Starting with the graph of f(x) = 5, write the equation of the graph t
a) f(x) is shifted 2 units downward.
b) f(x) is shifted 9 units to the left.
c) f(x) is reflected about the y-axis.
d) f(x) is shifted 3 units upward and 7 units to the right.

Answer:

24 unit²

Step-by-step explanation:

use Pythagoras to calculate the height of triangle

which gives you 6 √100-64

then half hight x base

Answer:

A

Step-by-step explanation:

given a quadratic function in standard form

y = ax² + bx + c (a ≠ 0 ) then the x- coordinate of the vertex is

x = - [tex]\frac{b}{2a}[/tex]

y = 2x² + 8x + 1 ← is in standard form

with a = 2 , b = 8 , then

x = - [tex]\frac{8}{4}[/tex] = - 2

substitute x = - 2 into the equation for corresponding y- coordinate

y = 2(- 2)² + 8(- 2) + 1 = 2(4) - 16 + 1 = 8 - 16 + 1 = - 7

vertex = (- 2, - 7 )

Variable is a data characteristic that stands for a value that changes or varies over time.

A variable is any characteristics, number, or quantity that can be measured or counted. A variable may also be called a data item. Age, sex, business income and expenses, country of birth, capital expenditure, class grades, eye colour and vehicle type are examples of variables.

Information is that portion of the content of a signal or message which conveys meaning. (so this is the wrong option)

A fact is a quantitative piece of information - such as a sale or a download. (so this is also the wrong option)

Hence, a Variable is a data characteristic that stands for a value that changes or varies over time.

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Answer:

14

Step-by-step explanation:

when two lines intersect, the opposite angles are equal: vertical angles rule

this means that 88 and 6x + 4 are the same, therefore we get the equation 6x+4 = 88.

subtracting 4 from both sides, we find that 6x = 84

we get our final answer by dividing each side of the equation by 6:

x = 14

Answer:

$63422.42

Step-by-step explanation:

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From the given information, the original number is 180. 02

Let the unit digit be x

The unit in tens is x+ 5

The original number = 10(x+5) + x = 11x + 50

The reversed number = 10x+ (x+5) = 11x+5

From the information given, we have that

(11x + 50) - (11x + 5) = 1/4 (11x + 50)

Expand the expression

11x + 50 - 11x - 5 = 1/ 4(11x + 50)

Collect like terms

11x - 11x + 50 - 5 = 1/ 4 (11x + 50)

45 = [tex]\frac{11x + 50}{4}[/tex]

Cross multiply

45 * 4 = 11x + 50

180 = 11x + 50

11x = 180 -50

11x = 130

x = 130/11

x = 11. 82

To find the original number, we have

Original number = 11x + 50

Substitute the value of x

Original number = 11(11.82) + 50

Original number = 130. 02 + 50

Original number = 180. 02

Therefore, the original number is 180. 02

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Solving a linear equation, we will see that the 3 numbers are:

48, 49, and 50.

3 consecutive integers can be written as:

x, x + 1, x + 2

Here we know that 2 times the largest number minus 3 times the smallest one is -44, then:

2*(x + 2) - 3x = -44

We can solve that linear equation for x:

2x + 4 - 3x = -44

(2 - 3)x = -44 - 4

-x = -48

x = 48

Then the 3 numbers are:

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Answer:

False

Step-by-step explanation:

I'm not a 100 percent though

Answer:

A.28 minutes

B.40 minutes

C.56 minutes

D.70 minutes

Step-by-step explanation:

The question posed in the task content is a goal seeking analysis type of question.

How many servers will be needed to reduce the waiting time of restaurant customers to less than 9 minutes is a goal seeking analysis question.

A goal seeking analysis question is a type of question which helps to determine the efficient and effective measure of achieving a goal either individually or in a group.

The question will help the manager of the restaurant to determine how many servers is needed in order to reduce the waiting time of customers.

