Determine an equivalent expression by rationalizing the denominator: (5√3)/(4-√6)

Answers

Answer 1

Step-by-step explanation:

so when you want to rationalize the denominator when it's in the form [tex](a-\sqrt{b})[/tex] you multiply by the conjugate which is [tex](a+\sqrt{b})[/tex] which is where the sign is the opposite. This is because it's using the difference of squares to get rid of the square root. Because [tex](a-b)(a+b) = a^2-b^2[/tex] this will remove the square root since it's going to become square and the ab - ab will cancel so there will be no square root

Multiply by conjugate

[tex]\frac{5\sqrt3}{4-\sqrt6} * \frac{4+\sqrt6}{4+\sqrt6}\\[/tex]

Simplify:

[tex]\frac{20\sqrt{3} + 5\sqrt{6 * 3}}{16-6}[/tex]

Simplify radical

[tex]\frac{20\sqrt{3} + 15\sqrt{2}}{10}\\[/tex]

You could go further and do

[tex]2\sqrt{3} + 1.5\sqrt{2}[/tex]


Related Questions

Find the first five terms of the sequence described:
a sub 1 = 3
a sub n+1 = a sub n + 5

Answers

From the given recursive definition,

[tex]a_1 = 3[/tex]

[tex]a_2 = a_1 + 5 = 3 + 5 = 8[/tex]

[tex]a_3 = a_2 + 5 = 8 + 5 = 13[/tex]

[tex]a_4 = a_3 + 5 = 13 + 5 = 18[/tex]

[tex]a_5 = a_4 + 5 = 18 + 5 = 23[/tex]

Which expression is equivalent to the following complex fraction? StartFraction 2 Over x EndFraction minus StartFraction 4 Over y EndFraction divided by StartFraction negative 5 Over y EndFraction + StartFraction 3 Over x EndFraction StartFraction 3 y + 5 x Over 2 (y minus 2 x) EndFraction StartFraction 2 (y minus 2 x) Over 3 y minus 5 x EndFraction StartFraction 2 (y minus 2 x) (3 y minus 5 x) Over x squared y squared EndFraction StartFraction x squared y squared Over 2 (y minus 2 x) (3 y minus 5 x) EndFraction

Answers

The equivalent expression of [tex]\frac{\frac 2x - \frac 4y}{-\frac 5y + \frac 3x}[/tex] is [tex]\frac {2(y - 2x)}{ 3y-5x}[/tex]

How to determine the equivalent expression?

The complete question is in the attached image

We have:

[tex]\frac{\frac 2x - \frac 4y}{-\frac 5y + \frac 3x}[/tex]

Take the LCM

[tex]\frac{\frac {2y - 4x}{xy}}{\frac{-5x + 3y}{xy}}[/tex]

Divide through by xy

[tex]\frac {2y - 4x}{-5x + 3y}[/tex]

Rewrite as:

[tex]\frac {2y - 4x}{ 3y-5x}[/tex]

Factor out 2

[tex]\frac {2(y - 2x)}{ 3y-5x}[/tex]

Hence, the equivalent expression of [tex]\frac{\frac 2x - \frac 4y}{-\frac 5y + \frac 3x}[/tex] is [tex]\frac {2(y - 2x)}{ 3y-5x}[/tex]

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A beauty supply store surveyed 1,000 customers to determine which of 3 brands of concealer they like the best. 335 customers chose Brand A, 402 customers chose Brand B, while 263 customers chose Brand C. What percent of customers chose Brand B? Round off your answer to the nearest tenths place.

Answers

40.2 percent of the customers at the beauty supply store choose brand B.

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

The percent of customers that choose brand B = (number of  brand B customers / total number of customers) * 100%

The percent of customers that choose brand B = (402/1000) * 100% = 40.2%

40.2 percent of the customers at the beauty supply store choose brand B.

