CAN SOMEONE HELP ME
Triangle not drawn to scale
Given: measure of angle A = 15 degrees, b = 16, and
c = 18. What is the length of a to the nearest tenth?

Answer:

m=months

clark= 10000-105m

lois= 7500-50m

10000-105m=7500-50m

+50m

10,000-55m=7500

-10000

-55m=-2500

simplify

55m=2500

divide by 55

m=45.45

so i would say b

Hope This Helps!!!

The margin of error for a 95% confidence interval for the population proportion is 0.0815.

Given sample size=60 and confidence interval of 95%.

We have to calculate margin of error for a confidence interval of 95%.

Margin of error is the difference between actual values and calculated values. Margin of error is a part of z test.

We have been given sample size=60.

8 people have received help from their parents from the sample.

p=8/60=0.13

which is sample proportion.

z=1-0.13

=0.87

To calculate standard error=[tex]\sqrt{p*z/n}[/tex]

=[tex]\sqrt{0.13*0.8/60}[/tex]

=0.0416

at 95% confidence interval

z(α/2)=1.96

therefore margin of error=1.96*0.0416

=0.081536

=0.0815

Hence the margin of error for 95% confidence interval is 0.0815

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Answer:

A.28 minutes

B.40 minutes

C.56 minutes

D.70 minutes

Step-by-step explanation:

Answer:

33.55

Step-by-step explanation:

Answer:

α = 33.56°  (nearest hundredth)

Step-by-step explanation:

Trigonometric ratios

[tex]\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}[/tex]

where:

Given:

As all sides of the right triangle have been given, any of the trigonometric ratios can be used to find α.

Sine Ratio

[tex]\begin{aligned}\sf \sin(\alpha) & = \sf \dfrac{\sqrt{11}}{6}\\\implies \alpha & = \sf \sin^{-1}\left(\dfrac{\sqrt{11}}{6}\right) \\& = \sf 33.55730976...^{\circ}\end{aligned}[/tex]

Cosine Ratio

[tex]\begin{aligned}\sf \cos(\alpha) & =\sf \dfrac{5}{6}\\\implies \alpha & = \sf \cos^{-1}\left(\dfrac{5}{6}\right) \\& = \sf 33.55730976...^{\circ}\end{aligned}[/tex]

Tangent Ratio

[tex]\begin{aligned}\sf \tan(\alpha) & =\sf \dfrac{\sqrt{11}}{5}\\\implies \alpha & = \sf \tan^{-1}\left(\dfrac{\sqrt{11}}{5}\right) \\& = \sf 33.55730976...^{\circ}\end{aligned}[/tex]

Therefore, α = 33.56°  (nearest hundredth)

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See below for the proof of the equation [tex]\frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b)[/tex]

The equation is given as:

[tex]\frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b)[/tex]

Take the LCM

[tex]\frac{(ax + by)(x - y) -(ax - by)(x + y)}{(x + y)(x - y)}= 2(a - b)[/tex]

Expand

[tex]\frac{ax^2 - axy + bxy - by^2 -ax^2 - axy + bxy + by^2}{(x + y)(x - y)}= 2(a - b)[/tex]

Evaluate the like terms

[tex]\frac{-2axy + 2bxy }{(x + y)(x - y)}= 2(a - b)[/tex]

Rewrite as:

[tex]\frac{-2axy + 2bxy }{x^2 - y^2}= 2(a - b)[/tex]

Factorize the numerator

[tex]\frac{2(a - b)(x^2 - y^2)}{x^2 - y^2}= 2(a - b)[/tex]

Divide

2(a - b)= 2(a - b)

Both sides are equal

Hence, the equation [tex]\frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b)[/tex] has been proved

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Answer:

e) 55°

Step-by-step explanation:

use the tangente ratio

[tex]tan\alpha =\frac{10}{7} =1.42857[/tex]

[tex]angle(?)=tan^{-1} (1.42857)=55^{0}[/tex]

Hope this helps

Answer:

55 degrees (e)

Step-by-step explanation:

This is a trigonometry problem. We are given a right triangle with an unknown angle in which the opposite and adjacent sides of the angle are known (10 and 7). We also know that the tangent of any angle is the length of the opposite divided by the length of the adjacent. If we let the unknown angle be Ф, we can say that tan(Ф) = 10/7. To isolate Ф, all we have to do is take the inverse. In other words, Ф = arctan(10/7). Using a graphing calculator, we find that arctan(10/7) is approximately 55 degrees.

