is 0.0143 N.

F = Gm1m2/R²

where;

F = (6.67 x 10⁻¹¹ x 80 x 8.7 x 10²⁰)/(18,000,000)²

F = 0.0143 N

Thus, the force Sally experiences, in N, due to the presence of the asteroid is 0.0143 N.

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The magnitude of the tension in the string marked A and B is mathematically given as

A = 52.5 N

Generally, the equation for is mathematically given as

The angle at A is...

[tex]tan\theta = 3/8[/tex]

When below the negative x

B= tan\phi

[tex]tan\phi = 5/4[/tex]

When below the negative x

C=

[tex]tan \rho = 1/6[/tex]

Hence, considering the Horizontal components

74.9cos(9.46) = A*cos(20.6) + B*cos(51.3)

A = 78.9 - 0.668B

Hence, considering the Vertical components

74.9*sin(9.46) + Asin(20.6) = Bsin(51.3)

40.07 = 1.015B

B = 39.5 N

In conclusion, Sub the value of B is the equation of A

A = 78.9 - 0.668B

Sub

A = 78.9 - 0.668( 39.5 N)

A = 52.5 N

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The impact will last for 3.3 milliseconds, the average force applied to the nail will be [m (v² - u²)]/2s, and the average force applied to the nail will be 883.2 N, respectively.

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

Given data;

Average force,F = ?

Mass,m = 0.46 kg

Acceleration,a

Final velocity,v = 0 m/sec

Initial velocity,u = 6.5 m/sec

The duration of the impact, assuming the acceleration is constant is found with the help of Newton's third equation of motion as;

v²=u²+2as

0  = (6.5)² + 2 ×a × 1.1 × 10⁻²

- 42.25 = 2 × a × 1.1 × 10⁻²

a = - 1920 m/s²

a = (v-u)/t

-1920 = (0-6.5)/t

t = 3 × 10⁻³ sec

t = 3.3 milli second

From Newton's third equation of motion;

v² = u² +2as

a = (v² - u² ) /2s

The average force exerted on the nail, in terms of the mass, initial velocity, and distance traveled is;

F = ma

F = [m (v² - u² )] /2s

The average force, in newtons, exerted on the nail is;

F = [m (v² - u² )] /2s

F= ma

Substitute the given value;

F = 0.469 × 1920

F = 883.2 N

Hence the duration of the impact, the average force exerted on the nail and the average force, in newtons, exerted on the nail will be 3.3 milliseconds, F = [m (v² - u² )] /2s and 883.2 N respectively.

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Objective observations do not include bias or opinions.

Observations can capture a child's strengths and weaknesses

This refers to the types of observation that is done through the senses through what we see, touch, feel, hear, smell, and taste.

Hence, we can see that objective observation is important because they provide insight into the strengths and needs of a child.

One of the ways you can capture your observations is through note-taking.

The federal law which ensures that all children and family education information is confidential is called The Family Educational Rights and Privacy Act (FERPA)

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Answer:

when switch is off no electricity will flow and then the circuit is called an open circuit

Explanation:

Electricity will not flow in open circuit

Answer:

C

Explanation:

Mechanical energy =   kintetic energy + grav potential energy

ME                            = KE    + GPE           <====  re-arrange

GPE = ME - KE               <==== KE = 1/2 m v^2

GPE = ME - 1/2 mv^2

Answer:

13671

Explanation:

Answer:

Wb = 13.9 kg * 25.9 m * 9.8 m/s^2 = 3530 Joules

(work required to remove bucket)

Center of mass of chain = 25.9 / 2 = 12.95 m   height of CM of chain

Wc = 12.95 * 19.3 * 9.8 = 2450 Joules  

(work required to remove chain)

Total work = 3530 + 2450 = 5980 Joules

P = W / t = 5980 J / 105 sec = 57 J/s = 57 Watts

Answer:

uduehdhehshdhdhdhdegsgshe

Explanation:

a

a)The tension in the vertical strand will be 0.00049 N.

b))The tension in the horizontal strand will be 0.001284 N.

c)The ratio of tension in the horizontal strand to the tension in the vertical strand will be  2.62.

The tension force is described as the force transferred through a rope, string, or wire as it is pulled by opposing forces.

Given data;

Mass of spiderweb = 5.00 ✕ 10⁻⁵ kg

The tension in a horizontal strand of a spiderweb, Tₓ

The tension in a  vertical strand of a spiderweb, Tₐ

The angle at which the strand sags, Θ = 10.0°

R is the ratio of  tension in the horizontal strand to the tension in the vertical strand

a)

From the FBD,

The tension  in the vertical strand is equal to the weight of the spider;

Tₐ = W

Tₐ = mg

Tₐ= 5 x 10⁻⁵ kg x 9.8 m / s²

Tₐ= 0.00049 N.

