Mathematics High School

Find the distribution of responses about whether there was broken glass at the accident for the subjects in this study using relative frequencies

Find The Distribution Of Responses About Whether There Was Broken Glass At The Accident For The Subjects

Answers

Answer 1

Answer:

Probability of having broken glass =  0.1933

Probability of not having broken glass = 0.8067

Step-by-step explanation:

The Treatment table in the file attached to the given question is written out and completed below;

                                                  Treatment

Response       Smashed into             Hit                 Control       Total

      Yes             16                               7                        6             29

       No             34                              43                     44            121

Total:                  50                            50                     50           150

Using relative frequencies,

the distribution of responses about whether there was broken glass at the accident for the subjects in this study can be computed as follows:

Probability of having broken glass = [tex]\dfrac{29}{150}[/tex]

Probability of having broken glass =  0.1933

Probability of not having broken glass = [tex]\dfrac{121}{150 }[/tex]

Probability of not having broken glass = 0.8067

Related Questions

What is 3X to the second power plus 4X -3+ negative 4X to the second power minus 2X -4 in polynomial form

Answers

Answer:

The polynomial form of the expression is: 25·X² + 2·X + 2.

Step-by-step explanation:

The expression that can be formed using the provided data is:

[tex](3X)^{2}+(4X-3)+(-4X)^{2}-(2X-4)[/tex]

Simplify the expression to get a result in polynomial form as follows:

[tex](3X)^{2}+(4X-3)+(-4X)^{2}-(2X-4)[/tex]

[tex]=9X^{2}+4X-3+16X^{2}-2X+5\\\\=(9+16)X^{2}+(4-2)X+(5-3)\\\\=25X^{2}+2X+2[/tex]

Thus, the polynomial form of the expression is: 25·X² + 2·X + 2.

x+a=3/4 I don't know how to solve this and I need someone to help explain it to me.

Answers

I think you should Subtract
a
a
from both sides of the equation.
x=3/4-a and that’s your answer

What is 4/q as a decimal

Answers

Answer:

what is the value of q?

Step-by-step explanation:

Dose every positive real number

also have both a positive and negative cube root?

Answers

Answer:

Any real number will have only one real cube root. Hence the technicalities associated with the principal root do not apply.

Step-by-step explanation:

what should be added m(m-n) to get square ofm(m-n)
​

Answers

Answer: m²-mn

Explanation: multiply the letter outside the brackets by everything inside the brackets, so, m×m = m² and m×n = mn, altogether it is m²-mn.

If the​ cost, C​, for manufacturing x units of a certain product is given by C=x2+10x+45, find the number of units manufactured at a cost of $ 10,020.

Answers

Answer: 95 units.

Step-by-step explanation:

The cost of making x units is:

C(x) = x^2 + 10*x + 45.

Now, if the cost is $10,020, then we can solve this for x as:

C(x) = 10,020 = x^2 + 10*x + 45

x^2 + 10*x + 45 - 10,020 = 0

x^2 + 10*x - 9,975 = 0

Now, remember that for a quadratic equation:

a*x^2 + b*x + c = 0

the solutions are:

[tex]x = \frac{-b +-\sqrt{b^2 - 4*a*c} }{2*a}[/tex]

In this case the solutions are:

x = [tex]x = \frac{-10 +-\sqrt{10^2 - 4*1*(-9,975)} }{2*1} = \frac{-10 +- 200}{2}[/tex]

Then we have two solutions, one for each sign:

x = (-10 -200)/2 = -110

x = (-10 + 200)/2 = 95

Here we must choose the positive option, as x represents a positive quaintity.

Then the number of units manufactured is 95.

36. Find the circumference of a circle with a radius of 8 kilometers. Use 3.14 or for T.
37.Find the area of a circle with a diameter of 26 inches. Use 3.14 or for T.

Answers

Answer:

36. 58.34

37. 530.66

Step-by-step explanation:

36. 2x3.14x8=7.28x8=58.34

so 36=58.34

37.

