Exactly how many -OH groups are found in a 6 carbon alditol?

Answer:

bonded

Explanation:

Compounds are two elements bonded together.

A mixture is multiple substances blended together.  The substances aren't bonded together and can easily be extracted  from each other.

Answer:

oxygen and Carbon dioxide

Answer:

A. 313.37 g of H3BO3.

B. 30.33 g of H2.

Explanation:

We'll begin by writing a balanced equation for the reaction. This is given below:

B2H6 + 6H2O → 2H3BO3 + 6H2

Next, we shall determine the mass of B2H6 that reacted and the masses of H3BO3 and H2 produced from the balanced equation equation. This can be obtained as follow:

Molar mass of B2H6 = (2×11) + (1×6) = 22 + 6 = 28 g/mol

Mass of B2H6 from the balanced equation = 1 × 28 = 28 g

Molar mass of H3BO3 = (1×3) + 11 + (3×16) = 3 + 11 + 48 = 62 g/mol

Mass of H3BO3 from the balanced equation = 2 × 62 = 124 g

Molar mass of H2 = 2×1 = 2 g/mol

Mass of H2 from the balanced equation = 6 × 2 = 12 g

From the balanced equation above:

28 g of B2H6 reacted to produce 124 g of H3BO3 and 12 g of H2.

A. Determination of the mass of H3BO3 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

28 g of B2H6 reacted to produce 124 g of H3BO3.

Therefore, 70.76 g of B2H6 will react to produce = (70.76 × 124)/28 = 313.37 g of H3BO3.

Therefore, 313.37 g of H3BO3 were obtained from the reaction.

B. Determination of the mass of H2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

28 g of B2H6 reacted to produce 12 g of H2.

Therefore, 70.76 g of B2H6 will react to produce = ((70.76 × 12)/28 = 30.33 g of H2.

Therefore, 30.33 g of H2 were obtained from the reaction.

Answer:

its the stamen, it also supports the Anther.

Answer:

The Stamen

Explanation:

The stamen is a slender filament supporting the anther, it is what produces and holds pollen in flowers.

Answer:

0.09865M of NaOH

Explanation:

As a diprotic acid, 1 mole of oxalic acid reacts with 2 moles of NaOH as follows:

H2C2O4 + 2 NaOH → 2 H2O + Na2C2O4

With the mass of the acid and its molar mass we can obtain the moles of oxalic acid. Twice these moles are the moles of NaOH in the solution. As you required 23.64mL = 0.02364L of the NaOH, you can knkow molarity, thus:

Moles Oxalic acid:

0.147g * (1mol / 126.07g) = 1.166x10⁻³ moles Oxalic acid.

Moles NaOH:

1.166x10⁻³ moles Oxalic acid * (2 moles NaOH / 1 mole H2C2O4) = 2.332x10⁻³ moles NaOH

Molarity:

2.332x10⁻³ moles NaOH / 0.02364L =

Answer:

B. H2CO3 and KHCO3

Explanation:

The buffer system is a system in which the solution deny for change in the ph level i.e. at the time when the acid is added to it. It can be made either in a weak acid and salt or can be a weak base and its salt. Now when the acid is added to a buffer so the ratio is not impacted due to which it does not change sufficient for pH level

As per the given options, the third one is correct as the H2CO3 denotes a weak acid and the KHCO3 represents the salt. And these two solution does not create any change in the level of pH

Therefore the option B is correct

Answer:

Approximately [tex]0.291\; \rm M[/tex] (rounded to two significant figures.)

Explanation:

The unit of concentration [tex]\rm M[/tex] is the same as [tex]\rm mol \cdot L^{-1}[/tex] (moles per liter.) On the other hand, the volume of both the [tex]\rm NaOH[/tex] solution and the original [tex]\rm HCl[/tex] solution here are in milliliters. Convert these two volumes to liters:

Calculate the number of moles of [tex]\rm NaOH[/tex] in that [tex]0.0182\; \rm L[/tex] of [tex]0.160\; \rm M[/tex] solution:

[tex]\begin{aligned} n(\mathrm{NaOH}) &= c(\mathrm{NaOH})\cdot V(\mathrm{NaOH})\\ &= 0.160\; \rm mol \cdot L^{-1} \times 0.0182\; \rm L \approx 0.00291\; \rm mol\end{aligned}[/tex].

[tex]\rm HCl[/tex] reacts with [tex]\rm NaOH[/tex] at a one-to-one ratio:

[tex]\rm HCl\; (aq) + NaOH\; (aq) \to NaCl\; (aq) + H_2O\; (l)[/tex].

Coefficient ratio:

[tex]\displaystyle \frac{n(\mathrm{HCl})}{n(\mathrm{NaOH})} = 1[/tex].