Question 4

1) [tex]\overline{BD}[/tex] bisects [tex]\angle ABC[/tex], [tex]\overline{EF} \perp \overline{AB}[/tex], and [tex]\overline{EG} \perp \overline{BC}[/tex] (given)

2) [tex]\angle FBE \cong \angle GBE[/tex] (an angle bisector splits an angle into two congruent parts)

3) [tex]\angle BFE[/tex] and [tex]\angle BGE[/tex] are right angles (perpendicular lines form right angles)

4) [tex]\triangle BFE[/tex] and [tex]\triangle BGE[/tex] are right triangles (a triangle with a right angle is a right triangle)

5) [tex]\overline{BE} \cong \overline{BE}[/tex] (reflexive property)

6) [tex]\triangle BFE \cong \triangle BGE[/tex] (HA)

Question 5

1) [tex]\angle AXO[/tex] and [tex]\angle BYO[/tex] are right angles, [tex]\angle A \cong \angle B[/tex], [tex]O[/tex] is the midpoint of [tex]\overline{AB}[/tex] (given)

2) [tex]\triangle AXO[/tex] and [tex]\triangle BYO[/tex] are right triangles (a triangle with a right angle is a right triangle)

3) [tex]\overline{AO} \cong \overline{OB}[/tex] (a midpoint splits a segment into two congruent parts)

4) [tex]\triangle AXO \cong \triangle BYO[/tex] (HA)

5) [tex]\overline{OX} \cong \overline{OY}[/tex] (CPCTC)

Question 6

1) [tex]\angle B[/tex] and [tex]\angle D[/tex] are right angles, [tex]\overline{AC}[/tex] bisects [tex]\angle BAD[/tex] (given)

2) [tex]\overline{AC} \cong \overline{AC}[/tex] (reflexive property)

3) [tex]\angle BAC \cong \angle CAD[/tex] (an angle bisector splits an angle into two congruent parts)

4) [tex]\triangle BAC[/tex] and [tex]\triangle CAD[/tex] are right triangles (a triangle with a right angle is a right triangle)

5) [tex]\triangle BAC \cong \triangle DCA[/tex] (HA)

6) [tex]\angle BCA \cong \angle DCA[/tex] (CPCTC)

7) [tex]\overline{CA}[/tex] bisects [tex]\angle ACD[/tex] (if a segment splits an angle into two congruent parts, it is an angle bisector)

Question 7

1) [tex]\angle B[/tex] and [tex]\angle C[/tex] are right angles, [tex]\angle 4 \cong \angle 1[/tex] (given)

2) [tex]\triangle BAD[/tex] and [tex]\triangle CAD[/tex] are right triangles (definition of a right triangle)

3) [tex]\angle 1 \cong \angle 3[/tex] (vertical angles are congruent)

4) [tex]\angle 4 \cong \angle 3[/tex] (transitive property of congruence)

5) [tex]\overline{AD} \cong \overline{AD}[/tex] (reflexive property)

6) [tex]\therefore \triangle BAD \cong \triangle CAD[/tex] (HA theorem)

7) [tex]\angle BDA \cong \angle CDA[/tex] (CPCTC)

8) [tex]\therefore \vec{DA}[/tex] bisects [tex]\angle BDC[/tex] (definition of bisector of an angle)

The values of a, b, and c are -4,0 and 0 and the parabola opens downward with y-intercept (0,0).

we have

y=-4x^2

The quadratic equation in standard form is equal to

ax^2+bx+c=0

So,In this problem

a=-4, b=0 and c=0

The y-intercept is the value of y when the value of x is equal to zero

y=-4(0)^2=0

The y-intercept is the point (0,0)

The coefficient a is negative, therefore the parabola opens down.

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Answer:

[tex]94.6cm^{2}[/tex]

Step-by-step explanation:

First we will find the area of Square PQRS.

Area of Square PQRS = Length x Width = 21 x 21

= [tex]441cm^{2}[/tex]

Next we will found the Area of Semicircles PS and QR.