3.14x26/2=3.14x13x13=530.66

please brainly

-5 - 1 =
please help me and it isnt -4

Answers

Answer:

the answer is -6

Step-by-step explanation:

if you have -5 and you take away another number, you end up with -6

Answer:

-6

Step-by-step explanation:

-5 - 1 ISNT -4

-5 + 1 IS -4

3. Given: a+b=12 and ab=9
Use (a + b)2 to find a² +bº. (Do not solve for a and b individually)

Answers

Answer:

a²+b²=126

Step-by-step explanation:

(a+b)²=a²+b²+2ab

(12)²=a²+b²+2×9

144=a²+b²+18

a²+b²=144-18=126

Owen made 60% of the shoys he attempted during his hockey practice he made 18 shots how many shots did owen attempt during hocjey pratice

Answers

he attempted 30 shots in all

Find sets of three consecutive odd integers whose sum is between 100 and 115

Answers

Answer:

33, 35, 37

Step-by-step explanation:

Consecutive: in a row

Odd: any number not evenly divisible by 2

Integers: Whole numbers

Sum: the answer to an addition problem

So, 100 is close to 30*3, so start there and move on. It has to be a little more, so start at 31, 33, and 35, but it's only 99, so you need something a little more. Check 33, 35, and 37 to be sure, and you've got your answer!

Point N is between M and R. If MN = 25 in, and NR = 12 in, then what is the length of MR?

Answers

Add MN and NR together.
25 + 12 = 37. Make sure to add the word units on the end if it’s not multiple choice.

HELP WILL GIVE BRAILEST AND WILL GIVE 50 POINTS!!!!! (also please tell me how you did it!) Simplify and Solve: 12x + 8 < 116

Answers

Answer:

Step-by-step explanation:

1. isolate the variable   subtract both sides by 8                   (12x+8-8<116-8)  

2. Divide both sides by twelve                                               (12x/12<116-8/12)                                            

3. Simplify                                                                                 (x<108/12)      

4. Answer                                                                   (x<9)                                                        

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                                                                                                                                                                                   

Step 1: Subtract 8 from both sides.

=12x+8−8<116−8

=12x<108

Step 2: Divide both sides by 12.

[tex] \frac{12x}{12} < \frac{108}{12} [/tex]

Answer

x<9

5/8-(1/4) to the 2 power

Answers

Answer:

0.5625

Step-by-step explanation:

please someone help me to prove this...​

Answers

Answer:  see proof below

Step-by-step explanation:

Use the following Power Reducing Identities:

[tex]\cos^2 A = \dfrac{1}{2}(1 + \cos 2A)\\\\\sin^2 A = \dfrac{1}{2}(1 - \cos 2A)[/tex]

Use the following Product to Sum Identity:

[tex]\cos A\cdot \cos B=\dfrac{1}{2}\bigg[\cos(A+B)+\cos(A-B)\bigg][/tex]

Proof LHS → RHS

[tex]\text{LHS:}\qquad \qquad \qquad \cos^2\beta\cdot \sin^4\beta\\.\qquad \qquad \qquad =\cos^2\beta\cdot \sin^2\beta\cdot \sin^2 \beta[/tex]

[tex]\text{Power Reducing:}\qquad \dfrac{1}{2}\bigg(1+\cos 2\beta\bigg)\dfrac{1}{2}\bigg(1-\cos 2\beta\bigg)\dfrac{1}{2}\bigg(1-\cos 2\beta\bigg)\\\\\\.\qquad \qquad \qquad \quad =\dfrac{1}{8}(1+\cos 2\beta)(1-\cos 2\beta)(1-\cos 2\beta)[/tex]

[tex]\text{Expand:}\qquad \qquad \dfrac{1}{8}\bigg(1-\cos 2\beta-\cos^2 2\beta+\cos^3 2\beta\bigg)\\\\.\qquad \qquad \qquad =\dfrac{1}{8}\bigg(1-\cos 2\beta-\cos^2 2\beta+\cos^2 2\beta \cdot \cos \2\beta\bigg)[/tex]