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You are the coordinator for a program that is going to take place at night in a rectangular amphitheater in the mountains. You will have no access to any electricity, but you must be able to illuminate the entire grounds. You know the intensity of the light from a lantern varies inversely as the square of the distance from the lantern. Suppose the intensity is 90 when the distance is 5 m.

a. Write an equation to model the situation.
b. Solve for the constant of variation.
c. Write the equation to model the situation using the constant () of variation.
d. You have been given lanterns with 40 light intensity. Use your equation to solve for the distance from the lantern.
e. You need to illuminate 225 km. How many meters do you need to light?
f. How many lanterns will you need?

Answers

The equation to model the situation is [tex]\mathbf{y = \dfrac{k}{x^2}}[/tex]. The constant for the variation is 2250.

What is the intensity of light?

The intensity of light from a lantern varies inversely to the square of the distance from the lantern.

From the given information:

Let y be the intensity of light, andx be the distance from the lantern

Then:

[tex]\mathbf{y \alpha \dfrac{1}{x^2} }[/tex]

[tex]\mathbf{y = \dfrac{k}{x^2} }[/tex]   here, k = constant.

2.

If y = 90 W/m² when the distance x = 5m

Then:

[tex]\mathbf{90 = \dfrac{k}{(5)^2}}[/tex]

k = 90 × 25

k = 2250

c.

The equation to model the situation by using the constant variation is:

[tex]\mathbf{y = \dfrac{2250}{x^2}}[/tex]

d.

If the light intensity y = 40, then x is determined as:

[tex]\mathbf{40 = \dfrac{2250}{x^2}}[/tex]

[tex]\mathbf{x = \sqrt{\dfrac{2250}{40}}}[/tex]

x = 7.5 m

e.

The light is needed in (225 × 1000)m = 225000 km of illumination.

f.

The lantern required for the new light estimation is:

y = 2250/225000

y = 0.01 intensity

Therefore, we can conclude that to get an intensity of 1 W/m², we need to put 100 lanterns.

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Classify the following triangle. Check all that apply.
11.3
45
A. Scalene
B. Right
C. Isosceles
D. Acute
E. Equilateral
F. Obtuse

Answers

Answer:

It's A and C

Step-by-step explanation:

the angles are 45, which is less than 90

Math HELP!!! 100PTS!!!

Sketch the region given by the set {(x,y)|xy<0} on a piece of paper. Which quadrants of the plane are included in the set? Input Yes or No at the corresponding space below:
quadrant 1:
quadrant 2:
quadrant 3:
quadrant 4:

Answers

Answer:

Quadrants 1 and 4 EDIT: Quadrants 2 & 4

Step-by-step explanation:

Quadrant 1  : Edit: no

Quadrant 2  : Edit: yes

Quadrant 3 : No

Quadrant 4 : Yes

The length of one side of a triangle is 2 feet less than three times the length of its second side. The length of the third side is 3/4
of the sum of the lengths of the first two sides. Find the lengths of all three sides if the perimeter of the triangle is 17.5 feet.


P=17.5 feet

Answers

Using a system of equations, it is found that the lengths of the sides of the triangle are given as follows:

0.91 feet, 0.73 feet, 1.23 feet.

What is a system of equations?

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are the lengths, given by x, y and z.

The length of one side of a triangle is 2 feet less than three times the length of its second side, hence:

y = 3x - 2.

The length of the third side is 3/4 of the sum of the lengths of the first two sides, hence:

[tex]z = \frac{3(x + y)}{4} = \frac{3(4x - 2)}{4}[/tex]

The perimeter of the triangle is 17.5 feet, hence:

[tex]x + y + z = 17.5[/tex]

[tex]x + 3x - 2 + \frac{3(4x - 2)}{4} = 17.5[/tex]

[tex]4x + \frac{3(4x - 2)}{4} = 19.5[/tex]

[tex]16x + 12x = 25.5[/tex]

x = 25.5/28

x = 0.91.

Then the other sides are:

y = 3x - 2 = 3(0.91) - 2 = 0.73 feet.[tex]z = \frac{3(4 x 0.91 - 2)}{4} = 1.23 feet[/tex]

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Please help ill give whoever answers the best the brainliest answer :0

Answers

Answer: Exponential

Step-by-step explanation:

Because every time x increases by 1, y increases by a factor of 3.