In other words, one mole of [tex]\rm NaOH[/tex] would neutralize exactly one mole of [tex]\rm HCl[/tex]. In this titration, [tex]0.291\; \rm mol[/tex] of [tex]\rm NaOH\![/tex] was required. Therefore, the same amount of [tex]\rm HC[/tex] should be present in the original solution:

[tex]\begin{aligned}&n(\text{$\mathrm{HCl}$, original})\\ &= n(\mathrm{NaOH})\cdot \frac{n(\mathrm{HCl})}{n(\mathrm{NaOH})} \\ &\approx 0.00291\; \rm mol \times 1 = 0.00291\; \rm mol\end{aligned}[/tex].

Calculate the concentration of the original [tex]\rm HCl[/tex] solution:

[tex]\displaystyle c(\text{$\mathrm{HCl}$, original}) = \frac{n(\text{$\mathrm{HCl}$, original})}{V(\text{$\mathrm{HCl}$, original})} \approx \frac{0.00291\; \rm mol}{0.0100\; \rm L} \approx 0.291\; \rm M[/tex].

Answer:

The equilibrium will shift to the right producing more Ag⁺ and CO₃²⁻

Explanation:

In the equilibrium:

Ag₂CO₃(s) ⇄ 2Ag⁺(aq) + CO₃²⁻(aq)

The change in concentration of Ag⁺ or CO₃²⁻ will shift the equilibrium

The addition of HCl(aq) (Dissociates in H⁺ and Cl⁻ ions) produce the formation of AgCl. The reaction is:

Ag⁺(aq) + Cl⁻(aq) ⇄ AgCl(s)

That means the addition of HCl decrease concentration of Ag⁺.

Based on LeChatelier's principle: As the Ag⁺ decreases, the equilibrium will decrease amount of Ag₂CO₃ producing more Ag⁺ and CO₃²⁻. That is:

Answer:

one mole of water contains 6.02 x 1023 MOLECULES of water.

But each molecule of water contains 2 H and 1 O atom = 3 atoms, so there are approximately 1.8 x 1024 atoms in a mole of water.

Explanation:

hope it helps you paigegeorge

Lol . same here. If u get any ideas please let me know

Answer:

See the picture you have to write like this

Answer:

B. Fluids

I hope this helps!

Answer:

B

Explanation:

Answer:

We have the final answer as

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

[tex]volume = \frac{mass}{density} \\[/tex]

From the question

mass = 6 g

density = 6 g/cm³

It's volume is

[tex]volume = \frac{6}{6} = 1 \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

Explanation:

Pellet form of NaOH is highly hygroscopic . It absorbs moisture from air and its weight is increased by the time one tries to weigh one gram of it . Moreover it also reacts with carbon dioxide gas of atmosphere to form sodium carbonate .

2 NaOH + CO₂ = Na₂CO₃ + H₂0.

It also increases its weight .

Answer:

2.6 kJ/mol

Explanation:

Step 1: Given data

Step 2: Calculate ΔG°

We can calculate ΔG° using the following expression.

ΔG° = ΔH° - T × ΔS°

ΔG° = 40.7 kJ/mol - 350 K × 0.109 kJ/mol.K

ΔG° = 2.6 kJ/mol

The change in Gibbs free energy, ΔG for the water is 2.55 KJ/mol

From the question given above, the following data were obtained:

The Gibbs free energy, ΔG° can be obtained as illustrated below:

ΔG° = ΔH° – TΔS°

ΔG° = 40.7 – (350 × 0.109)

ΔG° = 40.7 – 38.15

ΔG° = 2.55 KJ/mol

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Answer: NH4)2CO3

Explanation:

Ionic solids are the solids that are simply held together by ionic bonds. Ionic bonds are lattices that are typically made up of oppositely charged ions and they usually possess a high melting point.

An example of ionic bond is NH₄)₂CO₃ which is referred to as Ammonium carbonate. This is a salt and it readily degrades upon heating to carbon dioxide and gaseous ammonia.

The shape and function of a protein are primarily determined by its three-dimensional structure, which is a result of its primary, secondary, tertiary, and quaternary structures.

Primary Structure: The primary structure of a protein is the linear sequence of amino acids that make up the polypeptide chain. The sequence is dictated by the genetic information encoded in the DNA of the gene that corresponds to the protein. Each amino acid in the sequence is represented by a specific codon in the DNA, and this sequence of amino acids forms the backbone of the protein.

Secondary Structure: The secondary structure refers to the local spatial arrangement of the polypeptide backbone, which is stabilized by hydrogen bonds between amino acids. The two most common secondary structures are alpha-helices and beta-sheets. These structures are important for the stability and folding of the protein.