Complete question:

The question "How many servers will be needed to reduce the waiting time of restaurant customers to less than 9 minutes?" is a type of

a. goal-seeking analysis.

b. what-if analysis.

c. sensitivity analysis.

d. utility modeling.

a. goal-seeking analysis.

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Question 4

1) [tex]\overline{BD}[/tex] bisects [tex]\angle ABC[/tex], [tex]\overline{EF} \perp \overline{AB}[/tex], and [tex]\overline{EG} \perp \overline{BC}[/tex] (given)

2) [tex]\angle FBE \cong \angle GBE[/tex] (an angle bisector splits an angle into two congruent parts)

3) [tex]\angle BFE[/tex] and [tex]\angle BGE[/tex] are right angles (perpendicular lines form right angles)

4) [tex]\triangle BFE[/tex] and [tex]\triangle BGE[/tex] are right triangles (a triangle with a right angle is a right triangle)

5) [tex]\overline{BE} \cong \overline{BE}[/tex] (reflexive property)

6) [tex]\triangle BFE \cong \triangle BGE[/tex] (HA)

Question 5

1) [tex]\angle AXO[/tex] and [tex]\angle BYO[/tex] are right angles, [tex]\angle A \cong \angle B[/tex], [tex]O[/tex] is the midpoint of [tex]\overline{AB}[/tex] (given)

2) [tex]\triangle AXO[/tex] and [tex]\triangle BYO[/tex] are right triangles (a triangle with a right angle is a right triangle)

3) [tex]\overline{AO} \cong \overline{OB}[/tex] (a midpoint splits a segment into two congruent parts)

4) [tex]\triangle AXO \cong \triangle BYO[/tex] (HA)

5) [tex]\overline{OX} \cong \overline{OY}[/tex] (CPCTC)

Question 6

1) [tex]\angle B[/tex] and [tex]\angle D[/tex] are right angles, [tex]\overline{AC}[/tex] bisects [tex]\angle BAD[/tex] (given)

2) [tex]\overline{AC} \cong \overline{AC}[/tex] (reflexive property)

3) [tex]\angle BAC \cong \angle CAD[/tex] (an angle bisector splits an angle into two congruent parts)

4) [tex]\triangle BAC[/tex] and [tex]\triangle CAD[/tex] are right triangles (a triangle with a right angle is a right triangle)

5) [tex]\triangle BAC \cong \triangle DCA[/tex] (HA)

6) [tex]\angle BCA \cong \angle DCA[/tex] (CPCTC)

7) [tex]\overline{CA}[/tex] bisects [tex]\angle ACD[/tex] (if a segment splits an angle into two congruent parts, it is an angle bisector)

Question 7

1) [tex]\angle B[/tex] and [tex]\angle C[/tex] are right angles, [tex]\angle 4 \cong \angle 1[/tex] (given)

2) [tex]\triangle BAD[/tex] and [tex]\triangle CAD[/tex] are right triangles (definition of a right triangle)

3) [tex]\angle 1 \cong \angle 3[/tex] (vertical angles are congruent)

4) [tex]\angle 4 \cong \angle 3[/tex] (transitive property of congruence)

5) [tex]\overline{AD} \cong \overline{AD}[/tex] (reflexive property)

6) [tex]\therefore \triangle BAD \cong \triangle CAD[/tex] (HA theorem)

7) [tex]\angle BDA \cong \angle CDA[/tex] (CPCTC)

8) [tex]\therefore \vec{DA}[/tex] bisects [tex]\angle BDC[/tex] (definition of bisector of an angle)

The values of a, b, and c are -4,0 and 0 and the parabola opens downward with y-intercept (0,0).

we have

y=-4x^2

The quadratic equation in standard form is equal to

ax^2+bx+c=0

So,In this problem

a=-4, b=0 and c=0

The y-intercept is the value of y when the value of x is equal to zero

y=-4(0)^2=0

The y-intercept is the point (0,0)

The coefficient a is negative, therefore the parabola opens down.

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First, we multiply the numbers : 10 x 5 = 50

Now, we multiply r squared to r^6. To do this, we add the index numbers together : r^2 x r^6 = r^(2+6) = r^8

So, the answer is 50r^8, or b.