6/2 = 3

18/6 = 3

54/18 = 3

162/54 = 3

P.S.: I ANSWERED ONE OF YOUR PROBLEMS WITH EXACTLY THE DATA IN THIS TABLE BY COINCIDENCE HAHA

A princess has two pet dragons. The dragons can eat 300kg of chocolate in 12 days. How many DAYS will the same 300kg last if got 4 more dragons for her birthday?

Answers

The chocolate will last for 1 day, if she gets 4 more dragons

How to determine the number of days?

The expression can be represented using the following ratio:

Ratio = Dragons : Days : Chocolate

For the 2 dragons she has, we have:

Ratio = 2 : 12 : 300

When she gets 4 more dragons, we have:

Ratio = 6 : days : 300

Equate both ratios

6 : days = 12 : 2

Express as fraction

days/6 = 2/12

Multiply both sides by 6

days = 6 * 2/12

Evaluate

days = 1

Hence, the chocolate will last for 1 day

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3. (05.02 LC)
The lengths of two sides of a triangle are 14 inches and 4 inches. Which of the following dimensions is the third side of this triangle? (5 points)
10 inches
O11 inches
O 8 inches
O9 inches

Answers

The answer of this is 0 8 inches

A snail moves at about 3 inches per minute. How many miles per day could a
snail travel if it moved without taking a break?

0.068 mi
0.818 mi
9.818 mi
132 mi

Answers

Answer:

A. 0.068

Step-by-step explanation:

First, 3 inches to miles. 3 inches in a mile is 0.00004735.

The snail moves 0.00004735 miles per minute.

Next, search how many minutes are there in a day. There is 1440 minutes in a day.

Multiply the 1440 and 0.00004735.

1440*0.00004735=0.068

The snail can move 0.068 miles per day if it doesn't take a break.

Hope this helps!

If not, I am sorry.

For the upcoming parade, Lauren needed to make her school's triangular flag into a larger, similar triangular flag. Using the information given, determine which (if any) similarity postulate she used in making her school's new flag.

Answers

In order to make the new flag, Lauren decided to triple the sides of the old flag in order to get a new one.

What is the difference between these triangles

The old triangle is the smaller one. We can see that this triangle has increased by a factor of 3 on all sides.

We have 4 x 3= 12

2 x 3 = 6

7 x 3 = 21

The calculated values above is what produced the new larger flag.

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A store sells 3 categories of kitchen items: cups, bowls, and spoons. There are 5 typess of cups. 4 types of bowls, and 2 types of spoons. How many different combinations can you buy in this store of: A set of objects fom two different categories?

Answers

You can by 24 combinations of items from the store

How to determine the number of combination?

The given parameters are:

Cups = 3

Bowl = 4

Spoon = 2

The number of combination is:

Combination = Cups * Bowl * Spoon

So, we have:

Combination = 3 * 4 * 2

Evaluate

Combination = 24

Hence, you can by 24 combinations of items from the store

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CCAT Numerical Sample Question
A home appliance store has recently seen an increase in TV sales. Having noticed this, the
store manager decides to raise the TV price by 25% in order to increase the store's profits.
If the original price of a TV was 140$, how many could be bought post-raise for 4,200$?

Answers

Answer:

24

Step-by-step explanation:

140 times .25 = 35

140 + 35 = 175

4,200 divided by 175 =

24

jobtestprep

The number of TV bought post-raise for $4,200 is 24 if the store manager decides to raise the TV price by 25% in order to increase the store's profits.

What is the percentage?

It's the ratio of two integers stated as a fraction of a hundred parts. It is a metric for comparing two sets of data, and it is expressed as a percentage using the percent symbol.

We have:

A home appliance store has recently seen an increase in TV sales.

The store manager decides to raise the TV price by 25% in order to increase the store's profits.

Original price of TV = $140

Price after increasing:

= 140 + 25% of 140

= $175

The number of TV bought post-raise for $4,200 = 4200/175

= 24

Thus, the number of TV bought post-raise for $4,200 is 24 if the store manager decides to raise the TV price by 25% in order to increase the store's profits.