Tertiary Structure: The tertiary structure is the three-dimensional folding of the entire polypeptide chain, including the secondary structure elements. Various interactions, such as hydrogen bonds, disulfide bridges, ionic interactions, hydrophobic interactions, and van der Waals forces, play a crucial role in stabilizing the tertiary structure. This folding brings distant parts of the polypeptide chain close together, contributing to the unique shape of the protein.

Quaternary Structure: Some proteins are composed of multiple polypeptide subunits, and the way these subunits come together forms the quaternary structure of the protein. The interactions between the individual subunits contribute to the overall structure and function of the complex protein assembly.

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Answer:

4.54x10^-19 J

1.99x10^-25 J

1.93 x 10^-48 J

Answer:

Explanation:

Rivers may be contaminated by sewage.

I do hope I helped you! :)

Answer:

The option D is correct answer.

Decaying pants and animals are important to the ecosystem as they return the nutrients to the soil.

Ecosystem is defined as a system which consists of all living organisms  and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles  and flow of energy.

Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .Living organisms also influence the quantity of biomass present.By decomposition of dead plants and animals by microbes nutrients are released back in to the soil.

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Answer:

the answer is D

Explanation:

Answer:

the protection one

Explanation:

the cell wall acts a barrier

Answer:

Division by zero is undefined because there is no other number to divide it by.

Explanation:

Unlike 2/2, 2/0 doesn't have anything to divide the 2 by which makes it undefined and impossible to solve.

The division by zero is undefined​, because whatever response we may give, we will then have to concur that the answer times 0 = 1, which is illogical because anything multiplied by zero is zero.

Since any attempt at definition results in a contradiction, the outcome of a division by zero cannot be defined. a=r*b. r*0=a. (1) (1) But because r*0=0 for all r, there is no solution to the equation unless a=0 (1).

Again, mathematicians have left zero divided by zero as an open problem because they are both equally valid and, to be honest, neither of them is consistent with the rest of mathematics.

Mathematically, it is impossible to divide a number by zero, just as in this illustration. Or, at the very least, there isn't currently a means to do that. Numerous attempts have been made to figure out how to divide by zero, as mathematicians are constantly looking for solutions to intriguing mathematical issues.

Thus, The division by zero is undefined​, because whatever response we may give, we will then have to concur that the answer times 0 = 1.

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Answer:

194.569 g

Explanation:

6.022×10^23 molecules = 117.17 g

1 molecules = 117.17/ 6.022×10^23

So, 1×10^24 molecules = (117.17×1×10^24)/(6.022×10^23)= 194.569 g

Complete question is;

A pure copper penny contains approximately 2.9 × 10^(22) copper atoms.

1 doz = 12

1 gross = 144

1 ream = 500

1 mol = 6.022 × 10^(23)

Use these definitions to determine the following:

A) How many dozens of copper atoms are in a penny.

B) How many gross of copper atoms are in a penny

C) How many reams of copper atoms are in a penny.

D) how many moles of copper atoms are in a penny?

All answers can be rounded to two significant figures

Answer:

A) 2.4 × 10^(21) dozens

B) 2.01 × 10^(20) gross

C) 5.8 × 10^(19) reams

D) 0.048 mol

Explanation:

A) A dozen contains 12.

Therefore, 2.9 × 10^(22) copper atoms will contain;

(2.9 × 10^(22))/12 dozens = 2.42 × 10^(21).

In 2 significant figures, we have;

2.4 × 10^(21) dozens

B) 1 gross = 144

Therefore, 2.9 × 10^(22) copper atoms will contain;

(2.9 × 10^(22))/144 gross ≈ 2.01 × 10^(20) gross

C) 1 ream = 500

Therefore, 2.9 × 10^(22) copper atoms will contain;

(2.9 × 10^(22))/500 reams = 5.8 × 10^(19) reams

D) 1 mol = 6.022 × 10^(23)

Therefore, 2.9 × 10^(22) copper atoms will contain;

(2.9 × 10^(22))/(6.022 × 10^(23)) = 0.048 mol

R= 1155×100/6000×3/12

R= 1155×2/3

Answer:

[tex]m=173.58g[/tex]

Explanation:

Hello,

In this case, since the density is the ratio of the mass and volume:

[tex]\rho =\frac{m}{V}[/tex]

For the given density and volume, the correct mass which fills the given volume is:

[tex]m=\rho *V=0.789g/mL*220mL\\\\m=173.58g[/tex]

Best regards.

Answer:

Analytical science

Explanation:

Answer:

the answers are at the very bottom of each picture

Explanation:

i really hope this helps you:)