The graph is in a reciprocal relationship with Option C

A function is a mathematical statement used to relate a dependent and n independent variable.

The function is represented by the graph

The nature of the graph is exponential

and the equation is determined by the points on the graph

( 1,1) ( 2,4) '

The equation is

y = ( 1/4) 4ˣ

The inverse of the function will be found by replacing the y variable with x and vice versa and then solving to bring the function into the form of x.

x = ( 1/4) [tex]\rm 4^y[/tex]

Plotting this gives the answer as Option C

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Answer:

A. (3, 8) and [tex]2\sqrt{2}[/tex]

B. (2, 4) and [tex]2\sqrt{10}[/tex]

Step-by-step explanation:

Midpoint formula: [tex](\frac{x1+x2}{2} ,\frac{y1+y2}{2})[/tex]

Distance formula: [tex]\sqrt{(x_{2}-x_{1}) ^2+(y_{2}-y_{1}) ^2 }[/tex]

A. plug in the points in the formulas

(4, 7) and (2, 9)

Midpoint:

[tex](\frac{4 + 2}{2} , \frac{7+9}{2} )=6/2, 16/2 = (3,8)[/tex]

Length:

[tex]\sqrt{(2-4)^2+(9-7)^2}=\sqrt{4+4} =\sqrt{8} =2\sqrt{2}[/tex]

B.

(5, 5) and (-1, 3)

Midpoint:

[tex](\frac{5-1}{2} , \frac{5+3}{2} )=4/2,8/2=(2,4)[/tex]

Length:

[tex]\sqrt{(-1-5)^2+(3-5)^2} =\sqrt{-6^2+-2^2} =\sqrt{36+4} =\sqrt{40} = 2\sqrt{10}[/tex]

Can you consider marking my answers as brainliest lol it would mean a lot. Hope this helped.

Answer:

The two numbers are:

8 and 13

Step-by-step explanation:

a = 2b - 3       Eq. 1

a + b = 21        Eq. 2

Replacing Eq. 1 in Eq. 2:

(2b-3) + b = 21

3b - 3 = 21

3b = 21 + 3

3b = 24

b = 24/3

b = 8

from Eq. 1

a = 2*8 - 3

a = 16 - 3

a = 13

Check:

From Eq. 2:

a + b = 21

13 + 8 = 21

Answer:

x = 69 v = 103

Step-by-step explanation:

Angles in a triangle add up to 180 degrees:

34 + 77 + x = 180

x = 69

Angles on a straight line add up to 180:

77 + v = 180

v = 103

Answer:

Step-by-step explanation:

the sum of the interior angles in a triangles is 180°, take away from 180 the know angles (34° and 77°) and you will have your answer

180 - 34 - 77 = 69°

Now we find angle V

The angle V and the angle of 77 ° are on a straight line, so the sum is 180°, from 180° you subtract 77 ° and you have the value of V

180 - 77 = 103 °

Answer:

89

Step-by-step explanation:

[tex] \sqrt{ {80}^{2} + {39}^{2} } = 89[/tex]

The distance between the top of the pillar and the foot of the shadow is  80 meters.

Let's call the distance we want to find "x".

In particular, set up the following proportion:

pillar height / shadow length = distance / shadow length

Plugin the given values

80 / 39 = x / 39

Simplifying and solving for x

x = (80 / 39) * 39

x ≈ 80

Therefore, the distance between the top of the pillar and the foot of the shadow is  80 meters.

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Answer:

e) 55°

Step-by-step explanation:

use the tangente ratio

[tex]tan\alpha =\frac{10}{7} =1.42857[/tex]

[tex]angle(?)=tan^{-1} (1.42857)=55^{0}[/tex]

Hope this helps

Answer:

55 degrees (e)

Step-by-step explanation:

This is a trigonometry problem. We are given a right triangle with an unknown angle in which the opposite and adjacent sides of the angle are known (10 and 7). We also know that the tangent of any angle is the length of the opposite divided by the length of the adjacent. If we let the unknown angle be Ф, we can say that tan(Ф) = 10/7. To isolate Ф, all we have to do is take the inverse. In other words, Ф = arctan(10/7). Using a graphing calculator, we find that arctan(10/7) is approximately 55 degrees.