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At noon, Bradley began steadily increasing the
speed of his car by 2 miles per hour every minute. At 12:15 p.m., he realized he was going
15 miles per hour over the speed limit. If his speed at noon was 40 miles per hour, what was the speed limit at 12:15 p.m.?

Please show work step by step

Answers

Answer:

25.5 mph

Step-by-step explanation:

So Bradley's speed can be modeled by the equation y=2x+40 where y=speed, x=time in hours after noon, and b=initial speed

So 12:15 is 15 minutes after noon, which is also 0.25 or 1/4 of an hour after noon. This is the x-value. Plug this into the equation to get his speed at 12:15

y=2(0.25)+40

y=0.5+40

y=40.5

So his speed was 40.5 at the time and since he was going 15 miles over the speed limit, the speed limit is 15 less than his speed

40.5 - 15 = 25.5

Answer:

25.5 mph

Step-by-step explanation:

Given information:

Bradley increases the speed of his car by 2 miles per hour.  12.00 pm: Bradley's speed = 40 mph12.15 pm: Bradley is driving at 15 miles over the speed limit.

Calculate Bradley's speed at 12.15 pm:

60 minutes = 1 hour

⇒ 15 minutes = 1/4 hour

⇒ speed at 12.15 pm = speed at 12.00pm + 1/4 of 2 mph

                                  = 40 mph + 0.5 mph

                                  = 40.5 mph

If he was 15 miles over the speed limit at 12.15 pm then:

⇒ speed limit = speed at 12.15pm - miles over the limit

                       = 40.5 mph - 15

                       = 25.5 mph

Therefore, the speed limit was 25.5 mph.

What are the x-intercepts for the graph below?
A. (6,0), (-3,0)
B. (-6,0), (-3,0)
C. (-6,0), (3, 0)
OD. (6,0), (3, 0)

Answers

Answer:

-6,0 & -3,0

Step-by-step explanation:

B. (-6,0), (-3,0)

because both of the x intercepts are to the left of the origin (0,0).

HELP HELP HELP HELP

HELP HELP HELP HELP

HELP HELP HELP HELP

HELP HELP HELP HELP

Answers

Answer:

19 inches

Step-by-step explanation:

So the perimeter of a triangle is the sum of the three sides. So the perimeter is [tex]\sqrt{65} + \sqrt{35} + \sqrt{26}[/tex] which is approximately 19.077 inches but in this case the answer is 19 inches

Using a significance level of 5%, the appropriate conclusion for a test with a p-value of 0.0421 would be:

Answers

A significance level of 5% (more commonly referred to as 95%) corresponds to a statement that (only) a probability of 5% or less is that a particular randomly generated observation is accepted as significant.

In this example, the p-level (the true probability that the observations are randomly generated) is less than 5% (0.0421 <0.05), so we can draw the conclusion that the observations are significant.

p = 0.0421 means that the probability is only 0421/1000. The choice of significance level to reject the null hypothesis is optional. Traditionally, 5%, 1%, and 0.1% levels have been used. In rare situations, a 10% significance level is also used.

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i need help asapp...

Answers

The value of b is -16 and the value of ac is 60 after comparing with the standard equation.

What is a quadratic equation?

Any equation of the form [tex]\rm ax^2+bx+c=0[/tex] where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

As we know, the formula for the roots of the quadratic equation is given by:

[tex]\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}[/tex]

We have a quadratic function:

= 3x² - 16x + 20

On comparing with standard function:

b = -16

a = 3

c = 20

ac = 3(20) = 60

Thus, the value of b is -16 and the value of ac is 60 after comparing with the standard equation.

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An american tourist changed us $1100 into barbados currency at the exchange rate us $1.00= bbd=$5.50. calculate the amount of bbd he received.

Answers

The amount of bbd received for the given currency exchange rate is 6050  bbd.

What is the currency exchange rate?

The value of one country's currency in relation to the currencies of other countries or economic zones is known as the currency exchange rate.

The majority of currency exchange rates are free-floating and fluctuate according to market supply and demand.

There may be restrictions on some currency exchange rates since they are fixed to the value of other currencies.