[tex]\text{Power Reducing:}\qquad \dfrac{1}{8}\bigg(1-\cos 2\beta -\dfrac{1}{2}(1+\cos 4\beta)+\dfrac{1}{2}(1+\cos 4\beta)\cos 2\beta\bigg)\\\\.\qquad \qquad \qquad =\dfrac{1}{16}\bigg(2-2\cos 2\beta -1-\cos 4\beta +\cos 2\beta +\cos 4\beta \cdot \cos 2\beta \bigg)\\\\.\qquad \qquad \qquad =\dfrac{1}{16}\bigg(1-\cos 2\beta -\cos 4\beta+\cos 4\beta \cdot \cos 2\beta \bigg)[/tex]

[tex]\text{Product to Sum:}\quad \dfrac{1}{16}\bigg(1-\cos 2\beta -\cos 4\beta +\dfrac{1}{2}[\cos(4\beta+2\beta)+\cos (4\beta-2\beta)]\bigg)\\\\.\qquad \qquad \qquad =\dfrac{1}{32}\bigg(2-2\cos 2\beta -2\cos 4\beta +\cos 6\beta +\cos 2\beta\bigg)\\\\.\qquad \qquad \qquad =\dfrac{1}{32}\bigg(\cos 6\beta-2\cos 4\beta -\cos 2\beta +2 \bigg)[/tex]

[tex]\text{LHS=RHS:}\\ \dfrac{1}{32}\bigg(\cos 6\beta-2\cos 4\beta -\cos 2\beta +2 \bigg)=\dfrac{1}{32}\bigg(\cos 6\beta-2\cos 4\beta -\cos 2\beta +2 \bigg)[/tex]

Select the correct answer.
Which graph represents the solution to this inequality?
-(127 + 8) < -21 + 11
OA. tt
-17
-15
-13
-11
-9
7
-5
+
-17
- 15
- 13
-11
-9
-7
-5
Oc.
+
-17
- 15
-13
- 11
-9
7
-5
C
-17
-15 -13
-11
-9
-7
-5

Answers

Answer:

C

Step-by-step explanation:

Given

- [tex]\frac{1}{4}[/tex] (12x + 8) ≤ - 2x + 11 ← distribute parenthesis on left side

- 3x - 2 ≤ - 2x + 11 ( add 3x to both sides )

- 2 ≤ x + 11 ( subtract 11 from both sides )

- 13 ≤ x , thus

x ≥ - 13

Since x can equal - 13 then a solid circle at - 13 represents the solution

Since x greater than - 13 then the arrow is facing to the right of - 13 on the number line.

Then the graph representing the solution is C

Can someone please help to explain this?

Answers

Answer:

[tex]\frac{PQ}{DE}[/tex] = [tex]\frac{4}{6}[/tex]

Step-by-step explanation:

Given

Δ PQR ~ Δ DEF

Then the ratio of corresponding sides are equal

The corresponding letters in the names of the triangles gives the corresponding sides.

Thus PQ/DE, QR/EF, PQ/DF

In this case

[tex]\frac{PQ}{DE}[/tex] = [tex]\frac{4}{6}[/tex]

If m 8 =22, m 7=31, and m EAD=102 find m 9

Answers

S is the answer

Step-by-step explanation:

Let 3+4+8+9+13+14+18+___ 40 terms=S

A farmland is 30cm long and 15cm wild what is the area of the farmland

Answers

The answer is 450cm

Marco arranged the tiles in this way, and then wrote an expression based on his arrangement. What expression do you think Marco might have written?

Answers

Answer: 2(2a+b)^2

Step-by-step explanation:

4a+2b then squared which doubles it

unit rate 232 miles in 4 hours​

Answers

Answer:

58 miles per hour

Step-by-step explanation:

leave a heart please :D

The world's largest ocean, the Pacific ocean, has an area of about 200,000,000 km^(2) , which can be written as 2 x 10 ^(n) km^(2). What is n?​

Answers

n=8. All you have to do is count the amount of numbers after the 2 in 200,000,000. There are 8 numbers after the number 2 which makes n=8.