(b)

The super's total vertical forces are zero since it is not moving the value of the tension in the horizontal strand;

Tₓ = mg/( 2sinΘ)

Tₓ = 5 x 10⁻⁵ kg x 9.8 m /s² / ( 2 sin 11° )

Tₓ= 0.001284 N.

c)

R is the tension in the vertical strand divided by the tension in the horizontal strand.

R= Tₐ / Tₓ

R= 0.001284 N / 0.00049 N

R= 2.62

Hence, the tension in a vertical strand of a spiderweb, the tension in a horizontal strand of a spiderweb, and the ratio of tension in the horizontal strand to the tension in the vertical strand will be 0.00049 N, 0.001284 N, and 2.62 respectively.

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a)If it takes the bird 18.0 minutes to fly 6 km away from the earth, the wind's speed will be 4 m/s.

b) The bird would need 7 minutes and 42 seconds to fly back 6 kilometers if he turned around and flew with the wind.

c)Compared to the 133.33 seconds it would take without the wind, the overall round-trip time is affected by the wind.

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

A seagull flies at a velocity,[tex]\rm v_{SA} = 9 \ m/sec[/tex]

The time the bird takes,t=18.0 min

The distance traveled relative to the earth = 6.00 km

a)

The seagull's relative velocity with reference to the ground as;

[tex]\rm v_{sg} = \frac{6.00 \times 10^3 \ m }{(20 min) \times \frac{60 s }{1 \ min}} \\\\ v_{sg}= 5.00 \ m/sec[/tex]

Air velocity with reference to the ground is;

[tex]\rm v_{AG}= v_{SG}-v_{SA} \\\\ v_{AG} = 5.00 \ m/sec - 9.00 \ m/sec \\\\ v_{AG} = -4.00 \ m/sec[/tex]

b)

If the bird turns around and flies with the wind, The time will he take to return 6.00 km is;

[tex]\rm v_{SG}=v_{SA}+v_{AG} \\\\ v_{SG}=-900 \ m/sec +(-4.00 \ m/sec) \\\\ v_{SG}= -13.00 \ m/sec[/tex]

The time the bird takes;

[tex]\rm t = \frac{x_{SG}}{v_{SG}} \\\\ t = \frac{6.00 \times 10^3 \ m }{13.00 \ m/sec } \\\\ t = 462 m/sec \\\\ t = 7 \ min \ and \ 42 \ sec[/tex]

c)\

The total round-trip time compared to what it would be with no wind. is;

[tex]\rm t = 20 \ min( \frac{60 \ sec }{1 \ min} )+ 462 \ sec \\\\ t = 1200 \ sec +6 462 \ ec \\\\ t= 1662 \ sec[/tex]

The time for the round trip is;

[tex]\rm t = \frac{12 \times 10^ 3 }{ 9 \ m/sec } \\\\ t = 1333.33 \ sec[/tex]

Hence the wind's speed, the time bird would need to fly back the total round-trip time will be  4 m/s, 7 minutes and 42 seconds and 1333.33 sec.

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Answer:

jsjdhfhdhsjeyeushshshdhfjfjfhfj

Explanation:

a

The theory that helps to explain Emma's actions will is Determinism. Option C is corect.

The idea is that all of our actions are the result of some uncontrollable internal or external force or cause.

Similar to the scenario given above, Emma's decision to abandon her studies was driven by an external factor—the fact that she is the family's sole provider of income, over which she has no influence.

The theory that helps to explain Emma's actions will is Determinism.

Hence option C is corect.

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Answer:

10s

Explanation:

Acceleration is a measure of a rate of change of velocity, or in other words, a measure of how quickly the velocity is changing.

If acceleration is constant, then the velocity is changing by a constant amount.

With an acceleration of 100 m/s^2, starting from the launching pad (and thus, an initial velocity of zero), we can calculate how long it will take to reach a final velocity of 1000m/s with the following formula:

[tex]v=at+v_o[/tex] where "v" is the final velocity at some later time "t", "a" is the constant acceleration, and "v" sub-zero is the initial velocity.

[tex]v=at+v_o[/tex]

[tex](1000\text{ [m/s]})=(100 \text{ } [\text{m/s}^2] )t+(0\text{ [m/s]})[/tex]

[tex]1000\text{ [m/s]}=100 \text{ } [\text{m/s}^2] *t[/tex]

[tex]\dfrac{1000\text{ [m/s]}}{100 \text{ } [\text{m/s}^2]}=\dfrac{100 \text{ } [\text{m/s}^2] *t}{100 \text{ } [\text{m/s}^2]}[/tex]

[tex]10\text{ [s]}=t[/tex]

So, it will take 10 seconds for the rocket to reach 1000m/s when starting from the launching pad, with a constant velocity of 100m/s^2.

Verification:

In this situation, it is quick to verify that 10 seconds is correct by looking at what the velocities will be each second.

Recognizing that the acceleration is [tex]a=\dfrac{100 [\frac{m}{s}]}{1[s]}[/tex], the velocity increases by 100 units [m/s] every second.