According to the question,

Currency exchange rate: $1.00=5.50bbd

So, $1100=1100*5.50 bbd

               =6050 bbd

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Use π = 3
Calculate the area of a circle with
diameter
of 5cm

Answers

Answer:

18.75

Step-by-step explanation:

[tex]Area=\pi r^{2} \\Area=3(\frac{5}{2} )^{2} \\Area=18.75[/tex]

Write the ratio of sin X and cos X
Show your work

(20 points)

Answers

Answer:

see explanation

Step-by-step explanation:

sinX = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{YZ}{XY}[/tex] = [tex]\frac{\sqrt{119} }{12}[/tex]

cosX = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{XZ}{XY}[/tex] = [tex]\frac{5}{12}[/tex]

This is quadratic equations
Help asap!!

Answers

Answer:

x = - 3 ± [tex]\sqrt{2}[/tex]

Step-by-step explanation:

x² + 6x + 7 = 0 ( subtract 7 from both sides )

x² + 6x = - 7

using the method of completing the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(3)x + 9 = - 7 + 9

(x + 3)² = 2 ( take square root of both sides )

x + 3 = ± [tex]\sqrt{2}[/tex] ( subtract 3 from both sides )

x = - 3 ± [tex]\sqrt{2}[/tex]

74. REAL-WORLD APPLICATIONS
A car rental company offers two plans for renting a car. Plan A: $30 per day and $0.18 per mile Plan B: $50 per day with free unlimited mileage How many miles would you need to drive for plan B to save you money?

Answers

Answer:

For plan B to save money car rental need to drive 111.1 miles as [tex]\frac{x}{y}[/tex] expresses the average amounts of miles per day car rental drive and its obtained value is 111.1.

Step-by-step explanation:

In the question it is given that a car rental company offers two plans for renting a car.

Plan A: $30 per day and [tex]$\$ 0 \cdot 18$[/tex] per mile.

Plan B: $50 per day with free unlimited mileage

It is required to find that how many miles would be needed to drive for plan B to save money. be needed to drive for plan B to save money.

Step 1 of 5

In Plan A $30 per day and [tex]$\$ 0 \cdot 18$[/tex] per mile are costed so the cost of Plan A is given by following equation,

[tex]$$A=30 y+0 \cdot 18 x$$[/tex]

In Plan B $50 per day with free unlimited mileage are costed so the cost of Plan B is given by following equation,

[tex]$$B=50 y$$[/tex]

Step 2 of 5

Now comparing the obtained equations [tex]$A=30 y+0 \cdot 18 x$[/tex]

and B=50y.

[tex]$$30 y+0 \cdot 18 x=50 y$$[/tex]

Step 3 of 5

Subtract 30y from both the sides of the obtained equation 30 y+0.18x=50y and simplify using subtraction properties.

[tex]$$30 y+0 \cdot 18 x-30 y=50 y-30 y$$\\ $0 \cdot 18 x=20 y$[/tex]

Step 4 of 5

Divide both the sides of the obtained equation [tex]$0 \cdot 18 x=20 y$[/tex] by [tex]$0 \cdot 18$[/tex] and simplify using division properties.

[tex]$$\begin{aligned}&\frac{0 \cdot 18 x}{0 \cdot 18}=\frac{20 y}{0.18} \\&x=\frac{1000 y}{9}\end{aligned}$$[/tex]

Step 5 of 5 save money car rental need to drive 111.1 miles.

[tex]$$\begin{aligned}&\frac{x}{y}=\frac{1000 y}{9 y} \\&\frac{x}{y}=111.1\end{aligned}$$[/tex]


y varies directly with x. If y = -4 when x = -1, what is the constant of variation?

Answers

the constant variation, K= 4

Step-by-step explanation:

i have replace the constant variation by the letter K

First step is to write down the information

y directly proprotional to x

So, y= Kx

Replace the value given for x and y to find k

y= -4 and x = -1

Kx= y

K( -1) = -4

K = -4 ÷ -1

K= 4

Further answer

if you are asked the connecting equation between y and x just replace the value of K in the equation

y= Kx

y= 4x

Find the equation of the line shown

Answers

The equation of line passing through points (4.5. 0) and (0, 9) is y = -2x + 9.