Note: Area of Semicircle PS = Area of Semicircle QR

Area of Semicircle = [tex]\frac{1}{2} \pi r^{2}[/tex]

Total Area of Semicircles PS and QR combined = [tex]2(\frac{1}{2} \pi r^{2} )\\=\pi r^{2}[/tex]

We know that the diameter of PS = QR = 21 cm (due to the length of the square)

Radius = Half of Diameter = 0.5 x 21cm = 10.5cm

Total Area of Semicircles PS and QR = [tex]\pi (10.5)^{2} \\=110.25\pi cm^{2}[/tex]

Finally,

Area of Shaded Region = Area of Rectangle PQRS - Total Area of Semicircles PS and QR

= [tex]441 - 110.25\pi\\= 94.6cm^{2} (1dp)[/tex]

In this case , you can choose the nearest answer as there might be some rounding differences.

Answer:

[tex]a = (h)(2h - 5)[/tex]

Answer:

Area of the rectangle = 2h² - 5

Step-by-step explanation:

• base length l = 5 less than twice the height h

                        = 2h - 5

• height = h

Area of rectangle = base × height

                             ⇒ l × h

                             ⇒ (2h - 5)(h)

                              ⇒ 2h² - 5

Answer:

x = 69 v = 103

Step-by-step explanation:

Angles in a triangle add up to 180 degrees:

34 + 77 + x = 180

x = 69

Angles on a straight line add up to 180:

77 + v = 180

v = 103

Answer:

Step-by-step explanation:

the sum of the interior angles in a triangles is 180°, take away from 180 the know angles (34° and 77°) and you will have your answer

180 - 34 - 77 = 69°

Now we find angle V

The angle V and the angle of 77 ° are on a straight line, so the sum is 180°, from 180° you subtract 77 ° and you have the value of V

180 - 77 = 103 °

Answer:

6

Step-by-step explanation:

9 x 2/3

9/1   x 2/3 =   18 / 3  = 6

Solving a linear equation, we will see that the 3 numbers are:

48, 49, and 50.

3 consecutive integers can be written as:

x, x + 1, x + 2

Here we know that 2 times the largest number minus 3 times the smallest one is -44, then:

2*(x + 2) - 3x = -44

We can solve that linear equation for x:

2x + 4 - 3x = -44

(2 - 3)x = -44 - 4

-x = -48

x = 48

Then the 3 numbers are:

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The graph is in a reciprocal relationship with Option C

A function is a mathematical statement used to relate a dependent and n independent variable.

The function is represented by the graph

The nature of the graph is exponential

and the equation is determined by the points on the graph

( 1,1) ( 2,4) '

The equation is

y = ( 1/4) 4ˣ

The inverse of the function will be found by replacing the y variable with x and vice versa and then solving to bring the function into the form of x.

x = ( 1/4) [tex]\rm 4^y[/tex]

Plotting this gives the answer as Option C

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The equation of the perpendicular line to the given line is: y = -5/4x - 30.

The slope values of two perpendicular lines are negative reciprocal of each other.

Given that the line is perpendicular to y = 4/5x+23, the slope of y = 4/5x+23 is 4/5. Negative reciprocal of 4/5 is -5/4.

Therefore, the line that is perpendicular to it would have a slope (m) of -5/4.

Plug in m = -5/4 and (x, y) = (-40, 20) into y = mx + b to find b:

20 = -5/4(-40) + b

20 = 50 + b

20 - 50 = b

b = -30

Substitute m = -5/4 and b = -30 into y = mx + b:

y = -5/4x - 30

The equation of the perpendicular line is: y = -5/4x - 30.

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Answer:

A. (3, 8) and [tex]2\sqrt{2}[/tex]

B. (2, 4) and [tex]2\sqrt{10}[/tex]

Step-by-step explanation:

Midpoint formula: [tex](\frac{x1+x2}{2} ,\frac{y1+y2}{2})[/tex]

Distance formula: [tex]\sqrt{(x_{2}-x_{1}) ^2+(y_{2}-y_{1}) ^2 }[/tex]

A. plug in the points in the formulas

(4, 7) and (2, 9)

Midpoint:

[tex](\frac{4 + 2}{2} , \frac{7+9}{2} )=6/2, 16/2 = (3,8)[/tex]

Length:

[tex]\sqrt{(2-4)^2+(9-7)^2}=\sqrt{4+4} =\sqrt{8} =2\sqrt{2}[/tex]

B.