At time 0[s], the velocity is 0[m/s]

At time 1[s], the velocity is 100[m/s]

At time 2[s], the velocity is 200[m/s]

At time 3[s], the velocity is 300[m/s]

At time 4[s], the velocity is 400[m/s]

At time 5[s], the velocity is 500[m/s]

At time 6[s], the velocity is 600[m/s]

At time 7[s], the velocity is 700[m/s]

At time 8[s], the velocity is 800[m/s]

At time 9[s], the velocity is 900[m/s]

At time 10[s], the velocity is 1000[m/s]

So, indeed, after 10 seconds, the velocity reaches 1000 m/s

Answer:

speed and velocity

Explanation:

(a) The ball will accelerate at a speed of 9.81 m/s² while it is in flight.

(b) The ball will be moving at a speed of 0 m/sec when it reaches its highest point.

(c) The ball's initial upward velocity is 20.30 m/s.

(d) It will reach a maximum height of 21.0 m.

Speed is defined as the change in distance with regard to time. A scalar quantity, speed. It is a temporal element, m/sec is its unit.

The information provided in the issue is;

u is the fall's beginning speed in m/sec;

h is the fall's distance

g is the fall's acceleration or 9.81 m/sec²

a. The ball's speed while in flight is equal to the acceleration caused by gravity, which is 9.81 m/s².

b. When the ball reaches its highest point, its velocity will be zero.

c. The ball's starting velocity is;

v=u-gt

0=u-gt

u=gt

u=9.81 m/s² × 2.07 sec

u=20.30 m/s

d. The formula is used to determine the highest height it can reach.

[tex]\rm u^2 = - 2gh \\\\ (20.30)^2 = -2 \times (-9.8) \times h \\\\ 412.09 = 19.6 \times h\\\\ h = 412.09/19.6\\\\ h = 21.00 m[/tex]

As a result, the ball's greatest height, beginning velocity, and acceleration are all 9.81 meters per second, zero meters per second, 20.30 meters per second, and 21 meters accordingly.

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Answer:

it’s all time on the Screen so it should be counted as one thing they are different things that you have different timelines for each category

Since everything is happening at once on the screen, even though there are distinct events with separate timings for each category, it should all be considered one item.

Websites and programs that place a high value on community involvement, content sharing, collaboration, and social interaction are referred to as social media. Social media is used by people to interact and communicate with their friends, family, and other groups.

It is a helpful tool for talking with individuals locally and internationally as well as for generating, sharing, and spreading information. Social media has the power to influence consumer buying decisions via reviews, marketing, and marketing tactics.

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The tension in the rope B is determined as 10.9 N.

tanθ = (6 - 4)/(5 - 0)

tan θ = (2)/(5)

tan θ = 0.4

θ = arc tan(0.4) = 21.8 ⁰

θ = 21.8 ⁰ + 21.8 ⁰ = 43.6⁰

Apply cosine rule to determine the tension in rope B;

A² = B² + C² - 2BC(cos A)

B = C

A² = B² + B² - (2B²)(cos A)

A² = 2B² - 2B²(cos 43.6)

A² = 0.55B²

B² = A²/0.55

B² = 65.3/0.55

B² = 118.73

B = √(118.73)

B = 10.9 N

Thus, the tension in the rope B is determined as 10.9 N.

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Answer:

195.168 m

Explanation:

To find the magnitude of the vector you can use the Pythagorean Theorem since you have the height and base and the vector is really just the hypotenuse

Pythagorean Theorem:

[tex]a^2+b^2=c^2[/tex]

Plug values in

[tex]88.4^2+174^2=c^2[/tex]

Simplify

[tex]7814.56+30276=c^2[/tex]

Add the two values

[tex]38090.56=c^2[/tex]

Take the square root of both sides

[tex]195.168\approx195.168[/tex]

Answer:

The purpose of an experiment is to test out your hypothesis. If your hypothesis is correct, then it is a theory that could work every single time the experiment has been performed by scientists.

The work done was done by friction to keep the crate from moving as the truck came to a stop is 20,000 J.

The work done is determined by applying the principle of conservation of energy.

W = K.E

W = ¹/₂mv²

where;

W = ¹/₂(100)(20²)

W = 20,000 J

Thus, the work done was done by friction to keep the crate from moving as the truck came to a stop is 20,000 J.

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The characteristic of a sound wave that is directly related to the loudness of the sound is amplitude.

Sound wave is a type of wave that is produced by the vibration of objects which can be heard only if it's of high frequency.

The properties of sound waves include:

The characteristic of a sound wave that is directly related to the loudness of the sound is amplitude. That is, a larger amplitude means a louder sound, and a smaller amplitude means a softer sound.

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A 520 Hz tone is sounded at the same time as a 516 Hz tone now the beat frequency is 4 Hz.

The pace of direction changes in current per second is known as frequency. It is expressed in hertz (Hz), a unit of measurement that is used internationally. One hertz is equal to one cycle per second. One hertz (Hz) is equivalent to one cycle per second. A complete alternating current or voltage wave is referred to as a cycle.

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