What is the equation of a line passing through two given points in a 2-dimensional plane?

Suppose the given points are (x_1, y_1) and (x_2, y_2), then the equation of the straight line joining both two points is given by

[tex](y - y_1) = \dfrac{y_2 - y_1}{x_2 - x_1} (x -x_1)[/tex]

The graph of the picture shows two clear points (4.5. 0) and (0, 9)

[tex](y - 0) = \dfrac{9 - 0}{0 - 4.5} (x -4.5)\\\\\\(y - 0) = \dfrac{9 }{- 4.5} (x -4.5)\\\\\\-4.5y = 9(x -4.5)\\\\-4.5y = 9x - 40.5\\\\y = -2x + 9[/tex]

Hence, the equation of line passing through points (4.5. 0) and (0, 9) is y = -2x + 9.

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Find x so that l || m. Show your work.

Answers

Hello,

Answer:

x = 13

Step-by-step explanation:

    7x + 5 + 5x + 19 = 180

⇔ 12x + 24 = 180

⇔ 12x = 180 - 24

⇔ 12x = 156

⇔ x = 156/12

x = 13

A school laboratory has two types of conical flask. Large conical flasks can hold 1.6 litres and small conical flasks can hold 600 ml. a) Mark has f large flasks and w small flasks, all full of hydrochloric acid. Write an expression for how many millilitres (ml) of acid he has. b) Bev has 2f large flasks and 2w small flasks, all full of hydrochloric acid. Write an expression for how many millilitres (ml) of acid she has. ​

Answers

Answer:

[tex](a)1600f+600w\\\\(b)1600\times2f+600\times2w[/tex]

solve the following system of equations for x : y=4-x2 x-y=2

a. x= 2,-4
b. x= 2,-3
c. x= -2,4
d. x= -3

Answers

Answer:

b. x=2, -3

Step-by-step explanation:

So I'm assuming the two equations are: [tex]y=4-x^2[/tex] and [tex]x-y=2[/tex]

Since it's asking to solve to solve for x. Then we need to solve for y in one of the equations, so that's it's defined using x, then substitute that into the other equation, that way the only variable left is going to be the x variable.

So since y is already solved for in the first equation. I'll plug that into the second equation.

Original equation:

[tex]x-y=2[/tex]

Substitute 4-x^2 in as y

[tex]x-(4-x^2)=2[/tex]

Distribute the negative sign

[tex]x-4+x^2=2[/tex]

Organize it so it's in order by degree

[tex]x^2+x-4=2[/tex]

Subtract 2 from both sides

[tex]x^2+x-6=0[/tex]

So now we have a quadratic equation and we're trying to find the zeroes. You can use the quadratic equation, but since the only options are integers, we can easily factor this equation. So you need to look for factors of -6, which add up to 1. I like to think about it as find two numbers with a difference of 1, and then figure out which is going to be positive and which is going to be negative after. So knowing this you can easily see 3 and 2 have a difference of 1. Since the 1 is positive, that means the 3 has to be positive and the 2 has to be negative

Use the factors: 3 and -2 to rewrite the equation:

[tex](x+3)(x-2)[/tex]

Now set each factor equal to 0

x+3 = 0

x=-3

x-2=0

x=2

this gives you the two solutions: -3, and 2

Can someone help me with these geometry questions? I can’t seem to understand them. If u find the answers, can u explain it too? It’s urgent

Answers

Question 5

Vertical angles are congruent. Therefore, [tex]3y=\boxed{150}[/tex]. The sum of two supplementary angles equals [tex]\boxed{180^{\circ}}[/tex].

Therefore, [tex]6x+150=\boxed{180}[/tex]

Question 6

[tex]\angle b-14=90-\angle b\\\\2\angle b=104\\\\\angle b=\boxed{52^{\circ}}[/tex]

Question 7

[tex]\angle d+32=180-\angle d\\\\2\angle d=146\\\\\angle d=\boxed{73^{\circ}}[/tex]

Question 8

[tex]7x-80=3x\\\\-80=-4x\\\\x=20\\\\\implies \boxed{m\angle 1=m\angle 3=60^{\circ}}[/tex]

Other Questions
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