Answer:

n = 8

Step-by-step explanation:

:)

what is 3,393 divided by 13

Answers

Answer:

261

I hope this helps!

Suppose you have 20 coins that total $3.00. Some coins are nickels and some are quarters. Which of the following pairs of equations would you use to find out how many of each coin you have?

Answers

Answer:

Step-by-step explanation:

n + q = 20

.05n + .25q = 3.00

5n + 25q = 300

 n + q = 20

5n + 25q = 300

-5n - 5q = -100

20q = 200

q = 10 quarters

n + 10 = 20

n = 10 nickels

(10 nickels, 10 quarters)

The amount of water in reservoirs is often measured in acre-ft. One acre-ft is a volume that covers an area of one acre to a depth of one foot. An acre is 43,560 ft2. Find the volume in SI units of a reservoir containing 46.0 acre-ft of water.

Answers

Answer:

56740.15908m³

Approximately to the nearest whole number, the volume of 46 acre-ft of reservoir = 56740m³

Step-by-step explanation:

1 meter = 3.28084ft

1 acre = 43,560 ft²

Therefore, using our unit conversion, the volume in S.I units of a reservoir containing 46 acre- ft of water is calculated as :

46 acre - ft × (1 meter/3.28084ft) × (43,560ft²/1 acre) × (1 meter/3.28084ft)²

= 2003760/35.314670112

= 56740.15908m³

Approximately to the nearest whole number, the volume of 46 acre-ft of reservoir = 56740m³

Solve for a. 2z=4a/m +3

Answers

Answer:

               a = (2mz - 3m)/4

Step-by-step explanation:

2z = 4a/m +3

 -3        -3

2z - 3 = 4a/m

 ×m        ×m

(2z -3)m = 4a

     ÷4      ÷4

[(2z -3)m]/4 = a

a = (2mz - 3m)/4

i need help finding the range​

Answers

Answer:

I think it's -1, 4. But i'm not a 100% sure.

Step-by-step explanation:

Answer:

To find the range, first order the data from least to greatest. Then subtract the smallest value from the largest value in the set.

Step-by-step explanation:

This is how you solve for Range; I can't view the image on my chromebook.

what is the constant for -9x^3+12p+6

Answers

6 is the constant in that equation. The answer is 6 because it is the only number that is not attached to a variable.

A constant is any numbers in an equation that don't have any variable connected to it.

-9x^3 and 12p are not constants since they are connected to variables.

6 is a constant because its not connected to any variable.

Best of Luck!


The level of various substances in the
blood influences our health. Here are
measurements of the level of phosphate
in the blood of a patient, in milligrams of
phosphate per deciliter of blood, made
on 6 consecutive visits to the clinic:
5.6, 5.2, 4.6, 4.9, 5.7, 6.4
What is the standard deviation for these
data?
A. .642
B. 5.4
O. 32.4
D. 177.02

Answers

Answer:

A

Step-by-step explanation:

Mr. Green's lawn mower holds 600 milliliters of gasoline in the tank. He just filled his 6 liter gas can at the station. How many times will he be able to fill his lawn mower tank from the gas can?

Answers

Answer:

10 times.

Step-by-step explanation:

Since 1 liter = 1000 milliliters, we can say that 600 milliliters is equal to 0.6 liters because 600/1000 = 0.6

Since the gas can holds 6 liters, and the lawn mower holds 0.6 liters, 6/0.6 = 10.

So, he can fill his lawn mower 10 times with the gas can

Mr Green can fill his lawn 10 times

the first step is to convert the milliliters to liters

600 milliliters to liters

= 600/1000

= 0.6 liters

the number of times can be calculated as follows

= 6/0.6

= 10

hence it will take Mr. Green  10 times to fill his lawn mower

please see the link below for more information

https://brainly.com/question/632986?referrer=searchResults

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