(5, 5) and (-1, 3)

Midpoint:

[tex](\frac{5-1}{2} , \frac{5+3}{2} )=4/2,8/2=(2,4)[/tex]

Length:

[tex]\sqrt{(-1-5)^2+(3-5)^2} =\sqrt{-6^2+-2^2} =\sqrt{36+4} =\sqrt{40} = 2\sqrt{10}[/tex]

Can you consider marking my answers as brainliest lol it would mean a lot. Hope this helped.

Answer:

the third option

Step-by-step explanation:

Our equation is

[tex] {y}^{2} = 36(x - 10)[/tex]

Equation of a vertical parabola is

[tex]( {y - k)}^{2} = 4p(x - h)[/tex]

where (h,k) is the center

The focus is

(h+p, k)

Equation of directrix is

x= h-p,

Here the center is (10,0)

Next, we factor out 4 in the original equation

[tex]4(9)[/tex]

So we have

[tex] {y}^{2} = 4(9)(x - 10)[/tex]

So our p=9,

So our focus is

(10+9,0) or (19,0)

The third option is the answer

The location of the light bulb is at point A. (10, 0).

Option A is the correct answer.

We have,

To find the location of the light bulb, we need to identify the coordinates (x, y) at which the light bulb is located.

In the given parabolic mirror equation, y² = 36(x - 10), the vertex form of the equation for a parabola with a vertical axis is (h, k), where h is the

x-coordinate of the vertex and k is the y-coordinate of the vertex.

Comparing the given equation with the standard form

(y - k)² = 4a(x - h),

we can see that h = 10 and k = 0.

So, the location of the light bulb is at the point (10, 0).

Therefore,

The location of the light bulb is at point A. (10, 0).

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A searchlight uses a parabolic mirror to cast a beam of light in parallel rays where the light bulb is located at the focus of the parabola in order to give the best illumination.

The mirror is modeled by y² = 36 (x-10), where the measurements are in cm.

What is the location of the light bulb?

A. (10, 0)

B. (14, 0)

C. (19, 0)

D. (36, 0)

Answer:

False

Step-by-step explanation:

I'm not a 100 percent though

Answer:

10+1=11 but the 55 so it is now 11:55+15min so it makes it 12:10

Answer:

Hello! The answer to your question is 12:10.

Step-by-step explanation:

1 hour after 10:55 is equivalent to 11:55. Now, we have 15 minutes remaining. We can add in increments of 5 to get to 15 in terms of time:

11:55 + 5 minutes

= 12:00 + 5 minutes

= 12:05 + 5 minutes

= 12:10

5 + 5 + 5 = 15, so we reached 15.

The teacher collected the answer scripts at 12:10.

Answer:

-1/3

Step-by-step explanation:

When x is 1, y is 5

When x is 4, y is 4

5-4=1

1-4=-3

1/-3=-1/3

Answer:

x = -6-2y

Step-by-step explanation:

From the given information, the original number is 180. 02

Let the unit digit be x

The unit in tens is x+ 5

The original number = 10(x+5) + x = 11x + 50

The reversed number = 10x+ (x+5) = 11x+5

From the information given, we have that

(11x + 50) - (11x + 5) = 1/4 (11x + 50)

Expand the expression

11x + 50 - 11x - 5 = 1/ 4(11x + 50)

Collect like terms

11x - 11x + 50 - 5 = 1/ 4 (11x + 50)

45 = [tex]\frac{11x + 50}{4}[/tex]

Cross multiply

45 * 4 = 11x + 50

180 = 11x + 50

11x = 180 -50

11x = 130

x = 130/11

x = 11. 82

To find the original number, we have

Original number = 11x + 50

Substitute the value of x

Original number = 11(11.82) + 50

Original number = 130. 02 + 50

Original number = 180. 02

Therefore, the original number is 180. 02

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[tex]f( - 1) = - 3[/tex]

[tex]f(x) = 0 \\ for \: x = 2 \: or \: x = - 2[/tex]

wth is that wdym ???

Answer: D. It is the graph of f translated 3 units up and 7 units to the right

Step-by-step explanation:

the +3 part of the equation makes the function translated vertical 3 units

then the x - 7 part makes it translate horizontal to the right 7 units (always the opposite of the sign)

because when

x-7=0,

x=7