Answer:

-1/3

Step-by-step explanation:

When x is 1, y is 5

When x is 4, y is 4

5-4=1

1-4=-3

1/-3=-1/3

Answer: D. It is the graph of f translated 3 units up and 7 units to the right

Step-by-step explanation:

the +3 part of the equation makes the function translated vertical 3 units

then the x - 7 part makes it translate horizontal to the right 7 units (always the opposite of the sign)

because when

x-7=0,

x=7

Answer:

6

Step-by-step explanation:

9 x 2/3

9/1   x 2/3 =   18 / 3  = 6

Answer:

33.55

Step-by-step explanation:

Answer:

α = 33.56°  (nearest hundredth)

Step-by-step explanation:

Trigonometric ratios

[tex]\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}[/tex]

where:

Given:

As all sides of the right triangle have been given, any of the trigonometric ratios can be used to find α.

Sine Ratio

[tex]\begin{aligned}\sf \sin(\alpha) & = \sf \dfrac{\sqrt{11}}{6}\\\implies \alpha & = \sf \sin^{-1}\left(\dfrac{\sqrt{11}}{6}\right) \\& = \sf 33.55730976...^{\circ}\end{aligned}[/tex]

Cosine Ratio

[tex]\begin{aligned}\sf \cos(\alpha) & =\sf \dfrac{5}{6}\\\implies \alpha & = \sf \cos^{-1}\left(\dfrac{5}{6}\right) \\& = \sf 33.55730976...^{\circ}\end{aligned}[/tex]

Tangent Ratio

[tex]\begin{aligned}\sf \tan(\alpha) & =\sf \dfrac{\sqrt{11}}{5}\\\implies \alpha & = \sf \tan^{-1}\left(\dfrac{\sqrt{11}}{5}\right) \\& = \sf 33.55730976...^{\circ}\end{aligned}[/tex]

Therefore, α = 33.56°  (nearest hundredth)

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the average cost per class is $14.

Think of this as an algebraic equation, which would be expressed as 40+10s=total cost

The (s) would be the number of spinning classes you decide to take.

Therefore to find the average cost of the class, you would plug in 10 classes for s.

This brings the total cost to $140 dollars.

To find the average you must divide this cost by the number of classes you took.

This will be the price per class, which is $14.

Statement of the equality of two expressions formulated by way of making use of a set of variables the algebraic operations, particularly, addition, subtraction, multiplication, department, elevating to energy, and extraction of a root.

In arithmetic, an algebraic equation or polynomial equation is an equation of the form P=0 where P is a polynomial with coefficients in some area, regularly the field of rational numbers.

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[tex]f( - 1) = - 3[/tex]

[tex]f(x) = 0 \\ for \: x = 2 \: or \: x = - 2[/tex]

The equation of the perpendicular line to the given line is: y = -5/4x - 30.

The slope values of two perpendicular lines are negative reciprocal of each other.

Given that the line is perpendicular to y = 4/5x+23, the slope of y = 4/5x+23 is 4/5. Negative reciprocal of 4/5 is -5/4.

Therefore, the line that is perpendicular to it would have a slope (m) of -5/4.

Plug in m = -5/4 and (x, y) = (-40, 20) into y = mx + b to find b:

20 = -5/4(-40) + b

20 = 50 + b

20 - 50 = b

b = -30

Substitute m = -5/4 and b = -30 into y = mx + b:

y = -5/4x - 30

The equation of the perpendicular line is: y = -5/4x - 30.

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Answer:

m=months

clark= 10000-105m

lois= 7500-50m

10000-105m=7500-50m

+50m

10,000-55m=7500

-10000

-55m=-2500

simplify

55m=2500

divide by 55

m=45.45

so i would say b

Hope This Helps!!!